Answer:
(6, 8)
Step-by-step explanation:
A dilation scales an object on the coordinate plane using the scale factor, causing it to get bigger or smaller.
We are given that the point (3, 4) is dilated by 2; since 2 is greater than 1, this is an enlargement (in which the figure gets bigger).
So, all we need to do is multiply each of the coordinates by 2, like so:
[tex]3*2=6\\4*2=8[/tex]
Thus, the image of the point (3, 4), after being dilated by 2, is (6, 8).
In how many ways can a committee of two men and one women be formed from a group of ten men and eight women?
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman.
What is number?Numbers are mathematical units of measurement and labelling. It is a sign or collection of symbols that are used to represent a quantity, usually a real or integer number.
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman. The idea of combination can be used to arrive to this number.
Calculating the number of possible combinations of a given number of things is done mathematically using the concept of combination. C(n,r) = n! / (r! (n - r)!), where n is the total number of items and r is the number of things to be picked at a time, is the formula used to compute it. In this instance, r is the number of persons to be picked, which is 3, and n is the total number of people to be chosen from the group, which is 18, consisting of 10 males and 8 women.
As a result, there are a total of 10 ways for men and 8 ways for women to form a committee of two men and one woman C(18,3) = 18! / (3! (18 - 3)!) = 18! / (3! 15!) = 1320.
Thus, there are 1320 different methods to create a committee of two men and one woman out of a group of ten men and eight women.
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7(x + 2) = 7x + 14 i dont get this someone pls help
Answer:
7
(
x
−
2
)
−
7
x
−
14
=
0
7
(
x
−
2
)
−
7
x
−
14
=
07
(
x
−
2
)
−
7
x
−
14
=
0
Step-by-step explanation:
Answer: 0 = 0
Step-by-step explanation: i showed the steps with these screen shots
PLEASE HELP!!! This is due tomorrow and I haven’t had the time to finish since I have after school activities
Answer:
y int: (0, -23)
Step-by-step explanation:
first you find the slope by taking two points and substituting it in rise over run ([tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex])
I used 25-13/-72+54 which eventually simplified to -2/3
You then use point slope form and plug in one pair of points
I used (-36,1) since it seemed the easiest
y-1=[tex]\frac{-2}{3}[/tex](x+36) point slope form: [tex]y-y_{1}=m(x-x_{1} )[/tex]
y-1= [tex]\frac{-2}{3} x-\frac{72}{3}[/tex]
y-1=[tex]\frac{-2}{3} x-24[/tex]
y=[tex]\frac{-2}{3} x-23[/tex]
the number without the variable is always y int regardless of the numbers in the equation
therefore, the y int is (0,-23)
May anyone help with this question
Rounding to the nearest hundredth, the arc length of one slice is approximately 53.67 feet.
What is arc length?Arc length is the distance along the curved line or arc of a circle, measured in linear units such as centimeters, feet, or meters. It is calculated as the product of the radius of the circle and the angle subtended by the arc at the center of the circle, expressed in radians.
Here,
Since the circle is divided into eight equal slices, each slice is 360/8 = 45 degrees. The arc length of one slice can be calculated using the formula:
Arc length = (angle/360) x 2πr
where angle is the central angle in degrees, r is the radius of the circle, and π is the constant pi.
In this case, the diameter of the circle is 137 feet, so the radius is half of that, or 68.5 feet.
Substituting the given values into the formula, we get:
Arc length = (45/360) x 2 x 3.14 x 68.5
Arc length = 0.125 x 2 x 3.14 x 68.5
Arc length = 0.785 x 68.5
Arc length = 53.67 feet
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What is the answer to this question? (Please i need help)
A statement that is best supported by the data in the box plots include the following: H. the interquartile range of the data for the community college is greater than the interquartile range of the data for the university.
What is a box-and-whisker plot?In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.
How to calculate the interquartile range (IQR)?Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):
Interquartile range (IQR) of university = Q₃ - Q₁
Interquartile range (IQR) of university = 15 - 9
Interquartile range (IQR) of university = 6.
For the community college, we have;
Interquartile range (IQR) = 15 - 6
Interquartile range (IQR) = 9.
Therefore, 9 is greater than 6.
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state the nameof this quadrilateral...70 points
Answer:
Step-by-step explanation:
its a rectanlge
a company pays its employees an average of $5.25 per hour with a standard deviation of 60 cents. if the wages are approximately normally distributed: (a.) what percentage of the workers receive wages between $4.75 and $5.69 per hour? (b.) the highest 5% of the hourly wages are greater than what amount?
Using the standard normal distribution, we find that approximately 73.8% of workers receive wages between $4.75 and $5.69 per hour. Using the inverse of the standard normal distribution, we find that the highest 5% of hourly wages are greater than approximately $6.09.
Using a standard normal distribution table or calculator with a mean of 5.25 and a standard deviation of 0.60, we can find that approximately 79.42% of workers receive wages between $4.75 and $5.69 per hour.
Using a standard normal distribution table or calculator, we can find the z-score corresponding to the highest 5% of wages, which is approximately 1.645.
Then, we can solve for x in the equation z = (x - μ) / σ, where z is the z-score, μ is the mean of 5.25, and σ is the standard deviation of 0.60. This gives us x = zσ + μ, which is approximately $6.09 per hour. Therefore, the highest 5% of hourly wages are greater than $6.09 per hour.
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ANSWER ASAP AND PLEASE BE CORRECT FOR BRAINLIST
Question 12
A recent conference had 750 people in attendance. In one exhibit room of 70 people, there were 18 teachers and 52 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 193 principals in attendance.
There were about 260 principals in attendance.
There were about 557 principals in attendance.
There were about 680 principals in attendance.
Question 13
A college cafeteria is looking for a new dessert to offer its 4,000 students. The table shows the preference of 225 students.
Ice Cream Candy Cake Pie Cookies
81 9 72 36 27
Which statement is the best prediction about the number of cookies the college will need?
The college will have about 480 students who prefer cookies.
The college will have about 640 students who prefer cookies.
The college will have about 1,280 students who prefer cookies.
The college will have about 1,440 students who prefer cookies.
Question 14
A random sample of 100 middle schoolers were asked about their favorite sport. The following data was collected from the students.
Sport Basketball Baseball Soccer Tennis
Number of Students 17 12 27 44
Which of the following graphs correctly displays the data?
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
Question 15
The line plots represent data collected on the travel times to school from two groups of 15 students.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 4, 6, 14, and 28. There are two dots above 10, 12, 18, and 22. There are three dots above 16. The graph is titled Bus 47 Travel Times.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9, 18, 20, and 22. There are two dots above 6, 10, 12, 14, and 16. The graph is titled Bus 18 Travel Times.
Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer.
Bus 18, with a median of 13
Bus 47, with a median of 16
Bus 18, with a mean of 13
Bus 47, with a mean of 16
Below is the answer to the questions:
Q 12.
The prediction is that there were about 260 principals in attendance at the conference.
Q13.
The best prediction is that the college will have about 480 students who prefer cookies.
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A rectangular garden has a walkway around it. The area of the garden is 4(4.5x+3.5). The combined area of the garden and the walkway is 5.5(6x+5). Find the area of the walkway around the garden as the sum of two terms.
The product of two terms gives the walkway's area around the garden: 15x+13.5.
Define rectangleA rectangle is a four-sided polygon with two pairs of parallel and congruent sides, and four right angles. The opposite sides of a rectangle are equal in length and parallel to each other, while the adjacent sides are perpendicular to each other.
Area of garden = 4(4.5x + 3.5) = 18x+14
The combined area of the garden and the walkway = 5.5(6x+5) =33x+27.5
The area of the walkway (Aw) around the garden is the result of subtracting the total area minus the inner area:
Aw=combined area -Area of garden
=33x+27.5-18x-14
=15x+13.5
Thus, we can say that the area of the walkway around the garden is the sum of two terms: 15x+13.5.
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Find the exact value of sin a, given that cos a=-5/9 and a is in quadrant 3
Since cosine is negative and a is in quadrant III, we know that sine is positive. We can use the Pythagorean identity to solve for sine:
sin^2(a) + cos^2(a) = 1
sin^2(a) + (-5/9)^2 = 1
sin^2(a) = 1 - (-5/9)^2
sin^2(a) = 1 - 25/81
sin^2(a) = 56/81
Taking the square root of both sides:
sin(a) = ±sqrt(56/81)
Since a is in quadrant III, sin(a) is positive. Therefore:
sin(a) = sqrt(56/81) = (2/3)sqrt(14)
Which of the following combinations of side lengths would NOT form a triangle with vertices X, Y, and Z? A. XY = 11 mm , YZ = 12 mm , XZ = 18 mm B. XY = 16 mm , YZ = 12 mm , XZ = 23 mm C. XY = 16 mm , YZ = 17 mm , XZ = 18 mm D. XY = 11 mm , YZ = 12 mm , XZ = 28 mm
the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
How to solve the question?
To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
Let's check each option:
A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm
To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:
XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm
YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm
XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm
YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm
Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.
C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm
YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm
YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm
XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm
The first combination is less than the third side, so a triangle cannot be formed with these side lengths.
Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
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1. Calculate the perimeter, area and volume a) Classroom with Length=10m, breadth=8m and height=3m b) Box with Length=40cm, breadth=25cm and height=30cm c) Cabinet with length=80cm, breadth=70cm and height=2m Area Volume 26 a b C Perimeter
a) Classroom:
Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m
Area = length x breadth = 10m x 8m = 80m^2
Volume = length x breadth x height = 10m x 8m x 3m = 240m^3
What is the perimeter, area and volume?b) Box:
Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm
Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2
Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3
c) Cabinet:
Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm
Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2
Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3
Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.
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3 out of 7 questions. PLEASE help me.
Translate the solid circle 2 units to the left and 2 units down and dilate the solid circle by a scale factor of 2. and the circles are similar
Transforming the circles(a) To move the solid circle exactly onto the dashed circle, we need to perform the following transformations:
Translate the solid circle 2 units to the left and 2 units down.Dilate the solid circle by a scale factor of 2.Therefore, the blank spaces should be filled as follows:
Translate the solid circle 2 units to the left and 2 units down.
Dilate the solid circle by a scale factor of 2.
(b) Yes, the original solid circle and the dashed circle are not similar, because they have different radii.
This is because all circles are similar
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Becca is construction triangle d e f using the following angles 50°, 65°, 65°,
what mistake did she make?
Becca made a mistake while constructing triangle DEF by using the angles 50°, 65°, and 65°. The mistake she made was violating the triangle inequality theorem.
According to the theorem, the sum of any two sides of a triangle must be greater than the third side. In other words, if we add the lengths of two sides of a triangle, it must be greater than the length of the third side.
Since Becca only used angles to construct the triangle, she did not consider the side lengths of the triangle. Therefore, there is a possibility that the triangle she constructed does not satisfy the triangle inequality theorem, and it may not be a valid triangle.
In order to ensure the triangle is valid, Becca needs to consider the side lengths while constructing the triangle. She could use trigonometric ratios or a ruler and protractor to measure the side lengths and angles accurately.
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is 12% a reasonable estimate of the proportion of all americans who eat chocolate frequently? why or why not?
The reasonableness of the estimate depends on the quality and reliability of the data sources and methodology used to arrive at the estimate.
In order to determine whether 12% is a reasonable estimate of the proportion of all Americans who eat chocolate
frequently, we would need to define what is meant by "frequently."
If we define "frequently" as "at least once a week," then 12% may or may not be a reasonable estimate, depending on
the data source and methodology used to arrive at that estimate.
For example, if the estimate is based on a small sample size or a non-representative sample of the population, then it
may not be a reliable estimate of the true proportion of Americans who eat chocolate frequently. Additionally, if the
estimate is several years old, it may not accurately reflect current trends and habits.
On the other hand, if the estimate is based on a large, nationally representative sample of the population, and is
relatively recent, then 12% could be a reasonable estimate of the proportion of Americans who eat chocolate
frequently.
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Use the form |x-b |< c or |x-b | > c to write an absolute value inequality that has the solution set 5 < x < 7.
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
What is inequality?Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.
to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.
In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.
Therefore, we can write the absolute value inequality as:
[tex]| x - 6 | < 1[/tex]
Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:
[tex]x < 5 or x > 7[/tex]
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
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lee had scored the following points in his first 8 games 12,14,14,15,8,10,3,15 enter the number of points lee needs to score in the nest game to increase his keam score to 13 points PLS ANSER FASTE
ASAP I really need help doing a two column proof for this please.
The two column proof is written as follows
Statement Reason
MA = XR given (opposite sides of rectangle)
MK = AR given (opposite sides of rectangle)
arc MA = arc RK Equal chords have equal arcs
arc MK = arc AK Equal chords have equal arcs
Equal chords have equal arcsAn arc is a portion of the circumference of a circle, and a chord is a line segment that connects two points on the circumference.
If two chords in a circle are equal in length, then they will cut off equal arcs on the circumference. This is because the arcs that the chords cut off are subtended by the same central angle.
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Which comparison is not correct?
A. 1 > -9
B. 3 < 6
C. -8 > -6
D. -3 < 4
Answer:
The comparison that is not correct is:
C. -8 > -6
This is not correct because -8 is actually less than -6. Therefore, the correct comparison would be -8 < -6.
The other comparisons are correct:
A. 1 > -9 (true, because 1 is greater than -9)
B. 3 < 6 (true, because 3 is less than 6)
D. -3 < 4 (true, because -3 is less than 4)
Graph the solution of the inequality.
3.5
Find the measure of the line segment indicated, assume that lines which appear tangent, are tangent.
Find FS
Possible answers —>
A. 17
B. 21
C. None of the other answers are correct
D. 18
E. 45
The value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
What is the properties of intersecting chordsThe property of intersecting chords states that in a circle, if two chords intersect, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
UF × FS = VF × FT
8(10x - 1) = 9 × 16
80x - 8 = 144
80x = 144 + 8 {collect like terms}
80x = 152
x = 152/80 {divide through by 80}
x = 1.9
FS = 10(1.9) - 1 = 18
Therefore, the value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
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Sam makes tote bags for a school fundraiser. The fixed costs for making the bags is $30. The cost of the materials for each bag is $8.50. Sam can spend less than a total of $200 on the tote bags. Write an inequality that can be used to determine b , the number of tote bags that can be made.
Find the measure of the missing side.
1. 8.2
2. 9.9
3. 7.4
4. 10.9
Answer:
1
Step-by-step explanation:
First of all we use the "law of sines"
to get the measure/length we need the opposing angle of it of the side, now in this case the missing side is x
and its opposing angle is missing so using common sense, the sum of angles in the triangle is 180°
180°=70°+51°+ x
x = 180°-121°
=59°
Using law of sines:
(sides are represented by small letters/capital letters are the angles)
a/sinA= b/sinB= c/sinC
We have one given side which is "9"
so,
9/sin70= x/sin59
doing the criss-cross method,
9×sin59=sin70×x
9×sin59/sin70=x
x=8.2 (answer 1)
I hope this was helpful <3
Is the triangle equilateral, isoscele, or scalene?
Answer: This triangle is isoscele
Step-by-step explanation:
solve for x please
Choices are..
6
20
140
90
Answer:
Answer is 20
Step-by-step explanation:
When two lines intersect each other as a result of that, every opposite angles are equal
so,
6x+20 = 140
6x = 120
x = 120/6
x = 20
Answer:
x = 20
Step-by-step explanation:
Vertically opposite are equal
therefore
6x + 20 = 140
6x = 140-20
6x = 120
6x/6 = 120/6
x = 20
Grupo textil M & M destaca que los ingresos de este año vienen dados por la funcion f(x) = (x+2)(-x+9-3) donde "x" es el precio de cada unidad y f(x) es la ganancia expresada en dolares
Para entender mejor esta función, podemos expandirla y simplificarla:
f(x) = (x+2)(-x+6)
f(x) = [tex]-x^2 + 4x + 12[/tex]
Esta es una función cuadrática, lo que significa que tiene la forma de una parábola. El término cuadrático ([tex]-x^2[/tex]) hace que la parábola tenga una concavidad hacia abajo, lo que significa que el valor máximo de la función se encuentra en el vértice de la parábola.
Podemos encontrar el valor del precio de venta que maximiza la ganancia utilizando la fórmula x = -b/(2a), donde "a" es el coeficiente del término cuadrático y "b" es el coeficiente del término lineal.
En este caso, a = -1 y b = 4, por lo que:
x = -4/(2-1)
x = -4/-2
x = 2
Por lo tanto, el precio de venta que maximiza la ganancia es de 2 por unidad. Si se venden las unidades a este precio, la ganancia total sería de:
f(2) = [tex]-2^2 + 4(2) + 12[/tex]
f(2) = -4 + 8 + 12
f(2) = 16 dólares
Es importante tener en cuenta que la función f(x) también puede ser utilizada para calcular la ganancia total para cualquier precio de venta "x". Por ejemplo, si se venden las unidades a 3 por unidad, la ganancia sería:
f(3) = [tex]-3^2 + 4(3) + 12[/tex]
f(3) = -9 + 12 + 12
f(3) = 15 dólares
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What is the exact area of the trapezoid?
Answer:
135.07 mm2
Step-by-step explanation:
height = 10.39 mm
area = 135.07 mm2
the mean iq of the population of osu students is 100. a random sample of 5 students will be taken from the population, but the first student scored 150. what do expect the average to be for the 5 students?
Even though the first student scored 150, the expected average IQ score for the remaining four students is still 100.
Explain average
The average is a statistical measure that represents the central tendency of a set of values. It is calculated by adding up all the values and dividing them by the total number of values. The average provides a single value that represents the typical value in the set and is often used to compare different sets of data or to summarize large amounts of data.
According to the given information
Let X be the random variable representing the IQ score of an individual student. Then, the sample mean of the five students, denoted by Y, can be expressed as:
Y = (X1 + X2 + X3 + X4 + X5) / 5
Given that the first student scored 150, the expected value of the sample mean of the remaining four students, denoted by E(Y|X1=150), can be calculated as follows:
E(Y|X1=150) = E((X2 + X3 + X4 + X5) / 4 | X1 = 150)
Since X1 = 150 is an observed value, we can treat it as a constant and apply the linearity of expectation:
E((X2 + X3 + X4 + X5) / 4 | X1 = 150) = (E(X2 | X1 = 150) + E(X3 | X1 = 150) + E(X4 | X1 = 150) + E(X5 | X1 = 150)) / 4
Now, since the sample is random, the remaining four IQ scores are also independent and identically distributed as X, with the same mean of 100. Therefore, we have:
E(X2 | X1 = 150) = E(X3 | X1 = 150) = E(X4 | X1 = 150) = E(X5 | X1 = 150) = E(X)
Thus, we can simplify the expression as:
E(Y|X1=150) = (4E(X) / 4) = E(X) = 100
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a professor has two lightbulbs in her garage. when both are burned out, they are replaced, and the next day starts with two working lightbulbs. suppose when both are working, one of the two will go out with probability 0.03, and we cannot lose both lightbulbs on the same day. however, when only on lightbulb works, it will burn out with probability 0.07. what is the long-run fraction of time that there is exactly one lightbulb working?
The long-run fraction of time that there is exactly one lightbulb working (event O) is: 0.228.
Let's use the following notation:
Let W denote the event that both lightbulbs are working,
let O denote the event that one lightbulb is working, and
let B denote the event that both lightbulbs are burnt out.
We are given that when both lightbulbs are working (event W), one of them will go out with probability 0.03.
Therefore, the probability that both lightbulbs will still be working on the next day is 1 - 0.03 = 0.97.
On the other hand, when only one lightbulb is working (event O), it will burn out with probability 0.07, and the other lightbulb is already burnt out.
Hence, the probability of moving from O to B is 1.
We can set up the following system of equations to model the probabilities of being in each state on the next day:
P(W) = 0.97P(W) + 0.5P(O)
P(O) = 0.03P(W) + 0.93P(O) + 1P(B)
P(B) = 0.07P(O)
Note that in the first equation, we use 0.97 because the probability of staying in W is 0.97, and the probability of moving to O is 0.5 (because there are two ways for one of the lightbulbs to go out).
Simplifying the system of equations, we get:
0.03P(W) - 0.5P(O) = 0
-0.03P(W) + 0.07P(O) - 1P(B) = 0
0P(W) - 0.07P(O) + 1P(B) = 0
Solving for P(O), we get:
P(O) = 0.3P(W)
Substituting this into the second equation, we get:
-0.03P(W) + 0.07(0.3P(W)) - P(B) = 0
Simplifying, we get:
P(B) = 0.004P(W)
We also know that the sum of the probabilities of being in each state must be 1:
P(W) + P(O) + P(B) = 1
Substituting the expressions for P(O) and P(B), we get:
P(W) + 0.3P(W) + 0.004P(W) = 1
Solving for P(W), we get:
P(W) = 0.762
Therefore, the long-run fraction of time that there is exactly one lightbulb working (event O) is:
P(O) = 0.3P(W) = 0.228.
Approximately 22.8% of the time, there will be exactly one lightbulb working.
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If quadrilateral PQRS is a parallelogram, line segment QR is ≅ to line segment QT, and m∠TQR=60°, which angles are congruent to ∠S? Select all that apply.
a.) ∠P
b.) ∠PQR
c.) ∠RQT
d.) ∠QRT
e.) ∠SRQ
f.) ∠TQR
From the given information, you can deduce that triangle QTR is equilateral and equiangular (all angles are 60 degrees)
b, c, d, and f are true
The opposite angles of a parallelogram are congruent (b)
If 2 parallel lines are cut by a transversal, then the corresponding angles are congruent (d)
Angle RQT is congruent to angle QRT, and angle QRT is congruent to angle S. By the transitive property, angle RQT is congruent to angle S (c)
Transitive property, like c (f)