Size: large, drop height: 1 metre, surface: hard floor, and size: large, drop height: 10 metres, surface: hard floor are the two trials that would allow a researcher to examine the influence of increasing drop height upon the force experienced by the egg.
Since the goal of the experiment is to understand how a difference in mass (or size) can impact the force that the egg experiences, It means that the other points of measurement should remain the same and only the size should change. Therefore, the Trials that would enable an experimenter to ascertain the impact of increasing drop height on the force felt by the egg under two sets of experimental conditions are size: large, drop height: 1 metre, and surface: hard.
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electrons are accelerated by a 1000-v potential drop. (a) calculate the de broglie wavelength. (b) calculate the wave- length of the x-rays that could be produced when these elec- trons strike a solid.
The de Broglie wavelength of the electron is 2.212 x 10-11 m.
What is Broglie wavelength?The de Broglie wavelength is a concept in quantum mechanics which states that all matter has a wave-like nature, and can thus be described as a wave.
(a) The de Broglie wavelength (λ) of a particle is given by the equation: λ = h/p, where h is Planck's constant (6.626 x 10-34 J.s) and p is the momentum of the particle.
The momentum of an electron with a 1000-V potential drop is given by the equation p = eV/c,
where e is the electron charge (1.602 x 10-19 C) and c is the speed of light (2.998 x 108 m/s).
Therefore, the de Broglie wavelength of the electron is:
λ = h/(eV/c) = (6.626 x 10-34 J.s) / (1.602 x 10-19 C x 1000 V/2.998 x 108 m/s) = 2.212 x 10-11 m.
(b) X-rays are produced when high-energy electrons strike a solid.
The wavelength of the x-ray is inversely proportional to the energy of the electron.
The energy of the electron is equal to the potential drop, i.e. 1000 eV. Therefore,
the wavelength of the x-ray produced is: λ = hc/eV = (6.626 x 10-34 J.s x 2.998 x 108 m/s)/(1.602 x 10-19 C x 1000 eV) = 1.246 x 10-10 m.
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at what speed do a bicycle and its rider, with a combined mass of 120 kg , have the same momentum as a 1200 kg car traveling at 5.0 m/s ? express your answer to two significant figures and include the appropriate units.
The speed of a bicycle and its rider with a combined mass of 120 Kg is 50m/s.
It is given that a car of mass 1200 kg is traveling at a speed of 5.0 m/s.momemtum of the car = mass × speed
= 1200 × 5
= 6000 kg m/s
It is given that the bicycle and its rider will also be having the momentum same as the car. Therefore, the momentum of the bicycle = 6000 kg m/s.Mass of the bicycle = 120 kg.
momentum of the bicycle = mass × speed
[tex]speed = \frac{6000}{120} \\\\ speed = 50 m/s[/tex]
Therefore, the speed of the bicycle and its rider = 50 m/s
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a bullet penetrates 7 cm into a piece of wood when fired at a speed of 33 m/s. find the time required for the bullet to stop.
When fired at 33 m/s, a bullet pierce a wood block by 7 cm. Find the rate of deceleration and the stopping time.
How is the target penetrated by a bullet?EXPLANATION: Due to its great velocity, a bullet discharged from a gun has a very high kinetic energy. The bullet's kinetic energy affects the object it impacts or strikes. The enormous kinetic energy the bullet possesses as a result of its speed causes it to pierce its target.
Does a gunshot go through the body?In addition to piercing tissue, bullets that enter a human body also break a bone and dislocate limbs. In addition to piercing tissue, bullets that enter a human body also break a bone and dislocate limbs. A colostomy life-long bag is possible in the event of an intestinal damage.
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if replacing the lights with a fluorescent bulb would save 60 w per night, what savings in kwh does this represent in one year?
The savings in kWh from replacing the lights with a fluorescent bulb in one year is 496.4 kWh/yr.
Evaluating :
Saving power = 60 w per night .
340 J/s ( 4h/d)(3600 sec/h) (365 d/yr)
( 1kWh/ 3.6 x 10 6 J)
= 496.4 kWh/yr
Which unit represents energy?The capacity to perform work is a definition of energy. When energy is released, a body performs the same amount of work as it has energy stored. Scalar energy is a quantity. Joule is the SI unit for energy. 1 joule of energy is the amount of energy required to perform one joule of work.
What is the energy rule?According to the law of conservation of energy, energy can only be changed from one form to another rather than being created or destroyed. Unless energy is added from the outside, a system always has the same amount of energy.
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If the acceleration of an object is negative , the object must be slowing down .
Yes the given statement is true. Negative acceleration of an object shows that the object is slowing down.
The rate of change of velocity with respect to time is nothing but the acceleration. It is considered as a vector quantity that has both magnitude and direction. Its SI unit is m/s², and its dimension formula is [LT⁻²]. Mathematically
Acceleration, a = (v₂ - v₁)/Δt
Where v₂ is the final velocity after time Δt, and v₁ is the initial velocity. If the acceleration is negative it means final velocity is smaller than initial velocity. It means object is slowing down. Negative acceleration is also called deceleration. Hence the given statement is true.
--The given question is incomplete, the complete question is:
"Is it true that If the acceleration of an object is negative the object must be slowing down?"--
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A 15. 0-cm-long solenoid with radius 0. 750 cm is closely wound with 600 turns of wire. The current in the windings is 8. 00 A. Compute the magnetic field at a point near the center of the solenoid
The windings' current is 8.00 A. A location close to the solenoid's center has a magnetic field of 0.0111 T.
The magnetic field at a point near the center of a solenoid can be calculated using the following formula:
B = (μ₀xnxI) / L
Where:
B is the magnetic field
μ₀ is the permeability of free space, which is 4π x 10^(-7) Tm/A
n is the number of turns per unit length of the solenoid, in turns/m
I is the current flowing through the solenoid, in A
L, length of solenoid
Given the radius of the solenoid as 0.75 cm = 0.0075 m, and the length of the solenoid as 15.0 cm = 0.15 m, the cross-sectional area of the solenoid is:
π*(0.0075 m)² = 1.767 x 10^-5 m²
The number of turns per unit length of the solenoid can be calculated by dividing the total number of turns by the length of the solenoid:
600 turns / 0.15 m = 4000 turns/m
We can now substitute these values into the formula:
B = (4π x 10^(-7) Tm/A) * (4000 turns/m) * (8.00 A) / (0.15 m)
B = 0.0111 T
Therefore, the magnetic field at a point near the center of the solenoid is 0.0111 T.
It is worth noting that this result is valid only when the solenoid is long enough so that its ends do not affect the magnetic field inside. Also, the solenoid is considered as tightly wound and the radius of the solenoid much smaller than the length, so that the magnetic field inside the solenoid is uniform.
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HELPPPP ASPPP PLEASE THA K YOU
In the transverse wave, point D represents the trough of the wave.
option D.
What is the trough of a wave?A wave two important points point, one curves upwards while the other curves downwards.
The maximum value of upward displacement within a cycle of a wave is known as crest. So the crest is a point on a surface wave where the displacement of the medium is at a maximum.
The maximum value of downward displacement within a cycle of a wave is known as trough.
Thus, from the graph, point A represents crest of the wave while point D represents trough of the wave.
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in what region is the electric field strongest? in what region is the electric field strongest? along the x axis between x
The nearest point to a charged item or the position of a point charge has the greatest electric field. As the distance from the charge grows, the electric field's intensity diminishes.
A force field called an electric field is produced when one electric charge interacts with other charges in the field and either attracts or repels them. The volts per metre (V/m) unit of measurement for the electric field is the letter E. It may be seen as a charge producing lines of force. A positive test charge would be pushed towards the direction of the electric field at a specific spot if it were to be placed there. The strength of the electric field is highest when the lines are close together and weakest when they are far apart.
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An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0. 0 degrees Celsius and rejects heat to a room at a temperature of 19. 2 degrees Celsius. Suppose that liquid water with a mass of 76. 3kg at 0. 0 degrees Celsius is converted to ice at the same temperature. Take the heat of fusion for water to be L_f = 3. 34*10^5 J/kg.
How much energy E must be supplied to the device?
Express your answer in joules
The energy E must be supplied to the device is 1.8x10^3kJ when an ice-making machine inside a refrigerator operates in a Carnot cycle.
Given the temperature initially (Tl) = 0degrees Celsius = 273K
The final temperature (Tc) = 19.2degrees Celsius = 273 + 19.2 = 292.2K
Mass of liquid water (m) = 76.3kg
The water is converted to ice at 0 degrees Celsius
The heat of fusion for water to be Lf = 3.34*10^5 J/kg.
Let heat released from ice = Qc
Heat absorbed by water = Ql
We know that Ql = mLf = 76.3 x 3.34*10^5 = 2.54*10^4kJ
Then Qc/Ql = -Tc/Tl
Qc = - 254.842*10^5 (292.2/273)
Qc = -2.72x10^4kJ
The heat being lost to the hot reservoir is the cause of the negative sign.
We know that Ql = Qc + W where W is the work done
W = Qc - Ql = 2.54*10^4kJ - 2.72x10^4kJ
W = 1.8x10^3kJ
Hence the energy E that must be supplied to the device is 1.8x10^3kJ
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If a battery produces a voltage of 53V and a resistance of 31 Ohms, calculate the current.
for serial weight measurements, what time of day would you instruct the person to have his or her weight measured?
Answer: approximately the same time of day
Explanation:
for each of the following items, indicate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
For the investigation and analysis of micro- and nanoparticle imaging characterisation of solid objects, scanning electron microscopes (SEM) are among the most frequently used instrumentation.
What is the purpose of a scanning electron microscope? For the investigation and analysis of micro- and nanoparticle imaging characterisation of solid objects, scanning electron microscopes (SEM) are among the most frequently used instrumentation.The SEM's resolution of 10 nm, or 100, is one of the factors that make it popular for particle size analysis.Since many interior structures have membranes that are obscured by the light microscope, a transmission electron microscope would be the most effective tool for seeing the cell's internal architecture.Use both hands whenever you carry a microscope.With one hand, hold the arm firmly, and with the other, support it by placing it beneath the base.To learn more about electron microscope refer
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Which sentence best explains the relationship between cells, tissues. And organs in the human body
Organ function is related to cell size which determines the function of tissues explains the relationship between cells, tissues and organs in the human body
Define a cell.
The smallest structural and operational unit of an organism is a cell. Although it is often tiny, macroscopic cells can also exist. Your body's basic building blocks are these cells, which are present in many different forms.
A tissue is made up of a collection of comparable cells and the connective tissue that binds them together to serve a common purpose. An organ is a collection of tissues found in an organism that cooperate to carry out a specific task. The lungs, kidneys, and stomach are a few examples. The bronchi, bronchioles, and alveoli all work together to assist the lungs exchange oxygen and carbon dioxide from the blood.
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two equally charged particles are held 3.2x10-3 m apart and then released from rest. the initial acceleration of the first particle is observed to be 7.0 m/s2 and that of the second to be 9.0m/s2 . if the mass of the first particle is 6.3 x 10-7 kg, what are (a) the mass of the second particle and (b) the magnitude
The mass and magnitude of the second particle are calculated below.
The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.
Distance between the charges, r = 3.2 × [tex]10^{-3}[/tex]m
initial acceleration of first particle, [tex]a_{1}[/tex] = 7m / [tex]s^{2}[/tex]
Initial acceleration of second particle, [tex]a_{2}[/tex] = 9.0m / [tex]s^{2}[/tex]
Mass of first particle, [tex]m_{1}[/tex] = 6.3 × [tex]10^{-7}[/tex]kg
Mas of second particle, m₂ = ?
a) Since, [tex]F_{1}=F_{2}[/tex]
∴ [tex]m_{1}a_{1} = m_{2}a_{2}[/tex]
mass of second particle-[tex]m_{2}[/tex] =[tex]\frac{m_{1}\times a_{1}}{a_{2}}[/tex]
= [tex]\frac{6.3\times10^{-7}\times7.0}{9.0}[/tex]
=4.9 × [tex]10^{-7}[/tex]Kg
b)As, [tex]F_{1} = F_{2}[/tex]
= [tex]\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}[/tex] = [tex]m_{1}a_{1}[/tex]
= 6.3 × [tex]10^{-7} \times[/tex] 7.0
= 44.1 × [tex]10^{-7}[/tex]
∴ q = 7.1 × [tex]10^{-11}[/tex]C.
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A net force pushing a 15 kg wagon on a level road results in an acceleration of 2 m/s².
What is the net force?
Answer:
30N
Explanation:
As we know that ,
Force = mass * acceleration
so substitute the respective values,
F = 15kg * 2m/s²
F = 30N
and we are done!
is a=f/m = 10000/50000 does it equal 0.2 ms to the power of -2
Yes, a=f/m where a is the acceleration, f is the force, and m is the mass of an object, a=0.2m/s^2
According to Newton's 2nd law of motion, According to this law, the rate of change of linear momentum of a body is directly proportional to the external force applied on the body, and this change takes place always in the direction of the force applied. In simple terms, it means that a larger force will change the momentum of an object more quickly as compared to a smaller force.
Mathematically, we can write
F∝ dp/dT
where p is the momentum
F∝ (mv-mu)/t₂-t₁
where v is the final velocity and u is the initial velocity
Now, F∝{m(v-u)}/(t₂-t₁)
F∝ma [∵ a=(v-u)/t]
F=kma
∴ when k=1
F=ma
Now according to this question,
f=10,000 N and m=50,000kg
By applying the formula,
F=ma
10,000=50,000*a
∴ a= 10,000÷50,000
a=0.2 or 2×10⁻¹ m/s²
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The particles leave a trail behind them as they move. The longer the trail, the faster that the particle is moving. During any up-and-down cycle of the particle, describe the speed. At what point during its motion does it move with the greatest speed AND smallest speed?
The particles leave a trail behind them as they move. The longer the trail, the faster that the particle is moving. During any up-and-down cycle of the particle, describe the speed. It moves with the greatest speed AND smallest speed when there is a change in the direction.
What speed?The speed of an object is described as the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time;
Speed is a scalar quantity.
The particle will move faster when there is a change in the direction on the movement of the particle.
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What is the equivalent resistance of a number of identical resistances (n), each of resistance (R), when
connected in series?
1)nR
2)R/n
3)n/R
4)n*2R
Answer:
Explanation: It's R/n
a transverse wave travels along a rope describe how the particles of the Rope move relative to the direction of propagation of the wave
The wave itself, that is, the crests and troughs, will move along the direction of propagation, but the particles themselves will only move perpendicularly to it.
How does a transverse wave rope move?
A wave in which the displacement of the medium's particles is perpendicular to the direction of energy transfer is called a transverse wave. If a rope is stretched out horizontally and the end is vibrated back and forth vertically, a transverse wave can be produced in the rope.
Transverse wave propagation is only feasible via solids; it is not possible in liquids or gases. Only transverse waves can display the polarization phenomena. The plane of vibration or polarization is the location where all of the particle vibration in a medium occurs. Shaking the rope causes the rope's constituent parts to oscillate, which causes the wave to advance or retreat from the energy source. The rope moves at a straight angle—or perpendicular—to the direction that the wave moves.
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A hot-air balloon takes off from the ground traveling vertically with a constant upward acceleration of magni- tude g/4. After time interval ∆t, a crew member releases a ballast sandbag from the basket attached to the balloon. How many seconds does it take the sandbag to reach the ground?
The time it takes for the sandbag to reach the ground would depend on the height from which it was released. The value is calculated to be t = √(2 s/(3g/4)).
To find out how long it takes for the sandbag to reach the ground, we can use the equation of motion for a vertically falling object under the influence of gravity:
s = v₀ t + (1/2) g t²
where s is the distance fallen, v₀ is the initial velocity (which is 0 m/s for the sandbag), t is the time elapsed, and g is the acceleration due to gravity (approximately 9.8 m/s²).
We know that the sandbag is being released from the balloon and has an upward acceleration of g/4. So, the equation of motion becomes
s = v₀ t + (1/2)(g - g/4) t²
We also know that s is the distance fallen to the ground, which we can take as the final distance.
Now solving the equation for t, t = √(2 s/(g - g/4))
It is given that the magnitude of the upward acceleration is g/4, so (g - g/4) = 3g/4, so the final equation becomes t = √(2 s/(3g/4))
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An elevator cab is pulled upward by a cable. The cab and its single occupant have a combined mass of 1450 kg. When that occupant drops a coin, the tension in the cable is 12. 0 kN. What is the acceleration of the coin relative to the cab
The cable will be under 12.0 KN of tension when that person drops a coin. Then the acceleration of the coin relative to the cab is 0.00828 m/s^2.
To find the acceleration of the coin relative to the cab, we can use the equation for tension force:
Tension force = mass x acceleration
We are given the tension force (12.0 kN) and the combined mass of the cab and its occupant (1450 kg). Therefore, we can solve for acceleration:
12.0 kN = (1450 kg) x acceleration
acceleration = 12.0 kN / (1450 kg)
acceleration = 0.00828 m/s^2
So the acceleration of the coin relative to the cab is 0.00828 m/s^2
It is worth noting that the coin will fall with respect to the elevator with an acceleration of 9.8 m/s^2 (upwards) but relative to the elevator, the coin is accelerating downwards with 9.8 m/s^2 + 0.00828 m/s^2 = 9.80828 m/s^2.
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b On the Moon, the lunar module has a weight of 24 800 N
Calculate the Moon's gravitational field strength.
Give your answer correct to two significant figures.
N/kg
As we do not have the mass we can not give you the gravitational field strength, but you can find it out by measuring the mass of the lunar module and use the formula above.
What is the gravitational field?Generally, To calculate the gravitational field strength on the Moon, we need to divide the weight of the lunar module (in newtons) by its mass (in kilograms).
We do not have the mass of the lunar module, however we know that the weight is equal to the force of gravity acting on it. The weight is force, which is measured in newtons.
Weight = Mass * gravitational field strength (g)
g = Weight / Mass
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CQ not found
Within 4. 0 s of liftoff, a spacecraft that is uniformly
accelerating straight upward from rest reaches an altitude
of 4. 50 X 102 m [up).
(a) What is the spacecraft's acceleration?
The spacecraft's acceleration can be found using the equation: a = (v-u)/t = 4.50 x 10^2 m / 4.0 s = 11.25 m/s^2.
Can you explain the concept of uniformly accelerating motion?Uniformly accelerating motion refers to an object that is moving at a constant rate of acceleration. This means that the velocity of the object is changing at a constant rate, but the acceleration remains the same throughout the motion. An example of this type of motion is an object that is accelerating from rest at a constant rate. The motion of the object can be described mathematically by the equations of motion, such as distance = initial velocity * time + 1/2 * acceleration * time^2. The graph of uniformly accelerating motion is a parabola, with velocity on the y-axis and time on the x-axis. This type of motion is different from non-uniform acceleration, where the acceleration changes during the motion.
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A spacecraft that is uniformly accelerating straight upward from rest reaches an altitude of 4. 50 X 102 m [up) with acceleration of 11.25 m/s².
Evaluating :The spacecraft's acceleration can be found using the equation:
a = (v-u)/t
= 4.50 x 10² m / 4.0 s
= 11.25 m/s².
Uniformly accelerating motion :Uniformly accelerating motion refers to an object that is moving at a constant rate of acceleration. This means that the velocity of the object is changing at a constant rate, but the acceleration remains the same throughout the motion. An example of this type of motion is an object that is accelerating from rest at a constant rate.
The motion of the object can be described mathematically by the equations of motion, such as distance = initial velocity × time + 1/2 * acceleration × time². The graph of uniformly accelerating motion is a parabola, with velocity on the y-axis and time on the x-axis. This type of motion is different from non-uniform acceleration, where the acceleration changes during the motion.
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a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.
It is 1.93 metres away from the post.
for vertical motion
[tex]S= u t + \frac{1}{2} g t^{2}[/tex]
S = 0 + [tex]\frac{1}{2} g t^{2}[/tex]
1.7 = [tex]\frac{1}{2} 9.8 t^{2}[/tex]
t = 0.589 sec
using law of conservation of momentum, on the horizontal motion
[tex]m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}[/tex]
[tex]0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}[/tex]
[tex]v_{tin}[/tex] = 3.273 m/s
S = [tex]v_{tin} \ t[/tex]
= 3.273 m/s * 0.589 s
= 1.93 m
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a pendulum has a period of 1.04 seconds on earth. what is its period on mars, where the acceleration of gravity is about 0.37 that on earth? give the answer in seconds, to 2 decimal places.
Period of the pendulum on Mars is 1.84 seconds (rounded to 2 decimal places).
What is period of a pendulum?Period of any pendulum is the distance from the pivot to center of oscillation.
The period of a pendulum, T:
T = 2 * pi * sqrt(L/g); L is length of pendulum and g is acceleration due to gravity.
On Earth, period of the pendulum is 1.04 seconds. To find the period on Mars, we can use fact that the acceleration due to gravity is 0.37 times that on Earth:
g_mars = 0.37 * g_earth
T_mars = 2 * pi * sqrt(L/g_mars)
Now we know ; T_mars = T_earth * sqrt(g_earth/g_mars)
T_mars = 1.04 * sqrt(1/0.37) = 1.04 * 1.76 = 1.8368 s
Therefore, the period of the pendulum on Mars is 1.84 seconds (rounded to 2 decimal places).
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a thermometer is taken from a room where the temperature is to the outdoors, where the temperature is . after one minute the thermometer reads . (a) what will the reading on the thermometer be after more minutes?
The reading on the thermometer after more minutes will depend on the rate at which the temperature of the room and the outdoors change.
What is thermometer?A thermometer is a device used for measuring temperature. It consists of a hollow tube made of glass that is filled with a liquid, such as mercury or alcohol, and a scale. When the temperature changes, the liquid expands or contracts, causing the scale to indicate the temperature.
If the temperature of the room and the outdoors remain relatively constant, then the reading on the thermometer after more minutes would likely be the same as the reading after one minute. However, if the temperature of the room or the outdoors changes faster than the other, then the reading on the thermometer after more minutes will be different from the reading after one minute.
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A soccer player kicks a ball moving in a straight line
towards the field goal, causing it to accelerate into the field
goal.
O Negative work is done on the ball.
Positive work is done on the ball.
O No work was done on the ball.
O Negative work was done on the field.
When the force applied on the ball causes it o accelerate into the field
goal, Positive work is done on the ball.
option B.
What is work done?
A work is said to be done when an applied force causes a displacement of an object.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the applied forced is the displacement of the objectThus, when a soccer player kicks a ball moving in a straight line
towards the field goal, causing it to accelerate into the field goal, the work done on the ball is a Positive work.
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when an object reaches terminal velocity its acceleration is
When an object reaches terminal velocity its acceleration becomes zero.
Terminal velocity is also called constant velocity. When there is no acceleration in the moving object. We can take the example of sedimentation.
Sedimentation is the process of settling down the soil particles at the bottom of the water. When soil particles comes down in water there are three forces which act on the particles. Downward force is weight of the particle. Upward force buoyant force of the water, and drag force. When upward forces become equal to the downward force then particles begins to settle down with a constant velocity. which is called terminal velocity.
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How is the electrostatic force (Felect) related to the separation distance (d) the two charges? Keeping the magnitude of charge on both objects constant, conduct a systematic study to collect data relating separation distance to force. The separation distance is defined as the distance between the centers of the two objects; the best strategy involves centering the objects on a gridline and using distances that are a whole number of squares.
Make a claim describing the relationship between Felect and d. Support your claim with evidence (references to the data) and reasoning
Allow two positive charges. Cuban and American two were distantly separated B. Cubans also use force against one another. This is also cute. Thus, the force will be equal to Q1 + Q2 + R^2.
More on electrostatic force and two charges :A characteristic of matter that affects how much force an object experiences when exposed to an electromagnetic field. A substance's charge might be positive, negative, or neutral. Total electric charge is conserved and cannot be created or destroyed, much as energy and matter.
Coulomb's constant, often known as the electric force constant, has a value of
K= [tex]\begin{equation*} 9\times10^9 \end{equation*}[/tex] [tex]\begin{equation*} \frac{Nm^2}{C^2} \end{equation*}[/tex]
Electrostatic force formula
[tex]\begin{equation*} \left|F_{E} \right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
[tex]F_{E}[/tex] is a electric force [tex]q_{1}[/tex] and [tex]q_{2}[/tex] is electric charge in coulomb K is constant, r is the distance between the charges
The magnitude of the electric force between [tex]q_{1}[/tex] and [tex]q_{2}[/tex]
Directly proportional to the size of the charges and inversely proportional to the square of the distance between them is the formula q, start subscript, 2, end subscript. The name of this equation is Coulomb's Law.
Comparing electric force and gravitational force with Newton's law of gravitation:
[tex]\begin{equation*} \left|F_E\right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
[tex]\begin{equation*} \left|F_G\right|=K\left|\frac{q_1q_2}{r^2}\right| \end{equation*}[/tex]
Similar to how gravitational force grows in strength with mass, electric force grows in strength with the size of the charges. Along the fictitious line connecting the items, both forces operate. The inverse-square law states that both forces are inversely proportional to the square of the distance between the objects. Additionally, both forces have constants of proportionality.
The relative intensities of gravitational and electric forces, which are determined by the ratio of K to G, are a disparity between them. The gravitational force between an electron and a proton is much smaller than the electrostatic force between them by several orders of magnitude.
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In a 24 s interval, 228 hailstones strike a glass
window of area 0. 788 mº at an angle 20° to the
window surface. Each hailstone has a mass of
4g and speed of 8. 3 m/s.
If the collisions are elastic, find the average
force on the window.
Angwar in units of N.
The average force acting on a given area is 21.98 Pa.
What is force?A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.
Here,
Force = Mass X acceleration = 0.004kg x 9.8. This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.004kg x 9.8 x sin20= 0.005kg x 9.8 x 0.707= 0.0357N.
Therefore, total force for the 500 hailstones would be 500x0.0357N=17.85N
This force is acting on an area equal to 0.788m2
Pressure = Force per unit area = 17.32N/0.788m2 = 21.98Pa
The force is acting on an area known as average force is 21.98 Pa.
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