true or false
a)we should play inside our classroom..........
b)curd is made from milk........
c) wa.........t.............​

Answer:

Explanation:

weather pattern

A pattern of weather over three months is called a climate.

Climate is the long-term pattern of weather in a particular area. Weather can change from hour-to-hour, day-to-day, month-to-month or even year-to-year. A region's weather patterns, usually tracked for at least 30 years, are considered its climate.

Weather refers to short-term changes in the atmosphere, climate describes what the weather is like over a long period of time in a specific area.

A pattern of weather over three months is called a climate.

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Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

The following equations apply to proportionally changes circular motion:

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

Or

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

So :

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current

Answer:

So where's the problem now?

A kitten is just sitting

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

Generally, the equation for the  initial electric field intensity   is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

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Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

  Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

The potential energy that can be stored = ke^2 / 2

where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

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First normal transportation is the light energy of sun is transmitted to our earth .

Next for transportation inside sun they are

Fusion means when two hydrogen atoms reacts to form helium nucleus .

Fission means when one nucleus is broken into two or more nucleus

Explanation:

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A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.

The bias present in the survey may lead to error in the result obtained from the random sampling survey.

One of the likely source of bias in the survey is undercoverage.

It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.

Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.

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Answer:

B. Question wording bias may be present because the question leads those responding toward a certain response.

Explanation:

Hi there!

We can use the angular equivalent of the following kinematic equation:

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]

ωf = final angular velocity (1.9 rad/s)

ωi = initial angular velocity (11.3 rad/s)

α = angular acceleration (? rad/s²)

θ = angular displacement (17.95 rad)

We can rearrange the equation to solve for angular acceleration.

[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]

Plug in the given values and solve.

[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]

Answer:

Both are aquatic animals and are hunters

Explanation:

Answer:

i think its 100

Explanation:

For  a lawnmower that produces noise at a level of 91.0 dB,  the intensity of this sound is mathematically given as

I=1.26*10^-3W/m^2

Generally, the equation for the sound   is mathematically given as

B=(10dB)log10(1/1_0)

Therefore

91/10=log(I/10^{-12})

I=1.26*10^-3W/m^2

In conclusion, the intensity

I=1.26*10^-3W/m^2

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For a rock is suspended from the lower end of a light string,  the weight of the rock is mathematically given as

W = 3.10 N

Generally, the equation for the W = Fh1+  is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

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Answer:

42

Explanation:

P = M × V

so

P = 35 × 1.2

P = 42

Answer:

42kg•m/s

Explanation:

p=m*v

Answer:

1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

Answer:

a parachute falling to the ground is uniform

Answer:

Explanation:

When the balls meets, the time should be the same, let say t.

For the first ball (released from a loom):

[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)

So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]

For the second ball (which is thrown directly upwards):

[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]

Because the height of the loom is h :

[tex]h=\bar{h}+y[/tex]

[tex]h=25t[/tex]

So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y

The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

Power can be deifned as the rate at which work is done.

To calculate the power delivered to the truck, we use the formula below.

Formula:

Where:

From the question,

Given:

Subsitute these values into equation 1

Hence, The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

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coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      ..................1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

Answer:

50 cubic cm

Explanation:

As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.

The force of gravity of the sun on Earth is a large force, and it can be represented by a longer arrow.

The force of gravity of the sun on Earth is determined using the following formula.

F = mg

where;

F = 5.97 x 10²⁴ x  9.8

F = 5.85 x 10²⁵ N

Thus, the force of gravity of the sun on Earth is a large force, and it can be represented by a longer arrow.

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Answer:

Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.

Explanation:

pa follow po

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

Answer:

180 m amp

Explanation:

V = IR

v/r = i     mutiply both sides by

3

3v / r = 3 i     so the current will triple to 180 mAmp

Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

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Answer:

As mass increases, the acceleration of an object decreases because more force is required.

Explanation:

The question states that the student made a mass acceleration graph with the force being constant, if you think about this in everyday life, would pushing a 30 kg box be easier than that of a 15 kg box? Obviously not because if you have the same force for both of them the 15 kg box would have a greater acceleration than the 30 kg one (assuming they are on the same surfaces and the same amount of force is applied.)

Therefore we can say that as the mass of an object increases the acceleration must decrease because we need more force to push the object.