Tutoring ABC charges $50 sign up fee plus $12 an hour . HW helps charge a $38 sign up fee plus $15 an hour . After how many hours will the total for each company be the same​

Answers

Answer 1

Answer:

Step-by-step explanation:

Tutoring ABC - $50 sign up and $12 an hour

HW helps- $38 sign up and $15 an hour

 50                                    38

+12                                    +15

62                                     53

+12                                   +15

74                                     68                        Four months

+12                                  + 15

86                                     83

+12                                   +15

98                                    98


Related Questions

Kai can wrap 42 gifts in 3 hours. Answer the following questions, assuming that Kai can continue wrapping gifts at that same rate. How many gifts can Kai wrap in 24 hours? _______________ How many hours would it take him to wrap 126 gifts? _______________ How many gifts does Kai wrap per hour? _______________

Answers

Answer:

1. 336

2. 9

3. 14

Step-by-step explanation:

He wraps 42 gifts/3hours

24 hours is 8 "3 hours"

42 hours per 3 gifts * 8 "3 hours" = 336 gifts

126 gifts is 3 "42 gifts"

3 hours per 42 gifts * 3 "42 gifts" = 9 hours

He wraps 42 gifts/3hours

divide these values by 3 and you get  14 gifts/one hour

14 gifts every one hour

Please Help!!! I'll Give Best And Brainliest if it lets me!

Answers

Answer:

6

Step-by-step explanation:

this is the answer. have a great day.

6 is this answer, hope this help

Given that T=KX/Y,find the percentage increase in T when k, xandy all increase by 20%​

Answers

Answer:

The percentage increase in [tex]T[/tex] is 20 %.

Step-by-step explanation:

Let be [tex]T = \frac{k\cdot x}{y}[/tex], whose initial parameters are [tex]k = k_{o}[/tex], [tex]x = x_{o}[/tex] and [tex]y = y_{o}[/tex]. If these three parameters are increased by 20 %, then initial and final values of [tex]T[/tex] are, respectively:

Initial value

[tex]T_{i} = \frac{k_{o}\cdot x_{o}}{y_{o}}[/tex] (1)

Final value

[tex]T_{ii} = \frac{(1.2\cdot k_{o})\cdot (1.2\cdot x_{o})}{1.2\cdot y_{o}}[/tex]

[tex]T_{ii} = \frac{1.2\cdot k_{o}\cdot x_{o}}{y_{o}}[/tex] (2)

(1) in (2):

[tex]T_{ii} = 1.2\cdot T_{i}[/tex]

And the percentage increase in T is:

[tex]\%T = \frac{T_{ii}-T_{i}}{T_{i}}\times 100\,\%[/tex] (3)

[tex]\%T = \frac{1.2\cdot T_{i}-T_{i}}{T_{i}}\times 100\,\%[/tex]

[tex]\%T = 20\,\%[/tex]

The percentage increase in [tex]T[/tex] is 20 %.

Answer:

Step-by-step explanation:

Lets subsitute k, x and y as  100 to make it easier for us

So k = 100, x = 100, y = 100

Step 1 :-   T = kx/y

- T = 100 * 100 / 100 = 100

Step 2 :- Increase by 20% = 100 * 20% = 20,    100 + 20 = 120

Step 3 :- Percentage Increase = Increased value OVER original calue          MULTIPLIED by 100%

SO = ( 120 - 100 ) ,,,,   20/100 * 100% = 0.2* 100 = 20%

y∝1√x
If
y=7 when x=64
find,
x when y=8

Answers

Answer:

uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math

Step-by-step explanation:

Suppose lightning strikes at an average of 1.4 strikes per minute during a particular storm. You play the following game: if the next strike occurs within the next minute, you win 3 dollars, if the next strike occurs between 1 minute and 2 minutes from now, you win 5 dollars, and if the next strike occurs more than 2 minutes from now, you win 1 dollar. How much should someone be charged to play this game, to make it a "fair game?"

Answers

Answer:

$3.25

Step-by-step explanation:

Given that:

Mean, λ = 1.4

Strike within next minute = $3 won

Strike between one and 2 minutes = $5

Strike more than 2 minutes = $1

Probability that next strike occurs within the next minute :

Using poisson :

P(x < 1) = 1 - e^-(λx) ;

P(x < 1) = 1 - e^-(1.4*1) = 1 - e^-1.4

P(x < 1) = 1 - 0.2465969

P(x < 1) = 0.7534030

Next strike occurs between 1 and 2 minutes :

(1 < x < 2) :

P(x < 2) - P(x < 1)

P(x < 2) = 1 - e^-(λx) ;

P(x < 2) = 1 - e^-(1.4*2) = 1 - e^-2.8

P(x < 2) = 1 - 0.0608100

P(x < 2) = 0.9391899

P(x < 2) - P(x < 1)

0.9391899 - 0.7534030 = 0.1857869

P(striking after 2 minutes)

P(x > 2) = e^-(λx) ;

P(x > 2) = e^-(1.4*2) = e^-2.8

P(x > 2) = 0.0608100

Amount charged :

(0.7534030 * 3) + (0.1857869 * 5) + (0.06081 * 1)

= 3.2499

= $3.25

If 3 students eat 2 pizzas how many pizzas are needed for 54 students

Answers

Answer:

18 pizzas

Step-by-step explanation:

i will love you if u please answer this question PLSS

Answers

Answer:

On the dive boat deck

Step-by-step explanation:

This is above the water level and water level is considered to be 0

pls love me <3

What value of y makes the equation 3y+ 9 = 36 true?

Answers

Answer:

y=9

Step-by-step explanation:

what is the area of the triangle 10,24,26

Answers

Step-by-step explanation:

i d like to help but i fon knoeww

In a class of 30 students 16 have a cat and 15 have a dog there are 11 students who have a cat and a dog what is the probability that a student has a dog given they do not have a cat?

Answers

so we know 11 have cats and dogs and 15 have dogs so do 15-11=4 and divide that by all the students which is 30 and get 13.3%

The probability that a student has a dog given they do not have a cat is 0.1333.

What is probability?

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Total number of students = 30

[tex]n(s)=30[/tex]

Number of students have cat = 16

Number of students have dog = 15

Number of students have a cat and a dog = 11

The event is the probability that a student has a dog given they do not have a cat,

[tex]n(e)=15-11[/tex]

⇒ [tex]4[/tex]

Thus the probability that a student has a dog given they do not have a cat is

⇒ [tex]P(e)=\frac{n(e)}{n(s)}[/tex]

⇒ [tex]P(e)=\frac{4}{30}[/tex]

⇒ [tex]P(e)=0.1333[/tex]

Hence we can conclude that the probability that a student has a dog given they do not have a cat is 0.1333.

Learn more about probability here

https://brainly.com/question/16484393

#SPJ2

On a youth soccer team 3 out of 12 team members have played in previous years. Based on this information, if 150 kids are in the youth soccer league, then how many could be expected to have played the year before?​

Answers

Yes i also believe 30 is the answer

1. Los estudiantes de primer grado de la IE Miguel Grau son 184, si la relación entre los que usan anteojos y los que no usan es de 3/5. ¿Cuántos estudiantes usan anteojos?

Answers

Answer:

69 estudiantes.

Step-by-step explanation:

Sabemos que el número total de estudiantes en primer grado es 184.

También sabemos que la relación entre los que usan anteojos y los que no es 3/5.

Esta relación es igual al cociente entre el número de estudiantes que usan anteojos y el número de estudiantes que no usan anteojos.

Si definimos las variables:

A = número de estudiantes que usa anteojos

B = número de estudiantes que no usa anteojos.

Tenemos la relación:

A/B = 3/5

podemos reescribir como:

A = (3/5)*B

Y también sabemos que el número total de estudiantes es 184, entonces tendríamos que:

A + B = 184.

Podemos aislar B en esta segunda ecuación para luego reemplazarlo en la primera.

Aislando B obtenemos:

B = 184 - A

Si reemplazamos esto en la otra ecuación obtenemos:

A = (3/5)*B

A = (3/5)*(184 - A)

Ahora podemos resolver esto para A.

A = (3/5)*184 - (3/5)*A

A + (3/5)*A = (3/5)*184

A*(1 + 3/5) = (3/5)*184

A*(5/5 + 3/5) = (3/5)*184

A*(8/5) = (3/5)*184

A = (5/8)*(3/5)*184

A = 69

Podemos concluir que 69 estudiantes usan anteojos.

Trying to help my daughter can't figure this out.

The perimeter of a rectangle is 72 meters. The width of the rectangle is 4meters less than the length. Find the length and width of the rectangle. (use l for the length)​

Answers

Answer:

width equals 16

length = 20

Step-by-step explanation:

Hello there!

we know that the perimeter is 72 m

and the width is 4 m less then the length

perimeter is 2w+2l

w=width and l = length

72 + (2x-4) = 72+8 = 80

80 / 4 (because there are 4 values, w, w, l, l ) = 20

so now...

20 - 4 = w

16 = w

and 20 = l

16+16 = 32

20+20 = 40

32+40 = 72

the perimeter of a rectangle is 58m if its length is 17m find its breadth​
pls help its urgent

Answers

perimeter of rectangle=2(l+b)
58=2*17+2*b
58-34=2b
b=12 m

2. which formula should be used to find the area of the composite shape? A = 4(1/2Xbh) lw B. A=4bh+lw C. a=4bh+lw d. 2bh+bh Please select all that apply.

Answers

Answer: the answer is B and D I told the test

Step-by-step explanation:

i know mia is right but what’s the explaining?

Answers

Answer:

Just explain why you chose mia..

Step-by-step explanation: Why do you think mias right?

Answer:

Mia is right

Step-by-step explanation:

But the reason is because y=4+6x mark is going over the line and he needs to make sure its accross.

Simplify the expression:
​P + 7p + 5p

P = ?

A. 13p
B. 13
C. 16p
D. 16

Answers

The answer Is A. 13p hope it helps

Find the area of the shaded polygons



Answers

Explanation is in a file

Answer:

4 sq un

Step-by-step explanation:

72 is 40% of what number? A. 18 B. 144 C. 180 D. 280

Answers

Answer:180(D)

Step-by-step explanation: First, do 72/x=40/100. Then, cross muliply which is 7200 and 40*x. do 7200/40. The answer should be 180.

Answer:

The answer is C(180) on edg 2021

WILL MARK BRAINLEST
You want to estimate how many fish there are in a pond. Suppose you cature 145 fish, tag them, and throw them back into the pond. After a couple of days, you go back to the pond and capture 580 fish, of which 29 are tagged.

An estimate for the number of fish in the pond is
fish

Answers

Answer:

450fish estimate

Step-by-step explanation:

I need help please!!

Answers

Answer:

3 1/4 + 4 2/5 + 6 1/2 = 14.15 hours

Step-by-step explanation:

When the sum of a number and 14 is
divided by 3, the result is 4.

Answers

Answer:

it is 4.6 sorry girl

Step-by-step explanation:

Answer:

Step-by-step explanation:

4.6=4 3/5=23/5

Please help me with number 6

Answers

x-4=y so when x is 40 then y will be 36
It’s gonna be 36 I think

21 divided by 4 equals 5 1/4

Answers

Answer:

yes

Step-by-step explanation:

Will mark brainliest for any help!

Answers

Answer:

2) 523.3 in²

Steps:

the given polygon is a heptagon

a regular heptagon's area = 7/4 × s² × cot(180°/7)

for the given heptagon

A = 7/4 × 12² × cot(180/7) ≈ 523.28 in² = 523.3 in² (rounded)

Plssss helppppppl:((((

Answers

Answer:

I think it's 1.5 I'm not sure ._.

Answer:

1/3

Step-by-step explanation:

Total students = 36

No of boys = 24

No of girls = 36 - 24 = 12

Probability of selecting a girl = 12/36 = 1/3

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Answers

Answer:

0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniformly distributed between 0 and 5 minutes.

This means that [tex]a = 0, b = 5[/tex]

Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

[tex]P(X > 4.25) = \frac{5 - 4.25}{5 - 0} = 0.15[/tex]

0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Quadrilateral ABCD at A(-2,2),B(-2,4),C(2,4), and D(2,2). The quadrilateral is then transformed using the rule(x-2,y+8) to form the image A'B'C'D'. What are the new coordinates of A',B',C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

Answers

A(-4,10), B(-4,12), C(0,12), D(0,10). The shape will be exactly the same, just translated.

Leon older brother is 4 and 3/4 feet tall Leon is 1/3 foot shorter than his brother how tall is Leon

Answers

Answer:

4 5/12 feet tall

Step-by-step explanation:

All you have to do is subtract 1/3 from 4 and 3/4 in order to get this answer.

Answer:

Leon is 53/12 feet or 4 & 5/12 or 4.4167 (same answer different forms)

Step-by-step explanation:

Leon older brother is 19/4 feet tall or 57/12.

Leon is 1/3 or 4/12 foot shorter than his brother.

57/12-4/12= 53/12

Following are weights, in pounds, of two-month-old baby girls. It is reasonable to assume that the population is approximately normal.

12.32 11.87 12.34 11.48 12.66
8.51 14.13 12.95 9.34 8.63

Required:
a. Construct a interval for the mean weight of two-month-old baby girls.
b. According to the National Health Statistics Reports, the mean weight of two—month-old baby boys is 13.9 pounds. Based on the confidence interval, is it reasonable to believe that the mean weight of two-month—old baby girls may be the same as that of two-month-old baby boys? Explain.

Answers

Answer:

10.224 < μ < 12.622 ;

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

Step-by-step explanation:

The confidence interval is given as :

Mean ± Margin of Error

margin of error = Zcritical * standard deviation /sqrt(n)

n = sample size

From the data:

12.32, 11.87, 12.34, 11.48, 12.66, 8.51, 14.13, 12.95, 9.34, 8.63

From the data:

Using calculator :

Mean, = 11.423

Standard deviation, s = 1.934

Zcritical at 95% confidence interval = 1.96

Sample size, n = 10

Margin of Error = 1.96* 1.934/sqrt(10) = 1.199

Lower boundary = 11.423 - 1.199 = 10.224

Upper boundary = 11.423 + 1.199 = 12.622

10.224 < μ < 12.622

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

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