The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
Total mass of the twins and the car = 300 Kg
Initial velocity of the twins car = 10 m/s
Total mass of Melinda and her car = 125 Kg
Initial velocity of Melinda's car = 0 m/s (at rest)
Final velocity of the twins car = 4.12 m/s
Final velocity of Melinda's car = ?
Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1
Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1
Using the principle of conservation of linear momentum;
Total momentum before collision = Total momentum after collision
m1u1 + m2u2 = m2v1 + m2v2
(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)
3000 = 1236 + 125x
x = 3000 - 1236 /125
x = 14 ms-1
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
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A multi-dimensional being reaches down to Earth and pulls you out of the universe. You are then thrown back into the universe at a place and time of the being's choosing, and you are permitted to leave only after you have identified your surroundings. This process is repeated several times. Through a scientifically unexplainable miracle, you are able to survive in every one of the places that you find yourself. In each scenario below, identify your surroundings (and potentially your cosmic era) from among the choices given. You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe.
Required:
Where are you?
You are in an early universe.
In the study of the evolution of the universe, it has been determined before Plank time (before the big bang and right after it), the early universe had the following characteristics:
There was only one single force acting over all that existed.The early universe was very hot and dense because all matter had contracted before the big bang.Space and time were wrapped.These characteristics match the ones described, based on this, we can conclude you are in an early universe.
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pls help it's due today
Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
A mass is pulled to the right while on a table.
A. Label the forces.
5 kg
B. Calculate the
object's weight.
Answer:
weight in 49N
I hope it's correct
how does the function of the parts of the system contribute to its function as a whole
plsss help i need it rn i’ll give brainliest
I'll give brainlest
*the first pic is for Alberto and second for the mouse*
Question 1
Alberto created a graph to illustrate his trip. Answer the questions below.
A. How does Alberto's motion change at point B?
B. What is Alberto's speed from point C to point D?
C. What happens at point D? (1 point)
Question 2
Answer the question below about Smokey The Mouse.
A. Use inertia to explain how a balanced force will affect his motion. (Newton's 1st Law)
B. What are two ways Smoky can increase his speed? (Use Newton's 2nd Law to help you)
C. What is an example of an action and reaction at work in this picture? (Use Newton's 3rd Law to help you)
Answer:
The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.
According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.
From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;
Increasing the force acting on the mouse
Decreasing the mass of the mouse
Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
Explanation:
Which of these ALL require direction? Force, Time, Acceleration Displacement, Velocity, Force Mass, Time, Speed Speed, Velocity, Distance
PLS ANSWER QUICK!!!!
Answer:
force, acceleration, displacement, velocity requires direction
define Newton's law of motion
By definition, Newton's First Law, also called the Law of inertia, indicates that "Every body perseveres in its state of rest or of uniform rectilinear motion unless it is forced to change its state by forces impressed on it."
This means that for a body to come out of its state of rest or of uniform rectilinear motion, it is necessary for a force to act on it.
Definition of inertiaSo, in other words, all bodies are opposed to changing their state of rest or motion and this opposition is called inertia.
Body in equilibriumIn this way, a body is in equilibrium when the resultant of the forces acting on it is zero. That is, it is not possible for a body to change its initial state (be it rest or motion) unless one or more forces intervene.
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when is atmospheric pressure 1x10 to the power of 5 and when is it pgh
Answer:
1 atmospheris pressure is equal to10.33 meter under water
Explanation:
right ??
A plane flies from New York to LA at a constant speed of 800 km an hour how long will it take the plane to fly to 4,200 kilometers
Answer:
3.5 hours
Explanation:
What is the minimum number of overload units such as heaters, trip coils, or thermal cutouts allowed for a three-phase AC motor's protection
The minimum number of overload units for a three-phase AC motor's protection is THREE (3). It is a polyphase motor.
Three-phase motors are polyphase motors, which can be induction motors or synchronous motors.
A three-phase motor is organized to run on three-phase alternating current (AC) electrical power, which is required for diverse industrial devices that use a lot of electrical energy.
These motors (three-phase motor) are composed of a stator (the outer part), a rotor (rotating part), and the enclosure (the external skeleton).
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A pendulum has a mass of 3 kg and is lifted to a height of 0.3 m. What is the maximum speed of the pendulum
Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
Answer:
The gravitational force b) Increases with increase in mass.
Explanation:
The gravitational force between two objects is given by
F=G\frac{m_1 m_2}{r^2}F=Gr2m1m2
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
From the equation, we notice that:
- The force is proportional to the masses, m1 and m2: so, if the masses increase, the force will increase, and if the masses decrease, the force will decrease
- The force is inversely proportional to the distance between the masses, r: so, if the distance increases, the force will decreases, and if the distance decreases , the force will increases
Therefore, the correct options is only:
Increases with increase in mass
Answer: The answer is b increases in increase of mass because the heavier the object is the more gravitional pull it will have.
Explanation: Which of the following is true for gravitational force?
Group of answer choices
Decreases with decrease in distance
Increases with increase in distance
Decreases with increase in mass
Increases with increase in mass
Help please!
3. A 75 kg linebacker moving at 6 m/s is running towards an 80 kg tackle moving 4 m/s. If they collide and stick together, how fast will they be moving after the collision?
5. A 6 kg bowling ball and a 4 kg bowling ball are rolled toward each other. The 6 kg ball is initially moving at 5.1 m/s and the 4 kg ball is moving in the opposite direction at 1.3 m/s. If the 6 kg ball slows to 1.5 m/s, what is the final speed of the 4 kg ball?
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
Calculate the Work done if the force is 2000 Newtons
and the distance is 5 km.
Answer:
10 million joules or 10,000 KJ
Explanation:
Work= Force x Displacement
convert 5km into meters -5km=5000m
W= 2000N x 5000m
w=10,000,000 Joules
or 10,000KJ
a new planet is discovered that has twice the earth’s mass and twice the earth’s radius. on the surface of this new planet, a person who weighs 500 n on earth would experience a gravitational force of
Answer: 250n
Explanation:
The formula for gravitational force is: F = (gMm)/r^2
There are two factors at play here:
1) The mass of the planet 'M'
2) The radius 'r'
We can ignore the small M and the g, they are constants that do not alter the outcome of this question.
You can see that both M and r are double that of earth. So lets say earth has M=1 and r=1. Then, new planet would have M=2 and r=2. Let's sub these two sets into the equation:
Earth. F = M/r^2 = 1/1
New planet. F = M/r^2 = 2/4 = 1/2
So you can see that the force on the new planet is half of that felt on Earth.
The question tells us that the force on earth is 500n for this person, so then on the new planet it would be half! So, 250n!
How charged objects can affect other objects without touching them. ?
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
[tex]88.3ms {}^{ - 2} [/tex]
or 88.3m/s^2
Explanation:
Using suvat where we list everything that we are given
s=49m
u=0m/s
v=93m/s
a=?
t=we are not given this value, so we don't use
using a formula that doesn't involve time:
[tex]v {}^{2} = u {}^{2} + 2as[/tex]
rearranging to find acceleration by subtracting u^2 on both sides
[tex]v {}^{2} - u {}^{2} = 2as[/tex]
then dividing 2s on both sides
[tex] \frac{v {}^{2} - u {}^{2} }{2s} = a[/tex]
[tex] \frac{(93) {}^{2} - (0) {}^{2} }{2 \times(49) } = 88.3ms {}^{ - 2} [/tex]
so the acceleration is 88.3ms^-2 (1dp)
What is the equivalent resistance of a 12-ohm resistor wired in parallel with a 4-ohm resistor?
А
0.06 ohms
B
0.33 ohms
С
3.0 ohms
D
16.0 ohms
[tex]R=\frac{R1.R2}{R1+R2} = \frac{12.4}{12+4}=\frac{48}{16}=3<ohms>[/tex]
The answer is : C. 3.0 ohms
Ok done. Thank to me :>
A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.
Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.
A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is
A. 1350 J
B. 8820 J
C. 4410 J
D. 0 J
and his velocity is
E. 4.5 m/s
F. 0 m/s
G. 3.2 m/s
H. 9.9 m/s
Please help will mark brainliest
[tex]\\ \sf\longmapsto GPE=mgh[/tex]
[tex]\\ \sf\longmapsto GPE=90(5)(9.8)[/tex]
[tex]\\ \sf\longmapsto G PE=4410J[/tex]
Now
It's converted to kinetic energy while reaching ground.
[tex]\\ \sf\longmapsto K.E=4410[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]
[tex]\\ \sf\longmapsto 90v^2=8820[/tex]
[tex]\\ \sf\longmapsto v^2=98[/tex]
[tex]\\ \sf\longmapsto v=9.9m/s[/tex]
Done
Answer:
Hope it will help you a lot.
Change in inherited characteristics over time is called what?
Answer:
characteristics
Explanation:
Change in inherited characteristics over time is called what?Change in inherited characteristics over time is called what?Change iChange in inherited characteristics over time is called what?n inherited characteristics over time is called what?Change in inherited characteristics over time is called what?
Change in inherited characteristics over time is called what?Change in inherited characteristics over time is called what?Change in inherited characteristics over time is called what?
[tex] \color{blue}{ \sf lololololololol}[/tex]
Energy stores in food would be considered what
Answer:
Energy stored in food is consider as carbohydrate,protein,fats,etc.
Why does the size of a white dwarf affect its visual luminosity?
Answer:
A typical white dwarf has a carbon and oxygen mass similar to the Sun, but is much smaller in size (similar to the Earth). It is much hotter (25,000 K), but because of its small size its luminosity is low. ... Some very nearby white dwarf stars can be observed directly through telescopes, though they are extremely faint.
Explanation:
write down 4 situations where magnets are used in our daily life
Answer:
Magnets are used to make a tight seal on the doors to refrigerators and freezers
They power speakers in stereos, earphones, and televisions
Magnets are used to store data in computer's
magnets are used in the compass
If astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years, how long would its semi-major axis length be as it orbited the Sun in AU?
From Kepler's third law, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C
Given that an astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years.
According to Kepler's third law,
[tex]T^{2} \alpha r^{3}[/tex]
Where
T = Period ( in earth years) = time to complete one orbit
r = Length of the semi major axis in Astronomical unit.
[tex]T^{2}[/tex] = [tex]\frac{4\pi ^{2} }{GM} * r^{3}[/tex]
convert years to seconds
105 x 365 day x 24 hours x 3600 s
T = 3311280000 seconds
Mass of the sun M = 1.989 × 10^30 kg
G = 6.67 x [tex]10^{-11}[/tex]N m^2/kg^2
Substitute all the parameters into the formula
[tex]T^{2}[/tex] = 1.096 x [tex]10^{19}[/tex] = [tex]\frac{4\pi ^{2} }{6.67 * 10^{-11} * 1.989 * 10^{30} } * r^{3}[/tex]
1.096 x [tex]10^{19}[/tex] = 2.976 x [tex]10^{-19}[/tex] [tex]r^{3}[/tex]
[tex]r^{3}[/tex] = 1.096 x [tex]10^{19}[/tex] / 2.976 x [tex]10^{-19}[/tex]
[tex]r^{3}[/tex] = 3.68 x [tex]10^{37}[/tex]
r = [tex]\sqrt[3]{3.68 * 10^{37} }[/tex]
r = 3.33 x [tex]10^{12}[/tex] m
1 AU = 1.5 x [tex]10^{11}[/tex] m
r = 3.33 x [tex]10^{12}[/tex] / 1.5 x [tex]10^{11}[/tex]
r = 22.18 AU
Therefore, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C
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Answer:
C. 22.3 AU
Explanation:
Not only is the above an unnecessarily complicated answer, it's not even fully correct, and definitely not what they want you to do.
T^2 = s^3, where T = orbital period and s = semi-major axis length.
Substitute T and you get 105^2 = s^3. Solve for s.
11025 = s^3
3√11025 = s
22.25663649 = s
Therefore, the answer is C. 22.3 AU
Imagine that you are going to visit your friend. Before you get there, you decide to stop at the variety store. If you walk 200 m (N) from your home to the store, and then travel 600 m [S] to your friend's house, what is your total displacement?
Answer:
400m
Explanation:
Brainliest? :))
Let your initial displacement from your home to the store be
Dd
>
1 and your displacement from the store to your friend’s house
be Dd
>
2.
Given: Dd
>
1 = 200 m [N]; Dd
>
2 = 600 m [S]
Required: Dd
>
T
Analysis: Dd
>
T 5 Dd
>
1 1 Dd
>
2
Solution: Figure 6 shows the given vectors, with the tip of Dd
>
1
joined to the tail of Dd
>
2. The resultant vector Dd
>
T is drawn in red,
from the tail of Dd
>
1 to the tip of Dd
>
2. The direction of Dd
>
T is [S].
Dd
>
T measures 4 cm in length in Figure 6, so using the scale of
1 cm : 100 m, the actual magnitude of Dd
>
T is 400 m.
Statement: Relative to your starting point at your home, your
total displacement is 400 m [S].
What process primes a molecule to change in a way that increases its activity, produces motion, or does work
Answer:
cellular respiration.
explanation: cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.
a measure of change in velocity in a measure of time is
[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]
In simplified form
[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}[/tex]
The rate of change of velocity with respect to time period is called acceleration.SI units-m/s^2Solve the science problem
Answer:
1.hydrogen
2.helium
3. lithium
4.beryllium
5.boron
6.carbon
7.nitrogen
8.oxygen
9.fluorine
10.neon
Explain how energy changes in the spring toy below when it goes downstairs.
Given what we know, we can confirm that the spring toy uses the transfer of potential gravitational energy into kinetic energy of motion in order to fall down the stairs.
How does the toy do this?The toy stores potential energy. It does this using gravity. Once it begins to fall, it uses the momentum from each fall to continue to do so. With each fall, its stored potential energy is transferred to kinetic energy.Therefore, we can confirm that the spring toy uses its position at the top of each stair as a source of potential energy, which using the momentum from the last fall, it transfers into the kinetic energy of motion as it falls, all through the help of gravity.
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A 30 g mass is attached to one end of a 10-cm-long spring.
The other end of the spring is connected to a frictionless pivot on
a frictionless, horizontal surface. Spinning the mass around in a
circle at 90 rpm causes the spring to stretch to a length of 12 cm.
What is the value of the spring constant?
The value of the spring constant of the spring is 14.7 N/m.
The given parameters;
mass attached to the spring, m = 30 glength of the spring, L₀ = 10 cmangular speed of the mass = 90 rpmfinal length of the spring, L₁ = 12 cmThe extension of the spring is calculated as follows;
[tex]\Delta x = L_1 - L_0\\\\\Delta x = 12 \ cm - \ 10 \ cm\\\\\Delta x = 2 \ cm = 0.02 \ m[/tex]
The value of the spring constant of the spring is calculated by applying Hooke's law;
[tex]F = mg = k\Delta x\\\\k = \frac{mg}{\Delta x } \\\\k = \frac{0.03 \times 9.8}{0.02} \\\\k = 14.7 \ N/m[/tex]
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