Engineering High School

Two 40-ft long wires made of different materials are supported from the ceiling of a testing laboratory. Wire 1 is made of material H and has a diameter of 3/8 in. Wire 2 is made of material K and has a diameter of 3/16 in. When a load of 225 lb is applied to its lower end, wire 1 stretches 0.10 in. When the same 225 lb load is applied to the lower end of wire 2, wire 2 stretches 0.25 in. Compare materials H and K. Which material has the greater modulus of elasticity? Which is the stiffer material?

Answers

Answer 1

Answer:

Yes! I can help with.

Explanation:

To compare materials H and K, we need to determine the modulus of elasticity for each material. The modulus of elasticity is a measure of a material's stiffness, specifically the amount of stress required to produce a given amount of strain.

We can use the formula:

stress = force / area

strain = change in length / original length

modulus of elasticity = stress / strain

Let's start by calculating the stress on each wire:

For wire 1:

stress = force / area = (225 lb) / ((pi/4) * (3/8 in)^2) = 7,655 psi

For wire 2:

stress = force / area = (225 lb) / ((pi/4) * (3/16 in)^2) = 30,620 psi

Next, we can calculate the strain on each wire:

For wire 1:

strain = change in length / original length = 0.10 in / 480 in = 0.000208

For wire 2:

strain = change in length / original length = 0.25 in / 480 in = 0.000521

Finally, we can use the formula to calculate the modulus of elasticity for each material:

For material H:

modulus of elasticity = stress / strain = 7,655 psi / 0.000208 = 36,824,038 psi

For material K:

modulus of elasticity = stress / strain = 30,620 psi / 0.000521 = 58,745,334 psi

Therefore, material K has the greater modulus of elasticity and is the stiffer material.

Related Questions

A blocked drain on a pressure-reducing valve will
A) Result in no reduction of pressure
B) Prevent flow from the outlet of the valve
C) Block the inlet of the valve
D) Drop system pressure to zero

Answers

Answer:

Yes! I can Answer that!

Explanation:

C) Block the inlet of the valve.

A blocked drain on a pressure-reducing valve can prevent the valve from functioning correctly by blocking the drain line that is used to relieve excess pressure from the valve. As a result, the inlet of the valve can become blocked, causing the valve to malfunction and preventing it from reducing pressure. It is important to keep the drain line clear to ensure that the pressure-reducing valve works properly.

A 35-ft long solid steel rod is subjected to a load of 8,000 lb. This load causes the rod to stretch 0.266 in. The modulus of elasticity of the steel is 30,000,000 psi. Determine the diameter of the rod (precision of 0.00)

Answers

Answer:

The diameter of the rod can be determined using the following formula:

Explanation:

d = sqrt(4L / (pi * E * delta))

where:

d = diameter of the rod

L = length of the rod = 35 ft

E = modulus of elasticity of the steel = 30,000,000 psi

delta = elongation of the rod = 0.266 in

First, we need to convert the length of the rod and elongation to inches to maintain consistency with the units of E:

L = 35 ft * 12 in/ft = 420 in

delta = 0.266 in

Substituting the given values into the formula:

d = sqrt(4 * 420 / (pi * 30,000,000 * 0.266))

d = 0.615 in (rounded to 0.01)

Therefore, the diameter of the steel rod is 0.62 inches (rounded to 0.01).

Your load voltage and arc voltage measurement should be

Answers

Answer:

taken at the same time to ensure accurate results.

Explanation:

taken at the same time for get results
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