Answers
Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of
tan(θ) = 15.80 → θ ≈ 86.38°
The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of
∑ F = P - (M + m) g sin(θ) = (M + m) a
(see the attached free body diagram)
where
P = magnitude of the push
g = 9.80 m/s²
a = 2.53 m/s²
and M and m are the given masses.
Then the system requires a push of
P = (M + m) (a + g sin(θ))
P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
P ≈ 233 N
If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is
∑ F = T - M g sin(θ) = M a
where
T = tension in the rope
Then
T = M (a + g sin(θ))
T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
T ≈ 175 N
Related Questions
Two satellites are approaching the Earth from opposite directions. According to an observer on the Earth, satellite A is moving at a speed of 0.648c and satellite B at a speed of 0.795c. What is the speed of satellite A as observed from satellite B
Answers
Answer:
Explanation:
Satellite A and satellite B are approaching the earth from opposite directions , that means they are approaching each other . The velocity of satellite A and B are .648c and .795c respectively . Their velocities are comparable to velocity of light so they will follow relativistic laws .
Their relative velocity will be given by the following relation .
[tex]V_r=\frac{u+v}{1+\frac{uv}{c^2} } }[/tex]
where u and v are velocities of vehicles coming from opposite direction and c is velocity of light .
[tex]V_r=\frac{.795c+.648c}{1+\frac{.648c\times .795c}{c^2} } }[/tex]
[tex]V_r=\frac{1.443c}{1+.515 } }[/tex]
= .952c
Hlo
what is a force........??
Answers
Explanation:
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.
Formula
Newton's Second Law
F = m * a
F = force
m = mass of an object
a = acceleration
3N
3 N
What is the net force of the box?
Answers
The only force acting on a 3.1 kg canister that is moving in an xy plane has a magnitude of 5.0 N. The canister initially has a velocity of 4.4 m/s in the positive x direction and some time later has a velocity of 6.4 m/s in the positive y direction. How much work is done on the canister by the 5.0 N force during this time
Answers
Answer:
33.5J
Explanation:
Given:
Mass of the canister= 3.1 kg
Initial velocity of canister= v(i)= 4.4i m/s
Final velocity of canister= v(f)= 6.4j m/s
Force magnitude( xy plane)= 5 N
The magnitude of vector V'= Vxi + Vyj + Vzk
|V|= √( Vx^2 + Vy^2 + Vz^2
From Kinectic energy and work theorem.
Net work = Kinectic energy of the canister
ΔK= W
(Kf - Ki)= W
Where Kf= final Kinectic energy
= 1/2 mv^2
If we input the given values we have,
= 1/2 × 3.1 ×√(4.4^2 + 0^2 + 0^2)^2 = 30J
Ki= initial Kinectic energy
= 1/2 mv^2
If we substitute the given values we have
=1/2 × 3.1 ×√(0^2 + 6.4^2 + 0^2)^2 = 63.5 J
Work done by canister = (final Kinectic energy - initial energy)
= 63.5- 30
=33.5J
Hence, work done on the canister 33.5J
What is unusual about the material that Emily invented?
Answers
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
Hope it helps! Please mark brainliest.
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
A 10 kg remote control plane is flying at a height of 111 m. How much
potential energy does it have?
Answers
Answer:
10.88kJ
Explanation:
Given data
mass= 10kg
heigth= 111m
Applying
PE= mgh
assume g= 9.81m/s^2
substitute
PE= 10*9.81*111
PE=10889.1 Joules
PE=10.881kJ
Hence the potential energy is 10.88kJ
A racecar reaches 24 m/s in 6 seconds at the start of a race. What is the acceleration of the car?
Answers
Answer:
4m/s^2
Explanation:
Which characterictic of motion could change without changing the velocity of an object
Answers
Answer:
The direction could change
what Species can change over time to adapt to their environment
Answers
Answer:
Explanation:
Most environments have many niches. If a niche is "empty" (no organisms are occupying it), new species are likely to evolve to occupy it. This happens by the process of natural selection. By natural selection, the nature of the species gradually changes to become adapted to the niche.
Conservation of energy is explained as a scientific law and not a _______ because it does not explain why energy is conserved
Answers
Answer:
Theory
Explanation:
Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.
A law is a the statement of a scientific fact. It is a product of repeated experiment and observation through time. Most laws do not explain the reason for the logic behind their premise.
A theory on the other hand provides an explanation for an observed phenomenon. Most theories are no immutable. They are often changed when new finds are reported or made.
Laws are immutable and they stand still.
The sound from a trumpet travels at 351 m/s in the frequency of the note is 294 Hz, what is the wavelength of the sound wave?
Answers
Answer:
1.19m
Explanation:
Given parameters:
Speed of the trumpet sound = 351m/s
Frequency of the note = 294Hz
Unknown:
Wavelength of the sound = ?
Solution:
To solve this problem, we use the wave - velocity equation.
V = F x ∧
V is the velocity of the body
F is the frequency
∧ is the wavelength
So;
351 = 294 x ∧
∧ = [tex]\frac{351}{294}[/tex] = 1.19m
1.
Atennis ball is shot straight up with an initial velocity of 34 m/s. What is its velocity two seconds after launch?
Answers
Answer:
The speed (magnitude of the velocity) is 14.4 m/s
Explanation:
Vertical Launch Upwards
It occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.
If vo is the initial speed and g is the acceleration of gravity, the speed vf at any time is calculated by:
[tex]v_f=v_o-g.t[/tex]
A tennis ball is launched vertically up with an initial speed of vo=34 m/s. At time t=2 s, its speed is:
[tex]v_f=34-9.8*2[/tex]
[tex]v_f=34-19.6[/tex]
[tex]v_f=14.4\ m/s[/tex]
The speed (magnitude of the velocity) is 14.4 m/s
Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger D has a mass 4m and a speed v/2. Rank the joggers in order of increasing kinetic energy. Indicate ties when appropriate. Show your work.
Answers
Answer: B>A=D>C
Explanation:
Kinetic Energy is the product of mass and square of the velocity
For Jogger A
[tex]K.E._a=\frac{1}{2}mv^2[/tex]
For Jogger B
[tex]K.E._b=\frac{1}{2}\times\frac{m}{2}\times(3v)^2=\frac{9}{4}mv^2\\K.E._b=2.25mv^2[/tex]
For Jogger C
[tex]K.E._c=\frac{1}{2}\times3m\times(\frac{v}{2})^2=\frac{3}{8}mv^2\\K.E._c=0.375mv^2[/tex]
For Jogger D
[tex]K.E._d=\frac{1}{2}\times4m\times(\frac{v}{2})^2=\frac{1}{2}mv^2[/tex]
Kinetic Energy of Joggers in increasing order
B>A=D>C
Convert 20 C to F
-40 C to F
40C to F
Answers
2. -40 degrees fahrenheit
3. 104 degrees fahrenheit
Answer:
20 C to F
Ans: 68F
-40 C to F
Ans:-40F
40C to F
Ans:104F
Now complete your visual overview by identifying the known variables and the variables you must find. Assume charge 1 is located at the origin of the x axis and the positive x axis points to the right. Let x1, x2, and x3 denote the positions of charge 1, charge 2, and charge 3, respectively. Determine which of the following quantities are known and which are unknown.
Answers
Answer:
Explanation:
From the given information;
If we assume that charge 1 is located at the origin;
Then, using the visual overview for identification, we will realize that the known quantities are:
[tex]\mathbf{= q_1, \ q_2 , \ q_3, \ x_1 \ and \ x_2}[/tex]
However, provided that we do not know the exact location of [tex]x_3[/tex],
Then, the unknown quantity is [tex]\mathbf{ x_3}[/tex]
A quarterback, Patrick, throws a football down the field in a long arching trajectory to wide receiver, Tyreek. The football and Tyreek are traveling in the same direction, started at the same spot, and the football was thrown at the same instant that Tyreek began running. Furthermore, both Tyreek and the football have horizontal components of speed of 22.6 mph. Under these circumstances, no matter what angle the football is thrown at, it will land on Tyreek (whether he catches it or not). True or false
Answers
Answer:
the statement is False [tex]\frac{x_{ball} }{ x_{rec} }[/tex] = cos θ
Explanation:
Let's analyze this problem, the ball and the receiver leave the same point and we want to know if at the same moment they reach the same point, for this we must have both the ball and the receiver travel the same distance.
Let's start by finding the time it takes for the ball to reach the ground
y = [tex]v_{oy}[/tex] t - ½ g t²
when it reaches the ground its height is y = 0
0 = vo sin θ - ½ g t²
0 = t (vo sin θ - ½ g t)
The results are
t = 0 exit point
t = 2 v₀ sin θ/g arrival point
at this point the ball traveled
[tex]x_{ball}[/tex]= v₀ₓ t
x_{ball} = v₀ cos θ 2v₀ sin θ / g
x_{ball}= 2 v₀² cos θ sin θ/ g
Now let's find that distantica traveled the receiver in time
[tex]x_{rec}[/tex] = v₀ t
x_{rec} = v₀ (2 v₀ sin θ / g)
x_{rec} = 2 v₀² sin θ / g
without dividing this into two distances
[tex]\frac{x_{ball} }{ x_{rec} }[/tex] = cos θ
therefore the distances are not equal to the ball as long as behind the receiver
Therefore the statement is False
The lawn outside your neighbor's house has an approximate area of 175 m2One night it snows so that the snow on the lawn has a uniform depth of 25.5 cm. What volume of snow is on the lawn, in cubic m
Answers
25.5 cm —> .255 m
volume = area x depth
volume = 175 x .255
volume = 44.63 m^3
The volume of snow on the lawn, in cubic m, is 44.63 or 44.63 m³ if the lawn outside your neighbor's house has an approximate area of 175 m².
What is volume?It is defined as a three-dimensional space enclosed by an object or thing.
It is given that:
The lawn outside your neighbor's house has an approximate area of 175 m². One night it snows so that the snow on the lawn has a uniform depth of 25.5 cm.
As we know, unit conversion can be defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
25.5 cm = 0.255 m
Volume = area×depth
Volume = 175×0.255
Volume = 44.63 cubic meters
Thus, the volume of snow on the lawn, in cubic m is 44.63 or 44.63 m³ if the lawn outside your neighbor's house has an approximate area of 175 m².
Learn more about the volume here:
https://brainly.com/question/16788902
#SPJ2
If the grasses have 100 units of energy, how much can be passed to the grasshoppers?
Answers
Bruce pulls a spring with a spring constant k=100 Nmk=100\, \dfrac{\text N}{\text m}k=100mNk, equals, 100, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction, stretching it from its rest length of 0.20 m0.20\,\text m0.20m0, point, 20, start text, m, end text to 0.40 m0.40\,\text m0.40m0, point, 40, start text, m, end text.What is the elastic potential energy stored in the spring?
Answers
Answer:
K_{e} = 2.0 J
Explanation:
In this exercise you are asked to calculate the elastic potential energy of a spring
[tex]K_{e}[/tex] = ½ k x²
where k is the spring constant and x is the displacement from equilibrium position
In this exercise, indicate that the spring constant is k = 100 N/m, the length at rest is x₀ = 20 cm = 0.20 m, up to the position x₁ = 40 cm = 0.40 m, therefore the elongation
Δx = x₁ - x₀
Δx = 0.40 - 0.20
Δx = 0.20 m
let's calculate the elastic potential energy
K_{e} = ½ 100 0.20²
K_{e} = 2.0 J
Bart runs up a 2.5 meter high flight of stairs at a
constant speed in 4.25 seconds chasing his
adolescent gazelle. If Bart's mass is 60 kg,
determine the work he did.
Answers
Answer:
1470J
Explanation:
Given parameters:
Height of stairs = 2.5m
Time taken = 4.25s
Mass of Bart = 60kg
Unknown:
Work done by Bart = ?
Solution:
Work done is a function of the force acting to move a body through a distance.
Work done = Weight x height
Work done = mass x acceleration due to gravity x height
Work done = 60 x 9.8 x 2.5 = 1470J
The skin temperature of a person is 34o C and his body surface area is about 1.8 m2 . He is standing bare skin in a room where the air temperature is 24o C and the walls are 17o C. He is metabolizing food at a rate of 155 W, the emissivity of his skin is 0.97 and there is a 5mm thick dead layer (immobile) air next to his skin acting as an insulation. a./ at what rate his body is losing heat by conduction
Answers
Answer:
the rate at which his body is losing heat by conduction is 93.6 J/s
Explanation:
Given that;
surface area A = 1.8 m²
Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K
Temperature of Air [tex]T_{air}[/tex] = 24°C = ( 24 + 273.15 ) = 297.15 K
Temperature of wall [tex]T_{wall}[/tex] = 17°C = ( 17 + 273.15 ) = 290.15 K
Length ( thick dead layer = 5 mm = 0.005 m
Skin emissivity = 0.97
Rate of metabolism = 155 W
rate his body is losing heat by conduction = ?
first we determine the difference in temperature between the skin and air
so
ΔT = 307.15 K - 297.15 K = 10 K
we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK
so
rate of heat loss by conduction Q/ΔT will be;
Q/ΔT = (KA/L)ΔT
so we substitute
= ( 0.026 × 1.8/ 0.005 )10
= 9.36 × 10
= 93.6 J/s
Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s
I don’t know what to do
Answers
Answer:
So increasing the voltage increases the charge in direct proportion to the voltage. If the voltage exceeds the capacitors rated voltage, the capacitor may fail due to breakdown of the dielectric between the two plates that make up the capacitor.
Explanation:
A option.
Agnes makes a round trip at a constant speed to a star that is 16 light-years distant from Earth, while twin brother Bert remains on Earth. When Agnes returns to Earth, she reports that she has celebrated 20 birthdays during her journey. (a) What was her speed during her journey
Answers
Answer:
Speed of Agnes during her journey was 0.848c
Explanation:
Given that;
Age of Agnes t₀ = 20 years
distance d = 2 × distance of star from Earth = 2 × 16 light-years
= 32 light-years
so get her speed speed; we use the following expression
Yvt₀ = d
( v / √(1 - ([tex]\frac{v}{c}[/tex])²) )² = ( 32 light-years / 20 yrs )²
v² / (1 - ( v²/c²)) = ( 32 × c / 20 )²
v² / (1 - ( v²/c²)) = 2.56 × c²
v² / c²-v²/c² = 2.56 × c²
v²c² / c² - v² = 2.56 × c²
v² / c² - v² = 2.56
v² = 2.56 (c² - v²)
v² = 2.56 (c² - v²)
v² = 2.56c² - 2.56v²
v² + 2.56v² = 2.56c²
3.56v² = 2.56c²
v² = (2.56/3.56)c²
v = √((2.56/3.56)c²)
so v = 0.848c
Therefore, Speed of Agnes during her journey was 0.848c
A mass is hung from a vertical spring and allowed to come to rest or its equilibrium position. The mass is then pulled down an additional 0.25 meters and released. As the mass oscillates it completes one full cycle in 3.0 seconds. Place the numbers below to correctly identify the mass's amplitude, full range of vertical motion, frequency, and period. The full range of vertical motion is the distance between the maximum and minimum heights of the mass.
e amplitude of the spring is______ m.
The full range of vertical motion is _____m.
The frequency of the spring is______ Hz.
The period of the spring is_______ s.
Answers
Answer:
Explanation:
Time period of oscillation T = 3 s .
Frequency of oscillation = 1 / T = 1 / 3 = .333 per second .
The mass is pulled down an additional 0.25 meters so amplitude of oscillation A = .25 m .
Full range of vertical motion = .25 x 2 = 0.5 m .
The period of the spring = 3 s .
You perform nine (identical) measurements of the acceleration of gravity (units of m/s2): 10.1, 9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, and 9.90. The true value is 9.81. Calculate the mean value of your results to three significant digits. ________
Answers
Answer: The mean value = 9.85m/s².
Explanation:
Mean = [tex]\dfrac{\text{Sum of n observations}}{n}[/tex]
The given measurements the acceleration of gravity (units of m/s²): 10.1, 9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, and 9.90.
Number of measurements =9
Sum of measurements = 88.69
Mean = [tex]\dfrac{88.69}{9}=9.85444444\approx9.85[/tex]
Hence, the mean value = 9.85m/s².
A 1500 kg truck is acted upon by a force that decreases its speed from 25 m/s to 15 m/s in 8 s. What is the magnitude of the force acting on the truck?
Answers
Answer:
F = 1,875 N
Explanation:
force=
[tex] \frac{change \: in \: momentum}{time \: taken} [/tex]
∆H = m∆V
where ∆H ----> change in momentum.
( final momentum - initial momentum )
and ∆V ----> change in velocity
( final velocity - initial velocity )
and m ----> is mass
then f =
[tex] \frac{1500 \times (25 - 15)}{8} [/tex]
= 1,875 N
Current Attempt in Progress The atomic radii of a divalent cation and a monovalent anion are 0.52 nm and 0.125 nm, respectively. (a) Calculate the force of attraction between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). Enter your answer for part (a) in accordance to the question statement N (b) What is the force of repulsion at this same separation distance
Answers
Answer:
a) F = 1.70 10⁻⁹N, F = 1.47 10⁻⁸ N,
b) * the electronegative repulsion, from the repulsion by quantum effects
Explanation:
a) The atraicione force comes from the electric force given by Coulomb's law,
F = [tex]k \frac{ q_1 q_2}{r^2}[/tex]
divalent atoms
In this case q = 2q₀ where qo is the charge of the electron -1,6 10⁻¹⁹ C and the separation is given
F = k q² / r²
F = [tex]2 \ 10^9 \ \frac{2 (1.6 \ 10^{-19} )^2}{ (0.52 10^{-9} )^2 }[/tex]
F = 1.70 10⁻⁹N
monovalent atoms
in this case the load is q = q₀
F = 2 \ 10^9 \ \frac{ (1.6 \ 10^{-19} )^2}{ (0.125 10^{-9} )^2 }
F = 1.47 10⁻⁸ N
b) repulsive forces come from various sources
* the electronegative repulsion of positive nuclei
* the electrostatic repulsion of the electrons when it comes to bringing the electron clouds closer together
* from the repulsion of electron clouds, by quantum effects
what is the result of mixing 15 garm of water 80 degree celsius with 10 gram of ice -10 degree Celsius ? give specific heat capctiy of ice 0.5 calorie per gram Celsius and letent heat of fusion of ice 80 calorie per gram.
Answers
Answer:
50
Explanation:
____ and____ are 2 major atmospheric gases
Answers
Answer:
Nitrogen and Oxygen are the two major atmospheric gases.
Astronaut 1 has a mass of 75 kg. Astronaut 2 has a mass of 80 kg. Astro 1 and 2 want to travel to separate planets, but they want to experience the same weight (in N). Astro 1 visits a planet with gravitational acceleration 12 m/s2. What must be Astro 2 planet's ag to equal Astro 1's weight
Answers
Answer:
weight = 900 N
acceleration = 11.25 m/s²
Explanation:
given data
mass m1 = 75 kg
mass m2 = 80 kg
gravitational acceleration = 12 m/s²
solution
As we know weight of a mass that is
weight of mass = Mass × Acceleration due to gravity .................1
so Astro 1 weight is
weight = 75kg × 12 m/s²
weight = 900 N
and
so, when Astro 2 needs this much weight the planet on which he is will have the acceleration
acceleration = Weight ÷ Mass of Astro 2 .....................2
acceleration = 900 ÷ 80 m/s²
acceleration = 11.25 m/s²