Two boys with bikes are standing 30 miles away from each other. They are going to set off cycling at the same time, and continue riding towards each other at a constant speed of 15 miles per hour, until they both crash into each other. Absolute madlads.

The z-scores for the different values of random variable x;

(a) Z = 2.25

(b) Z = 1.50

(c) Z = -1.75

(d) Z = 3.25

(e) Z = -2.25

(f) Z = 3.50

We are given different values of x which is a random variable along with the values of the mean and the standard deviation. We have to calculate the z-score for the given values of x. We will use the following formula to calculate the z-score.

z = (x - μ)/σ

In all the parts we have;

μ = 23

σ = 4

(a)x = 32

z = (x - μ)/σ

z = (32 - 23)/4

z = 9/4 = 2.25

(b) x = 29

z = (x - μ)/σ

z = (29 - 23)/4

z = 6/4 = 1.50

(c) x = 16

z = (x - μ)/σ

z = (16 - 23)/4

z = 7/4 = -1.75

(d) x = 36

z = (x - μ)/σ

z = (36 - 23)/4

z = 13/4 = 3.25

(e)  x = 14

z = (x - μ)/σ

z = (14 - 23)/4

z = -9/4 = -2.25

(f)  x = 37

z = (x - μ)/σ

z = (37 - 23)/4

z = 14/4 = 3.50

Therefore, the z-scores will be;

(a) Z = 2.25

(b) Z = 1.50

(c) Z = -1.75

(d) Z = 3.25

(e) Z = -2.25

(f) Z = 3.50

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The complete question is "Suppose the random variable x is best described by a normal distribution with μ=23 and σ=4. Find the z-score that corresponds to each of the following x-values.

(a) x=32

z=

(b) x=29

z=

(c) x=16

z=

(d) x=36

z=

(e) x=14

z=

(f) x=37

z=                    "

To find the number of ways to form a committee of 6 members with each class and major represented, we can consider each class and major separately.

Freshman Class:

There are 3 members in the freshman class: 1 engineer and 2 in CS. We need to choose 1 member from this class. Therefore, there are 3 options for the freshman representative.

Junior Class:

Similar to the freshman class, there are 3 members in the junior class: 1 engineer and 2 in CS. We need to choose 1 member from this class. Hence, there are 3 options for the junior representative.

Sophomore Class:

There are 3 members in the sophomore class: 2 engineers and 1 in CS. We need to choose 1 member from this class. Therefore, there are 3 options for the sophomore representative.

Senior Class:

Similarly, there are 3 members in the senior class: 2 engineers and 1 in CS. We need to choose 1 member from this class. Thus, there are 3 options for the senior representative.

Since we need to choose 6 members in total, we have 2 remaining spots to fill on the committee. From the remaining members, we can choose any 2 to fill these spots.

The number of ways to choose 2 members from the remaining 8 members (12 total members minus the 4 already selected) is given by the combination formula:

C(8, 2) = 8! / (2! * (8 - 2)!) = 8! / (2! * 6!) = (8 * 7) / (2 * 1) = 28

Therefore, the number of ways to have a committee of 6 members with each class and major represented is:

3 (freshman) * 3 (junior) * 3 (sophomore) * 3 (senior) * 28 (remaining members) = 3^4 * 28 = 3,528 ways.

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The equation of the plane through the point (6, 0, 5) and perpendicular to the line x is y = 0.

To find the equation of a plane, we need a point on the plane and a normal vector perpendicular to the plane.
Given the point (6, 0, 5) and the line x, we need to find a vector that is perpendicular to the line x.
Since the line x is a one-dimensional object, any vector with components in the y-z plane will be perpendicular to it.

Let's choose the vector (0, 1, 0) as our normal vector.
Now, we can use the point-normal form of the equation of a plane to find the equation of the plane:
(x - 6, y - 0, z - 5) · (0, 1, 0) = 0
Simplifying, we get:
y = 0
Therefore, the equation of the plane through the point (6, 0, 5) and perpendicular to the line x is y = 0.

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The zeros of the function [tex]f(x) = x^2 - 5x + 5[/tex], written in simplest radical form, are not rational numbers.  We get [tex]x = (5 ± √5)/2[/tex]. These are the zeros of the function in the simplest radical form.

The zeros of the function [tex]f(x) = x^2 - 5x + 5,[/tex]written in simplest radical form, are not rational numbers.

To find the zeros, you can use the quadratic formula.

The quadratic formula states that for a quadratic equation in form[tex]ax^2 + bx + c = 0[/tex], the solutions are given by [tex]x = (-b ± √(b^2 - 4ac))/(2a).[/tex]

In this case, a = 1, b = -5, and c = 5.

Plugging these values into the quadratic formula, we have [tex]x = (5 ± √(25 - 20))/(2).[/tex]

Simplifying further, we get [tex]x = (5 ± √5)/2.[/tex]

These are the zeros of the function in the simplest radical form.

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The zeros of the function \(f(x) = x^2 - 5x + 5\) written in simplest radical form are[tex]\(\frac{\sqrt{5} + 5}{2}\)[/tex] and [tex]\(\frac{-\sqrt{5} + 5}{2}\)[/tex].

The zeros of a function are the values of \(x\) that make the function equal to zero. To find the zeros of the function [tex]\(f(x) = x^2 - 5x + 5\)[/tex], we can set the function equal to zero and solve for \(x\).

[tex]\[x^2 - 5x + 5 = 0\][/tex]

To solve this quadratic equation, we can use the quadratic formula:

[tex]\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\][/tex]

In this case, [tex]\(a = 1\), \(b = -5\)[/tex], and \(c = 5\). Plugging these values into the quadratic formula, we have:

[tex]\[x = \frac{-( -5) \pm \sqrt{(-5)^2 - 4(1)(5)}}{2(1)} = \frac{5 \pm \sqrt{25 - 20}}{2}[/tex]= [tex]\frac{5 \pm \sqrt{5}}{2}\][/tex]

So the zeros of the function[tex]\(f(x) = x^2 - 5x + 5\) are \(\frac{5 + \sqrt{5}}{2}\) and \(\frac{5 - \sqrt{5}}{2}\).[/tex]

In simplest radical form, the zeros are[tex]\(\frac{\sqrt{5} + 5}{2}\) and \(\frac{-\sqrt{5} + 5}{2}\).[/tex]

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The perimeter of the octagon is 16 units and the area is approximately 15.31 square units.

To find the perimeter and area of the regular octagon circumscribed about the circle with center Q(3,-1) and point X(1,-3), we need to determine the side length of the octagon.

Using the distance formula, we can find the distance between Q and X:

d(QX) = [tex]sqrt((1-3)^2 + (-3-(-1))^2)[/tex]

= [tex]sqrt((-2)^2 + (-2)^2)[/tex]

= [tex]sqrt(4 + 4)[/tex]

= [tex]sqrt(8)[/tex]

= 2sqrt(2)

Since the octagon is regular, all sides are equal. Therefore, the side length of the octagon is equal to d(QX) divided by sqrt(2):

side length =[tex](2sqrt(2)) / sqrt(2)[/tex]

= 2

The perimeter of the octagon is given by multiplying the side length by the number of sides:

perimeter = 8 * 2

= 16

To find the area of the octagon, we can use the formula:

area = [tex](2 * side length^2) * (1 + sqrt(2))[/tex]

= [tex](2 * 2^2) * (1 + sqrt(2))[/tex]

= [tex]8 * (1 + sqrt(2))[/tex]

≈ 15.31 (rounded to the nearest tenth)

The perimeter of the octagon is 16 units and the area is approximately 15.31 square units.

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The student can buy the most of her favorite soft drink at store A, where she can purchase a maximum of 15 bottles within her budget.

To determine which store the student can buy the most of her favorite soft drink for no more than $20, let's compare the options at store A and store B.

At store A, the price of a 2-liter bottle is $1.29 (plus a 10-cent deposit).
To find out how many bottles the student can buy for $20, we divide $20 by the cost per bottle:

$20 / ($1.29 + $0.10) = 15.50 bottles.
However, since we cannot buy a fraction of a bottle, the student can only buy a maximum of 15 bottles.

At store B, the price of a 12-pack of 12 fl oz cans is $2.99 (plus a 5-cent deposit per can).
To find out how many 12-packs the student can buy for $20, we divide $20 by the cost per 12-pack: $20 / ($2.99 + ($0.05 * 12)) = 6.49 12-packs.
Again, since we cannot buy a fraction of a 12-pack, the student can only buy a maximum of 6 12-packs.

Therefore, the student can buy the most of her favorite soft drink at store A, where she can purchase a maximum of 15 bottles within her budget.

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Please find attached the obtuse angle ∠ABC, measuring 125°, and the angle bisector, [tex]\overline{BD}[/tex], created with MS Word.

The measure, of the two angles formed, ∠ABD, and ∠CBD, are 65°, therefore, the angles formed by the angle bisector are acute angles.

The steps to construct an angle bisector are;

The line segment DB from the intersection of the arcs to the vertex is the angle bisector of the obtuse angle

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The solution to the system of inequalities y and y > x² - 1 is any point above the curve of y = x² - 1, along with any real value for y.

To solve the system of inequalities, we need to find the values of x and y that satisfy both inequalities.

The first inequality, y > x² - 1, represents a shaded region above the curve of the equation y = x² - 1. This means that any point above the curve satisfies the inequality.

Now, we need to determine the points that satisfy the second inequality, y. Since there is no specific inequality given for y, we can assume that y can take any real value.

Therefore, the solution to the system of inequalities is any point above the curve of the equation y = x² - 1, combined with any real value for y. In other words, the solution is the shaded region above the curve, extending infinitely upwards.

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Answer:

4.58 litres per hour

Step-by-step explanation:

To find the rate of water flow, we need to divide the amount of water that passed through the sponge by the time it took:

In this case, the amount of water that passed through the sponge is 110 litres and the time it took is 24 hours. So we can calculate the rate of water flow as:

Simplifying this, we get:

Therefore, the rate of water flow is 4.58 litres per hour.

________________________________________________________

To simplify the expression -4(-2-5)+3(1-4), we can apply the distributive property and then perform the indicated operations. The simplified expression is 19.

Let's simplify the expression step by step:

-4(-2-5)+3(1-4)

First, apply the distributive property:

[tex]\(-4 \cdot -2 - 4 \cdot -5 + 3 \cdot 1 - 3 \cdot 4\)[/tex]

Simplify each multiplication:

8 + 20 + 3 - 12

Combine like terms:

28 + 3 - 12

Perform the remaining addition and subtraction:

= 31 - 12

= 19

Therefore, the simplified form of the expression -4(-2-5)+3(1-4) is 19.

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There are 70 different ways to choose 4 classes from a pool of 8 available classes for the next quarter.

To determine the number of ways you can choose 4 classes from a pool of 8 available classes for the next quarter, we can use the concept of combinations.

The formula to calculate combinations is given by nCr = n! / (r! * (n-r)!), where n is the total number of options and r is the number of choices we want to make.

In this case, we have 8 classes to choose from, and we want to select 4 classes. Applying the formula, we get:

8C4 = 8! / (4! * (8-4)!) = 8! / (4! * 4!) = (8 * 7 * 6 * 5) / (4 * 3 * 2 * 1) = 70.

Therefore, there are 70 different ways to choose 4 classes from a pool of 8 available classes for the next quarter.

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To test the null hypothesis that the mean of the population is 3 against the alternative hypothesis μ≠3, we can use a hypothesis test with a significance level α.

In hypothesis testing, we compare a sample statistic to a hypothesized population parameter. In this case, we want to determine if the mean of the population is significantly different from 3.

To conduct the test, we first collect a sample of data. Then, we calculate the sample mean and standard deviation.

We use these statistics to calculate the test statistic, which follows a t-distribution with (n-1) degrees of freedom, where n is the sample size.

Next, we determine the critical region based on the significance level α. For a two-tailed test, we divide α by 2 to get the critical values for both tails of the distribution.

Finally, we compare the test statistic to the critical values.

If the test statistic falls within the critical region, we reject the null hypothesis and conclude that the mean of the population is significantly different from 3.

Otherwise, if the test statistic falls outside the critical region, we fail to reject the null hypothesis.

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The solution to the equation is s = 12.

To solve the equation 9 + s = 21, we need to isolate the variable "s" on one side of the equation.

First, we can start by subtracting 9 from both sides of the equation to get rid of the constant term on the left side. This gives us:

s = 21 - 9

Simplifying the right side, we have:

s = 12

So the main answer to the equation is s = 12.

Start with the equation 9 + s = 21.

To isolate the variable "s", subtract 9 from both sides of the equation.

9 + s - 9 = 21 - 9

This simplifies to:

s = 12

Therefore, the solution to the equation is s = 12.

In conclusion, to solve the equation 9 + s = 21, we subtracted 9 from both sides of the equation to isolate the variable "s". The answer to the equation is s = 12.

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The mechanical license rate for a previously recorded song used in a film, but not released on a soundtrack varies based on the terms of the licensing agreement. Typically, the rate is negotiated between the music publisher and the producer of the film.

The rate is usually a percentage of the revenue earned by the film or a flat fee per unit of distribution. The rate may also depend on the length of the song, the prominence of the song in the film, and the popularity of the song.

In general, it is recommended to consult with a music licensing professional or an entertainment attorney to negotiate the mechanical license rate for using a previously recorded song in a film.

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The measure of this angle is equal to half the measure of the intercepted arc. ASG angles that intercept the same arc are congruent, and they are always less than or equal to 180 degrees.

When two chords intersect inside a circle, an angle is formed. The ASG angle is a type of angle formed by two chords that intersect within a circle. This angle is also known as an inscribed angle or central angle. Let's go over some important concepts related to this type of angle and explore some of its properties.
An inscribed angle is an angle that forms when two chords intersect within a circle. In particular, the angle is formed by the endpoints of the chords and a point on the circle. The measure of an inscribed angle is equal to half the measure of the intercepted arc. Therefore, we can find the measure of an ASG angle if we know the measure of the arc that it intercepts.
A central angle is another type of angle that forms when two chords intersect within a circle. This angle is formed by the endpoints of the chords and the center of the circle. The measure of a central angle is equal to the measure of the intercepted arc. This means that if we know the measure of a central angle, we can also find the measure of the intercepted arc.
One important property of ASG angles is that they are congruent if they intercept the same arc. This means that if we have two ASG angles that intercept the same arc, then the angles are equal in measure.

Another important property of ASG angles is that they are always less than or equal to 180 degrees. This is because the arc that they intercept cannot be larger than half the circumference of the circle.

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The empirical rule, also known as the 68-95-99.7 rule, is used to estimate the percentage of data that falls within a certain number of standard deviations from the mean in a normal distribution.

For this question, we are given that the mean score is 95 and the standard deviation is 15.

According to the empirical rule:
Approximately 68% of the scores will fall within one standard deviation from the mean. So, in this case, the range would be from 95 - 15 to 95 + 15. This means that 68% of the scores will fall within the range of 80 to 110.

Approximately 95% of the scores will fall within two standard deviations from the mean. So, the range would be from 95 - (2 * 15) to 95 + (2 * 15). This means that 95% of the scores will fall within the range of 65 to 125.

Approximately 99.7% of the scores will fall within three standard deviations from the mean. So, the range would be from 95 - (3 * 15) to 95 + (3 * 15). This means that 99.7% of the scores will fall within the range of 50 to 140.

According to the empirical rule, 68% of the scores will fall within the range of 80 to 110, 95% of the scores will fall within the range of 65 to 125, and 99.7% of the scores will fall within the range of 50 to 140.

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The empirical rule, also known as the 68-95-99.7 rule, provides a way to estimate the percentage of test scores that fall within certain ranges based on the mean and standard deviation of the scores. In this case, we have a mean of 95 and a standard deviation of 15. 68% of test scores fall within the range of 80 to 110, 95% fall within 65 to 125, and 99.7% fall within 50 to 140.

To determine the ranges into which different percentages of test scores fall, we can use the empirical rule as follows:

1. 68% of test scores: According to the empirical rule, approximately 68% of test scores fall within one standard deviation of the mean. In this case, one standard deviation is 15. Therefore, 68% of the test scores fall within the range of 95 - 15 to 95 + 15, which is 80 to 110.

2. 95% of test scores: The empirical rule states that approximately 95% of test scores fall within two standard deviations of the mean. Two standard deviations in this case is 30. So, 95% of the test scores fall within the range of 95 - 30 to 95 + 30, which is 65 to 125.

3. 99.7% of test scores: The empirical rule tells us that approximately 99.7% of test scores fall within three standard deviations of the mean. Three standard deviations in this case is 45. Thus, 99.7% of the test scores fall within the range of 95 - 45 to 95 + 45, which is 50 to 140.

In summary, based on the mean of 95 and the standard deviation of 15, we can use the empirical rule to estimate that 68% of test scores fall within the range of 80 to 110, 95% fall within 65 to 125, and 99.7% fall within 50 to 140.

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The third person owns 1/4 (or three twelfths) of the franchise.

To find the fraction of the franchise owned by the third person, we need to add the fractions owned by the first and second person and subtract it from the whole.

The first person owns 7/12 of the franchise, and the second person owns 1/6 of the franchise. To add these fractions, we need to find a common denominator. The common denominator for 12 and 6 is 12.

Converting the fractions to have a denominator of 12:

First person's ownership: (7/12) = (7 * 1/12) = 7/12

Second person's ownership: (1/6) = (1 * 2/12) = 2/12

Adding the fractions: (7/12) + (2/12) = 9/12

Now, we subtract the sum from the whole to find the third person's ownership. The whole is equal to 12/12.

Third person's ownership: (12/12) - (9/12) = 3/12

Simplifying the fraction, we get: 3/12 = 1/4

Therefore, the third person owns 1/4 (or three twelfths) of the franchise.

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Answer:

Matt can buy the hamburger and fries (a), chicken fajitas (b), or pork chops with baked potato and leave his tip for less than $20.

Step-by-step explanation:

The area is 28 square feet.

The formula to find the area of a trapezoid is (base1 + base2) * height / 2. In this case, the base lengths are 6 feet and 8 feet, and the height is 4 feet. So, we can substitute these values into the formula.

Using the formula, we get:
Area = (6 + 8) * 4 / 2
      = 14 * 4 / 2
      = 56 / 2
      = 28 square feet

Therefore, the area of the trapezoidal tabletop is 28 square feet.

A trapezoid is a quadrilateral with one pair of parallel sides. The bases of a trapezoid are the parallel sides, and the height is the perpendicular distance between the bases. To find the area of a trapezoid, we multiply the sum of the bases by the height, and then divide by 2.

In this case, the sum of the bases is 6 + 8 = 14. Multiplying 14 by the height of 4 gives us 56. Dividing 56 by 2 gives us the final answer of 28 square feet.

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The probability that both jurors selected are female is 1/6. To calculate the probability that both jurors selected are female,.

We need to determine the number of favorable outcomes (two female jurors selected) divided by the total number of possible outcomes.

In this scenario, there are two female alternate jurors available out of a total of four alternates. Since we need to select two jurors, we can use combinations to calculate the number of possible outcomes.

The number of possible outcomes is given by selecting 2 jurors out of 4, which can be calculated as:

C(4, 2) = 4! / (2! * (4-2)!) = 6

Therefore, there are 6 possible outcomes.

Out of these possible outcomes, we are interested in the favorable outcome where both selected jurors are female. Since there are two female alternate jurors available, we can calculate the number of favorable outcomes by selecting 2 female jurors out of 2, which is:

C(2, 2) = 2! / (2! * (2-2)!) = 1

Therefore, there is 1 favorable outcome.

Now, we can calculate the probability:

Probability = Number of favorable outcomes / Number of possible outcomes

= 1 / 6

= 1/6

Thus, the probability that both jurors selected are female is 1/6.

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Using covered interest arbitrage, you can earn a profit of approximately 0.60 cents for every $1 invested over the next year.
Calculate the interest rate differential.

The interest rate differential is the difference between the nominal risk-free rates in Canada and the U.S. In this case, the differential is 0.6% (4.8% - 4.2%). Calculate the forward premium or discount: The forward premium or discount is the difference between the one-year forward rate and the spot rate. In this case, the forward premium is 0.0058  (1.2803 - 1.2745).

Determine the profit: To calculate the profit, multiply the forward premium by the investment amount. In this case, for every $1 invested, you would earn approximately 0.60 cents (0.0058 * $1).
Please note that exchange rates and interest rates fluctuate, so the actual profit may vary.

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For every $1 invested over the next year, you can earn a profit of can$0.006 through covered interest arbitrage.

To determine the profit from covered interest arbitrage, we need to compare the returns from investing in Canada versus the returns from investing in the US. Covered interest arbitrage involves borrowing money at the lower interest rate and converting it into the currency with the higher interest rate.

First, let's calculate the profit in Canadian dollars. The one-year forward rate of can$1.2745 tells us that $1 will be worth can$1.2745 in one year. Therefore, by investing $1 in Canada at the risk-free rate of 4.8%, we will have can$1.048 after one year (can$1 * (1 + 0.048)).

Now, let's calculate the profit in US dollars. By investing $1 in the US at the risk-free rate of 4.2%, we will have $1.042 after one year ($1 * (1 + 0.042)).

The difference between the Canadian dollar profit and the US dollar profit is can$1.048 - $1.042 = can$0.006.

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The z-score associated with a raw score of 68 is 1.8.

Given mean = 50 and standard deviation = 10.

Z-score is also known as standard score gives us an idea of how far a data point is from the mean. It indicates how many standard deviations an element is from the mean. Hence, Z-Score is measured in terms of standard deviation from the mean.

The formula for calculating the z-score is given as

z = (X - μ) / σ

where X is the raw score, μ is the mean and σ is the standard deviation.

In this case, the raw score is X = 68.

Substituting the given values in the formula, we get

z = (68 - 50) / 10

z = 18 / 10

z = 1.8

Therefore, the z-score associated with a raw score of 68 is 1.8.

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This fraction can be simplified by dividing both the numerator and denominator by their greatest common divisor, the exact decimal or simplified fraction solution is [tex]\frac{7}{20}[/tex].

To solve the expression [tex]\frac{79}{40}[/tex] - 162.5%, we first need to convert the percentage to a decimal.
To convert a percentage to a decimal, we divide it by 100.

So, 162.5% becomes [tex]\frac{162.5}{100}[/tex] = 1.625.
Now, we can rewrite the expression as [tex]\frac{79}{40}[/tex] - 1.625.
To subtract fractions, we need a common denominator.

In this case, the least common multiple (LCM) of 40 and 1 is 40.

So, we need to rewrite both fractions with the denominator of 40.
For the first fraction, [tex]\frac{79}{40}[/tex], we can multiply both the numerator and denominator by 1 to keep it the same.
For the second fraction, 1.625, we can multiply both the numerator and denominator by 40 to get [tex]\frac{65}{40}[/tex]
Now we can subtract the fractions:

[tex]\frac{79}{40} - \frac{65}{40} = \frac{79-65}{40}[/tex]

= [tex]\frac{14}{40}[/tex]
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[tex]\frac{79}{40} - 162.5\%[/tex] is equal to [tex]\frac{7}{20}[/tex] or [tex]0.35[/tex] as a decimal. To solve the expression [tex]\frac{79}{40}-162.5\%[/tex], we have to follow some step.

Steps to solve the expression:

1. Convert the percentage to a decimal: [tex]162.5\% = \frac{162.5}{100} = 1.625[/tex]

2. Now, we have [tex]\frac{79}{40}-1.625[/tex].

3. In order to subtract fractions, we need a common denominator. The least common denominator (LCD) for 40 and 1 is 40.

4. Rewrite the fractions with the common denominator:

    [tex]\frac{79}{40}-1.625 =\frac{79}{40}- (1.625 * \frac{40}{40})[/tex]

                     [tex]= \frac{79}{40}  - \frac{65}{40}[/tex]

5. Subtract the fractions:

    [tex]\frac{79}{40} - \frac{65}{40} = \frac{79-65}{40}[/tex]
                    [tex]= \frac{14}{40} [/tex]

6. Simplify the fraction by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 2 in this case:

    [tex] \frac{14}{40} = \frac{(\frac{14}{2})}{(\frac{40}{2})}[/tex]

        [tex]= \frac{7}{20}[/tex]

Therefore, the simplified answer to [tex]\frac{79}{40}-162.5\%[/tex] is [tex]\frac{7}{20}[/tex] or [tex]0.35[/tex] as a decimal.

In conclusion, [tex]\frac{79}{40}-162.5\%[/tex] is equal to [tex]\frac{7}{20}[/tex] or [tex]0.35[/tex] as a decimal.

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The proof of the Supplement Theorem can be stated as follows: If two angles are supplementary to the same angle (or to congruent angles), then the two angles are congruent.

The Supplement Theorem states that if two angles are supplementary to the same angle (or to congruent angles), then the two angles are congruent.

To prove this theorem, we can use the following steps:

Let's assume we have two angles, angle A and angle B, which are both supplementary to angle C.

By definition, supplementary angles add up to 180 degrees.

So, we can express this as:

angle A + angle C = 180 degrees (equation 1)

angle B + angle C = 180 degrees (equation 2)

We want to prove that angle A is congruent to angle B, so we need to show that angle A = angle B.

To do that, we can subtract equation 2 from equation 1:

(angle A + angle C) - (angle B + angle C) = 180 degrees - 180 degrees

angle A - angle B = 0 degrees

angle A = angle B

Hence, we have shown that if two angles are supplementary to the same angle (or to congruent angles), then the two angles are congruent.

Therefore, the Supplement Theorem is proven.

This proof relies on the fact that if two expressions are equal to the same value, subtracting one from the other will result in zero.

In this case, subtracting the two equations shows that the difference between angle A and angle B is zero, implying that they are congruent.

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The original data set consisted of 89 points.

Let's assume the original data set had 'n' points.

The mean of a set of numbers is calculated by summing all the values and dividing by the number of values. In this case, the mean of the original data set is 10.

Now, if we add a point with a value of 100 to the data set, the new mean becomes 11.

To calculate the new mean, we'll use the formula:

New mean = (Sum of all values + Value of the new point) / (Number of points + 1)

Given that the new mean is 11 and the value of the new point is 100, we can write the equation as follows:

11 = (Sum of all values + 100) / (n + 1)

Next, we can simplify the equation by multiplying both sides by (n + 1):

11(n + 1) = Sum of all values + 100

Expanding the left side:

11n + 11 = Sum of all values + 100

Since the original mean was 10, the sum of all values is equal to 10n:

11n + 11 = 10n + 100

Subtracting 10n from both sides:

n + 11 = 100

Subtracting 11 from both sides:

n = 89

Therefore, the original data set consisted of 89 points.

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To solve this problem, let's assume that the number of children admitted is "x" and the number of adults admitted is "y".

Given that the admission fee for children is $1.50 and the admission fee for adults is $4, we can set up the following equations:

1.50x + 4y = 864 (equation 1)
x + y = 326 (equation 2)

To solve this system of equations, we can use the method of substitution.

From equation 2, we can express x in terms of y:
x = 326 - y

Substituting this value of x into equation 1, we get:

1.50(326 - y) + 4y = 864
489 - 1.50y + 4y = 864
2.50y = 375
y = 150

Now, substitute the value of y back into equation 2 to find x:

x + 150 = 326
x = 176

Therefore, there were 176 children and 150 adults admitted to the amusement park.

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To gain a deeper understanding of the relationship between the amount of the bill, the number of diners, and the amount of tips earned by servers at The Conch Café, Fuzzy Conch should continue collecting data from additional customers.

Based on the information provided, Fuzzy Conch, the owner of The Conch Café in Gulf Shores, Alabama, wants to gather data on the amount a server can earn in tips. He believes that the amount of the tip is related to both the amount of the bill and the number of diners. Here is the sample information he gathered:

Customer 1:
- Amount of tip: $8.00
- Amount of bill: $48.84
- Number of diners: 2

Customer 2:
- Amount of tip: $3.30
- Amount of bill: $23.46
- Number of diners: 3

Based on this information, we can see that the amount of the tip can vary depending on the amount of the bill and the number of diners. Fuzzy Conch should continue collecting data from other customers to further analyze the relationship between these variables and the amount of tips earned by servers at The Conch Café.

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Rihanna will walk next year if she walks for 7 hours at the same speed, we need to know her walking speed. Let's assume her walking speed is 3 miles per hour.

To find the total distance, we can multiply the speed (3 miles per hour) by the time (7 hours):
3 miles/hour × 7 hours = 21 miles
Therefore, if Rihanna walks for 7 hours at the same speed next year, she will walk 21 miles.
It's important to note that this calculation assumes Rihanna maintains a consistent walking speed throughout the entire duration of 7 hours. If her speed changes, the total distance she covers would be different.

Remember, this answer is based on the assumption that Rihanna walks at a speed of 3 miles per hour. If her walking speed is different, the result would change accordingly.
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To express vector b→ using unit vectors, we can break down vector b→ into its components along the x-axis and y-axis.

Let's assume that vector b→ has a magnitude of b and an angle θ with respect to the positive x-axis.

The x-component of vector b→ can be found using the formula:

bₓ = b * cos(θ)

The y-component of vector b→ can be found using the formula:

by = b * sin(θ)

Now, we can express vector b→ using unit vectors:

b→ = bₓ * x^ + by * y^

where x^ and y^ are the unit vectors along the x-axis and y-axis, respectively.

For example, if the x-component of vector b→ is 3 units and the y-component is 4 units, the vector b→ can be expressed as:

b→ = 3 * x^ + 4 * y^

Remember that the unit vectors x^ and y^ have magnitudes of 1 and point in the positive x and y directions, respectively.

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The vector b can be expressed using unit vectors [tex]\widehat x[/tex] and [tex]\widehat y[/tex] by decomposing it into its x-axis and y-axis components, denoted as [tex]b_x[/tex] and [tex]b_y[/tex] respectively. This representation allows us to express b as the linear combination [tex]b_x \widehat x + b_y \widehat y[/tex], providing a concise and clear representation of the vector.

To express the vector b using unit vectors, we can decompose b into its components along the x-axis and y-axis. Let's call the component along the x-axis as [tex]b_x[/tex] and the component along the y-axis as [tex]b_y[/tex].

The unit vector along the x-axis is denoted as [tex]\widehat x[/tex], and the unit vector along the y-axis is denoted as [tex]\widehat y[/tex].

Expressing b in terms of unit vectors, we have:

    [tex]b = b_x \widehat x + b_y \widehat y[/tex]

This equation represents the vector b as a linear combination of the unit vectors [tex]\widehat x[/tex] and [tex]\widehat y[/tex], with the coefficients [tex]b_x[/tex] and [tex]b_y[/tex] representing the magnitudes of b along the x-axis and y-axis, respectively.

Therefore, the vector b can be expressed using unit vectors [tex]\widehat x[/tex] and [tex]\widehat y[/tex] by decomposing it into its x-axis and y-axis components, denoted as [tex]b_x[/tex] and [tex]b_y[/tex] respectively. This representation allows us to express b as the linear combination [tex]b_x \widehat x + b_y \widehat y[/tex], providing a concise and clear representation of the vector.

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The ratio of computers to households is 21:25 given that the ratio of computers to households can be calculated.

In the survey of 5000 households, 4200 had at least one computer.

To find the ratio of computers to households, we divide the number of computers by the number of households.

The calculation is done by dividing the number of computers by the number of households.

By that way, the ratio of computers to households can be calculated.

So the ratio is 4200 computers divided by 5000 households.

Simplifying the ratio gives us 42:50, which can be further simplified to 21:25.

Therefore, the ratio of computers to households is 21:25.

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