Answer:
Step-by-step explanation:
We will make a table and fill it in according to the information provided. What this question is asking us to find, in the end, is how long did it take the cars to travel the same distance. In other words, how long, t, til car 1's distance = car 2's distance. The table looks like this:
d = r * t
car1
car2
We can fill in the rates right away:
d = r * t
car1 40
car2 60
Now it tells us that car 2 leaves 3 hours after car 1, so logically that means that car 1 has been driving 3 hours longer than car 2:
d = r * t
car1 40 t + 3
car2 60 t
Because distance = rate * time, the distances fill in like this:
d = r * t
car1 40(t + 3) = 40 t+3
car2 60t = 60 t
Going back to the interpretation of the original question, I am looking to solve for t when the distance of car 1 = the distance of car 2. Therefore,
40(t+3) = 60t and
40t + 120 = 60t and
120 = 20t so
t = 6 hours.
area perimeter for grade 4
Answer:
what is the questions.
The length of ZX is 2 units. What is the perimeter of triangle XYZ? 5 + + 2 units 5 + 3 units 5 + + 2 units 10 + 2 units
Answer:
B) 5 + 3√5 units
Step-by-step explanation:
The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?
A) 5 +√3 + 2 √5 units
B) 5 + 3√5 units
C) 5 + √6 + 2√5 units
D) 10 + 2√5 units
From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).
The distance between two point
[tex]O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
The lengths of the sides of the triangle are:
[tex]|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit[/tex]
The perimeter of the triangle is the sum of all the sides, i.e.
Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5
Answer:
B
Step-by-step explanation:
Answer the problem below
Answer:
D. 4z^3
Step-by-step explanation:
First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3
Hope this helps, if you want me to explain more, feel free to ask questions.
Have a good day! :)
Answer:
4 z^3
Step-by-step explanation:
( 64 z^9) ^ 1/3
Rewriting 64 as 4^3
( 4^3 z^9) ^ 1/3
We know that ( ab) ^c = a^c * b^c
4^3 ^ 1/3 z^9 ^ 1/3
We know that a^ b^c = a^ ( b*c)
4^(3 * 1/3) z^ (9 * 1/3)
4 ^ ( 1) z^ ( 3)
4 z^3
The sales tax on clothing in Nebraska is 5.5%. Calculate how much tax you need to pay on a shirt if it costs $18.20 before tax. Round your answer to the nearest cent. ( pls answer asap and thanks ) will give BRANLIEST
Answer:
$1.00
Step-by-step explanation:
The tax rate in Nebraska = 5.5%
Cost of the shirt before tax = $18.20
Therefore:
Tax to be paid = 5.5% of $18.20
[tex]=0.055 \times \$18.20\\=\$1.00 $(correct to the nearest cent)[/tex]
The amount you need to pay as tax is $1.00.
The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream cones (one scoop) can a customer order? a 40 b 18 c 45 d 35
Answer:
45
Step-by-step explanation:
There are 3 cones and 15 flavors
Multiply the number of cones by the number of flavors
3*15
45
There are 45 possible combinations
Paul has four paper strips of the same length. He glues two of them together with a 4 cm overlap, and the new strip is 36 cm long. He wants to make a 30 cm long strip with the other two strips. How long should the overlap be?
Answer:
10 cm overlap required to make a 30 cm long strip.
Step-by-step explanation:
Given:
Four paper strips of the same length.
Two of them glued together with a 4 cm overlap to make a new strip which is 36 cm long.
To find:
Overlap required to make a strip which is 30 cm long = ?
Solution:
First of all, let us understand the concept of overlap.
Please refer to the attached image.
Let length of each strip be [tex]x[/tex] cm.
Given that there is 4 cm overlap resulting in new strip of length 36 cm.
The overlapping length is counted only once as clear from the figure attached.
So, Let us try to find the equation:
[tex]x +(x-4) = 36\\\Rightarrow 2x=40\\\Rightarrow x = 20\ cm[/tex]
i.e. each strip length is 20 cm.
Now, let us assume, an overlap of 'y' cm is to be made to make a new strip of 30 cm.
The equation will be:
[tex](20-y)+20 =30\\\Rightarrow y = 40-30\\\Rightarrow y = 10\ cm[/tex]
Help please! Thanks
Answer:
E. 0
Step-by-step explanation:
There isn't any guarantee that there are any people that have their birthdays in the same month based on what you're given, so your answer would be 0.
Brad walked a total of 24 kilometers by making 6 trips to school. After 21 trips to school, how many kilometers will Brad have walked in total? Solve using unit rates.
Answer:
84 km... Mark me as BRAINLIEST
Step-by-step explanation:
Refer to the pic...
Hope it helped you!
Step-by-step explanation:
Since it takes 6 trips to cover 24 km -
1 trip = 24/6
Therefore 1 trip is -
4 km
Now, the distance for 21 trips is -
21*4 = 84
Therefore, Brad has walked -
84 km
HOPE YOU FIND THIS HELPFUL
WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched. Graphon the coordinate plane.
Answer:
[tex]h=64t-4.9t^{2}[/tex]
Please refer to the attached graph.
Step-by-step explanation:
Given that
Initial velocity of rocket = 64 and is launched vertically.
To find:
Quadratic equation in time to represent the height of rocket in feet.
Solution:
Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.
Initial velocity, u = 64 feet/s
The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.
Formula for distance traveled is given as:
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here Let us represent s by 'h'
a = -g = 9.8 m/[tex]s^2[/tex]
Let us put the known values in the formula:
[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]
It is a quadratic equation, the equation represents the graph of a parabola.
Please refer to the attached graph.
Value of height is 0 at 0 second and ~13 seconds
Which choice shows the coordinates of B' if the trapezoid is reflected across the x-axis? On a coordinate plane, trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1). (–7, 2) (2, –7) (7, –2) (–2, 7)
Answer:
(7, -2)
Step-by-step explanation:
The trapezoid A B C D has points (2, 2), (7, 2), (5, 1), (3, 1).
Transformation of a point is the change in location from an original position to a new position. If a shape is transformed, all its points are also transformed. A transformation can either be a rotation, translation, reflection or dilation.
If a point O(x,y) is reflected across the y axis, the new coordinate of the point is at O'(x, -y), i.e. the x coordinate does not change, but the y coordinate is negated.
Since in trapezoid ABCD, the coordinate of point B is (7, 2). The trapezoid is reflected across the x-axis, therefore the new coordinate of B' is at (7, -2)
Answer:c
Step-by-step explanation:
I took the test
 what is the measure of AC 
Answer:
A
Step-by-step explanation:
The inscribed angle ABC is half the measure of its intercepted arc, thus
arc AB = 2 × 44° = 88° → A
Answer:
A
Step-by-step explanation:
The measure of an inscribed angle is half the measure of it's intercepted arc
2.
The roots of the equation x2-3x - m(m + 3) = 0,
where m is a constant, are
(a) m, m + 3
(b) -m, m + 3
(c) m,- (m+3) (d) -m, -(m + 3)
(AI 2011)
Answer:
(b) -m, m + 3
Step-by-step explanation:
x² − 3x − m(m + 3) = 0
x² − 3x = m(m + 3)
x² − 3x + 9/4 = m(m + 3) + 9/4
(x − 3/2)² = m(m + 3) + 9/4
(x − 3/2)² = m² + 3m + 9/4
(x − 3/2)² = (m + 3/2)²
x − 3/2 = ±(m + 3/2)
x − 3/2 = m + 3/2, -m − 3/2
x = m + 3, -m
This is probably pretty easy, I could solve all the other ones but I got stuck on this one.
Answer:
78
Step-by-step explanation:
Let x be the score on the next test
We are averaging 6 tests and want an average of 75
( 82+91+38+78+83+x) /6 = 75
Multiply each side by 6
( 82+91+38+78+83+x) = 75*6
( 82+91+38+78+83+x) =450
Combine like terms
x+372 = 450
Subtract 372 from each side
x+372-372 = 450-372
x =78
Please answer this in two minutes
Answer:
[tex] s = 14.1 [/tex]
Step-by-step explanation:
Given:
<S = 31°
SQ = r = 9
SR = q = 21
s = ?
To find s, use the Law of Cosines:
s² = r² + q² - 2rs*cos(S)
[tex] s^2 = 9^2 + 21^2 - 2*9*21*cos(31) [/tex]
[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]
[tex] s^2 = 522 - 324.02 [/tex]
[tex] s^2 = 197.98 [/tex]
[tex] s = 14.1 [/tex] (nearest tenth)
vertical stretch of the graph f(x)= x² by a factor of 5
PLEASE HELP!!
Answer:
f(x) = 5x^2
Step-by-step explanation:
A vertical stretch is in the y direction
y = Cf(x) C > 1 stretches it in the y-direction
f(x) = 5x^2
solve for x, if a solution is extraneous identify in the final answer. thx :)
Answer:
x = 6 and x = 11.
Step-by-step explanation:
sqrt(x - 2) + 8 = x
sqrt(x - 2) = x - 8
(sqrt(x - 2))^2 = (x - 8)^2
x - 2 = x^2 - 16x + 64
x^2 - 16x + 64 = x - 2
x^2 - 17x + 66 = 0
We can use the discriminant to find whether there are solutions to the equation.
b^2 - 4ac; where a = 1, b = -17, and c = 66.
(-17)^2 - 4 * 1 * 66
= 289 - 264
= 25
Since the discriminant is positive, we know there are two valid solutions to the equation.
x^2 - 17x + 66 = 0
(x - 6)(x - 11) = 0
The solutions are when x - 6 = 0 and x - 11 = 0.
x - 6 = 0
x = 6
x - 11 = 0
x = 11
Hope this helps!
Answer:
x=11 solution
x=6 extraneous
Step-by-step explanation:
sqrt( x-2) + 8 = x
Subtract x from each side
sqrt(x-2) = x-8
Square each side
(sqrt(x-2))^2 = (x-8) ^2
x-2 = x^2 -8x-8x+64
x-2 = x^2 -16x+64
Subtract ( x-2) from each side
0 = x^2 -17x +66
Factor
0 = (x-6) ( x-11)
Using the zero product property
x=6 x=11
Checking the solutions
x=6
sqrt( 6-2) + 8 = 6
sqrt(4) +8 = 6
2 +8 = 6
False not a solution
x=11
sqrt( 11-2) + 8 = 11
sqrt(9) +8 =11
3 +8 = 11
solution
Hi how to solve this simultaneous equation
Answer:
[tex]\large \boxed{\sf \ \ x=\pm8 \ \ or \ \ x=\pm2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
First of all, we can assume that x and y are different from 0, as we cannot divide by 0.
And from the first equation we can write y as a function of x as below.
[tex]y=\dfrac{16}{x}[/tex]
And then, we replace it in the second equation to get.
[tex]\dfrac{x}{\frac{16}{x}}+\dfrac{\frac{16}{x}}{x}=\dfrac{17}{4}\\\\<=> \dfrac{x^2}{16}+\dfrac{16}{x^2}=\dfrac{17}{4}\\\\\text{*** We multiply by }16x^2 \text{ both sides ***}\\\\x^4+16*16=\dfrac{17*16}{4}x^2\\\\x^4-68x^2+3600=0\\\\\text{*** The product of the zeroes is 3600 = 64*4 and the sum is 64+4=68 ***}\\\\\text{*** So we can factorise *** }\\\\x^4-64x^2-4x^2+3600=x^2(x^2-64)-4(x^2-64)=(x^2-64)(x^2-4)=0\\\\x^2=64=8^2 \ \ or \ \ x^2=4\\\\x=\pm8 \ \ or \ \ x=\pm2\\[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
In Central City, Elm Street and Maple Street are parallel to one another. Oak Street crosses both Elm Street and Maple Street as shown.
Answer:
a. (True) Since ∠6 and ∠8 are vertical angles, they are congruent.
b. (False) ∠1 and ∠2 are supplementary but 65 + 125 ≠ 190.
c. True
d. True
e. True
Answer:
The answer is Freddy Kruger
Step-by-step explanation:
Elm Street, duh
Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem?
Answer:
The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR
Step-by-step explanation:
Given DF/PR = FE/RQ = 3/2
The Side Side Side, SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar
Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.
If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.
Answer:
D: DE/PQ = 3/2
Step-by-step explanation:
Did it on edge 2020
2 There are x fish in a pond.
Omar puts 5 more fish in the pond.
How many fish are in the pond now?
Answer:
x+5
Step-by-step explanation:
We are adding fish
There were x and then we added 5
There are now
x+5
Answer:
x+5
Step-by-step explanation:
since there are x fish, adding five more would make it x+5
can someone help....
Answer:
-7 is no, -2 is no, 7 is no, and 10 is yes
Step-by-step explanation:
-5+9*(-7)>58
-5+-63>58
-68>58
-5+9*(-2)>58
-5+-18>58
-23>58
-5+9*(7)>58
-5+63>58
58>58
-5+9*(10)>58
-5+90>58
85>58
so the only one that is a solution is v=10, hope this helps
Answer: No, No, No, Yes
Step-by-step explanation:
Solve the equation for "v":
-5 + 9v > 58
9v > 63
v > 7
Check the options to see if they make a true statement:
-7 > 7 False
-2 > 7 False
7 > 7 False
10 > 7 TRUE!
plzzz hellpppppp...........
Answer:
Bearing of R from S = S 45° E or 135°
The bearing of R from Q
= S 66.42° w or 246.42°
Step-by-step explanation:
Distance between R and S
RS²= RP²+PS²
RS²= 15²+15²
RS²=225+225
RS= √450
RS= 21.21
Angle at S
21.21= 15/sins
Sin s= 15/21.21
S= sin^-1 15/21.21.
S= 45°
90+45= 135°
Bearing of R from S = S 45° E or 135°
Distance between R and Q
RQ²= PQ²+PR²
RQ²= 35²+15²
RQ²=1225+225
RQ= √1450
RQ= 38.08
RQ= 15/sinQ
SinQ= 15/38.08
SinQ= 0.40
Q=23.58°
90-23.58 = 66.42°
66.42+180= 246.42°
The bearing of R from Q
= S 66.42° w or 246.42°
How does the period of f(x)= cos(2x) relate to the period of the parent function cos x?
Answer:
Both have the same period which is 2π
Step-by-step explanation:
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.
Answer:
A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.
Step-by-step explanation:
Answer:
WHEN U GRAPH WITH A CALCULATOR IT IS MUCH MORE ACCURATE
ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER ENDS
Step-by-step explanation:
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
In one U.S. city, the taxi cost is $3 plus $0.60 per mile. If you are traveling from the airport, there is an additional charge of $5.50 for tolls. How far can you travel from the airport by taxi for $26.50?
the airport by taxi for $26.50?
Answer:
30 milesStep-by-step explanation:
How far can you travel from the airport by taxi for $26.50 ?($26.5 - $3 - $5.50) : $0.6/m =
= $18 : 0.6$/m
= 30 miles
Drag the tiles to the correct boxes to complete the pairs.
This table gives Information about vehicles sold at a dealership in a month.
Gasoline Diesel
18
5
Hatchback
Sedan
15
12
SUV
3
7
Analyze this data, and match each percentage to the description It represents. Round your answers to the nearest whole number.
30%
44%
21%
8%
42%
78%
the percentage of hatchbacks that run on gasoline
the percentage of diesel vehicles that are hatchbacks
tum. All rights reserved.
Answer:
The percentage of hatchbacks that run on gasoline: 78%
The percentage of diesel vehicles that are hatchbacks: 21 %
Step-by-step explanation:
The given table represents the following:
Hatchbacks that run on Gasoline = 18
Hatchbacks that run on Diesel = 5
Total number of hatchbacks = 23
Sedan that run on Gasoline = 15
Sedans that run on Diesel = 12
Total number of sedans = 27
SUVs that run on Gasoline = 3
SUVs that run on Diesel = 7
Total number of SUVs = 23
Total number of gasoline vehicles = 36
Total number of Diesel vehicles = 24
To find:
the percentage of hatchbacks that run on gasoline
the percentage of diesel vehicles that are hatchbacks
Solution:
[tex]\text{Percentage of hatchbacks that run on gasoline = } \dfrac{\text{Number of hatchbacks on gasoline}}{\text{Total number of hatchbacks}}\times 100\\\Rightarrow \text{Percentage of hatchbacks that run on gasoline = } \dfrac{18}{23}\times 100 \approx 78\%[/tex]
[tex]\text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{\text{Number of hatchbacks that run on diesel}}{\text{Total number of diesel vehicles}}\times 100\\\Rightarrow \text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{5}{24}\times 100 \approx 21\%[/tex]
So, the answer is:
The percentage of hatchbacks that run on gasoline: 78%
The percentage of diesel vehicles that are hatchbacks: 21%
Answer:
I used a calculator and this is what can up with
Step-by-step explanation:
For every 2 males birds in a birdcage, there are 5 females. What is the ratio of
males to females? *
Answer:
2:5
Step-by-step explanation:
The structure of a ratio is x:y.
So all you have to do is place the former as the first digit and the latter as the second and separate them by a colon.
32 is an example of A. an algebraic equation B. a numerical expression C. a numerical equation D. an algebraic expression Reset
ayuda plis nosé donde estoy q Brainli es este
ayuda
Answer:
hmm I'm not sure but i think it's B. a numerical expression
Sowwy if this didn't help :c
how do i find x?
is the formula
"the sum of exterior angles=360°" false for concaved polygons?
Answer:
To find x you need to divide polygon into trianglesThe formula : "the sum of exterior angles=360°" is false for concaved polygonsStep-by-step explanation:
α = 180° - 135° = 45°
β = 180° - 120° = 60°
γ = 180° - 60° = 120°
δ = 180° - x
ε = 180° - 80° = 100°
If we divide the pentagon into five triangles then:
5•180° = α + β + γ + δ + ε + 4x
900° = 45° + 60° + 120° + x + 100° + 4x
900° = 325° + 5x
5x = 575°
x = 115°
60° + 120° + 135° + 80° + 115° = 510° ≠ 360°
Find the area of the shape shown below.
Answer:
28
Step-by-step explanation:
We divide the shape covenientely, like this, and area 1 is 4*4=16
area 2=4*4/2=8
area 3= 2*4/2=4
Area total = Area 1 + Area 2 + Area 3=16+8+4=28