two cars in an inelastic collision . A small car with a mass of 1600kg is moving east at 55 km/hr a van with a mass of 3300 kg is moving west 65 km/hr . calculate the speed and direction of the combined vehicles just after impact

Imagine the same bouncing basketball as it is moving down, it is having a negative acceleration, as it is moving down.

This is because acceleration is defined as the rate of change of velocity, and negative acceleration occurs when an object's velocity is decreasing. The basketball is moving down, it is losing height, and its velocity is decreasing, thus it has a negative acceleration. To be more precise, the negative acceleration of the basketball is due to the force of gravity acting upon it, which is pulling it down toward the earth. The force of gravity is a constant force, acting downward, and it causes all objects to accelerate downward at a rate of 9.8 m/s^2 (on the surface of the earth). ​

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As acceleration increases from 8.0 m/s^2 to 16.0 m/s^2 in 10 seconds, the object travel during this 10 seconds is 84 meters.

To calculate the distance traveled by an object undergoing constant acceleration, we need to use the equation of motion for uniformly accelerated motion, which is given by:

d = v_0t + 0.5 at^2

where d is the distance traveled, v_0 is the initial velocity (8.0 m/s in this case), t is the time interval (10 s in this case), and a is the acceleration. To find the acceleration, we can use the following equation:

v = v_0 + at

Putting the final velocity (16.0 m/s) and the initial velocity (8.0 m/s) and the time interval (10 s), we get:

16 = 8 + a x 10

Solving for acceleration:

a = 0.8 m/s^2

Now that we have the acceleration, we can use the first equation to find the distance traveled:

d = v_0t + 0.5at^2

d = 8 x 10 + 0.5 x 0.8 x 10^2

d = 80 + 4

d = 84 m

So, the object travels 84 meters during the 10 seconds.

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The effect of the stress between the two cables acts downward on the tower below. the consequent 11.96 kN's magnitude. 8 kN is the tension force in cable ac.

Tac = 8kN [40/sqrt(402+602) I - 60/sqrt(402+602)]

Tac is equal to 4.438 i-6.656 j kN.

If the tension force in AB is T, then Tab = T is equal to T [- 50 / sqrt(502 + 602) I - 60 / sqrt(502 + 602)].

The resulting Tnet = Tac + Tab = Tab = - 0.64 T I - 0.768 T j k N (4.438 - 0.64T) Since the consequent of I - (6.656 + 0.768 T) j is along j, the component along I will be zero.

magnitude of resultant = 6.656 + 0.768 T = 6.656 + 0.768(6.91) = 11.96 kN 4.438 - 0.64 T = 0 T = 6.91 kN

Simply said, "distance or amount" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an item.

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The velocity of the jet is calculated to be 900 miles/hr when the relation between velocities of both propeller and the jet is given.

The distance travelled by a propeller plane and a jet = 3000 miles

Velocity of the plane Vp = 1/3 Velocity of the jet Vj

Vp = 1/3 Vj

Vj = 3 Vp ----(1)

Time taken by the propeller plane to complete the trip = 10 hours

Velocity of the propeller plane = Distance of the propeller plane/Time

⇒ 3000/10 = 300 miles/hr

The velocity of the jet = 3 times the velocity of the propeller plane

⇒ 3 × 300 miles/hr = 900 miles/hr

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Two 1.6 kg masses are 1.3 m apart (center to center) on a frictionless table. Each has + 9.6 µC of charge.

What is the magnitude of the electric force on one of the masses? Express your answer to two significant figures and include the appropriate units.

ANSWER:

F -0.49N

The electric force is the force experienced by a charged object that is in an electric field. The formulation of the electric force is sometimes confused with Coulomb's law, even though the electric force is more general in nature than this law, which only applies to two point charges./ the force possessed by electrically charged objects

Electric force, as is generally the case, is denoted by the letter F or usually given a small index under E  (electric) or L (electricity).

F=qE

with:

q: is the payload of the object

E : is the electric field

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The number of flights of stairs you would have to climb to equal the work of the lightbulb in this time is approximately 589 stairs.

Given that,

Mass = 88 kg

Height of stairs = 2.1 meters.

Power = 300 Watt

Time = 1 hour

To calculate how many flights of stairs you would need to travel to accomplish the same amount of work as the lightbulb in this period of time:

First, we would figure out how much effort is required to ascend a set of steps that is 2.1 metres high.

Work done, mathematically, is given as,

W = m g h = 88 × 10 × 2.1 = 1848 J

Energy is given by, E = power × time

E = 300 × 3600 = 1080000 J

We can now determine how many flights of stairs you would need to climb to accomplish the same amount of work as the lightbulb in this period:

Flights = Energy/work done = 1080000/1848 = 588.41 ≈ 589 stairs

The given question is incomplete. The complete question is 'Assume your mass if 88 kg and the acceleration of gravity is 10 m/s². How much work do you do against gravity when you climb a flight of stairs that is 2.1 meters high?'

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After the collision, cart 1 will have a velocity of v/10, and cart 2 will have a velocity of 9v/10.

The velocity of both carts after the collision can be calculated by using the conservation of momentum principle. In an elastic collision, both momentum and kinetic energy are conserved.

Before the collision, the total momentum of the system is equal to the momentum of cart 1, which is equal to m*v  where the mass of cart 1 is multiplied by its velocity.

After the collision, the total momentum of the system is equal to the combined momentum of the two carts.

Consider the velocity of carts 1 & 2 after the collision as v1 & v2.

The total momentum after the collision is:

mv1 + 9mv2 = m*v (conservation of momentum)

By solving v1 & v2, we get:

v1 = (mv) / (m + 9m) = v / 10

v2 = (9mv) / (m + 9m) = 9v / 10

So after the collision, cart 1 will have a velocity of v/10, and cart 2 will have a velocity of 9v/10.

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The power generated by the object with a mass 6 kg and accelerate from rest to 9 m/s in 9 seconds is 27 watts.

Power is energy transformed by the device per unit time.

The symbol for power is P and the unit of power is watt.

The formula used to calculate the power is as follows:

Power = [tex]\frac{E}{t}[/tex], which E is kinetic energy and t is time

To calculate the kinetic energy (E), can use the following formula :

[tex]E = \frac{1}{2} mv^{2}[/tex] or [tex]E = \frac{1}{2} m(v2^{2} - v1^{2})[/tex]

By combining both formulas above, here is the new formula that can be applied :

Power = [tex]\frac{\frac{1}{2} m(v2^{2} - v1^{2})}{t}[/tex] = [tex]\frac{\frac{1}{2} 6(9^{2} - 0^{2})}{9}[/tex] = [tex]\frac{\frac{1}{2}x6x81}{9}[/tex] = 27 watts

Thus, as the object has a mass 6 kg and accelerate from rest to 9 m/s in 9 seconds will generate power 27 watts.

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A polar molecule is usually formed when the one end of the molecule is said to possess more positive charges and whereas the opposite end of the molecule has negative charges, creating an electrical pole.

The unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that a water molecule has two poles -

a positive charge on the hydrogen pole (side) and

a negative charge on the oxygen pole (side).

We say that the water molecule is electrically polar.

A nonpolar molecule is one whose charge distribution is spherically symmetric when averaged over time; since the charges oscillate, a temporary dipole moment exists at any given instant in a so-called nonpolar molecule.

These temporary dipole moments fluctuate rapidly in magnitude and direction,…

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All of the given options are correct as the velocity of each ball is transferred via collision

Given,

5 balls are placed one after the other

the velocity of the second ball is V0

if the second ball is given the velocity, it will rebound back and hit the first one. Also, all the other balls will undergo collision due to the velocity given to the second ball.

therefore, 5 collisions will take place

as the second ball collides with the 3rd one, its momentum is transferred to the 4th and will carry on to 5th ball and thus separation velocity of 5th and 1st ball will be the same.

Again, as the collision ends up with only 1st and 2nd ball being separated by velocity V0 , then other 3 balls remain stationary

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The charge on the larger of the two-point charges is 90 coulombs

To determine the charge on the larger point charge, we can use Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the known values of the force (120 N), distance (0.5 m), and the universal constant (8.99 x 10^9 Nm^2/C^2), we can use the equation F = k(q1q2)/r^2 to solve for one of the charges.

By rearranging the equation and substituting the known values, we get q1 = (Fr^2)/k. Then by substituting the given values, we get q1 = (120 N * (0.5 m)^2) / (8.99 x 10^9 Nm^2/C^2) = 90 coulombs.

Since we know the total charge is 180 coulombs and q1 is 90 coulombs, then the charge on the second point charge would also be 90 coulombs.

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The work done on a block of certain mass when pushed with specific force is -162 J.

Mass of the block = 3 kg

Force with which the block is pushed = 12 N

Distance pushed = 9 m

The net force is nothing but the force minus the frictional force on the block.

Mathematically, Fnet = F - mg = 12 - (3×10) = -18 N

The work done is given by the formula, W = F × d

where, F is the force

d is the distance

W is the work done

Plugging in the values in equation, we have,

W = F × d = -18 × 9 = -162 J

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The work done by the car is equal to the change in kinetic energy.

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Answer:A

Explanation:

Answer:

The object's mass

The object's acceleration

Explanation:

To determine how much force was used on an object, we need to know the object's mass and acceleration. The force acting on an object can be calculated using the equation force = mass x acceleration (F = m*a) So, the more massive the object is, the more force is required to accelerate it, and the greater the acceleration is, the greater the force applied to the object.

The net work that has been done is obtained as  5.02 * 10^4J. Option B

We have to note that the work that is done is defined as the product of the force that has been applied and the acceleration of the object. In this case ,we can see that there is work that has been done as the velolcity of the object is changed.

Hence;

Work done = 1/2mΔv^2

m = mass of the object

v = velocity of the object

Thus;

Work done = 0.5 * 5020 * (21 - 41)^2

Work done =  5.02 * 10^4J

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The magnitude of resultant force of the two forces (40 N and 30 N) at right angles is 50 N.  

The Pythagorean theorem is used to calculate the consequence of two forces acting at right angles to one another. According to the Pythagorean theorem, the square of the hypotenuse, the longest side opposite the right angle, in a right triangle, equals the sum of the squares of the other two sides. (the two shorter sides).

In this instance, the two forces combine to form the triangle's two shorter sides, with the hypotenuse as the third force.

Therefore, the amount of the resulting force can be determined as follows:

⇒ √(40² + 30²) = √(1600 + 900) = √2500 = 50 N

Hence, the magnitude of the resultant force of the two forces (40 N and 30 N) at right angles is 50 N.

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Without more information about the specific characteristics and appearance of the small creatures that Shilpa found, it is difficult to determine exactly what they are.

However, there are many different types of small aquatic animals that can be found in fresh water, including insects, crustaceans, and mollusks. Some examples of small aquatic creatures that are commonly found in fresh water include:

Aquatic insects: Mayflies, stoneflies, caddisflies, and dragonflies are examples of aquatic insects that can be found in freshwater. These insects typically have a complete metamorphosis, where they go through four distinct stages in their life cycle: egg, larva, pupa, and adult.

Crustaceans: Freshwater crustaceans include crayfish, freshwater shrimp, and freshwater crabs. These animals have a complete metamorphosis, where they go through a series of stages in their life cycle, including a planktonic stage, megalopa stage, and juvenile stage before reaching adulthood.

Mollusks: Freshwater snails, freshwater mussels, and freshwater clams are examples of mollusks that can be found in freshwater. These animals typically have a complete metamorphosis, where they go through different stages in their life cycle, including a planktonic stage, a glochidium stage, and a juvenile stage before reaching adulthood.

It is important to note that without more information about the specific characteristics of the creatures that Shilpa found, it is impossible to determine their exact species and if they show complete or incomplete metamorphosis in their life cycle.

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The height the ball reaches when the boy throws the ball up in the air is 12.6m.

Given the maximum horizontal distance a boy can throw a ball (s) = 50m

The initial speed of the ball = um/s

The maximum height reached = ym

The motion in vertical direction is given as:

y = ut1 + 1/2at1^2 where v is the speed in vertical direction and a is the acceleration and t1 is the time taken to travel upward distance.

s = 0 + gt^2/2 then t = √2s/g = √2 x 50/9.8 = 3.18s

We know that as the velocity is same at any point in distance travelled distance = speed x time = 50m

So t1 = t/2 as it covers half time when reached maximum height.

The velocity (v) = gt = 9.8 x 3.18 = 31.164m/s

The maximum height reached (y) = vt1 +  1/2gt1^2 where t1 - t/2

y = vt/2 + 1/2g(t/2)^2

y = 50/2 + 1/2(9.8)(3.18/2)^2

y = 12.6m

Hence the maximum height the ball can be thrown is 12.6m.

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Cold TCS food should be stored at an internal temperature of

41° F or below.

TCS full form is Time/Temperature Control for Safety. Foods that typically spoil more quickly than other foods are referred to as TCS. These foods may either have a high initial microorganism load naturally or possess qualities that are ideal for the growth of pathogens.

The TCS food definition makes it clear that any time and temperature control has a significant impact on the foods that fall under this category. Food handlers may find it extremely beneficial to know how TCS foods behave in order to better formulate, prepare, and serve their food products to consumers. In order to avoid causing foodborne illnesses and food waste, this task is a crucial duty of both food managers and food handlers.

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The ability to do activities for more than a few minutes is called aerobic ability.

Endurance is the ability to maintain an activity for extended periods of time and usually refers to aerobic ability. For example, children can play actively for hours. We need this ability to perform repetitive activities of daily living, such as stirring food while cooking, using a hair dryer to dry our hair, or walking up steps.

Recreational and job-related activity also often require a high level of endurance. Local muscle endurance is best defined as the ability to resist muscular fatigue and demonstrate how a given type of contraction can be sustained, typically measured in terms of the number of repetitions.

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The minimum number of degrees  is  108°.

Based on the accompanying figure,

The angle of rotation from point A to point B is the smallest angle at which the star can overlap itself.

Let a° be the angle formed by A and B.

By connecting the star's vertices, we can form a pentagon.

The formula to calculate a polygon's internal angle is

The internal angle measurement is

=> 180 x (n-2)/n

=> 180 x (5-2)/5

=> 180 x 3/5

=> 36

ABC measured as:

= 108°

Since the inner angle is divided into three equal parts by a side star,

36° is the internal angle measurement.

the AOB,

The sum of a triangle's inner angles is 180 degrees, or m(OAB) + m(AOB) + m(ABO).

36° + a + 36° = 180°

a + 72° = 180°

a = 180 - 72

a = 108°

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The full question is :

What is the minimum angle of rotation (in degrees) that will carry the star onto itself?

A third charged particle (does not matter whether it is a positive or negative charged particle) can be placed in between -3q and -q at x along .

Is  equilibrium stable or unstable?

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The balls will be at the same height above the ground at 1.16s.

Equations of motion in physics are equations that explain how a physical system behaves in terms of how its motion changes over time. The behaviour of a physical system is described in more detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables.

Before they collide, the falling ball travels a distance of (20m-h), where h is the height above the earth. We submit

yf= yi + vit - 0.5 gt²

to the falling ball to obtain,

-(20-h)= - 0.5 gt²

Applying yf= yi + vit - 0.5 gt² to the rising ball gives,

h= 17.2t - 0.5gt²

Combining both equations,

t= [tex]\frac{20}{17.2}[/tex] = 1.16 s

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The new angular speed of the merry go round after the man came to the point 0m on the merry go round will be 1.37 rev/s.

The merry go round is rotating at the speed of 0.27 rev/s with a man of mass 85 kg on it at a pint of 2.2 m form he center of the axis of rotation.

We have to find the new speed of the merry go round when the person walk to the center of the circle.

The mass and radius of the merry go round are given to be 67 kg and 2.2m.

Using the conservation of momentum as the system is not under any external force,

Initial momentum = final momentum

I₁W₁ = I₂W₂

I₁ and W₁ are initial moment of inertia and angular speed, I₁ and W₁ are final moment of inertia and angular speed.

Putting values,

(85+67)(2.2)₂0.27 = (67)W₂

1.34 rev/s = W₂

So, the final angular speed is 1.34 rev/s.

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a) The gravitational force on the earth is 81 times that on the moon

b) The slope of the graph is the universal gravitational constant

c) The force is  5 * 10^19 N

d) The acceleration due to gravity is the same.

We know that the term gravity has to do with the force that acts on any object that we can be able to find on the surface of the earth. We know that the larger the mass of the object, the greater the magnitude of the gravitational force on the object.

We can see that in the question the distance between the earth and the moon was halved hence the force would now be one quarter of its initial value hence;

New force = 1/4 * 2 * 10^20

= 5 * 10^19 N

The acceleration  due to gravity does not change hence it is the same both at the surface and near the surface.

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A thermometer sensitive is a bulb with a thin glass wall. so, option (a) is correct.

What is thermometer?

A thermometer is a device that measures temperature. The three most used ways to measure temperature are in degrees Celsius, degrees Fahrenheit, and degrees kelvin. The metric system incorporates the Celsius scale.

What is thermometer sensitive?

The degree of change in a thermometer's thermometric property for a unit change in temperature is referred to as its sensitivity. It speaks of the smallest temperature difference that may be seen or quantified. The difference between the maximum and least temperature is referred to as a thermometer's range.

Therefore, a thermometer sensitive is a bulb with a thin glass wall. so, option (a) is correct.

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The acceleration of the box is 4 m/s²  to the left.

option 4 is the correct answer.

The acceleration of the box is calculated by applying Newton's second law of motion as follows;

∑F = ma

where;

F₁ - F₂ = ma

1 N - 9 N = ( 2 kg ) a

-8 N =  ( 2 kg ) a

divide both sides by 2

- 8 /  ( 2 kg ) = a

- 4 m/s² = a

Thus, the acceleration of the box will be directed to the left which has greater force.

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Answer:

C

Explanation:

it shows how forces are converted from a certain pole to the other

Equations of motion for constant acceleration to find maximum elevation, time and velocity are as follows :

y = yi + vi*t + (1/2)*a*t^2

vf = vi + a*t

V^2= U^2 + 2 a s

Givens:

vf = 0 m/s (the ball stops at the time in question)

yi = 0 m (or assume whatever initial height you wish, and add to the final answer)

a = -9.8 m/s (we can add more significant digits, but this is close enough)

b) The maximum elevation above the roof the ball will reach can be found by,  y= yi + vi*t + (1/2)*a*t^2

c)Time to reach maximum height can be obtained from v = u + at

     at = v - u

therefore, time required is t = v - u / a

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At the height of 3h/4 meter, the velocity of the baseball will be half of its original velocity v, if it reaches a maximum height h.

Maximum height reached by the baseball, = h

The velocity of the ball at maximum height v₁ = 0

Initial velocity, = v

by the 3rd equation of motion, v₁² = v² - 2gh

0 = v² - 2gh

v² = 2gh

Now let the height at which the velocity will be half of the original velocity = h₁

Then by the 3rd equation of motion,

(v/2)² = v² - 2gh₁

2gh₁ = v² - v²/4 = 3v²/4

h₁ = 3v²/8g

We know v² = 2gh, So

h₁ = 3(2gh)/8g = 3h/4 m.

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