Two companies provide home Internet services.
The first company charges a one-time fee of $55 for the equipment, plus $30 per month for the service.
The second company charges a one-time fee of $25 for the equipment, plus $45 per month for the service.
In how many months will the services of the two companies cost the same?

Answer:

3991680 or 792

Step-by-step explanation:

12P7 = 3991680

or

12C7 = 792

P = permutation

C = combination

Sorry, I am not sure which answer is correct or if any of the answers are correct.

[tex]\qquad\qquad\huge\underline{{\sf Answer♪}}[/tex]

If the given triangles are congruent, then their corresponding sides are equal as well ~

So, let's use this condition

[tex]\qquad \sf  \dashrightarrow \:2y + 5 = 3y + 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:3y - 2y = 5 - 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 3[/tex]

and

[tex]\qquad \sf  \dashrightarrow \:2x + 7 = 15[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x = 8[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 4[/tex]

Answer:

1/4 is the correct answer

Step-by-step explanation:

Even after replacing the marble the propability will not chance.

Answer:

cover an area of 404 area

Step-by-step explanation:

23*8+11*20=404(area)

Answer:

A, C, and D

Step-by-step explanation:

Let's analyze each option:

A) As supply rises, prices generally decrease. This is true as supply and demand have an inverse relationship. The supply curve has a positive slope, showing that as the quantity supplied increases, the price increases. So, shifting the curve to the right does decrease the equilibrium price (assuming the demand curve doesn't fluctuate).

B) As demand decreases, costs generally increase. This is false because a demand curve shows that as the quantity of demand increases, the price decreases for the product. So, shifting the curve to the left only decreases the equilibrium price (assuming the supply curve doesn't fluctuate).

C) As supply decreases, prices increase. This is true because the supply curve has a positive slope, showing that as the quantity supplied increases, the price increases. So, shifting the curve to the left does increase the equilibrium price (assuming the demand curve doesn't fluctuate).

D) The average rate of change describes how much a quantity changes as price increases. This is true because the supply curve measures how much the quantity supplied increases as the price increases, while the demand curve measures how much the quantity demanded increases as the price decreases.

E) As demand rises, the price of the product decreases. This is false because a demand curve shows that as the quantity of demand increases, the price decreases for the product. So, shifting the curve to the right only increases the equilibrium price (assuming the supply curve doesn't fluctuate).

I've attached an example graph to help you visualize all of these factors.

Answer:

Hi shelp >//<

[tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][/tex]

Answer:

Hi shelp >//<

[tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][tex] [/tex][/tex]

Step-by-step explanation:

enebe eeeHAHAHA

Answer:

Ans is mean .because mean means average.

Answer(s):

[tex]\displaystyle y = 4sin\:(2x + \frac{\pi}{2}) \\ y = 4cos\:2x[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 4sin\:2x,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4sin\:(2x + \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-1\frac{1}{4}\pi, 0],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{4}, 0],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

771 is the absolute value of -771.

Step-by-step explanation:

The absolute value is the distance of that number from 0. Therefore, negative or not, the number shown will always be the positive number that it is.

Examples:

|-8| = 8.

|2|=2

|-9912|=9912

|236|=236

Continued explanation:

Because the absolute value is the distance of that number from zero, the value will always be positive. And then the distance is going to be the same number.

I hope this helps!

-No one

Answer:

£29.75.

Step-by-step explanation:

15% = 0.15 as a decimal fraction.

Sale price = 35 - 0.15*35

= £29.75.

Answer:

54.03% probability that a randomly selected road has between 128 and 136 potholes per 10 miles.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean  and standard deviation, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the probability that a randomly selected road has between 128 and 136 potholes per 10 miles.

This probability is the pvalue of Z when X = 136 subtracted by the pvalue of Z when X = 128. So

X = 136

has a pvalue of 0.8849.

X = 128

has a pvalue of 0.3446.

0.8849 - 0.3446 = 0.5403

54.03% probability that a randomly selected road has between 128 and 136 potholes per 10 miles.

C

ЖStep-by-step explanationЖ

⇒ [tex]7x^2\sqrt{2x^4}\bullet\ 6\sqrt{2x^1^2}[/tex]

[tex]=7\sqrt{2}x^4\bullet 6\sqrt{2}x^6[/tex]

[tex]=84x^1^0[/tex]

[tex]So\ choose\ C[/tex]

[tex]\{square\ root\ \}.[/tex]

I hope this helps you

:)

Answer:

See attached graph

Step-by-step explanation:

We need to convert the polar coordinates into Cartesian coordinates using the rules [tex]x=r\:cos\theta[/tex] and [tex]y=r\:sin\theta[/tex] (see table in attached file).

The converted points will start to resemble a circle with a horizontal pole and a diameter of 4, so by connecting the points, we get our equation [tex]r=4\:cos\theta[/tex].

Answer:

$4.75

Step-by-step explanation:

To find the unit price (price for one), just divide $9.30 by 2. You get that one clay pot (the price for one unit) is $4.75.

Hopefully this helps- let me know if you have any questions!

Answer:

The total surface area of a solid is the sum of the areas of all of the faces or surfaces that enclose the solid. The faces include the tops and bottoms (bases) and the remaining surfaces. The lateral surface area of a solid is the surface area of the solid without the bases.

Step-by-step explanation:

Answer:

48% chance to be female and 52% chance to be male.

Step-by-step explanation:

14 female + 15 males =  29 total people

a) 14 females/29 total = 0.48... * 100 = 48%

b) 15 males/29 total = 0.57.... * 100 = 52%

Answer:

23 cubic units

Step-by-step explanation:

1st layer: 8 units
2nd layer: 7 units
3rd layer: 5 units
4th layer: 3 units

8+7+5+3 = 23
See the attachments below

Hope this helps :)

Answer:

exponential

Step-by-step explanation:

there is a multiplier of 8 between each number

Answer:

5m - 10

Step-by-step explanation:

Use distributive property;

5(m - 2)

(5 x m) (5 x -2)

5m - 10

Answer: A = and then below is incorrect then state how to find the correct answer and why it is correct.

Step-by-step explanation: hope it helps

Answer:

Θ = (π/6) + πn

Θ = (5π/6) + πn

Step-by-step explanation:

4sin²Θ + 4 = 5

            -4    -4

4sin²Θ = 1

÷4         ÷4

sin²Θ = (1/4)

√sin²Θ = √(1/4)

sinΘ = (1/2), (-1/2)

-------------------------

Θ = arcsin (1/2)

Θ = (π/6)

to find the quadrant subtract π

Θ = π - (π/6)

Θ = (5π/6)

Find the period

2π / |b|

b = 1

2π/1 = 2π

The sin Θ function is 2π, so values will repeat 2π in both directions.

Θ = (π/6) + 2πn (n is the variable)

Θ = (5π/6) + 2πn

-------------------------------------------------------------------------------------------------------

sin Θ = (-1/2)

Θ = arcsin (-1/2)

Θ = (-π/6)

To find the second function add π

Θ = 2π + (π/6) + π

Θ = (7π/6)

Find the period

2π/|b|

2π/1

2π

(-π/6) + 2π

2π       6         π

----- ×  ----- -  -----

1           6        6

Θ = (11π/6) will repeat every 2π in both directions

-------------------------------------------------------------------------------------------------------

Θ = (π/6) + 2πn

Θ = (5π/6) + 2πn

Θ = (7π/6) + 2πn

Θ = (11π/6) + 2πn

(π/6) + π = (7π/6)

(5π/6) + π = (11π/6)

Θ = (π/6) + πn

Θ = (5π/6) + πn

----------------------------------------------------------------------------------------------------------

I hope this helps!

Answer: Is Square feet/minute if there is two of them the second one is Cubic feet/minute

Step-by-step explanation: feet/minute would cover anything linear {forward, backward, left, right}

square feet/minute would cover two-dimensional areas  {walls, floors, sides of buildings, etc.}

cubic feet/minute would cover three dimensional situations  {swimming pools, buckets, containers, etc.}

Answer:

27.2

Step-by-step explanation:

sin 54 = opposite / hyp = 22 / x

sin 54 = 22/x

x = 22/sin54 = 27.2

Answer:

20 years time

Step-by-step explanation:

[tex] \frac{1}{8} = 0.125[/tex]

[tex]3 = 3[/tex]

[tex] \frac{1}{3} = 0.333[/tex]

[tex]8 = 8[/tex]

Answer:

A. y=1/8x^

Step-by-step explanation:

Answer:

First, find the time when Jackie and her friend meet.

Using:

[tex]\sf s=ut+\dfrac12at^2[/tex]

where:

Jackie and her friend are not accelerating, so a = 0, which means the formula can be reduced to:

[tex]\sf s=ut[/tex]

Create equations

Jackie:  [tex]\sf s_1= 3t[/tex]

Friend:  [tex]\sf s_2 = 12t[/tex]

As the distance covered by Jackie and her friend at the time they meet equals 3 miles:

[tex]\sf s_1+s_2=3 \ miles[/tex]

[tex]\sf \implies 3t + 12t = 3[/tex]

[tex]\sf \implies 15t = 3[/tex]

[tex]\sf \implies t = 0.2 \ hr[/tex]

[tex]\sf \implies t=0.2 \times 60=12 \ mins[/tex]

Therefore, they meet 12 mins after they both start moving.

3 mph = 3 ÷ 60 = 0.05 miles per min

12 mph = 12 ÷ 60 = 0.2 miles per min

Therefore,

Jackie traveled:  0.05 x 12 = 0.6 miles

Her friend traveled: 0.2 x 12 = 2.4 miles

when they meet.

To find the speed Jackie's brother must walk to catch up with her at the same time she meets her friend, use s = 0.6 miles (as this is the distance Jackie walked) and t = 12 - 4 = 8 mins (since he left 4 mins after Jackie left):

[tex]\sf s=ut[/tex]

[tex]\sf \implies u = \dfrac{s}{t}[/tex]

[tex]\implies \sf u = \dfrac{0.6}{8}[/tex]

[tex]\implies \sf u = 0.075 \ miles \ per \ min[/tex]

[tex]\sf \implies u = 0.075 \times 60 = 4.5 \ mph[/tex]

So Jackie's brother needs to walk faster than 4.5 mph to catch up with Jackie before she meets her friend.

(If he walks at 4.5 mph, he will catch up to Jackie at the instant she meets her friend.  If he walks slower than 4.5 mph, he will not catch up with Jackie before she meets her friend).

Answer:

0.08 I hope this is right

Step-by-step explanation:

2/5 = 0.4÷5 = 0.08

Answer:

Step-by-step explanation:

Use KCF method

K - Keep the first fraction

C- change the operation ÷ to multiplication

F - Flip the second fraction

[tex]\textbf{$\dfrac{2}{5} \div 5$}=\dfrac{2}{5}*\dfrac{1}{5}\\\\\\=\dfrac{2}{25}[/tex]

[tex] \frac{12}{16} = \frac{x}{13} [/tex]

[tex]16x = 12 \times 13[/tex]

[tex]x = \frac{12 \times 13}{16} [/tex]

[tex]x = \frac{156}{16} = 9.75[/tex]