As comparison to 15°C water, 85°C water allows the food coloring to spread out more quickly. Due to convection currents, the food coloring will only disperse halfway through the water in each beaker.
What happens to the food dye drop?Adding a few drops of food coloring to a glass of water causes it to spread out and eventually color the water. Diffusion, a process, is typically to blame for this. The blending of components in a liquid is caused by diffusion.
Water osmosis or diffusion while adding food coloring?The food coloring spreads slowly through cold water as it diffuses. Food coloring diffuses more quickly in hot water. Particles travel more quickly when temperatures are higher.
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a uniform rope hangs from a ceiling. without tugging on the rope, you give the bottom of the rope a wiggle and a wave travels upward along the rope. what can you say about the speed of the wave as the wave travels up the rope?
When a uniform rope hangs from a ceiling and you give the bottom of the rope a wiggle, the speed of the wave as the wave travels up the rope will remain constant.
A wave is a transfer of energy in which energy travels through a medium without the medium itself traveling. When the medium is influenced, this energy transmission can either be a mechanical wave, such as sound waves, or an electromagnetic wave, such as radio waves or light waves.
The way that waves transmit energy determines the characteristics of the wave.
The speed of the wave as it travels up the rope will remain constant due to the transverse nature of the wave that travels along a rope.
When a wave travels along a rope, the particles in the rope move perpendicular to the wave's direction. This is because the wave travels along a transverse plane, which means that it oscillates up and down at right angles to its propagation direction.
As a result, the rope will experience both compression and rarefaction, which will cause the wave to travel along the length of the rope in a manner that will maintain the speed of the wave constant.
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a balloon with an internal pressure of 300. torr rises to a height of 30,000 feet, where the pressure is 15. torr. assuming temperature remains constant, by what ratio did the volume change?
The volume of the balloon increased by a factor of 20 or increased by 20 times.
We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant.
Boyle's Law: P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and
P2 and V2 are the final pressure and volume.
Also we know that P1 = 300 torr, P2 = 15 torr, and V1 = V
Therefore, after substituting
300 V = 15 (V2)
V2 = 300/15
V2 = 20 V1
Therefore, the volume changed by a factor of 20 or increased by 20 times.
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4x10^-15C charged experiences a 5x10^-16N force. What is the strength of the electric field in that region of space?
Answer:
Explanation:
The electric force F exerted by the field on the positive charge is F = qE
where q is electric charge and E is electric field.
E=F/q=5 *10^-16/4*10^-15=1.25*10^-1 = 0.125N/C
a 56.2-gram tennis ball is loaded into a 1.27-kg homemade cannon. the cannon is at rest when it is ignited. immediately after the impulse of the explosion, a photogate timer measures the cannon to recoil backwards a distance of 6.1 cm in 0.0218 seconds. determine the post-explosion speed of the cannon and of the tennis ball.
A photogate timer measures the cannon to recoil backward at a distance of 6.1 cm in 0.0218 seconds. The post-explosion speed of the cannon and of the tennis ball is: 599.9 m/s
The post-explosion speed of the cannon and of the tennis ball can be determined using the impulse-momentum theorem. This theorem states that the impulse (change in momentum) is equal to the product of the average force and the time interval during which it acts.
The impulse is equal to the mass of the cannon times the change in velocity of the cannon. The mass of the cannon and the tennis ball is the sum of the mass of the cannon and the mass of the tennis ball, which is 1.326 kg. The time interval is 0.0218 seconds.
We can calculate the change in velocity of the cannon and the tennis ball using the equation impulse = mass x change in velocity. This gives us:
change in velocity = impulse / mass = (1.326 kg) x (6.1 cm) / (0.0218 s) = 599.9 m/s.
Therefore, the post-explosion speed of the cannon and the tennis ball is 599.9 m/s.
This calculation is based on the assumption that the impulse of the explosion is the same for both the cannon and the tennis ball. Therefore, the post-explosion speed of the cannon and the tennis ball is the same and equal to 599.9 m/s.
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A car wheel of radius 0.3 m has an angular acceleration of 2.45 rad/s2
. Calculate
the linear acceleration of wheel.
The linear acceleration of the car wheel is 0.735 m/s².
What is the the linear acceleration of car wheel?The linear acceleration of a point on the rim of a wheel is related to the angular acceleration of the wheel by the equation:
a = rα
Where "a" is the linear acceleration, "r" is the radius of the wheel, and "α" is the angular acceleration.
Given the data in the question;
angular acceleration of α = 2.45 rad/s² radius r = 0.3 m. linear acceleration a = ?Plug the given values into the above formula and solve for the linear acceleration of wheel.
a = r × α
a = 0.3 m × 2.45
a = 0.735 m/s²
Therefore, the linear acceleration is 0.735 m/s².
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