Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a current of 4.33 A. (a) Find the force per meter exerted on the 2.75-A wire. (b) Is the force per meter exerted on the 4.33-A wire greater than, less than, or the same as the force per meter exerted on the 2.75-A wire

Answer:

The Gas Giants have more moons.

Explanation:

Mercury-0

Venus-0

Earth-1

Mars-2

Jupiter-66

Saturn-62

Uranus-27

Neptune-13

Answer:

These linear thermal expansion coefficients are room temperature values of metals. Linear thermal expansion coefficient is defined as material's fractional change in length divided by the change in temperature.

Explanation:

The change in temperature caused is 0.0000207 K.

To calculate the change in temperature we use the formula of linear expansivity below.

⇒ Formula:

⇒ Where:

⇒ Make ΔT the subject of the equation

From the question,

⇒ Given:

⇒ Substitute these values into equation 2

Hence, the change in temperature caused is 0.0000207 K

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Answer:

a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.

Answer:

hope it is you

Answer:

0.02 kg/cm³

Explanation:

Answer:

Acceleration of the car = 5.51 m/s²

Explanation:

Given:

Initial speed of car = 0 m/s

Final speed of car = 27 m/s

Time taken by car = 4.9 seconds

Find:

Acceleration of the car

Computation:

Using first equation of motion

v = u + at

Where

v = Final velocity

u = Initial velocity

t = Time taken

a = Acceleration

So,

v = u + at

27 = 0 + a(4.9)

a(4.9) = 27

a = 5.51 m/s²

Acceleration of the car = 5.51 m/s²

Answer:

Yes, I agree with rich

Explanation:

Yes I agree with rich.

Thus is because;

The electromagnetic process is what will determine how electromagnetic radiation will be emitted. Now, the mode of travel of electromagnetic energy is in the form of waves and then the wavelength of these waves is what will enable us know the form of energy. This includes light, x-rays, gamma rays e.t.c. This means that light and the others are just parts of the spectrum emitted and are called photons.

Thus, light can be said to be electromagnetic radiation.

I can agree with Rich that light is the same as electromagnetic radiation since the two terms can conveniently be used interchangeably.

Light has become a generic term that is used to describe all electromagnetic waves. All the waves in the electromagnetic spectrum have different frequencies and wavelengths but they are travel at the same speed which has been designated as "speed of light".

Therefore, i can agree with Rich that light is the same as electromagnetic radiation since the two terms can conveniently be used interchangeably.

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Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P  = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light  = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a  = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

Answer:

conservation of linear momentum

We were told that two objects became stuck together hence we have to use the principle of conservation of  momentum to obtain the final velocities of the carts.

The principle of conservation of momentum lets us know that the momentum before collision is equal to the momentum after collision. As such we can write; m1u1 + m2u2 = m1v1 + m2v2.

We can use this thus principle to obtain the final speeds of the carts since the two objects that collided became stuck together.

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Answer:

the answer is D I tought

Solution :

Given :

Mass of grinding wheel, m = 700 g

                                             = 0.7 kg

Diameter of the grinding wheel, d = 22 cm

                                                         = 0.22 m

Radius of the grinding wheel, r = 0.11 m

Initial angular velocity of grinding wheel, [tex]$\omega_0$[/tex] = 215 rpm

                                                                               [tex]$=215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}$[/tex]

where, [tex]$\pi = \frac{22}{7}$[/tex]

Time taken to stop, t = 50 s

Final angular velocity is [tex]$\omega$[/tex] = 0

Angular acceleration of the grinding wheel is given by :

[tex]$\alpha = \frac{\omega-\omega_0}{t}$[/tex]

   [tex]$=\frac{0-215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}}{50 \ s}$[/tex]

   [tex]$=-0.45 \ rad/s^2$[/tex]

Magnitude of the angular acceleration of grinding wheel [tex]$\alpha$[/tex] [tex]$=-0.45 \ rad/s^2$[/tex]

Moment of inertia of the grinding wheel (solid disk),

[tex]$I=\frac{1}{2}mR^2$[/tex]

   [tex]$=\frac{1}{2} \times 0.7 \times 0.11^2$[/tex]

  [tex]$=4.235 \times 10^{-3} \ kgm^2$[/tex]

Torque exerted by friction while the wheel is slowing down is

[tex]$\tau = I \alpha$[/tex]

  [tex]$=4.235 \times 10^{-3} \times 0.45$[/tex]

 [tex]$=1.90 \times 10^{-3} \ Nm$[/tex]

Answer:

number 1

Explanation:

they have common ancestors

Answer:

No. Because it would correspond to zero Instantaneous acceleration.

Explanation:

hope this helps

Answer:

It will bob 7.887640449 times a minute

Explanation:

I hope this is correct!!

Answer:

By talking about something that interesto you’

sorry if wrong

Explanation:

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the concept of resistors,

The equivalent circuit is given as,

1/Rp = 1/3 + 1/6 + 1/9

1/Rp = 6+3+2/18

1/Rp = 11/18

Rp = 18/11 ==> 1.63 ==> 1.6 ohms

hence the equivalent resistance of the circuit is 1.6 ohms

The equivalent resistance of the circuit is 1.6Ω. The correct option is B.

Ohm’s law state that ” At constant temperature, the current (I) flowing through a conductor is directly proportional to the potential difference(V) across the two endpoints of the given conductor.”

I.e V ∝ I

V=IR

Where V= potential difference across the conductor.

I = current flowing through the conductor.

R= constant pf proportionality i.e resistance which unit is ohm(Ω).

There are two ways we can connect the resistors.

(i) series connection

If a number of resistors are said to be connected in series When the same current (I) flows through them.

Let R1, R2, and R3 be the resistors connected in series.

Then the R equivalent is

Req=R1+R2+R3

(ii) parallel connection

A number of resistors are said to be connected in parallel when the same potential difference(V) exists across each of them.

Let R1, R2, and R3 be the resistors connected in parallel.

Then the R equivalent is

1/Req=1/R1+1/R2+1/R3

In this question,

The three resistance connected in parallel by applying the above formula we get,

1/Req=1/R1+1/R2+1/R3

1/Req = 1/3 + 1/6 + 1/9      .................  (∵R1=3Ω,R2=6Ω AND R3=9Ω)

1/Req =11/18

Req=18/11

Req=1.6363Ω

Req≈1.6Ω

Therefore, The equivalent resistance of the circuit is 1.6Ω.

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Answer:

7.4375N

Explanation:

According to Newtons second law

F = ma

m is the mass = 140g = 0.14kg

Get the acceleration

v = u + at

8.5 = 0+0.1a

a = 8.5/0.16

a = 53.125m/s²

Get the required force

F = 0.14 * 53.125

F = 7.4375N

Hence the magnitude of the average force on the wall is 7.4375N

Answer:

Explained below.

Explanation:

For a boat or any object to float on water, it's density must be less than that of water.

Now, when the maximum capacity of people to be carried by the boat is exceeded, it's possible that the maximum mass of people will also be exceeded depending on the mass of the people in the boat.

Now, we know that; density = mass/volume.

Thus, the higher the mass of the people, the higher the density and the higher the density, the more likely it is to be above that of water and the more likely it is to sink.

Answer:

what

you need to elaborate

Answer: Can you please write question clearly.

Explanation:

Explanation:

The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.

Answer:

hi your question is incomplete below is the complete question

A charge of 2.15 mC is placed at each corner of a square 0.500 m on a side. Determine the direction of the force on a charge.

answer : Along the line between the charge and the center of the square outward of the center ( A )

Explanation:

The direction of the force on a charge is along the line between the charge and the center of the square outward of the center

Given that; Fnet = 3.17 * 10^-1 N ( calculated value )

The nature of the Force is repulsive in nature

attached below is a Pictorial representation of the direction of the force on a charge

Answer:

R = 7.915 10⁶ m,  M = 1.04 10³⁵ kg

Explanation:

Let's start by finding the acceleration of the planet's gravity, let's use the kinematic relations

           v = v₀ - g t

the velocity of the body when it falls is the same for equal height, but it is positive when it rises and negative when it falls

          v = -v₀

         -v₀ = v₀ - g t

          g = 2v₀ / t

          g = 2 15 / 2.7

          g = 11.11 m / s²

I now write the law of universal gravitation and Newton's second law

          F = m a

          G m M / R² = m a

         a = g

          g = G M / R²

Now let's work with the cruiser in orbit

         F = ma

acceleration is centripetal

         a = v² / r

         G m M / r² = m v² / r                        (1)

the distance from the center of the planet is

        r = R + h

        r = R + R = 2R

we substitute in 1

        G M / 4R² = v² / 2R

        G M / 2R = v²

The modulus of the velocity in a circular orbit is

         v = d / T

the distance is that of the circle

          d = 2π r

          v = 2π 2R / T

          v = 4π R / T

          G M / 2R = 16pi² R² / T²

          T² = 32 pi² R³ / GM

let's write the equations

             g = G M / R² (2)

             T² = 32 pi² R³ / GM

we have two equations and two unknowns, so it can be solved

let's clear the most on the planet and equalize

             g R² / G = 32 pi² R³ / GT²

              g T² = 32 pi² R

             R = g T² / 32 pi²

let's reduce the period to SI units

           T = 250 min (60 s / 1 min) = 1.5 104 s

let's calculate

             R = 11.11 (1.5 10⁴) ² / 32 π²

           R = 7.915 10⁶ m

from equation 2 we can find the mass of the planet

             M = g R² / G

             M = 11.11 (7.915 10⁶) ² / 6.67 10⁻¹¹

             M = 1.04 10³⁵ kg

Answer:

C

Explanation:

a=f/m

10Kgm/s2/4kg

2.5m/s2

When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration. The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

Given in the question, force 10 N and mass 4.0 Kg the acceleration is,

a = 10/4 = 2.5 m/sec²

When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².

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Answer:

C: Ignoring

Explanation:

On edge 2021

Answer:

It's C.

Explanation:

Answer:

[tex]9.495 \times 10^3\ m[/tex]

Explanation:

From the given information:

Using the equation of Barometric formula as related to density, we have:

[tex]\rho (z) = \rho (0) e^{(-\dfrac{z}{H})} \ \ \ \ --- (1)[/tex]

Here;

[tex]p(z) =[/tex] the gas density at altitude z

[tex]\rho(0) =[/tex] the gas density  at sea level

H = height of the scale

[tex]H = \dfrac{RT}{M_ag } \ \ \ --- (2)[/tex]

Also;

R represent the gas constant

temperature (T) a= 280 K

g = gravity

[tex]M_a =[/tex] molaar mass of gas; here, the gas is Oxygen:

∴

[tex]M_a =[/tex] 15.99 g/mol

= 15.99 × 10⁻³ kg/mol

[tex]H = \dfrac{8.3144 \times 280}{15.99 \times 10^{-3} \times 9.8 }[/tex]

[tex]H =14856.43 \ m[/tex]

Now we need to figure out how far above sea level the density of oxygen drops to half of what it is at sea level.

This implies that we have to calculate z;

i.e. [tex]\rho(z) =\dfrac{\rho(0) }{(2)}[/tex]

By using the value of H and [tex]\rho(z)[/tex] from (1), we have:

[tex]\dfrac{\rho(0) }{(2)} = \rho (0) e^{(-\dfrac{z}{14856.43})}[/tex]

∴

[tex]\dfrac{1}{2} = e^{(-\dfrac{z}{14856.43})} \\ \\ e^{(-\dfrac{z}{14856.43})} =\dfrac{1}{2}[/tex]

By rearrangement and taking the logarithm of the above equation; we have:

[tex]- z = 14856.43 \times \mathtt{In}\dfrac{1}{2} \\ \\ -z = 14856.43 \times (-0.6391) \\ \\ z = 9495 \ m \\ \\ z = 9.495 \times 10^3\ m[/tex]

As a result, the oxygen density at  [tex]9.495 \times 10^3\ m[/tex] is half of what it is at sea level.

Answer:

velocity ratio

mechanical advantage

Relative density

Answer:

a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights

b) ed lights and flashlights transform into light energy and thermal energy

c)  Em₀ = U = m gh,  Em_f = K = ½ m v²

Explanation:

In this exercise ask to complete the sentences

a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights

b) These devices transform the chemical energy stored in the batteries into other forms of energy.

Led lights and flashlights transform into light energy and thermal energy

Keyboards transform into electromagnetic energy that is emitted

clocks transform to mechanical energy from the movement of the needles

Electronic weights transforms the chemical energy of the baria into gravitational potential energy that prevents the movement of the plate and this translates into the reading of the body weight

c) The total energy of the cylinder mechanical energy when sustained is

          Em₀ = U = m gh

it is transformed as it descends into kinetic energy, at any point

          Emₙ = K + U = 1/2 m v² + m g y

at the lowest point of the trajectory all energy is transformed

           Em_f = K = ½ m v²

Answer:

Z

Explanation:

correct on edge

Answer: Z

good luck!