Answer:
a) I= I₀ (cos²θ - cos⁴θ) b) 75.5º
Explanation:
a) For this exercise we must use Malus's law
I = I₀ cos² θ
where tea is the angle between the two polarizers.
We apply this expression to our case
* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical
I₁ = I₀ cos² θ
* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.
The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical
θ₂ = 90- θ’ = θ
fiate that in the exercise we must take a reference system and measure everything with respect to this system.
I = I₁ cos² θ'
we substitute
I = (I₀ cos² tea) cos² (θ - 90)
cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ
I = Io cos² θ sin² θ
1= cos²θ+ sin²θ
sin²θ = 1 - cos²θ
I= I₀ (cos²θ - cos⁴θ)
b) to find when the intensity is maximum,
we can use that we have an extreme point when the drift is zero
[tex]\frac{dI}{d \theta}[/tex] = 0
\frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0
whereby
cos θ - 2 cos³ θ = 0
cos θ ( 1 - 2 cos² θ) = 0
The zeros of this function are in
θ = 90º
1-2cos²θ =0 cos θ = 0.25 θ = 75.5º
Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.
Consequently, the angle that allows the maximum intensity to pass is 75.5º
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. a) Find the force constant of the spring. b) Find the total energy of the oscillating system. c) Where will the object be from the equilibrium position when its velocity is -2.0 m/s (negative 2 m/s)
Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:[tex]F = - k * \Delta x (1)[/tex]
where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).Solving for k:[tex]k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)[/tex]
b)
Assuming no friction present, total mechanical energy mus keep constant.When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} (3)[/tex]
Replacing k and Δx by their values, we get:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)[/tex]
c)
When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).So, we can write the following expression:[tex]\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)[/tex]
Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:[tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)[/tex]
⇒ [tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)[/tex]
⇒ [tex]\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)[/tex]
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
Question number 11 how did we found the answer ?
Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s
If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.
What is a satellite?
Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.To know more about satellite, click the link given below:
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8. Cart 1 with mass of 2kg moving at +6m/s collides with cart 2 with a mass of 1kg,
which is at rest. If cart 1 moves at +2m/s after the collision, what is the velocity of
cart 2 after the collision? (include correct units, or you get no credit)
Answer:its 2kg
Explanation:
6. What is the wavelength of a wave that is traveling at 30 m/s and has a frequency of 3.2 Hz?
Answer:
6. 9.4 m
7. 1050 m/s.
Explanation:
6. Determination of the wavelength
Velocity (v) = 30 m/s
Frequency (f) = 3.2 Hz
Wavelength (λ) =?
v = λf
30 = λ × 3.2
Divide both side by 3.2
λ = 30 / 3.2
λ = 9.4 m
Thus, the wavelength of the wave is 9.4 m.
7. Determination of the speed of the wave.
Wavelength (λ) = 350 m
Frequency (f) = 3 Hz
Velocity (v) =.?
v = λf
v = 350 × 3
v = 1050 m/s
Thus, the speed of the wave is 1050 m/s
unit 3 test waves sps4 physics need all answers
Answer:
What is the question on the testtt
Mike is deciding which route to take to the beach. If he takes the highway, he can travel at an average velocity of 100 km/hr for 17 km. If he takes surface streets, he can travel at an average velocity of 70 km/hr for 10 km. Which is the faster route for Make to take?
Answer: Highway
Explanation:
The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.
HELP ASAP PLEASE Comparing the types and amounts of EM radiation in an object could help scientists determine an object's what? structure age chemical composition all of the above are correct
Answer: Its all of the above
Explanation:
I had the same question and got it correct
2. What is the total effect of sound produced in an enclosed space called?
Acoustics
Overtones
sound quality
Color
Answer:
Acoustics
Explanation:
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s
What is the wavelength associated with an electron with a velocity of 4.8X10s m/s? (Mass of the electron is 9.1X10-31kg)?
Answer:
1.52 nm
Explanation:
Using the De Broglie wavelength equation,
λ = h/p where λ = wavelength associated with electron, h = Planck's constant = 6.63 × 10⁻³⁴ Js and p = momentum of electron = mv where m = mass of electron = 9.1 × 10⁻³¹ kg and v = velocity of electron = 4.8 × 10⁵ m/s
So, λ = h/p
λ = h/mv
substituting the values of the variables into the equation, we have
λ = h/mv
λ = 6.63 × 10⁻³⁴ Js/(9.1 × 10⁻³¹ kg × 4.8 × 10⁵ m/s)
λ = 6.63 × 10⁻³⁴ Js/(43.68 × 10⁻²⁶ kgm/s)
λ = 0.1518 × 10⁻⁸ m
λ = 1.518 × 10⁻⁹ m
λ = 1.518 nm
λ ≅ 1.52 nm
if up is up and down is down isn't downside up , upside down
Answer:
No they arent because they are opposite to each other.
Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration would be small, but it could continue for months or years in the vacuum of space. Consider a 1200 kg uncrewed space probe powered by a 15 MW laser. After one year, how far will it have traveled and how fast will it be going
Answer:
Acceleration = 0.0282 m/s^2
Distance = 13.98 * 10^12 m
Explanation:
we will apply the energy theorem
work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )
where :
work done = p * t
= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J
( note : convert 1 year to seconds )
and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0
back to equation 1
473040000 * 10^6 = 1/2 mv^2
Vf^2 = 2(473040000 * 10^6 ) / 1200
∴ Vf = 887918.92 m/s
i) Determine how fast the rocket is ( acceleration of the rocket )
a = Vf / t
= 887918.92 / ( 1 year )
= 0.0282 m/s^2
ii) determine distance travelled by rocket
Vf^2 - Vi^2 = 2as
Vi = 0
hence ; Vf^2 = 2as
s ( distance ) = Vf^2 / ( 2a )
= ( 887918.92 )^2 / ( 2 * 0.0282 )
= 13.98 * 10^12 m
A parallel-plate capacitor is constructed of two disks spaced 2.00 mm apart. It is charged to a potential difference of 500. V. A proton is shot through a small hole in the negative plate with a speed of 2.0 × 105 m/s. What is the farthest distance from the negative plate that the proton reaches?
Answer:
[tex]0.000835\ \text{m}[/tex]
Explanation:
d = Distance between plates = 2 mm
V = Potential difference = 500 V
v = Velocity of proton = [tex]2\times 10^5\ \text{m/s}[/tex]
a = Acceleration
m = Mass of proton = [tex]1.67\times 10^{-27}\ \text{kg}[/tex]
Electric field is given by
[tex]E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{500}{2\times 10^{-3}}\\\Rightarrow E=250000\ \text{V/m}[/tex]
Force balance is given by
[tex]ma=qE\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times 250000}{1.67\times 10^{-27}}\\\Rightarrow a=2.395\times 10^{13}\ \text{m/s}^2[/tex]
We have the relation
[tex]v^2=u^2+2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(2\times 10^5)^2-0}{2\times 2.395\times 10^{13}}\\\Rightarrow s=0.000835\ \text{m}[/tex]
The farthest distance from the negative plate that the proton reaches is [tex]0.000835\ \text{m}[/tex].
The farthest distance from the negative plate that the proton reaches will be s=0.000835 m
What is electric field?The electric field is defined as the force across the charged particles which attract or repel the other charged particles.
Now it is given in the question that
d = Distance between plates = 2 mm
V = Potential difference = 500 V
v = Velocity of proton = [tex]2\times 10^5\ \dfrac{m}{s}[/tex]
a = Acceleration
m = Mass of proton = [tex]1.67\times10^{-27} kg[/tex]
The Electric field will be calculated as
[tex]E=\dfrac{V}{d}[/tex]
[tex]E=\dfrac{500}{2\times10^{-3}} =250000\ \frac{V}{m}[/tex]
Force balance is given by
[tex]ma=qe[/tex]
[tex]a=\dfrac{qE}{m}[/tex]
[tex]a=\dfrac{1.6\times10^{-19}\times250000}{1.67\times10^{-27}}[/tex]
[tex]a=2.395\times 10^{13}\frac{m}{s^2}[/tex]
Now from equation of motion
[tex]v^2=u^2+2as[/tex]
[tex]s=\dfrac{v^2-u^2}{2a}[/tex]
[tex]s=\dfrac{(2\times10^5)^2-0}{2\times 2.395\times 10^{13}}[/tex]
[tex]s=0.000875 m[/tex]
Thus the farthest distance from the negative plate that the proton reaches will be s=0.000835 m
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What would be the mass of an atom with 2 protons and 3 neutrons?
Answer:
5
Explanation:
From the question given above, the following data were obtained:
Proton number = 2
Neutron number = 3
Mass number =.?
The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:
Mass number = proton + neutron
With the above formula, we can obtain the mass number of the atom as follow:
Proton number = 2
Neutron number = 3
Mass number =.?
Mass number = proton + neutron
Mass number = 2 + 3
Mass number = 5
Thus, the mass number the atom is 5.
How do these terms relate to what is being attempted when making a nuclear
bomb (quick, explosive effect) as opposed to a nuclear power plant (controlled
steady production of energy)?.
Answer:
More than four-fifths of the single points of light we observe in the night sky are actually two or more stars orbiting together. The most common of the multiple star systems are binary stars, systems of only two stars together.o
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brake and the train comes to a halt in 135 sevonds several meters before the car. What was the train's accleration during the emergency?
Answer:
final velocity = 0
because the train stoped
so,
acceleration = (v - u) ÷ tacceleration = (0 - 22) ÷ 135acceleration = -22 ÷ 135acceleration = -0.162 m/s²Someone please help me
What effect would lowering the temperature have on this reaction?
3H2 + N2 + 2NH3 + energy
A. H2 and N2 would react to produce more NH3.
B. The reaction would proceed more slowly in both directions.
C. Decreasing the temperature would not have an effect on this
reaction.
D. NH3 would react to produce more H2 and N2.
On lowering the temperature of the given reaction, H₂ gas and N₂ gas would react to produce more NH₃. Therefore, option (A) is correct.
What is the effect of temperature on equilibrium?When the chemical reaction is exothermic then increasing the temperature will cause the backward reaction to occur, decreasing the amounts of the products while increasing the amounts of reactants. Lowering the temperature will produce more reactants and cause the reaction to occur in the forward direction.
The formation of the ammonia is an exothermic reaction that can be represented as:
N₂ (g) + 3 H₂ (g) ⇄ 2NH₃ (g)
If the temperature will be decreased, the chemical reaction will proceed forward to produce more heat. The effect of temperature on equilibrium will change the value of the equilibrium constant of the chemical reaction. The production of more ammonia on lowering the temperature.
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what are the materials that you have illustrated?
Answer:
An illustration is a decoration, interpretation or visual explanation of a text, concept ... such as posters, flyers, magazines, books, teaching materials, animations, video games and films.
Explanation:
choose the correct answer 14: which of the following force follows the inverse square law of distance A: gravitaional force B: electromagnetic force C: both (a) and (b) D: none of these
Answer:
C. both A and B
Explanation:
Sana nakatulong
The amplitude of a wave function representing a moving particle can change from positive to negative values in the domain (0, a) over which the wave function is defined. It must therefore pass through zero at some value x0, where 0 < x0 < a. Therefore the probability of the particle being at x0 is zero and the particle can't get from a position x < x0 to a position x > xo.
Required:
Is this reasoning correct?
Answer:
Explanation:
In a standing wave function[tex]\psi (x,t) = A sin(kx)[/tex] characterized for x between (0.a). on the off chance that the amplitude of the wave interchange from positive to negative at the interval. there probably been a node at [tex]x_0[/tex], among 0 and a to such an extent that [tex]0<x_0 <a[/tex]. The reasoning is right that the likelihood of discovering the particle at the node [tex]x_0[/tex] is 0 in light of the fact that by definition, the nodes of the wave are the place where the wave function falls and is equivalent to 0. Since the likelihood of discovering a particle at a position [tex]x_0[/tex] at time [tex]t_0[/tex], is provided by [tex]P=|\psi(x_0,t_0)|^2 dx[/tex], this implies that at the nodes of a standing wave,
[tex]P = | \psi (x_0,t_0)|^2 \ dx \\ \\ P = |0|^2 dx \\ \\ P = 0[/tex]
So the reasoning that the likelihood of the particle being at [tex]x_0[/tex] is 0 is right.
However, to examine whether the particle can travel from a position [tex]x <x_0[/tex] to a position of [tex]x_0>x[/tex]. All together words, can the molecule be found on one or the other side of the node?
The appropriate response is yes.
Recall that in quantum mechanics. wave functions at most present with the likelihood of discovering a particle at a specific time inside a time frame. The wave function doesn't present with an old classical actual trajectory that a particle should follow to go in space: all things being equal, it simply yields chances of whether a particle can be found in a specific spot at a specific time. So the reasoning that a particle can't get from a position [tex]x <x_0[/tex] to a position of [tex]x>x_0[/tex], is incorrect.
A 50 kg crateis being pushed on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk= 0.1, what is push force f ( friction)?
Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage
Answer:
D. A lower Voltage into a higher
1. Lucky Larry was in a car crash. He hit a brick wall going 40 mph. But his airbag
inflated and saved him because
A. it reduced the time of the collision.
B. it reduced his initial velocity.
C. it reduced his change in momentum.
D.it reduced his average
force.
Answer:
The answer is D (It reduced his average
force.)
9.
A 2.85-cm diameter coin is placed a distance of 31.4 cm from a diverging lens that has a focal length
of-11.6 cm. Determine the image distance and the diameter of the image.
Answer:
image distance = -8.47 cm
diameter of the image = 0.769 cm