Answer:
[tex]\frac{T_x}{T_y} = 22.63[/tex]
Explanation:
Kepler's third law is an application of Newton's second law for circular motion
T² = K a³
let's apply this expression for each satellite
satellite X
Tₓ² = K aₓ³
satellite Y
[tex]T_y^2 = K a_y^3[/tex]
the relation of the periods is
[tex]\frac{T_x}{T_y} = \sqrt{ (\frac{a_x}{a_y} )^3 }[/tex]
they indicate us
aₓ = 8 a_y
substitutes
[tex]\frac{T_x}{T_y} = 8^{3/2}[/tex]
[tex]\frac{T_x}{T_y} = 22.63[/tex]
Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
Answer:
The answer is B
Explanation:
I WILL REPORT YOU IF YOU DON'T ANSWER QUESTION OR POST OTHER LINKS
Rank these objects in order of their resistance to change in motion (from greatest to least).
A. pyramid, cone, sphere, cube
B. cube, pyramid, cone, sphere
C. sphere, cone, pyramid, cube
D. None of the above
Answer:
pyramid, cone, sphere, cube
Sonya hears water dripping from the eaves of the house onto a porch roof. She counts 30 drops in 1.0 min.
Explain how grality and electric charge are different
Help please & actually answer thank youu :)
Answer:
highest KE and lowest GPE = Dhighest GPE and lowest KE = Asome KE and some PE = BA car covers 8m in the first second and 12m in the second second. Find
a) Initial Velocity
b) Acceleration
c) Distance covered in the third second
Explanation:
Given that,
Distance travelled by the car in first second = 8 m⠀⠀⠀⇒ S′ = u + a/2(2n ― 1)
⠀⠀⠀⇒8 = u + a/2× [2(1) ― 1]
⠀⠀⠀⇒8 = u + a/2× [2 ― 1]
⠀⠀⠀⇒8 = u + a/2× 1
⠀⠀⠀⇒8 = u + a/2⠀⠀⠀⠀⠀ … ( 1 )
And,
Distance travelled by the car in second second = 12 m⠀⠀⠀⇒ S″ = u + a/2(2n ― 1)
⠀⠀⠀⇒12 = u + a/2× [2(2) ― 1]
⠀⠀⠀⇒12 = u + a/2× [4 ― 1]
⠀⠀⠀⇒12 = u + a/2× 3
⠀⠀⠀⇒12 = u + 3a/2⠀⠀⠀⠀ … ( 2 )
Subtract ( 1 ) from ( 2 ).
⠀⠀⠀⇒12 ― 8 = u + 3a/2 ― (u + a/2)
⠀⠀⠀⇒4 = u + 3a/2 ― u ― a/2
⠀⠀⠀⇒4 = 3a/2 ― a/2
⠀⠀⠀⇒4 = 2a/2
⠀⠀⠀⇒4 × 2 = 2a
⠀⠀⠀⇒8 = 2a
⠀⠀⠀⇒8 ÷ 2 = a
⠀⠀⠀⇒4 m/s² = a⠀⠀⠀⠀⠀[Ans]
Substitute the value of a in equation ( 1 ).
⠀⠀⠀⇒8 = u + a/2⠀⠀⠀⠀⠀ … ( 1 )
⠀⠀⠀⇒8 = u + 4/2
⠀⠀⠀⇒8 = u + 2
⠀⠀⠀⇒8 ― 2 = u
⠀⠀⠀⇒6 m/s = u⠀⠀⠀⠀⠀[Ans]
Now, distance travelled in third second.
⠀⠀⠀⇒ S′″ = u + a/2(2n ― 1)
⠀⠀⠀⇒ S′″ = 6 + 4/2 × [2(3) ― 1]
⠀⠀⠀⇒ S′″ = 6 + 2 × [6 ― 1]
⠀⠀⠀⇒ S′″ = 6 + 2(5)
⠀⠀⠀⇒ S′″ = 6 + 10
⠀⠀⠀⇒ S′″ = 16 m⠀⠀⠀⠀⠀[Ans]
Explain how the fountain pen is filled up with ink
Answer:
It is because of air pressure
Explanation:
Filling a fountain pen with ink involves various methods, but the most common approach uses a piston or converter mechanism.
To begin, the pen is prepared by removing the cap and separating the barrel from the grip section. The type of filling system is checked, whether it's a built-in piston or a removable converter.
For a piston-filling method, the knob is twisted counterclockwise to retract the piston. The nib is submerged in the ink bottle, and by turning the knob clockwise, the piston extends, creating a vacuum that draws ink into the reservoir through capillary action.
The piston is then retracted, sealing the ink inside. In the case of a converter, it is removed from the grip section and dipped into the ink bottle, followed by operating the plunger or squeezing to expel air.
Releasing the plunger allows ink to enter the converter through atmospheric pressure. After cleaning any excess ink, the pen is reassembled.
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A car travels 60km in 45 minutes. At the same average speed, how far will it travel in 1 hour 30 minutes?
Please solve it.... Urgent
Answer:
a) ferromagnetic type, b) superconductor or ferromagnetic
Explanation:
In substances, magnetism is the result of the magnetic moments of the electrons in their orbits and of the spin.
These two let us take interacting magnetic between them, if the sum of these magnetic moments is maximum we have a material of the ferromagnetic type, which is represented in figure a, where all the magnetic moments are aligned in one direction and this type of material is a magnet permanent.
Figure b shows a material where the magnetic moments have a circular shape, so the total moment is zero.The type of substrate material can have several possibilities
* The most test is that the substrate material is a superconductor where the marked areas are the superconducting magnetic areas and the areas without spine are the normal areas
* Another possibility is that the material is ferromagnetic, that is, there are several magnetic sub-networks in different orientation, resulting in a random field, the material is not a permanent magnet
A standard 1kilogram weight is a cylinder 50.5mm in height and 52.0mm in diameter. What is the density of the meterial?(kg/m^3)
Answer:
The correct answer is - 93.24×10^4 kg/m^3.
Explanation:
Given:
height of cylinder: 50.5 mm
diameter = 52.0
then radius will be diameter/2 = 52/2 = 26
Formula:
Density = mass/ volume
Volume = πr^2h
solution:
Now the volume of a cylinder is v = (22/7)×r^2×h
= 22/7×26×26×50.5
= 107261.59 mm^3
Now volume in cubic meter V =10.7261 ×10^(-5) m^3
So density d = m/V = 1/(10.7261 ×10^(-5))
Or d = 93.24×10^4 kg/m^3
What happens when a neutral atom gains an electrons?
Answer:
The neutral atom becomes an anion.
Explanation:
When a neutral atom gains an electron (e−), the number of protons (p+) in the nucleus remains the same, resulting in the atom becoming an anion (an ion with a net negative charge).
A pulley in the shape of a solid cylinder of mass 1.50 kg and radius 0.240 m is free to rotate around a horizontal shaft along the axis of the pulley. There is friction between the pulley and this shaft. A light, nonstretching cable is wrapped around the pulley, and the free end is tied to a 2.00 kg textbook. You release the textbook from rest a distance 0.900 m above the floor. Just before the textbook hits the floor, the angular speed of the pulley is 10.0 rad/s. What is the speed of the textbook just before it hits the floor
Answer:
the speed of the textbook just before it hits the floor is 2.4 m/s
Explanation:
Given the data in the question;
mass of pulley = 1.50 kg
radius of pulley = 0.240 m
mass of text book = 2.0 kg
height from which text book was released = 0.9 m
angular speed of the pulley = 10.0 rad/s
the speed of the textbook just before it hits the floor = ?
the speed of the textbook v = angular speed of the pulley × radius of pulley
we substitute
v = 10.0 rad/s × 0.240 m
v = 2.4 m/s
Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s
The sensor on a door for a home security system consisted of a small coil of wire
embedded in the doorframe, and a small steel disk on the door opposite the coil.
When the door was opened, what characteristic of the coil changed for the home
security system?
Answer:
Probably electromagnetism
Explanation:
When the door is closed, the steel disk on the door is in close proximity to the coil of wire in the doorframe. This creates a magnetic field around the coil, which induces a small current in the coil.
What is the magnetic field?Ampere's law, which says that the magnetic field created by a current-carrying wire is proportional to the current and inversely proportional to the distance from the wire, may be used to describe the magnetic field produced by a long straight wire carrying a current.
When the door is opened, the steel disk moves away from the coil, which causes the magnetic field to weaken. As a result, the current induced in the coil decreases. This change in current is detected by the home security system as a change in the magnetic field and is interpreted as the door being opened.
In other words, the characteristic of the coil that changes when the door is opened is the amount of current induced in it. The decrease in the magnetic field as the steel disk moves away from the coil results in a decrease in the induced current, which signals to the home security system that the door has been opened.
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Please answer the one you know!
Pushing open door .action force and reaction
Answer: Newtons third law
Explanation: According to Newton's third law of motion, forces always act in equal but opposite pairs. Another way of saying this is for every action, there is an equal but opposite reaction. This means that when you push on a wall, the wall pushes back on you with a force equal in strength to the force you exerted.
Newton's third law we find that the reaction to the force is an out applied by the putting door towards to the person.
given parameters
Push the door open
to find
The reaction
Newton's third law states that the forces between bodies always occur in pairs, that is, the two bodies interacting with each other, therefore these forces are of equal magnitude, but opposite direction. Consequently each force acts on one of the bodies, these forces are called action and reaction.
By applying Newton's third law to the open door; we exert a force on the door therefore the door exerts a force of equal magnitude, but opposite direction on us.
Using Newton's third law we find that the reaction to the force is an out applied to the person.
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Which of the following best describes
pollutants?
A. harmful substances in the air, water, or soil
B. radioactive particles that pass through the atmosphere
C. oxygen molecules that are released by plants
D. beneficial substances that increase overall health
Answer:
A. harmful substances in the air, water, or soil
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Answer:
is the amount of matter in this object
Table 1 contains data about two completely ionised samples of pure boron.
Each sample contains only isotopes X and Y.
Table 1
Sample | Number of ions Mass of Charge on
number in sample = ple / kg each ion/ C
fot | 3.50 x 1016 6.31 x 107! +1.60 x 10719
3.50 x 10” 6.20 x 10°? +1.60 x 10°?
Deduce which sample, 1 or 2, contains a greater percentage of isotope Y.
[3 marks]
Answer:
I think it would most likely be 2... but not so sureee
a disk of radius 10 cm speeds up from rest. it turns 60 radians reaching an angular velocity of 15 rad/s. what was the angular acceleration?
b. how long did it take the disk to reach this velocity?
Answer:
a) α = 1.875 [tex]\frac{rad}{s^{2} }[/tex]
b) t = 8 s
Explanation:
Given:
ω1 = 0 [tex]\frac{rad}{s}[/tex]
ω2 = 15 [tex]\frac{rad}{s}[/tex]
theta (angular displacement) = 60 rad
*side note: you can replace regular, linear variables in kinematic equations with angular variables (must entirely replace equations with angular variables)*
a) α = ?
(ω2)^2 = (ω1)^2 + 2α(theta)
[tex]15^{2}[/tex] = [tex]0^{2}[/tex] + 2(α)(60)
225 = 120α
α = 1.875 [tex]\frac{rad}{s^{2} }[/tex]
b)
α = (ω2-ω1)/t
t = (ω2-ω1)/α = (15-0)/1.875 = 8
t = 8 s
What is the angle of refraction for a beam of light moving from a prism to air if the angle of incidence is 30° and the prism’s index of refraction is 1.6?
Answer:
Refraction involves passing through a boundary (choice a) and changing speed (choice ... A ray of light in air is incident on an air-to-glass boundary at an angle of 30. ... If the index of refraction of the glass is 1.65, what is the angle of the refracted ray ... The critical angle is the angle of incidence (which is always in the more ...
Explanation:
A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude Ap and frequency fp. Use v for the speed of sound. Part A Find the maximum sound frequency that you would hear at a position directly above the siren. At what point in the motion of the platform is the minimum frequency heard
Answer:
he maximum frequency occurs when the denominator is minimum
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
Explanation:
This is a doppler effect exercise, where the sound source is moving
f = fo [tex]\frac{v}{v-v)s}[/tex] when the source moves towards the observer
f ’=f_o [tex]\frac{v}{v+v_{sy}}[/tex] Alexandrian source of the observer
the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
a
Ten 2.2 v cells each having an internal
resistance of o.1ohms in are connected in series
to a load of 21ohm. Determine
pd at the battery terminals
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
A textbook of mass 2.10 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.100 m , to a hanging book with mass 3.10 kg . The system is released from rest, and the books are observed to move a distance 1.29 m over a time interval of 0.850 s . Part A What is the tension in the part of the cord attached to the textbook
Answer:
the tension in the part of the cord attached to the textbook is 7.4989 N
Explanation:
Given the data in the question;
As illustrated in the image below;
first we determine the value of the acceleration,
along vertical direction; we use the second equation of motion;
y = ut + [tex]\frac{1}{2}[/tex]a[tex]_y[/tex]t²
we substitute;
0 m/s for u, 1.29 m for y, 0.850 s for t,
1.29 = 0×0.850 + [tex]\frac{1}{2}[/tex]×a[tex]_y[/tex]×(0.850)²
1.29 = 0.36125a[tex]_y[/tex]
a[tex]_y[/tex] = 1.29 / 0.36125
a[tex]_y[/tex] = 3.5709 m/s²
Now when the text book is moving with acceleration , the dynamic equation will be;
T₁ = m₁a[tex]_y[/tex]
where m₁ is the mass of the text book ( 2.10 kg )
a[tex]_y[/tex] is the vertical acceleration ( 3.5709 m/s² )
so we substitute
T₁ = 2.10 × 3.5709
T₁ = 7.4989 N
Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N
Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
PLEASE HELP! I'LL GIVE BRAINLEST
Answer:
8.162
Explanation:
W=mg
= 2.2 x 3.71
= 8.162 N
Guys can you please help me with this
Which lists the springs in order of increasing spring constant?
W, Y, X, Z
OW, Y, Z, X
O Z, X, Y, W
OX,Z,Y, W
Answer:
is there supposed to be a picture?
Explanation:
The correct order of the springs in increasing spring constant is: W, Y, X, Z. The correct option is A.
What is the spring constant?Spring constant, also known as force constant or stiffness, is a measure of the resistance of a spring to deformation when a force is applied to it. It is defined as the amount of force required to stretch or compress a spring by a given distance.
The formula for the spring constant is:
k = F/x
Where
k = is the spring constant,
F = is the applied force,
x =is the displacement or deformation of the spring.
The unit of spring constant is newtons per meter (N/m) in the SI system of units, or pounds per inch (lb/in) in the Imperial system.
A higher spring constant means that a spring is stiffer and requires more force to be stretched or compressed by a given distance. A lower spring constant means that a spring is more flexible and requires less force to be stretched or compressed by a given distance. The spring constant is an important property of springs, which are used in various applications, such as in suspension systems, mattresses, and mechanical watches.
Here in the Question,
In order to determine the order of increasing spring constant, we need to compare the given springs and see which one requires more force to stretch or compress.
Therefore, The correct order of the springs in increasing spring constant is: W, Y, X, Z. This is because the spring constant increases as we move from W to Z.
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Someone please help me...
the distance from the Earth to the sun equals 1 AU. Neptune is 30 AU from the sun. How far is Neptune from the Earth?
Answer:
1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.
Short Answer: it is 29
Explanation:
sorry if its wrong
Answer:
29
Explanation:
I just took a test! not only that but the other person who answered this question had the corrected answer.
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1 E
e. 1 to 1
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is 5 to 1 C.
We have that for the Question, it can be said that the ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
Option B
From the question we are told
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1
e. 1 to 1
Generally the equation for the average speed of Molecules is
mathematically given as
[tex]For Helium\\\\C_h=\frac{8P_hV_h}{\pim_h}\\\\Neon gas\\\\C_n=\frac{8P_nV_n}{\pim_n}\\\\Where\\\\Ph=P_n\\\\Vh=Vn\\\\[/tex]
[tex]\frac{C_h}{C_n}=\frac{\frac{8P_hV_h}{\pim_h}}{\frac{8P_nV_n}{\pim_n}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{\frac{1}{5}}{{\frac{1}{5}}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{5}{1}[/tex]
Therefore
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
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3.
Two Cars, A and B, (starting, at the same time, from the same point) are moving
with average speeds of 40 km/h and 50 km/h, respectively, in the same direction.
Find how far will Car B be from Car A after 3 hours.
Answer:
car B will be 30 Km ahead of car A.
Explanation:
We'll begin by calculating the distance travelled by each car. This is illustrated below:
For car A:
Speed = 40 km/h
Time = 3 hours
Distance =?
Speed = distance / time
40 = distance / 3
Cross multiply
Distance = 40 × 3
Distance = 120 Km
For car B:
Speed = 50 km/h
Time = 3 hours
Distance =?
Speed = distance / time
50 = distance / 3
Cross multiply
Distance = 50 × 3
Distance = 150 Km
Finally, we shall determine the distance between car B an car A. This can be obtained as follow:
Distance travelled by car B (D₆) = 150 Km
Distance travelled by car A (Dₐ) = 120 Km
Distance apart =?
Distance apart = D₆ – Dₐ
Distance apart = 150 – 120
Distance apart = 30 Km
Therefore, car B will be 30 Km ahead of car A.