The acceleration of the boat is 30 miles per hour per hour.
To solve this problem, we need to convert the time from minutes to hours since the speed is given in miles per hour.
30 minutes = 0.5 hours
We can use the formula:
Acceleration = (Final Speed - Initial Speed) / Time
where,
Initial Speed = 45 mph
Final Speed = 60 mph
Time = 0.5 hours
Acceleration = (60 mph - 45 mph) / 0.5 hours
Acceleration = 30 mph/h
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--The complete question is, A boat is traveling at a speed of 45 mph, then the captain orders to accelerate until the speed is 60 mph. If the operation lasts for 30 minutes. Find the acceleration.--
water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a cylinder of mass 50 kg and diameter 25 cm. as you turn this cylinder with a crank, the rope raises the bucket. if the mass of a bucket of water is 20 kg, what torque must you apply to the crank to raise the bucket of water at a constant speed?
m_c (mass of cylinder)=50 kg
d=25 cm so r=12.5 cm = 0.125 m m_b
(mass of bucket)=20 kg
So using the equations: RT = � = I � RT= I � (m_b)g-T= (m_b)aR And from what I understand, this is the same as the tangential acceleration? (m_b)g-T=(m_b) � r = F T= ( i � ) / r (m_b)g -(( i � ) / r ) = m � r � ( ((m_b)r) + (I /R ) ) = (m_b)g Leaving us with the final : � = ((m_b)g)/(((m_b)r) + (I /r)) Using this equation, I found I = 0.390625 and the final answer would be 35 rad/s^2 Sorry for such a long post--this is my first time on the website and I read the rules so hopefully I've done everything correctly! Thank you all!
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how far from the nut of the guitar must a fret (and your finger) be placed on this string to play g (392 hz )?
To play G note (392 Hz) on a guitar string, place the fret and your finger at a distance of approximately 40.4 cm (or 16 inches) from the nut of the guitar.
The distance that the fret and your finger must be placed from the nut of the guitar is determined by the length of the string that is allowed to vibrate when the string is plucked. The length of the vibrating string determines the frequency of the sound produced by the guitar string.
The distance from the nut of the guitar to the fret that must be placed to play a G note with a frequency of 392 Hz can be calculated using the formula:
[tex]L = (v / 2f) * (n^2 - 1)[/tex]
where L is the length of the string from the nut to the fret, v is the velocity of the wave (which is dependent on the tension and mass per unit length of the string), f is the frequency of the note, and n is the fret number (with n=1 corresponding to the distance from the nut to the first fret).
For a standard guitar tuning and using typical values for the velocity of the wave and string tension, the distance from the nut to the third fret would be approximately 40.4 cm to play a G note with a frequency of 392 Hz.
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a drawing, provided by the manufacturer, that details permitted interconnections between the intrinsically safe and associated apparatus or between the nonincendive field wiring apparatus or associated nonincendive field wiring apparatus is called a
The drawing provided by the manufacturer, which details the permitted interconnections between intrinsically safe and associated apparatus or between nonincendive field wiring apparatus or associated nonincendive field wiring apparatus, is called a wiring diagram.
A wiring diagram typically includes detailed information about the wiring connections between components, as well as any necessary safety measures such as grounding or shielding. It may also include information about the voltage, current, and power requirements of the system, as well as any limitations or restrictions on the use of particular components or configurations.
This diagram is a critical part of the installation and maintenance process for intrinsically safe and nonincendive electrical systems, as it helps ensure that the correct connections are made and that the system operates safely and effectively.
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The complete question is:
A drawing, provided by the manufacturer, that details permitted interconnections between the intrinsically safe and associated apparatus or between the nonincendive field wiring apparatus or associated nonincendive field wiring apparatus is called a ______________
what is the quantum number of an electron confined in a 5.4- nm -long one-dimensional box if the electron's de broglie wavelength is 1.8 nm ?
The calculation produced a non-integer number using the supplied inputs. The values provided may include approximations or rounding mistakes as a result.
How can the de-Broglie wavelength of an electron at a certain speed be determined?The following is a definition of the deBroglie wavelength: Lambda is the Greek letter for wavelength, while h, Planck's constant, m, and v are the particle's mass and velocity.
The following equation describes the energy levels of an electron contained in a one-dimensional box:
E = (n² * h²) / (8 * m * L²)
An electron's de Broglie wavelength is determined by: λ = h / p
The following equation can be used to link an electron's energy and momentum: E = p² / (2 * m)
In the equation above, we can solve for p by inserting the expression for and obtain: p = h / λ
Using this expression as p's replacement in the energy equation, we obtain: E = (n² * h² * λ²) / (8 * m)
The box's length, L, and de Broglie's wavelength,, are both given as 5.4 nm and 1.8 nm, respectively. Planck's constant, h = 6.626 x 10⁻³⁴ J*s, and the mass of an electron, m = 9.1094 x 10⁻³¹ kg, respectively.
In the following equation, we can solve for n by substituting these numbers. The result is:
n = sqrt(8 * m * E) / (h * λ)
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a circuit breaker is rated for a current of 15 a rms at a voltage of 240 v rms. (a) what is the largest value of imax that the breaker can carry?
The largest value of I_max that the breaker can carry is approximately 21.21 A.
Given a circuit breaker rated for 15 A RMS at 240 V RMS, we want to find the largest value of Imax (maximum current) that the breaker can carry. To do this, we'll use the following formula:
I_max = √2 * I_RMS
Where I_RMS is the rated current in RMS, which is 15 A in this case.
Substitute the value of I_RMS into the formula:
Imax = √2 * 15 A
Calculate the value of Imax:
Imax ≈ 21.21 A
Therefore approximately 21.21 A is the largest value of Imax that the breaker can carry.
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the command module of the apollo spacecraft can be modelled as a truncated cone with a base diameter of 3.9 meters, a diameter at the upper (apex) end of 1.3 meters and a length of 3.5 meters. suppose the base of the spacecraft is encircled by a metal ring which is an excellent conductor. the magnitude and direction of the earth's magnetic field do not vary significantly over a distance the size of the spacecraft. if the spacecraft is oriented while in orbit so that its long axis is parallel to the earth's magnetic field, which has a magnitude of 1.0 x 10-4 t, and it then rotates about a perpendicular axis, which one of maxwell's equations allows us to calculate how much current will flow in the metal ring?
The Maxwell's equation that allows us to calculate the current flowing in the metal ring is Faraday's Law of Electromagnetic Induction, which states that the magnitude of the induced EMF (electromotive force) is equal to the rate of change of magnetic flux through a conducting loop.
In this case, the rotating Apollo spacecraft generates a changing magnetic flux through the metal ring due to its motion through the Earth's magnetic field. Therefore, an EMF is induced in the metal ring, which causes a current to flow.
To calculate the magnitude of this current, we need to know the rate of change of the magnetic flux through the metal ring. This can be found by taking the time derivative of the magnetic flux. Since the spacecraft is rotating about a perpendicular axis, the magnetic flux through the metal ring will vary sinusoidally with time. Therefore, we can express the time-varying magnetic flux through the metal ring as:
Φ(t) = Φmax sin(2πft)
where Φmax is the maximum magnetic flux through the metal ring, f is the frequency of the spacecraft's rotation, and t is time.
Taking the time derivative of this expression, we get:
dΦ/dt = Φmax (2πf) cos(2πft)
This expression gives us the rate of change of magnetic flux through the metal ring, which is proportional to the induced EMF. Finally, by applying Ohm's Law (V = IR) to the metal ring, we can calculate the current flowing in the ring. The current is given by:
I = V/R
where V is the induced EMF and R is the resistance of the metal ring. The resistance of the ring depends on its material properties and dimensions.
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at the sea level the plane can takeoff at the speed of 150 mi/hr. what is the required takeoff speed at albuquerque
The indicated airspeed (IAS) of the aircraft should be raised by roughly 2% for every 1,000 feet above sea level, according to a pilot's rule of thumb.
In order to generate enough lift during takeoff from a sea level airport, an aeroplane must attain a specific speed. Less dense air can be found at higher altitudes, such at Albuquerque, where the airport is situated at an altitude of 5,355 feet above sea level.
This necessitates a faster takeoff speed. Generally speaking, the plane's takeoff speed must rise by around 2% for every 1,000 feet of height. Under normal conditions and with conventional aeroplane characteristics, the estimated necessary takeoff speed at Albuquerque would be roughly 166 miles per hour.
The indicated airspeed (IAS) of the aircraft should be raised by roughly 2% for every 1,000 feet above sea level, according to a pilot's rule of thumb.
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higher takeoff speed to generate enough lift to take of
The required takeoff speed at Albuquerque would depend on several factors such as altitude, temperature, and runway length. If Albuquerque is at a higher altitude than sea level, the air is less dense and the plane would require a higher takeoff speed to generate enough lift to take off.
Additionally, if the temperature is higher, the air is less dense and the plane would also require a higher takeoff speed. The length of the runway at Albuquerque would also play a role in determining the required takeoff speed. Without more specific information, it is difficult to provide an exact answer to your question.
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help me please oml 2 one
Color: Both the bromine gas and steak have a brownish color.
What is bromine gas?Bromine gas is a reddish-brown, nonflammable, and highly toxic gas with a very strong, unpleasant odor. It is composed of two heavy, diatomic, halogen molecules, Br2, and is the only nonmetal element that exists as a liquid at room temperature. Bromine gas is denser than air and is soluble in water and organic solvents.
Texture: The bromine gas is a gas and therefore has no texture, while the steak is solid and has a firm texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the steak, which is at room temperature.
Bromine Gas and Juice:
Color: The bromine gas is brownish and the juice is a yellowish or orange color.
Texture: The bromine gas is a gas and therefore has no texture, while the juice is a liquid and has a smooth texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the juice, which is at room temperature.
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Power supplies are rated for efficiency based on. drawn to supply sufficient power to the PC. a. volts b. watts c. amperes d. ohms. Study These Flashcards.
B. Power supplies are rated for efficiency based on watts. The efficiency of a power supply is determined by the ratio of its output power (in watts) to its input power (also in watts).
The lesser the effectiveness, the lower power is wasted as heat and the lesser the power given to the computer's factors. In addition to effectiveness, power inventories are rated for maximum affair power, which is generally expressed in watts. This standing represents the loftiest quantum of power that the power force can deliver to the computer's factors.
Other conditions, similar as voltage and amperage conditions for their different affair connections, may be assigned to power inventories. The maximum voltage and current that the power force can produce on each connection are indicated by these conditions. Ohms, on the other hand, are a resistance unit that's infrequently used to grade power force.
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A 3. 0-kg mass moving in the positive x direction with a speed of 10 m/s collides with a 6. 0-kg mass initially at rest. After the collision, the speed of the 3. 0-kg mass is 8. 0 m/s, and its velocity vector makes an angle of 35° with the positive x axis. What is the magnitude of the velocity of the 6. 0-kg mass after the collision?
The magnitude of the velocity of the 6.0 kg mass after the collision is approximately 1.7 m/s.
We can solve this problem using conservation of momentum and conservation of kinetic energy. Conservation of momentum states that the total momentum of a system is conserved if there are no external forces acting on it. In this case, the system is the two masses.
Let p1 and p2 be the initial momenta of the 3.0 kg and 6.0 kg masses, respectively, and p1' and p2' be their final momenta after the collision. Since the 6.0 kg mass is initially at rest, we have:
p1 = m1v1 = (3.0 kg)(10 m/s) = 30 kg·m/s
p2 = m2v2 = (6.0 kg)(0 m/s) = 0 kg·m/s
After the collision, the 3.0 kg mass moves at an angle of 35° with a speed of 8.0 m/s. We can break its velocity into x- and y-components:
vx = v1' cos(35°) = 8.0 m/s cos(35°) ≈ 6.6 m/s
vy = v1' sin(35°) = 8.0 m/s sin(35°) ≈ 4.6 m/s
The total momentum of the system after the collision is:
p1' + p2' = m1v1' + m2v2'
We can use conservation of momentum to say that p1 + p2 = p1' + p2', so:
p1' + p2' = 30 kg·m/s
Substituting in the known values, we have:
(3.0 kg)(6.6 m/s) + (6.0 kg)v2' = 30 kg·m/s
Solving for v2', we get:
v2' = (30 kg·m/s - 19.8 kg·m/s) / 6.0 kg ≈ 1.7 m/s
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019 (part 1 of 2) 10.0 points
A Carnot engine has a power output of
197 kW. The engine operates between two
reservoirs at 20◦C and 425◦C.
How much thermal energy is absorbed each
hour?
Answer in units of J.
020 (part 2 of 2) 10.0 points
How much thermal energy is lost per hour?
Answer in units of J.
Thermal energy is absorbed each hour is 13.53 x 10¹² J and thermal energy lost per hour is 7.092 x 10¹² J.
What is the Carnot engine's operating principle?a technique of isothermal gas expansion that is reversible. In this process, the ideal gas in the system receives amount heat from a heat source at a high temperature Thigh, expands and does work on surroundings. a technique of adiabatic gas expansion that is reversible. The system is thermally insulated throughout this process.
Temp_cold = 20°C + 273.15 = 293.15 K
Temp_hot = 425°C + 273.15 = 698.15 K
efficiency = 1 - (Temp_cold / Temp_hot)
= (698.15 K * 293.15 K) / (698.15 K)² - (293.15 K)²
efficiency = 0.524 or 52.4%
thermal energy absorbed/ hour = power output / efficiency
= 197 kW / 0.524
= 375.95 MJ/h x 3.6 x 10⁶ J/kWh = 13.53 x 10¹² J
thermal energy is lost per hour
W = power output x time = 197 kW x 1 h = 197 kWh
W = 197 kWh x 3.6 x 10⁶ J/kWh = 7.092 x 10¹²1J
Since the engine is running in a cycle, the system's internal energy is equal to zero, hence U = 0.
Q = ΔU + W
hence, thermal energy lost per hour = Q = W = 7.092 x 10^11 J
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What is the receiving body of the force?
To answer this question, more context is needed, since force can be exerted by one object on another object. In this case, the body receiving the force would be the object that receives the force, that is, the object on which the force is being exerted. For example, if a person pushes a box, the receiving body of the force would be the box, since it is receiving the force exerted by the person.
Answer:
The question is not quite clear but the receiving body of a force will be the object on which the force is being exerted upon. Hope this helps.
a classmate bought a new digital thermometer for her child and tried it on herself a few times with these results: 97.3°f, 98.0°f, 99.0°f, and 97.7°f. calculate her mean temperature.
The mean temperature of her child with the following results 97.3°F, 98.0°F, 99.0°F, and 97.7°F is 98° F
The mean temperature is also known as the average of the temperature taken by her with the digital thermometer. The digital thermometer is used to measure the temperature of the body by placing it either orally or axially.
The mean temperature is calculated as the ratio of the sum of all the temperatures recorded and the number of times the frequency with which temperature is recorded.
It can be written as = [tex]= \frac{T_1+T_2+....T_N}{N}[/tex]
where N is the number of observations
Therefore mean temperature
[tex]=\frac{97.3+98.0+99.0+97.7}{4}\\\\=\frac{392}{4}\\\\[/tex]
=98° F
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Your classmate's mean temperature is 98°F.
Solution - Hi! To calculate the mean temperature of your classmate after using the digital thermometer, follow these steps:
1. Add up the temperatures: 97.3°F + 98.0°F + 99.0°F + 97.7°F = 392°F
2. Count the number of temperature readings: 4
3. Divide the total temperature by the number of readings: 392°F / 4 = 98°F
Your classmate's mean temperature is 98°F.
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what is the weight of a cubic meter of cork? could you lift it? (use 400 kg/m^3 for the density of cork.)
To lift this weight, you would need a force greater than or equal to 3,920 N (assuming you are lifting it vertically).
weight = [tex]1 m^3 \times 400 kg/m^3 \times9.8 m/s^2[/tex]
weight = 3,920 N
Force is a physical quantity that describes the interaction between objects or systems. The SI unit of force is the Newton (N), which is defined as the amount of force required to accelerate a one kilogram mass at a rate of one meter per second squared.
Force is also responsible for deformations in solid objects, such as stretching or compressing a spring. Nuclear forces are responsible for the interactions between subatomic particles, and frictional forces are the forces that resist motion when two surfaces come into contact. Gravitational force is the force that pulls objects towards each other due to their masses. Electromagnetic force is responsible for the interactions between charged particles, such as in electricity or magnetism.
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. for schrodinger's equation of the h2 molecule, the kinetic energy has contributions from a. electrons only b. nuclei only c. both electrons and nuclei d. only one electron and one nucleus
The kinetic energy in Schrödinger's equation for the H2 molecule includes contributions from both electrons and nuclei. Thus the correct option is C.
The kinetic energy term in Schrödinger's equation for the H2 molecule refers to the energy involved in the motion of the particles. The H2 molecule comprises two hydrogen nuclei and two electrons, therefore the electrons and the nuclei both contribute to the kinetic energy.
The nuclei contribute to the kinetic energy by their mobility, whereas the electrons do so through their wave-like behaviour. The H2 molecule's kinetic energy term in Schrödinger's equation includes contributions from both electrons and nuclei, making option C the right response.
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The kinetic energy in Schrödinger's equation for the H2 molecule includes contributions from both electrons and nuclei. Thus the correct option is C
explanation - For Schrödinger's equation of the H2 molecule, the kinetic energy has contributions from both electrons and nuclei. This is because the kinetic energy term in the equation accounts for the motion of all particles in the system, which in this case includes both the electrons and nuclei of the H2 molecule. Therefore, options a, b, and d are incorrect.
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The majority of Venus's surface is:
A. volcanic plains with flowing lava.
B large, flat mesas with tiny valleys.
C. thick, soupy clouds of hydrogen.
D. frozen dunes of dust and sand.
Answer:
C.
Explanation:
When Venus surface get bit cold when weather hits the planet gets soupy clouds and etc.
as the afterload is increased, how did the latency change
Latency increases as afterload increases because it takes the muscle more time to generate enough muscle tension to overcome the added resistance of the increased afterload.
The muscle needs to develop a greater force to shorten and lift the added load, resulting in a delay or lag time before the contraction begins. This delay is the latency, which increases as the afterload increases. Once the muscle tension is great enough to overcome the afterload, the muscle can then contract and move the load. This phenomenon is due to the properties of the muscle fibers and the amount of energy required to generate muscle tension, which increases with greater afterload.
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what is the typical voltage drop (in volts) across the collector and emitter (vce) of a bjt when in saturation?
The VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V.
How VCE voltage drop in saturation for a typical BJT?The voltage drop across the collector and emitter (VCE) of a bipolar junction transistor (BJT) when it is in saturation depends on several factors such as the type of BJT, the collector current, and the biasing conditions.
However, as a general rule of thumb, the VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V, depending on the specific characteristics of the transistor. This value may vary based on the operating conditions and the specific transistor used.
It's worth noting that the VCE voltage drop in saturation is typically lower than the voltage drop in the active region, where the BJT behaves as a current amplifier. In the active region, the VCE voltage drop can range from a few tenths of a volt up to several volts, depending on the transistor's characteristics and operating conditions.
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A bow is drawn so that it has 40 J of potential energy. When fired, the arrow will have a kinetic energy of: Select one: O a. 80) o b. 20) O 0.60) O d. 40)
When a bow is drawn and has 40 J of potential energy, the arrow's kinetic energy when fired will be:
Your answer: d. 40 J
Explanation:
Potential energy is the energy that an object possesses due to its position, configuration, or state of being. It is stored energy that has the potential to do work in the future. The amount of potential energy that an object has depends on its position or configuration relative to other objects or systems. For example, a bow that is pulled back has potential energy that can be released as kinetic energy when it is released.
Kinetic energy, on the other hand, is the energy that an object possesses due to its motion. It is the energy that an object possesses because it is in motion and is able to do work by causing a change in another object's motion or position. The amount of kinetic energy that an object has depends on its mass and its velocity. For example, a moving car has kinetic energy that can be transferred to another object if it collides with it.
When the bow is drawn, it stores potential energy. When fired, this potential energy is converted into kinetic energy for the arrow. In an ideal situation with no energy loss, the arrow's kinetic energy will be equal to the bow's potential energy. Therefore, the arrow will have a kinetic energy of 40 J.
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.A cannonball is launched upward with a velocity of 73.5 m/s at an angle of 20 degrees above the
horizontal.
(a) How long is the cannonball in the air?
(b) How far away does it land?
() How high does it travel? Cut your time in half!
Answer:
time of flight=( 2U sinx ) ÷ g
Explanation:
a)
u=73.5m/s , x= 20° , g =10m/s^2 then t= {2×73.5 × sin 20°} ÷ 10 = 134.2 ÷ 10 = 13.42 sec b) range is the distance, range= (u^2 sin 2 x ) ÷g = ({73.5 }^2 × sin 2 × 20 )÷ 10 =4025.3÷10 = 402.53meters. I couldn't finish the question so sorry
15) monochromatic coherent light shines through a pair of slits. if the distance between these slits is decreased, which of the following statements are true of the resulting interference pattern? (there is more than one correct choice.) a) the distance between the maxima stays the same. b) the distance between the maxima decreases. c) the distance between the minima stays the same. d) the distance between the minima increases. e) the distance between the maxima increases.
Two of the correct statements regarding this are:
b) the distance between the maxima decreases
d) the distance between the minima increases
When monochromatic coherent light shines through a pair of slits, an interference pattern is created. This pattern is dependent on the distance between the slits. If the distance between the slits is decreased, the resulting interference pattern will be affected.
When the distance between the slits is decreased, the interference pattern becomes wider, and the distance between the maxima decreases. The distance between the minima, on the other hand, increases.
This is because the interference pattern is created by the interaction of waves, and when the distance between the slits is decreased, the waves interfere with each other differently.
This causes the pattern to shift and change. Therefore, the resulting interference pattern is affected by the distance between the slits.
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Two point charges are separated by 25. 0 cm (see (Figure 1)). Assume that q1 = -7. 50 nC and q2 = -10. 5 nC.
Figure1 of 1Two negative point charges are placed on a dashed horizontal line. The charge on the left is q subscript 1, and the charge on the right is q subscript 2. The charges are separated by a distance of 25. 0 centimeters. Two points are marked at the dashed line. Point A is marked 10. 0 centimeters to the left of charge q subscript 2, and point B is marked 10. 0 centimeters to the left of charge q subscript 1.
Two negative point charges are placed on a dashed horizontal line. The charge on the left is q subscript 1, and the charge on the right is q subscript 2. The charges are separated by a distance of 25. 0 centimeters. Two points are marked at the dashed line. Point A is marked 10. 0 centimeters to the left of charge q subscript 2, and point B is marked 10. 0 centimeters to the left of charge q subscript 1.
Part A
Find the net electric field these charges produce at point A.
Express your answer in newtons per coulomb
The net electric field at point A is 3.58 x 10^7 N/C, directed towards q₂.
To find the net electric field at point A, we need to first find the electric field due to each charge individually, and then add them up vectorially. The electric field due to a point charge is given by:
E = kq/r²
where k is Coulomb's constant, q is the charge of the point charge, and r is the distance between the point charge and the point where the electric field is being calculated.
For point A, the distance between q₁ and A is 35 cm (25 cm between q₁ and q₂ + 10 cm between q₂ and A), and the distance between q₂ and A is 10 cm. Therefore, the electric field due to q₁ at A is:
E₁ = kq₁/r₁² = (9.0 x 10^9 N*m²/C²)(-7.50 x 10^-9 C)/(0.35 m)²
= -1.95 x 10^6 N/C
The negative sign indicates that the electric field due to q₁ is directed towards the charge itself. Similarly, the electric field due to q₂ at A is:
E₂ = kq₂/r₂² = (9.0 x 10^9 N*m²/C²)(-10.5 x 10^-9 C)/(0.10 m)²
= -3.78 x 10^7 N/C
The negative sign here also indicates that the electric field due to q₂ is directed towards the charge itself.
To find the net electric field at A, we add these two electric fields vectorially. Since the electric fields are in opposite directions, we subtract their magnitudes:
|E_net| = |E₁| - |E₂| = 3.58 x 10^7 N/C
The direction of the net electric field is towards q₂, which is the direction of E₂.
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a common way to describe acceleration is to express it in multiples of g, earth's gravitational acceleration. if a dragster accelerates at a rate of 39.2 m/s2, how many g's does the driver experience?
The acceleration of the dragster in multiple of g, when he accelerates at a rate of 39.2 m/s², is 4g.
To express the acceleration of the dragster in multiples of g, we need to divide the acceleration by the acceleration due to gravity on Earth.
Number of g's = (Acceleration of the dragster) / (Earth's gravitational acceleration)
First, we need the value of Earth's gravitational acceleration, which is approximately 9.81 m/s².
Now, we can use the given acceleration of the dragster (39.2 m/s²) and the formula:
Number of g's = (39.2 m/s²) / (9.81 m/s²) = 4
Therefore, the driver of the dragster experiences an acceleration equivalent to about 4 times the acceleration due to gravity on Earth.
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If a vehicle starts to skid on water (hydroplane), the driver should ease off the accelerator, brake gently and gently steer back onto the pavement. (true or false)
If a vehicle starts to skid on water (hydroplane), the driver should ease off the accelerator, brake gently and gently steer back onto the pavement True.
If a vehicle starts to skid on water (hydroplane), it means that the tires have lost contact with the road and are riding on a thin layer of water, resulting in a loss of traction and control. To regain control of the vehicle, the driver should ease off the accelerator to reduce the speed, and gently steer the vehicle back onto the pavement.
Braking should be done gently, as sudden braking can cause the wheels to lock up and increase the risk of a spin-out or loss of control. It is important for drivers to stay calm and focused during hydroplaning to avoid accidents.
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True. To restore control, the driver should gradually release the gas, softly use the brakes and turn the car back onto the roadway.
This is due to the fact that hydroplaning makes it challenging to regulate the direction and speed of the vehicle since it happens when the tyres lose contact with the road due to a layer of water. If the brakes are used too firmly, the wheels may lock up and the skid will worsen. To regain control of the vehicle, it is crucial to avoid making abrupt moves and instead make small adjustments. Additionally, keeping adequate tyre tread depth and the right tyre pressure might aid in avoiding hydroplaning altogether.
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Which word best describes something that works in the same way as a radar
The word that best describes something that works in the same way as a radar is "sonar".
Sonar is an acronym for "sound navigation and ranging," and it is a technology that uses sound waves to detect and locate objects underwater. Sonar works by emitting a sound wave or pulse and then measuring the time it takes for the sound to bounce back from an object and return to the source. This information is then used to calculate the distance to the object and its location. Like radar, sonar is used in a variety of applications, including military, scientific, and commercial.
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the james webb space telescope is scheduled to launch in 2018. in what range of the electromagnetic spectrum will it operate?
The James Webb Space Telescope is designed to operate primarily in the infrared portion of the electromagnetic spectrum, with a wavelength range of 0.6 to 28 microns.
What is the James Webb Space TelescopeThe James Webb Space Telescope (JWST) is a large, infrared-optimized space telescope that was originally scheduled to launch in 2018, but has since been delayed multiple times.
The range for JWST is a much wider range than the Hubble Space Telescope, which operates mainly in the visible and ultraviolet parts of the spectrum. By studying the infrared light emitted by stars and galaxies, the JWST will be able to observe objects that are too faint or too distant to be seen by other telescopes, and will provide new insights into the early universe, the formation of galaxies, and the formation of stars and planetary systems.
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Please help I need to answer fast the fate of my graduation depends on it.
First, we need to find the total mass of the system by adding the masses of the two objects: m_total = m1 m2 = 50.0 kg 75.0 kg = 125.0 kg Next, we can plug in the given force and mass values into the equation: F = ma 40.0 N = 125.0 kg * a Solving for a: a = 40.0 N
125.0 kg * a
Solving for a:
a = 40.0 N / 125.0 kg
a = 0.32 m/s^2
Therefore, the acceleration of the system is 0.32 m/s^2.
credit-card magnetic strips experiments carried out on the television show mythbusters determined that a magnetic field of 1000 gauss is needed to corrupt the information on a credit card's magnetic strip. (they also busted the myth that a credit card can be demagnetized by an electric eel or an eelskin wallet.) suppose a long, straight wire carries a current of 6.5 a . part a how close can a credit card be held to this wire without damaging its magnetic strip? express your answer using two significant figures.
A credit card can be held up to 1.04 cm away from the wire with a magnetic field of 1000 gauss.
How close can a credit card be held to this wire without damaging its magnetic strip?We can use the formula for the magnetic field around a long, straight wire to calculate the magnetic field at a certain distance from the wire:
B = μ0I / (2pi*r)
where B is the magnetic field, μ0 is the permeability of free space (4pi10^-7 T*m/A), I is current, and r is the distance from the wire.
We want to find the maximum distance r such that the magnetic field is less than 1000 gauss (0.1 tesla). We can rearrange the formula to solve for r:
r = μ0I / (2pi*B)
Plugging in the values given, we get:
r = (4pi10^-7 Tm/A)(6.5 A) / (2pi0.1 T) = 1.04 cm
Therefore, a credit card can be held up to 1.04 cm away from the wire without damaging its magnetic strip, rounded to two significant figures.
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standing waves result from the superposition of two waves that have group of answer choices the same amplitude, frequency, and direction of propagation. the same amplitude and frequency and opposite directions of propagation. the same amplitude, slightly different frequencies, and the same direction of propagation. the same amplitude, slghtly different frequencies, and opposite directions of propagation.
The correct option is B, Standing waves result from the superposition of two waves that have the same amplitude and frequency and opposite directions of propagation .
Amplitude is a fundamental concept in physics and refers to the maximum displacement or distance of an oscillating system from its equilibrium position. It is commonly used to describe the magnitude of a wave or vibration, and is measured in units such as meters or volts.
In the context of waves, amplitude represents the maximum height or depth of the wave crest or trough, and is often used to describe the intensity or strength of the wave. In sound waves, amplitude is directly related to the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds. In electrical engineering, amplitude refers to the maximum voltage or current of an alternating current (AC) waveform.
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Complete Question:-
Standing waves result from the superposition of two waves that have
a. the same amplitude, frequency, and the direction of propagation.
b. the same amplitude and frequency and opposite directions of propagation .
c. the same amplitude, slightly different frequencies, and the same direction of propagation.
d.the same amplitude, slightly different frequencies, and opposition directions of propagation
if the display is located 12.8 cm from the 12.0- cm focal length lens of the projector, what is the distance between the screen and the lens?
The distance between the screen and the lens of the projector is approximately 6.19 cm.
To determine the distance between the screen and the lens of the projector, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens (12.0 cm)
v = distance of the image (screen) from the lens (unknown)
u = distance of the object (display) from the lens (12.8 cm)
Plugging in the values into the lens formula:
1/12.0 = 1/v - 1/12.8
Now, let's solve for v:
1/v = 1/12.0 + 1/12.8
1/v = (12.8 + 12.0) / (12.0 * 12.8)
1/v = 24.8 / 153.6
v = 153.6 / 24.8
v ≈ 6.19 cm
Therefore, the distance between the screen and the lens of the projector is approximately 6.19 cm.
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