Un objeto cuesta $9200 perot iene un aumento del 16% por iva, cuanto tendre que pagar por el?

The observed mean service time falls within the current control limits. We can conclude that the process is stable, the service time is in control, and it meets the required specifications.


1. Calculate the process capability index (Cpk) using the formula: Cpk = min((USL - mean)/3σ, (mean - LSL)/3σ), where USL is the upper specification limit, LSL is the lower specification limit, mean is the observed mean service time, and σ is the standard deviation.
2. Plug in the values: USL = 5 minutes, LSL = 3 minutes, mean = 4 minutes, σ = 0.2 minutes.
3. Calculate Cpk: Cpk = min((5-4)/(3*0.2), (4-3)/(3*0.2)) = min(0.556, 0.556) = 0.556.
4. Since the calculated Cpk is greater than 1, the process is considered capable and the service time is in control.
5. The current control limits (3.1 and 4.9 minutes) are wider than the specification limits (3 and 5 minutes) and the observed mean (4 minutes) falls within these control limits.
6. Therefore, the process is stable and meets the specifications.

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Using triple integration, the volume of tetrahedron cut from the plane 2x + y + z = 4 is [tex]\frac{16}{3}[/tex].

A tetrahedron is nothing but a three dimensional pyramid.

To find the volume of tetrahedron cut from the plane 2x + y + z = 4, we need to first take one of the three dimension as base. Let as take xy plane as base.

XY as plane implies z = 0, equation becomes 2x + y = 4. To find the limits of X and Y, we put y = 0.

Thus, 2x + 0 = 4 , implying, x = 2.

Thus the range of x is : [0,2]

Putting the value of x in the given equation, the range of y is [0, 4 - 2x]

Similarly, range of z becomes: [0, 4 - 2x - y]

Since z is dependent upon y and x, and, y is dependent on x, Therefore the order of integration must be z, then y and then x.

The volume of tetrahedron becomes:

[tex]=\int\limits^0_2 \int\limits^{4-2x}_0 \int\limits^{4-2x-y}_0 {1} \, dz \, dy \, dx \\\\=\int\limits^0_2 \int\limits^{4-2x}_0 4-2x-y \, dy \, dx \\\\=\int\limits^0_2[ (4-2x)y - \frac{y^2}{2}]^{4-2x}_0 dx\\ \\=\int\limits^0_2 (4-2x)^2 - \frac{1}{2} (4-2x)^2 dx\\\\[/tex]

[tex]=\int\limits^2_0 {\frac{1}{2}(16+4x^2-16x )} \, dx \\\\=\int\limits^2_0(8+2x^2-8x)dx\\\\=[8x+\frac{2}{3} x^3-4x^2]^2_0\\\\=\frac{16}{3}[/tex]

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The complete question is given below:

Use triple integration to find the volume of tetrahedron cut from the plane 2x + y + z = 4.  

The z-score associated with a raw score of 68 is 1.8.

Given mean = 50 and standard deviation = 10.

Z-score is also known as standard score gives us an idea of how far a data point is from the mean. It indicates how many standard deviations an element is from the mean. Hence, Z-Score is measured in terms of standard deviation from the mean.

The formula for calculating the z-score is given as

z = (X - μ) / σ

where X is the raw score, μ is the mean and σ is the standard deviation.

In this case, the raw score is X = 68.

Substituting the given values in the formula, we get

z = (68 - 50) / 10

z = 18 / 10

z = 1.8

Therefore, the z-score associated with a raw score of 68 is 1.8.

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The amount of Insurance on the home as $216,000, but the amounts of coverage for the garage, loss of use, and personal property cannot be determined without additional information.

To calculate the amounts of coverage for the different components, we need to use the given replacement value and coverage percentages.

a. Amount of insurance on the home:

The amount of insurance on the home can be calculated by multiplying the replacement value by the coverage percentage for the home. In this case, the coverage percentage is 80%.

Amount of insurance on the home = Replacement value * Coverage percentage

Amount of insurance on the home = $270,000 * 80% = $216,000

b. Amount of coverage for the garage:

The amount of coverage for the garage can be calculated in a similar manner. We need to use the replacement value of the garage and the coverage percentage for the garage.

Amount of coverage for the garage = Replacement value of the garage * Coverage percentage for the garage

Since the replacement value of the garage is not given, we cannot determine the exact amount of coverage for the garage with the information provided.

c. Amount of coverage for the loss of use:

The amount of coverage for the loss of use is usually a percentage of the insurance on the home. Since the insurance on the home is $216,000, we can calculate the amount of coverage for the loss of use by multiplying this amount by the coverage percentage for loss of use. However, the percentage for loss of use is not given, so we cannot determine the exact amount of coverage for loss of use with the information provided.

d. Amount of coverage for personal property:

The amount of coverage for personal property can be calculated by multiplying the insurance on the home by the coverage percentage for personal property. Since the insurance on the home is $216,000 and the coverage percentage for personal property is not given, we cannot determine the exact amount of coverage for personal property with the information provided.

the amount of insurance on the home as $216,000, but the amounts of coverage for the garage, loss of use, and personal property cannot be determined without additional information.

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The sum of the arithmetic sequence is -468 (option D).

To find the sum of an arithmetic sequence, we can use the formula:

Sum = (n/2) * (first term + last term)

In this case, the first term of the sequence is 4, and the common difference between consecutive terms is -3. We need to find the last term of the sequence.

To find the last term, we can use the formula for the nth term of an arithmetic sequence:

last term = first term + (n - 1) * common difference

In this case, the last term is -56. We can use this information to find the number of terms (n) in the sequence:

-56 = 4 + (n - 1) * (-3)

-56 = 4 - 3n + 3

-56 - 4 + 3 = -3n

-53 = -3n

n = -53 / -3 = 17.67

Since the number of terms should be a whole number, we round up to the nearest whole number and get n = 18.

Now, we can find the sum of the arithmetic sequence:

Sum = (18/2) * (4 + (-56))

Sum = 9 * (-52)

Sum = -468

Therefore, the sum of the arithmetic sequence is -468 (option D).

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All the students in an algebra class took a 100-point test. Five students scored 100, each student scored at least 60, and the mean score was 76. What is the smallest possible number of students in the class Let the number of students in the class be n. The total marks obtained by all the students = 100n.

The total marks obtained by the five students who scored 100 is 100 x 5 = 500.As per the given condition, each student scored at least 60. Therefore, the minimum possible total marks obtained by n students = 60n.Therefore, 500 + 60n is the minimum possible total marks obtained by n students.

The mean score of all students is 76.Therefore, 76 = (500 + 60n)/n Simplifying the above expression, we get: 76n = 500 + 60n16n = 500n = 31.25 Since the number of students must be a whole number, the smallest possible number of students in the class is 32.Therefore, there are at least 32 students in the class.

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