Una piedra se deja caer desde la azotea de un edificio tarda en llegar 8 segundos al suelo, determina:

a)altura del edificio

b)velocidad con la que se chocó en el suelo

a) An unbiased estimator for λ is [tex]\hat{\lambda}=\frac{1}{n}\sum Y_i[/tex]

b) E(C) = 4λ - λ²

c) [tex]\hat{C}=4\hat{\lambda}-(\hat{\lambda})^2[/tex] is an unbiased estimator of E(C).

(a) To find an unbiased estimator for λ, we can use the sample mean. The sample mean is an unbiased estimator for the population mean of a Poisson distribution.

Therefore, an unbiased estimator for λ is:

[tex]\hat{\lambda}=\frac{1}{n}\sum Y_i[/tex]

where n is the sample size and [tex]\sum Y_i[/tex] is the sum of the observed breakdowns.

(b) The weekly cost of repairing the breakdowns is given by C = -3Y + Y². To find the expected value of C, we need to compute E(C).

E(C) = E(-3Y + Y²)

Using linearity of expectation, we can split this into two parts:

E(C) = E(-3Y) + E(Y²)

Since Y follows a Poisson distribution with mean λ, we know that E(Y) = λ.

E(C) = -3E(Y) + E(Y²)

The second term E(Y²) can be computed using the variance of Y.

Var(Y) = λ

E(Y²) = Var(Y) + (E(Y))²

= λ + λ²

= λ(1 + λ)

Substituting this back into E(C):

E(C) = -3E(Y) + E(Y²)

= -3λ + λ(1 + λ)

= λ + λ² - 3λ

= λ² - 2λ

E(C) = 4λ - λ²

Therefore, E(C) = 4λ - λ²

(c) To find an unbiased estimator of E(C), we need to find a function of Y₁, Y₂, ..., Yₙ that is an unbiased estimator of E(C). Let's call this estimator [tex]\hat{C}[/tex].

[tex]\hat{C}=4\hat{\lambda}-(\hat{\lambda})^2[/tex]

Since [tex]\hat{\lambda}[/tex] is an unbiased estimator of λ (as derived in part (a)), [tex]\hat{C}[/tex] is an unbiased estimator of E(C).

Therefore, [tex]\hat{C}=4\hat{\lambda}-(\hat{\lambda})^2[/tex] is an unbiased estimator of E(C).

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Answer:

y = -3x - 1

Step-by-step explanation:

Pick any 2 points on the line and find the slope, m:  

(-1, 2) and (1, -4)

m = (-4 - 2) / (1 - -1) = -6/2 = -3

The y-intercept, b,  is -1  (read it right off the graph, where the line passes through the y axis).

Equation of the line in y = mx + b form:

y = -3x - 1

The response variable in this study is the yield of the crop, as it is the variable that is being measured to see if it is affected by the amount of rainfall.

In a statistical study, the response variable is the variable of interest that is being measured or observed. It is the outcome that we want to understand, predict, or explain.

The response variable can be a numerical quantity, such as height, weight, temperature, or yield, or it can be a categorical variable, such as gender, species, color, or rating.

The choice of a response variable is crucial in a statistical study, as it determines the research question and the type of analysis that will be used.

In the given study, the researchers are trying to determine whether there is a relationship between two variables: the amount of rainfall and the yield of the crop.

The amount of rainfall is the independent variable, as it is the variable that is being manipulated (or measured) to see if it has an effect on the dependent variable, which is the yield of the crop.

Therefore,

The response variable in this study is the yield of the crop, as it is the variable that is being measured to see if it is affected by the amount of rainfall.

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If the two angles shown are equal, the u and v are parallel.

So set the angles equal to each other, solve for x.

6x + 14 = 80

6x = 80-14

6x = 66

x = 11

So if x = 11, then lines u and v will be parallel.

Answer: X=11 because 80-14=66 and 66/6 is 11

Answer is

Step-by-step explanation:

Answer:

[tex]a. \: (2. \frac{ - 7}{5} )[/tex]

Step-by-step explanation:

Greetings!!!!

To get the answer substitute these values that are given in the choices to the equation and crosscheck the expression.

[tex]6(2) + 5( \frac{ - 7}{5} ) = 5[/tex]

cancel out 5 by 5

[tex]12 - 7 = 5[/tex]

subtract 7 from 12

[tex]5 = 5[/tex]

If you have any questions tag it on comments

Hope it helps!!!!

To provide a margin of error of 3 or less with a 95% confidence level when the population standard deviation equals 11, we need a sample size of 73.

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence.

To calculate the sample size needed to provide a margin of error of 3 or less with a 95% confidence level when the population standard deviation equals 11, we can use the following formula:

n = (Zα/2 * σ / E)²

where n is the sample size, Zα/2 is the critical value from the standard normal distribution corresponding to the desired confidence level (in this case, 1.96 for a 95% confidence level), σ is the population standard deviation, and E is the maximum margin of error.

Substituting the values given in the problem, we get:

n = (1.96 * 11 / 3)²

n = 72.85

Rounding up to the nearest whole number, we get a sample size of 73.

Therefore, to provide a margin of error of 3 or less with a 95% confidence level when the population standard deviation equals 11, we need a sample size of 73.

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Therefore, the angle between V and w is approximately 75.97 degrees.

To find the angle between V and w, we can use the dot product formula:

V · w = |V| |w| cosθ

where θ is the angle between the two vectors, and |V| and |w| are the magnitudes of the vectors.

First, let's calculate the dot product:

V · w = (-5)(4) + (8)(12)

= 61

Next, let's calculate the magnitudes:

|V| = √((-5)^2 + 8^2)

= √89

|w| = √(4^2 + 12^2)

= 4√5

Now we can solve for cosθ:

cosθ = (V · w) / (|V| |w|)

= 61 / (4√5 √89)

≈ 0.2577

Finally, we can find the angle θ:

θ = cos^(-1)(0.2577)

≈ 75.97°

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We can solve this problem by using a Venn diagram. Let's start by drawing two circles, one for Time and one for Newsweek:

```

   _________

 /           \

/             \

/_______________\

|               |

|               |

|               |

|               |

|               |

|     Time      |

|               |

|               |

|               |

|               |

|_______________|

\             /

 \           /

  \_________/

    Newsweek

```

Let x be the number of families that subscribe to both magazines. Then, we know that:

- 75 - x subscribe to Time only

- 50 - x subscribe to Newsweek only

- 5 subscribe to neither

We want to find the value of x. We know that the total number of families surveyed is 95, so:

Total = Time only + Newsweek only + Both + Neither

95 = (75 - x) + (50 - x) + x + 5

Simplifying the equation, we get:

95 = 130 - x

x = 35

Therefore, 35 families subscribe to both Time and Newsweek.

The estimate for the difference between the two population mean for 95% confidence interval is given by ( 3, 7 ).

The 95% interval estimate for the difference between the two population means,

Use the two-sample t-interval formula,

( X₁ - X₂ ) ± tα/2 × SE

where X₁ and X₂ are the sample means of the two branches,

tα/2 is the critical value of the t-distribution with degrees of freedom equal to the smaller of (n₁ - 1) and (n₂ - 1).

And α/2 = 0.025 for a two-tailed test at the 95% confidence level,

And SE is the standard error of the difference between the means, given by,

SE = √(s₁²/n₁ + s₂²/n₂)

Plugging in the given values, we get,

= ( 11 - 6 ) ± t0.025 × √(4²/25 + 1²/20)

Simplifying ,

5 ± t0.025 × 0.83

Using a t-table with 43 degrees of freedom the smaller of 25-1 and 20-1, find the critical value t0.025 = 2.017.

using calculator ( attached value)

Plugging this in, we get,

5 ± 2.017 × 0.83

So the 95% confidence interval for the difference between the two population means is (3.33, 6.67)

Nearest whole number = ( 3, 7 )

Therefore, 95% confidence interval that the true difference between the average hourly wages of employees of the downtown store and the north mall store is between  3 and 7.

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The Trigonometric Equation solutions  to the equation 36 sin²θ - 1 = 0 are:

[tex]θ ≈ 22.08°[/tex] + 360°k, 157.92° + 360°k, 202.08° + 360°k, 337.92° + 360°k

where k is an integer.

We can start by using the trigonometric identity:

sin²θ + cos²θ = 1

Rearranging the terms, we get:

sin²θ = 1 - cos²θ

Substituting this into the original equation:

36 sin²θ - 1 = 0

36(1 - cos²θ) - 1 = 0

Expanding and simplifying:

36 - 36cos²θ - 1 = 0

35 = 36cos²θ

cos²θ = 35/36

Taking the square root of both sides:

cosθ = ±√(35/36)

Now we can use a calculator to find the approximate values of θ:

[tex]θ ≈ 22.08°[/tex], 157.92°, 202.08°, 337.92°

To find all solutions, we need to add multiples of 360° to each of these angles:

[tex]θ ≈ 22.08°[/tex] + 360°k, 157.92° + 360°k, 202.08° + 360°k, 337.92° + 360°k

where k is an integer.

Therefore, the Trigonometric Equation solutions to the equation 36 sin²θ - 1 = 0 are:

[tex]θ ≈ 22.08°[/tex] + 360°k, 157.92° + 360°k, 202.08° + 360°k, 337.92° + 360°k

where k is an integer.

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Chevrolet owners are more loyal than owners of different cars, at least based on this sample of 870 Chevrolet owners.

In order to determine if Chevrolet owners are more loyal than owners of different cars, we need to conduct a hypothesis test. Our null hypothesis (H0) would be that there is no significant difference in loyalty between Chevrolet owners and owners of different cars, while our alternative hypothesis (Ha) would be that Chevrolet owners are more loyal. To test this, we can use a one-sample proportion test, since we are comparing the proportion of Chevrolet owners who would buy another Chevrolet (56%) to the proportion of the general consumer population who are loyal to their automobile manufacturer (47%). Using a significance level of 0.05, we can calculate the test statistic and p-value. Our test statistic is: z = (0.56 - 0.47) / √((0.47 × 0.53) / 870) = 4.71
Our p-value is then calculated as the probability of obtaining a z-value of 4.71 or higher:
p = P(Z ≥ 4.71) ≈ 0
Since our p-value is less than 0.05, we reject the null hypothesis and conclude that there is evidence to support the alternative hypothesis. Therefore, we can say that Chevrolet owners are more loyal than owners of different cars, at least based on this sample of 870 Chevrolet owners.

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The indefinite integral of 2x^2/47dx is (2/47)∫x^2dx which equals (2/47)(x^3/3) + C, where C is the constant of integration. To check this result, we can differentiate the obtained expression using the power rule of differentiation. The derivative of (2/47)(x^3/3) is (2/47)(3x^2/3) which simplifies to (2/47)x^2, which is the integrand we started with. Therefore, the obtained result is correct.

In summary, the indefinite integral of 2x^2/47dx is (2/47)(x^3/3) + C, where C is the constant of integration. We can check this result by taking the derivative of the obtained expression and verifying that it equals the original integrand.

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The domain of f(x) is all real numbers except x = -4, and the range is (-∞, +∞) excluding zero.

To determine the domain and range of the function f(x) = (x^2 + 5x + 4) / (x + 4), we need to consider the restrictions on x that make the function defined and the possible output values.

First, let's examine the domain, which refers to the set of all possible input values for the function. In this case, the only value that would make the denominator (x + 4) equal to zero is -4. Therefore, we need to exclude -4 from the domain to avoid division by zero. Hence, the domain of f(x) is all real numbers except x = -4.

Next, let's determine the range, which represents the set of all possible output values. As x approaches infinity or negative infinity, the function f(x) also approaches positive or negative infinity, respectively. This means that the range of f(x) is (-∞, +∞), excluding the value zero.

Additionally, we can analyze the behavior of the numerator (x^2 + 5x + 4). By factoring the quadratic expression, we have (x + 1)(x + 4). This implies that the numerator can be zero when x = -1 or x = -4. However, since we have excluded x = -4 from the domain, the only critical point is x = -1. By evaluating f(-1), we find that f(-1) = 0. Therefore, the range of f(x) does not include zero.

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The rate per mile in this problem is given as follows:

0.88 minutes per mile.

The rate per mile in this problem is obtained applying the proportions in the context of the problem.

A proportion is applied as the rate per mile is given by the division of the number of minutes by the number of miles.

The parameters for this problem are given as follows:

Hence the rate per mile in this problem is given as follows:

30/34 = 0.88 minutes per mile.

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The largest value of 2sin^2θ - 3cos^2θ is 2, which occurs when θ=π/4+nπ, where n is an integer. The smallest value is -3, which occurs when θ=3π/4+nπ.

To find the maximum and minimum values, we can use the identity sin^2θ + cos^2θ = 1. We can rewrite 2sin^2θ - 3cos^2θ as 2(1 - cos^2θ) - 3cos^2θ, which simplifies to -cos^2θ + 2. To find the maximum value, we want to minimize the negative term, so we set cos^2θ = 0, which occurs when θ=π/2+nπ.

Plugging this into the expression gives us 2 as the maximum value. To find the minimum value, we want to maximize the negative term, so we set cos^2θ = 1, which occurs when θ=0+nπ. Plugging this into the expression gives us -3 as the minimum value.

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The largest value of 2sin^2θ - 3cos^2θ is 2, which occurs when θ=π/4+nπ, where n is an integer. The smallest value is -3, which occurs when θ=3π/4+nπ.

To find the maximum and minimum values, we can use the identity sin^2θ + cos^2θ = 1. We can rewrite 2sin^2θ - 3cos^2θ as 2(1 - cos^2θ) - 3cos^2θ, which simplifies to -cos^2θ + 2. To find the maximum value, we want to minimize the negative term, so we set cos^2θ = 0, which occurs when θ=π/2+nπ.

Plugging this into the expression gives us 2 as the maximum value. To find the minimum value, we want to maximize the negative term, so we set cos^2θ = 1, which occurs when θ=0+nπ. Plugging this into the expression gives us -3 as the minimum value.

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The condition that ensures a solution for the mentioned equation is :

1. b₂ = 2b₁ and 6b₁-3b₃ +b₄ = 0.

In mathematics, an equation is a formula that connects two expressions with the equal sign = to indicate that they are equal. An equation consists of two expressions joined by an equal sign ("="). Expressions for both sides of the equals sign are called the "left side" and the "right side" of the equation. Usually the right side of the equation is assumed to be zero. If this is accepted, it does not reduce the generality, since it can be done by subtracting the right side from the two sides.

According to the Question:

Given that:

x₁+ 2x₂= b₁       ------------------------- (1)

2x₁ + 4x₂ = b₂  ------------------------- (2)

3x₁ + 7x₂ = b₃   ------------------------ (3)

3x₁ + 9x₂ = b₄   ------------------------ (4)

From equation (1) and (2), we get:

b₂ = 2b₁

After analysis equation (1), we have:

  6b₁-3b₃ +b₄ = 0

Using equation (1), (3) and (4), we get:

3(x₁+2x₂) -6(3x₁+7x₂) + 3x₁ + 9x₂ ≠ 0

Putting the value from equation (1),(3) and (4), we get:

6(x₁+2x₂) -3(3x₁+7x₂) + 3x₁ + 9x₂ = 0

Hence option (1) is correct.

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Complete Question:

Consider the following system of linear equations:

x₁+ 2x₂= b₁

2x₁ + 4x₂ = b₂

3x₁ + 7x₂ = b₃

3x₁ + 9x₂ = b₄

which one of the following conditions ensures that a solution exists for the above system.

1. b₂ = 2b₁ and 6b₁-3b₃ +b₄ = 0

2. b₃ = 2b₁ and 6b₁-3b₃ +b₄ = 0

3. b₂ = 2b₁ and 3b₁-6b₃ +b₄ = 0

4. b₃ = 2b₁ and 3b₁-6b₃ +b₄ = 0

The polar coordinates of the point (-6, 8) are (10, 2.21).

To convert the point (-6, 8) from rectangular coordinates to polar coordinates, we can use the following formulas:

r = √(x^2 + y^2)

θ = tan^-1(y/x)

where x and y are the rectangular coordinates, r is the radial distance, and θ is the angular distance.

Substituting the given values, we have:

r = √((-6)^2 + 8^2) = √(36 + 64) = √100 = 10

θ = tan^-1(8/(-6)) = tan^-1(-4/3) = 2.2143 radians (approx.)

Therefore, the polar coordinates of the point (-6, 8) are (10, 2.21).

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The definite integral of -f(u) from 3 to 4 is 4.

Since we know the definite integral of f(x) from 3 to 4 is -4, we can use the following formula to find the definite integral of 9f(u) from 3 to 4:
∫[3 to 4] 9f(u) du = 9 ∫[3 to 4] f(u) du

This is because we can factor the constant 9 outside of the integral, and we're left with the integral of f(u) from 3 to 4.

So, we can substitute -4 for the integral of f(x) from 3 to 4:
∫[3 to 4] 9f(u) du = 9(-4) = -36

Therefore, the definite integral of 9f(u) from 3 to 4 is -36.

Now, let's find the definite integral of -f(u) from 3 to 4. We can use a similar method:
∫[3 to 4] -f(u) du = -∫[3 to 4] f(u) du

This is because we can factor out the constant -1, which changes the sign of the integral. So, we can substitute -4 for the integral of f(x) from 3 to 4:
∫[3 to 4] -f(u) du = -(-4) = 4

Therefore, the definite integral of -f(u) from 3 to 4 is 4.

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The correct answer is A, P = p1 * p2*...* pn. This is because the probability of independent events occurring simultaneously is equal to the product of their individual probabilities.

The probability of any one event occurring is represented by a number between 0 and 1, where 0 means it cannot happen and 1 means it is certain to happen. When multiple events are considered, the probability of all of them occurring is the product of their individual probabilities. This is because the probability of one event does not affect the probability of another event occurring, since they are independent.

The answer is not C, which suggests that the probability of all events occurring is equal to the number of events raised to the tenth power because the probability of each event is not considered in this formula. It is not B as this formula suggests that the probability of all events occurring is equal to the sum of their individual probabilities. because the sum of probabilities can exceed 1, which is not possible. It is not D, which suggests that the probability of all events occurring is equal to 1 because it assumes that all events are certain to occur, which may not be the case for independent events. This means that the answer to the given question is A.

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Answer:

A ) 1/7

Step-by-step explanation:

slope = rise/run

slope = (y2-y1)/(x2-x1)

slope = (-3 - -4)/(2- -5)

slope = (1)/(7)

slope = 1/7

The inverse of the given function is g'(x) = ±√x-7/6

Given that a function g(x) = 6x²-7,

We need to find the inverse of the given function.

To find the inverse of any function, we flip the x and y  in the original function.

f(x) = 6x² - 7

y = 6x² - 7

x = 6y² - 7

6y² = x - 7

y = ±√x-7/6

Hence the inverse of the given function is g'(x) = ±√x-7/6

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In sigma notation, the sum is represented as follows: ∑ (k^2 + 1), k = 1 to 2.

The given sum is: 12 + 22 + 32 + 132.

To write this sum using sigma notation, we can observe the pattern in the terms. The first term is 12, the second term is 22 (which is 12 + 1), the third term is 32 (which is 22 + 1), and the fourth term is 132 (which is 32 + 1 + 2).

We can see that each term is obtained by adding the square of the position number (k^2) to the previous term, along with an additional constant value of 1 or 2 depending on the position.

So, let's write the sum using sigma notation:

∑ [(k^2 + c(k-1))], where k starts from 1 and goes up to 4.

In this notation, k represents the position of the term, k^2 represents the square of the position number, and c represents the constant value added to the previous term.

For the given sum, the constant value c changes depending on the position of the term:

For the first term (k = 1), c is 1.

For the second term (k = 2), c is 1.

For the third term (k = 3), c is 1.

For the fourth term (k = 4), c is 2.

So, the corrected sigma notation for the given sum is:

∑ [(k^2 + c(k-1))], k = 1 to 4.

This indicates that we sum the terms (k^2 + c(k-1)) as k takes values from 1 to 4, where c changes based on the position of the term.

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Answer: I see 26 Squares

Answer: 49 houses

Step-by-step explanation:

63 x 1/3 =63/3= 21 houses were sold last month. 63 - 21 = 42 houses remained unsold last month. 42 x 2/3 =[42 x 2] / 3 = 84 / 3 = 28 houses were sold this month. 21 + 28 = 49 houses sold altogether.

The final expression is 20(5x - 1)2 + 2x + 8.

The given expression is (20x2-12x+8)+ (2x+8). We are required to simplify the given expression.To do that, we will first simplify the expressions inside the parentheses followed by the addition.(20x2-12x+8) can be written as 4 * 5x2-3x+2. This is because we can take 4 as the GCF (Greatest Common Factor) from the given expression. 4 is also a perfect square so we can write 4 * 5x2-3x+2 as 2 * 2 * 5x2-3x+2.

This expression can further be simplified using the (a + b)2 formula which is a2 + 2ab + b2. In this case, a is 5x and b is 1. Hence, we can write 2 * 2 * 5x2-3x+2 as 2 * 2 * (5x - 1)2. Now, the given expression becomes 2 * 2 * (5x - 1)2 + (2x + 8).We will simplify this expression further by distributing the factor 2 on the right-hand side of the addition. Therefore, the given expression becomes 2 * 2 * (5x - 1)2 + 2x + 2 * 4. This can be simplified to get the following expression:20(5x - 1)2 + 2x + 8We have now successfully simplified the given expression.

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To find out how much the painter charged for the last job, we need to substitute h=15 and c=3 in the expression 35h 30c and simplify. The painter charged $615 for the last job which required 3 cans of paint and took 15 hours to complete.

The painter uses the expression 35h + 30c to determine the cost of a job, where h represents the hours spent and c represents the number of paint cans used. In the last job, it took the painter 15 hours and 3 cans of paint to complete the work. To find the cost, we will plug these values into the given expression.
Cost = 35h + 30c
Cost = 35(15) + 30(3)
Now, we will perform the calculations:
Cost = 525 + 90
By adding these values, we get the total cost:
Cost = 615

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The quadratic equation on the given graph is y = (x - 2)² - 9.

For a quadratic with leading coefficient a and vertex (h, k), the equation is:

y = a*(x - h)² + k

Here we can see that the vertex is at (2, -9), replacing that:

y = a*(x - 2)² - 9

We can see that the y-intercept is at y = -5, then:

-5 = a*(0 - 2)² - 9

-5 = a*4 - 9

-5 + 9 = a*4

4 = a*4

4/4 = a

1 = a

The quadratic is:

y = (x - 2)² - 9

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