Use the diagram to answer the question. Triangle A B C. Segment B C measures 13. Segment A C measures 15. Angle B is a right angle. What is the measure of ∠A?

Answer:

hope it helps

this is my best

please tell me if I'm wrong

Answer:

x<-5 is the correct answer

Answer:

x<-5 is the answer

Step-by-step explanation:

Answer:

7 < (third side length) < 37

Step-by-step explanation:

Add these two side lengths together.  We get 37.  Unless the 3rd side is LESS than 37, we cannot form a triangle.  

Next, subtract 15 from 22, obtaining 7.  The 3rd side has to be GREATER than 7 in order for the sides 7+, 15 and 22 to form a triangle.

7 < (third side length) < 37

Answer:

26.63 ??

Step-by-step explanation:

I think you use pythagorean theorum to solve.

do 22^2 and 15^2 and get 709.1569

sqrt of that is 26.63

Answer:

The awnser is 64

Step-by-step explanation:

It is 64 because you devide the perimiter (32) by 4, to get all sides, and then multiply 1 side by the other to get 64

THIS METHOD ONLY WORKS FOR A SQUARE

Answer: y = -1/2x -1

Step-by-step explanation: since the new line is parallel to the given line the slope of both the lines world be same. Therefore putting the new values in the equation

y-y1=m(x-x1)

y-1=-1/2(x+4)

y-1=-1/2x -2

y=-1/2x-1

Step-by-step explanation:

the inverse of the inverse of a function is the function itself

It's like going and coming back

Answer:

9

Step-by-step explanation:

The inverse of the inverse is the input

f^-1 (f^-1(9))  = 9

As a proof

f(x) = 4x+5

y = 4x+5

Exchange x and y

x = 4y+5

Solve for y

(x+5) = 4y

(x+5)/4 = y

f^-1 (x) =  ( x-5)/4

Then find the inverse of this function

y = ( x-5) /4

Exchange x and y

x = (y-5)/4

4x = y-5

4x+5 = y

Which gives us the original function back

f^-1( input) = 4x+5

Using the value given

f^-1 (9) =  ( 9-5)/4=4/4 =1

Using the 1 from the previous part as the input

f^-1( 1) = 4*1+5  = 4+5 = 9

Answer:

Tina

Step-by-step explanation:

Since Amy owns the dog, she doesn't have the ferret and we know that Jewel doesn't have the ferret so the answer is Tina.

Answer:

72cm2 (2 means squared)

Step-by-step explanation:

you add all the sides once you get the are for each side. To do that you multiply l(w)

Answer:

The surface area of the rectangular prism is [tex]136cm^{2}[/tex]

Step-by-step explanation:

What is surface area?

Surface area is the amount of space covering the outside of a three-dimensional shape.

What is rectangular prism?

A rectangular prism can be defined as a 3-dimensional solid shape which has six faces that are rectangles. A rectangular prism is also a cuboid.

Given, length l= 7cm

          breadth b=6cm

          height h=2cm

The surface area of the cuboid is,

=2(lb+bh+lh)

=2(7*6+6*2+2*7)

=2(42+12+14)

=2*68

=136 [tex]cm^{2}[/tex]

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Answer:

88

Step-by-step explanation:

89+85+95+83= 352,

352/4 = 88

Answer:

mark my answer as the brainliest

Step-by-step explanation:

x = 53/4

Answer:

4×+1-9 (2^)+2)=0

4×+1-9 (4+2)=0

4×+1(-36-18)=0

4×+1 (-54)=0

4×-54=0

4×=54

×=54÷4

×=13.5

Answer:

[tex]x=\frac{7}{8}[/tex]

Step-by-step explanation:

[tex]10x-3-2x=4[/tex]

First, collect and rearrange the like terms.

[tex]10x-3-2x=4[/tex]

[tex]8x-3=4[/tex]

[tex]8x=4+3[/tex]

Then, solve the equation:

[tex]8x=4+3[/tex]

[tex]8x=7[/tex]

[tex]x=\frac{7}{8}[/tex]

So, the answer is [tex]x=\frac{7}{8}[/tex]. Hope my solution and explanation can help you. Thank you!

If you still cannot get the point, you can ask me anytime.

Answer:

x=7/8

Step-by-step explanation:

10x-3-2x=4

collect like term

8x-3=4

move constant to the right-hand side and change its sign

8x-3=4 into 8x=4+3

add up the number : 8x=4+3

8x=7 divide both sides of the equation by 8

x = 7/8

Answer:

Answer- 3/4 divided by 1/8 = 6/8

Answer:

[tex]$\frac{3\pi }{2}$[/tex]

Step-by-step explanation:

Solve for the interval: [tex][0, 2\pi)[/tex]

[tex]4 \csc(\theta)+1=-3[/tex]

[tex]4 \csc(\theta)=-4[/tex]

[tex]\csc(\theta)=-1[/tex]

[tex]$\frac{1}{\sin(\theta)} =-1 \Rightarrow \sin(\theta)=-1$[/tex]

We have [tex]\sin(\theta)=-1[/tex] for coterminal angles [tex]$\frac{3\pi }{2}+2\pi n$[/tex]

Once we just want the interval [tex][0, 2\pi)[/tex]

The solution is [tex]$\frac{3\pi }{2}$[/tex]

Answer:

62.5°

Hope this helps :)

3x+4y=12 is Linear.

y-1/2x+6 is Linear.

y=4x^2 is nonlinear.

y+2=|4| is linear.

y+6=4x is linear.

In order to tell whether an equation is linear or not, you have to first see if there is any variable^2 or more than ^1. If that is the case, it isn't linear. For example the equation x^2=4 or y^5=100 isn't linear. It also isn't linear if the equation is divided by X or Y.For example the equation 1/x=1 isn't linear or 1/y^2=5 isn't linear.

A question is also linear if you can write it in the form y=mx+b , 'm' meaning the slope of the equation and 'b' meaning the y-intercept of the equation.

Answer:

arccsc(x)=1/cos(x)

Step-by-step explanation:

Answer:

the answer to your question is D

Step-by-step explanation:

Answer:

C. [tex](5-\frac{1}{2})^6[/tex]

Step-by-step explanation:

Given

[tex]15(5)^2(-\frac{1}{2})^4[/tex]

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

[tex]Sum = 2 + 4[/tex]

[tex]Sum = 6[/tex]

Each term of a binomial expansion are always of the form:

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

Where n = the sum above

[tex]n = 6[/tex]

Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion

[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

Substitute 6 for n

[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

By direct comparison of

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

and

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

We have;

[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]

Further comparison gives

[tex]^nC_r = 15[/tex]

[tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]b^r= (-\frac{1}{2})^4[/tex]

[Solving for a]

By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]a = 5[/tex]

[tex]n = 6[/tex]

[tex]r = 4[/tex]

[Solving for b]

By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]

[tex]r = 4[/tex]

[tex]b = \frac{-1}{2}[/tex]

Substitute values for a, b, n and r in

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

Solve for [tex]^6C_4[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]

Check the list of options for the expression on the left hand side

The correct answer is [tex](5-\frac{1}{2})^6[/tex]

Answer:

The second choice

Step-by-step explanation:

So first we would plug in the first term which is 2 so we would get [tex]an=2[/tex] times [tex]rn-1[/tex] so next we would see that the common ration is -3 since every time the number is being multiplied by -3. so then our equation would be [tex]an= 2[/tex] times [tex]-3n-1[/tex]. Now we would just find the choice that matches and it would be the second choice.

Answer:

option 2

Step-by-step explanation:

First term [tex]a_{1} = 2\\[/tex]

common ratio = r = second term ÷ first term

                            = -6 ÷2 = -4

Plug in the values of  [tex]a_{1}[/tex] & r in the formula

[tex]a_{n} = a_{1}*r^{n-1}\\\\\\a_{n}=2 * (-3)^{n-1}[/tex]

Part A

House 1: we make exponential can be used to describe the

value of house 1. After 1 year, 253480 = 249000 x 1.02

After 2 years, 259059.6 = 25398×1.02. After 3 years 264240.79 =259059.60x1.02.

House 1: we make linear. 256000=249000 + 1000.263000 = 256000 +7000.270000=263000 + 1000.

Part B.

House 1: f(x)=249000 1.02x [genometic sequence]

House 2: f(X) = 24900 + 1000x [arithmetic progression]

Part C

House 1: f(45)=249000×1.02 45 = 607025.697

House 2: f(45) = 249000 +7000x45 = 564000

"House 1 is an arithmetic sequence that increases in price each year while House 2 is an arithmetic sequence that only increases by 1000 per year.

In computational mathematics, a word problem is a problem of deciding whether two given expressions are equivalent with respect to a set of rewriting identities. A prototypical example is the word problem for groups, but there are many other instances as well.

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Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

[tex]\angle AED = \angel BEC[/tex] ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

[tex]\angle ABC = 90^{\circ}[/tex]

In ΔDBC

BC=DC (Given)

So,[tex]\angle CDB=\angle DBC[/tex](Opposite angles of equal sides are equal)

So,[tex]\angle CDB=\angle DBC=x[/tex]

So,[tex]\angle CDB+\angle DBC+\angle BCD = 180^{\circ}[/tex] (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,[tex]\angle CDB=\angle DBC=x = 65^{\circ}[/tex]

Now,

[tex]\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90[/tex]

So,[tex]\angle ABD=90-x=90-65=25^{\circ}[/tex]

In ΔABD

AB = BD (Given)

So,[tex]\angle BAD=\angle BDA[/tex](Opposite angles of equal sides are equal)

So,[tex]\angle BAD=\angle BDA=y[/tex]

So,[tex]\angle BAD+\angle BDA+\angle ABD = 180^{\circ}[/tex](Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

Answer:

The rhombus ABCD has an area of 22 square units.

Step-by-step explanation:

The coordinates of rhombus ABCD are shown in the image attached below. The area of the rhombus can be found in terms of their diagonals, which are now calculated by Pythagorean Theorem:

[tex]AC = \sqrt{[6-(-4)]^{2}+[8-(-4)]^{2}}[/tex]

[tex]AC = 15.620[/tex]

[tex]BD = \sqrt{(4-6)^{2}+[0-(-2)]^{2}}[/tex]

[tex]BD \approx 2.828[/tex]

The area of the rhombus is: ([tex]AC = 15.620[/tex] and [tex]BD \approx 2.828[/tex])

[tex]A = \frac{AC\cdot BD}{2}[/tex]

[tex]A = \frac{(15.620)\cdot (2.828)}{2}[/tex]

[tex]A = 22.087[/tex]

The rhombus ABCD has an area of 22 square units.

Answer:

22 units

Step-by-step explanation:

Answer:

the answer is just 2

Step-by-step explanation:

start at the -3 and move right 3 and up 6 this is a inclined line so the answer will be positive the fraction put the numbers into a rise over run fraction which will be 6/3 which will reduce to 2/1 which is 2.

Answer:

3/10

Step-by-step explanation:

1/5 of total income - spent on car

remainder income = 4/5

3/8 of remainder = 3/8 ×4/5 = 3/10(of total income spent on rent)

the word "of" means you can find it by multiplication

e.g. 2 of 1/2 means 2 × 1/2 which is 1

Answer: B.

k=3

Step-by-step explanation:

g(x) is 3 units higher than f(x)

so k must be equal to 3

Answer:

it is b i think

k=3

Step-by-step explanation:

Answer:

Range of Function :  { - 9, - 5, - 1,  4 }

Step-by-step explanation:

We know that y = 2x - 5 provided the domain ( x - values ) { - 2, 0, 2, 4 }. Let us substitute each element in this set of domain as x in the equation "y = 2x - 5" as to solve for the y - values, otherwise known as the range of the function.

{ - 2, 0, 2, 4 }

y = 2( - 2 ) - 5 = - 9,

y = 2( 0 ) - 5 = - 5,

y = 2( 2 ) - 5 = - 1,

y = 2( 4 ) - 5 = 4

We have the set of y - values as { - 9, - 5, - 1, 4 }. This is the range of our function.

Answer:

HIG=28°

Step-by-step explanation:

HI is a diameter therefore it's measure is 180°

HI-IG=HG

180-128=HG

52°=HG

HIG=1/2HG

HIG=1/2(56°)

HIG=28°

Answer:

  8 servings

Step-by-step explanation:

At the ratio of 15:1, the 75 grams of rice in one serving will require 75/15 = 5 g of spice. David's inventory of 40 g of spice is enough for ...

  40 g/(5 g/serving) = 8 servings

Only 8 servings can be made with the available spice.

Rice to spice ratio = 15 : 1

Number of grams per serving = 75 grams

Grams of spice available = 40 grams

Grams of rice, r required for available spice :

15 grams of rice = 1 gram of spice

r grams of rice = 40 grams of spice

Cross multiply :

r = (40 × 15)

r = 600 grams

The grams of rice which can go with the available spice :

Number of servings = grams of rice / grams per serving

Number of serving = 600 grams / 75 grams

Number of grams per serving = 8

Hence, The number of servings which can be made with the available spice is 8 servings

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Answer:

C. X=27

Step-by-step explanation:

-11+1/3x+9=7

1/3x=7+11-9

1/3x=9

x=9x3

x=27

Answer:

Hello There. ☆~\《`°---_●£●__---`°》\~☆

An exponential growth function is represented by

f(x)=a(b)^{x},a>0,b>1.

The given functions can be written as,

A)f(x)=.001(1.77)^x,0.001>0,1.77>1

B)f(x)=2(1.5)^{x/2}=2(\sqrt{1.5} )^x,2>0,\sqrt{1.5} >1

C)f(x)=5(0.5)^{-x}=5(2)^x,5>0,2>1

D) f(t)=5e^{-t}=5(\frac{1}{e} )^x,5>0,1/e.

So the function f(t)=5e^{-t}=5(\frac{1}{e} )^x,5>0,1/e violates the conditions for an exponential growth function. It is an exponential decay function.

The correct choices are (A), (B), (C).

Hope It Helps!~ ♡

ItsNobody~ ☆

The functions that represent exponential growth are choices (A), (B), and (C). The correct option is A, B, and C.

Exponential growth is the process of gradual increase of quantity over time.

An exponential growth function is represented by

[tex]\rm f(x)=a(b)^{x}[/tex],  a>0,b>1

The given functions can be written as,

A)[tex]f(x) = .001(1.77)^x[/tex], 0.001>0,1.77>1

B) [tex]f(x) = 2(1.5)^{x/2} = 2(\sqrt{1.5} )^x,[/tex]   2>0,  [tex]\sqrt{1.5}[/tex] >1

C)[tex]f(x) = 5(0.5)^{-x}=5(2)^x[/tex],    5>0, 2>1

D) [tex]f(t) = 5e^{-t}=5(\frac{1}{e} )^x[/tex],        5>0,  1/e.

So, the function [tex]f(t)=5e^{-t}=5(\frac{1}{e} )^x,5 > 0,1/e[/tex] violates the conditions for an exponential growth function. It is an exponential decay function.

The correct choices are (A), (B), and (C).

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