using a map give the coordinates of the capital of the neighboring countries of the philippines e.g tokyo japan​

Answer:

sorry don't know the answer!!!

Answer:

d

Explanation:did test

Answer:

Boiling - The process of a liquid changing to gas.

Boiling point - The temperature at which a liquid boils.

Condensing - The process of a gas changing to a liquid.

Distillate - The liquid collect from the condenser.

Residue - The liquid left behind in the distillation flask.

Vapour - Another name for gas.

Hope it helps :)

Explanation:

Have a good luck with ur exam

the equation is not present.

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

m = 6400 ÷ 7.77

m = 823.7g

Answer:

There are 823.68 grams.

Explanation:

Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.

Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:

Q= C*m* (T2- T1) = C*m* ΔT

In this case:

Replacing:

6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C

Solving:

[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]

m=823.68 grams

There are 823.68 grams.

Answer:

methyl ethanoate

Explanation:

To name the compound given above, the following must be obtained:

1. Determine the functional group of the compound.

In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.

2. Determine the longest chain before the functional group and the compound after the functional group.

In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.

3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.

This is illustrated below:

After the functional group => methyl

Before the functional group => ethane

Name of the compound => methyl ethanoate

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

[tex]R = \dfrac{u^2 sin 2\theta}{g}[/tex] ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

[tex]R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m[/tex]

Therefore, the horizontal range of projectile is 80 m.

Answer:

1.054 x 10²⁴ molecules

Explanation:

In order to convert moles of any given substance into a number of molecules, we need to use Avogadro's number, which states the number of molecules -or atoms, in the case of elements- present in one mol:

We now convert 1.75 moles into molecules:

Answer: 2. The outermost shell

Explanation:

In an elements ground state, its electrons have the least amount of energy that they could have so they stay in their shells. When Krypton is in this state therefore, its valence electrons will stay in the outermost shell.

As Krypton has a total of 36 electrons in this state, there will be 8 valence electrons and they will all be in the outer shell.

Answer:

An increase in pressure would cause less volume and vice versa. They are inversely proportional.

Explanation:

This is due to Boyle's Law (and because an increase in pressure would increase the force on the container, however, if it's a closed container, it would burst)

Feel free to mark it as brainliest :D

Answer:

0.960 mol of Ag

Explanation:

Mg(s) + 2AgNO3(aq) → Mg(NO3)2(aq) + 2Ag(s)

1.00 mol of Mg ---- 2.00 mol of Ag

0.480 mol of Mg ---- x

x = (0.480×2)/1 = 0.960 mol of Ag

Answer:

We have to find out which of the reactants that is the Limiting Reagent.

The Limiting Reagent is the reactant that finishes before reaction is complete or simply put... Its the reactant that's NOT IN EXCESS.

We use the reactant that's not in excess to find the Number of moles of product because once that reactant is used up.... The reaction also ends or stops(hence the name;Limiting reactant).

Now

We have 10moles of NO

We also have 6moles of O2

The balanced equation of Reaction is

2NO + O2 ===> 2NO2

Now

looking at this equation

2moles of NO is required to react with 1mole of O2

So since we have NO=10moles and O2 = 6moles

It means that

20moles of NO is required to react with 6 moles of O2.

We were only given 10moles of NO and this is not even enough to react with the whole 6moles of Oxygen because from what we just discovered... We need 20moles of NO to react with all 6moles of O2.

So

This means that NO is the LIMITING REACTANT. It is in short supply and would be used up before the whole reaction takes place.

So we use the limiting reactant to find the Number of Moles of Product formed.

Now

From the eqn of reaction

2moles of NO forms 2Moles of NO2.

Their Mole ratio is 2:2 or 1:1...

This simply means that an equal amount of NO2 will be Produced

MEANING.... 10 MOLES OF NO2 IS PRODUCED.

HAVE A GREAT DAY!!!

Answer: D it’s is 2.0 s

i think..

Explanation:

Answer:

Beta decay

Explanation:

Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.

Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.

The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.

Beta decay decreases the neutron - proton ratio.

Answer:

28.55 mL or 0.02855 L

Explanation:

Applying,

Density(D) = mass(m)/Volume(V)

D = m/V............... Equation 1

Where D = Density of the Bromine, m = mass of the bromine, V = volume of the bromine

make V the subeject of the equation

V = m/D............. Equation 2

From the question,

Given: m = 88.5 g, D = 3.10 g/mL

Substitute these values into equation 2

V = 88.5/3.10

V = 28.55 mL

Hence the volume occuppied by the Bromine gas is  28.55 mL or 0.02855 L

Answer:100

Explanation:

Answer:

The lowest point on a wave?

The lowest point on the wave is called as through or wave through.

The highest point on the wave is known as the crest or wave crest

The space between the crests is called the wave length.

The distance between the wave crest and the wave trough is called the wave height.

#CarryOnLearning

Answer:

Trough

Explanation:

The trough is the lowest point on a wave. The highest point on a wave is called a crest.

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

Answer:

Nitrogen molecule (N2)

The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.

The total number of electrons present in the nitrogen molecule (N2) is 14.

In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.

N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2

Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.

The bond order of N2can be calculated as follows:

Here, Nb = 10 and Na = 4

Bond order = (Nb−Na) /2

B.O = (10−4)/2

B.O = 3

So your answer should be C3.

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

Answer:

O2

Explanation:

for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:

MM FeS2 = 120n  = 26.2g / 120g/mol = 0,218 mol

MM O2  = 32n = 5,44g/32g/mol = 0,17 mol

The limiting reactant is  

O2

Answer:

Explanation:

A chemical bond formed when two atoms share three pairs of electrons is a triple bond; it is best described as covalent.

Answer:

Your answer will be b(molten material from the outer core makes its way to the surface of earth)

Explanation:

Answer:

C

Explanation:

I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!

Answer:

See Explanation

Explanation:

Given that;

N/No = (1/2)^t/t1/2

Where;

No = amount of radioactive isotope originally present

N = A mount of radioactive isotope present at time t

t = time taken

t1/2 = half life

N/1000=(1/2)^3/6

N/1000=(1/2)^0.5

N = (1/2)^0.5 * 1000

N= 707 unstable nuclei

Since the value of the initial activity of the radioactive material was not given, the activity of the radioactive material after three months is given by;

Decay constant = 0.693/t1/2 = 0.693/6 months = 0.1155 month^-1

Hence;

A=Aoe^-kt

Where;

A = Activity after a time t

Ao = initial activity

k = decay constant

t = time taken

A = Aoe^-3 *0.1155

A=Aoe^-0.3465

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Answer:

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode

Explanation:

Electrolysis is a process whereby ionic compound is broken down or degraded into smaller substances when electric current flow through it.

During electrolysis of magnesium iodide, At the cathode reduction reaction occur .

MgI2 is dissociated to is Mg2+(aq) and 2I−(aq)

Then Iodine is reduced to 2I−(aq) which is 0 in (MgI2) then change to -1 (2I−(aq))

Therefore;

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode.

Answer:

1. Ferric sulfate - Fe2(SO4)3

2. Strontium oxalate – SrC2O4

3. Chromic acid – CrO3

4. Nickel (III) carbonate – NiCO3

5. Silver bromate – AgBrO3

6. Dinitrogen difluoride - N2H2

7. Magnesium molybdate – MgMoO4

8. Sodium hydrogen phosphate - Na2PO4