Using complete sentence, describe how the variable h and the variable k of the general formula for a cube root function effects the graph. And than here is the general formula,
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The variable k translates the graph of the function vertically, if k is positive then the translation is up; is k is negative the translation is up. Similarly the variable h translates the graph of the function horizontally, if h is positive the translation is to the right whereas if h is negative the translation is to the left.
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The Moore's are purchasing a new upright freezer. The inner dimensions of the freezer are 0.5 meter by 0.6 meter by 1.5 meters. (a) What is the volume of the freezer in cubic meters? (b) What is the volume of the freezer in cubic centimeters? (Hint 1 cubic meter = 100 x 100 x 100 cubic 1.5 m centimeters.) 0.6 m 0.5 m T = lwh Response
Answers
Explanation:
a)
The volume of a rectangular prism - which is the shape this freezer has - is:
[tex]V=\text{width x length x height}[/tex]These measures are all in meters, so the volume of the freezer in meters is:
[tex]V=0.5m\times0.6m\times1.5m=0.45m^3[/tex]b) If 1 m³ = 100 x 100 x 100 cm³ this is the same as 1 m³ = 1,000,000 cm³. To find the volume in cubic centimeters we have to use this equality to transform the volume found in item (a) from cubic meters to cubic centimeters:
[tex]\frac{0.45m^3}{1m^3}\times1,000,000\operatorname{cm}=450,000\operatorname{cm}^3[/tex]Answers:
• a) ,V = 0.45 m³
,• b) ,V = 450,000 cm³
What’s the least common denominator of 2/7 and 1/9
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Solution
- The least common denominator of 2/7 and 1/9 is simply gotten by finding the smallest multiple of the denominator of both fractions.
- The smallest multiple of both 7 and 9 is simply the multiplication of both numbers.
- The least common denominator is
[tex]7\times9=63[/tex]Record: 0/3 Score: o Penalty: 1 offComplete: 0%Saniya HallExpected ValueMar 07, 9:58:18 AM?Jacob owns a small business selling bagels. He knows that in the last week 65customers paid cash, 26 customers used a debit card, and 8 customers used a creditcard.If next week, he is expecting 600 customers, about how many would you expect topay with a credit card? Round your answer to the nearest whole number.Answer:Submit Answerattempt 1 out of 2LO
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Solution:
Given:
[tex]\begin{gathered} \text{cash}=65 \\ \text{debit card=26} \\ \text{credit card=8} \\ \\ \text{Total customers for the w}eek=99 \\ \\ \text{Expected value for the following we}ek=600 \end{gathered}[/tex]To get the expected value that will pay with a credit card the following week, we use the expected value formula.
[tex]\begin{gathered} E(x)=x.P(x) \\ \\ \text{where} \\ E(x)\text{ is the expected value} \\ x\text{ is the total expected=600} \\ P(x)\text{ is the probability} \end{gathered}[/tex]For credit card customers, the probability for the past week was;
[tex]P(x)=\frac{8}{99}[/tex]Hence, the expected value for the following week will be;
[tex]\begin{gathered} E(x)=x.P(x) \\ E(x)=600\times\frac{8}{99} \\ E(x)=\frac{4800}{99} \\ E(x)=48.48 \\ \\ To\text{ the nearest whole number,} \\ E(x)=48 \end{gathered}[/tex]Therefore, to the nearest whole number, Jacob will expect 48 customers to pay with a credit card the following week.
Martha Invests $7700 in a new savings account which earns 5.2 % annual interest, compounded continuously. What will be the value of her
Investment after 4 years?
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The value of Martha's investment after 4 years will be $32,443.80.
What is the value of the investment?When an amount earns an interest that is compounded continuously, it means that the investment grows at an exponential rate continuously over the investment period. The investment period in this question is 4 years.
The formula for calculating future value when there is continuous compounding is : A x e^r x N
Where:
A= amount e = 2.7182818 N = number of years r = interest rateFuture value of the investment = $7,700 x (2.718^0.052) x 4 = $32,443.80
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what quantities in a coordinate plane represent in real world relationships
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In a coordinate plane, the objects are represented in the x and y coordinates.
We can identify each object on the coordinate plane by its value on both the horizontal axis (x - axis) and the vertical axis (y - axis)
If h(x)=|1-7x|, find each value
1. h(1)
2. h(-7)
3. -h(9)
Please and thanks!
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Step-by-step explanation:
1. h(1)=|1-7*1|=|-6|=6;
2. h(-7)=|1-7*(-7)|=|50|=50;
3. -h(9)= -|1-7*9|=-|-62|= -62.
Solve for x. Using that value, find the measurement of
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Given: Four corners of a perpendicular intersection
[tex]\begin{gathered} m\angle ABE=(6x+2)^0 \\ m\angle DBE=40^0 \end{gathered}[/tex]To Determine: The value of x and the measure of angle m∠ABE
From the given diagram, it can be seen that m∠ABE and m∠DBE are in one of the four corners of the perpendicular intersection.
Also note that all four corners of a perpendicular intersection is a right angle. Therefore:
[tex]\begin{gathered} m\angle ABE+m\angle DBE=90^0 \\ 6x+2^0+40^0=90^0_{} \\ 6x+42^0=90^0 \\ 6x=90^0-42^0 \\ 6x=48^0 \\ x=\frac{48^0}{6} \\ x=8^0 \end{gathered}[/tex][tex]\begin{gathered} m\angle ABE=6x+2 \\ m\angle ABE=6(8)+2 \\ m\angle ABE=48+2 \\ m\angle ABE=50^0 \end{gathered}[/tex]Hence:
x = 8⁰
m∠ABE = 50⁰
Problem 2 Fill in the chart with appropriate values that satisfy this equation y= 3x - 5
Answers
The given equation:
[tex]y=3x-5[/tex]put x=3 in the above equation,
[tex]\begin{gathered} y=3(3)-5 \\ y=9-5 \\ y=4 \end{gathered}[/tex][tex]\begin{gathered} 10=3x-5 \\ 10+5=3x \\ 15=3x \\ x=5 \end{gathered}[/tex]when x= 5, y = 10
put x = - 2 in the equation.
[tex]\begin{gathered} y=3(-2)-5 \\ y=-6-5 \\ y=-11 \end{gathered}[/tex]when x = -2 y= - 11.
put x = 0 in the equation.
[tex]\begin{gathered} y=3(0)-5 \\ y=-5 \end{gathered}[/tex]when x = 0 , y = -5.
put y =0 in the equation.
[tex]\begin{gathered} 0=3x-5 \\ 5=3x \\ x=\frac{5}{3} \end{gathered}[/tex]put y = -17 in the equation.
[tex]\begin{gathered} -17=3x-5 \\ -17+5=3x \\ -12=3x \\ x=-\frac{12}{3} \\ x=-4 \end{gathered}[/tex]Determine the range using interval notation f(x)= -1/2x-3 for the domain (-4,2]
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We have the following:
[tex]\begin{gathered} f(x)=-\frac{1}{2}x-3 \\ \end{gathered}[/tex]the domain is the input values and the range the output values, therefore:
[tex]\begin{gathered} f(-4)=-\frac{1}{2}\cdot-4-3=2-3=-1 \\ f(2)=-\frac{1}{2}\cdot2-3=-1-3=-4 \end{gathered}[/tex]now, the range is:
[tex]\lbrack-4,1)[/tex]The answer is the option 2
what would the constant of proportionality be? If not, explain why.
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The equation of proportionality is
y = k x, where k is the constant of proportionality
To check the table is in proportion or not let us find the value of k using each line of data, if all of them give the same value of k, then they are proportional
(5, 85)
85 = k(5)
Divide both sides by 5
17 = k
The value of k = 17
let us check the second line
(10, 79)
79 = k(10)
Divide both sides by 10
7.9 = k
Since k has different values, then
Distance to the listener not proportion with the sound level
There is no constant of proportionality
Divide.the question is 0.75 divide60.75)6
Answers
Given data:
The expression for the question is,
[tex]\frac{0.75}{6}=0.125[/tex]Thus, the value of the given expression is 0.125.
Mary Jo spends $1,980 to buy stock in two companies. She pays $15 a share to one of the companies and $12 a share to the other. If she ends up with a total of 150 shares, how many shares did she buy at $15 a share and how many did she buy at $12 a share?
Answers
She bought 60 shares at $15 and 90 shares at $12
Explanation
to solve this we can use a system of equations
so
Step 1
set the equations
let x represents the number of shaper she bougth at $ 15
let x represents the number of shaper she bougth at $12
so
a)Mary Jo spends $1,980 to buy stock in two companies.
[tex]15x+12y=1980\Rightarrow equation(1)[/tex]b)she ends up with a total of 150 shares,so
[tex]x+y=150\Rightarrow\text{ equation\lparen2\rparen}[/tex]Step 2
now, solve the equations
[tex]\begin{gathered} 15x+12y=1980\Rightarrow equation(1) \\ x+y=150\operatorname{\Rightarrow}\text{equat}\imaginaryI\text{on}\operatorname{\lparen}\text{2}\operatorname{\rparen} \end{gathered}[/tex]a) isolate the x value in equation (1) and replace the result in equation(1)
[tex]\begin{gathered} x+y=150\Rightarrow\text{ equation\lparen2\rparen} \\ subtract\text{ y in both sides} \\ x+y-y=150-y \\ x=150-y \end{gathered}[/tex]replace in equation (1) and solve for y
[tex]\begin{gathered} 15x+12y=1980\Rightarrow equation(1) \\ 15(150-y)+12y=1980 \\ 2250-15y+12y=1980 \\ 2250+3y=1980 \\ subtract\text{ 2250 in both sides} \\ 2250+3y-2250=1980-2250 \\ 3y=270 \\ divide\text{ both sides by 3} \\ \frac{3y}{3}=\frac{270}{3} \\ y=90 \end{gathered}[/tex]
so,she bougth 90 shares at $12
b) now, replace the y value in equation (2) and solve for x
[tex]\begin{gathered} x+y=150\Rightarrow\text{ equation\lparen2\rparen} \\ x+90=150 \\ subtract\text{ 90 in both sides} \\ x+90-90=150-90 \\ x=60 \end{gathered}[/tex]so, she bougth 60 shares at $15
therefore, the answer is
She bought 60 shares at $15 and 90 shares at $12
I hope this helps you
Evaluate the expression for the values of x given in the first column. Value of xValue of expressio
Answers
Given expression is 9x-5.
The value of x is x= 4.
Then the expression becomes 9(4)-5=31.
The value of x is x= 6.
Then the expression becomes 9(6)-5=49
The value of x is x= 2.
Then the expression becomes 9(2)-5=13.
The value of x is x= 7.
Then the expression becomes 9(7)-5=58
Tha values are 31, 49, 13, 58 in order
Write the proportional equation for the table that represents a proportional relationship. Use the variable that is provided in parenthesis beside each label.
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The proportional relationship can be express as y = kx, where x is the independent variable and y is the dependent variable.
For table 1, T is the independent variable and C is the dependent variable, so the relationship that we are looking for is C = kT
Using the table, C = 30 when T = 2.
Substitute this to find k.
[tex]\begin{gathered} C=kT \\ 30=2k \\ k=\frac{30}{2}=15 \end{gathered}[/tex]Therefore, the equation is C = 15T
For table 2, G is the independent variable and C is the dependent variable. So the equation is C = kG
Using the table, C = 10.60 when G = 4.
Substitute this to find k.
[tex]\begin{gathered} C=kG \\ 10.60=4k \\ k=\frac{10.60}{4}=2.65 \end{gathered}[/tex]The equation is C = 2.65G
three times a certain number plus 6 is equal to twice the number plus 15.what is the number
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The value of the number is 9
How to determine the number?From the question, the statement is given as
Three times a certain number plus 6 is equal to twice the number plus 15
Let the number be x
So, we have the following equation
Three times x + 6 = twice x plus 15
Express the statements as numbers
So, we have
3x + 6 = 2x + 15
Collect the like terms
This gives
3x - 2x = 15 - 6
Evaluate the difference
x = 9
Hence, the number is 9
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2. The weight of a paper clip is about 0.0009 grams . Write this number in Scientific notation *(2 points)O A. 9 x 10-3B. 9 x 104C. 9 x 10-4D. 9 x 104
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Note that we can "get rid of" the point (in 0.0009) if we move it four spaces (numbers) to the right. These four spaces amount to the exponent in the Scientific notation. For we're moving to the right, the exponent must be negative. The answer is
[tex]9\times10^{-4}[/tex]C.
Given the residual plot below, which of the following statements is correct?Residual Plot10.5Residuals0010-0.5VariableA. There is a pattern, so the data is linear.aB. There is not a pattern, so the data is linear.Ο Ο Ο ΟC. There is not a pattern, so the data is non-linear.D. There is a pattern, so the data is non-linear.
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From the graph we notice that there are no pattern; when this happens we can't use a linear model to fit the data.
Therefore, there is not a pattern so the data is non-linear and the answer is C.
It says to find the surface area of each figure. Round to the nearest hundredth. Please help!
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SOLUTION
The figure given is a sphere, and we want to find the surface area. The diameter of the sphere has been given as 11 cm.
Surface area of a sphere is found using the formula
[tex]\begin{gathered} S.A=4πr^2 \\ where\text{ r = radius = }\frac{diameter}{2}=\frac{11}{2}=5.5 \end{gathered}[/tex]Putting in the values of pi and radius r into the formula, we have the surface area S.A as
[tex]\begin{gathered} S.A=4πr^2 \\ =4\times\pi\times5.5^2 \\ =380.13271108\text{cm}^2 \end{gathered}[/tex]Hence the answer is 380.13 square-centimeter to the nearest hundredth
calculate the distance Katie rides her bike if she rides 7/10 mile each day for 9 days. Drag your answers in the boxes to complete the answer.
Answers
Answer
[tex]6\frac{3}{10}[/tex]6 and 3 will fill the boxes respectively.
Explanation
Each day, Katie rides her bike (7/10) miles
She then rides for 9 days
1 day = (7/10) mile
9 days = 9 × (7/10) mile = (63/10) mile
We can then convert (63/10) into mixed fractions,
(63/10) = 6 (3/10) miles
Hope this Helps!!!
1 [how much money do they have together. write as a fraction and a decimal
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Given data:
[tex]\begin{gathered} \text{Iris has} \\ 1\frac{3}{5}\text{ dollars} \end{gathered}[/tex][tex]\begin{gathered} \text{Violet has} \\ 2\frac{5}{10}\text{ dollars} \end{gathered}[/tex]Together, they will have:
[tex]\text{Iris}+\text{Violet}=1\frac{3}{5}+2\frac{5}{10}[/tex]step 1=> convert to improper fraction
[tex]\begin{gathered} 1\frac{3}{5}=\frac{8}{5} \\ \\ 2\frac{5}{10}=\frac{25}{10} \end{gathered}[/tex]step 2: sum the improper fractions
[tex]\frac{8}{5}+\frac{25}{10}[/tex]To do this, we will find the lowest common multiple of the denominators
The denominators are 5 and 10
The lowest common multiple of 5 and 10 = 10
Step 3:Express each denominator so they will have the same lowest common multiple as shown below
[tex]\begin{gathered} \frac{8}{5}=\frac{16}{10} \\ \frac{25}{10}=\frac{25}{10} \end{gathered}[/tex][tex]\frac{8}{5}+\frac{25}{10}=\frac{16}{10}+\frac{25}{10}[/tex]Since they now have a common denominator which is their lowest common multiple, we can easily sum the fractions up
[tex]\frac{16}{10}+\frac{25}{10}=\frac{16+25}{10}=\frac{41}{10}[/tex]The answers are:
Expressed as a fraction:
[tex]\frac{41}{10}[/tex]Expressed as a mixed fraction:
[tex]4\frac{1}{10}[/tex]Expressed as a decimal:
[tex]4.1[/tex]after swimming 60 ft below the surface of the water a whale swims up 30 ft. Use a number line to help you create an equation that shows the new location of the whale and relation of the water surface sorry it shows rumed out if you need I can take another picture
Answers
Let's begin by listing out the information given to us:
The whale swam 60 ft below = -60 ft
The whale swam up 30 ft = 30 ft
[tex]\Rightarrow-60+30=-30ft[/tex]Hence, the whale is 30 ft below the surface; option B is the correct answer
Identify the congruence statement that proves both triangles below to be congruent.
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Given: Two triangles
To Determine: The congruence statement that proves both triangles to be congruent
Solution
It can be observed that the two triangles have the same hypothenuse, also both have right angles, and both have a common sides
Using the above, we can conclude that the given triangles are congruent as a result of the congruence statement below
Right-angle Hypothenuse Side (RHS)
$10×$10 -$50+$30 = ?
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the numbers from 1 to 12 are written on separate papers folded and shaken. 6 students pick a pair each and adds the number..they sum of the pair of each student is 4,6,13,14,20,21.find the numbers in each pair
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To answer this question, we will have to list the possible combinations for each outcome.
We can'rt have repetitions and we only have integer numbers from 1 to 12.
So, for 4, we would have the possible pairs of 1 and 3 or 2 and 2, but since we don't have repeating numbers, we only can have 1 and 3.
We will need to do this for every number:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(1+5),(2+4) \\ 13\colon(1+12),(2+11),(3+10),(4+9),(5+8),(6+7) \\ 14\colon(2+12),(3+11),(4+10),(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]Now, the outcome of 4 has onle the possible pair of 1 and 3, so we already know that the first par is 1 and 3.
Since we can't have repetitions, every other pair that has either 1 or 3 can't happen, so:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon\cancel{\mleft(1+5\mright)},(2+4) \\ 13\colon\cancel{(1+12)},(2+11),\cancel{\mleft(3+10\mright)},(4+9),(5+8),(6+7) \\ 14\colon(2+12),\cancel{\mleft(3+11\mright)},(4+10),(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]Now, the outcome of 6 has only one possible pair: 2 and 4. So, we need to exclude any other pair with either 2 or 4:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon\cancel{(1+12)},\cancel{(2+11)},\cancel{\mleft(3+10\mright)},\cancel{\mleft(4+9\mright)},(5+8),(6+7) \\ 14\colon\cancel{\mleft(2+12\mright)},\cancel{\mleft(3+11\mright)},\cancel{\mleft(4+10\mright)},(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]Now, notice that if we pick the pair 5 and 8 for the outcome 13, both remaining possbile outcomes for 14 would be impossible, because each has either 5 or 8. This means that the outcome 13 can't be 5 and 8, so it has to be 6 and 7, so we can exclue the other pairs with 6 or 7:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon\cancel{\mleft(2+12\mright)},\cancel{\mleft(3+11\mright)},\cancel{\mleft(4+10\mright)},(5+9),\cancel{\mleft(6+8\mright)} \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]This makes the only possible pair for 14 to be 5 and 9, so we can exclude the other pairs with either 5 or 9:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon(5+9) \\ 20\colon(8+12),\cancel{\mleft(9+11\mright)} \\ 21\colon\cancel{\mleft(9+12\mright)},(10+11) \end{gathered}[/tex]And this leave us with only one possible pair for 20 and 21, which is 8 and 12 and 10 and 11, so we have all pairs:
[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon(5+9) \\ 20\colon(8+12) \\ 21\colon(10+11) \end{gathered}[/tex]A bank loaned out $18,000 part of it at the rate of 8% per year and the rest at 16% per year. If the interest received in one year total $2500, how much was loaned at 8%? How much of the 18,000 did the bank loan out at 8%?
Answers
The Solution:
Given that a bank loaned out $18000.
Let the amount loaned out at 8% per year be represented with x.
So that the amount loaned out at 16% per year will be $(18000-x)
Recall: By formula for simple interest ( since the simple interest is the same as compound interest if the period under consideration is 1 year), we have:
[tex]I=\frac{\text{PRT}}{100}[/tex]So, for the loan at 8% per year:
[tex]\begin{gathered} I_{1_{}}=\text{ interest=?} \\ P\text{ =principal=\$x} \\ T=\text{ time =1year} \end{gathered}[/tex]So, for the loan at 16% per year:
[tex]\begin{gathered} I_{2_{}}=\text{ interest=?} \\ P\text{ =principal=\$(18000-x)} \\ T=\text{ time =1year} \end{gathered}[/tex][tex](I_1+I_2)=\frac{8\times x\times1}{100}+\frac{(18000-x)\times16\times1}{100}[/tex][tex](I_1+I_2)=\text{ \$2500}[/tex][tex]2500=\frac{8x}{100}+\frac{16(18000-x)}{100}[/tex][tex]2500=\frac{8x+288000-16x}{100}[/tex]Cross multiplying, we get
[tex]250000=288000-8x[/tex][tex]\begin{gathered} 8x=288000-250000 \\ 8x=38000 \end{gathered}[/tex]Dividing both sides by 8, we get
[tex]x=\frac{38000}{8}=\text{ \$4750}[/tex]Thus, the amount loaned at 8% is $4750.
Therefore, the correct answer is $4750.
The roller skating rink has a track that is circular. The inside of the rink can't be used, but has a diameter of 24 feet. The track is 6 feet wide and goes around the outside of the rink. What is the approximate area of the track?
Answers
The track surrounds the rink, it goes around the outside of the rink.
Area of the rink = area of a circle
Area of the track = area of a circle too
[tex]\text{Area of circle = }\pi\text{ }\times r^2[/tex]Diameter of rink = 24 , radius of rink = 24/2 = 12
Area of rink = pi x (24/2)^2 = pi x 12^2= 3.142 x 144 = 452.448 square feet
Diameter of rink + track = 24 + 6+6 = 36, radius = 36/2= 18
Area of rink + track = pi x (18)^2 = 3.142 x 324 = 1018.008 square feet
Finally, Area of just the track = Area of track + rink - area of rink = 1018.008 - 452.448 = 565.56 square feet
Answer = 565.56 square feet
future ker on com/con Btion and ne comp abels will o send e box in next stu nust be ithdra ement return er is s Graph the linear equation given the representation. State if the equation is proportional or nonproportional and justify your decision. V 9 5+ 9 4- 0 -2 3 2+ 1 -1 9 4 Y 2 3 5 6 -6 -5 - 4 -3 - 2 Proportional? Justify: -2+ 3 -4 5+ 6
Answers
First we graph the given points
For the equation to be proportional, the line should pass through the origin (0,0), then this equation is not proportional.
SandwichSideDrinkJr. Bacon Cheeseburger(65%) Fries (63%)Coke(33%)Crispy Chicken Sandwich(35%) Salad (17%)Diet Coke(18%)Baked Potato (20%) Dr. Pepper (26%)Sprite (23%)So based on these sales numbers, whatare the odds that the next customerorders a Jr. Bacon Cheeseburger, fries orpotato, and a Dr. Pepper?
Answers
It is given that the probability of odering a Cheeseburger, fries or potato, and a Dr. Pepper is given by:
[tex]\begin{gathered} P(A)=P(C)\times(P(F)+P(P))\times P(DP) \\ P(A)=0.65\times(0.63+0.2)\times0.26 \\ P(A)=0.14027 \end{gathered}[/tex]Hence the probability is 14%.
Option B is correct.
part A- which equation represents the selling price ,s, in dollars of an item originally priced p dollars after a markdown of 30%A-s=0.3pB-s=0.7pC-p=0.3sD-p=0.7spart B- complete the table below to show pairs of solutions to the equation in part A
Answers
Let s be the selling price and let p be the original price
s = 30% of p
= 0.3 x p
= 0.3p
s = 0.3p
500 students attend Ridgewood Junior High School. 4% of students bring their lunch to school everyday. How many students brought their lunch to school on Thursday? Divide/scale down to solve for the missing percent
Answers
The number of students brought their lunch to school on Thursday is 20 students.
Percentage -
A percentage is a figure or ratio that can be stated as a fraction of 100 in mathematics.
If we calculate % of a number then we have to divide the number by whole and multiple by hundred.No. of students attend Ridgewood Junior High School. = 500
percentage of students bring their lunch to school = 4%
students brought lunch of thursday = 4% 0f 500
= (4/100) x 500
= 4 x 5
= 20 students
The number of students brought their lunch to school on Thursday is 20 students.
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