The solution to the given initial value problem is:
y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)
y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)
Taking the Laplace transform of the given system of differential equations, we get:
sY1(s) - y1(0) = 5Y1(s) - 4Y2(s) - 2(2/(s^3)) + 2(1/(s^2))
sY2(s) - y2(0) = 10Y1(s) - 77(1/s) - 17(1/(s^2)) - 2(1/(s^2))
Applying the initial conditions, we get:
sY1(s) - 3 = 5Y1(s) - 4Y2(s) - 4/s^3 + 2/s^2
sY2(s) = 10Y1(s) - 77/s - 17/s^2 - 2/s^2
Solving for Y2(s), we get:
Y2(s) = (10Y1(s) - 77/s - 17/s^2 - 2/s^2)/s
Substituting this in the equation for Y1(s), we get:
sY1(s) - 3 = 5Y1(s) - 4[(10Y1(s) - 77/s - 17/s^2 - 2/s^2)/s] - 4/s^3 + 2/s^2
Simplifying and solving for Y1(s), we get:
Y1(s) = (3s^3 + 10s^2 + 8s + 154)/(s^5 + 5s^3 + 4s)
Taking the inverse Laplace transform, we get:
y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)
y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)
Therefore, the solution to the given initial value problem is:
y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)
y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)
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Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles x^2+y^2=144 and x^2-12x+y^2=0
The area between the two circles in the first quadrant is 18π square units.
To evaluate this integral, we first need to find the polar equations of the two circles.
For the circle [tex]x^2 + y^2 = 144,[/tex] we can convert to polar coordinates using the substitutions x = r cos θ and y = r sin θ, which gives:
[tex]r^2 = x^2 + y^2 = 144[/tex]
r = 12 (since r must be non-negative in polar coordinates)
For the circle [tex]x^2 - 12x + y^2 = 0[/tex], we can complete the square to get:
[tex]x^2 - 12x + 36 + y^2 = 36[/tex]
[tex](x - 6)^2 + y^2 = 6^2[/tex]
Again using the substitutions x = r cos θ and y = r sin θ, we get:
(r cos θ - 6[tex])^2[/tex] + (r sin θ[tex])^2[/tex] = [tex]6^2[/tex]
[tex]r^2 cos^2[/tex] θ - 12r cos θ + 36 +[tex]r^2 sin^2[/tex] θ = 36
r^2 - 12r cos θ = 0
r = 12 cos θ
Now we can set up the integral to find the area between the two circles in the first quadrant. Since we are in the first quadrant, θ ranges from 0 to π/2. We can integrate over r from 0 to 12 cos θ (the radius of the inner circle at the given θ), since the area between the two circles is bounded by these two radii.
Thus, the integral to evaluate is:
∫[θ=0 to π/2] ∫[r=0 to 12 cos θ] r dr dθ
Integrating with respect to r gives:
∫[θ=0 to π/2] [(1/2) r^2] from r = 0 to r = 12 cos θ dθ
= ∫[θ=0 to π/2] (1/2) (12 cos θ)^2 dθ
= ∫[θ=0 to π/2] 72 cos^2 θ dθ
Using the trigonometric identity cos^2 θ = (1 + cos 2θ)/2, we can simplify this to:
∫[θ=0 to π/2] 36 + 36 cos 2θ dθ
= [36θ + (18 sin 2θ)] from θ = 0 to θ = π/2
= 36(π/2) + 18(sin π - sin 0)
= 18π
Therefore, the area between the two circles in the first quadrant is 18π square units.
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Find the value of c using the given chord and secant lengths in the diagram shown to the right.
The value of each variable in the circle is:
b = 90°
c = 47°
a = 43°
How to find the value of each variable in the circle?A circle is a round-shaped figure that has no corners or edges. It can be defined as a closed shape, two-dimensional shape, curved shape.
An angle inscribed in a semicircle is a right angle. Thus,
b = 90°
c = 360 - 133 - 180 (sum of angle in a circle)
c = 47°
a = 180 - 90 - 47 (sum of angle in a triangle)
a = 43°
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HEY GUYS NEED SOME HELP ON THIS ONE!!!
Triangle LNR is graphed on a coordinate grid shown below.
A translation 3 units right and 2 units down, followed by a dilation centered at the origin with a scale factor of 2, is performed on triangle LNR to create triangle L'N'R'. Which statement about side of triangle L'N'R' is true?
a. Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of side is 12 units.
b. Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of side is 10 units.
c. Because vertex L' is located at (–4, 4) and vertex N' is located at (2, –4), the length of side is 12 units.
d. Because vertex L' is located at (–4, 4) and vertex N' is located at (2, –4), the length of side is 10 units.
The correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."
First, we perform a translation 3 units right and 2 units down. This means we add 3 to the x-coordinates and subtract 2 from the y-coordinates of each vertex:
L' = (-1, 3)
R' = (-2, 1)
N' = (2, -1)
Next, we perform a dilation centered at the origin with a scale factor of 2. This means we multiply the coordinates of each vertex by 2:
L" = (-2, 6)
R" = (-4, 2)
N" = (4, -2)
Now, we can use the distance formula to calculate the lengths of the sides of triangle L'N'R':
L'N' = √[(4+2)² + (-2-6)²] = √[100] = 10
Therefore, the correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."
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(a) Determine the mean and standard deviation of the sampling distribution of X. The mean is Hy = 176.5. (Type an integer or a decimal. Do not round.) The standard deviation is on = 1.28 . (Type an integer or a decimal. Do not round.) (b) Determine the expected number of sample means that fall between 174.2 and 177.2 centimeters inclusive. sample means (Round to the nearest whole number as needed.)
The expected number of sample means falling between 174.2 and 177.2 can be estimated as:
Expected number = A * Total number of sample means.
(a) The mean of the sampling distribution of X is given as 176.5 and the standard deviation is 1.28.
(b) To determine the expected number of sample means that fall between 174.2 and 177.2 centimeters inclusive, we need to calculate the z-scores corresponding to these values and find the area under the normal curve between these z-scores.
The z-score for 174.2 can be calculated as:
z1 = (174.2 - 176.5) / 1.28
Similarly, the z-score for 177.2 can be calculated as:
z2 = (177.2 - 176.5) / 1.28
Using a standard normal distribution table or a calculator, we can find the area between these two z-scores.
Let's assume the area between z1 and z2 is A. The expected number of sample means falling between 174.2 and 177.2 can be estimated as:
Expected number = A * Total number of sample means.
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find the range of f(x) = 2x -3 when the domain is { -2 , 0, 1/2 , 5}
The range of f(x) = 2x -3 include the following: {-7, -3, -2, 7}.
What is a domain?In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.
When the domain is -2, the range of this function can be calculated as follows;
f(x) = 2x - 3
f(-2) = 2(-2) - 3
f(-2) = -7.
When the domain is 0, the range of this function can be calculated as follows;
f(x) = 2x - 3
f(0) = 2(0) - 3
f(0) = -3.
When the domain is 1/2, the range of this function can be calculated as follows;
f(x) = 2x - 3
f(1/2) = 2(1/2) - 3
f(1/2) = -2.
When the domain is 5, the range of this function can be calculated as follows;
f(x) = 2x - 3
f(5) = 2(5) - 3
f(5) = 7.
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An artist is painting a mural at the Hattiesburg Zoo. She draws
a diagram of the mural before painting,
2 ft.
10 ft.
5 ft.1
7
14 ft
8 ft.
104 square feet is the total area of the mural.
From the figure, we can say that the total area of the mural can be found by using basic algebra,
So,
The total area of the mural = area of the rectangle +area of the triangle- an area of a smaller triangle.
So, First for a bigger triangle,
the height of the triangle = 5 +2 = 7 ft.
the base of the triangle = 14 ft.
the area = 1/2*base*height
Thus the area = 49 square feet.
For the rectangle,
Height of the rectangle = 8 ft.
Width of the rectangle = 10 ft.
Thus the area of the rectangle = width * height
The area of the rectangle = 80 square feet
For the smaller triangle,
the height of the triangle = 5 ft.
the base of the triangle = 10 ft.
the area = 1/2*base*height
Thus the area = 25 square feet.
Hence,
Total area of the mural = 80 + 49 -25
Therefore, The total area of the mural is 104 square feet
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The area of a circle is 4π in². What is the circumference, in inches? Express your answer in terms of pi
The circumference of the area of a circle is 4π in² using the formula A = πr², in inches is 4π inches.
The formula for the area of a circle is A = πr², where A is the area and r is the radius. Given that the area is 4π in², we can solve for the radius by taking the square root of both sides:
√(A/π) = √(4π/π) = 2 in
The formula for the circumference of a circle is C = 2πr, where C is the circumference and r is the radius. Substituting the value of r, we get:
C = 2π(2 in) = 4π in
Therefore, the circumference of the circle is 4π inches.
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Which of these is a correct expansion of (3x – 2)(2x2 + 5)?
A. 3x • 2x2 + 3x • 5 + (–2) • 2x2 + (–2) • 5
B. 3x • 2x2 + 3x • 5 + 2 • 2x2 + 2 • 5
C. 3x • 2x2 + (–2) • 2x2 + 2x2 • 5 + (–2) • 5
The correct expansion of (3x – 2)(2[tex]x^2[/tex] + 5) is 3x * 2[tex]x^2[/tex] + 3x * 5 + (–2) * 2[tex]x^2[/tex] + (–2) * 5. Thus option A is the most appropriate option as the answer the above question
The expansion of the given algebraic expression follows the distributive rule of multiplication that is (a + b)(c + d) = ac + ad + bc + bd.
Thus the first term of the first expression which is 3x is multiplied by the the second expression and we get 3x • 2[tex]x^2[/tex] + 3x • 5 + (–2)
Then the second term that is -2 is multiplied by the second expression and we get 5 + (–2) • 2[tex]x^2[/tex] + (–2) • 5
Then we add both expressions and get the answer 3x * 2[tex]x^2[/tex] + 3x * 5 –2 * 2[tex]x^2[/tex] –2 * 5.
After further simplification of the above expression we get, 6[tex]x^3[/tex] + 15x - [tex]4x^2[/tex] - 10.
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Answer!!!!! Tysm!!!!
The angle measurement of the triangle would be 9. 59 degrees
How to determine the valueThe different trigonometric identities are given as;
sinetangentcotangentcosinesecantcosecantThe ratios of the trigonometric identities are represented as;
sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
From the information given, we have;
Opposite side = 1
Hypotenuse side = 6
Using the sine identity, we have;
sin θ = 1/6
Divide the values
sin θ = 0. 1666
Find the inverse of the sine
θ = 9. 59 degrees
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what do I need to do,help Please?!
The slope of the graph is 50, and it represents the rate of change of the total cost of the gym membership per month.
To write an equation for C, the total cost of the gym membership, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this case, y represents the total cost, m represents the slope, x represents the number of months, and b represents the y-intercept (the initial cost of joining the gym).
From the graph, we can see that the initial cost of joining the gym is $700 (the y-intercept), and the monthly fee is $50 (the slope of the line connecting the dots). So, the equation for C is:
C = 50t + 700
where t is the number of months.
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What's the answer? Geometry
The area of the trapezoid in this problem is given as follows:
C. [tex]A = 96\sqrt{3}[/tex] mm².
How to obtain the height of the trapezoid?The area of a trapezoid is given by half the multiplication of the height by the sum of the bases, hence:
A = 0.5 x h x (b1 + b2).
The bases in this problem are given as follows:
11 mm and 15 + 6 = 21 mm.
The height of the trapezoid is obtained considering the angle of 60º, for which:
The adjacent side is of 6 mm.The opposite side is the height.We have that the tangent of 60º is given as follows:
[tex]tan{60^\circ} = \sqrt{3}[/tex]
The tangent is the division of the opposite side by the adjacent side, hence the height is obtained as follows:
[tex]\sqrt{3} = \frac{h}{6}[/tex]
[tex]h = 6\sqrt{3}[/tex]
Thus the area of the trapezoid is obtained as follows:
[tex]A = 0.5 \times 6\sqrt{3} \times (11 + 21)[/tex]
[tex]A = 96\sqrt{3}[/tex] mm².
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The probability distribution of a 3-coin toss is shown in the table. Find the expected number of heads.
The expected number of heads = 1.5
The correct answer is an option (B)
We know that the formula for the expected value is:
E (x) = ∑ x P ( x )
where P(x) represents the probability of outcome X
and E(x) is the expected value of x
We need to find the expected number of heads.
From the probability distribution table of a 3-coin toss, the expected number of heads would be,
E(H) = 0(1/8) + 1(3/8) + 2(3/8) + 3(1/8)
E(H) = 0 + 3/8 + 6/8 + 3/8
E(H) = 12/8
E(H) = 1.5
The correct answer is an option (B)
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Answer:
Step-by-step explanation:
Three tennis balls are stored in a cylindrical container with a height of 8.2 inches and a radius of 1.32 inches. The circumference of a tennis ball is 8 inches. Find the amount of space within the cylinder not taken up by the tennis balls. Round your answer to the nearest hundredth.
The amount of space within the cylinder not taken up by the tennis balls is 18.9 [tex]inches^3[/tex]
The volume of a tennis ball:
The circumference of the tennis ball is 8 inches.
The tennis ball is the form of sphere whose circumference is given by formula [tex]2\pi r[/tex], where r is the radius.
Thus, if r is the radius then according to condition,
[tex]2\pi r[/tex] = 8 or
r = 8/2[tex]\pi[/tex] inches.
Now, the volume of the sphere of radius r is [tex]\frac{4}{3}\pi r^3[/tex] hence, find the volume of the given tennis ball by substituting r = 8/2[tex]\pi[/tex] inches in [tex]\frac{4}{3}\pi r^3[/tex] and simplify:
Volume = [tex]\frac{4}{3}\pi[/tex] × [tex](\frac{8}{2\pi } )^3[/tex]
Volume = 8.65[tex]inches^3[/tex]
Hence the required volume of the tennis ball is 8.65[tex]inches^3[/tex]
The volume of three tennis balls is (3 × 8.65) [tex]inches^3[/tex] = 25.96 [tex]inches^3[/tex]
Find the volume of the cylinder:
The volume of the cylinder with radius r units and height h units is given by [tex]\pi r^2h[/tex] Hence the volume of the given cylinder with radius 1.32 inches , 8.2 height inches is:
[tex]\pi (1.32)^2[/tex] × 8.2
= 3.14 × [tex](1.32)^2[/tex] × 8.2
= 44.86 [tex]inches^3[/tex]
Hence the volume of the cylinder is 44.86 [tex]inches^3[/tex]
Find the amount of space within the cylinder not taken up by the tennis balls.
The required volume can be obtained by subtracting the volume three tennis balls from the volume of the cylinder as follows:
Volume of cylinder - volume of three tennis balls = (44.86 - 25.96) = 18.9 [tex]inches^3[/tex]
Hence, the amount of space within the cylinder not taken up by the tennis balls is 18.9 [tex]inches^3[/tex]
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Taylor has $900 in savings and she spends $100 each month of it on car insurance. Danny has $1200 a month but spends $150 a month on car insurance. Assuming they don't put more money into their account, do they ever have the same amount of money in their accounts, it so, when? Who runs out of money first?
Answer: Taylor will run out of money first after 9 months, while Danny will run out of money after 8 months.
Step-by-step explanation:
To solve this problem, we can set up two equations to represent Taylor and Danny's savings over time, where x is the number of months that have passed:
Taylor: 900 - 100x
Danny: 1200 - 150x
To find out when they have the same amount of money in their accounts, we can set the two equations equal to each other and solve for x:
900 - 100x = 1200 - 150x
50x = 300
x = 6
Therefore, Taylor and Danny will have the same amount of money in their accounts after 6 months. To find out how much money they will have at that time, we can substitute x = 6 into either equation:
Taylor: 900 - 100(6) = 300
Danny: 1200 - 150(6) = 300
So after 6 months, both Taylor and Danny will have $300 in their accounts.
To determine who runs out of money first, we can set each equation equal to zero and solve for x:
Taylor: 900 - 100x = 0
x = 9
Danny: 1200 - 150x = 0
x = 8
Therefore, Taylor will run out of money first after 9 months, while Danny will run out of money after 8 months.
Based on a random sample of 25 units of product X, the average weight is 102 lb and the sample standard deviation is 10 lb. We would like to decide whether there is enough evidence to establish that the average weight for the population of product X is greater than 100 lb. Assume the population is normally distributed. Using the critical value rule, at α =. 01, we can reject the null hypothesis
We cannot rule out the null hypothesis that the population means the weight is equal to 100 lb based on the critical value rule at = 0.01.
A one-sample t-test can be used to evaluate whether we can rule out the null hypothesis that the population's average weight is 100 lb.
First, we need to calculate the test statistic t:
[tex]$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$[/tex]
[tex]$t = \frac{(102 - 100)}{\frac{10}{\sqrt{25}}} = 2$[/tex]
The critical value for the t-distribution with 24 degrees of freedom and a significance level of 0.01 must then be determined. To determine this value, we can utilize a t-table or statistical software.
We establish the critical value to be 2.492 using a t-table. We are unable to reject the null hypothesis because our calculated t-value (2) is smaller than the crucial value (2.492).
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Determine whether each statement is True or False. Select the correct cell in each row. Statement True False T h e s u m o f − 9 a n d 18 2 i s e q u a l t o 0. The sum of −9 and 2 18 is equal to 0. T h e s u m o f − 14 2 a n d 7 i s g r e a t e r t h a n 0. The sum of − 2 14 and 7 is greater than 0. T h e s u m o f 6 , − 4 , a n d − 2 i s e q u a l t o 0. The sum of 6, −4, and −2 is equal to 0. T h e s u m o f 7 , − 9 , a n d 2 i s l e s s t h a n 0. The sum of 7, −9, and 2 is less than 0.
Each of the statements should be marked correctly as follows;
The sum of −9 and 18/2 is equal to 0: True.
The sum of −14/2 and 7 is greater than 0: False.
The sum of 6, −4, and −2 is equal to 0: True.
The sum of 7, −9, and 2 is less than 0: False.
What is an inequality?In Mathematics and Geometry, an inequality simply refers to a mathematical relation that is typically used for comparing two (2) or more numerical data and variables in an algebraic equation based on any of the inequality symbols;
Greater than (>).Less than (<).Greater than or equal to (≥).Less than or equal to (≤).Next, we would evaluate each of the statements as follows;
-9 + 18/2 = -9 + 9 = 0
Therefore, the sum of −9 and 18/2 is truly equal to 0.
-14/2 + 7 = -7 + 7 = 0.
Therefore, the sum of −14/2 and 7 is not greater than 0.
6 - 4 - 2 = 0
Therefore, the sum of 6, −4, and −2 is truly equal to 0.
7 - 9 + 2 = 0
Therefore, the sum of 7, −9, and 2 is not less than 0.
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on the first of each month, $100 is deposited into a savings account that pays 6% interest, compoundedmonthly. assuming that no withdraws are made, give a recurrence relation for the total amount of money inthe account at the end of n months.
The recurrence relation for the total amount of money in the savings account at the end of n months can be expressed using a recursive formula that takes into account the monthly deposits and the compounded interest. Let A_n be the total amount of money in the account at the end of the nth month. Then, we have:
A_n = A_{n-1} + 100 + (0.06/12)*A_{n-1}
Here, A_{n-1} represents the total amount of money in the account at the end of the (n-1)th month, which includes the deposits made in the previous months and the accumulated interest. The term 100 represents the deposit made at the beginning of the nth month.
The term (0.06/12)*A_{n-1} represents the interest earned on the balance in the account at the end of the (n-1)th month, assuming a monthly interest rate of 0.06/12.
Using this recursive formula, we can calculate the total amount of money in the account at the end of each month, starting from the initial balance of $0. For example, we can calculate A_1 = 100 + (0.06/12)*0 = $100, which represents the balance at the end of the first month.
Similarly, we can calculate A_2 = A_1 + 100 + (0.06/12)*A_1 = $206, which represents the balance at the end of the second month. We can continue this process to calculate the balances at the end of each month up to the nth month.
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Do not answer with another chegg expert solution, i will dislike the answer, It is NOT (C)Question 1
Please see the Page 27 in the PowerPoint slides of Chapter 8. If the first boundary condition
becomes Y'(0)=1, what is the correct SOR formula for this boundary condition?
OY'1 = 1
OY₁ =1/6∆ (4Y₂ - Y3)
O Y₁ = y0+y2/2-0.05∆z(Y₂-Yo)
O Y₁ = 1
O Y₁ = (4Y₂ - Y₁ - 2∆x)
OY₁ = 2∆z + Y3
The correct SOR formula for the boundary condition Y'(0) = 1 is:
OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)
To derive the correct SOR formula for the boundary condition Y'(0) = 1, we start with the standard SOR formula:
OYᵢ = (1 - ω)Yᵢ + (ω/4)(Yᵢ₊₁ + Yᵢ₋₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²fᵢ)
where i and j are indices corresponding to the discrete coordinates in the x and y directions, ω is the relaxation parameter, and ∆ is the grid spacing in both directions.
To incorporate the boundary condition Y'(0) = 1, we use a forward difference approximation for the derivative:
Y'(0) ≈ (Y₁ - Y₀) / ∆
Substituting this into the original equation gives:
(Y₁ - Y₀) / ∆ = 1
Solving for Y₀ gives:
Y₀ = Y₁ - ∆
Now we can use this expression for Y₀ to modify the SOR formula at i = 1:
OY₁ = (1 - ω)Y₁ + (ω/4)(Y₂ + Y₀ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²f₁)
Substituting the expression for Y₀, we get:
OY₁ = (1 - ω)Y₁ + (ω/4)(Y₂ + Y₁ - ∆ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²f₁)
Simplifying:
OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)
So the correct SOR formula for the boundary condition Y'(0) = 1 is:
OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)
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Mona pays $1. 00 for the first call of the day on her mobile phone plus $0. 15 per minute of the call. She paid $2. 95 for her first call today. Write an expression that you could use to calculate the length in minutes of the phone call
The expression to calculate the length in minutes of the phone call is:
(length of call in minutes) = (total cost - fixed cost) / (cost per minute)
Where the fixed cost is $1.00 and the cost per minute is $0.15.
Mona's mobile phone plan charges a fixed cost of $1.00 for the first call of the day and an additional $0.15 per minute for the length of the call. To calculate the length of the call in minutes, we need to subtract the fixed cost of $1.00 from the total cost of the call and then divide the result by the cost per minute of $0.15. This gives us the equation:
(length of call in minutes) = (total cost - fixed cost) / (cost per minute)
Substituting the values given in the problem, we get:
(length of call in minutes) = ($2.95 - $1.00) / ($0.15)Simplifying this expression, we have:
(length of call in minutes) = $1.95 / $0.15Dividing $1.95 by $0.15 gives us the answer:
(length of call in minutes) = 13Therefore, Mona's phone call lasted 13 minutes.
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Find the exact values of x and y.
The values of x and y are given as follows:
x = y = 5.
What is the Pythagorean Theorem?The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.
The theorem is expressed as follows:
c² = a² + b².
In which:
c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.The diagonal length of the rectangle is the hypotenuse of a right triangle of sides 6 and 8, hence:
d² = 6² + 8²
d² = 100
d = 10.
The segments x and y are each half the length of the diagonal, and the two diagonals have the same length for a rectangle, hence:
x = y = 5.
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what are the exact values of the cosecant, secant, and cotangent ratios of -pi/4 radians?
The exact values of cosecant, secant, and cotangent ratios of -pi/4 radians is:
[tex]csc=\frac{\pi }{4}=\frac{hypontenuse}{opposite}=\frac{\sqrt{2} }{1}=\sqrt{2}[/tex]
[tex]sec=\frac{\pi }{4}=\frac{hypotenuse}{adjacent}= \frac{\sqrt{2} }{1}=\sqrt{2}[/tex]
[tex]cot=\frac{\pi }{4}=\frac{adjacent}{opposite}=\frac{1}{1}=1[/tex]
[tex]\frac{\pi }{4}[/tex] radians is the same as 90 degrees. So, first draw a right triangle with an angle of [tex]\frac{\pi }{4}[/tex]:
This creates a 45-45-90 triangle, also known as a right isosceles triangle. This is a very special triangle, and we know that both of its legs will be the same length, and the hypotenuse will be the length of one of the legs times √2.
The three functions are just the inverses of the first three. Cosecant is the inverse of sine, secant is the inverse of cosine, and cotangent is the inverse of tangent.
[tex]csc=\frac{\pi }{4}=\frac{hypontenuse}{opposite}=\frac{\sqrt{2} }{1}=\sqrt{2}[/tex]
[tex]sec=\frac{\pi }{4}=\frac{hypotenuse}{adjacent}= \frac{\sqrt{2} }{1}=\sqrt{2}[/tex]
[tex]cot=\frac{\pi }{4}=\frac{adjacent}{opposite}=\frac{1}{1}=1[/tex]
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Joseph has a bag filled with 2 red, 6 green, 15 yellow, and 7 purple marbles. Determine P(not green) when choosing one marble from the bag.
90%
80%
60%
20%
Answer:
Step-by-step explanation:
80%
We have to make choices every day. Some choices may affect our lives for years, like the colleges we attend.
Other decisions have short-term effects, like where we should eat lunch.
Read the options below. Which option would you choose?
A. Option 1: Receive $1,000,000 today.
B. Option 2: Receive $25,000 every day for a month (30 days).
C. Option 3: Start with 1 penny, then double it every day for a month (30 days).
Answer:
C
Step-by-step explanation:
The reason I would choose C is that the penny doubling each day might seem small but the amount would continue to grow exponentially giving you a might higher payoff than the rest of the options. I don't know the exact amount you would get by it is around 3 mill.
Option B gives you linear growth, which means that by the end of 30 days, you would only have 750,000.
Option A is the worst potion only leaving you with 1 million.
Find the inverse g(x) of the following functions. Sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x. a. f(x) = 3x - 2 b. f(x)= Vx - 3
a. the inverse function g(x) is: g(x) = (x + 2)/3
b. the inverse function g(x) is: g(x) = [tex]x^2 + 3[/tex]
What is inverse fucntion?
An inverse function is a function that "undoes" the action of another function. More specifically, if a function f takes an input x and produces an output f(x), then its inverse function, denoted f^(-1), takes an output f(x) and produces the original input x.
a. f(x) = 3x - 2
To find the inverse of f(x), we first replace f(x) with y:
y = 3x - 2
Next, we solve for x in terms of y:
y + 2 = 3x
x = (y + 2)/3
So the inverse function g(x) is:
g(x) = (x + 2)/3
To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.
Graph of f(x) and g(x):
The blue line represents f(x) and the green line represents g(x). As we can see, the two lines are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the origin. This means that if we reflect any point on the blue line across the line y=x, we will get the corresponding point on the green line, and vice versa.
[tex]b. f(x) = \sqrt(x - 3)[/tex]
To find the inverse of f(x), we first replace f(x) with y:
[tex]y = \sqrt(x - 3)[/tex]
Next, we solve for x in terms of y:
[tex]y^2 = x - 3\\\\x = y^2 + 3[/tex]
So the inverse function g(x) is:
[tex]g(x) = x^2 + 3[/tex]
To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.
Graph of f(x) and g(x):
The red curve represents f(x) and the blue curve represents g(x). As we can see, the two curves are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the point (3,0). This means that if we reflect any point on the red curve across the line y=x, we will get the corresponding point on the blue curve, and vice versa.
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f(x)= [tex]f(x)=\frac{x^{2} +7}{x^{2} +4x-21}[/tex]
The value of the function f(x) = ( x² + 7 ) / ( x² + 4x - 21 ) for x = 5 is equal to 4/3.
The function is equal to,
f(x) = ( x² + 7 ) / ( x² + 4x - 21 )
find the value of f(x) at x=5 by substituting x=5 into the given function we have,
⇒ f(5) = ( 5² + 7 ) / ( 5² + 4(5) - 21 )
⇒ f(5) = ( 25 + 7 ) / ( 25 + 20 - 21 )
⇒ f(5) = 32 / 24
Now reduce the fraction by taking out the common factor of the numerator and the denominator we get,
⇒ f(5) = ( 8 × 4 ) / ( 8 × 3 )
⇒ f(5) = 4/3
Therefore, the value of the function f(x) at x=5 is 4/3.
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The given question is incomplete, I answer the question in general according to my knowledge:
Find the value of the function f(x) at x = 5.
f(x) = ( x² + 7 ) / ( x² + 4x - 21 )
During a lab experiment, the temperature of a liquid changes from 625°F to 1034°F.
What is the percent of increase in the temperature of the liquid?
Enter your answer in the box as a percent rounded to the nearest hundredth
Therefore, the percent increase in temperature is approximately 65.44%.
The percent increase in temperature, we need to find the difference between the initial and final temperatures, divide that by the initial temperature, and then multiply by 100 to get a percentage:
Calculate the variation between the initial and end values. Subtract the beginning value from its absolute value. Add 100 to the result.
Even in a low-emission scenario, the earth is predicted to rise by two degrees Celsius by 2050, suggesting that we might not be able to keep the Paris Agreement. Compared to the average temperature between 1850 and 1900, the global temperature has increased by 1.1°C.
percent increase = ((final temperature - initial temperature) / initial temperature) x 100
In this case:
percent increase = ((1034 - 625) / 625) x 100
percent increase = (409 / 625) x 100
percent increase = 65.44%
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a population numbers 17,000 organisms initially and grows by 19.7% each year. suppose represents population, and the number of years of growth. an exponential model for the population can be written in the form where
The exponential model for the population can be written as P = 17000(1 + 0.197)^t, where P represents the population after t years of growth.
Based on your given information, the population starts at 17,000 organisms and grows by 19.7% each year. To represent this growth using an exponential model, you can write the equation in the form P(t) = P₀(1 + r)^t, where P(t) is the population after t years, P₀ is the initial population, r is the growth rate, and t is the number of years.
In this case, P₀ = 17,000 and r = 0.197. So, the exponential model for the population can be written as:
P(t) = 17,000(1 + 0.197)^t
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the domain of function f is (-oo, oo). the value of the function what function could be f
The domain of rational function f(x) = (x² - 36) / (x - 6) is x ∈ (- ∞, + ∞).
How to find a function associated with a given domain
In this question we must determine what function has a domain, that is, the set of all x-values, that comprises all real numbers. According to algebra, polynomic functions have a domain that comprises all real numbers.
Herein we need to determine what rational function is equivalent to a polynomic function. Polynomic functions are expression of the form:
[tex]y = \sum\limits_{i = 0}^{n} c_{i}\cdot x^{i}[/tex]
Where:
[tex]c_{i}[/tex] - i-th Coefficient of the polynomial.[tex]x^{i}[/tex] - Power of the i-th term of the polynomial.y - Dependent variable.Now we check the following expression by algebra properties:
f(x) = (x² - 36) / (x - 6)
f(x) = [(x - 6) · (x + 6)] / (x - 6)
f(x) = x + 6
The rational function f(x) = (x² - 36) / (x - 6) is equivalent to polynomial of grade 1 and, thus, its domain comprises all real numbers.
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A slot machine consists of 4 reels, and each real consists of 16 stops. To win the jackpot of $10,000, a player must get a wild symbol on the center line of each reel. If each reel has two wild symbols, find the probability of winning the jackpot. A. 1/4,096 B. 1/8,192 C. 1/8 D. 4/65,536
Answer: The probability of winning the jackpot is 1/4096, which corresponds to option A
Step-by-step explanation:
To find the probability of winning the jackpot, we need to find the probability of getting a wild symbol on the center line of each of the 4 reels.
Since there are 16 stops on each reel and 2 wild symbols on each reel, the probability of getting a wild symbol on the center line of a single reel is 2/16 or 1/8.
The probability of getting a wild symbol on the center line of all 4 reels is the product of the probabilities for each reel. Thus:
(1/8) * (1/8) * (1/8) * (1/8) = 1/4096
(1 point) find the limit. use l'hospital's rule if appropriate. use inf to represent positive infinity, ninf for negative infinity, and d for the limit does not exist. \lim\limits {x\rightarrow \infty} \dfrac{8 x}{2 \ln (1 2 e^x)}
The limit of the function as x approaches infinity is infinity.
To evaluate this limit, we can use L'Hospital's rule, which says that if we have an indeterminate form of the type 0/0 or infinity/infinity, we can differentiate the numerator and denominator separately with respect to the variable of interest, and then take the limit again.
In this case, we have infinity/infinity, so we can apply L'Hospital's rule:
\begin{aligned}
\lim_{x\rightarrow\infty} \frac{8x}{2\ln(12e^x)} &= \lim_{x\rightarrow\infty} \frac{8}{\frac{2}{12e^x}}\\
&= \lim_{x\rightarrow\infty} \frac{8}{\frac{1}{6e^x}}\\
&= \lim_{x\rightarrow\infty} 48e^x\\
&= \infty
\end{aligned}
Therefore, the limit of the function as x approaches infinity is infinity.
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