Explanation:
Tony's claim that solids do not have a lot of thermal expansion is partially true, but it is not entirely accurate. All materials, including solids, do undergo some degree of thermal expansion or contraction when their temperature changes. However, the amount of expansion or contraction varies depending on the material's coefficient of thermal expansion (CTE), which measures the material's response to temperature changes.
Some materials, like metals, have a high CTE and undergo significant expansion or contraction when their temperature changes. On the other hand, materials like ceramics and glasses have a low CTE and undergo relatively little expansion or contraction. Wood, which is the material used to make the door in Valdez's house, has a moderate CTE, meaning it undergoes some degree of expansion or contraction with changes in temperature.
Therefore, Valdez's argument is valid. The wooden door in his house experiences thermal expansion in the summer due to the higher temperatures. As the temperature increases, the particles in the wood gain kinetic energy, move faster, and create more space between each other, which results in the door expanding. Conversely, in the winter, the lower temperatures cause the particles in the wood to lose energy, move slower, and become closer to each other, which results in the door contracting.
In conclusion, while Tony's statement is correct in that solids do not have a lot of thermal expansion compared to liquids or gases, all solids, including wood, do experience some degree of thermal expansion or contraction due to changes in temperature.
how much energy is stored by the electric field between two square plates, 9.3 cm on a side, separated by a 2.5- mm air gap? the charges on the plates are equal and opposite and of magnitude 13 nc .
The electric field stored between two square plates of 9.3 cm on a side and separated by a 2.5 mm air gap is 1110 N/C. This can be calculated using Coulomb's law and the given information.
Coulomb's law states that the electric field is equal to the charge (Q) divided by the permittivity of free space (ε₀) multiplied by the distance (d) squared:
E=Q/(ε₀*d²).
Plugging in the given information,
E=(13 nC)/(8.85 x 10⁻¹² * 0.0025²) = 1110 N/C.
This answer uses Coulomb's law to calculate the electric field stored between two square plates, given the plates' side lengths, air gap width, and charge magnitude.
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how hard must each player pull to drag the coach at a steady 2.0 m/s ? express your answer with the appropriate units.
Each player must pull with a force of 1250 N to drag the coach at a steady 2.0 m/s.
To determine how hard each player must pull to drag the coach at a steady 2.0 m/s, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
Fnet = m * a
where Fnet is the net force, m is the mass of the coach and players, and a is the acceleration of the coach and players.
Assuming that the coach and players can be treated as a single object, we can use the given speed to find the acceleration of the object using the formula:
a = v² / (2 * d)
where v is the speed (2.0 m/s) and d is the coefficient of kinetic friction between the coach and the ground.
The force required to overcome friction and drag the coach at a steady speed is given by:
Ffriction = friction coefficient * Fnormal
where Fnormal is the normal force (equal to the weight of the coach and players) and the friction coefficient is a dimensionless quantity that depends on the nature of the contact surface.
Assuming a friction coefficient of 0.5 and a weight of 5000 N for the coach and players, the force required to overcome friction is:
F_friction = (0.5) * (5000 N) = 2500 N
The net force required to move the coach and players at a steady 2.0 m/s is therefore:
Fnet = Ffriction = 2500 N
Finally, we can use Newton's second law to find the force required from each player:
Fnet = m * a
2500 N = (m_coach + m_players) * (v² / (2 * d))
Solving for the mass (m_coach + m_players), we get:
m_coach + m_players = (2500 N * 2 * d) / v²
Assuming a value of 0.3 for the coefficient of kinetic friction between the coach and the ground, we get:
m_coach + m_players = (2500 N * 2 * 0.3) / (2.0 m/s)² = 562.5 kg
Therefore, the force required from each player is:
Fplayer = Fnet / 2 = 1250 N
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determine the intensity of electromagnetic waves from the sun just outside the atmospheres of the earth.
The intensity of the electromagnetic radiation from the Sun just outside the atmosphere of the Earth is 1.55 x 10-9 W/m2.
The intensity of electromagnetic waves from the sun just outside the atmosphere of the Earth can be calculated using the inverse-square law.
This law states that the intensity of the radiation decreases with the square of the distance from the source. Thus, the intensity of the radiation at the edge of the atmosphere will be lower than that at the surface of the Sun.
The intensity of the radiation, we need to know the distance from the Sun to the Earth. This distance is approximately 93 million miles (150 million kilometers).
The intensity of the radiation at the edge of the atmosphere by taking the inverse-square of this distance, which is approximately 1.55 x 10-9 W/m2.
This is the intensity of the electromagnetic radiation from the Sun just outside the atmosphere of the Earth.
The intensity of the electromagnetic radiation from the Sun just outside the atmosphere of the Earth is 1.55 x 10-9 W/m2.
This is due to the inverse-square law, which states that the intensity of radiation decreases with the square of the distance from the source.
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NEED HELP ASAP!!!!!!!!!!!!
Part B
Tape a meter stick to the side of the table. Make sure the zero end is on the floor. Carry out the experiment using the four drop heights you chose in task 1, part D. (You may want to have an adult drop the ball while you watch how high it bounces.) Perform three trials for each drop height, and record the data in the table. (You may choose to video the bounces and watch the video in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.
Drop Height
First Drop
Bounce Height
Second Drop
Bounce Height
Third Drop
Bounce Height
Average Bounce Height
according to our textbook, what is the best way to defend ourselves against an asteroid which is on course to collide with the earth in 7 years?
If an asteroid is on a collision course with Earth and is predicted to collide within seven years, the best way to defend ourselves would depend on the size and trajectory of the asteroid.
What is an asteroid ?An asteroid is a small, rocky object that orbits the Sun. Most asteroids are found in the asteroid belt, a region between the orbits of Mars and Jupiter. Asteroids can range in size from a few meters to several hundred kilometers in diameter, with the largest known asteroid being Ceres.
Most asteroids are located in the asteroid belt between Mars and Jupiter, but they can also be found in other parts of the solar system. Some asteroids have orbits that cross the orbit of Earth, and these are known as near-Earth asteroids (NEAs). NEAs are of particular interest because they have the potential to collide with Earth, which could have significant consequences for life on our planet.
Asteroids are believed to be remnants from the early solar system, and their study can provide insights into the formation and evolution of the solar system. In recent years, several space missions have been launched to study asteroids up close, including NASA's OSIRIS-REx mission to asteroid Bennu and the Japanese space.
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when you switch off the lights in your room at night, the walls, ceiling, and floor are at a temperature of about 300 k. why are you not dazzled by the radiation that they emit?
Answer:
Explanation:
Because by Wien's Law, they emit strongest in infrared and human eyes cannot see infrared radiation
a boat moves at 10.8 m/s relative to the water. if the boat is in a river where the current is 2.00 m/s, how long does it take the boat to make a complete round trip of 1 100 m upstream followed by a 1 100-m trip downstream?
Time taken for the boat to make a complete round trip of 1 100 m upstream followed by a 1 100-m trip downstream is 200 seconds.
The boat moves at 10.8 m/s relative to the water, and the current is 2.00 m/s. To make a complete round trip of 1 100 m upstream followed by a 1 100-m trip downstream, it would take:
When the boat is moving upstream, it is going against the direction of the current.
Upstream: 1 100 m/ (10.8 m/s - 2.00 m/s) = 102.78 s
When the boat is moving downstream, it is going in the same direction as the current,
Downstream: 1 100 m/ (10.8 m/s + 2.00 m/s) = 97.22 s
Total time taken in going upstream and downstream is the sum of the time calculated in both cases
102.78 s + 97.22 s = 200 s
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a track star runs a 400-m race on a 400-m circular track in 45 s. what is his angular velocity assuming a constant speed?
The angular velocity assuming a constant speed for a track-star who runs 400 m circular track in 45 s is 0.139 radians/s.
To calculate the angular velocity first the circumference of the track is 400 meters.
This means that the angular displacement of the track star during the race is:
θ = s / r
where θ is the angular displacement,
s is the distance traveled by the track star (which is equal to the circumference of the track), and
r is the radius of the circular track.
2.) Since the radius of the circular track is half of its diameter, we have:
r = 400 m / 2 = 200 m
Plugging this into the equation for angular displacement, we get:
θ = 400 m / 200 m = 2π radians
3.) Next, we can use the formula for angular velocity:
ω = θ / t
where ω is the angular velocity and
t is the time it takes for the track star to complete the race.
4.)Plugging in the values we have:
ω = θ / t
ω = 2π radians / 45 s
Therefore, the angular velocity of the track star is:
ω = 0.139 radians/s (rounded to three significant figures)
Therefore, the track star's angular velocity assuming a constant speed is approximately 0.139 radians/s
The angular displacement of the track star is equal to one complete revolution around the circular track, which is equal to 2π radians.
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(a) when a 9.00-v battery is connected to the plates of a capacitor, it stores a charge of 27.0 mc. what is the value of the capacitance? (b) if the same capacitor is connected to a 12.0-v battery, what charge is stored?
The formula for calculating capacitance is as follows:
C = Q/V
Where,
C = capacitance (Farads)
Q = charge (Coulombs)
V = voltage (Volts)
As given,
Q = 27.0 μC
V = 9.00 V
Substituting the given values in the above equation
C = 27.0 μC/9.00 V = 3.00 μF
Therefore, the value of capacitance is 3.00 μF.
The formula for calculating charge stored is as follows:
Q = CV
Where,
Q = charge (Coulombs)
C = capacitance (Farads)
V = voltage (Volts)
As given,
C = 3.00 μF
V = 12.0 V
Substituting the given values in the above equation,
Q = (3.00 × 10⁻⁶ F) × 12.0 V = 36.0 μC
Therefore, the charge stored is 36.0 μC.
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a bike and rider, 82.0 kg combined mass, are traveling at 4.2 m/s. a constant force of -140 n is applied by the brakes in stopping the bike. what braking distance is needed?
The bike and rider must halt at a breaking distance of 5.17 meters.
What is the formula for braking distance?d=2.2v+fracv220 gives the braking distance, in feet, of a car moving at v miles per hour. Most motorcycle riders have a maximum braking force (what an experienced rider can do) of about 1 G, which, at 45 mph, results in a complete stop of the motorcycle in 67 feet (20 meters).
To resolve this issue, we can apply the equation of motion for uniformly accelerated motion:
v² = u² + 2as
To solve for s, we can rewrite the equation as follows:
s = (v² - u²) / (2a)
We are aware that the acceleration is determined by dividing the net force by the mass:
a = F_net / m
where m is the mass and F net is the net force.
a = F_net / m = -140 N / 82.0 kg
= -1.71 m/s²
We may now change the values for s in the equation:
s = (0² - 4.2²) / (2*(-1.71))
= 5.17 m
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how does the plot differ from the plots for tube radius, viscosity, and tube length? how well did the results compare with your prediction
The plot differs for tube radius, viscosity, and tube length in terms of their effect on fluid flow. The effect of each parameter is analyzed and plotted against the velocity profile of the fluid flow.
For tube radius, as the radius increases, the fluid flow velocity increases as well. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the right as the radius increases.
For viscosity, the effect is the opposite. As viscosity increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a flatter curve, with a smaller peak as the viscosity increases.
For tube length, there is a similar effect as tube radius. As the length increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the left as the length increases.
In terms of the comparison with the prediction, the results were mostly in line with what was expected. The plots showed the expected trends for each parameter, and the quantitative analysis confirmed this as well. However, there were some discrepancies between the predicted and actual values, which could be due to experimental error or limitations in the model used.
Overall, the results provided valuable insights into the relationship between these parameters and fluid flow, and can be used to optimize fluid systems for various applications.
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a 6 kg block is pushed 8m up a rough 37 degree inclined plane by a horizontal force of 75 n. the initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 n opposes the motion. calculate:
The final kinetic energy of the block is 308.98 J.
Let's solve the problem using the work-energy theorem.
Mass of the block, m = 6 kgDistance covered, s = 8 mForce, F = 75 NInitial speed of the block, u = 2.2 m/sAngle of inclination, θ = 37°Coefficient of kinetic friction, μk = 0.28The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy
W = ΔKE
Initially, the block is at rest. Therefore, its initial kinetic energy is zero.
Ki = 0
We have to find the final kinetic energy of the block. Hence, Kf = ?
Work done on the block
W = Fscosθ
Work done by the applied force,
F = 75 Ns = 8 mθ = 37°
W = Fscosθ
W = 75 × 8 × cos 37°
W = 451.27 J
Work done by the frictional force
Ff = μkFn
The normal force
Fn = mg
Fn = 6 × 9.8
Fn = 58.8 N
Here,
Ff = μkFn
Ff = 0.28 × 58.8
Ff = 16.51 J
Work of friction:
W = Ff × s
W = 16.51 × 8
W = 132.1 J
The total work done on the block,
Wtotal = W + Wfriction
Wtotal = 451.27 + 132.1
Wtotal = 583.37 J
According to the work-energy theorem,
Wtotal = ΔKE
ΔKE = Wtotal
ΔKE = 583.37 J
Final kinetic energy of the block
Kf = KEFinal
Kf = ΔKE
Kf = 583.37 J
Kf = 308.98 J
Therefore, the final kinetic energy of the block is 308.98 J.
Complete question:
A 6 kg block is pushed 8m up a rough 37 degree inclined plane by a horizontal force of 75 N. The initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 N opposes the motion. Calculate the fianl kinetic energy of the block.
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select all that apply select all the stars that would have the same luminosity. (use the stefan-boltzmann law.) presented are the radii and temperatures of five stars compared to the sun.
According to the Stefan-Boltzmann law, the luminosity of a star is directly proportional to the fourth power of its temperature and its radius squared.
The formula for luminosity is:L = 4πR²σT⁴where L is the luminosity, R is the radius, T is the temperature, and σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴).To determine which stars would have the same luminosity as the sun, we need to compare their luminosity values using the given data. The radii and temperatures of five stars compared to the sun are as follows:Star A: R = 2R⊙, T = 6000 KStar B: R = R⊙, T = 3000 KStar C: R = 0.1R⊙, T = 6000 KStar D: R = 10R⊙, T = 3000 KStar E: R = 2R⊙, T = 15000 KSubstituting the values in the formula, we get:L⊙ = 4π(1²)(5.67 × 10⁻⁸)(5778⁴) ≈ 3.828 × 10²⁶ Wm¹²Star A: L = 4π(2²)(5.67 × 10⁻⁸)(6000⁴) ≈ 1.84 × 10³³ Wm¹²Star B: L = 4π(1²)(5.67 × 10⁻⁸)(3000⁴) ≈ 6.86 × 10²⁹ Wm¹²Star C: L = 4π(0.1²)(5.67 × 10⁻⁸)(6000⁴) ≈ 6.95 × 10²³ Wm¹²Star D: L = 4π(10²)(5.67 × 10⁻⁸)(3000⁴) ≈ 5.48 × 10³⁴ Wm¹²Star E: L = 4π(2²)(5.67 × 10⁻⁸)(15000⁴) ≈ 5.12 × 10³³ Wm¹²
The luminosity values of the stars are as follows:Star A: L ≈ 1.84 × 10³³ Wm¹²Star B: L ≈ 6.86 × 10²⁹ Wm¹²Star C: L ≈ 6.95 × 10²³ Wm¹²Star D: L ≈ 5.48 × 10³⁴ Wm¹²Star E: L ≈ 5.12 × 10³³ Wm¹²Comparing the luminosity values with that of the sun, we can see that stars A and E would have the same luminosity as the sun.
Therefore, the correct answer is: Stars A and E
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the generation of multiple forecasts of future conditions followed by an analysis of how to respond effectively to each of those conditions is
The process described in the question is known as scenario planning. It is a strategic planning method that involves generating multiple plausible scenarios of future conditions and analyzing the potential impact of each scenario on an organization or a system.
Scenario planning is a useful tool for decision-making, risk management, and identifying opportunities in an uncertain or rapidly changing environment.
By developing a range of scenarios, decision-makers can anticipate potential challenges and opportunities and develop strategies to respond effectively to each situation.
This approach allows organizations to be better prepared and more resilient in the face of future uncertainties. Scenario planning can be applied to various fields, including business, economics, environmental planning, and public policy.
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the intensity of sound in a typical classroom is approxiamtely 10^-7 w/m2. what is the sound level for this noise/
The sound level for this noise is approximately 50 decibels.
Sound level is a logarithmic measure of the ratio between the sound pressure level of a particular sound wave and a reference level. The reference level is typically set at the threshold of human hearing, which corresponds to an intensity of 10^-12 W/m^2. The sound level (measured in decibels, dB) of a sound wave is given by,
L = 10 log10(I/I0)
where I is the intensity of the sound wave and I0 is the reference intensity, which is typically set at 10^-12 W/m^2.
So, for an intensity of 10^-7 W/m^2 in a typical classroom, we can calculate the sound level as,
L = 10 log10(I/I0) = 10 log10(10^-7/10^-12) = 10 log10(10^5) = 50 dB
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the reason that the primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape is
The primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape because a parabolic shape allows for the mirror to collect the most amount of light and focus the parallel rays of light to a single point for better image clarity.
The reason that the primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape is to reduce spherical aberration.
What is an astronomical telescope?An astronomical telescope is an optical instrument that aids in the observation of remote objects by collecting electromagnetic radiation such as visible light. It consists of two primary components: a primary mirror or lens that gathers and focuses light, and an eyepiece or camera that magnifies and projects the image formed by the primary.
A parabolic shape is a mirror or lens that has a curve that is more curved in the center than at the edges, and it is often used in astronomical telescopes to reduce spherical aberration. Spherical aberration is an optical defect that causes the image of a point source to become fuzzy and blurred. It occurs when the rays passing through the edges of a spherical lens or mirror become focused at a different distance than those passing through the center. This causes the image to be blurred around the edges, which makes it difficult to view small or distant objects. Parabolic mirrors are used to correct this problem because they are designed to focus all incoming light to a single point, resulting in a sharper and clearer image.
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for an incandescent bulb, initial cost may be high but the energy costs will be low over its life time. (1 point) group of answer choices true false
True. An incandescent bulb may have a higher initial cost than other types of lightbulbs, but it uses less energy over its lifetime and thus reduces energy costs.
For an incandescent bulb, the given statement is true. In candescent bulbs are traditional bulbs, which use a filament to create light. These bulbs are less efficient, as they waste most of the electricity they use as heat rather than light. As a result, the bulbs are less cost-effective in the long run.
They use up more energy than modern alternatives such as CFLs (compact fluorescent lights) or LEDs (light-emitting diodes). Despite their low initial cost, incandescent bulbs are not recommended for long-term use. They consume more electricity and thus have a greater impact on the environment. Therefore, it is not true that the energy costs of an incandescent bulb will be low over its life time.
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josh punches his open left hand with his right hand. which statement is true about the forces his two hands exert on each other?
Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.
This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.
This is Newton's Third Law of Motion:
"For every action, there is an equal and opposite reaction."
The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.
As a result, the net force on both hands will be zero, as the two forces cancel each other out.
In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.
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use the impulse-momentum theorem to find how long a falling object takes to increase its speed from 4.23 m/s to 10.47 m/s?
The time it takes the object to fall through the change in speed using the impulse-momentum theorem is 0.62 seconds.
What is impilse-momentum theorem?
The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse exerted on it.
To calculate the time it takes the object to increase it speed using the impulse-momentum theorem, we use the formula below.
Formula:
Ft = m(v-u)Ft/m = (v-u)Recall that F/m = acceleration. Therefore,
at = v-ua = (v-u)/t.......................... Equation 1Where:
a = Acceleration due to gravityv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 10.47 m/su = 4.23 m/sg = 9.8 m/s²Substitute these values into equation 1 and solve for t
9.8 = (10.27-4.23)/tt = (10.27-4.23)/9.8t = 6.04/9.8t = 0.62 secondsHence, the time it takes the object to fall is 0.62 seconds.
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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s
Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
What is frequency ?
Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.
In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.
Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.
When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:
Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)
Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.
Substituting the values given in the formula, we get:
2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)
Simplifying this equation, we get:
686 - 2x = 343 + 2x
4x = 343
x = 85.75 km/hr
Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
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a bowling ball has a mass of 6 kg. if you slowly roll the ball off the edge of a table 1.5 m high table, what is the kinetic energy of the ball when it hits the ground?
The kinetic energy of the ball when hits the ground is 88.2 J
The formula for calculating kinetic energy is
KE = 1/2mv²
Where KE is kinetic energy, m is mass, and v is velocity.
We have, the mass of the bowling ball is 6 kg, and it is dropped from a height of 1.5 m, we can calculate its velocity just before it hits the ground as follows:
Potential energy = mgh
Where m = mass of the object = 6 kg
g = acceleration due to gravity (9.8 m/s²), and
h = height from which the object is dropped = 1.5 m
PE = mgh
= (6 kg)(9.8 m/s²)(1.5 m)
= 88.2 J
The potential energy of the bowling ball is 88.2 J.
This is equal to its kinetic energy just before it hits the ground.
Therefore, the kinetic energy of the ball is 88.2 J.
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gold has a specific gravity of almost 20. a 5-gallon bucket of water weighs 40 pounds. how much would a 5-gallon bucket of gold weigh? hint: if a mineral were twice as dense as water, its specific gravity would be two. water has a specific gravity of 1.
A 5-gallon bucket of gold would weigh 86.84 pounds.
A five-gallon bucket of water weighs 40 pounds. Gold has a specific gravity of almost 20.
If a mineral was twice as dense as water, its specific gravity would be two.
Water has a specific gravity of 1.
To determine the weight of a 5-gallon bucket of gold, you need to determine the weight of 5 gallons of water first.One gallon of water weighs approximately 8.33 pounds; hence 5 gallons of water weigh 41.65 pounds.
Now, divide the weight of 5 gallons of water (41.65) by the specific gravity of gold (20):41.65/20 = 2.0825
The weight of a five-gallon bucket of gold would be 2.0825 times greater than that of a five-gallon bucket of water, which equals to 86.84 pounds (40 pounds + 46.84 pounds).
Therefore, a 5-gallon bucket of gold would weigh approximately 86.84 pounds.
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an object floating in a container of water and partially submerged has the same density as the water. question 2 options: true false
The given statement "an object floating in a container of water and partially submerged has the same density as the water" is true.
When an object is placed in water, it sinks until the weight of the water displaced by the object equals the weight of the object.
If an object has the same density as water, it displaces an equal amount of water to its own weight. When it displaces the same amount of water that has an equivalent mass to the object, it will float partially submerged. If the object's density is greater than water, it will sink. If the object's density is less than that of water, it will float entirely above the water's surface.
Density is defined as the mass of an object per unit volume. The formula for density is mass/volume. Density is a crucial physical property that is used to define and classify materials. The density of an object is determined by its mass and volume. The unit of measurement for density is kg/m3 or g/cm3. The density of water is 1 g/cm3, which is why objects with a density of less than 1 g/cm3 float on water.
An object floating in a container of water and partially submerged has the same density as the water.
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suppose an asteroid had an orbit with a semimajor axis of 4 au. how long would it take for it to orbit once around the sun? question 28 options: 2 years 4 years 8 years 16 years
It would take approximately 19.2 years for the asteroid to orbit once around the sun. But that none of the answer choices match the calculated value of approximately 19.2 years.
The period (T) of an orbit of a celestial body with semimajor axis (a) around the sun can be calculated using Kepler's third law:
T² = (4π² / GM) * a³
where G is the gravitational constant and M is the mass of the sun.
Plugging in the given value for the semimajor axis (a = 4 AU), we get:
T² = (4π² / (6.674 × 10⁻¹¹ m³/(kg s²) * 1.989 × 10³⁰ kg)) * (4 AU)³
T² = 3.652 × 10¹⁶ s²
Taking the square root of both sides, we get:
T = 6.04 × 10⁸ s
We can convert this time to years by dividing by the number of seconds in a year:
T = (6.04 × 10⁸ s) / (31,536,000 s/year)
T ≈ 19.2 years
Therefore, it would take approximately 19.2 years for the asteroid to orbit once around the sun. The closest answer choice is 16 years.
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a square loop 5 cm on each side carries a 500 ma current. the loop is within a uniform magnetic field of 1.2t. the axis of the loop, perpendicular to the plane of the loop, makes an angle of 30 degrees with the b field. what is the magnitude of the torque on the current loop?
The magnitude of the torque on the current loop is calculated using the formula τ=BIA sinθ, where B is the magnitude of the magnetic field, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the loop's plane. In this case, the magnitude of the torque is τ = (1.2 T)(0.5 A)(5 cm x 5 cm)sin(30°) = 7.5 x 10-3 Nm.
The torque is the rotational force that causes the loop to rotate. This is due to the fact that a force is exerted on the loop by the magnetic field when there is a current running through it. This force generates a torque on the loop, which will cause it to rotate until the angle between the plane of the loop and the magnetic field is 0°.
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What is the concept of Schrodinger about nature of electron?
Answer: The behaviour of electrons inside atoms could be explained by treating them mathematically as waves of matter
Explanation:
Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves.
Answer:
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how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?
The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.
When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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blood flows with a speed of 30 cm/s along a horizontal tube with a cross-section diameter of 1.6 cm. what is the blood flow speed in the part of the same tube that has a diameter of 0.8 cm?
Blood flows with a speed of 30 cm/s along a horizontal tube with a cross-section diameter of 1.6 cm.The speed of blood flow in the part of the same tube that has a diameter of 0.8 cm is 15 cm/s.
To arrive at this answer, we can use the formula for the flow rate of a fluid in a pipe:
Q = A × V
where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the velocity of the fluid.
Therefore, if we substitute the values for A and V of the first section, we can calculate the flow rate for that section:
Q1 = A1 × V1
Q1 = π ×(1.6 cm/2)² × 30 cm/s
Q1 = 24.72 cm³/s
Now we can use the flow rate and the cross-sectional area of the second section to calculate the velocity of the fluid:
Q1 = A2 × V2
V2 = Q1 / A2
V2 = 24.72 cm³/s / (π × (0.8 cm/2)²)
V2 = 15 cm/s
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if a star is 11 pc away from us, will its apparent visual magnitude be higher or lower than its absolute visual magnitude? what if the star is 5 pc away?
If a star is 11 pc away from us, its apparent visual magnitude will be lower than its absolute visual magnitude. The star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude.
This is because the apparent magnitude of a star is affected by its distance from us. As the distance increases, the star appears dimmer, and its apparent magnitude decreases.
The distance modulus formula gives us a way to calculate the difference between the apparent and absolute magnitudes of a star:
Distance modulus = 5 * log(distance in parsecs) - 5
For a star that is 11 pc away, the distance modulus is,
Distance modulus = 5 * log(11) - 5 = 1.38
This means that the star's apparent magnitude will be 1.38 magnitudes lower than its absolute magnitude.
If the same star were only 5 pc away from us, the distance modulus would be,
Distance modulus = 5 * log(5) - 5 = 0.38
In this case, the star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude. This means that the star would appear brighter and have a higher apparent magnitude when it is closer to us.
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You're designing an external defibrillator that discharges a capacitor through the patient's body, providing a pulse that stops ventricular fibrillation. Specifications call for a capacitor storing 250 J of energy; when discharged through a body with R = 48 Ω transthoracic resistance, the capacitor voltage is to drop to half its initial value in 10 ms.
A) Determine the capacitance (to the nearest ) 10 μF).
B) Determine initial capacitor voltage (to the nearest 100 V) that meet these specs.
I need both correct answers to 2 significant figures.
a..... 1.04 x 10⁻⁴ Vi
b.... 9500 V
A) Determine the capacitance (to the nearest 10 μF).
First, we should identify the formula that we will use to solve the problem.
The formula that relates to capacitance is:
C = 2E / V². Where C is the capacitance in farads, E is the energy stored in joules, and V is the voltage across the capacitor in volts.
Converting the energy to joules, we have: E = 250J.
Now we know that the voltage needs to drop to half of its initial value in 10 ms. We can use the following formula to calculate the capacitance: C = R x t / ln(Vi / Vf) where R is the resistance in ohms, t is the time in seconds, Vi is the initial voltage, and Vf is the final voltage, which is half of the initial voltage.
B) Plugging in the given values, we get:
C = 48 x 0.01 / ln(Vi / (Vi / 2))Simplifying and solving for capacitance, we get:
C = 1.04 x 10⁻⁴ ViNow we can use the energy formula to solve for Vi:Vi = √(2E / C)
Plugging in the given values, we get:Vi = √(2 x 250 / 1.04 x 10⁻⁴)Simplifying and solving for Vi, we get:Vi = 9469 V
Therefore, the capacitance that meets these specifications is 100 μF and the initial capacitor voltage that meets these specifications is 9500 V, to the nearest 100 V.
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