vinegar is an aqueous solution of acetic acid, ch3cooh. suppose you titrate a 49.6 ml sample of vinegar with 34.80 ml of a standardized 0.4164 n solution of naoh. what is the normality of acetic acid in this vinegar?

Answers

Answer 1

The normality of acetic acid in the vinegar is 0.2919 N.

To determine the normality of acetic acid in the vinegar, you can follow these steps:

1. Write the balanced equation for the reaction:
  CH₃COOH (acetic acid) + NaOH → CH₃COONa + H₂O

2. Calculate the milliequivalents of NaOH used in the titration:
  Milliequivalents of NaOH = volume (mL) × normality
  Milliequivalents of NaOH = 34.80 mL × 0.4164 N
  Milliequivalents of NaOH = 14.49 meq (rounded to two decimal places)

3. Since the reaction is a 1:1 ratio, the milliequivalents of acetic acid will be equal to the milliequivalents of NaOH:
  Milliequivalents of acetic acid = 14.49 meq

4. Calculate the normality of acetic acid in the vinegar:
  Normality of acetic acid = milliequivalents of acetic acid/volume of vinegar (mL)
  Normality of acetic acid = 14.49 meq / 49.6 mL
  Normality of acetic acid = 0.2919 N (rounded to four decimal places)

So, the normality of acetic acid in the vinegar is 0.2919 N.

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Answer 2

Vinegar is an aqueous solution of acetic acid, ch3cooh. suppose you titrate a 49.6 ml sample of vinegar with 34.80 ml of a standardized 0.4164 n solution of NaOH. The normality of acetic acid in this vinegar is 0.292 N.

To find the normality of acetic acid in the vinegar, we can use the titration information provided. Here's a step-by-step explanation:
1. Write down the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH):
  CH3COOH + NaOH → CH3COONa + H2O
2. Calculate the number of equivalents of NaOH used in the titration:
  Number of equivalents of NaOH = Volume of NaOH solution × Normality of NaOH solution
  Number of equivalents of NaOH = 34.80 mL × 0.4164 N
  (Note: Convert mL to L by dividing by 1000)
  Number of equivalents of NaOH = 0.03480 L × 0.4164 N = 0.0145 equivalents
3. Since the balanced equation shows a 1:1 ratio between acetic acid and NaOH, the number of equivalents of acetic acid in the vinegar is equal to the number of equivalents of NaOH used in the titration.
4. Calculate the normality of acetic acid in the vinegar:
  Normality of acetic acid = Number of equivalents of acetic acid / Volume of vinegar sample
  Normality of acetic acid = 0.0145 equivalents / 0.0496 L = 0.292 N
So, the normality of acetic acid in the vinegar is 0.292 N.

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Related Questions

The atmospheric pressure on top of Mt. Everest (elevation 29,028) is 250. torr. Calculate the atmospheric pressure in mmHg and atm. Round each of your answers to 3 significant digits.

Answers

The atmospheric pressure on top of Mt. Everest is 250 mmHg and 0.328 atm, when rounded to 3 significant digits.

What is Pressure?

Pressure is a force that is exerted over a surface area. It is the amount of force applied to an object per unit area. Pressure is typically expressed in units of force per unit of area, such as pounds per square inch (psi) or pascals (Pa). Pressure is an important factor in many areas of engineering, physics, chemistry, and biology.

Atmospheric pressure can be measured in torr (1 Torr = 1mmHg), atm (1 atm = 760mmHg) or in kPa (1 atm = 101.3kPa).
250 torr = 250 mmHg
250 mmHg / 760 mmHg = 0.328 atm

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6Na + Fez0g -> 3NazO + 2Fe

If you are provided 200g of sodium and 250 grams of iron(Ill) oxide, how much of excess reagent is left?

Answers

The amount of excess reagent that will remain would be 11.76 g.

Stoichiometric problem

To determine the excess reagent in the reaction, we need to first determine which reactant is limiting and which reactant is in excess.

The balanced chemical equation for the reaction is:

6Na + Fe2O3 -> 3Na2O + 2Fe

The molar mass of Na is 23 g/mol, and the molar mass of Fe2O3 is 159.69 g/mol (2 x 55.85 g/mol for Fe + 3 x 16 g/mol for O).

Using the given masses, we can calculate the number of moles of each reactant:

Number of moles of Na = 200 g / 23 g/mol = 8.70 molNumber of moles of Fe2O3 = 250 g / 159.69 g/mol = 1.57 mol

According to the balanced chemical equation, 6 moles of Na react with 1 mole of Fe2O3. Therefore, the number of moles of Na required to react with 1.57 mol of Fe2O3 is:

(1.57 mol Fe2O3) x (6 mol Na/1 mol Fe2O3) = 9.42 mol Na

Since we only have 8.70 mol of Na available, it is the limiting reagent. This means that Fe2O3 is in excess.

To determine the amount of excess Fe2O3, we need to calculate how much Fe2O3 is required to react with 8.70 mol of Na:

(8.70 mol Na) x (1 mol Fe2O3/6 mol Na) x (159.69 g/mol Fe2O3) = 238.24 g Fe2O3

Since we only have 250 g of Fe2O3, the amount of excess Fe2O3 is:

250 g - 238.24 g = 11.76 g

Therefore, the amount of excess Fe2O3 left after the reaction is 11.76 g.

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Consider the energy diagram
Forward Reverse
Energy (kJ) −36
−7
48
Find ∆Eforward.
Answer in units of kJ/mol.
038 (part 2 of 4) 10.0 points
Find ∆Ereverse.
Answer in units of kJ/mol.
039 (part 3 of 4) 10.0 points
Find Ea.
Answer in units of kJ/mol.
040 (part 4 of 4) 10.0 points
Find E

a
.
Answer in units of kJ/mol.

Answers

E'a (also known as reverse activation energy) is the (Ea = +7 kJ/mol)  energy barrier for the reverse reaction, which is the energy difference between the products and the transition state in the reverse direction.

What is Energy?

Energy is a fundamental concept in physics and refers to the ability or capacity to do work or cause change. It is a scalar quantity, typically measured in joules (J) or other units such as kilocalories (kcal) or electron volts (eV).

In general, the activation energy (Ea) is the energy barrier that must be overcome for a chemical reaction to occur. It is the energy difference between the reactants and the transition state or activated complex of the reaction. The activation energy can be determined from the energy diagram by subtracting the energy of the reactants from the peak energy of the transition state.

∆Eforward = -36 kJ/mol

∆Ereverse = +48 kJ/mol

Ea = +7 kJ/mol

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the solvent choice in a nucleophilic substitution reaction would affect which of the following? (select all that apply.) multiple select question. product functional group stereochemical outcomes mechanism of substitution product structure rate of reaction

Answers

The solvent choice in a nucleophilic substitution reaction would affect stereochemical outcomes, the product structure ,the rate of reaction.

The Nucleophilic substitution reactions are the type of the reactions in which the electron rich nucleophile will attacks the positively charged electrophile and to replace the leaving group.

The more polar the solvents are helpful in the nucleophilic substitutions. In the nucleophile the  ionic compound itself, and the more polar solvent helps to dissolve. Therefore, the polar solvents may be provide the additional stability to the ions. The Polar solvents will either decrease the nucleophilicity and it will not affect it, but do not increase the nucleophilicity.

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in this experiment you will build molecules with model axnem. what does the a, x and e stand for? question 3 options: e a x 1. central atom 2. terminal atoms 3. lone pairs 4. double pairs 5. covalent pairs 6. ionic pairs

Answers

In the context of building molecules using model kits such as AXNEM, A, X, and E are abbreviations used to represent the different parts of a molecule.

1) A stands for "central atom," which is usually the atom that has the lowest electronegativity in the molecule and is located at the center of the molecular structure.

2) X stands for "terminal atoms," which are the atoms that are bonded to the central atom. They can be identical or different from one another.

3) E stands for "lone pairs," which are pairs of electrons that are not involved in any bonding and are located on the outer shell of the central atom.

By using these abbreviations, it becomes easier to represent the molecular structure and to understand how the atoms are arranged and bonded to each other.

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This is for chemistry for specific heat

if the mass of h2o is 102. 3g and the initial temp is 23. 1c and the final temp is 26. 0c what is the final initial temp?

Answers

If the mass of H₂o is 102. 3g and the initial temp is 23. 1c and the final temp is 26. 0c . The final initial temp is 296.67 K or 23.52 °C.

The amount of heat required to raise the temperature of a substance by 1°C is known as specific heat capacity of that substance.

Given that,

The mass of water (H₂O ), m = 102.3 g.

The initial temperature is given by T₁ = 23.1°C = 296.1 K

The finial temperature is T₂= 26°C =299 K

Therefore, change in temperature,ΔT = T₂- T₁= 299k - 296.1k=2.9

The final initial temperature is given as

= mΔT

=102.3 ×2.9

=296.67 K

=23.52 °C

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PLEASE HELPPPP
For each pair, predict which substance becomes more positively charged and which becomes more negatively charged when the two substances are rubbed together.
1. cotton, steel
2. cotton, silk
3. human hair, human hands (dry)
4. Teflon®,wood
5. glass, plastic wrap

Answers

1. Cotton is charged negatively while steel doesn't charge by rubbing. 2. cotton acquires negative while silk acquires positive charge. 3. human hair is negative charge while human hand is positively charged. 4. teflon gets negative charge while wood doesn't acquire charge. 5. glass acquires positive charge when rubbed with plastic wrap.

Triboelectric chargingThe transfer of electrons between two different materials occurs when they are rubbed together. The result is that the electron gainer becomes negatively charged and the electron loss becomes positively charged.Triboelectric effect, often referred to as triboelectric charging, is a form of contact electrification in which certain materials acquire an electrical charge after being cut off from another substance with which they had come into touch.According to a type of contact electrification known as the triboelectric effect, some materials acquire an electrical charge after being cut off from another substance with which they had come into touch.

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ammonia is a weak electrolyte. which of the following is true about the behavior of ammonia in water? question 11 options: ammonia is insoluble in water ammonia forms no ions when it dissolves in water ammonia ionizes completely in water ammonia ionizes only partially in water

Answers

Ammonia ionizes only partially in water. Option 4 is correct.

When ammonia dissolves in water, it reacts with water to form ammonium ions (NH₄⁺) and hydroxide ions (OH⁻), according to the equation: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. However, this reaction is reversible and only a small fraction of ammonia molecules ionize to form ions. As a result, ammonia is classified as a weak electrolyte, meaning that it only conducts electricity weakly in solution.

Weak electrolytes are characterized by their partial ionization in solution, and they have relatively low electrical conductivity compared to strong electrolytes, which ionize completely in solution. Hence Option 4 is correct.

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extend the left chain as far as the simulation allows. what is the base name for an ester with a propyl group attached to the carbonyl carbon atom?

Answers

The base name for an ester with a propyl group attached to the carbonyl carbon atom is "propyl ester." In the context of a simulation, you would need to extend the left chain according to the given parameters within the simulation for the specific compound you are working with.

If we extend the left chain of an ester with a propyl group attached to the carbonyl carbon atom as far as the simulation allows, we would have the following structure:

CH3-(CH2)2-C(=O)-OR

Where R represents the rest of the ester molecule.The base name for an ester with a propyl group attached to the carbonyl carbon atom is propyl propanoate. This name is derived from the parent carboxylic acid, which is propanoic acid (also known as propionic acid), and the alcohol used to form the ester, which is propanol (also known as 1-propanol or n-propanol).The esterification reaction between propanoic acid and propanol yields propyl propanoate as the ester product, with the elimination of a molecule of water. The ester is commonly used as a flavor and fragrance ingredient in various food and cosmetic products.

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consider a silicon crystal containing 10 12 phosphorous atoms per cubic centimeter. is the conductivity increasing or decreasing when the temperature is raised from 300 ? c to 350 ? c? explain by giving numerical values for the mechanisms involved.

Answers

The silicon crystal becomes an n-type semiconductor at normal temperature when the phosphorous atoms contribute an extra electron, producing an overabundance of negative charge carriers.

The conductivity of the crystal will rise as the temperature is raised from 300°C to 350°C. This is because a greater temperature results in a higher concentration of free charge carriers since there is more thermal energy available to promote electrons from the valence band to the conduction band.

We can use the following equation to calculate the conductivity change:

σ = nqμ

When the charge of an electron is q, the number of charge carriers is n, the conductivity is, and the mobility of the charge carriers. If the number of charge carriers increases by 10% as a result of the temperature increase.

As a result, we can see that raising the temperature from 300°C to 350°C causes the conductivity to increase by about 14%.

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if he gas has an average kinetic energy of 6430 j/mol under certain conditions, what is the root mean square speed of f2 gas molecules under the same conditions?

Answers

The root mean square speed of F2 Gas molecules under the same conditions is approximately 582.19 m/s

Given: Average kinetic energy (E_k) = 6430 J/mol
Molar mass of F2 = 2 * Molar mass of F = 2 * 19 g/mol = 38 g/mol (since F has a molar mass of 19 g/mol)

First, let's convert the molar mass of F2 from grams to kilograms:
Molar mass of F2 = 38 g/mol * (1 kg/1000 g) = 0.038 kg/mol

Now, we can use the equation for the average kinetic energy to determine the root mean square speed (v_rms):

E_k = (3/2) * R * T = (1/2) * m * v_[tex]rms^{2}[/tex]

Where R is the universal gas constant (8.314 J/mol K) and T is the temperature in Kelvin.

Since we want to find v_rms, we can rearrange the equation as follows:

v_[tex]rms^{2}[/tex] = (2 * E_k) / m

Plugging in the given values:

v_[tex]rms^{2}[/tex] = (2 * 6430 J/mol) / 0.038 kg/mol = 338947.37[tex]m^{2}/ s^{2}[/tex]

Finally, we take the square root to find the root mean square speed: a

v_rms = √338947.37[tex]rms^{2}[/tex] = 582.19 m/s

So, the root mean square speed of F2 gas molecules under the same conditions is approximately 582.19 m/s.

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Why is cerium sulfate (Ce2(SO4)3) the only compound that experiences a dip in solubility as temperature increases?

Answers

Answer: Because its dissolution is exothermic

Explanation:

if a glass manufacturer has only a few of reducing pollutants, it will .

Answers

If a glass manufacturer has only a few costly ways of reducing pollutants, it will end up paying the pollution tax, option A.

A chemical or energy that is introduced into the environment and has negative consequences or reduces the usability of a resource is referred to as a pollutant or new entity. These can be either anthropogenic in origin (i.e., produced materials or results of biodegradation) or naturally formed (i.e., minerals or extracted chemicals like oil). When pollutants are present in sufficient quantities to have noticeable detrimental effects on the environment or public health, pollution results.

By altering the development rate of plant or animal species, or by affecting human amenities, comfort, health, or property values, a pollution may inflict long- or short-term damage.

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Complete question:

If a glass manufacturer has only a few ________________ of reducing pollutants, it will ____________________ .

A. costly ways; end up paying the pollution tax.

B. inexpensive ways; incur the pollution tax instead.

C. costly ways; do so to minimize its pollution taxes.

D. inexpensive ways; buy the most expensive technology.

Which of the following is evidence for a chemical reaction?(a) Dropping sodium metal into water gives a yellow flame.(b) Dropping iron metal into acid produces gas bubbles.

Answers

Both options (a) and (b) are evidence for a chemical reaction.

In option (a), the yellow flame is an indication that a chemical reaction has occurred between the sodium metal and water, producing hydrogen gas and sodium hydroxide.

In option (b), the gas bubbles produced indicate that a chemical reaction has occurred between the iron metal and the acid, producing hydrogen gas and iron(II) ions. Based on the given options, evidence for a chemical reaction can be observed in both (a) and (b).

In (a), dropping sodium metal into water produces a yellow flame, indicating a chemical reaction as new substances are formed. In (b), dropping iron metal into acid produces gas bubbles, which also signifies a chemical reaction as a new product, in this case gas, is generated.

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given two orbitals as linear combinations of two atomic orbitals on carbon atom in ethene: where the hydrogen-like atomic orbitals are orthonormal. what is the value of the overlap integra

Answers

the overlap integral simplifies to:

S = c1c2 + d1d2d1d2.

To calculate the overlap integral between two linear combinations of atomic orbitals on a carbon atom in ethene, we first need to express the orbitals in terms of the hydrogen-like atomic orbitals. Let's assume that the two orbitals are denoted as ψ1 and ψ2, and can be expressed as linear combinations of the hydrogen-like atomic orbitals ϕ1 and ϕ2 as follows:

ψ1 = c1ϕ1 + d1ϕ2
ψ2 = c2ϕ1 + d2ϕ2

where c1, d1, c2, and d2 are constants.

The overlap integral between these two orbitals can be calculated using the following formula:

S = ∫ψ1ψ2*dτ

where dτ represents the infinitesimal volume element.

Substituting for ψ1 and ψ2, we get:

S = ∫(c1ϕ1 + d1ϕ2)(c2ϕ1 + d2ϕ2)*dτ

Expanding the product, we get:

S = c1c2∫ϕ1ϕ1*dτ + c1d2∫ϕ1ϕ2*dτ + d1c2∫ϕ2ϕ1*dτ + d1d2∫ϕ2ϕ2*dτ

Since the hydrogen-like atomic orbitals are orthonormal, the integral of ϕ1ϕ2 and ϕ2ϕ1 will be zero. Therefore, we can simplify the expression as follows:

S = c1c2∫ϕ1ϕ1*dτ + d1d2∫ϕ2ϕ2*dτ

Using the orthonormality of the hydrogen-like atomic orbitals, we know that the integral of ϕ1ϕ1 and ϕ2ϕ2 will both be equal to 1. Therefore, the overlap integral simplifies to:

S = c1c2 + d1d2d1d2.

In order to calculate the value of S, we need to know the values of the constants c1, d1, c2, and d2. These constants will depend on the specific linear combinations of atomic orbitals that we are considering. Without this information, we cannot calculate the value of the overlap integral.

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If two orbitals as linear combinations of two atomic orbitals on carbon atom in ethene, then value of the overlap integral [tex]S_{12} = \int{\phi_{1}}^{*}\phi_{2}d \tau[/tex], is equals to zero. So, option(b) is correct.

Orthonormal atomic orbitals are follow the following property:

[tex]\int{ m _i }* n_i d\tau = 1[/tex][tex]\int m_i^{*} n_j d\tau = 0[/tex]

Now, we have provide that two orbitals are as a linear combinations of two atomic orbitals on carbon atom in ethene. [tex]\phi_{1 } = \frac{1}{ \sqrt{2} } ( {\psi_{2s }} + {\psi_{2p }}_{2})[/tex]

[tex]\phi_{2 } = \frac{1}{ \sqrt{2} } ( \psi_{2 s} - {\psi_{2p} }_{2})[/tex]

In the ethylene molecule, consists each carbon atom is bonded to two hydrogen atoms. Therefore, for the C-H, σ bond (sp²(C) - 1s(H)) in ethylene, the two sp² hybrid orbitals overlap with the 1s orbitals of the two hydrogen atoms. Let the hydrogen-like atomic orbitals, [tex]\psi_{2 s} and {\psi_{2p} }_{2}[/tex] are orthonormal to each other. So, the overlap integral [tex]S_{12} = \int{ \phi_{1}}^{*}\phi_{2}d \tau[/tex]

[tex] = \int \frac{1}{\sqrt{2}}( \psi_{2s} + {\psi_{2p} }_{2}) \frac{1}{\sqrt{2}}( \psi_{2s} - {\psi_{2p} }_{2})d \tau\\ [/tex]

[tex] = \frac{1}{\sqrt{2}}( \int \psi_{2s}\psi_{2s} d \tau + \int {\psi_{2p} }_{2}\psi_{2s} d \tau - \int \psi_{2s} {\psi_{2p}}_{2} d \tau - \int {\psi_{2p} }_{2} {\psi_{2p} }_{2} d \tau) \\ [/tex].

Using above formula, [tex]\psi_{2 s} [/tex] and [tex]{\psi_{2p} }_{2}[/tex] are orthonormal so, [tex]\int \psi_{2 s} {\psi_{2p} }_{2} d\tau = 0[/tex]. Also [tex]\psi_{2 s} [/tex] and [tex]\psi_{2 s}[/tex] are normalised so [tex]\int \psi_{2 s} \psi_{2 s} d\tau = 1[/tex]. Similarly [tex]\int {\psi_{2p} }_{2} {\psi_{2p} }_{2} d\tau = 1 [/tex].

Substitute all integral values in equation (1),

= 1 + 0 - 0 - 1

= 0

Hence, the required integral value is 0.

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Complete question:

given two orbitals as linear combinations of two atomic orbitals on carbon atom in ethene:

[tex]\phi_{1 } = \frac{1}{ \sqrt{2} } ( {\psi_{2s }} + {\psi_{2p }}_{2})[/tex]

[tex]\phi_{2 } = \frac{1}{ \sqrt{2} } ( \psi_{2 s} - {\psi_{2p} }_{2})[/tex]

where the hydrogen-like atomic orbitals are orthonormal. what is the value of the overlap integral,

[tex] S_{12} = \int \phi_{1} \times \phi_{2}dr[/tex]

a) 1

b) 0

c) 1.5

d) 2

consider a solution formed by the dissolving of sodium acetate (nac2h3o2) in pure water. is the resulting solution acidic, basic or neutral? why?

Answers

Answer:

The resulting solution formed by dissolving sodium acetate in water is basic.

Explanation:

When sodium acetate (NaC2H3O2) dissolves in water, it dissociates into its constituent ions, sodium (Na+) and acetate (C2H3O2-). The sodium ion is a spectator ion and does not participate in any acid-base reactions. However, the acetate ion is the conjugate base of acetic acid, which is a weak acid.

In an aqueous solution, acetate ions can accept hydrogen ions (H+) from the water, leading to the formation of acetic acid and hydroxide ions (OH-). This process is called hydrolysis and results in the solution having a pH greater than 7, indicating it is basic.

So, the resulting solution formed by dissolving sodium acetate in water is basic.

Help what's the answer?

Answers

The partial pressure of helium in the flask is 1.12 atm and the total pressure in the flask is 1.99 atm.

What is the partial pressure of the gas?

To find the partial pressure of helium, we need to first find the moles of each gas present in the mixture.

Moles of methane:

n(CH4) = mass / molar mass = 2.68 g / 16.04 g/mol = 0.167 mol

Moles of helium:

n(He) = mass / molar mass = 0.864 g / 4.00 g/mol = 0.216 mol

Total moles of gas:

n(total) = n(CH4) + n(He) = 0.167 mol + 0.216 mol = 0.383 mol

To find the total pressure in the flask, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Rearranging this equation to solve for P:

P = nRT / V

where R = 0.0821 L·atm/mol·K is the gas constant.

Converting temperature to Kelvin:

T = 65°C + 273.15 = 338.15 K

Plugging in the values:

P = (0.383 mol) x (0.0821 L·atm/mol·K) x (338.15 K) / (5.93 L) = 1.99 atm

To find the partial pressure of helium, we can use the mole fraction of helium:

X(He) = n(He) / n(total) = 0.216 mol / 0.383 mol = 0.563

The partial pressure of helium is then:

P(He) = X(He) x P = 0.563 x 1.99 atm = 1.12 atm

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The cloud droplets in a cloud are formed by water vapor molecules and: A) protons. B) ions. C) molecules of air. D) condensation nuclei.

Answers

Answer:

condensation nuclei

Explanation:

Boyle's Law: If it takes 0.0500L of oxygen gas kept in a cylinder under pressure to fill an evacuated 4.00L reaction vessel in which the pressure is 0.980atm. What was the initial pressure of the gas in the cylinder?

Answers

We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant. This means that we can use the formula:

P1V1 = P2V2

where P1 and V1 are the pressure and volume at the initial state, and P2 and V2 are the pressure and volume at the final state.

We are given:

V1 = 0.0500 L
V2 = 4.00 L
P2 = 0.980 atm

We can solve for P1:

P1 = (P2V2) / V1

P1 = (0.980 atm x 4.00 L) / 0.0500 L

P1 = 78.4 atm (rounded to one decimal place)

Therefore, the initial pressure of the gas in the cylinder was about 78.4 atm.

a solution containing 20.0 g of an unknown non-electrolyte liquid and 110.0 g water has a freezing point of -1.32 °c. given kf = 1.86°c/m for water, the molar mass of the unknown liquid is ____g/mol.

Answers

The molar mass of the unknown non-electrolyte liquid is given as

256 g/mol, option A.

The ratio between the mass and the amount of substance (measured in moles) of any sample of a chemical compound is known as the molar mass (M) in chemistry. The molar mass of a material is a bulk attribute rather than a molecular one.

ΔTemp.f = i x Kf x b

where,

ΔTemp.f = the freezing-point depression;

i = the Van't Hoff factor

Kf = the cryoscopic constant of the solvent;

b = the molality of the solution.

Solving for the molality, b = ΔTemp.f/( i * Kf)

                   = 1.32/(1*1.86)

                   = 0.71 mol/kg

Converting from mol/kg to mol/g,

            0.71 mol/kg * 1kg/1000g

             = 0.00071 mol/g.

Mass of solvent = 110g

              Number of moles = mass * molality

              = 0.00071 * 110

              = 0.078 mol.

To calculate molar mass,

          Molar mass (g/mol) = mass/number of moles

          Mass of solute (liquid) = 20g

          Molar mass = 20/0.078

          = 256.2 g/mol. ≈ 256 g/mol

Therefore, molar mass of the unknown liquid is 256.2 g/mol.

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Complete question:

A solution containing 20.0 g of an unknown non-electrolyte liquid and 110.0 g water has a freezing point of -1.32 °c. given kf = 1.86°c/m for water, the molar mass of the unknown liquid is ____g/mol.

A)256B) 69.0 C) 619 D) 78.1

The molar mass of the unknown liquid is 256.5 g/mol.To solve this problem, we can use the formula for calculating the freezing point depression: ΔTf = Kf·m·i

where ΔTf is the change in freezing point (in °C), Kf is the freezing point depression constant (in °C/m), m is the molality of the solution (in mol/kg), and i is the van't Hoff factor (which is 1 for non-electrolytes).

First, we need to calculate the molality of the solution:

molality = moles of solute / mass of solvent (in kg)

We know that the mass of the solvent (water) is 110.0 g, which is 0.1100 kg. To find the moles of solute (the unknown liquid), we need to divide its mass (20.0 g) by its molar mass (which we don't know yet). Let's call the molar mass "M":

moles of solute = 20.0 g / M

So, the molality is:

molality = (20.0 g / M) / 0.1100 kg
molality = (20.0 / M) / 0.1100 mol/kg

Now, we can plug this into the formula for freezing point depression:

ΔTf = Kf·m·i
-1.32 = 1.86·[(20.0 / M) / 0.1100]·1

Simplifying this equation, we get:

-1.32 = 1.86·(181.8 / M)
-1.32 = 338.628 / M
M = 338.628 / 1.32
M = 256.5 g/mol

Therefore, the molar mass of the unknown liquid is 256.5 g/mol.

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When baking soda is heated it decomposes according to the following reaction:


2 NaHCO3(s) ⇌ Na2CO3(s) + H2O(g) + CO2(g)




If sufficient baking soda is placed in a container and heated to 90°C, the total pressure of the gases is 0. 5451 atm. What is the value of Kp at that temperature?

Answers

The value of Kp at 90°C is zero. This indicates that the decomposition of baking soda at this temperature is essentially complete, and the equilibrium lies far to the right.

We can use the expression for the equilibrium constant Kp, which is given by:

Kp = (P([tex]CO_{2}[/tex] ) × P([tex]H_{2} O[/tex])) / (P([tex]Na_{2} CO_{3}[/tex] ))

where P([tex]CO_{2}[/tex]), P([tex]H_{2} O[/tex]), and P([tex]Na_{2} CO_{3}[/tex]) are the partial pressures of carbon dioxide, water vapor, and sodium carbonate, respectively, at equilibrium.

From the balanced equation, we know that for every 2 moles of [tex]NaHCO_{3}[/tex]that decompose, 1 mole of [tex]CO_{2}[/tex] is produced. Therefore, the partial pressure of [tex]CO_{2}[/tex] can be calculated as:

P([tex]CO_{2}[/tex] ) = (1/2) × (total pressure) = 0.2726 atm

Similarly, for every 2 moles of [tex]NaHCO_{3}[/tex] that decompose, 1 mole of Na2CO3 is produced. Therefore, the partial pressure of [tex]Na_{2} CO_{3}[/tex]can be calculated as:

P([tex]Na_{2} CO_{3}[/tex]) = (1/2) × (total pressure) = 0.2726 atm

Finally, the partial pressure of water vapor can be calculated as the difference between the total pressure and the partial pressures of CO2 and [tex]Na_{2} CO_{3}[/tex]:

P([tex]H_{2} O[/tex]) = (total pressure) - P([tex]CO_{2}[/tex]) - P([tex]Na_{2} CO_{3}[/tex]) = 0.5451 - 0.2726 - 0.2726 = 0.0 atm

This means that there is no water vapor present at equilibrium, and we can assume that its partial pressure is zero. Substituting these values into the expression for Kp, we get:

Kp = (P([tex]CO_{2}[/tex]) × P([tex]H_{2} O[/tex])) / (P([tex]Na_{2} CO_{3}[/tex]))

= (0.2726 × 0.0) / 0.2726

= 0.0

Therefore, the value of Kp at 90°C is zero. This indicates that the decomposition of baking soda at this temperature is essentially complete, and the equilibrium lies far to the right.

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If 120 cm3 of oxygen gas is collected at 27 oC and 713.3 mm Hg pressure, what will the volume (in cm3) of the dry gas be at STP?

Answers

If 120 cm³ of oxygen gas is collected at 713.3 mm Hg pressure, the volume of the dry gas at STP is 0.102 cm³.

How do you calculate  the volume of the dry gas to be at STP?

To solve this problem, we will use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

First, we need to convert the given conditions to the correct units. The temperature is already in Celsius, so we need to convert it to kelvins by adding 273.15:

T = 27 + 273.15 = 300.15 K

The pressure is given in millimeters of mercury (mm Hg), so we need to convert it to atmospheres (atm) to use in the ideal gas law. There are 760 mm Hg in 1 atm, so:

P = 713.3 mm Hg / 760 mm Hg/atm = 0.938 atm

Next, we can use the ideal gas law to find the number of moles of oxygen gas:

n = PV/RT = (0.938 atm)(120 cm³)/(0.08206 L·atm/(mol·K))(300.15 K) = 0.00454 mol

Finally, we can use the molar volume of a gas at STP (standard temperature and pressure) to find the volume of the dry gas at STP. At STP, the temperature is 273.15 K and the pressure is 1 atm. The molar volume of a gas at STP is 22.4 L/mol, so:

V = n(22.4 L/mol) = (0.00454 mol)(22.4 L/mol) = 0.102 cm³

Therefore, the volume of the dry gas at STP is 0.102 cm³.

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What is the concentration (in molality) of an aqueous solution of NaCl made by adding
4.56 g of NaCl to enough water to give 20.0 mL of solution. Assume the density of the
solution is 1.03 g/mL

Answers

Answer:

data given

mass of NaCl 4.56

dissolved volume 20ml(0.02l)

density of solution 1.03g/ml

Required molality

Explanation:

molarity=m/mr×v

where

m is mass

mr molar mass

v is volume

now,

molarity=4.56/58.5×0.02

molarity =3.9

: .molarity is 3.9mol/dm^3

According to molal concentration, the concentration (in molality) of an aqueous solution of NaCl is 0.0047 mole/kg.

What is molal concentration?

Molal concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molal concentration is moles/kg.

The molal concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molal concentration is calculated by the formula, molal concentration=mass/ molar mass ×1/mass of solvent in kg.

In terms of moles, it's formula is given as molal concentration= number of moles /mass of solvent in kg.

Substitution in formula gives the answer but first mass of solution is determined which  is density×volume= 1.03×20=20.6 g , mass of solvent= 20.6-4.56=16.05, thus molal concentration=4.56/58.5×1/16.05=0.0047 moles/kg.

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what characteristic of carbohydrates is not commonly found in the previously studied classes of compounds?

Answers

Answer:

Their ability to act as a source of energy.

Explanation:

One characteristic of carbohydrates that are not commonly found in previously studied classes of compounds is their ability to act as a source of energy. Carbohydrates are considered the primary source of energy for living organisms and are broken down through cellular respiration to release energy for use in metabolic processes. In contrast, lipids, proteins, and nucleic acids have other primary functions in living organisms such as membrane structure, enzyme activity, and genetic information storage and expression.

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Name an ester that can be synthesized from propanol and methanoic acid?

Answers

Answer:

Propyl methanoate

Explanation:

The ester that can be synthesized from propanol and methanoic acid is propyl methanoate (also known as methyl propanoate or propyl formate). The reaction between propanol and methanoic acid, which is a carboxylic acid, is a classic example of an esterification reaction, which results in the formation of an ester and water.

consider the pictured structure of a dipeptide. dipeptide structure with labels a through d. the a label is at the end of the molecule with the positively charged nh3 group. the b label is placed by the bond between the carbonyl group and the amine. the c label is next to a carbon with shown single bonds to the carboxylate, a ch2oh, and the rest of the molecule. the d label is next to the carboxylate at the end of the molecule. what does each label on the structure represent?

Answers

The dipeptide structure with labels a through d represents the different functional groups and atoms present in the molecule.

Label a is located at the end of the molecule with the positively charged NH3 group, indicating the presence of an amino group. The b label is placed by the bond between the carbonyl group and the amine, indicating the presence of a peptide bond.

Label c is next to a carbon with shown single bonds to the carboxylate, a CH2OH, and the rest of the molecule, indicating the presence of a side chain. Finally, the d label is next to the carboxylate at the end of the molecule,

indicating the presence of a carboxylic acid functional group. Understanding the different functional groups and atoms present in the dipeptide structure is important in understanding its properties and behavior in chemical reactions and biological processes.

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the decrease in the second ionization energy of alkali metals going down the group, as shown in the table above, can be best attributed to a decrease in the coulombic force of attraction due to

Answers

The decrease in the second ionization energy of alkali metals going down the group is due to the increase in atomic radius.

As the atomic radius increases, the distance between the nucleus and the outermost electron increases, which reduces the coulombic force of attraction between the nucleus and the electron.

This reduced coulombic force of attraction reduces the energy required to remove the electron, thus resulting in a decrease in the ionization energy. Additionally, due to the increased number of electrons, the effective nuclear charge decreases, which further reduces the force of attraction between the nucleus and the electron, thus resulting in a further decrease in the ionization energy.

Therefore, the decrease in the second ionization energy of alkali metals going down the group can be attributed to a decrease in the coulombic force of attraction due to the increase in atomic radius and the decrease in the effective nuclear charge.

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the density of pure propionic acid is 0.9930 g.cm-3 and its molecular mass is 74.08g.mol-1. a. calculate the mass of propionic acid required to make 250ml of 0.50m propionic acid solution

Answers

The density of pure propionic acid is 0.9930 g.cm-3 and its molecular mass is 74.08g.mol-1.  

a. The mass of propionic acid required to make 250ml of 0.50m propionic acid solution is 9.26 grams.

To calculate the mass of propionic acid required to make 250ml of 0.50m propionic acid solution, we need to use the formula:
m = n x M
where:
m = mass of propionic acid required (in grams)
n = number of moles of propionic acid (in moles)
M = molecular mass of propionic acid (in grams per mole)
First, we need to calculate the number of moles of propionic acid required for a 250ml solution of 0.50m concentration:
Molarity = moles of solute/litres of solution
0.50m = n / 0.250 L
n = 0.50m x 0.250 L
n = 0.125 moles
Now we can substitute the values in the formula:
m = n x M
m = 0.125 moles x 74.08 g/mol
m = 9.26 g
Therefore, the mass of propionic acid required to make 250ml of 0.50m propionic acid solution is 9.26 grams.

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what causes the release of energy from a chemical bond? group of answer choices atoms having an uneven number of electrons in their outer shell the sharing of electrons between atoms the breaking of the bond the damage from free radicals

Answers

Option b. The breaking of the chemical bond causes the release of energy from a chemical bond.

The arrival of energy from a substance bond happens when the bond is broken, either through synthetic responses or actual cycles. Compound bonds result from the sharing or move of electrons among particles, and the energy expected to frame a bond is put away inside the actual bond. At the point when the bond is broken, this put away energy is delivered as dynamic energy, intensity, or light. How much energy delivered relies upon the strength of the bond and the particular synthetic responses included. In this way, the breaking of the bond is the reason for energy discharge, while different choices - iotas having a lopsided number of electrons, harm from free revolutionaries, and the sharing of electrons between molecules - don't straightforwardly connect with the arrival of energy from a bond.

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in an alternative version of this experiment, the h2o ligands are instead replaced with co ligands (not nh3). based on your knowledge of the spectrochemical series what would you expect to happen to the ligand field splitting?

Answers

Answer:
The splitting is going to be larger for CO.

Explanation:

"The ligand field splitting in a coordination complex is determined by the strength of the interaction between the metal center and the ligands, which is affected by various factors, including the ligands' identity. CO ligands are stronger field ligands than H2O ligands, meaning that they interact more strongly with the metal center and cause a larger ligand field splitting. Therefore, if H2O ligands are replaced with CO ligands in this experiment, we would expect the ligand field splitting to be larger for CO."

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