Answer:
[tex]\rho =1.96\frac{g}{L}[/tex]
Explanation:
Hello there!
In this case, since this imaginary gas can be modelled as an ideal gas, we can write:
[tex]PV=nRT[/tex]
Which can be written in terms of density and molar mass as shown below:
[tex]\frac{P}{RT} =\frac{n}{V} \\\\\frac{P}{RT} =\frac{m}{MM*V}\\\\\frac{P*MM}{RT} =\frac{m}{V}=\rho[/tex]
Thus, by computing the pressure in atmospheres, the resulting density would be:
[tex]\rho = \frac{165/760 atm * 314.2 g/mol}{0.08206\frac{atm*L}{mol*K}*425K} \\\\\rho =1.96\frac{g}{L}[/tex]
Best regards!
What force is required to accelerate a car at a rate of 4 m/s2 if the car has a mass of 37.5 kg?
Answer:150
Explanation:I think because f=MxA and the mass is 37.5 kg while acceleation is 4 m/s^2 and when you multiply that is gets 150 so F=150 N
what is acid by Lewis in science
A Lewis acid is a substance that accepts a pair of electrons to form a covalent bond. A Lewis base is a substance that donates a pair of electrons to form a covalent bond. So, a Lewis acid-base reaction is represented by the transfer of a pair of electrons from a base to an acid.
b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol
Answer:
Explanation:
You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.
This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.
Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH3COONa, in 50.0 mL of 0.10 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 x 10^-5.
Answer:
pH = 5.35
Explanation:
Given 1.60 grams sodium acetate (NaOAc(aq))*** added to 50ml of 0.10M acetic acid (HOAc(aq)) solution.
Applying common ion effect keeping in mind that the addition of NaOAc provides the common-ion (OAc⁻).
HOAc(aq) ⇄ H⁺(aq) + OAc⁻(aq)
I 0.10m 1.32 x 10⁻³M ≈ ∅M* (1.6g/82.03g/mol) / 0.050L = 0.39M
C -x +x 0.39M + x ≈ 0.39M**
E 0.10M - x x 0.39M
≈ 0.10M
Ka = [H⁺][OAC⁻]/[HOAC] => [H⁺] = Ka·[HOAc] / [OAc⁻]
[H⁺] = (1.75 X 10⁻⁵)(0.10) / (0.39) = 4.5 x 10⁻⁶M
∴ pH = -log[H⁺] = -log(4.5 x 10⁻⁶) = -(-5.35) = 5.35
_______________________________________________
* [H⁺] before adding NaOAc = SqrRt(Ka · [HOAc]) = SqrRt(1.75 x 10⁻⁵· 0.10) = 1.32 x 10⁻³M. Since this concentration value is so small, the initial [H⁺] is assumed to be zero molar (∅M).
** The added [H⁺] is negligible and dropped in the ICE table. That is, adding ~[H⁺] in the order of 10⁻³M does not change the H⁺ ion concentration sufficiently to affect problem outcome and is therefore dropped in the ICE table.
*** Acetic Acid and Sodium Acetate are frequently written HOAc and NaOAc where the OAc⁻ anion is the acetate ion (CH₃COO⁻) for brevity.
The pH of the solution measures the acid of the liquid throughout the molar concentration of hydrogen ions in a solution.
[tex]\bold{CH_3COONa \ mass = 1.60\ g}\\\\[/tex]
Solution Volume (V) [tex]=50.0\ mL =0.05\ L\\\\[/tex]
[tex]\bold{CH3COONa \ molarity =0.10\ M }[/tex]
[tex]\bold{\text{Calculating the CH3COONa moles} =\frac{mass}{molar\ mass}}[/tex]
[tex]= \frac{1.60\ g}{82.03\frac{g}{mol}} \\\\=0.0195\ mol\\\\[/tex]
[tex]\bold{M = \frac{ \text{amount of solute moles} } { \text{solution volume in L} }}[/tex]
[tex]= \frac{0.0195\ mol}{0.05\ L}\\\\ =0.39\ M[/tex]
Using Henderson Hasselbach equation:
[tex]\bold{pH = -\log K_{a} + \log{[salt]}{[acid]}}\\\\[/tex]
[tex]=\bold{ -\log (1.75\times 10^{-5}) + \log ( \frac{0.39}{0.10}) }\\\\=\bold{ 4.757 + \log (3.9)}\\\\=\bold{ 4.757 + 0.5910}\\\\=\bold{ 5.348}\\\\=\bold{ 5.35}\\[/tex]
So, the final answer is "5.35".
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In a titration of nitrous acid with NaOH, the pH of the solution is 3.14 when the moles of HNO2 and the moles of NO2-- are equal. What is the Ka of nitrous acid?
Answer:
[tex]Ka=3.98x10^{-4}[/tex]
Explanation:
Hello there!
In this case, since the modelling of titration problems can be approached via the Henderson-Hasselbach equation to set up a relationship between pH, pKa and the concentration of the acid and its conjugate base, we can write:
[tex]pH=pKa+log(\frac{[NO_2^-]}{[HNO_2]} )[/tex]
Whereas the pH is given as 3.14 and the concentrations are the same, that is why the pH would be equal to the pKa as the logarithm gets 0 (log(1)=0); thus, we can calculate the Ka via:
[tex]Ka=10^{-pKa}=10^{-3.14}\\\\Ka=3.98x10^{-4}[/tex]
Best regards!
Identify the reactants and products in the following chemical equation: Zn +2HCl --> ZnCl2 + H2 *
20 points
A: Reactants: Zn & HCl Products: ZnCl2 & H2
B: Reactants: ZnCl2 & H2 Products: Zn & HCl
C: Reactants: Zn & H2 Products: ZnCl2 & HCl
Answer:
A.
Explanation:
zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.
hope it helps. :)
What is the density at STP of the gas sulfur hexafluoride, SF6?
O 3.93 x 1024 g/L
O 0.153 g/L
O 6.52 g/L
O 3270 g/L
Answer:
Explanation:
There is a formula for this:
M = DRT/P where M = molar mass. This just derived from PV = nRT where you say n = grams/molar mass. However, just with this formula, we can get D which is density at STP (1 atm and 273K). We find that D = 6.52g/L.
If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?
Answer: 31.9 g of KOH can be produced from 22.2 g of KOH
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]
[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]
According to stoichiometry :
2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]
Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex] of [tex]KOH[/tex]
Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]
Thus 31.9 g of KOH can be produced from 22.2 g of KOH
how can two rocks made by the same process be so different in color
Answer: Although the rocks of the produced by similar processes but their chemical composition may vary dependent upon the type of mineral present in these rocks so the color of the rock also varies depending upon the mineral composition.
Explanation:
The rocks are made by basic steps like disintegration of parent rock material, erosion, crystallization, metamorphism, and sedimentation. These basic steps are common in same kind of rocks but their color may vary because of the mineral composition in them for example, Rhyolite is of light colored because of the presence of quartz mineral present in it.
Two gases helium and x are released from one end of an evacuated long cylinder at the same time if it takes helium atoms 3 times faster than gas X to effuse from one end. What is gas X?
Answer:
Hypoflorous acid, HOF
Explanation:
From the question, we're told that the helium atoms effuses 3 times than the said gas X.
We can determine the rate of effusion by using the formula
r is inversely proportional to 1/√M, where M is the molecular mass of the gas.
And also,
r is inversely proportional to 1/t, where t is the time taken for effusion.
From both formulas I listed, we can conclude that t is directly proportional to √M. And thus we proceed.
The molecular mass of Helium is 4.
tHe = tX/3, where tx is the time taken for the unknown gas X
As of yet, we don't know the molecular mass of X. Next, we say that
tX/tHe =√Mx/MHe
3 = √Mx/4
If we square both the sides, to remove the square root, we have
9 = Mx/4
Mx = 36
The molecular mass of the unknown gas X is 36.
You want to produce a casting of sterling silver that is silver plus 13 atomic% copper. Pure silver is too soft for many applications and adding 13 atomic% copper strengthens the silver without significantly changing the color. To produce the sterling silver casting, you are going to melt commercially available pure silver and copper in a furnace, and then you will pour the liquid metal mixture into a mold. The following questions relate to this alloy. (a) In selecting a furnace, what must be the minimum value of the high-temperature capability of your selected furnace
Answer:
1085° C
Explanation:
From the phase diagram of Ag-Cu shown below:
The minimum value of the high-temp required to be selected for the furnace is: 1085° C
This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.
How many grams are in 2.4 moles of sulfur?
Answer:
76.96
Explanation:
A mole is Avagadro’s number of atoms of a substance. My periodic table of the elements gives the Gram Atomic Mass of natural sulphur is 32.066 grams/mole. Therefore, 2.4 moles would have a mass of 76.96 grams.
Our most recent mass extension happened about 65million years ago. Describe the effects of this event.
Answer:
To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.
ection
9)
A compound consists of 25.9% nitrogen and 74.1% oxygen by mass. What is the empirical
formula of the compound?
A)
NOZ
B)
NO
C)
N₂Os
D)
0
1
N20
2
3
4
5
6
7
8
9
0
21
2
Answer:
69
Explanation:
2. A plant growing in response to the sunlight.
Gravitropism
Phototropism
Thigmotropism
Hydrotropism
Answer:
Phototropism.
Explanation:
Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.
The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.
Thus, the correct answer is phototropism.
11 D. Organism 4 When Charles Darwin observed finches on the Galapagos Islands, he noted differences in the shapes of birds' beaks. redeater bexl, Leal, and fruit estet Ceci este Soalanxei celer A 0 If there is a two-year drought that kills off many seed and fruit plants, which finch species have traits that could make them more successful? A. A and B B. A and C C. B and C D. C and D
Ammonia is produced by the chemical reaction of hydrogen and nitrogen
N2 + 2H2 → 2NH3
How many moles of H2 are needed to react with 1.8 moles of N2
Answer:
3.6 mol H₂
Explanation:
N₂ + 2H₂ → 2NH₃In order to convert from N₂ moles to H₂ moles we need to use a conversion factor. This conversion factor has to have N₂ moles in the denominator and H₂ moles in the numerator, using the stoichiometric coefficients of the reaction, as follows:
1.8 mol N₂ * [tex]\frac{2molH_2}{1molN_2}[/tex] = 3.6 mol H₂if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point
Answer:
14.91 mL
Explanation:
Assuming the weak acid is monoprotic, we can solve this problem using the equation:
C₁V₁=C₂V₂Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.
We input the data:
25.00 mL * 0.1084 M = 0.1817 M * V₂And solve for V₂:
V₂ = 14.91 mLThe volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.
How we calculate the volume?Volume for the given solution will be calculated from the below equation:
M₁V₁ = M₂V₂, where
M₁ = Molarity of weak acid = 0.1084 M
V₁ = volume of weak acid = 25 mL
M₂ = molarity of NaOH = 0.1817 M
V₂ = volume of NaOH = to find?
On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL
Hence required volume is 14.91 mL.
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How many moles are in 4.28 x 1023 atoms of carbon?
0.711 moles C
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 4.28 × 10²³ atoms C
[Solve] moles C
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 4.28 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})[/tex][DA] Divide [Cancel out units]: [tex]\displaystyle 0.710727 \ moles \ C[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.710727 moles C ≈ 0.711 moles C
What is total distance traveled?
What is the displacement (change in positions)
Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
Given the balanced equation:
2H2 + 02 --> 2H20
How many grams of H20 is produced if you have 7g of O2
Answer: 7.88375g
Explanation:
Here is the dimensional analysis table
7g O2 | 1 mol O2 | 2 mol H2O | 18.02 g H2O
| 32 g O2 | 1 mol O2 | 1 mol H2O
You use grams to convert to moles of O2, then use that to find grams of H20
The body system responsible for breaking down food and absorbing nutrients is the ____
a
circulatory system
b
respiratory system
c
excretory system
d
digestive system
Answer:
d
digestive system
Explanation
What is the IUPAC name for the compound shown?
bromine pentachloride formula
Answer:
Bromine pentafluoride, BrF5
bromine pentafluoride is an interhalogen compound and a fluoride of bromine. It is a strong fluorination reagent. BrF5 finds use in oxygen isotope analysis.
The chemical formula of a compound is obtained from the symbols of the elements that compose the compound. The formula of bromine pentachloride is BrCl5.
In chemistry, compounds are represented using shorthand symbols called chemical formula.
The chemical formula is composed of the symbols of the respective elements that compose the compound as well as the number of atoms of each element that compose the compound.
For the compound bromine pentachloride, there is one bromine atom and five chlorine atoms giving the formula BrCl5.
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What is the main difference between rain and hail?
Answer:
Rain is a liquid and hail is a solid.
A ___________ ion is made of 2 or more atoms of different elements
O nuclear
O polyatomic
O magnetic
O mono-atomic
Answer: polyatomic
Explanation:hope you find helpful
When 4.088 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.82 grams of CO2 and 2.829 grams of H2O were produced.
In a separate experiment, the molecular weight of the compound was found to be 78.11 amu. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer:
Empirical formula: CH
Molecular formula: C₆H₆
Explanation:
Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.
The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:
Moles C -Molar mass CO₂ = 44.01g/mol-:
13.82g * (1mol / 44.01g) = 0.314 moles C
Moles H -Molar mass H₂O = 18.01g/mol-:
2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H
The ratio of moles H: moles C:
0.314 moles / 0.314 moles = 1
That means empirical formula is:
CHWith the molecular weight and empirical formula we can find the molecular formula:
Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol
As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:
78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula
That means molecular formula is:
C₆H₆What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?
Answer:
Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.
Explanation:
Is anyone good at chemistry if so can someone help me please ?
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In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.
Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.
Statements C, E, and F, as a whole, generally aren't true of such salts.
How many grams of iron contain 4.06X10^24 atoms of iron?
We have that the grams of iron contained 4.06X10^24 atoms of iron is
g= 376.6g
From the question we are told
How many grams of iron contain 4.06X10^24 atoms of iron?
Generally the equation for the Moles of Iron is mathematically given as
[tex]M=\frac{4.06x10^24}{6.02x10^23} \\\\M=6.744moles[/tex]
Therefore
Where Molar mass of Iron =55.845
Generally the equation for the mass is mathematically given as
g= 6.744 x 55.85
g= 376.6g
Therefore
the grams of iron contained 4.06X10^24 atoms of iron is
g= 376.6g
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