Water from a river or reservoir enters a hydroelectric power plant through a.....????

The complete options are;

A. The average kinetic energy of their particles is the same.

B. The total kinetic energy of their particles is equal.

C. Heat flows from the larger object to the smaller object.

D. Heat flows from the object with higher potential energy to the object with lower potential energy.

Answer:

Explanation:

From the relationship between average kinetic energy and temperature, we have the formula;

E_k = (3/2)kT

Where;

k is a constant known as boltzmann constant.

T is known as temperature

We can see that at the same temperature (T), kinetic energy will remain the same because from the formula, E_k depends km only the temperature.

Thus, average kinetic energy of their particles saying that.

Complete question:

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?

Answer:

The specific gravity of the oil is 0.8.

Explanation:

Given;

density of the oil, [tex]\rho_o[/tex] = 800 kg/m³

density of water, [tex]\rho_w[/tex] = 1000 kg/m³

The specific gravity of any substance is the ratio of the substance density to the density of water.

Specific gravity of the oil = density of the oil / density of water

Specific gravity of the oil = 800/1000

Specific gravity of the oil = 0.8

Therefore, the specific gravity of the oil is 0.8.

Answer: I like your profile picture

Explanation:

Answer:

A)        d = 6.1857 10⁻⁵ m

Explanation:

In the double-slit experiment the constructive interference is given by the expression

          d sin θ = m λ

          d =[tex]\frac{m \lambda }{sin \theta}[/tex]

let's use the relationship between speed, wavelength and frequency

          c = λ f

          λ = c / f

          λ = 3 10⁸ / 5.60 10¹²

          λ = 5.357 10⁻⁵ m

I do not know India in order of interference, we will assume that  m= 1

          d = 1  5,357 10⁻⁵ / sin 60

          d = 6.1857 10⁻⁵ m

Explanation:

[tex]let \: coefficient \: of \: friction \: be \: \gamma \\ from \: third \: law \: of \: solid \: friction \\friction \: force = \gamma \times normal \: reaction \\ F = \gamma R \\ but \: R = mg = 240N \\ \gamma = \frac{ F}{R} \\ \gamma = \frac{12}{240} \\ \gamma = \frac{1}{20} [/tex]

Answer:

Displacement and Velocity

Answer:

Who is liang

Explanation:

i need more info if i'm going to help you out

He is most likely trying to figure out how to upload the picture to Brainly.

He knows that his question cannot be answered as long as nobody can see the picture.

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μ[tex]_B[/tex]B × cos0°

= -μ[tex]_B[/tex]B × 1

= -μ[tex]_B[/tex]B

Final potential energy = -μ[tex]_B[/tex]B × cos180°

= -μ[tex]_B[/tex]B × -1

= μ[tex]_B[/tex]B

so change in energy will be;

ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )

ΔE = 2μ[tex]_B[/tex]B

now, difference in energy levels will be;

ΔE = hc/λ

2μ[tex]_B[/tex]B = hc/λ

2μ[tex]_B[/tex]Bλ = hc

B = hc /  2μ[tex]_B[/tex]λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

we know that,

Frequency = 1/ time period

hence, Feq = 1/5 ===> 0.2 Hz

hence, wave velocity = freq * wavelength

hence,

V = 0.2 * 100

==> Wave velocity = 20 m/s

Answer:

d.) form supernovas

Explanation:

Learned this in physical school last year

Answer:

B. As gravity increases weight increases and as gravity decreases weight decreases

Explanation:

Option B is the correct answer.

From the information given, we can deduce that as the gravity increases, the weight also increases and as the gravity decreases, the weight decreases as well.

This is true from the  given table. On earth, the gravity of the man was 9.8m/s² and his weight 588N. But get to space, moon precisely, the gravity reduced to 1.62m/s². Then we discover that such decrease in his gravity also led to the sharp decrease in the weight. The weight decreased from 588N on earth to 96N on the moon.

This actually reveals that weight and gravity are related in a way. Weight of an object is known to be the force of gravity on the object. The weight actually vary as a result of varying gravity.

Answer: b

since the pull of gravity on the moon is less we weigh less.

Answer:

The answer is C, I just guessed and got it right lol

Explanation:

Answer:

I would say color.

Explanation:

Because for me most of the time the warm color mean It hot. and the cool color most likily to mean cold  

Answer:

Color

Explanation:

The temperature of a star is determined by the color. lol :)

Answer:

I cheated on

Spanish

ELA

history

Explanation:

Answer:

thx

Explanation:

Answer:

R = (18 ± 2) 10¹ Ω

ΔR = 2 10¹ Ω

Explanation:

Ohm's law relates voltage to current and resistance

           V = i R

            R = [tex]\frac{V}{i}[/tex]V / i

the absolute error of the resistance is

           ΔR = | [tex]| \frac{dR}{DV} | \ \Delta V + | \frac{dR}{di} | \ \Delta i[/tex]

the absolute value guarantees the worst case, maximum error

           ΔR = [tex]\frac{1}{i} \Delta V+ \frac{V}{i^2} \Delta i[/tex]

The error in the voltage let be approximate, if we use a scale of 10 V, in general the scales are divided into 20 divisions, the error is the reading of 1 division, let's use a rule of direct proportion

          ΔV = 1 division = 10 V / 20 divisions

          ΔV = 0.5 V

The current error must also be approximate, if we have the same number of divisions

           Δi = 50 mA / 20 divisions

           Δi = 2.5 mA

let's calculate

          ΔR = [tex]\frac{1}{45.5 \ 10^{-3}} \ 0.5 + \frac{8.2}{(45.5 \ 10^{-3})^2 } \ 2.5 \ 10^{-3}[/tex]

          ΔR = 10.99 + 9.9

          ΔR = 20.9 Ω

The absolute error must be given with a significant figure

          ΔR = 2 10¹ Ω

the resistance value is

          R = 8.2 / 45.5 10-3

          R = 180 Ω

the result should be

          R = (18 ± 2) 10¹ Ω

Answer:

2.72*10^-7m

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Substitute for λ

λ = v/f

λ = 2.05 x 10^8/7.55 x 10^14

λ = 2.05/7.55 * 10^{8-14}

λ = 0.272 * 10^-6

λ = 2.72*10^-7m

Hence the wavelength of the wave in carbon tetrachloride is 2.72*10^-7m

Answer:

The force holding you down is gravity.

Explanation:

Gravity is a force between two objects with mass. It pulls things together. You have mass, and the Earth has mass, so gravity tries to pull you and the Earth together. The gravitational force is much bigger for more massive objects.

Answer:

Gravitational Force

Explanation:

Gravitational Force holding everything down

-TheUnknownScientist

Answer:

Explanation:

Given that:

[tex]mass \ m_ 1 = 11.0 \ kg[/tex]

[tex]mass \ m_2 = 19.0 \ kg[/tex]

[tex]mass \ of \ the \ pulley\ M = 7.90 \ kg[/tex]

[tex]Radius \ of \ the \ pulley = 0.200\ m[/tex]

1) Provided that the mass in [tex]m_2[/tex] is greater than the mass we have in [tex]m_1[/tex], then likewise the tension we have in [tex]T_2[/tex] will be greater than the tension in [tex]T_1[/tex]

Using Newton's second law to mass [tex]m_1[/tex], we have:

[tex]m_2g - T_2 = m_2 a \\ \\ T_1 = m_1 g +m_1 a \\ \\ T_1= m_1 (g+a) --- (1)[/tex]

By using the second law, we have:

[tex]m_2g - T_2 = m_2a \\ \\ T_2 = m_2 (g-a)---(2)[/tex]

For the pulley, let's use the torque equation, so we have:

[tex]T_2 r -T_1 r = I \alpha \\ \\ T_2r -T_1r = \Big ( \dfrac{Mr^2}{2}\Big) \dfrac{a}{r} \\ \\ T_2 -T_1 = \dfrac{Ma}{2} ---- (3)[/tex]

Altogether, from equation (1)(2) and (3), we have:

[tex]m_2(g-a) -m_1 (g+a) = \dfrac{Ma}{2} \\ \\ m_2g -m_2a -m_1g-m_1a = \dfrac{Ma}{2} \\ \\ a = \dfrac{(m_2 -m_1) g}{(m_1 + m_2 + \dfrac{M}{2})} \\ \\ a = \dfrac{(19.0 \ kg - 11.0 \ kg ) ( 9.8 \ m/s^2)}{(19.0 \ kg + 11.0 \ kg + \dfrac{7.90 \ kg }{2} )}[/tex]

[tex]a = 2.31 \ m/s^2[/tex]

Also; from equation (1), the tension in the string is:

[tex]T_1[/tex] = (11.0 kg ) ( 9.8 + 2.31) m/s²

[tex]T_1[/tex] = 133.21 N

[tex]T_1[/tex] ≅ 133 N

From equation (2):

[tex]T_1[/tex] = m_2(g-a)

[tex]T_1[/tex] = (19.0 kg) ( 9.8 - 2.31) m/s²

[tex]T_1[/tex] = 142.31 N

[tex]T_1[/tex]  = 142 N

Answer:

The base of taller buildings are made broader because it reduces the pressure exerted on the ground so that they do not sink in due to the extremely high pressure of the building.

Explanation:

hope thiss helpss~!

A broad base is used to engage or recruit a diverse range of individuals to broad-based environmentalism.

Find out more about the broader base here:

brainly.com/question/14313691

Answer:

I am calculating the total area of a solar panel for a particular load demand by ... designing according to energy demand for a day then how will it affect total solar area? ... Total Power Output=Total Area x Solar Irradiance x Conversion Efficiency ... would need is a 1 m2 solar panel to produce 1000 Watts of electrical energy.

Explanation:

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex]  (1)

Where:

[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s

[tex]\omega_{0}[/tex]: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

[tex] \omega_{0} = \omega_{f} - \alpha t [/tex]   (2)

Now, by entering equation (2) into (1) we have:

[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]                        

[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]                              

[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

Gases - Water vapor, Nitrogen, Oxygen etc. Describe what happens to air pressure as you rise upwards in the atmosphere. What causes this change in air pressure? As altitude increases, air pressure will decrease As altitude increases the gas molecules that make up the air spread further apart

Answer: As you rise upwards in the atmosphere, air pressure decreases

Explanation: Because there are fewer molecules in the air, the air has a lower density, which results in a drop in air pressure. At different altitudes, the air is not the same. The area close to the earth is denser. As we rise, it continues to thin out. As a result of more air nearby, there is also increased air pressure. The weight and pressure of the air also continue to reduce as the volume of air does.

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

Answer:

I hope it's helpful .............

Answer:

-33750 N

Explanation:

Use coulomb's law: [tex]\frac{k(q1)(q2)}{r^{2} } = \frac{(9x10^{9})(-5x10^{-6})(3x10^{-6})}{0.002^{2} } = -33750 N[/tex]

Answer:

Explanation:

The light waves in the reflected sunlight are horizontally polarized, which illustrates that they oscillate at a [tex]90^o[/tex] angle related to a vertical line.

Depending on the condition of the height of the light, the glare can be almost entirely horizontally polarized. Furthermore, all reflections from over-water surfaces are partially polarized. The water becomes more translucent when using polarized sunglasses.

If polarized sunglasses are to be efficient against solar glare, the transmission axis should be positioned at an angle of [tex]\theta = 45^{o}[/tex]

Answer: c is correct

Explanation: i did this

Answer:

A) q_o = 0.001 C

B) I = 0.001•e^(-t)

C) V_c = 1000e^(-t)

D) V_r = 1000e^(-t)

E) P = e^(-2t) watts

Explanation:

A) We are given;

Initial stored energy; U_o = 0.5 J

Capacitance; C = 1.0μF = 1 × 10^(-6) F

To find the charge, we will use the formula for energy in capacitors which is given by;

U = q²/2C

Thus, since we are dealing with initial energy, U is U_o and q is q_o

Making q the subject, we have;

q_o = √2CU_o

q_o = √(2 × 1 × 10^(-6) × 0.5)

q_o = 0.001 C

B) The charge as a function of time is expressed as;

q = q_o•e^(-t/RC)

Now the current is gotten by differentiating the charge function. Thus;

I = (q_o/RC)•e^(-t/RC)

Where;

R is Resistance = 1.0MΩ = 1 × 10^(6) Ω

C is capacitance = 1 × 10^(-6) F

(q_o/RC) is the initial current = 0.001/(1 × 10^(6) × 1 × 10^(-6))

(q_o/RC) = 0.001 A

Thus;

I = 0.001•e^(-t/(1 × 10^(6) × 1 × 10^(-6)))

I = 0.001•e^(-t)

C) Formula for potential difference across the capacitor is;

V_c = IR

I = 0.001•e^(-t)

R = 1 × 10^(6) Ω

Thus;

V_c = 1 × 10^(6) × 0.001•e^(-t)

V_c = 1000e^(-t)

D) Potential difference across the resistor will be the same as that across the capacitor because the resistor is connected in parallel to the capacitor.

Thus;

V_r = V_c = 1000e^(-t)

E) rate at which thermal energy is produced is basically the power.

Thus;

P = (V_r)²/R

P = (1000²e^(-2t))/1 × 10^(6)

P = e^(-2t) watts