What are 2 sources of proteins?

Answers

Answer 1
These are examples of protein: lean meat , milk , yoghurt , and cheese

Related Questions

Suppose that white light strikes a flat piece of flint glass in air, coming in at an angle of 60 degrees to the surface (30 degrees from the normal or perpendicular). The index of refraction of this dense glass for red light is 1.710, for green light is 1.723, and for blue light is 1.735. What is the order of colors you would see in the refracted light inside the glass as they leave the surface

Answers

Answer:

The order of the light starting from the light closest to the normal line is

Blue light, followed by green ight and then lastly red light

Explanation:

White light travels from one medium to another such as from air to glass is refracted according to Snell's law as follows

n₁·sin(θ₁) = n₂·sin(θ₂)

The given parameters of the white light are;

The angle the incident (incoming) light makes with the surface = 90°

The angle of incidence of the light, θ₁ = 30°

The index of refraction of red light for the glass, n₂ = 1.710

The index of refraction of green light for the glass, n₃ = 1.723

The index of reaction of blue light for the glass, n₄ = 1.735

The refractive index of air, n₁ = 1

The angle of refraction of the red light, θ₂ is given as follows;

1 × sin(30°) = 1.710 × sin(θ₂)

sin(θ₂) = 1 × sin(30°)/1.710

θ₂ = sin⁻¹(1 × sin(30°)/1.710) ≈ 17°

The angle of refraction (to the surface's normal line) of the red light, θ₂ ≈ 17°

The angle of refraction of the green light, θ₃ is given as follows;

1 × sin(30°) = 1.723 × sin(θ₃)

sin(θ₃) = 1 × sin(30°)/1.723

θ₃ = sin⁻¹(1 × sin(30°)/1.723) ≈ 16.869°

The angle of refraction of the green light, θ₃ ≈ 16.869°

The angle of refraction of the green light, θ₄ is given as follows;

1 × sin(30°) = 1.723 × sin(θ₄)

sin(θ₄) = 1 × sin(30°)/1.735

θ₄ = sin⁻¹(1 × sin(30°)/1.735) ≈ 16.749°

The angle of refraction of the green light, θ₄ ≈ 16.749°

The order of colors we see as the in the refracted light inside the glass as the light leave the surface are;

The red light, with an angle of refraction of approximately 17° will be furthest from the normal

The green light which has an angle of refraction of 16.869° will follow and will be intermediate between the red and the blue light

The blue light which has an angle of refraction of 16.749° will follow next and it will be closest to the normal

The order of the light from the normal line will be blue, followed by green and then red light

The ballistic pendulum is a device used to measure the speed of a fast - moving projectile such as a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet embeds in the block, and the entire system swings up to a height h. A Walther PPK, the gun used by James Bond, has an average muzzle velocity of 950 m/s. In a ballistic pendulum, how high would we expect the block to travel when shot by a Walther PPK, given the mass of a 0.32 ACP is 5 grams, a the mass of the block is 2kg

Answers

Answer:

 h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]

Explanation:

To solve this problem, let's work in parts, let's start with the conservation of the moment, for this we define a system formed by the block and the bullet, in such a way that the forces during the collision have been internal and the moment is conserved.

 

initial instant. Before the crash

         p₀ = m v₀

final instant. Right after the crash, but before the pendulum started to climb

         m_f = (m + M) v

the moment is preserved

        p₀ = p_f

        m v₀ = (m + M) v

        v = [tex]\frac{m}{m+M} \ v_o[/tex]  

Now we work the pendulum system with embedded block, we use the concept of conservation of energy

starting point. Lower

        Em₀ = K = ½ (m + M) v²

final point. higher, when it stops

         Em_f = U = (m + M) g h

as there is no friction, energy is conserved

        Em₀ = Em_f

        ½ (m + M) v² = (m + M) g h

         h = [tex]\frac{v^2}{2g}[/tex]

we substitute the speed value of the block plus bullet set

        h = [tex]( \frac{m}{ m+M} \ v_o )^2 \ \frac{1}{2g}[/tex]

     

        h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]

An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed

Answers

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

[tex]qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s[/tex]

So, the speed of the electron is 2591.83 m/s.

Car X is travelling at 30m/s north. Its driver looks at car Y approaching on another road and he estimates it is moving at 15m/s south-west relative to his car. Calculate the velocity of car Y relative to the ground.

Answers

Answer: 22.1 m/s

Explanation:

The velocity of Car traveling 30 m/s towards the north

In vector form it is

[tex]v_x=30\hat{j}[/tex]

The velocity of car Y w.r.t X is

[tex]\Rightarrow v_{yx}=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}][/tex]

Solving this

[tex]\Rightarrow v_{yx}=v_y-v_x\\\Rightarrow v_y=v_{yx}+v_x[/tex]

putting values

[tex]\Rightarrow v_y=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}]+30\hat{j}[/tex]

[tex]\Rightarrow v_y=-10.606\hat{i}+19.39\hat{j}[/tex]

absolute velocity relative to ground is

[tex]\left | v_y\right |=\sqrt{(-10.606)^2+(19.39)^2}\\\left | v_y\right |=22.101\ m/s[/tex]

Fossil clues are one of the _____________ clues that support the theory of continental drift.
A. crust B. resource C. climate D. rock

Answers

Answer:

a

Explanation:

I think don't get mad if I'm wrong

The Sun is divided into three regions.
True оr False?

Answers

Answer:

false I think

Explanation:

hope that help

so it's not divided in 3 regions

A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating over one period of the waveform. Hint: the equation for a square wave will be a piecewise function and it will be convenient to start the integration where the voltage changes; for example in this problem we could define that during the first half of the period the voltage is 0 V and for the second half of the period the voltage is 4 V

Answers

Answer:

V_{average} = [tex]\frac{1}{2} V_o[/tex]  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = [tex]\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.[/tex]

to substitute in the equation let us separate the into two pairs

             V_average = [tex]\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt[/tex]

             V_average = [tex]V_o \ \int\limits^{1/2}_0 {} \, dt[/tex]

             V_{average} = [tex]\frac{1}{2} V_o[/tex]

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

A 31.0-kg child on a 3.00-m-long swing is released from rest when the ropes of the swing make an angle of 27.0° with the vertical.
(a) Neglecting friction, find the child's speed at the lowest position.
(b) If the actual speed of the child at the lowest position is 2.20 m/s, what is the mechanical energy lost due to friction?

Answers

Answer:

a)  v = 2.53 m / s, b)  ΔEm = -24.32 J

Explanation:

a) For this exercise we can use the conservation of energy,

starting point. Highest point

           Em₀ = U = m g h

final point. Lower of the trajectory

           Em_f = K = ½ m v²

as there is no friction energy is conserved

           Em₀ = Em_f

           mgh = ½ m v²

           v² = 2gh

we are used trigonometry to find the height

           h = L - L cos tea

we substitute

           v = [tex]\sqrt{2gL (1- cos \theta)}[/tex]

let's calculate

           v = [tex]\sqrt { 2 \ 9.8 \ 3.00 \ ( 1- cos \ 27) }[/tex]

           v = 2.53 m / s

b) The loss of mechanical energy due to friction

          ΔEm = Em_f -Em₀

          ΔEm = ½ m v² - m g h

          ΔEem = ½ m v² - m g L (1-cos θ)

let's calculate

          ΔEm = ½ 31.0  2.20² - 31  9.8  3.00 (1-cos 27)

           ΔEm = 75.02 - 99.34

           ΔEm = -24.32 J

the negative sign indicates that power has been requested

Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the speaker is amplified, the book can be torn apart into small pieces.

Answers

Answer:

yes with a lot of time it eventualy could be, but in short term no

Explanation:

Jim and Sally both do identical jobs. Jim works quickly while Sally works slowly. Which of the following is true?

A) Sally uses more energy.
B) Jim uses more energy.
C) Jim uses more power.
D) Sally uses more power.

Answers

The answer should be C

A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 121 N is applied tangent to the rim of the tire. (a) What force must be applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2

Answers

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

Approximately; F2 = 834 N

The force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

What is force?

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now the moment of inertia of the wheel which is assumed to be a hoop is given by;

[tex]I=mr_1^2[/tex]

Where

r1 = 0.315 m

I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

[tex]I\alpha=F_1\times r_1-F_2\times r_2[/tex]

Where [tex]F_2[/tex]  is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

0.1736 × 4.4 = (121 × 0.315) - (0.0448[tex]F_2[/tex])

0.76384 = 38.115 - (0.0448[tex]F_2[/tex])

[tex]F_2= \dfrac{38.115-0.7638}{0.0448}[/tex]

[tex]F_2=833.73\ N[/tex]  

Approximately; F2 = 834 N

Thus the force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

To know more about Force follow

https://brainly.com/question/25239010

plz help me with my career!!!
part one...

Answers

Answer:

#1 Yes

Explanation: #1: The rest of them are used mainley by farmers, and crops are used by common citizens in the world.

Question 1: Crops.

Question 2: Diagnostic Services.

Question 3: A cable company needs to lay new fiber optic cable to reach its customers across a large lake.

Question 4: A bachelor's degree in energy research.

Question 5: Environmental Resources.

If any of these answers are incorrect, please tell me, so I can fix my mistake. Thank you.

A ball is dropped off the side of a bridge,
After 1.55 S, how far has it fallen?
(Unit=m)

Answers

Answer:

Distance S = 11.77 m (Approx.)

Explanation:

Given:

Time t = 1.55 Second

Gravity acceleration = 9.8 m/s²

Find:

Distance S

Computation:

S = ut + (1/2)(g)(t)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

Distance S = 11.77 m (Approx.)

Aunt Jane weights 45 Newtons. What is her mass?

Answers

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

Mars orbits the sun at less then 60% of the speed of earth. True or false?

Answers

Answer:

True im pretty sure

Explanation:

Answer:

False

Explanation:

The answer is false, I tested it on IXL

How do the sclera and the cornea compare?
The sclera is the inside layer at the back of the eyeball, and the cornea is on the outside of the eyeball.
The sclera focuses light that enters the eye, and the cornea controls how much light enters the eye.
The sclera does not alloy light to enter the eyeball
and the cornea allows light to enter the eyeball.
The sclera is the outer surface of the eyeball
and the cornea fills the inside of the eyeball.

Answers

Answer:

The sclera focuses light that enters the eye, and the cornea controls how much light enters the eye.  

Explanation:

A block with mass m1m1m_1 is placed on an inclined plane with slope angle ααalpha and is connected to a second hanging block that has mass m2m2m_2 by a cord passing over a small, frictionless pulley. The coefficient of static friction is μsμsmu_s and the coefficient of kinetic friction is μkμkmu_k. Find the smallest value of m2 when the blocks will remain at rest if they are released from rest.

Answers

Answer:

Explanation:

m₂ is hanging vertically and m₁ is placed on inclined plane . Both are in limiting equilibrium so on m₁ , limiting friction will act in upward direction as it will tend to slip in downward direct . Tension in cord connecting the masses be T .

For equilibrium of m₁

m₁ g sinα= T + f where f is force of friction

m₁ g sinα= T + μsx m₁ g cosα

m₁ g sinα -  μs x m₁ g cosα = T

For equilibrium of m₂

T = m₂g

Putting this value in equation above

m₁ g sinα -  μs x m₁ g cosα = m₂g

m₂ = m₁ sinα -  μs x m₁ cosα

A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 3.83 × 10–6 m2 cross section. Nichrome has a resistivity of 5.00 × 10–7 Ω·m. (a) If the element dissipates 5200 W, what is its length? (b) If 120 V is used to obtain the same dissipation rate, what should the length be?

Answers

Answer:

Explanation:

power of a heating element = V² / R where V is voltage and R is resistance

putting in the values

5200 = 75² / R

R = 1.082 ohm

Formula for resistance

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

1.082 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 8.29 m

b )

power of a heating element = V² / R , R is new resistance

5200 = 120² / R

R = 2.77 ohm

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

2.77 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 21.22 m

In an effort to be the star of the half-time show, the majorette twirls a highly unusual baton made up of four mases fastened to the ends of light rods. Each rod is 1.0 m lone. Find the moment of inertia of the system about an axis perpendicular to the page and passing through the point where the rods cross.

Answers

Answer:

"0.25 kg-m²" is the appropriate answer.

Explanation:

The diagram of the question is missing. Find the attachment of the diagram below.

According to the diagram, the values are:

m₁ = 0.2

m₂ = 0.3

m₃ = 0.3

m₄ = 0.2

d₁ = d₂ = d₃ = d₄ = 0.5 m

As we know,

The moment of inertia is:

⇒  [tex]I=\Sigma M_id_i^2[/tex]

then,

⇒  [tex]I=m_1d_1^2+m_2d_2^2+m_3d_3^2+m_4d_4^2[/tex]

⇒     [tex]=d^2(m_1+m_2+m_3+m_4)[/tex]

On substituting the values, we get

⇒     [tex]=0.5^2\times (0.2+0.3+0.3+0.2)[/tex]

⇒     [tex]=0.25\times 1[/tex]

⇒     [tex]=0.25 \ Kg-m^2[/tex]

Which one is it? Help ASAP

Answers

Answer:

extreme heat, because no physical damage can demagnetize a magnet

Explanation:

Answer:

the 3rd one

Explanation:

If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Answers

My Response:

If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Sample Response:

If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.

The power of an engine is a measure of
A) the total amount of work it can perform.
B) the rate at which it can perform work.
C) its ability to outperform a horse.
D) its volume.

Answers

Answer:

d

Explanation:

Answer:

C

Explanation:

Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.

Ps:Can I be brainliest.

Have a nice day

To understand the relationship between the force and the potential energy changes associated with that force and to be able to calculate the changes in potential energy as definite integrals. Imagine that a conservative force field is defined in a certain region of space. Does this sound too abstract

Answers

Answer:

This does not sound too abstract

Explanation:

An example of an Imaginative conservative force field defined in terms of a certain region of space is : A gravitational field and it can be expressed as

[tex]Fx = - \frac{dU_{x} }{dx}[/tex]  and this is because the potential energy in a gravitational field is determined only by the initial and final position of the objects found with the Gravitational field

To determine the change in potential energy  ΔU we will integrate the above equation

hence :  ΔU = [tex]\int\limits^2_1 {F} \, ds[/tex]  

Hence this does not sound too abstract

Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader

Answers

Answer:

7.55 g

Explanation:

Using the relation :

Δt = temperature change = (6° - 0°) = 6°

Q = quantity of heat

C = specific heat capacity = 4190 j/kg/k

1000 J = 1kJ

333 KJ = 333000 j

The quantity of ice that will melt ;

= 0.419 * 6 * 100 / 333000

= 2514000 / 333000

= 7.549 g

The mass of ice that will melt :

2.514 / 0.333

= 7.549 g

1) A man leans against the wall and...
a) The man's shoulder pushes against the wall
b) The wall pushes against the man
c) Bricks in the wall push against each other
d) The ground pushes against the man, supporting him.

Answers

Answer:

I thinks its a, but its really about gravity im not sure

Explanation:

:)

What is an electric current?

a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb
What is an electric current?

a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb

Answers

Answer:

c

Explanation:

mark brainleyest plz if right

Part D Here is one last question as a final check on your understanding of your work for this problem, looking at this problem as an example of the Conservation of Energy. The action in this problem begins at location A , with the block resting against the uncompressed spring. The action ends at location B, with the block moving up the ramp at a measured speed of 7.35 m/s . From A to B, what has been the work done by non-conservative forces, and what has been the change in the mechanical energy of the block-Earth system (the ramp is a part of the Earth)

Answers

Answer:

The answer is "39.95 J".

Explanation:

Please find the complete question in the attached file.

[tex]\to W_{AC}=(\mu \ m \ g \ \cos \theta ) d[/tex]

            [tex]=(0.45 \times 1.60 \times 9.8 \times \cos 26^{\circ}) 6.30 \\\\=(7.056 \times \cos 26^{\circ}) 6.30 \\\\=6.34189079\times 6.30\\\\=39.95 \ J\\\\[/tex]

[tex]\therefore \\\\\bold{\Delta E =39.95 \ J}[/tex]

you're reading from the journal of a European explorer from the early 1600s. In one passage, the explorer describes itting on the Atlantic Ocean with little wind. He describes the area as being quite far north of the equator and having nigh pressure. n which type of global wind was this explorer sailing? doldrums horse latitudes jet stream O polar easterlies ​

Answers

Answer: horse latitudes

Explanation:

Answer:

B

Explanation:

Doldrums are located some 5 degrees away from north while horse latitude is located some thirty degrees away from north latitude and by same degrees from the southern hemisphere. Polar eastariles are cold winds blowing across the Polar Regions and jet stream is fast blowing winds.  

Horse latitude is silent winds and the region has high pressure and very little precipitation.  

Hence, option B is correct

Match the following:​

Answers

Answer:

iron metal :chromiummachinery part :nickel or chromiumornamentation and decoration pieces :silver and goldprocessed food :tin coated iron canbridges and automobiles :zinc metaldistilled water:bad conductor

What is the frequency of a wave with a wavelength of 0.5 m and speed of 50 m/s

Answers

Answer: 25 m/s

Explanation:

To calculate the speed of a wave, simply multiply its wavelength and its frequency (given that you are provided with the two variables).

This makes sense, since the unit for speed (m/s) matches that of the product of wavelength (m) and frequency (Hz). Keep in mind that one Hz is equivalent to one inverse second (

s

1

or

1

s

).

If you multiply m (the unit for wavelength) with

1

s

(the unit for frequency), you will get m/s, the unit for speed.

Now multiply!

.5 m * 50 Hz = 25 m/s

25 m/s is your final answer!

Other Questions
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