What are Heredity and Punnett Squares?

Answers

Answer 1

Answer: A Punnett square can be used to predict genotype and phenotypes of offspring from genetic crosses. ... In the P generation, one parent has a dominant yellow phenotype and the genotype YY, and the other parent has the recessive green phenotype and the genotype yy.

Explanation:


Related Questions

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.310 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. m/s (b) Calculate his acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2 (c) Calculate the force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Answers

Answer:A)u =4.295m/s  , B)a = 29.746m/s²   C) F=3,153N

Explanation:

Using the kinematic expression  

v² = u² - 2as

where

u = initial velocity

v = final velocity

s = distance

g = acceleration due to gravity .

Given that he reaches a height of 0.940 m above the floor,

the final velocity  = 0

Here, acceleration due to gravity is acting in  opposite the initial direction of motion. So, a=-9.81 m/s.

v² = u² + 2as

0² - u² = 2 (- 9.81) × 0.940

- u² = 2 × - 9.81 × 0.920

- u² = -18.4428

cancelling the minus in both sides , we have that  

u² = 18.4428

u = √18.4428

u =4.295m/s

(b) His acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2

Using v² = u² + 2as

where u = initial speed of basketball player before lengthening = 0 m/s,

v = final speed of basketball player after lengthening =  4.295m/s,

a = acceleration while  straightening his legs

s = distance moved during lengthening = 0.310m

v² = u² + 2as  

 a = (v² - u²)/2s

a = (4.29m/s)² - (0 m/s)²)/(2 × 0.310m)

a = (18.4428 m²/s² - 0 m²/s²)/(0.62 m)

a = (18.4428 m²/s²/(0.62 m)

a = 29.746m/s²

c) The force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Force= mass x acceleration.

F = 106 kg X 29.746m/s²

 F = 3,153.076 rounded to  3,153N

The acceleration used for the height is 9.81 m/s2 because it is the acceleration due to gravity. (true or false)

Answers

Answer:

true

Explanation:

Gravity (or the acceleration due to gravity) is 9.81 meters per second squared, on the surface of Earth, because of the size of Earth and the distance we are on its surface from its center.

Which DOES NOT happen during the phase change from liquid to solid?

Kinetic energy decreases

Particles move slower

Freezing occurs

Temperature increases

Answers

Answer:

Temperature increases

During the phase transition from liquid to solid, kinetic energy diminishes, particles move slower, and freezing occurs.

Phase change:

Extreme heat is more likely to occur as a result of rising temperatures, and it will last longer. Heatwaves can indeed be deadly, resulting in manifestations including heat kinks and heat exhaustion, as well as death.

Warmer temperatures have the potential to trigger a cascade of other changes around the world.The greenhouse effect is worsened by these gas emissions, which cause the earth's crust temperature to rise. Burning fossil fuels has the greatest impact on climate change of any human activity.

Since in changement from liquid to solid the temperature will decrease.Therefore, the final answer is "Temperature increases".

Find out more about the phase change here:

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PLEASE HELP!

what would the answer be?

Answers

Answer:

Tie aluminium foil on each end of the battery using rubber band, then use copper wire to attach the led to the aluminium foil...... probably would work

The potential energy of an object is 16.0 joules. The object is 145cm high.
What is the mass of the object?

Answers

Answer:

I don't know but you got this!!

how were the outer planets formed?

Answers

Answer:

All planets including the outer larger planets were formed at the same time somewhere around 4.5 Billion years ago.

Explanation:

the young sun drove away most of the gas from the inner solar system, leaving behind the rocky cores also known as the terrestrial planets.

8. A weight lifter lifts a set of weights a vertical distance of 2 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights? Please show full working out ( not in words)​

Answers

Answer:  Work = change in energy which can be calculated by force * displacement so taking this we can multiply 350n by *2m and we can come out with 700 joules

Explanation: I Hope This Helps I'm new at this.


Which of the following is the tendency of a system to become more
disordered?
A. Energy
B. Heat
C. Entropy
D. Efficiency

Answers

Answer:

b

Explanation:

the more heat the hotel it get which cause more heat

Answer: C. Entropy

Explanation: a pex :)

help meee plisssssssssssssssssssssssssssss

Answers

Answer:

Resistance = 0.22 Ohms

Current = 13.63636 A

Explanation:

Total resistance for resistors in parallel is given by:

[tex]\frac{1}{T} =\frac{1}{R1} +\frac{1}{R2} +...+\frac{1}{Rn}[/tex] where n is the number of resistors

[tex]\frac{1}{T} = \frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1}[/tex]

if you solve that you get [tex]\frac{1}{T} = 5/1.1 \\\\T = 1.1/5T = 0.22 Ohms[/tex]

Solve current using V=IR

I=V/R =

I=3/0.22

I = 13.63636 A

A 100 W engine generates 1000 J of energy. How long did it run for?
A. 1 s
B. 10 s
C. 5 s
D. 100 s

Answers

Answer:

B. 10 s

Explanation:

Given the following data;

Power = 100 Watts

Energy = 1000 Joules

To find the time;

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

Making time the subject of formula, we have;

[tex] Time = \frac {Energy}{Power} [/tex]

Substituting into the formula, we have;

[tex] Time = \frac {1000}{100} [/tex]

Time = 10 seconds

Attempt 2 You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 15151515 lb and was traveling eastward. Car B weighs 11251125 lb and was traveling westward at 42.042.0 mph. The cars locked bumpers and slid eastward with their wheels locked for 17.517.5 ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.7500.750 . How fast (in miles per hour) was car A traveling just before the collision

Answers

Answer:

v = 28.98 ft / s

Explanation:

For this problem we must solve it in parts, let's start by looking for the speed of the two cars after the collision

In the exercise they indicate the weight of each car

          Wₐ = 1500 lb

          W_b = 1125 lb

Car B's velocity from v_b = 42.0 mph westward, car A travels east

let's find the mass of the vehicles

             W = mg

             m = W / g

             mₐ = Wₐ / g

             m_b = W_b / g

             mₐ = 1500/32 = 46.875 slug

             m_b = 125/32 = 35,156 slug

Let's reduce to the english system

             v_b = 42.0 mph (5280 foot / 1 mile) (1h / 3600s) = 61.6 ft / s

We define a system formed by the two vehicles, so that the forces during the crash have been internal and the moment is preserved

we assume the direction to the east (right) positive

initial instant. Before the crash

           p₀ = mₐ v₀ₐ - m_b v_{ob}

final instant. Right after the crash

           p_f = (mₐ + m_b) v

the moment is preserved

           p₀ = p_f

           mₐ v₀ₐ - m_b v_{ob} = (mₐ + m_b) v

           v = [tex]\frac{ m_a \ v_{oa} - m_b \ v_{ob} }{ m_a +m_b}[/tex]

we substitute the values

           v = [tex]\frac{ 46.875}{82.03} \ v_{oa} - \frac{35.156}{82.03} \ 61.6[/tex]

           v = 0.559 v₀ₐ - 26.40                  (1)

Now as the two vehicles united we can use the relationship between work and kinetic energy

the total mass is

              M = mₐ + m_b

              M = 46,875 + 35,156 = 82,031 slug

starting point. Jsto after the crash

              K₀ = ½ M v²

final point. When they stop

             K_f = 0

The work is

             W = - fr x

the negative sign is because the friction forces are always opposite to the displacement

Let's write Newton's second law

Axis y

           N-W = 0

           N = W

the friction force has the expression

            fr = μ N

we substitute

            -μ W x = Kf - Ko

             

            -μ W x = 0 - ½ (W / g) v²

            v² = 2 μ g x  

            v = [tex]\sqrt{ 2 \ 0.750 \ 32 \ 17.5}[/tex]Ra (2 0.750 32 17.5  

            v = 28.98 ft / s

A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a giant spring at the bottom of the elevator shaft. As the elevator falls, its safety clamp applies a constant frictional force of 17,000 N. 1. List all the forces acting on the elevator after the cable breaks but before it hits the spring. Determine the work done by each force on the elevator. Make sure these work terms have the appropriate signs (positive or negative). 2. Calculate the net work done on the elevator. 3. Use the work-kinetic-energy theorem to determine the speed of the elevator right before it encounters the spring. 4. After the elevator encounters the spring, the spring compresses by 0.6 m before the elevator comes to rest. The safety clamp continues to apply a constant 17,000 N force. List all the forces acting on the elevator while it falls this final 0.6 m. 5. For each force listed in question F4, determine an expression for the work it does on the elevator. Make sure each work term has the appropriate sign (positive or negative). 6. Use the work-kinetic-energy theorem to determine the value of the spring constant k.

Answers

Explanation:

work done =force *distance

work done =17000*26

work done=442,000 joules.

What is one disadvantage of sending information over long distances
wirelessly using digital signals?
O A. The signals become weaker the farther the receiver is from the
source.
B. The farther the signals travel, the more slowly they move.
C. The signals become stronger the farther the receiver is from the
source.
O D. The farther the signals travel, the easier they are to detect.

Answers

The disadvantage of sending information over long distances wirelessly using digital signals is "the signals become weaker the farther the receiver is from the source."

Since most of the signal which we use for communication are radio signal Radio signal are basically electromagnetic waves.As the wave moves forward it looses its amplitude.So basically radio signal becomes weaker for long distance.

What are radio signals?Radio signals or radio waves are a form of electromagnetic wave. Although this may sound complicated, it is possibly sufficient to say that these waves have both electric and magnetic components. They are the same as light rays, ultra-violet and infra-red. The only difference is in the wavelength of the waves.

Thus , The disadvantage of sending information over long distances wirelessly using digital signals is "the signals become weaker the farther the receiver is from the source."

Learn more about Radio waves here -

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Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the drive force is shut off, the snowmobile coasts to a halt. The snowmobile and its rider have a mass of 128 kg. Under the influence of a drive force of 195 N, it is moving at a constant velocity whose magnitude is 5.90 m/s. The drive force is then shut off. Find (a) the distance in which the snowmobile coasts to a halt and (b) the time required to do so.

Answers

Answer:

a) Δx = 11.6 m

b) t = 3.9 s

Explanation:

a)

Since the snowmobile is moving at constant speed, and the drive force is 195 N, this means that thereis another force equal and opposite acting on it, according to Newton's 2nd Law, due to there is no acceleration present in the horizontal direction .This force is just the force of kinetic friction, and is equal to -195 N (assuming the positive direction as the direction of the movement).Once the drive force is shut off, the only force acting on the snowmobile remains the friction force.According Newton's 2nd Law, this force is causing a negative acceleration (actually slowing down the snowmobile) that can be found as follows:

       [tex]a = \frac{F_{fr} }{m} = \frac{-195N}{128kg} = -1.5 m/s2 (1)[/tex]

Assuming the friction force keeps constant, we can use the following kinematic equation in order to find the distance traveled under this acceleration before coming to an stop, as follows:

       [tex]v_{f} ^{2} -v_{o} ^{2} = 2* a* \Delta x (2)[/tex]

Taking into account that vf=0, replacing by the given (v₀) and a from (1), we can solve for Δx, as follows:

       [tex]\Delta x =- \frac{v_{o}^{2}}{2*a} =- \frac{(5.90m/s)^{2}}{2*(-1.5m/s2)} = 11.6 m (3)[/tex]

b)

We can find the time needed to come to an stop, applying the definition of acceleration, as follows:

       [tex]v_{f} = v_{o} + a*\Delta t (4)[/tex]

Since we have already said that the snowmobile comes to an stop, this means that vf = 0.Replacing a and v₀ as we did in (3), we can solve for Δt as follows:

       [tex]\Delta t = \frac{-v_{o} }{a} = \frac{-5.9m/s}{-1.5m/s2} = 3.9 s (5)[/tex]

Which has the greater kinetic energy–a 1-ton car moving at 30 m/s or a half-ton car
moving at 60 m/s?
A) Both have the same kinetic energy
B) The half-ton car
C) The 1-ton car
D) It cannot be determined because the mass of the cars can't be found

Answers

Answer:

B). half-ton car

Explanation:

We can find Kinectic using below expresion.

m= mass of the object

v= velocity

mass (1) 1 ton= 1000kg

Mass(2)0.5= 500kg

K.E= 1/2 mv^2

For 1 ton car

Substitute the values

Kinectic energy= 1/2( 1000) 30^2

= 450,000J

For 0.5 ton car

Kinectic energy= 1/2(500)60^2

= 900,000J

Hence, half-ton car has greater Kinectic energy

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

Tectonic Plate Movement

Explanation:

Each continent and ocean sits on its own tectonic plate which floats on the Earths upper mantle. They move very little over time.

Answer:

tectonic plates movement

1. Is it possible for the ball to move so quickly that the angle between the cable and vertical post stays at ninety degrees?
2. When the ball is moving in a horizontal circle, what vertical force (or component) balances gravity?
3. What happens to the centripetal force as the length of the cord increases?

Answers

Answer:

Tetherball is an interesting game in which two players tries to hit the ball hard so that it goes around the

pole.Each time the player hits the ball, it's orbit rises higher off the ground.Let's understand the physics

behind this.The motion of a tetherball is governed by two forces.These two forces combine to generate a

net force, i.e. centripetal force.If the ball is moving more quickly, it requires a greater centripetal force,

which in turn requires a greater tension force.Since the ball's weight hasn't changed, the angle of the

tension force changes until the ball is in vertical equilibrium.

To access this physics simulation visit: http://goo.gl/xVdwgO Page 02Exploration Series www.ck12.org

Ball Mass : This slider controls the mass of the ball. A ball with more mass will have more inertia, requiring

a greater net force to accelerate it. A ball with more mass will ALSO have a greater gravitational force

acting on it. Watch both of these effects occur when you manipulate this slider.

Cable Length : This slider controls the length of the cable. A longer cable is capable of allowing a greater

circular radius of motion for the ball. It is important to remember that the radius of the circular motion is

NOT equal to the length of the cable. Instead, if you want to understand the size of the circle of the ball's

motion, ignore the cable and just imagine the path of the ball.

Ball Speed : This slider controls the speed of the ball - imagine a kid just hit the ball and it sped up. A ball

moving more quickly is also accelerating more quickly because its velocity is changing as it moves in a

circle (remember that changes in DIRECTION of velocity 'count' as changes to velocity).

Force Diagram : This allows you to turn on or off the diagram of the forces acting on the ball. Look for the

ball to be in vertical force balance, which means the vertical component of tension is canceled by the

gravitational force. The ball should NOT be in horizontal force balance - it is accelerating towards the center

of the circle! It is important to note that this free body diagram should really be moving with the ball so that

To access this physics simulation visit: http://goo.gl/xVdwgO Page 03Exploration Series www.ck12.org

the tension force always points along the cord - we are just showing the forces at the moment the ball is at

the furthest-right on this screen.

Centripetal force vs Tetherball speed : This is a plot of centripetal force required to keep the ball in

circular orbit about the pole as a function of its speed. As expected, a more quickly-moving ball is changing

in velocity more often in a given amount of time, and so is accelerating more. This greater (centripetal, or

center-pointing) acceleration requires a greater net force.

Explanation:

)) What do these two changes have in common?
mixing chocolate syrup into milk
rain forming in a cloud
) Select all that apply.
Both involve chemical bonds breaking.
Both are changes of state.
Both are only physical changes.
Both are chemical changes.

Answers

Answer:

Both are only physical changes

Explanation:

A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.

According to this question, two processes were given as follows:

1. mixing chocolate syrup into milk

2. rain forming in a cloud

These two processes are similar in the sense that they are both examples of physical changes.

A block starting from rest slides down the length of an 18 plank with an acceleration of 4.0 meters per second. How long does the block take to reach the bottom?

Answers

Answer:

[tex]\boxed{\text{\sf \Large 3.0 s}}[/tex]

Explanation:

Use distance formula

[tex]\displaystyle d=ut+\frac{1}{2} at^2[/tex]

[tex]u= \text{\sf initial velocity}\\d= \text{\sf distance}\\a= \text{\sf acceleration}\\t= \text{\sf time taken}[/tex]

[tex]\displaystyle 18=0 \times t+\frac{1}{2} \times 4 \times t^2[/tex]

[tex]t=3[/tex]

A block starting from rest slides down the length of an 18 m plank with an acceleration of 4.0 meters per second square. Time taken by the block  to reach at the bottom is 3 sec.

What is acceleration?

The rate at which an object changes its velocity is known as acceleration. Acceleration is a vector quantity. If an object's velocity is changing then it is accelerating and an object with a constant velocity is not accelerating.

The speed at which something moves in a specific direction is known as its velocity. As an illustration, think of the speed of a car travelling north on a highway or the speed at which a rocket takes off.

Given that in the question block slides down an 18 m plank length with an acceleration of 4.0 meters per second square when it begins at rest.

Using equation of motion,

S = ut + (1/2)at²

s is distance, s = 18 m

u is initial velocity, u = 0

a is acceleration, a = 4 m/sec²

t is time

18 = 0*t + (1/2)*4*t

solving we get t = 3 sec.

Time taken by the block  to reach at the bottom is 3 sec.

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The new roller coaster at Carowinds flies along at 80 m/s. How long does it take to
travel 16000 meters of track?

Answers

It takes about a really long time

A bar magnet has
a. one magnetic pole.
b. two magnetic poles.
c. three magnetic poles.
d. four magnetic poles.

Answers

Answer:

b

Explanation:

Bar magnets have two magnetic poles

he inductance of a tuning circuit of an AM radio is 4 mH. Find the capacitance of the circuit required for reception at 1200 kHz.

Answers

Answer:

4.4pF

Explanation:

the capacitance of the circuit required for reception is given:

wL =  [tex]\frac{1}{wC}[/tex]

w = 2π [tex]f[/tex]

Using both equation

Capacitance is given

C =   1 - 4π2  f2 L

1- 4×9.8969×144×10 10 ×0.004

​=4.4pF

A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot

Answers

The answer is Copper

A researcher plans to release a weather balloon from ground level, to be used for high-altitude atmospheric measurements. The balloon is spherical, with a radius of 2.00 m, and filled with hydrogen. The total mass of the balloon (including the hydrogen within it) and the instruments it carries is 20.0 kg. The density of air at ground level is 1.29 kg/m3. (a) What is the magnitude of the buoyant force (in N) acting on the balloon, just after it is released from ground level

Answers

Answer:

B = 423.64 N

Explanation:

The thrust force in a fluid is equal to the weight of the displaced fluid,

         B = ρ g V

where the density is that of air ρ=1.29 kg / m³ and the volume of the spherical balloon is

          V = [tex]\frac{4}{3} \pi r^3[/tex]

          v = 4/3 π 2³

          V = 33.51 m³

let's calculate the thrust

          B = 1.29  9.8  33.51

          B = 423.64 N

.HOW DOES PHYSICAL EDUCATION BENEFIT YOUR EMOTIONAL HEALTH ?

Answers

Answer: reduce anxiety, depression, and  negative mood and by improving self-esteem and cognitive function.

Explanation:

explain why radiation is dangerous for humans

Answers

Answer:

because it affects the attom in living things

Radiation is dangerous to humans as it can result in long-term health effects such as cancer and cardiovascular disease.

A toy projectile is fired vertically from the ground upward with a velocity of +29 meters per second. It arrives at its maximum altitude in 3.0 seconds. How high does the projectile go?

Answers

Answer:

[tex]\boxed{\text{\sf \Large 42 m}}[/tex]

Explanation:

Use height formula

[tex]\displaystyle \sf H=\frac{u^2 sin(\theta)^2}{2g}[/tex]

u is initial velocity

θ = 90° (fired vertically upward)

g is acceleration of gravity

[tex]\displaystyle \sf H=\frac{29^2 \times sin(90 )^2}{2 \times 10}=42.05[/tex]

A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe very large accelerations.
Part A) What is the acceleration at the end of a test tubethat is 10 cm from the axis of rotation?
Part B) For comparison, what is the magnitude of theacceleration a test tube would experience if dropped from a heightof 1.0 m and stopped in a 1.0-ms-long encounter with a hardfloor?

Answers

Answer:

A)  a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²

Explanation:

Part A) The relation of the test tube is centripetal

               a_c = v² / r

the angular and linear variables are related

              v = w r

we substitute

               a_c = w² r

let's reduce the magnitudes to the SI system

              w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s

               r = 1 cm (1 m / 100 cm) = 0.10 m

let's calculate

              a_c = 418.88² 0.1

               a_c = 1.75 10⁴ m / s²

part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor

as part of rest the initial velocity is zero and on the floor the height is zero

                v² = v₀² - 2g (y- y₀)

                v² = 0 - 2 9.8 (0 + 1)

                v =√19.6

                v = -4.427 m / s

now let's look for the applied steel to stop the test tube

                v_f = v + a t

                0 = v + at

                a = -v / t

                a = 4.427 / 0.001

                a = 4.43 10³ m / s²

why do the stars rotate​

Answers

Answer:

Angular momentum

Explanation:

Stars are formed as a result of a collapse of a low-temperature cloud of gas and dust. During the colapse conservation of angular momentum causes any small net rotation of the cloud to increase thus forcing the material into rotating

In the “Elastic Collision" part of this activity, what happened to the momentum of the red cart after the collision? What happened to the momentum of the blue cart after the collision?​

Answers

Explanation:

Elastic collision between balls of equal mass viimis 1.5 mys 1.5m/s 1! mis ... Make a data table for the following: mass, velocity and momentum of each ball before ... Part 2 moving faster. ... Summary: Describe the main ideas learned in this activity regarding initial and ... Collision 2: Blue Cart Moving Slower than the Red Cart.

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PLS HELP URGENT I WILL MAKE BRAINLY AND LIKE FIVE STARS try box be1) Solve for m: 2m + 21 = 3Help please Sally agrees to roof a house for Bob.After doing his research,Bob chooses Sally based on her great reputation for being conscientious and doing good work.Bob knows little about roofing and stays away from all the noise involved.Sally provides her own tools for herself and other workers,sets her own schedule,and charges a flat rate of $10,000 to be paid when the job is completed.Sally hires Trudy,Glen,and Fred to help with the roofing.She pays them an hourly rate,supervises their work,provides them with tools and materials,and sets their schedules.Curious about what is going on there,Bob's friend Spencer walks by the house while the roofing is being done.Glen absentmindedly throws some old shingles off the roof and hits Spencer in the head,resulting in him going to the local emergency room and receiving a couple of stitches in his scalp.Spencer decides to sue all the roofers,Bob,and Sally for his hospital expenses and for pain and suffering.Which of the following is the most likely characterization of Trudy,Glen,and Fred in relation to Sally?A) They are both employees and independent contractors.B) They are employees.C) They are independent contractors.D) They are undisclosed principals.E) They are both employees and disclosed principals. Potential energy is related to the speed of an object.True or False I need an answer to this problem 1) What sort of characterization technique is used in the fifth paragraphof this passage to describe Buddy?A) descriptionB) dialogueC) generalizationD) illustration What percent of 29 is 99? What were some of the noble strategies that the German army used during World War I, were they successful or not? The mean number of people per day visiting an art show in July was 120. If 30 more people each day visited the museum in August, what was the mean number of people per day visiting in August?A. 620B. 150C. 650D. 120 Helpp plzzz I will mark brainliestttt How do the four fundamental forces differ Find the equation of the line passing through the given points, (1,5) and (2, 7). Whichformula should you use first? Which of the following would most likely be a valid informational text ? A an encyclopedia B a blog C a novel What happened to Alexander's armies on the march home?many of the soldiers decided to settle in persiathousands of soldiers died from heat in the desertthey fought unexpected battles against persiathe army and the cavalry fought with each other Need answer to this urgently Valley Mills Sports Center has a total of 318 footballs and basketballs. There are 76 more footballs for sale than basketballs.How many footballs are for sale?A. 121B. 176C. 197D. 242 JUST ANSWER RIGHT NOTHING ELSE 25 POINTS!!! plEase thank you IF YOU CAN DO THIS FOR ME IT WOULD REALLY HELP!!!THE QUESTION I CHOSE IS IN THE COMMENTS BELOW!!!Introduction: In your introduction, you will explain in complete sentences what you were trying to accomplish through the project. You will explain the question you were trying to answer, as well as "why" you selected that question.Methods: In this section, you need to explain the methods that you used in the data collection project. This explanation needs to include a description of the population, the sample, and the sampling methods. You also need to include the survey question in this section. You can include the survey question right in the text, or if you used a document to pass out your survey or online form, you can reference the document or the online form (provided the document or form is included in your report in some way whether through an appendix or separate document that is referenced in the Methods section).Data: In the data section, you will not only include your frequency table and graph, but you will also include a written description of the results. Since this is the "data" and not the "conclusion," just talk about the sample population in this section. Answer the question "What were the results of the survey?" in this section.Conclusion: Now you will have a written description of the generalizations that you made from looking at the data. This is where you would use language that applies the results to the larger population. You can use language like "On the basis of these findings." or "The results of this survey suggest." You should also include some mathematical examples of how the data applies to the larger population. How do key details in paragraph 5 through 7 help support the central idea of Flying with a tiger by Elana Kopel with 2 supporting details in the text. How did new technologies increase the numbers of casualties compared with previous wars