Explanation:
Turbines might cause noise and aesthetic pollution.
Although wind power plants have relatively little impact on the environment compared to conventional power plants, concern exists over the noise produced by the turbine blades and visual impacts to the landscape.
The inflexibility, variability, and relative unpredictability of wind power as a means for electricity production, are the most obvious barriers to an easy integration and widespread application of wind power." Thus, the uncertainty of the wind requires a system that is always available to replace all the electrical output created by the wind turbine system. In other words, it is too expensive to have wind turbines lying around that don't do anything.
Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.
Answer:
v = 4.233 m/s
Explanation:
By applying the rate of boiling from [tex]Q= mL_v[/tex];
the rate of the boiling can be described as:
[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]
The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:
[tex]P_oV_o = nRT[/tex] --- (1)
where;
n = number of moles;
[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]
Then; equation (1) can be rewritten as:
[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]
∴
[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]
Then:
[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]
making (v) the subject of the formula:
[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]
Given that:
[tex]\mathcal{P}[/tex] = 0.90 kW = 900 W
R(rate constant) = 8.314 J/mol.K
Temperature at 100° C = 373K
For water vapor:molar mass= 18.015 g/mol ≅ 0.0180 kg/mol
Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg
Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]
Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²
[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]
v = 4.233 m/s
Plz help don’t understand solve please
Which of these would have the most kinetic energy?
O A. a stormy ocean
O B. a running stream
O C. an icy lake
O D. a lake in summer
Answer:
A stormy ocean, having the most kinetic energy means it moves more and faster
Typical novae occur when (a) a red-giant star ejects a planetary nebula; (b) two neutron stars merge, forming a more massive neutron star; (c) an extremely massive star collapses, and also ejects its outer atmosphere; (d) matter accreted from a companion star unstably ignites on the surface of a white dwarf; or (e) a neutron star’s magnetic field becomes strong enough to produce two oppositely directed jets of rapidly moving particles.
Answer:
I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.
Track and field is an individual sport.
True or False?
Track and field is an individual sport. This statement is True.
What is Track and field ?Track and field is a sport which includes jumping, running, and throwing. it is also know as track and field athletics, or track. This sport is organized in a stadium in which there are running tracks, set up for high jump and long jump and field for throwing. Hence the name is track and field. In this sport different participant participate to get one winner from each game from each weight group. The International Association of Athletics Federations(IAAF) is the international governing body for track and field.
The two most prestigious international track and field competitions are the athletics competition at the Olympic Games and the World Athletics Championships. World Athletics, formerly known as the International Association of Athletics Federations (IAAF),
Hence Track and field is an individual sport.
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A ball of mass 8kg falls from rest from a height of 100m. Neglecting air resistance, calculate its total energy after falling a distance of 40m.
Answer:
Total energy, T= 4704 Joules
Explanation:
Given the following data;
Mass = 8kg
Initial height, h1 = 100m
Final height, h2 = 40 m
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the total energy, T;
T = mg(h1 - h2)
T = 8 * 9.8 * (100 - 40)
T = 78.4 * 60
Total energy, T= 4704 Joules
Describe the processes that take place inside the nucleus for the following decays; Beta- decay and Beta+ decay.
Answer:
Explanation:
(a) Electron Emission (Beta- decay):
When an unstable nucleus decays by the emission of Beta- particle, its charge number ‘Z’ increases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:
[tex]_zX^A\ -------->\ _{Z+1}Y^A\ +\ _{-1}e^0[/tex]
It is called ‘Negative Beta Decay’. It is more common than alpha decay.
Example:
[tex]_6C^{14}\ -------->\ _{7}N^{14}\ +\ _{-1}e^0[/tex]
Note:
There are no electrons in a nucleus so, with the emission of a particle, one of the neutrons is converted to a proton and an electron.
[tex]_0n^1\ --------->\ _1P^1\ +\ _{-1}e^0[/tex]
(b) Positron Emission (Beta+ decay):
When an unstable nucleus decays by the emission of the positron, its charge number ‘Z’ decreases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:
[tex]_zX^A\ -------->\ _{Z-1}Y^A\ +\ _{+1}e^0[/tex]
Examples:
[tex]_{15}P^{30}\ -------->\ _{14}Si^{30}\ +\ _{+1}e^0[/tex]
Note:
Inside the nucleus, only a proton can be transformed into a neutron with the emission of a positron (anti-particle of electron)
[tex]_1P^1\ -------->\ _0n^1\ +\ _{+1}e^0[/tex]
A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?
Answer:
[tex]0.01\ \text{A}[/tex]
[tex]0.0015\ \text{C}[/tex]
[tex]0.0608\ \text{s}[/tex]
Explanation:
[tex]V_0[/tex] = Voltage = 1.5 V
[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]
[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]
Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].
Charge is given by
[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]
The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].
Voltage is given by
[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]
Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].
Please help with all three questions
Answer:
The correct answer is D C A
PLEASE HELP ME WITH THIS ONE QUESTION
A cylindrical copper wire has a resistance of 10 Ω across a 1-meter length. The resistivity of copper is 1.7 x 10^-8 Ω-m. What is the cross-sectional area of the wire?
The cross-sectional area of the cylindrical copper wire is 1.7 x 10⁻⁹ m².
What is meant by resistivity ?Resistivity is defined as the amount of electrical resistance of a conductor, per unit cross-sectional area and unit length.
Here,
Resistance of the wire, R = 10 Ω
Length of the wire, l = 1 m
Resistivity of the wire, ρ = 1.7 x 10⁻⁸ Ωm
The expression for the resistivity of a conductor is given as,
ρ = RA/l
where A is the cross-sectional area of the conductor.
Therefore, the area of cross-section of the copper wire,
A = ρl/R
A = 1.7 x 10⁻⁸ x 1/10
A = 1.7 x 10⁻⁹ m²
Hence,
The cross-sectional area of the cylindrical copper wire is 1.7 x 10⁻⁹ m².
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The temperatures of one northeastern state range from 105° F in the summer to -25°F in the winter. Express this temperature range in degrees Celsius and in kelvins. *
Farenheit is an interesting unit so the conversions get a bit weird.
To convert from Farenheit to Celcius you follow this formula:
T(°C) = (T(°F) - 32) × 5/9
It is also easier to convert to Celcius to Kelvin shown in this formula:
T(K) = T(°C) + 273.15
To Answer your question:
105° F = 40.5°C
-25° F = -31.7°C
105° F = 313.65K
-25° F = 241.45K
write the formula of mechanical advantage
Answer:
the formula of mechanical advantage is
MA = load / effort
VR = effort distance / load distance
hope it is helpful to you
PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.
Please select the best answer from the choices provided
T
F
Help pls. Edge 2021- Motion in space
Collaboration is critical to successful product design, and with Solid Edge, OEMs and suppliers can improve and manage collaboration across design teams, regardless of location. By reducing design revisions and communication delays, our customers enjoy quicker time-to-market and increased profitability.
23. Lunar Gravity Compare the force holding a
10.0-kg rock on Earth and on the Moon. The
gravitational field on the Moon is 1.6 N/kg.
Explanation:
Given
mass of the rock is 10 kg
Force requires to hold the rock is equal to its weight
Weight is given by the product of mass and acceleration due to gravity
Weight on the earth surface
[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]
Weight on the moon surface
[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]
So, the force holding the rock on earth is approximately 6 times the force on the moon.
A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?
Answer:
law of Action and Reaction F = 2250 N
Explanation:
The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction
F = 2250 N
directed from trailer to tractor
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.854 rad/s2.
(a) What is the moment of inertia of the wheel?
kg · m2
(b) What is the mass of the wheel?
kg
(c) If the wheel starts from rest, what is its angular velocity after 5.80 s have elapsed, assuming the force is acting during that time?
rad/s
Answer:
c
Explanation:
units c mark me brainless k
URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.
Answer:
A
Explanation:
because the speed divide by the frequency is equal to the wavelength(in meters)
5×10² m
You have a well-trained athlete (although not specifically a track athlete) come to the lab to perform a Wingate anaerobic test (WAnT). The subject is a 24-year-old male. He is 89.2kg, and 1.85 m tall. His Resting HR is 47 bpm, and his BMI is ~26.The participant does a warm-up on the cycle ergometer to prepare for the test. You are getting the weights ready to be applied to the flywheel. How much resistance will you use (in kg)
Answer:
6.69 kg
Explanation:
Given that:
The mass of the athlete = 89.2 kg
Height = 1.85 m
Resting HR = 47 bpm
BMI = ~26
The essence of the Wingate anaerobic test is to evaluate and access how much energy is released by phosphagen breakdown and anaerobic glycolysis. By applying a fixed amount of weight to that same cycle's weight tray, tension is added to the flywheel. The flywheel resistance is usually set at 0.075 kg per kilogram of body weight.
For athlete sprinters, the resistance is usually set at 1.0 kg which is then multiplied by the body mass up to 1.3 kg
Hence, the amount of the resistance applied for the athlete = (0.075 × 89.2)kg
= 6.69 kg
Electric field inside a charged rubber balloon is maximum or zero?
Light of wavelength 520 nm passes through two narrow slits 0.66 mm apart. The screen is 1.60 m away. A second source of unknown wavelength produces its second-order fringe 1.23 mm closer to the central maximum than the 520 nm light. What is the wavelength of the unknown light
Answer:
λ = 266 nm
Explanation:
In this case, we need to determine first the separation of the second fringe from the central maximum. We can determine that with the following expression:
d sinθ = mλ (1)
However, as the slits are very narrow, we can assume that sin θ ≈ θ and so θ = x/l
Replacing this in (1) we have:
d(x/l) = mλ
and solving for x:
x = mλl / d (2)
Where:
x: separation of the 2nd fringe from the central maximum
m: order of the fringe
λ: wavelength of light
l: distance of the screen
d: distance between the slits
All the units must be in meters (m), so we can convert the units first or during the resolution. In this case, we'll do it in the resolution. Replacing the given data, we have:
x = 2 * (520 nm * 1m/10⁻⁹ nm) * 1.6 m / (0.66 mm * 1m/1000 mm)
x = 0.00252 m or just 2.52 mm
With this value, we can compute or determine the separation of the 2nd order fringe of the unknown light in the central maximum:
x₂ = 2.52 - 1.23 = 1.29 mm or 0.00129 m
Now, using (2) we can solve for λ:
λ = dx / ml (3)
Replacing we have:
λ = (0.00129 * 0.0066) / (2 * 1.6)
λ = 2.66x10⁻⁷ m or simply 266 nmHope this helps
How does energy change from kinetic to potential?
Answer:
A: An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).
Explanation:
what is acceleration?
Answer:
the rate of change of velocity per unit of time.
Answer:
accelerate is rate of chang of velocity
Convert 0.00553s to cs
Answer: 0.553
Explanation:
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
PLEASE HELP ME WITH THOSE TWO QUESTIONS
A 122 Ohm, 232 Ohm, and 500 Ohm resistors are all connected in series with a 12 V battery. What is the current flowing through them?
A 100 Ohm, 200 Ohm, and 300 Ohm resistor are all connected in series to a 12 V battery. What is the potential difference drop across the 100 Ohm resistor?
Answer:
(a) 0.014 A
(b) 2 V
Explanation:
(a) Applying
V = IR'...................... Equation 1
Where V = Voltge, I = current, R = total resistance.
make I the subject of the equation
I = V/R'................... Equation 2
From the question,
Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms
Substitute these values into equation 2
I = 12/854
I = 0.014 A
(b) Applying
V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3
Where V' = Voltage across the 100 ohms resistor.
From the question,
V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.
Substitute these values into equation 3
V' = (12×100)/(100+200+300)
V' = 1200/600
V' = 2 V
True or false? When two objects interact, both force and motion are caused.
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do
Answer:
1568 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 80 Kg
Distance (d) = 5 m
Coefficient of kinetic friction (μ) = 0.4
Workdone (Wd) =?
Next, we shall determine the normal reaction. This can be obtained as follow:
Mass (m) = 80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?
N = mg
N = 80 × 9.8
N = 784 N
Next, we shall determine force of friction. This can be obtained as follow:
Coefficient of kinetic friction (μ) = 0.4
Normal reaction (N) = 784 N
Force of friction (F) =?
F = μN
F = 0.4 × 784
F = 313.6 N
Finally, we shall determine the work done. This can be obtained as follow:
Distance (d) = 5 m
Force of friction (F) = 313.6 N
Workdone (Wd) =?
Wd = F × d
Wd = 313.6 × 5
Wd = 1568 J
Thus, the workdone is 1568 J
Two people are carrying a uniform 704.0 N log through the forest. Bubba is 2.2 m from one end of the log (x), and his partner is 0.9 m from the other end (y). The log is 6.2 m long (z). What weight is Bubba supporting
Answer:
F₁ = 499.61 N , this is the force that Bubba support
Explanation:
The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation
let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive
Let's write the expression for the translational equilibrium
subscript 1 is for Bubba's mass and subscript 2 for his partner
F₁ + F₂ -W = 0
F₁ + F₂ = W
the expression for rotational equilibrium
∑ τ = 0
F₁ 2.2 + F₂ (6.2-0.9) - W 6.2/2 = 0
2.2 F1 + 5.3 F2 = 3.1 W
let's write our system of equations
F₁ + F₂ = W
2.2 F₁ + 5.3 F₂ = 3.1 W
we solve for F₁ in the first equation and substitute in the second
F₁ = W-F₂
2.2 (W- F₂) + 5.3 F₂ = 3.1 W
F₂ ( -2.2 +5.3) = W (3.1 - 2.2)
F₂ = 704 0.9 / 3.1
F₂ = 204.39 N
This is the force that the partner supports
we look for F1
F₁ = W-F₂
F₁ = 704 - 204.39
F₁ = 499.61 N
This is the force that Bubba support
HELPPPPPP!!!! Jupiter has a gravity that is 2.4 times that of Earth. A person has a mass of 60kg. What is the mass of this person on Jupiter?
60 kg
144 kg
600N
1440N
60
because mass of an object never change
but weight can change for example if it's
mass is 60kg 5he wieght will be 60kg * 9.8m/s²
=588N