What are the coordinates of the orthocenter of triangLe ABC with the vertices at A(1,2), B(1,6), and C(5,6)?
Answers
Orthocenter is the intersection of all the three altitudes of a triangle. The location of orthocenter depends on the type of triangle. If it is acute, it will lie within the triangle. If it is obtuse, it will lie outside the triangle. If it is right, it will occur at the vertex of the triangle.
For us to know, let's plot this triangle first in a graph.
As we can see in the plotted triangle above, the triangle is a right triangle and its vertex is at B(1, 6) therefore, the orthocenter of this triangle is located at (1, 6) as well.
Related Questions
3. Solve for the intersection of the two properties (two variable systems of equations using thecost and the Square Footage as the variables)a. Condo: $2.2 million / 1946 sq feetb. House : $.3 million / 4681 sq feet
Answers
Part A
Condo: $2.2 million / 1946 sq feet
Let
y ----> total cost in dollars
x ---> Square Footage
the equation is of the form
y=kx
where
k is the constant of proportionality
k=y/x
k=2,200,000/1,946=$1,130.52 per square footage
therefore
the equation for the total cost of a Condo is
y=1,130.52xPart B
House : $.3 million / 4681 sq feet
Let
y ----> total cost in dollars
x ---> Square Footage
the equation is of the form
y=kx
where
k is the constant of proportionality
k=y/x
k=300,000/4,681=$64.09 per Square Footage
therefore
the equation for the total cost of a house is
y=64.09x11 more than 4 times a number is 35. What is the equation and what is the solution?
Answers
Answer :
equation = 4x + 11 = 35
x = 6
Let the number be x
11 more than 4 times a number can be written mathematically
more than means addition
Since, the number is x
Therefore, 4 * x + 11 = 35
4x + 11 = 35
The equation is 4x + 11 = 35
To find x, collect the like terms
4x = 35 - 11
4x = 24
Divide both sides by 4
4x/4 = 24/4
x = 6
Therefore, the number is 6
what is the volume of the first container the bottom is 6inch and the height is 8inch
Answers
First: 226.19 in³
Second: 176.71 in³
1) Considering that these containers are cylinders we can find the volume by using this formula:
[tex]\begin{gathered} V_{\text{cylinder}}=\pi\cdot r^2\cdot h \\ \end{gathered}[/tex]2) Plugging the red one's data. Considering that 6, and 5 inches refer to the Diameter, then D=2r R= D/2 then the radi of those are
[tex]\begin{gathered} V_{\text{RED}}=\pi\cdot r^2\cdot h \\ V_{\operatorname{Re}d}=\pi\cdot(3)^2\cdot8 \\ V_{\text{red}}=72\pi\text{ }\approx226.19in^3 \\ \\ V_{\text{BLACK}}=\pi\cdot(\frac{5}{2})^2\cdot9 \\ V_{\text{BLACK}}=\frac{225}{4}\pi\text{ in³ }\approx176.71in^{^{3}} \end{gathered}[/tex]3) Hence, the answer is The Volume of the First container is approximately 226.19 in ³ and the Second one is approximately 176.71 in³
additional information is needed to prove that the triangles below are congruent select all options that would provide enough information to prove the triangles are congruent
Answers
we need that
AC=BD
CD=AB
with only these rwo conditions the triangles are congruent by SAS
because
the angle
is given
In the election for class president. Sophie received 72 of the 160 votes. What precent of the votes did she receive?
Answers
Total number of votes Sophie received = 72
Total number of votes cast = 160
Percentage of votes received by Sophie = (72/160) x 100
= 45%
Therefore, Sophie received 45% of the total votes.
A tank is being filled with a liquid. L (t), given below, is the amount of liquid in liters in the tank after t minutes.L (t) = 1.25t + 73Complete the following statements.
Answers
To find (L(t))^-1, we replace t by [L(t)]^-1 and L(t) by t in the expression L(t) = 1.25t + 73
With this, we got: t = 1.25*(L(t))^-1 + 73, which implies [L(t)]^-1 = (t - 73)/1.25
B) If x = L(t), we got [L(x)]^-1 = (x - 73)/1.25 = (L(t) - 73)/1.25 = [(1.25t + 73) - 73]/1.25 = t
A) Therefore, [L(x)]^-1 is the the amount of time (in minutes) it takes to have x liter os liquid
C) And finally, if t = 125 we got: [L(125)]^-1 = (125 - 73)/1.25 = 41.6
solve this question:. x² = -169
Answers
ANSWER
[tex]x\text{ = 13i or 13}\sqrt{-1}[/tex]EXPLANATION
We want to solve the equation:
[tex]x^2\text{ = -169}[/tex]To do this we will find the square root of both sides:
[tex]\sqrt{x^2}\text{ = }\sqrt{-169}[/tex]Because we can't find the square root of a negative number, we have to split the number:
[tex]\begin{gathered} x\text{ = }\sqrt{-1\cdot\text{ 169}} \\ x\text{ = }\sqrt{-1\text{ }}\cdot\text{ }\sqrt{169} \\ x\text{ = }\sqrt{-1\text{ }}\cdot\text{ 13} \\ x\text{ = 13}\sqrt{-1}\text{ or better written as 13i} \end{gathered}[/tex]Note: i is referred to as unit complex number.
One tennis ball can holds 3 balls. Jenna filled 5 cans and had 1 ball left over.Which equation could we use to find n, the number of tennis balls?Choose 1 answer:1)3+5+1=n2)5 X 3+1=n3)n x 5=1+3
Answers
N = the number of tennis balls
5 cans
1 ball left over
N = 5 x 3 + 1
N = 16 tennis balls
1. How many hours is 3,500 minutes? (Remember your answer need to have the correct amount of significant figures and the correct units written).2. Two-Step Conversion:How many grams is 45.0 lbs? (Remember your answer need to have the correct amount of significant figures and the correct units written).(1 Kg = 2.2 lbs)3. Three-Step Conversion:How many cm is 4.0 mi? (Remember your answer need to have the correct amount of significant figures and the correct units written).(1 mi = 5280 ft, 1 in=2.54 cm) (hint: cm -> in -> ft -> mi)
Answers
We are to convert 3,500 minutes to hours. This is done as shown below:
[tex]\begin{gathered} 60minutes=1hour \\ 3,500minutes=x\cdot hour \\ We\text{ will proceed to solve by cross multiplying, we have:} \\ 60\times x=3,500\times1 \\ 60x=3,500 \\ \text{Make ''x'' the subject of equation, we have:} \\ \frac{60}{60}x=\frac{3,500}{60} \\ x=58.33333\approx58 \\ x=58hours(to\text{ significant figures)} \end{gathered}[/tex]A phone company offers two long-distance plans. The first charges a flatvalue of $5.00 per month plus $0.99 for each minute used, and thesecond charges $10.00 a month plus $0.79 for each minute used.If x represents the number of minutes used each month, which system ofequations represents the total amount of money, y, you would spend foreach long-distance plan?
Answers
The first phone company charges a flat monthly fee of $5 plus $0.99 per minute used. Let y = the total cost of the plan and x = the number of minutes used. Thus, the equation for this company is.
y = 0.99x + 5
The second company charges a flat monthly fee of $10 plus $0.79 per min
Simplify each of the fractions. If there is no answer, enter "undefined."A. 4/12B. 0/8C. 16/0
Answers
Let's simplify the given fractions.
A.) 4/12 ; Simplified value = 1/3
[tex]\frac{4}{12}\text{ = }\frac{\frac{4}{4}}{\frac{12}{4}}\text{ = }\frac{1}{3}[/tex]B.) 0/8 ; Simplified value = 0
[tex]\frac{0}{12}\text{ = 0}[/tex]C.) 16/0 ; Undefined.
[tex]\text{ A fraction with a denominator of zero (0) is undefined.}[/tex]Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage rate of increase or decrease. y = 980(1.08)
Answers
the change represent growth. And the rate of increase is 8%
Question 5 of 6Which values are equivalent to the fraction below? Check all that apply.11.В.A.31 1c.33OF 3-3
Answers
The question is given to be:
[tex]\frac{3^5}{3^8}[/tex]Applying the law of indices:
[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]Therefore, we have the expression to be:
[tex]\frac{3^5}{3^8}=3^{5-8}=3^{-3}[/tex]Recall the law of negative exponents:
[tex]a^{-m}=\frac{1}{a^m}[/tex]Therefore, the expression becomes:
[tex]3^{-3}=\frac{1}{3^3}=\frac{1}{3\times3\times3}=\frac{1}{27}[/tex]The expression is also equivalent to:
[tex](\frac{1}{3})^3[/tex]Since:
[tex](\frac{1}{3})^3=\frac{1^3}{3^3}=\frac{1}{27}[/tex]ANSWER
The correct options are OPTION C, OPTION E, and OPTION F.
log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x
Answers
The given equation is
[tex]\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}[/tex]hence
[tex]x=0\text{ or x=3}[/tex]But x cannot be zero so x=3
So the value of x is 3
h
A retailer needs to purchase 12 printers. The first printer costs $54, and each additional printer costs 5% less than the price of the previous printer, up to 15 printers. What is the total cost of 12 printers? $368.58 $496.41 $615.60 $618.30
Answers
Given that a retailer needs to purchase 12 printers, the first printer cost $54.
It is known that each additional printer costs 5% less than than the cost of the previous printer.
[tex]\text{Cost of first printer = \$54}[/tex]Cost of the second printer
The second printer costs 5% less than the first printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the second printer = }\frac{\text{5}}{100}\times54=2.7 \\ \text{Thus the price of the second printer =54-2.7=51.3} \end{gathered}[/tex]Cost of the third printer
The third printer costs 5% less than the second printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the third printer = }\frac{\text{5}}{100}\times51.3=2.565 \\ \text{Thus the price of the third printer =51.3-2.565=}48.735 \end{gathered}[/tex]Cost of the fourth printer
The fourth printer costs 5% less than the third printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the fourth printer = }\frac{\text{5}}{100}\times48.735=2.437 \\ \text{Thus the price of the fourth printer =48.735-2.437=}46.298 \end{gathered}[/tex]Cost of the fifth printer
The fifth printer costs 5% less than the fourth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the fifth printer = }\frac{\text{5}}{100}\times46.298=2.315 \\ \text{Thus the price of the fifth printer =46.298-2.315=}43.981 \end{gathered}[/tex]Cost of the sixth printer
The sixth printer costs 5% less than the fifth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the sixth printer = }\frac{\text{5}}{100}\times43.981=2.199 \\ \text{Thus the price of the sixth printer =43.981-2.199=}41.782 \end{gathered}[/tex]Cost of the seventh printer
The seventh printer costs 5% less than the sixth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the seventh printer = }\frac{\text{5}}{100}\times41.782=2.089 \\ \text{Thus, the price of the seventh printer =41.782-2.089=}39.693 \end{gathered}[/tex]Cost of the eighth printer
The eighth printer costs 5% less than the seventh printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the eighth printer = }\frac{\text{5}}{100}\times39.693=1.985 \\ \text{Thus, the price of the eighth printer =39.693-1.985=}37.708 \end{gathered}[/tex]Cost of the ninth printer
The ninth printer costs 5% less than the eighth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the ninth printer = }\frac{\text{5}}{100}\times37.708=1.885 \\ \text{Thus, the price of the ninth printer =37.708-1.885=}35.823 \end{gathered}[/tex]Cost of the tenth printer
The tenth printer costs 5% less than the ninth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the tenth printer = }\frac{\text{5}}{100}\times35.823=1.791 \\ \text{Thus, the price of the tenth printer =35.823-1.791=}34.032 \end{gathered}[/tex]Cost of the eleventh printer
The eleventh printer costs 5% less than the tenth printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the eleventh printer = }\frac{\text{5}}{100}\times34.032=1.702 \\ \text{Thus, the price of the eleventh printer =34.032-1.702=}32.33 \end{gathered}[/tex]Cost of the twelfth printer
The twelfth printer costs 5% less than the eleventh printer, we thus have
[tex]\begin{gathered} D\text{iscount price on the twelfth printer = }\frac{\text{5}}{100}\times32.33=1.617 \\ \text{Thus, the price of the twelfth printer =32.33-1.617=}30.713 \end{gathered}[/tex]Thus, the total cost of 12 printers is evaluated as
[tex]\begin{gathered} 54+51.3+48.735+46.298+43.981+41.782+39.693+37.708+35.823+34.032+32.33+30.713_{_{_{}}} \\ =496.4 \end{gathered}[/tex]Thus, the sum of twelve printers is $496.4
The second option is the correct answer.
what are they different types of triangles and how can you tell the difference. if you don’t understand the question this is kinda what i’m talking about
Answers
7)
This triangle has two congruent sides, therefore it is an isosceles triangle.
Also, it has all angles smaller than 90° (acute angles), therefore it is an acute triangle.
8)
All three sides with different lengths, so it's a scalene triangle.
One angle is a right angle (the third angle is equal 180-30-60=90°), so it's an right triangle.
9)
All three sides are congruent, so it's an equilateral triangle.
All three angles are acute, so it's an acute triangle.
10)
All three sides with different lengths, so it's a scalene triangle.
One angle is greater than 90° (obtuse angle), so it's an obtuse triangle
11)
This triangle has two congruent sides, therefore it is an isosceles triangle.
Since the two base angles are 40°, the third angle is equal 180-40-40=100°, therefore the triangle is obtuse.
12)
All three sides with different lengths, so it's a scalene triangle.
All three angles are acute, so it's an acute triangle.
A textbook store sold a combined total of 252 chemistry and physics textbooks in a week. The number of chemistry textbooks sold was 78 more than the number of physics textbooks sold. How many textbooks of each type were sold?Number of chemistry textbooks sold:Number of physics textbooks sold:
Answers
We need to find the number of textbooks of each type that were sold.
Let's call C the number of Chemistry books and P the number of Physics books that were sold.
Since the store sold a combined total of 252, we have:
[tex]C+P=252[/tex]Also, the number of chemistry textbooks sold was 78 more than the number of physics textbooks sold:
[tex]C=78+P[/tex]Then, in order to find the value of P, we can replace C with 78+P in the first equation. We obtain:
[tex]\begin{gathered} 78+P+P=252 \\ \\ 78+2P=252 \\ \\ 78+2P-78=252-78 \\ \\ 2P=174 \\ \\ \frac{2P}{2}=\frac{174}{2} \\ \\ P=87 \end{gathered}[/tex]Now, we can use the above result to find C:
[tex]\begin{gathered} C=78+87 \\ \\ C=165 \end{gathered}[/tex]Therefore, the answers are:
• Number of chemistry textbooks sold:, ,165
• Number of physics textbooks sold:, ,87
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1Illustrated: 0.2389The indicated z score is:
Answers
ANSWER:
-0.71
The indicated z score is -0.71STEP-BY-STEP EXPLANATION:
We can know the indicated value of z, with the help of the normal table that relates the z-score, as shown below (We must look for the value of 0.2389 in the table and the value that matches the value of z, is the corresponding value):
The indicated z score is -0.71
which expressions are equivalent to 3(2/3p + 3 - 1/3p - 5)
Answers
Let's simplify
open the bracket
[tex]2p\text{ + 9-p-15}[/tex]Rearrange
2p - p + 9 - 15
p - 6
The correct options are either the same values as this directly or options that will give the same values when simplified
They are;
p- 6
[tex]3(\frac{1}{3}p+\text{ 3-5)}[/tex]when you simplify this it becomes;
p - 6
[tex]3(\frac{1}{3}p-2)[/tex]when you simplify, it gives p - 6
To this function, does limit x approaching zero (without + or -) exist? Aside from that, is f(x) continuous at x=1?
Answers
Given:
[tex]f(x)=\begin{cases}{-\frac{1}{x},x<0} \\ {3,0\leq x<1} \\ {\sqrt{x}}+2,x\ge1\end{cases}[/tex]Required:
To find the limit exist if x approaching to 0.
Explanation:
As limit x approaching to 0,
[tex]\lim_{x\rightarrow0}f(x)=3[/tex]Therefore the limit exist.
[tex]\begin{gathered} \lim_{x\rightarrow1^{-1}}f(x)=\lim_{x\rightarrow1^{-1}}3 \\ \\ =3 \end{gathered}[/tex][tex]\begin{gathered} \lim_{x\rightarrow1^+}f(x)=\lim_{x\rightarrow1^+}\sqrt{x}+2 \\ \\ =\sqrt{1}+2 \\ \\ =1+2 \\ \\ =3 \end{gathered}[/tex]Find the area of the shaded region.15007 cmA ~[?] cm2Enter a decimal rounded to the nearest tenth.
Answers
Answer
Area of the shaded portion = 102.0 square cm
Explanation:
Radius is given as 7cm
Angle = 150 degrees
Area of shaded area = area of circle + area of triangle
Area of circle = pi x r^2
where pi = 3.14
radius = 7cm
Area of circle = 360 - 150/360 x pi x r^2
Area = 210/360 x 3.14 x 7^2
Area = 0.5833 x 3.14 x 49
Area = 89.75 square cm
Area of triangle = 2 * (1/2) * sin75 * 7 cos 75 x 7
Area of triangle = sin 75 x 7 x cos 75 x 7
sin 75 = 0.9659
cos 75 = 0.2588
Area = 0.9659 x 7 x 0.2588 x 7
Area = 12.25 square cm
Area of shaded portion = 89.75 + 12.25
Area of the shaded portion = 102.0 square cm
1. What are the x-intercepts ofy = 2x^2 – 3x-20?
Answers
The given equation is,
[tex]y=2x^2-3x-20[/tex]Put y=0 in the above equation and solve for x to find the x intercepts.
Putting y =0 in the above equation,
[tex]0=2x^2-3x-20\ldots\ldots(1)_{}[/tex]The above equation is in the form of a quadratic equation given by,
[tex]ax^2+bx+c=0[/tex]Comparing the equations, a=2, b=-3 and c=-20.
Now, using discriminant method solve equation (1) for x.
[tex]\begin{gathered} x=\frac{-(-3)\pm\sqrt[]{(-3)^2-4\times2\times(-20)}}{2\times2} \\ =\frac{3\pm\sqrt[]{9^{}+160}}{4} \\ =\frac{3\pm\sqrt[]{169}}{4} \\ =\frac{3\pm13}{4} \\ x=\frac{3+13}{4}\text{ or x=}\frac{3-13}{4} \\ x=\frac{16}{4}\text{ or x=}\frac{-10}{4} \\ x=4\text{ or x=}\frac{-5}{2} \end{gathered}[/tex]Therefore, the x intercepts of the graph of the given equation is x=4 or x=-5/2.
Please help me solve this im not really sure how:( I’ve been trying no luck
Answers
Solution:
Given the average score model;
[tex]f(t)=85-6\log_{10}(t+1)[/tex]On the original exam;
[tex]\begin{gathered} t=0 \\ \\ f(0)=85-6\log_{10}1 \\ \\ f(0)=85 \end{gathered}[/tex]His average score on the original exam is 85
(b) After one year;
[tex]\begin{gathered} t=12 \\ \\ f(12)=85-6\log_{10}(12+1) \\ \\ f(12)=78.3 \\ \\ f(12)\approx78 \end{gathered}[/tex]His average score after one year is 78
(c)
[tex]\begin{gathered} f(t)=80 \\ \\ 80=85-6\log_{10}(t+1) \\ \\ \frac{-5}{-6}=\log_{10}(t+1) \\ \\ t+1=10^{(\frac{5}{6})} \\ \\ t=6.81-1 \\ \\ t=5.81 \end{gathered}[/tex]the area of a square can be represented by the expression x10. Which monomial represents a side of the square.x^2x^5x^20x^100
Answers
The given expression is
[tex]x^{10}[/tex]The side of the square is the square root of the are
[tex]s=\sqrt[]{x^{10}}=x^{\frac{10}{2}}=x^5[/tex]Hence, the answer is B.Find the equation (in terms of x) of the line through the points (-4,3) and (3,1)y =
Answers
The Slope-Intercept Form of the equation of a line is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
So, given the points:
[tex]\begin{gathered} \mleft(-4,3\mright) \\ \mleft(3,1\mright) \end{gathered}[/tex]You can find the slope by using this formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, you can set up that.
[tex]\begin{gathered} y_2=3 \\ y_1=1 \\ \\ x_2=-4 \\ x_1=3 \end{gathered}[/tex]Then, substituting values into the formula and evaluating, you get:
[tex]m=\frac{3-1}{-4-3}=\frac{2}{-7}=-\frac{2}{7}[/tex]Now you can substitute the slope of the line and the coordinate of one of the points given in the exercise, into the equation
[tex]y=mx+b[/tex]Then, substituting the coordinates of the point:
[tex](3,1)[/tex]And then solving for "b", you get that this is:
[tex]\begin{gathered} 1=(-\frac{2}{7})(3)+b \\ \\ 1=-\frac{6}{7}+b \\ \\ 1+\frac{6}{7}=b \\ \\ b=\frac{13}{7} \end{gathered}[/tex]Finally, knowing "m" and "b", you can determine that the equation of this line (in terms of "x"), is:
[tex]\begin{gathered} y=mx+b \\ \\ y=-\frac{2}{7}x+\frac{13}{7} \end{gathered}[/tex]The answer is:
[tex]y=-\frac{2}{7}x+\frac{13}{7}[/tex]2. Which of the following shows the numbers listed from greatest to least? null. 65%, 0.3, 0.11 null, 0.11, 65% 0.3 null. 0.11.5.0.3, 65% % null. 65%, 0.11 0.3 I
Answers
The first option is the correct one.
THe numbers we have are:
65%
1/3
0.3
and 0.11
To solve this, let's convert them to decimal:
to convert from percentage to decimal we divide the percentage by 100:
65% ÷ 100 = 0.65
1/3 is
[tex]0.\bar{3}[/tex]Then, now it's easy to see tha t0.65 is the biggest, then it goes 0.3
Look at the steps and find the pattern.step 1step 2step 3How many dots are in the 5th step?dots
Answers
In step 1
You have 4 dots per vertical column and 4 columns
4+4+4+4=16
If you sum the dots you find 16 dots.
In step 2
You have 5 dots per vertical column and 5 columns
5+5+5+5+5=25 or 5 x 5=25 or 5^2=25
If you sum the dots you find 25 dots.
In step 3
You have 6 dots per vertical column and 6 columns
6+6+6+6+6+6=36 or 6 x 6=36 or 6^2=36
If you sum the dots you find 36 dots.
In step 4
You have 7 dots per vertical column and 7 columns
7+7+7+7+7+7+7=49 or 7 x 7=49 or 7^2=49
If you sum the dots you find 49 dots.
In step 5
You have 8 dots per vertical column and 8 columns
8+8+8+8+8+8+8+8=64 or 8 x 8=64 or 8^2=64
If you sum the dots you find 64 dots.
Answer 64 dots
Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distributionThe per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 108 pounds and a standard deviation of 37.9pounds. Random samples of size 17 are drawn from this population and the mean of each sample is determined.u(x) =. (Round to three decimal places as needed)Sketch a graph of the sampling distribution.
Answers
We have a population normally distributed with a mean of 108 pounds and a std deviation of 37.9 pounds.
The sample size is 17.
The sample mean is expected to be equal to the population mean, so it will be 108 pounds.
The standard error for this sample size can be calculated as:
[tex]\sigma_s=\frac{\sigma}{\sqrt[]{n}}=\frac{37.9}{\sqrt[]{17}}\approx9.192[/tex]Then, we have a sampling mean of 108 and a std. error of 9.192.
Most of the data (95%) should be within 2 std. error from the mean. This is between 90 and 126:
[tex]\begin{gathered} 108-2\cdot9.192\approx90 \\ 108+2\cdot9.192\approx126 \end{gathered}[/tex]Then, graph number C shows this condition: most of the data is within 90 and 126, with a mean of 108.
Answer:
μs = 108
σs = 9.192
Graph C is representing the sampling distribution.
Question 6Given the true/false statements are true (facts), select the best logical induction made from those statements:Betsy likes oranges. Jose does not like oranges. Benjamin likes oranges.A People only like orangesB) People do and do not like orangesPeople like apples and orangesD People like all fruit
Answers
The Solution:
Given the following statements:
Betsy likes oranges.
Jose does not like oranges.
Benjamin likes oranges.
It follows that:
People do and do not like oranges
Therefore, the correct answer is [option B]
.Hi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great dayHi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great dayHi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great dayHi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great dayHi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great dayThe problem is the number 6.I will send the picturePlease answer all parts of the question with a complete sentenceThanks very much and have a great day
Answers
so we need to find D
By using the Trignometry function for the diagram
opp = 3 Adj = 2
[tex]\begin{gathered} \tan \theta\text{ =}\frac{3}{2} \\ \tan \theta\text{ = 1.5} \\ \theta=tan^{-1}(1.5) \\ \theta\text{ = 56}.3^{\cdot} \\ \end{gathered}[/tex]QUESTION 2
To solve for AD
[tex]\begin{gathered} AD^2\text{ =}AE^2+DE^2 \\ AD^2=3^2+2^2 \\ AD^2\text{ = 9 + 4} \\ AD^2=13 \\ AD\text{ = }\sqrt[]{13}\text{ } \\ AD\text{ =3.6in} \end{gathered}[/tex]