Answer:
12, 48
The pattern is: Divide by 2, then multiply by 4
-9y > 9. Solve for the inequality
Answer:
-1
Step-by-step explanation:
make it equal to zero
-9y - 9 = 0
add 9 to both sides
-9y = 9
divide both sides by -9 to get y alone
y = 9/-9
simplify
y = -1
please help soon!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
its 63 you got it right
Step-by-step explanation:
Calculate the perimeter of the rectangle in centimeters.
Lenght= 14cm
Width= 8cm
In Smithville, there were 234 teachers in 1990 and 318 teachers in 2000. Find the percent of increase in the number of teachers in Smithville during this time period.
Answer:
35.90%
Step-by-step explanation:
First, subtract the new no with that of 1990
318-234= 84
percentage of increase will be given by;
84/234×100= 35.8974%
The length of a rectangle is four less than twice its width. If the perimeter of the rectangle is 76 units, what is its width?
a
13
b
14
c
20
d
26
e
28
Can somebody help me if you know what this is
Answer:-2,2.5,-7/3
Step-by-step explanation:
Solve for the value of y.
Based on the given parameters, the value of y in the figure is 13
How to determine the value of y?The measures of the angles are given as:
Angle 1 = 8y
Angle 2 = 6y - 2
The angles are supplementary angles
So. we have
8y + 6y - 2 = 180
Evaluate the like terms
14y =182
Divide both sides by 14
y = 13
Hence, the value of y in the figure is 13
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Janine is analyzing spending habits of students in her high school. She finds a mean monthly discretionary expense of $70 spent on having meals
out with friends. The standard deviation of a distribution is 5. What is the variance?
Answer:
Variance = 25
Step-by-step explanation:
I'm smart
Hi
The following set of four ordered pairs below defines the vertices, in counterclockwise order, of a quadrilateral (four-sided figure).
((-4, 1), (1, 2), (-1,6).(-6,5)}
Step 1 of 3: Find the slopes of the indicated sides of the quadrilateral. Simplify your answer.
Side connecting (-4,1) and (-6,5)
Side connecting (1, 2) and (-1,6)
G
7
a
Suba
The slope of the side connecting (-4,1) and (-6,5) = -2
The slope of the side connecting (1,2) and (-1,6) = -2
The slope of the segment joining two points (x₁, y₁) and (x₂, y₂) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
We have to find the slope of the side joining the points (x₁, y₁) = (-4,1) and (x₂, y₂) = (-6,5)
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{5-1}{-6--4}[/tex]
= 4/ -2
= -2
We have to find the slope of the side joining the points (x₁, y₁) = (1, 2) and (x₂, y₂) = (-1,6)
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{6-2}{-1-1}[/tex]
= 4/-2
= -2
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The cost of gas in England is 96.4 pound sterling/liter. How much is this in U.S. dollars/gallon? (3.875 litres = 1 gallon and 1.47 US$= 1 pound sterling)
The cost of gas in England is 96.4 pound sterling/liter is 549.1185 U.S. dollars/gallon
The cost of gas in England is 96.4 pound sterling/liter.
3.875 liters = 1 gallon
1 liter = 1/3.875 gallon
1.47 US$= 1 pound sterling
pound sterling / liter = 1.47/(1/3.875)) U.S. dollars/gallon
= (1.47)(3.875) U.S. dollars/gallon
96.4 pound sterling / liter = (96.4)(1.47)(3.875) U.S. dollars/gallon
= 549.1185 U.S. dollars/gallon
Sterling is the arena's oldest forex that is still in use and that has been in continuous use due to the fact that its inception.
it is presently the fourth maximum-traded currency in the forex market, after the USA dollar, the euro, and the Javanese yen.
collectively with the ones 3 currencies and Renminbi, it paperwork the basket of currencies which calculate the price of IMF unique drawing rights. As of mid-2021, sterling is likewise the fourth most-held reserve forex in international reserves.
these kinds of currencies are government-issued fiat currencies.
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[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\omega[/tex] is a 2020th root of unity, so [tex]\omega^{2020}=1[/tex] and we have a kind of reflection identity of [tex]\omega^{2020-n} = \omega^{-n}[/tex] for [tex]n\in\Bbb Z[/tex].
Let's evaluate the product first. Denote it by [tex]P_k[/tex]. We split the product where the [tex]j=k[/tex] factor would belong, and pull out powers of [tex]\omega^k[/tex].
[tex]\displaystyle P_k = \prod_{j=1, j\neq k} (\omega^k - \omega^j) \\\\ ~~~~ = \prod_{a=1}^{k-1} (\omega^k - \omega^a) \prod_{b=k+1}^{2019} (\omega^k - \omega^b) \\\\ ~~~~ = (\omega^k)^{k-1} \prod_{a=1}^{k-1} (1-\omega^{a-k}) \cdot (\omega^k)^{2019-k} \prod_{b=k+1}^{2019} (1 - \omega^{b-k}) \\\\ ~~~~ = (\omega^k)^{2018} \prod_{a=1}^{k-1} (1 - \omega^{-a}) \prod_{b=1}^{2019-k} (1 - \omega^b) \\\\ ~~~~ = \omega^{-2k} \prod_{a=1}^{k-1} (1-\omega^{-a}) \prod_{b=1}^{2019-k} (1-\omega^b)[/tex]
Now introduce some factors to "complete" the [tex]b[/tex]-product and have it contain 2019 factors.
[tex]\displaystyle P_k = \omega^{-2k} \prod_{a=1}^{k-1} (1-\omega^{-a}) \frac{\displaystyle \prod_{b=1}^{2019} (1 - \omega^b)}{\displaystyle \prod_{b=2020-k}^{2019} (1 - \omega^b)}[/tex]
It's relatively straightforward to show that if [tex]\zeta[/tex] is an [tex]n[/tex]-th root of unity, then
[tex]\displaystyle \sum_{m=1}^{n-1} (1-\zeta^m) = n[/tex]
which gives
[tex]\displaystyle P_k = 2020 \omega^{-2k} \frac{\displaystyle \prod_{a=1}^{k-1} (1-\omega^{-a})}{\displaystyle \prod_{b=2020-k}^{2019} (1 - \omega^b)}[/tex]
Shifting the index in the denominator and again using the reflection property eliminates all but one factor.
[tex]\displaystyle P_k = 2020 \omega^{-2k} \frac{\displaystyle \prod_{a=1}^{k-1} (1-\omega^{-a})}{\displaystyle \prod_{b=1}^k (1 - \omega^{-b})} \\\\ ~~~~ = \frac{2020 \omega^{-2k}}{1 - \omega^{-k}}[/tex]
Now evaluate the sum. We can exploit symmetry. Split the sum at the 1010th term, so that
[tex]\displaystyle - \sum_{k=1}^{2019} P_k = -2020 \left(\sum_{k=1}^{1009} \frac{\omega^{-2k}}{1 - \omega^{-k}} + \frac{\omega^{-2020}}{1-\omega^{-1010}} + \sum_{k=1011}^{2019} \frac{\omega^{-2k}}{1-\omega^{-k}}\right)[/tex]
The middle terms reduces to 1/2. Shifting the index in the second sum, we can condense it to
[tex]\displaystyle -\sum_{k=1}^{2019} P_k = -2020 \left(\frac12 + \sum_{k=1}^{1009} \left(\frac{\omega^{-2k}}{1-\omega^{-k}} + \frac{\omega^k}{1-\omega^k}\right)\right)[/tex]
Join the fractions.
[tex]\displaystyle \frac{\omega^{-2k}}{1-\omega^{-k}} + \frac{\omega^k}{1-\omega^k} = 1 - \frac{2-\omega^{2k}-\omega^{-2k}}{2-\omega^k-\omega^{-k}} = -(1+\omega^k + \omega^{-k})[/tex]
The remaining sums are trivial.
[tex]-\displaystyle \sum_{k=1}^{2019} P_k = -2020 \left(\frac12 - 1009 - \frac{1-\omega^{1010}}{1-\omega} - \frac{1-(-\omega)^{1010}}{1+\omega}\right) \\\\ ~~~~ = 2020\cdot1009 - 1010 \\\\ ~~~~ = (2000+20)(1000+9) - 1000 - 10 \\\\ ~~~~ = 2\cdot1000^2 + 37\cdot1000 + 170[/tex]
Taking this last result mod 1000, we find the last 3 digits to be 170.
Simplify the expression where possible. 1/(x^4)^-2
According to the solving the simplified value of the equation 1/(x^4)^-2 is
= x⁸.
What are the simplification rules?PEMDAS stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction and is the main rule for simplifying expressions.
Simplification seems to be the process of substituting a mathematical expression with a simpler, usually shorter counterpart.
What is the simplification method?Designers employ simplification to make designs more memorable and instantly recognizable in logos, emblems, posters, computer icons, as well as other design applications.
According to the given data:Given :[tex]\frac{1}{\left(x^4\right)^{-2}}[/tex]
On simplifying we get:
Use (aⁿ)ˣ = aⁿˣ
so we get:
[tex]\frac{1}{X^{(4)(-2)}}[/tex]
=[tex]\frac{1}{x^{-8}}[/tex]
Use a⁻ⁿ = 1/aⁿ
Now:
= [tex]\frac{1}{\frac{1}{x^8}}\\=x^8[/tex]
According to the solving the simplified value of the equation 1/(x^4)^-2 is
= x⁸
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solve y-3x=13 for y
Answer:
y=3x+13
Step-by-step explanation:
Simply add the 3x to the other side.
Answer: y = 13 + 3x
Step-by-step explanation:
you just add 3x to both sides of the equation !! sorry if it doesn’t help but you basically put it the other way around and put 3x on both sides
Question 4
Use the given sets to find An B.
Answer
AnB =
Correct
A = {1, 2, 3, 4, 5, 6, 7, 8, 9}
B = {2, 4, 6, 8, 10, 12}
Ta
A n B = {2,4,6,8}
The intersection of Sets :
The intersection of sets for two given sets is the set that contains all the elements that are common to both sets. The symbol for the intersection of sets is "∩''. For any two sets A and B, the intersection, A ∩ B (read as A intersection B) lists all the elements that are present in both sets, and are the common elements of A and B.
Intersections of sets have properties similar to the properties of numbers. The properties of the intersection of sets include the commutative law, associative law, the law of null set and universal set, and the idempotent law. The following table lists the properties of the intersection of sets.
Name of Property/Law Rule
Commutative Law A ∩ B = B ∩ A
Associative Law (A ∩ B) ∩ C = A ∩ (B ∩ C)
Law of ϕ and U ϕ ∩ A = ϕ , U ∩ A= A
Idempotent Law (A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
(A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
Important Notes:
(A ∩ B) is the set of all the elements that are common to both sets A and B.
If A ∩ B = ϕ, then A and B are called disjoint sets.
n(A ∩ B) = n(A) + n(B) - n(A ∪ B)
Given :
A = {1, 2, 3, 4, 5, 6, 7, 8, 9}
B = {2, 4, 6, 8, 10, 12}
Find :
A n B = {2,4,6,8}
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In which interval is the radical function f of x is equal to the square root of the quantity x squared minus 2 times x minus 24 end quantity increasing? HELP!!! PLEASE!!! ASAP!!!
Answer:
Step-by-step explanation: C
Devan borrowed $27. They then earned $33. After paying back what they owed, how much money does Devan have?(1 point)
Answer: Devon would have -6 dollars left
Step-by-step explanation:
2. 50 vehicles belong to an enterprise that has three departments, A, B and C. 6 vehicles are available for the use of all three departments, while 2 vehicles give service to neither of the departments. 24 vehicles are administrated by department B, although 16 of them are also used by the others departments. There are twice as many vehicles in department A as there are in department C. If equal numbers of vehicles are allocated when used by any two departments, find the number of vehicles administrated by each department.
The number of vehicle administered by department A only = 18
The number of vehicle administered by department B only = 8
The number of vehicle administered by department C only = 1
Given data
50 vehicles belong to an enterprise that has three departments, A, B and C
6 vehicles are available for the use of all three departments
2 vehicles give service to neither of the departments
24 vehicles are administrated by department B
16 of the 24 used by B are also used by the others departments
There are twice as many vehicles in department A as there are in department C.
equal numbers of vehicles are allocated when used by any two departments
How to find the number of vehicles administrated by each departmentnumber of vehicles on department A = 2 * number of vehicles in department C.
say A = 2C
B = 24
let x represent the number of vehicles used by any two departments
16 of the 24 used by B are also used by the others departments and equal numbers of vehicles are allocated when used by any two departments hence
16 = 2x + 6
2x = 16 - 6
2x = 10
x = 5
B only = 24 - 2x - 6 = 18 - 2x = 18 - 10 = 8
A only = A - 2x - 6 = 2C - 10 - 6 = 2C - 16
C only = C - 2x - 6 = C - 10 - 6 = C - 16
adding up all the vehicles as allocated to get to the sum of 50
24 - 2x - 6 + A - 2x - 6 + C - 2x - 6 + x + x + x + 6 + 2 = 50
24 - 6 - 6 - 6 + 6 + 2 - 2x - 2x - 2x + x + x + x + A + C = 50
24 - 10 - 6x + 3x + 2C + C = 50
14 - 3x + 3C = 50
3C - 3X = 50 - 14
3C - 3(5) = 36
3C - 15 = 36
3C = 36 + 15 = 51
C = 17
C only
C only = C - 16
C only = 17 - 16
C only = 1
A only
A only = 2C - 16
A only = 2 * 17 - 16 = 34 - 16 = 18
The number of vehicle administered by department A only = 18
The number of vehicle administered by department B only = 8
The number of vehicle administered by department C only = 1
The number of vehicle administered by department A = 2C = 34
The number of vehicle administered by department B = 24
The number of vehicle administered by department C = 17
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if AC=38 3/4,AB=6x, BC=8x+1/4
what’s the value of x?
Applying the segment addition postulate:
x = 2.75
AB = 6x = 6(2.75) = 16.5 units
BC = 8x + 1/4 = 8(2.75) + 1/4 = 22.25 units.
What is the Segment Addition Postulate?Based on the segment addition postulate, since B lies between points A and C on a line segment, then:
AB + BC = AC
AC = 38 3/4
AB = 6x
BC = 8x + 1/4
Substitute
6x + 8x + 1/4 = 38 3/4 [segment addition postulate]
14x + 1/4 = 155/4
14x = 155/4 - 1/4
14x = (155 - 1)/4
14x = 154/4
14x × 4 = 154
56x = 154
x = 154/56
x = 2.75
AB = 6x = 6(2.75) = 16.5 units
BC = 8x + 1/4 = 8(2.75) + 1/4 = 22.25 units.
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There are 5 people from Arizona (A), 7 people from California (C), and 3 people from Nevada (N)
equally qualified for a job. There are three job openings for three different people. What is the probability that not all three people are from Arizona
Answer
.9780
Step-by-step explanation:
Probability, not all 3 people are from Arizona
Arizona Equals 1- 2/91 = 89/91 = .9780
Probability is .9780
PLEASE HELP GIVING BRAINLIEST IF IT IS NOT VALID THEN I WILL REPORT AND BAN THANKYOU
Cary is 9 years older then Dan. In 7 years the sum of their ages will be 93. Find the age of each man now
Cary's and Dan's present ages are 44 and 35 years respectively.
Let the Dan's present age be x years.
According to the given question.
Cary is 9 years older then Dan.
And, after seven years the sum of their ages will be 93.
So, from the given conditon we can say that
cary's age = 9 + x
And after seven years, sum of the ages of Cary and Dan
9 + x + 7 + x + 7 = 93
⇒ 23 + 2x = 93
⇒ 2x = 93 - 23
⇒ 2x = 70
⇒ x = 70/2
⇒ x = 35
⇒ Dan's present age is 35 years.
Therefore, Cary's age = 35 + 9 = 44 years.
Hence, Cary's and Dan's present ages are 44 and 35 years respectively.
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Shawn has 2 3/4 cups of berries. He uses 5/8 cups of berries to make a smoothie. He then uses 1/2 cup for a fruit salad.
Part A: How many cups of berries did he use?
Select the correct answer.
Function bis nonlinear, and b(9) = 4. Which equation could represent function b?
The nonlinear- function which represents b(9)=4 is given by b(x)=72/x - 4 .
In mathematics and physics, a nonlinear system is one in which the change in the output is not proportional to the change in the input. Engineers, biologists, physicists, mathematicians, and many other scientists are interested in nonlinear problems since the majority of systems are inherently nonlinear.
Nonlinear function graphs don't resemble lines at all. It contains the formula f(x) = ax + b. Its equation can take any form, with the exception of f(x) = ax + b. The slope of the curve is the same between any two points. The point pairs on the graph do not all have equal slopes.
Of all the given options: the only equations which imply that b(9)=4 are :
i) b(x)=72/x - 4 and (iv) b(x)=4
Of this two options only the first option is non-linear.
Hence the required option is b(x)=72/x - 4 .
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Disclaimer:
The missing options are:
i) b(x) = 72/x - 4
ii) b(x) = √x + 7
iii)b(x) = 2x+1
iv) b(x) = 4
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Pentagon FGHJK is similar to pentagon MPQST. K What is the value of x? A 16 cm B Not here C) 12.5 cm 18 cm G S 12 cm M P
Answer:
I think it's a (16cm) ....
Which of the following equations is equivalent to
2x + y = 10
Ay = -2x - 10
By = 2x + 10
y=-2x + 10
y = -10x - 2
Answer:
y = -2x + 10
Step-by-step explanation:
Which equation represents a line which is parallel to the line
y = −3/5x − 7?
-
3x + 5y = 15
5x + 3y = 12
3y - 5x = 6
3x - 5y = -30
Submit Answer
Answer:
3x+5y=15
Step-by-step explanation:
3x+5y=15
5y=-3x-15
y=-3/5x-3
Because it has the same slope and a different y-intercept, it is parallel because the lines won't ever touch.
Just need help on one answer I’ll give Brainly!
Answer:
Q1 = 8
Hope this helps with your question :)
The line at the start of the "box" is Q1, the middle line in the "box" is the median also called Q2, and the last line of the "box" is Q3.
Community Gym charges a $60 membership fee and a $65 monthly fee. Workout Gym charges a $190 membership fee and a $55 monthly fee. After how many months will the total amount of money paid to both gyms be the same? What will the amount
Answer:
13 months$905Step-by-step explanation:
You want the cost and the number of months of membership such that the cost of both gyms is the same.
Total costThe total cost of x months of membership at each gym will be the sum of its initial fee and the product of the monthly fee and the number of months.
SetupThe cost at Community Gym is ...
c = 60 + 65x
The cost at Workout Gym is ...
w = 190 +55x
These costs will be the same when ...
c = w
60 +65x = 190 +55x
SolutionSubtracting 60+55x from both sides of the equation leaves ...
10x = 130
x = 13 . . . . . . divide by 10
The cost will be the same after 13 months.
That cost will be ...
60 +65(13) = 60 +845 = 905
The amount paid at each gym after 13 months will be $905.
Thomas bought 12 glass and plastic cups from
the store. Glass cups cost $3.25 and plastic
cups cost $2.75. Thomas spent a total of
$36.00. How many glass cups (g) and how
many plastic cups (p) did he buy?
g+p=12
3.25g +2.75p = 36
[?] glass cups [] plastic cups
Thomas bought 6 glass cups and 6 plastic cups
How to calculate the number of glass and plastic cups ?
Thomas bought 12 glass and plastic cups from the store
Glass cups costs $3.25
Plastic cups cost $2.75
He spent a total of $36
Let g represent the number of glass cups and p represent the number of plastic cups
g + p= 12.........equation 1
3.25g + 2.75p= 36..........equation 2
From equation 1
g+p= 12
g= 12-p2
Substitute 12-p for g in equation 2
3.25(12-p)+2.75p = 36
39-3.25p+2.75p= 36
39-0.5p= 36
-0.5p= 36-39
-0.5p= -3
p= -3/-0.5
p= 6
Substitute 6 for p in equation 1
g + 6= 12
g= 12-6
g= 6
Hence there are 6 glass cups and 6 plastic cups
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In triangle ABC, the size of angle B is 3 times the size of
angle A, and the size of angle C is 16° less than 6 times
the size of angle A.
Find the size of the angles.
Step-by-step explanation:
Here,
angle B = 3 x angle A
angle C = 6 x angle A - 16
now, for a triangle,
angle A + angle B + angle C = 180
or, angle A + 3 x angle A + 6 x angle A - 16 = 180
or, 10 x angle A = 196
so, angle A = 19.6 degrees
angle B = 3 x 19.6 = 58.8 degrees
angle C = 6 x 19.6 - 16 = 101.6 degrees