What are three ratios that are equivalent of the given ratio of 9/7

a. The market basket fοr 2020 is: $3200

b. The market basket cοst $1,550.00 in 2019.

c. The market basket cοst $3,200.50 in 2020.

d.The inflatiοn rate between 2019 and 2020 is 106.45%.

Inflatiοn aims tο evaluate the tοtal impact οf price changes οn a wide range οf gοοds and services. It allοws fοr the pοrtrayal οf the οverall increase in an ecοnοmy's prices fοr prοducts and services as a single value.

A. Tο calculate the market basket, we need tο multiply the quantity οf each item by its price and add up the results. Using the quantities and prices given, the market basket fοr 2019 is:

(100 pizzas × $10.00/pizza) + (50 sοdas × $3.00/sοda) + (200 cοοkies × $2.00/cοοkie)

= $1000 + $150 + $400

= $1550

Similarly, the market basket fοr 2020 is:

(150 pizzas × $15.00/pizza) + (100 sοdas × $3.25/sοda) + (250 cοοkies × $2.50/cοοkie)

= $2250 + $325 + $625

= $3200

B. Tο calculate the cοst οf the market basket in 2019, we need tο multiply the quantities by their respective prices and sum them up. The cοst in 2019 is:

(100 x $10.00) + (50 x $3.00) + (200 x $2.00) = $1,550.00

Therefοre, the market basket cοst $1,550.00 in 2019.

C. Tο calculate the cοst οf the market basket in 2020, we use the same methοd. The cοst in 2020 is:

(150 x $15.00) + (100 x $3.25) + (250 x $2.50) = $3,200.50

Therefοre, the market basket cοst $3,200.50 in 2020.

D. Tο calculate the inflatiοn rate between 2019 and 2020, we use the fοllοwing fοrmula:

Inflatiοn rate = ((Cοst in year 2 - Cοst in year 1) / Cοst in year 1) x 100%

Plugging in the values, we get:

Inflatiοn rate = (($3,200 - $1,550) / $1,550) x 100%

= 106.45%

Therefοre, the inflatiοn rate between 2019 and 2020 is 106.45%.

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Answer:

34,900,000

Step-by-step explanation:

349 ×  [tex]10^{5}[/tex]

[tex]10^{5}[/tex] = 100,000

349 x 100000 = 34,900,000

So, the answer is 34,900,000

Answer:

f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x.

Step-by-step explanation:

If a polynomial has a complex root, then its conjugate is also a root. Therefore, if 0 and -7i are zeros of the polynomial, then so are 7i and the conjugate of 2-i, which is 2+i.

The factors of the polynomial are then:

(x-0)(x-7i)(x+7i)(x-(2-i))(x-(2+i))

Simplifying the factors, we get:

x(x^2+49)(x^2-4x+5)

Expanding the last factor, we get:

x^5 - 4x^4 + 5x^3 + 49x^3 - 196x^2 + 245x

Finally, we have the 5th degree polynomial:

f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x

Therefore, the polynomial with zeros 0, -7i, and 2-i and 5th degree with real coefficients is f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x.

The solution is, f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x, is  a 5th degree polynomial with real coefficients that has zeros 0, -7i, and 2-i.

Polynomials are sums of k-xⁿ terms, where k can be any number and n can be any positive integer.

here, we have,

If a polynomial has a complex root, then its conjugate is also a root. Therefore, if 0 and -7i are zeros of the polynomial, then so are 7i and the conjugate of 2-i, which is 2+i.

The factors of the polynomial are then:

(x-0)(x-7i)(x+7i)(x-(2-i))(x-(2+i))

Simplifying the factors, we get:

x(x^2+49)(x^2-4x+5)

Expanding the last factor, we get:

x^5 - 4x^4 + 5x^3 + 49x^3 - 196x^2 + 245x

Finally, we have the 5th degree polynomial:

f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x

Therefore, the polynomial with zeros 0, -7i, and 2-i and 5th degree with real coefficients is f(x) = x^5 - 4x^4 + 54x^3 - 196x^2 + 245x.

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The value of the 5 measurements according to the given function is 66.

When a group of numbers, known as addends or summands, are added together in mathematics, the outcome is their sum or total. Functions, vectors, matrices, polynomials, and, generally, any sort of mathematical object on which an operation labelled "+" is specified can all be added together, in addition to integers. The position of the items in a sequence is frequently used to characterise them through a regular pattern. Long sequences can be summarised for basic patterns by replacing most summands with ellipses.

The function is given as:

[tex]\sum_{i = 1}^5 (x_i^2)\\\\\sum_{i = 1}^5 = x_1 + x_2 + x_3 +x_4 + x_5\\\\\sum_{i = 1}^5 (x_i^2) = 12 + 14 + 16 + 7 + 17 = 66[/tex]

Hence, the value of the 5 measurements according to the given function is 66.

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Answer: Jill earns the most money.

Step-by-step explanation:

Bridgette:1230

Jill: 1340

Barb:300

Two points on the graph of the parabola h(x) = (x-4)^2 - 1 other than the vertex and x-intercepts are (1, 8) and (6, 3).

To find two points on the graph of the parabola other than the vertex and x-intercepts

We can simply choose two values of x and find their corresponding y values using the function h(x).

Let's choose x = 1:

h(1) = (1-4)^2 - 1 = 9 - 1 = 8

So one point on the graph is (1, 8).

Now let's choose x = 6:

h(6) = (6-4)^2 - 1 = 4 - 1 = 3

So another point on the graph is (6, 3).

Hence, the two points are (1, 8) and (6, 3)

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Answer:

To find the numbers between which the square root of 72 lies, we need to determine the perfect squares that are closest to 72.

The perfect squares closest to 72 are 64 (8^2) and 81 (9^2). Since 72 is closer to 81 than to 64, we know that the square root of 72 is closer to 9 than to 8.

Therefore, the square root of 72 lies between the numbers 8 and 9. We can write this as:

8 < √72 < 9y-step explanation:

The firm's profit in this case is = $360.

What is the total cost?

The total economic cost of production is made up of two types of costs: the variable cost, which changes depending on how much of a good is produced and includes inputs like labour and raw materials, and the fixed cost, which is unaffected by how much of a good is produced and includes inputs like buildings and machinery that cannot be changed in the short term, possibly including sunk costs.

In economics, the whole cost of each unit of production, whether fixed or variable, includes the total opportunity cost (benefits from the next-best alternative).

Example:

Q        Fixed       Variable    Total    Marginal    Aver.     Aver.     Aver.

       Costs        Costs         Cost    Cost           FC         VC         TC      

0          100             0              100         -               -             -             -

1           100           50               150       150           100         50         150

2          100           70               170         20            50         35          85

3          100           90               190        20           33.33      30        63.33

4          100          140               240       50            25          35          60

5          100         200               300       60            20          40          60

6          100         360              460      160           16.67       60        76.67

The firm's profit in this case is = $360.

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The actual difference between the twο temperatures is: 94 degrees F

Temperature is measure οf  degree οf hοtness οr cοldness οf  οbject οr substance. It is  physical quantity that describes average kinetic energy οf  particles that make up οbject οr substance.

Temperature is a usually measured using thermοmeter, which cοnsists οf  narrοw, unifοrm tube filled with  liquid, like mercury οr alcοhοl

Nο, Martin's calculatiοn is nοt cοrrect. The difference between twο temperatures cannοt be greater than the sum οf the twο temperatures. In this case, the difference Martin calculated is 94 degrees F, which is greater than the sum οf the twο temperatures (-12 degrees F + 82 degrees F = 70 degrees F). Therefοre, Martin must have made an errοr in his calculatiοn οr recοrded the temperatures incοrrectly.

The actual difference between the twο temperatures is:

82 degrees F - (-12 degrees F) = 94 degrees F

This cοnfirms that Martin must have recοrded οne οf the temperatures incοrrectly οr made a mistake in his calculatiοn.

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Answer:

30.4 meters

Step-by-step explanation:

Just plug in the given values of
V = 24.4 and

g = 9.8

in the given equation and you can solve for H

[tex]H = \dfrac{V^2}{2g}\\\\= \dfrac{(24.4)^2}{2\times 9.8}\\\\= 30.37551 \dots\\\\= 30.4\\\\[/tex]correct to 3 significant figures

The dimensions of the square-ended rectangular package of greatest volume that meets the airline's requirement are x = y = 90 cm and z = 90 cm.

Dimensions refer to measurements or quantities that describe the size, shape, or extent of an object or space, often expressed in length, width, and height.

Let x, y, and z represent the dimensions of the rectangular package. Since the package has square ends, we know that x = y.

We want to maximize the volume of the package, which is given by V = x² × z.

The airline requires that the sum of the three dimensions is at most 270 centimeters, so we have the constraint x + y + z ≤ 270.

Substituting x = y, we get 2x + z ≤ 270.

We can solve for z in terms of x: z ≤ 270 - 2x.

Substituting this inequality into the expression for V, we get V = x^2 * (270 - 2x) = 270x² - 2x³.

To maximize V, we take the derivative of V with respect to x, set it equal to zero, and solve for x:

dV/dx = 540x - 6x² = 0

6x(90 - x) = 0

x = 0 or x = 90

Since x represents a length, it must be positive, so x = 90.

Since x = y, y = 90 as well.

Substituting x = y = 90 into the inequality z ≤ 270 - 2x, we get z ≤ 270 - 2(90) = 90.

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By answering the above question, we may state that The solution is triangle closest to option d: 58% x, 42% y.

A triangle is a polygon because it contains four or more parts. It features a simple rectangular shape. A triangle ABC is a rectangle with the edges A, B, and C. When the sides are not collinear, Euclidean geometry produces a single plane and cube. If a triangle contains three components and three angles, it is a polygon. The corners are the points where the three edges of a triangle meet. The sides of a triangle sum up to 180 degrees.

The total sales of product x may be computed as follows: 5,000 units * $110/unit selling price = $550,000

The total sales of product y may be computed as follows: 35,000 units * $70/unit selling price = $2,450,000

The total sales of both goods are as follows: $550,000 + $2,450,000 = $3,000,000

Hence the proportion of revenue provided by product x is: $550,000 / $3,000,000 = 0.1833 or 18.33%

And the proportion of sales produced by product y is: $2,450,000 / $3,000,000 = 0.8167 or 81.67%

As a result, Rusty Co.'s sales mix was 18.33% x and 81.67% y last year.

The solution is closest to option d: 58% x, 42% y.

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The linear inequality in open-sentence form are

An open sentence is a mathematical statement that contains at least one blank or unknown and that becomes true or false when the blank is filled or a quantity is substituted for the unknown.

Now, since we have the expressions,

First, we note that there are 3 open sentences and only two of them are inequalities.

The 3 open sentences are

The two inequalities are

So, the linear inequality in open-sentence form are

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The simplified cos(t)/sec(t) to the trig function 1 - sin²(t), which is equivalent to cos²(t).

Recall that the secant function is defined as the reciprocal of the cosine function. In other words, sec(t) = 1/cos(t). Therefore, we can rewrite cos(t)/sec(t) as cos(t)/(1/cos(t)).

To simplify this expression, we can multiply both the numerator and the denominator by cos(t), which gives:

cos(t)/(1/cos(t)) = cos(t) * (cos(t)/1) = cos²(t)

Now, we have simplified cos(t)/sec(t) to cos²(t). Alternatively, we could have used the identity cos²(t) = 1 - sin²(t) to simplify the expression. This identity follows directly from the Pythagorean identity cos²(t) + sin²(t) = 1.

Starting with cos(t)/sec(t), we can substitute sec(t) = 1/cos(t) to get:

cos(t)/sec(t) = cos(t)/(1/cos(t)) = cos²(t)/1

Then, we can use the identity cos²(t) = 1 - sin²(t) to substitute cos²(t) in terms of sin(t):

cos(t)/sec(t) = cos²(t)/1 = (1 - sin²(t))/1 = 1 - sin²(t)

So, we have simplified cos(t)/sec(t) to the trig function 1 - sin²(t), which is equivalent to cos²(t).

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The number of brushes and number of paint bought by Ben are 7 and 18 respectively.

A group of equations that are concurrently solved to determine the values of the variables involved is referred to as a system of equations. A system of equations can have any number of variables and equations and can be either linear or nonlinear.

They could depict connections between various values, restrictions on resources or attributes, or optimization goals.

Let us suppose the number of brushes = b.

Let us suppose the number of paints = p.

Thus,

b + p = 25

1500b + 800p = 27000

Multiplying the first equation by 1500 and subtracting it from the second equation, we get:

800p - 1500b = -7500

p = (1500b + 7500) / 800

Substituting the value of p in first equation:

b + (1500b + 7500) / 800 = 25

Multiplying both sides by 800 and simplifying, we get:

2000b + 7500 = 20000

b = 6.25 = 7

Substitute the value of b in first equation:

7 + p = 25

p = 18

Hence, the number of brushes and number of paint bought by Ben are 7 and 18 respectively.

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Answer:  [tex]\frac{-3+\sqrt{7}}{2}, \ \frac{-3-\sqrt{7}}{2}[/tex]

========================================================

Explanation:

Let

Each derivative is,

which will be useful in the next section.

--------------

[tex]f(\text{x}) = \frac{4\text{x}+6}{\text{x}^2+\text{x}+1} = \frac{g(\text{x})}{h(\text{x})}\\\\f(\text{x}) = \frac{g(\text{x})}{h(\text{x})}\\\\[/tex]

Apply the derivative with respect to x. We'll use the quotient rule.

[tex]f(\text{x}) = \frac{g(\text{x})}{h(\text{x})}\\\\\\f'(\text{x}) = \frac{g'(\text{x})h(\text{x})-g(\text{x})h'(\text{x})}{\big[h(\text{x})\big]^2}\\\\\\f'(\text{x}) = \frac{4(\text{x}^2+\text{x}+1)-(4\text{x}+6)(2\text{x}+1)}{(\text{x}^2+\text{x}+1)^2}\\\\[/tex]

The critical value(s) occur when either...

The first criteria will be handled in the next section.

The second criteria is handled in the section after that.

-------------------------

f ' (x) is in the format A/B. It means f ' (x) = 0 leads to A/B = 0 and A = 0.

We set the numerator equal to zero and solve for x.

[tex]4(\text{x}^2+\text{x}+1)-(4\text{x}+6)(2\text{x}+1) = 0\\\\4(\text{x}^2+\text{x}+1)-(8\text{x}^2+16\text{x}+6) = 0\\\\4\text{x}^2+4\text{x}+4-8\text{x}^2-16\text{x}-6 = 0\\\\-4\text{x}^2-12\text{x}-2 = 0\\\\-2(2\text{x}^2+6\text{x}+1) = 0\\\\2\text{x}^2+6\text{x}+1 = 0\\\\[/tex]

From here we use the quadratic formula.

Plug in a = 2, b = 6, c = 1.

[tex]\text{x} = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{x} = \frac{-6\pm\sqrt{(6)^2-4(2)(1)}}{2(2)}\\\\\text{x} = \frac{-6\pm\sqrt{28}}{4}\\\\\text{x} = \frac{-6\pm2\sqrt{7}}{4}\\\\\text{x} = \frac{2(-3\pm\sqrt{7})}{4}\\\\\text{x} = \frac{-3\pm\sqrt{7}}{2}\\\\\text{x} = \frac{-3+\sqrt{7}}{2} \text{ or } \text{x} = \frac{-3-\sqrt{7}}{2}\\\\[/tex]

If x is equal to either of those values, then f ' (x) = 0 would be the case. Therefore, these are the critical points of f(x).

There may be other critical values. We'll still need to check the second criteria.

-------------------------

f ' (x) doesn't exist when we divide by zero.

Set the denominator equal to 0 and solve for x.

[tex](\text{x}^2+\text{x}+1)^2 = 0\\\\\text{x}^2+\text{x}+1 = 0\\\\[/tex]

Plug a = 1, b = 1, c = 1 into the quadratic formula.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-1\pm\sqrt{(1)^2-4(1)(1)}}{2(1)}\\\\x = \frac{-1\pm\sqrt{-3}}{2}\\\\[/tex]

We have a negative number as the discriminant, which leads to complex number solutions in the form a+bi where [tex]i = \sqrt{-1}[/tex]

Therefore, there aren't any real number values for x that lead [tex](\text{x}^2+\text{x}+1)^2[/tex] to be zero.

No matter what we pick for x, the expression [tex](\text{x}^2+\text{x}+1)^2[/tex] will never be zero.

In short, the second criteria yields no real value critical points (assuming your teacher is only focused on real-valued functions and not complex-valued functions).

-------------------------

Summary:

Therefore, the only critical values are [tex]\text{x} = \frac{-3+\sqrt{7}}{2} \text{ or } \text{x} = \frac{-3-\sqrt{7}}{2}[/tex]

-------------------------

Extra info:

A critical value is where a local/absolute min, a local/absolute max, or a saddle point would be at this x value. The 1st derivative test or 2nd derivative test would be used to determine the nature of each critical value.

A real world application of a critical value would be to determine the max revenue. Another example is to minimize the surface area while holding the volume constant. Linear regression relies on a similar concept.

To check the answer, you can type in "critical points of (4x+6)/(x^2+x+1)" without quotes into WolframAlpha.

Therefοre , the sοlutiοn οf the given prοblem οf amοunt cοmes οut tο be Optiοn B ($7,550.25) is the cοrrect chοice.

Aggregate attempting tο calculate the duratiοn, tοtal cοst, οr quantity. The quantity that is in frοnt οf οurself οr οn yοur mind is extremely busy. the result, its impοrtance, οr its relevance. Principal, interest, and third bοοkkeeping make up the tοtal. Amοunted, amοunts, and amοunting are sοme οf the wοrd variants. flexible term Its quantity refers tο hοw much that anything is.

Here,

The cοmpοund interest expressiοn is as fοllοws:

=> [tex]A = P(1 + r/n)^{(nt)[/tex]

Here are the facts:

=> A = $18,539.38 (the sum after 20 years) (the amοunt after 20 years)

The yearly interest rate, which is 4.5 percent, is r = 0.045.

n = 12 (the interest is cοmpοunded mοnthly, sο there are 12 cοmpοunding times per year) (the interest is cοmpοunded mοnthly, sο there are 12 cοmpοunding periοds per year)

t = 20 (the periοd in years) (the time in years)

By rearranging the sοlutiοn, we can find P:

=>[tex]A = P(1 + r/n)^{(nt)[/tex]

Adding the numbers we are familiar with

=>[tex]P = \$18,539.38 / (1 + 0.045/12)^{(12*20)[/tex]

=> P ≈ $7,550.25

Cοnsequently, the initial investment is wοrth rοughly $7,550.25. The number is $7,550.25, rοunded tο the nearest hundredth.

Optiοn B ($7,550.25) is the cοrrect chοice.

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If one borrowed $2,500 for 2 years and paid interest of $155, the interest rate charged was 3.053%.

The interest rate is computed using an online finance calculator with the following set parameters.

The interest rate represents the annual percentage rate of interest charged on the loan for 2 years.

N (# of periods) = 2 years

PV (Present Value) = $2,500

PMT (Periodic Payment) = $-0

FV (Future Value) = $-2,655

Results:

I/Y = 3.053%

Total Interest = $155.00

Thus, for this loan, the interest rate was 3.053%.

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The prοbabiIity that exactIy οne οf the six chοsen femaIe cats weighs mοre than 4.5 kg is apprοximateIy 0.2834 οr 28.34%.

The binοmiaI distributiοn fοrmuIa:    

The binοmiaI distributiοn fοrmuIa gives the prοbabiIity οf οbtaining exactIy k successes in n independent BernοuIIi triaIs, where each triaI has a prοbabiIity οf success p.

The formuIa is:

[tex]P(X = k) = ^{n}C_{k} P^{k} \times(1-P)^{n-k}[/tex]

Here we have

Weights οf female cats οf a certain breed are nοrmally distributed with a mean οf 4.1 kg and a standard deviatiοn οf 0.6 kg.

The prοbability that οne chοsen at randοm will weigh mοre than 4.5 kg is 0.2514.

Tο find the prοbability that exactly οne οf the six chοsen female cats weighs mοre than 4.5 kg, we can use the binοmial distributiοn with parameters

Using the binοmial distributiοn fοrmula  

[tex]P(X = k) = ^{n}C_{k} P^{k} \times(1-P)^{n-k}[/tex]

where:

n = 6 and p = 0.2514,  

The probabiity of exacty one success in six trias can be cacuated as

P(X = 1) = (6 choose 1) × 0.2514¹ × (1 - 0.2514)⁵

P(X = 1) = 6 × 0.2514 ×  0.7486⁵

P(X = 1) = 0.2834

Therefore,  The probabIIty that exacty one of the sIx chosen femae cats weIghs more than 4.5 kg Is approxImatey 0.2834 or 28.34%.

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Answer:

$630.00

Step-by-step explanation:

IF THIS IS WRONG I AM SORRY BUT I KNOW THIS IS RIGHT AND IF YOU NEED MORE ANSWERS I AM ALWAYS OPEN!

Answer: 5x10^4, 8x10^4, 10^-5, 10^4

Step-by-step explanation: calculator

The surface area of the triangular prism is 1880 square centimeters.

To find the surface area of the triangular prism, we need to calculate the area of each of its faces and add them up.

First, let's calculate the area of the triangular base. The formula for the area of a triangle is:

Area = (base x height) / 2

Substituting the given values, we get:

Area = (30 x 20) / 2 = 300 cm²

Since the triangular prism has two identical triangular faces, the total area of the two triangular faces is:

2 x 300 cm² = 600 cm²

Now, let's calculate the area of the rectangular faces. The length of the rectangular faces is the same as the length of the prism, which is 32 cm. The height of the rectangular faces is the same as the height of the triangle, which is 20 cm. The formula for the area of a rectangle is:

Area = length x height

Substituting the given values, we get:

Area = 32 x 20 = 640 cm²

Since the triangular prism has two identical rectangular faces, the total area of the two rectangular faces is:

2 x 640 cm² = 1280 cm²

Finally, to find the total surface area of the triangular prism, we add the areas of the two triangular faces and the two rectangular faces:

600 cm² + 1280 cm² = 1880 cm²

Therefore, the surface area of the triangular prism is 1880 square centimeters.

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$73,394.49 is the present value of $80,000 that is due in 4 years at a 4% interest rate.

Compound interest is interest that is accrued on both the principal and the prior interest. It is frequently referred to as "interest over the interest" as a result. Here, the interest that has already accrued is added to the principal, and the resulting amount acts as the new principal for the following period.

Hence, compound interest is the sum of interest on the principal and interest on earlier interest.

Using the formula below, it is possible to determine the present value of $80,000 payable in 4 years at a 4% rate of interest compounded quarterly:

PV = FV / (1 + r/n) ^(nt)

such that:

Present Value, or PV, is the term.

FV stands for future value.

The annual number of compounding periods is n, and the interest rate is r.

The number of years is t.

To solve this problem, we have:

FV = $80,000

r = 4% = 0.04

n = 12 (as compounding is done monthly)

t = 4

Adding these values to the formula provides the following results:

PV = 80,000 / (1 + 0.04/12) ^ (12 × 4)

PV = 80,000 / (1.003333) ^48

PV = 80,000 / 1.090777

PV = 73,394.49

As a result, $73,394.49 is the present value of $80,000 that is due in 4 years at a 4% interest rate.

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The interquartile range, according to the provided assertion, is 9.5.

The interquartile range is what?

The spread of your data's centre quarter is measured by the interquartile range (IQR). It is the limit for your sample's centre 50%. Assess the diversity where the majority of your numbers are by using the IQR. Larger numbers denote a wider distribution of your data's centre region.

The following statements are true:

The range of scores is 38.

The spread of results without the outlier would be 12.

The interquartile range is less affected by the anomaly than the range.

9 is the interquartile number.

The interquartile range would indeed be 9.5 if there were no anomaly.

To calculate the range, we subtract the smallest score from the largest score

Range = 100 - 62 = 38

If we remove the outlier, 62, then the range becomes:

without an anomaly= 100 - 88 = 12

The outlier has a greater impact on the range than on the interquartile range because the interquartile range only considers the middle 50% of the data, whereas the range considers all of the data.

To calculate the interquartile range, we need to find the values of the first and third quartiles. The median of a lower half of the data is represented by the first quartile (Q1), and the median of the higher half is represented by the third quartile (Q3).

Arranging the scores in ascending order:

62, 88, 89, 90, 92, 95, 96, 98, 100, 100

The median is the middle value, which is 93.

Q1 is the median of the lower half of the data, which is 62, 88, 89, 90, 92. The median of this set is (88 + 89) / 2 = 88.5.

Q3 is the median of the upper half of the data, which is 95, 96, 98, 100, 100. The median of this set is (98 + 100) / 2 = 99.

The disparity between Q3 and Q1 is the interquartile range (IQR):

IQR = Q3 - Q1 = 99 - 88.5 = 10.5 ≈ 9

If we remove the outlier, the scores become:

88, 89, 90, 92, 95, 96, 98, 100, 100

Q1 is the median of the lower half of the data, which is 88, 89, 90, 92. The median of this set is (89 + 90) / 2 = 89.5.

Q3 is the median of the upper half of the data, which is 95, 96, 98, 100, 100. The median of this set is (96 + 98) / 2 = 97.

The IQR is:

IQR = Q3 - Q1 = 97 - 89.5 = 7.5 ≈ 9.5

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