what components of static electricity theory does Electrostatic Precipitator make use of

Answer: d)endothermic with a positive entropy change

Explanation:

Endothermic reactions are those in which heat is absorbed by the system and exothermic reactions are those in which heat is released by the system.

 Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

As temperature of water decreases on dissolution of [tex]NH_4NO_3[/tex] , it means heat has been absorbed by [tex]NH_4NO_3[/tex] during dissolution and that heat is taken from water. Thus process is endothermic. As dissolution will lead in the formation of ions [tex]NH_4^+[/tex] and [tex]NO_3^-[/tex] , randomness will increase and thus there is a positive entropy change.

Answer:

[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]

Explanation:

In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.

Self-condensation:

Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.

Cross-condensation:

Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.

[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]

Explanation:

It is represented using the ideal gas equation , or PV = nRT, where P is the pressure in atmospheres, V is the volume in liters, n represents the quantity of particles in the container, T represents the temperature in Kelvin, and R is the ideal gas constant equal to 0.0821 liters atmospheres per moles Kelvin.

The ocean water found near the poles has a higher level of salinity because the area of rain reduces as one moves toward the poles, and as a result of less rain and more sunshine, evaporation increases.

Salinity is the presence of salt in the water. Freshwater bodies have very less amount of salt, but ocean water has a large amount of salt dissolved in it.

Because cold polar air cools the water and decreases its temperature, raising its salinity, water close to the poles frequently has more salinity. When fresh water freezes out of seawater to form sea ice, the salinity of the remaining water likewise rises.

Therefore, as one travels toward the poles, the area of rain decreases, and as a result of less rain and more sunshine, evaporation increases, and the ocean water there has a higher level of salinity.

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Answer:

Explanation:

It processes the environment and sends out signals.

Answer:

3224 kJ/mol

Explanation:

The combustion of benzoic acid occurs as follows:

C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE

The change in temperature in the reaction is the change due the energy released, that is:

3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts

To find the heat released per mole we have to find the moles of benzoic acid:

Moles benzoic acid -Molar mass: 122.12g/mol-:

1.250g * (1mol / 122.12g) = 0.0102 moles

The dE combustion per mole of benzoic acid is:

33.00kJ / 0.0102moles =

3224 kJ/mol

centimetres

Explanation:

centimetres

Answer:

D. Centimeter is used when measuring the length of a paperclip

Answer:

Option D.

Explanation:

First we convert the given reactant masses into moles, using their respective molar masses:

0.05 moles of P₄ would react completely with (6*0.05) 0.3 moles of H₂. There are more H₂ moles than required, meaning H₂ is in excess and P₄ is the limiting reactant.

Now we calculate how many PH₃ moles could be formed, using the number of moles of the limiting reactant:

Finally we convert 0.2 mol PH₃ into grams, using its molar mass:

So the correct answer is option D.

Answer:

stress

Explanation:

people cn get stressed and not want to do work

Answer:

When a solid is heated the particles gain energy and start to vibrate faster and faster. ... At this point the solid is melting to form a liquid. The particles in the liquid are the same as in the solid but they have more energy.

Explanation:

sana maka help

Answer:

Promethium

Pm 61

Discovered by Jacob .A. Marinsky

Answer:

Approximately [tex]3.06 \times 10^{2}\; \rm g[/tex] (approximately [tex]306\; \rm g[/tex].)

Explanation:

Calculate the quantity [tex]n[/tex] of lithium phosphate in [tex]V = 2.5\; \rm L[/tex] of this[tex]c = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1}[/tex] lithium phosphate solution.

[tex]\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}[/tex].

Empirical formula of lithium phosphate: [tex]\rm Li_3PO_4[/tex].

Look up the relative atomic mass of [tex]\rm Li[/tex], [tex]\rm P[/tex],and [tex]\rm O[/tex] on a modern periodic table:

Calculate the formula mass of [tex]\rm Li_3PO_4[/tex]:

[tex]M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}[/tex].

Calculate the mass of that [tex]n = 2.65\; \rm mol[/tex] of [tex]\rm Li_3PO_4[/tex] formula units:

[tex]\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}[/tex].

Answer:

MgS + KI = K2S + MgI2

aswer: protactinium-234 is more dang erous than uranium

There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore protactinium-234 is more dangerous than uranium-234.

Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle.  Protactinium-234 and uranium-234 are radioactive element.

If we were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials then protactinium-234 is more dangerous than uranium-234. The half-life of protactinium-234 is smaller than that of uranium-234. So, protactinium-234 is more active than uranium-234 and hence more harmful than uranium-234.

Therefore, protactinium-234 is more dangerous than uranium-234.

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Answer:

20. ²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. ⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

Explanation:

20. ²⁴¹₉₅Am —> __ + ⁴₂He

Let ⁿₘX be the unknown.

Thus, the equation becomes:

²⁴¹₉₅Am —> ⁿₘX + ⁴₂He

Next, we shall determine n, m and X. This can be obtained as follow:

241 = n + 4

Collect like terms

n = 241 – 4

n = 237

95 = m + 2

Collect like terms

m = 95 – 2

m = 93

Thus,

ⁿₘX => ²³⁷₉₃X => ²³⁷₉₃Np

Therefore, the complete equation is:

²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. __ —> ⁰₋₁β + ⁴²₂₀Ca

Let ʸₓZ be the unknown.

Thus, the equation becomes:

ʸₓZ —> ⁰₋₁β + ⁴²₂₀Ca

Next, we shall determine y, x and Z. This can be obtained as follow:

y = 0 + 42

y = 42

x = –1 + 20

x = 19

Thus,

ʸₓZ => ⁴²₁₉Z => ⁴²₁₉K

Therefore, the complete equation is:

⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

Answer:

ok so if I remember correctly then it basically its like if I have a baseball and throw it full force the the ball will go far because the mass is light and the force was great but if I get a bowling ball and do the same with equal force it will go shorter than the base ball because the mass if more than the force I put in

Answer:

42.39, 64.06

Explanation:

Formula Weight can be calculated by adding the atomic mass of the elements in the formula.

LiCl

AM for Li is 6.94 amu, AM for Cl is 35.45 amu

[tex](6.94)+(35.45)=42.39[/tex]

SO₂

AM for S is 32.06 amu, AM for O is 16 amu

[tex](32.06)+2(16.00)=64.06[/tex]

Answer:

I think one significant figure??

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]