what is the effect of cigarette smoke in your family
Rolled cookies are cut into fancy shapes.
True
False
Answer:
false
Explanation:
the answer is false
Answer:
true
Explanation:
cause why not, try new things init
Two copper rods are rubbed together will they become charged
Answer:
Explanation:When insulating materials rub against each other, they may become electrically charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged.
Can you please help me with this worksheet I will give BRAINLISET to whoever answers first?
Which of the following parallel plate diagrams would have the greatest electric fields between them?
The greatest electric field between them is Option B.
An electric field is the physical subject that surrounds electrically charged particles and exerts a force on all other charged debris inside the area, either attracting or repelling them. It also refers back to the bodily field of a machine of charged particles.
Reasoning:-
Electric field = Kq/r²
Since the distance is inversely proportional to the square root of the distance between them. therefore decreasing the distance electric field will be the greatest. Hence Option B.
The electrical field is defined mathematically as a vector discipline that can be related to each point in space, the force in step with unit charge exerted on a fine take a look at the price at rest at that factor. the electric field is generated by the electrical rate or through time-varying magnetic fields. electric fields provide us with the pushing force we need to set off the contemporary float.
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they enjoy being alone for quit small time
A gas is stored in a sealed container of constant volume. The temperature of the gas increases.
This causes the pressure of the gas to increase
What happens to the gas molecules during this pressure increase?
A The average kinetic energy of the molecules increases.
B The average separation of the molecules decreases
The average separation of the molecules increases,
с
D
The volume of each molecule increases.
Answer:
If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas. Avogadro's law. At constant pressure and temperature, the frequency and force of molecule-wall collisions are constant.
Explanation:
As the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container. The force exerted by the particles per unit of area on the container is the pressure, so as the temperature increases the pressure must also increase.
As the temperature of the gas increases, the particles gain kinetic energy and their speed increases. This means that the particles hit off the sides more often and with greater force. Both of these factors cause the pressure of the gas to increase.
What is temperature ?
Temperature is a measure of the degree of hotness of a body. The SI unit of temperature is kelvin (K).The instrument used to measure temperature is called a thermometer.
What is kinetic energy ?
Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.
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In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00 102 m distance in 9.5 s. Assuming that he ran with a constant speed equal to his average speed, and his kinetic energy was 3.40 103 J, what was Burrell’s mass?
Answer:
61.33 Kg
Explanation:
From the question given above, the following data were obtained:
Distance = 1×10² m
Time = 9.5 s
Kinetic energy (KE) = 3.40×10³ J
Mass (m) =?
Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:
Distance = 1×10² m
Time = 9.5 s
Velocity =?
Velocity = Distance / time
Velocity = 1×10² / 9.5
Velocity = 10.53 m/s
Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:
Kinetic energy (KE) = 3.40×10³ J
Velocity (v) = 10.53 m/s
Mass (m) =?
KE = ½mv²
3.40×10³ = ½ × m × 10.53²
3.40×10³ = ½ × m × 110.8809
3.40×10³ = m × 55.44045
Divide both side by 55.44045
m = 3.40×10³ / 55.44045
m = 61.33 Kg
Thus, the mass of Leroy Burrell is 61.33 Kg
A5 N object at a height has gravitational potential energy of 30 J. What is the height of the object?
30=5×h then divide both sides by 5 you will get h=6m
If a 5 N object at a height has a gravitational potential energy of 30 J , then the height of the object would be 6 meters.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As given in the problem a 5 N object at a height has gravitational potential energy of 30 J, then we have to find the height of the object.
Similarly, the total gravitational potential energy of the object,
PE = m × g × h
30 = 5 × h
h = 30 / 5
h = 6 meters
Thus, if a 5 N object at a height has a gravitational potential energy of 30 J, then the height of the object would be 6 meters.
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Question
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500 - kg particle rests on a frictionless horizontal surface and is attached to the free end of the spring. The particle is displaced from the origin to x = 5.00 cm and released from rest at t = 0. (a) What is the force constant of the spring? (b) What are the angular frequency ω, the frequency, and the period of the motion? (c) What is the total energy of the system? (d) What is the amplitude of the motion? (e) What are the maximum velocity and the maximum acceleration of the particle? (f) Determine the displacement x of the particle from the equilibrium position at t = 0.500 s. (g) Determine the velocity and acceleration of the particle when t = 0.500 s.
Explanation:
(a) Hooke's law:
F = kx
7.50 N = k (0.0300 m)
k = 250 N/m
(b) Angular frequency:
ω = √(k/m)
ω = √((250 N/m) / (0.500 kg))
ω = 22.4 rad/s
Frequency:
f = ω / (2π)
f = 3.56 cycles/s
Period:
T = 1/f
T = 0.281 s
(c) EE = ½ kx²
EE = ½ (250 N/m) (0.0500 m)²
EE = 0.313 J
(d) A = 0.0500 m
(e) vmax = Aω
vmax = (0.0500 m) (22.4 rad/s)
vmax = 1.12 m/s
amax = Aω²
amax = (0.0500 m) (22.4 rad/s)²
amax = 25.0 m/s²
(f) x = A cos(ωt)
x = (0.0500 m) cos(22.4 rad/s × 0.500 s)
x = 0.00919 m
(g) v = dx/dt = -Aω sin(ωt)
v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)
v = -1.10 m/s
a = dv/dt = -Aω² cos(ωt)
a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)
a = -4.59 m/s²
An Atwood's machine consists of two masses, m1 and m2, connected by a string that passes over a pulley. If the pulley is a disk of radius R and mass M , find the acceleration of the masses. Express your answer in terms of the variables m1, m2, R, M, and appropriate constants.
Answer:
Explanation:
Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.
Let tension in string be T₁ and T₂ . Let common acceleration of system be a
For motion of m₁
T₁-m₁g = m₁a ----- (1)
For motion of m₂
m₂g- T₂ = m₂a ------- (2)
For motion of pulley
(T₂-T₁ )R represents net torque
(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc
(T₂-T₁ )R = 1/2 M R² x a / R
(T₂-T₁ ) = M a /2
Adding (1) and (2)
(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )
(m₂-m₁)g = (m₂+m₁)a + Ma/2
(m₂-m₁)g = (m₂+m₁+ 0.5M)a
a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)
The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
Given to us
Masses = m₁, m₂
The radius of the pulley = R
Mass of the pulley = M
Assumption
Let the mass m₁ > m₂. therefore, the mass m₁ is going down due to its weight while m₂ is going up.Assuming the tension in the string be T₁ and T₂, respectively.Also, the common acceleration in the system is a.Tensions in stringsWe know the acceleration due to gravity is denoted by g,
Tension in string 1, T₁[tex]T_1 = m_1(a+g)[/tex]......... equation 1
Tension in string 2, T₂[tex]T_2 = m_2(a-g)[/tex]......... equation 2
Inertia and acceleration of the pulleyThe inertia of the pulley, [tex]I = \dfrac{1}{2}MR^2[/tex]
Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]
Torque in the pulley[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]
Substitute the values we get,
[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]
[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]
[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]
[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]
[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]
Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].
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A movie stunt double is supposed to run across the top of a train (in the opposite direction that the train is moving) and just barely jump off before reaching a tunnel, but after running the entire length of the train (starting from the front). If the train is moving at 50 km/hr, is 3 km long and the tunnel is 40 km away from the end (where the stunt double is going to jump from), how fast (in km/hr) will the stunt double need to run
Answer:
3.49km/hr
Explanation:
This train is moving at 50km/hr
Distance = length of train + distance of tunnel
= 3 km + 40 km
= 43 km
Time taken by train to get to tunnel
Time = distance / velocity
Time = 43 km/50km perhour
= 0.86
How fast will stunt double have to run?
Velocity = 3km/0.86
= 3.49 km/hr
The stunt double will have to run as fast as 3.49 kilometer per hour
how much work is done if a force of 20 N moves an object a distance of 6 m?
Explanation:
W=F×s
w=20N×6m=120J
W=120J
When a 2kg metal is exposed to 2MJ of
heat it dissolves into liquid at 500K
Calculate the latent heat of fusion for
the metal. Betty went in to get you metal is exposed to to megajoules of heat
Answer:
1×10⁶ J/Kg
Explanation:
From the question given above, the following data were obtained:
Mass (m) of metal = 2 Kg
Heat (Q) = 2 MJ
Latent heat of Fusion (Hf) =?
Next, we shall convert 2 MJ to J. This can be obtained as follow:
1 MJ = 1×10⁶ J
Therefore,
2 MJ = 2 MJ × 1×10⁶ J / 1 MJ
2 MJ = 2×10⁶ J
Finally, we shall determine the latent heat of fusion. This can be obtained as follow:
Mass (m) of metal = 2 Kg
Heat (Q) = 2×10⁶ J
Latent heat of Fusion (Hf) =?
Q = m•Hf
2×10⁶ = 2 × Hf
Divide both side by 2
Hf = 2×10⁶ / 2
Hf = 1×10⁶ J/Kg
Thus, the latent heat of fusion for the metal is 1×10⁶ J/Kg
10. What patterns do you notice between the angles of incidence and the
angles of the reflected light rays?
1
EXPLORE/EXPLAIN Lesson 2 Reflection and Mir
Answer:
The law of reflection states that the angle of reflection equals the angle of incidence—θr = θi. The angles are measured relative to the perpendicular to the surface at the point where the ray strikes the surface.
A forward honzontal force of 50 N is applied to a crate. A second horizontal force o
180 N is applied to the crate in the opposite direction. Determine the magnitude and
direction of the resultant force acting on the crate
Answer:
Explanation:
magnitude: 180-50=130N
Direction: in the direction same as the second horizontal force
What is the gravitational potential energy of a 3 kg ball that is 1 meter above the floor?
Answer:
PE=mgh
M= Mass (kg)
G= Gravitational field strength (N/kg)
H= Hight (m)
PE= Gravitational Potential Energy (J)
Explanation:
Gravitational Potential Energy is the energy stored in a object due to its position above the Earth's surface.
The potential energy of the ball is 29.4 joules
The parameters given are;
mass= 3 kg
height= 1 meter
g= 9.8 m/s²
P.E= mgh
= 3 × 9.8 × 1
= 29.4
Hence the potential energy is 29.4 joules
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miniature spring-loaded, radio-controlled gun is mounted on an air puck. The gun's bullet has a mass of 5.00 g, and the gun and puck have a combined mass of 120 g. With the system initially at rest, the radio controlled trigger releases the bullet causing the puck and empty gun to move with a speed of 0.500 m/s. What is the bullet's speed
Answer:
12 m/s
Explanation:
From the question,
Applying the law of conservation of momentum,
total momentum before collision = Total momentum after collision
mu+Mu' = mv+Mv'........................... Equation 1
Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck
make v the subeject of the equation
v = [(mu+Mu')-Mv']/m................. Equation 2
Given: m = 5.00 g = 0.005 kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s
Substitute these values into equation 2
v = [0-(0.12×0.5)]/0.005
v = -0.06/0.005
v = -12 m/s
The negative sign can be ignored since we are looking for the speed, which has only magnitude.
Hence the speed of the bullet is 12 m/s
can someone pls tell me what a force diagram is
2. Which process is used by plants to cycle water from the ground, through the roots, and out the leaves as water vapor?
sublimation
O perspiration
O transpiration
O runoff
Answer:
The answer is transpiration
What order shows increasing frequency for gamma
rays, microwaves, visible light, and X-rays?
A. gamma rays, X-rays, visible light, microwaves
B. microwaves, visible light, X-rays, gamma rays
C. visible light, gamma rays, microwaves, X-rays
D. X-rays, microwaves, gamma rays, visible light
Answer:
The answer is B: microwaves, visible light, X-rays, gamma rays
Explanation:
I had the same question and I got option B as the correct answer.
The waves arranged in their order of increasing frequency will be
Microwaves,Visible light, X-rays and Gamma rays.What order shows the increasing frequency for gamma rays, microwaves, visible light, and X-rays?Generally, frequency is the numeral of occurrences of a repeating event per unit of duration.
Therefore, gamma rays, microwaves, visible light, and X-rays will be arranged in their order of increasing frequency
In conclusion, The order is given as folllows
microwaves, Visible light, X-rays, and Gamma rays.
Option B is correct
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In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequency is of particular interest. On the basis of the ICNIRP guidelines, what is the maximum intensity of an electromagnetic wave at this frequency to which the general public should be exposed
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
[tex]I[/tex] = [tex]\frac{1}{2}[/tex]ε₀cE[tex]_{max[/tex]²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E[tex]_{max[/tex] is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E[tex]_{max[/tex] )
E[tex]_{max[/tex] = 350/f kV/m
given that frequency of 60 Hz, we substitute
E[tex]_{max[/tex] = 350/60 kV/m
E[tex]_{max[/tex] = 5.83333 kV/m
E[tex]_{max[/tex] = 5.83333 kV/m × ( [tex]\frac{1000 V/m}{1 kV/m}[/tex] )
E[tex]_{max[/tex] = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
[tex]I[/tex] = [tex]\frac{1}{2}[/tex]ε₀cE[tex]_{max[/tex]²
[tex]I[/tex] = [tex]\frac{1}{2}[/tex] × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
[tex]I[/tex] = 45 × 10³ W/m²
[tex]I[/tex] = 45 × 10³ W/m² × ( [tex]\frac{1 kW/m^2}{10^3W/m^2}[/tex] )
[tex]I[/tex] = 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Ashley decides to enter her pet turtle in a race. She knows her turtle can travel at a rate of 2 meters per hour. The race track measures 5 meters from start to finish. How long will it take Ashley’s turtle to finish the race?
A) 3 hours
B) 10 hours
C) .4 hours
D) 2.5 hours
Thanks for the help! And if it’s not a bother could you please explain how you got the answer? However it’s not necessary if you don’t want to.
PLEASE HELP ASAP!!!
A car is sitting on a hill which is 25 m higher than ground level. What is the mass of the car if it contains 360,800 J of potential energy?
Answer:
14,432 g
Explanation:
PE=mh
360,800 J = (m)(25)
[tex]\frac{360,800 J}{25 m}[/tex] = m
14,432 g = m
Given three different locations on Earth's surface, where will the weight of a person be greatest?
Answer:
Explanation:
In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.
The equation given by Newton tells us that
[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.
In the case of [tex]G, m_{1} ,m_{2}[/tex], we understand that they are constant.
We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.
In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.
In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line
The energy that a substance contains is
a. equilibrium
b. heat
c. thermal energy
d. entropy
The energy that a substance contains is known as heat. Thus, the correct option for this question is B.
What is Entropy?Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.
Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.
Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.
Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.
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what is the terminal velocity of blood
Answer:
25.1
Explanation:
Two sticky spheres are suspended from light ropes of length LL that are attached to the ceiling at a common point. Sphere AA has mass 2mm and is hanging at rest with its rope vertical. Sphere BB has mass mm and is held so that its rope makes an angle with the vertical that puts BB a vertical height HH above AA. Sphere BB is released from rest and swings down, collides with sphere AA, and sticks to it.
In terms of H,H, what is the maximum height above the original position of A reached by the combined spheres after their collision?
Answer:
h’ = 1/9 h
Explanation:
This exercise must be solved in parts:
* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy
starting point. Higher
Em₀ = U = m g h
final point. Lower, just before the crash
Em_f = K = ½ m [tex]v_{b}^2[/tex]
energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v_b = [tex]\sqrt{2gh}[/tex]
* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved
initial instant. Just before the crash
p₀ = 2m 0 + m v_b
final instant. Right after the crash
p_f = (2m + m) v
the moment is preserved
p₀ = p_f
m v_b = 3m v
v = v_b / 3
v = ⅓ [tex]\sqrt{2gh}[/tex]
* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together
Starting point. Lower
Em₀ = K = ½ 3m v²
Final point. Higher
Em_f = U = (3m) g h'
Em₀ = Em_f
½ 3m v² = 3m g h’
we substitute
h’= [tex]\frac{v^2}{2g}[/tex]
h’ = [tex]\frac{1}{3^2} \ \frac{ 2gh}{2g}[/tex]
h’ = 1/9 h
Would this be C ?? Please tell me if I’m wrong ..
Answer:
yes its c
Explanation:
took it already
We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that: (A) No magnetic field exists in that region of space. (B) The particle must be moving parallel to the magnetic field. (C) Either no magnetic field exists or the particle is moving parallel to B. (D) Either no magnetic field exists or the particle is moving vertical (perpendicular) to B.
Answer:
(C) Either no magnetic field exists or the particle is moving parallel to B.
Explanation:
The moving charged particle tends to show no magnetic forces. Due to its moving in the same direction and will be parallel to the field. As when the magnetic fed and charged particle velocity is parallel then there will be no force. As the magnetic field are made by the generation of the current with the field line concentric to the current-carrying wire.