Answers
Answer:
eeeeeeeeeeeeeeeeeeeeeeeeeee
Related Questions
A 5.00 cm tall object is placed a distance of 24 cm from a convex lens. If the image is
formed 48 cm from the lens, determine the type and height of the image?
Answers
Answer.:
Explanation:
The image is either virtual or real and the height of the image is 10cm.
To find the image type and its height, we need to know about the magnification of convex lens.
What is magnification of an image formed by lens?magnification of an image is the comparison of the image size with respect to that of object.It's the ratio of image height to that of object height.What is the mathematical formula of magnification of image?Mathematically, the magnification of an image isHeight of image/height of object or image distance(V) / object distance(U)
If the magnification is positive, image is virtual and if it's negative, the image is real.What is the magnification, if image distance is 48cm and object distance is 24 cm?Object is placed on the left of the lens and the object distance is taken as negative using sign convention.If the image is also formed on the left, the image distance is taken as negative. Corresponding magnification is -48cm/-24cm = 2. Since, the magnification is positive, so, image is virtual.But, if the image is formed on the right of the lens at 48cm, the image distance is taken as positive. So the magnification is 48cm/(-24)cm = -2. Since, the magnification is negative, so image is real.What is the image height, absolute value of magnification is 2 and object height is 5cm?Magnification = image height / object heightSo, image height = magnification × object height
= 2×5 = 10 cm
Thus, we can conclude that the image is virtual if it's formed on the left of the lens and is real if it's formed on the right of the lens. The height of the image is 10 cm.
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How much power flows through a circuit with 5 amps and 120 volts?
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Which is an example of negative acceleration?
A) a snowboarder who increases speed when traveling downhill
B) a biker who maintains a constant speed through a race
C) a skateboarder who reduces speed when moving up a hill
D) a runner who fluctuates speed by increasing and decreasing speed
Answers
Answer:
A) a snowboarder who increases speed when traveling downhill
A snowboarder who increases speed when traveling downhill will have negative acceleration.
What is acceleration ?
Acceleration is described as the rate of change of velocity with time.
[tex]a&=\frac{\Delta v}{\Delta t}[/tex]
Here, as the snowboarder is traveling in negative y direction therefore the final velocity will be great than initial velocity with negative sign. It should be noted that velocity and acceleration are vector quantities i.e. depends upon the direction in which they have been applied.
Also negative acceleration is denoted as the situation when the object moves in the direction that is opposite to its direction of velocity.
In the above situation, the force is being applied to travel downhill(speeding up in the negative direction) in the opposite direction which exemplifies negative acceleration.
Thus, option A is the correct answer.
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How does energy affect the appearance of light?
Answers
Answer:
The bigger the energy source the more light it makes
Answer:
Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.
for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.
Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.
The acceleration of a motorcycle is given by ax(t)=At-Bt2,A=1.5m/s2,B=0.120m/s2,the motorcycle at rest at t=0 a)Find its position and velocity as function of time b)What maximum velocity it attains
Answers
Answer:
(a)
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex] --- velocity
[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex] --- position
(b) The maximum velocity is: 39.0625m/s
Explanation:
Given
[tex]a_x(t) =At -Bt^2[/tex]
[tex]A = 1.5m/s^3[/tex]
[tex]B = 0.120m/s^4[/tex]
Solving (a): The position and velocity as a function
To calculate the change in velocity, we integrate the given acceleration
i.e.
[tex]\int\limits^{v(t)}_{v(0)} {dv} = \int\limits^t_0 {a(t)} \, dt[/tex]
Integrate
[tex]v|\limits^{v(t)}_{v(0)} = \int\limits^t_0 {a(t)} \, dt[/tex]
Substitute v(t) and v(0) for v
[tex]v(t) - v(0) = \int\limits^t_0 {a(t)} \, dt[/tex]
[tex]v(0) = 0[/tex] ---- The initial velocity.
So, we have:
[tex]v(t) - 0 = \int\limits^t_0 {a(t)} \, dt[/tex]
[tex]v(t) = \int\limits^t_0 {a(t)} \, dt[/tex]
Substitute: [tex]a_x(t) =At -Bt^2[/tex]
[tex]v(t) = \int\limits^t_0 {[At -Bt^2]} \, dt[/tex]
Integrate
[tex]v(t) = {\frac{At^2}{2} -\frac{Bt^3}{3}}|\limits^t_0[/tex]
Substitute 0 and t for t
[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - [\frac{A*0^2}{2} -\frac{B*0^3}{3}][/tex]
[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - 0[/tex]
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
To calculate the change in position, we integrate the calculated velocity
i.e.
[tex]\int\limits^{x(t)}_{x(0)} {dx} = \int\limits^t_0 {v(t)} \, dt[/tex]
Integrate
[tex]x(t)|\limits^{x(t)}_{x(0)} = \int\limits^t_0 {v(t)} \, dt[/tex]
Substitute x(t) and x(0) for x(t)
[tex]x(t) - x(0) = \int\limits^t_0 {v(t)} \, dt[/tex]
Substitute: [tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
[tex]x(t) - x(0) = \int\limits^t_0 {\frac{At^2}{2} -\frac{Bt^3}{3}} \, dt[/tex]
Integrate
[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}}|\limits^t_0[/tex]
Substitute t and 0 for t
[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [\frac{A*0^3}{6} -\frac{B*0^4}{12}][/tex]
[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [0][/tex]
[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}[/tex]
Make x(t) the subject
[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex]
Where x(0) represents the initial position
Solving (b): The maximum velocity
First, we calculate the time at which it attains the maximum height
Set acceleration to 0
[tex]a_x(t) =At -Bt^2[/tex]
[tex]At - Bt^2 = 0[/tex]
Factorize
[tex]t(A - Bt) = 0[/tex]
Split
[tex]t = 0\ or\ A - Bt = 0[/tex]
t can't be 0.
So, we have:
[tex]A - Bt = 0[/tex]
Solve for t
[tex]-Bt = -A[/tex]
[tex]t = \frac{-A}{-B}[/tex]
[tex]t = \frac{A}{B}[/tex]
Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]
[tex]t = \frac{1.5m/s^3}{0.120m/s^4}[/tex]
[tex]t = \frac{1.5}{0.120}s[/tex]
[tex]t = 12.5s[/tex]
Substitute [tex]t = 12.5s[/tex] in v(t) to get the maximum velocity
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
[tex]v(t) = \frac{A*12.5^2}{2} -\frac{B*12.5^3}{3}[/tex]
[tex]v(t) = \frac{156.25A}{2} -\frac{1953.125B}{3}[/tex]
Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]
[tex]vmax = (156.25*1.5)/2 -(1953.125*0.120)/3[/tex]
[tex]v_{max} = 117.1875 - 78.125[/tex]
[tex]v_{max} = 39.0625[/tex]
Fast cooling rates tends to promote transformations that result in relatively course structures (e.g. for a reaction resulting in multiple product phases, the secondary phase particles are (i) fewer in count (ii) larger in size and (iii) relatively spherical). True or False
For most materials, the formation of a glass from a liquid typically requires extremely slow cooling rates, thereby taking on the order of years or even centuries to produce. True or False
For a system below its melting point, a glass (or non-crystalline / amorphous) configuration is the most energetically stable state that is possible, since it offers the lowest Gibbs free energy for all possible solid configurations. True or False
When measured experimentally, most materials tend to exhibit the same exact temperature value for both melting and freezing (crystallization). True or False
Gray iron is a microstructure that tends to result when a cast iron of appropriate composition is cooled fairly quickly. True or False
Coarsening refers to the scenario where, upon heating and/or annealing for sufficient time, the scale of a microstructure tends to reduce (e.g. grains become smaller, secondary phase particles separate into smaller particles and become more finely dispersed, often reverting to high aspect ratio or high surface-area-to-volume ratio configurations. True or False
Answers
Answer:
1) correct answer is ii larger size
2) false, 3) false, 4) true, 5) true, 6) true
Explanation:
In this exercise, the answer is asked if the statement is true.
1) in the rapid cooling speed, there is no thermodynamic equilibrium, so the secondary phases do not have time to transform into the main one, therefore many phases appear in the products,
the correct answer is ii
2) False. The transformation of a material to the glass state requires a fixed temperature and rapid changes to reach this temperature,
3) False. The most stable state is the crystalline state, the glass states are metastable, their Gibbs energy is not the lowest possible and they must transition to the crystalline state over time, it can be years or centuries.
4) True. The melting and freezing temperatures change for each material, within the same material it always has the same value, since it corresponds to a change in the state of the system.
5) true. Cast iron is called gray because of the impurities inside that have not had time to move due to rapid cooling.
6) True. The microstructure is reduced in the process of cooling and heating
Please help me with this no wrong answer I am begging you please help me ASAP thanks
Answers
Answer: Hope This Helps!
Explanation:
1: The first one is true because, if it was full there would be more weight and you would have to apply more force for it to start moving. But an empty one you don't have to apply so much force to it. (Newtons 2nd Law.)
2: The second one is true because, the skate board has a lot of kinetic energy and when it hits the rocks a collosion occurs where all the enrgy points into the front of the board and the back side lifts of the floor so it flips over the rock.(Newtons 1st Law.)
3: The third one is false because, the road cant push onto the tire the tire can push onto the road though. Additional information: Also the when the tire pushes on the road friction happens and because of the rough surface of the road.(Newtons 3rd Law.)
What is a disadvantage of using fuses? A.When a fuse burns out, it cannot be used again b.
A fuse shuts off when the current gets too high c. A fuse contains a thin strip of metal that can melt d. A fuse prevents circuits from overheating
Answers
what was the main cause of the near extinction of the black-footed ferret?
A. Climate change
B. Dwindling prairie dog populations
C. Natural predators
D. For hunters hunted them to extinction
Answers
Answer:
b
Explanation:
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Answers
Answer:
B. Large mountain ranges
What is transformation of energy
Answers
Answer:
Energy transformation
Explanation:
Energy transformation means the changing of energy from one type to another.
The fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that Select one: A. they must be in directions where intergalactic absorption by dark matter is minimum, allowing us to see them. B. they must be intrinsically far more luminous than the brightest galaxies. C. they have not been as redshifted by their motion as have galaxies, and hence they can still be seen. D. they must be in directions where gravitational focusing by the masses of nearer galaxies makes them visible from Earth.
Answers
Answer:
B. they must be intrinsically far more luminous than the brightest galaxies.
Explanation:
Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.
The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?
Question 23 options:
4
16
0.6
1.67
Answers
magnification = [tex]\bf\dfrac{height of image}{height of object}[/tex]
= [tex]\bf\dfrac{6cm}{10cm}[/tex]
= 0.6
small block with a mass of 0.150 kg is attached to a cord passing through a hole in a frictionless, horizontal surface. The block is originally revolving a distance of 0.5 m from thehole with a seed of 0.9 m/s. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.23 m. a) Explain if the tension force causes the change of angular momentum. b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius. c) How much work was done by the person who pulled on the cord
Answers
Answer:
a. Thus, the tension in the cord causes no change in angular momentum.
b. 0.112 N
c. -0.048 J
Explanation:
a) Explain if the tension force causes the change of angular momentum.
A centripetal force F initially acts on the block to keep at at a radius of 0.5 m and speed of 0.9 m/s.
When the cord is pulled, the tension causes a change in the centripetal force to a new value at a radius of 0.23 m.
But since the force is applied in the radial direction and not perpendicular to the radius, there is no torque applied (since torque τ = rFsinθ and θ = 0 thus τ = rFsin0 = 0)and thus, there is tangential acceleration α (since α = τ/I where I = rotational inertia of block)and thus no change in angular speed ω (since α = Δω/Δt, α = 0 ⇒ Δω/Δt ⇒ Δω = 0).
Since there is a no change in angular speed, there is thus no change in angular momentum.
Thus, the tension in the cord causes no change in angular momentum.
b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius.
The centripetal force in the cord is equal to the tension at the smaller radius.
We find the angular speed of the block from v = rω where v = initial tangential speed of block at r = 0.5 m = 0.9 m/s and r = 0.5 m.
So, ω = v/r = 0.9 m/s ÷ 0.5 m = 1.8 rad/s
The centripetal force at radius r = 0.23 m is F = mrω² where m = mass of block = 0.150 kg, r = distance = 0.23 m and ω = angular speed = 1.8 rad/s
So, F = 0.150 kg × 0.23 m × (1.8 rad/s)²
F = 0.150 kg × 0.23 m × 3.24 rad²/s²
F = 0.11178 kgmrad²/s²
F ≅ 0.112 N
c) How much work was done by the person who pulled on the cord
From work-kinetic energy principles, the work done by the tension equals the kinetic energy change of the block.
ΔK = W
1/2m(v₂² - v₁²) = W where m = mass of block = 0.150 kg, v₁ = initial speed of block = 0.9 m/s, v₂ = final speed of block distance r = 0.23 m,
Since the tangential speed v ∝ r the radial distance,
v₂/v₁ = r₂/r₁
v₂ = (r₂/r₁)v₁
= 0.23 m × 0.9 m/s ÷ 0.5m
= 0.207 m²/s ÷ 0.5 m
= 0.414 m/s
So, W = 1/2m(v₂² - v₁²)
W = 1/2 × 0.150 kg((0.414 m/s)² - (0.9 m/s)²)
W = 1/2 × 0.150 kg((0.1714 m/s)² - (0.81 m/s)²)
W = 1/2 × 0.150 kg((-0.6386 m²/s²)
W = 1/2 × -0.09579 kgm²/s²)
W = -0.0479 kgm²/s²
W = -0.0479 J
W ≅ -0.048 J
what are the Properties of Transverse Waves and Longitudinal wave
Answers
Answer:
Key terms
TermMeaningTransverse waveOscillations where particles are displaced perpendicular to the wave direction.Longitudinal waveOscillations where particles are displaced parallel to the wave direction
Two cells each of EMF 1.5 v and an internal resistance of 2 ohms are connected in parallel. calculate the current flowing when the cells are connected to 1 ohm resistor
Answers
Answer:2.30
Explanation:
The types of electronic components include diodes, transistors,
and integrated circuits.
TRUE
FALSE
Answers
Yep. Those three things are all electronic components.
There are a lot more besides those.
Lithium is the lightest of metals and the least dense of all nongaseous elements. A pure lithium sample with a volume of 13.0cm^3 has a mass of 6.94g. What is the density of lithium?
Answers
Answer:
D(ensity) = M / V = 6.94 g / 13 cm^3 = .534 g / cm^3
Compare to H20 at 1 gm / cm^3
Which diagram best shows the perceived sound wave heard by a woman after a police car has passed her?
An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.
An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength longer closer to the siren and closer together the farther from the siren on both sides.
An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren that are concentric and evenly spaced.
An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength changing in all directions.
Answers
Answer:
A. An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.
The diagram best shows the perceived sound wave heard by a woman after a police car has passed her is
An illustration of a person listening to the siren of a passing police car. There are circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.
The correct option is first.
What is wavelength?The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
The diagram representing circles spreading out from the siren with the wavelength close together in the front and farther apart in the back.
Thus, the correct option is first.
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How does the digestive system help the muscular system?
A.
The digestive system absorbs the nutrients necessary for the functioning of the muscular system.
B.The digestive system delivers the blood used by the muscular system.
C.
The digestive system exchanges gases used by the muscular system.
D.The digestive system provides structural support to the muscular system.
Answers
Answer:
I would say the answer is A... but I'm not so sure ....
At what voltage can a 10 μF capacitor be energized to 0.45 J?
Answers
Given :
Capacity of capacitor is, [tex]C = 10\ \mu F[/tex].
To Find :
At what voltage can a 10 μF capacitor be energized to 0.45 J.
Solution :
We know, energy in capacitor is given by :
[tex]E = \dfrac{CV^2}{2}[/tex]
So,
[tex]V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V[/tex]
Therefore, voltage required is [tex]0.3 \ \mu V[/tex] .
light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of this frequency of light?
Answers
Answer:
4.13×10⁻⁷ m
Explanation:
Applying
v = λf................... Equation 1
Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.
make λ the subject of the equation
λ = v/f....................... Equation 2
Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.
From the question,
Given: f = 7.26×10¹⁴ Hz
Constant: v = 3×10⁸ m/s
Substitute these values into equation 2
λ = (3×10⁸)/(7.26×10¹⁴)
λ = 4.13×10⁻⁷ m
calculate their densties in Si unit.
200mg,0.0004m
Answers
Question: calculate their densties in Si unit.
200mg,0.0004m³
Answer:
0.5 kg/m³
Explanation:
Applying,
D = m/V........................ Equation 1
Where D = density, m = mass, V = volume.
From the question,
Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³
Substitute these values into equation 1
D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)
D = 2/4
D = 0.5 kg/m³
Hence the density in S.I unit is 0.5 kg/m³
You toss a ball at 30 m/s straight upwards. How much time will take the ball to reach the top of its path?
Answers
Answer:
Explanation:
One thing we need to remember is that at the max height of parabolic motion, the velocity is 0 (because the object has to stop for a millisecond in the air to turn around and head back down). Use the one-dimensional motion equation
v = v₀ + at and filling in:
0 = 30 + (-9.8)(t) and
-30 = -9.8t so
t = 3 seconds
write down two advantages of parallel combination
Answers
Answer:
In parallel combination each appliance gets the full voltage.
If one appliance is switched on/of others are not affected.
The parallel circuit divide the current through the appliances.
In a parallel combination it is very easy to connect or disconnect a new appliance without affecting the working of other appliances.
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Explanation:
If 230 W of power is produced in 10 seconds, how much work is done?
Answers
Answer:
Hello There!!
Explanation:
Use this equation:Work done = Force x Distance.
Work done=230W×10s
Work done=2300J
hope this helps,have a great day!!
~Pinky~
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
Work done = force × distance
work done = 230W×10s
work done = 2300J
Thanks hope it helps.Which component of a galaxy is often found between the stars and looks like a cloud or smoke?
Dust
Gas
Object
Star
Answers
Answer:
Hey I would say Dust
hope this helped
Answer:
The answer is A/Dust
Explanation:
is ammonia a substance
Answers
Answer:
yes
Explanation:
it is regulated in United States that is non flamable gas
9. Calculate the kinetic or potential energy in joules for each of the following situations: a. A 2.5 kg book is held 2.0 m above the ground. b Anabolieman
Answers
Explanation:
[tex]kinetic \: energy = \frac{1}{2} m {v}^{2} \\ but \: {v}^{2} = {u}^{2} + 2gh \\ {v}^{2} = 0 + (2 \times 10 \times 2) \\ v = 6.32 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times 2.5 \times 6.32 {}^{2} \\ = 50 \: joules[/tex]
[tex]potential \: energy = mgh \\ = 2.5 \times 2 \times 10 \\ = 50 \: joules[/tex]
do transistors amplfy a.c or d.c
Answers
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
Answer:
Yes,by using direct coupling(transistors) amplifier we will amplify low frequency (DC) signals. A transistor is certainly capable of taking a small-current input signal and controlling a high-current output at the same voltage, thereby amplifying the power of the input signal whether it's AC or DC.
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