Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. The child pushing the sled is exerting a horizontal a force of 8.00 N. There is a force of friction of 5.00 N. What is the acceleration of the sled? Round the answer to the nearest hundredth
how does bimettalic strip work?
factorise x^3 - 3x^2 - 9x - 5
Answer:
(x +1), (x -5) and (x +1)
Explanation:
The computation of the factorization is shown below
Data provided in the question
[tex]X^3 - 3x^2 - 9x - 5[/tex]
Based on the above information, the factors are
Now we have to open these equations in order to get the factors which are as follows
[tex]= x^3 + x^2 - 4x^2 - 4x - 5x - 5[/tex]
[tex]= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)[/tex]
[tex]= (x + 1) (x^2 - 4x - 5)[/tex]
[tex]= (x + 1)(x^2 -5x + x - 5)[/tex]
So,
= (x + 1) (x - 5) (x + 1)
Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question
what is the velocity of an object that has been in free fall for 2.5 seconds??
Answer:
calculate the free fall distance and velocity without air resistance from, the free fall. i hope that helps
Explanation:
A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car's average velocity?
Answer:
v = -4 m / s
Explanation:
The average speed of a body is defined by the distance traveled in a given time interval
v = (x₂ -x₁) / (t₂ -t₁)
in this case the end point is x₂ = -10 m and the start point is x₁ = 10 m, the negative sign is because the point is below the reference that can be considered as zero point
let's calculate
v = (-10 - 10) / 5
v = -20 / 5
v = -4 m / s
PLEASE HELPPPPP 1 gal 4 qt and 1 quart 0.946 l. how many liters are in a gallon a 1.06L b 3.78 L c 4.23 L d 4.95 L
Answer: b. 3.78
Explanation:
ASAP! HELP!
A 66.4 kg person sits on the right end of a seesaw, 2.35m from the fulcrum. On the other end, how far from the fulcrum should a 84.2kg person sit to balance the seesaw?
1: 1.92 m
2: 1.85m
3: 2.08m
4: 1.61 m
Answer:
2. 1.85
Explanation:
the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85
A high surface tension results from _____.
Answer:
Capillary Action.
Explanation:
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
if the period wave is 6 seconds what is its frequency
Answer:
.17Hz
Explanation:
The formula for frequency is f= 1/T , where T is the period.
f = 1/6 and 1/6 ≈ .17
Does the speed of the object affect friction?
So which one would increase friction, going slowly, or going fast.
If possible an explanation? Thanks a bunch. :D
Answer:
it would
Explanation:
this is because as something rubs against a surface fast, friction heats it up, like when you rub a surface fast and it gets warm on the palm of your hand, that is friction. hope it helped :)
Pls help waves for physics
Answer:
b) 252 Hz or 260 Hz
c) 0.25 s
Explanation:
b) The frequency of the beats is 4 Hz, and one tuning fork has a frequency of 256 Hz. Therefore, the second tuning fork is either 4 Hz lower or 4 Hz higher.
f = 252 Hz or 260 Hz
c) Period is the inverse of frequency.
T = 1/f
T = 1 / (4 Hz)
T = 0.25 s
need help with ASAP please
Answer:
first blank is chemical second blank is kinetic energy
When an object is located 32 cm to the left of the lens, the image is formed 17 cm to the right of the lens. What is the focal length of the lens?
Answer: 11.1cm
Explanation:
Object distance (u) = 32cm
Image distance(v) = 17cm
Focal length(f) =?
Lens formular:
1/f = 1/u + 1/v
1/f = 1/32 + 1/17
Taking the L. C. M of 17 and 32
1/f = (17 + 32) / 544
1/f = 49/544
Taking the reciprocal
f = 544/49
f = 11.1 cm
Therefore, Focal length of the lens is 11.1cm
A substance in a solid phase (state) of matter has what?
Answer:
COMPACTED MOLECULES
Explanation:
The molecules are compacted in a solid
The________ is a membrane that surrounds a cell Nucleus
Answer:
nuclear envelope
Explanation:
it surrounds the nucleus and all of its contents
The length of a wooden rod is 25.5 cm. What is this length in:
(a) millimetres?
(b) metres?
Answer:
[tex](a)255mm \\ (b)0.255m[/tex]
Explanation:
[tex](a)1cm = 10mm \\ 25.5cm = x[/tex]
Cross multiply
[tex]1x = 25.5 \times 10 \\ x = 255mm[/tex]
[tex](b)100cm = 1m \\ 25.5cm = x[/tex]
cross multiply
[tex]100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer:
A. 255
B. 0.255
Explanation:
10mm = 1cm
100cm = 1m
<a href="https://en.wikiafripedia.org/wiki/Centimetre">Learn more</a>
https://en.wikiafripedia.org/wiki/Centimetre
Acceleration is the magnitude of average velocity true or false
Answer:
False
Explanation:
what is the working principle of lever
Answer:
Explanation:
A lever is a simple machine made of three parts: two load arms and a fulcrum. Sometimes the two arms are referred to as the force arm and the load arm, to distinguish which arm is initiating movement.
Number of atoms present in 1 mole of oxygen atom
Answer:
1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant
HELP ASAP!
Why is it misleading to include too many significant figures in a laboratory report?
Answer:
The last significant figure is inherently uncertain because of the rounding off. The rounding-off uncertainty is usually half of the last figure's decimal-place value if no other uncertainty is expressed. As a rule of thumb results of measurements and calculations have a limited number of significant figures.
A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of the truck, is pushed along the length of the ramp. If the ramp is 4.5 m long and friction between the ramp and crate can be ignored, what is the mechanical advantage of the ramp?
Answer:
3Explanation:
Using the efficiency formula. Efficiency = MA/VR * 100%
MA = Mechanical Advantage
VR = velocity ratio = [tex]\frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}[/tex]
Distance moved by effort = 4.5m
distance moved by load = 1.5m
VR = 4.5/1.5 =3
Assuming efficiency is 100% (since friction can be ignored)
100% = MA/3 * 100%
1 = MA/3
MA = 3*1
MA = 3
Mechanical Advantage of the ramp is 3
Amina has a mass of 48.4kg, what is her weight.please show calculation
G=m×g
since g=10N,
G=48.4×10
G=484
I hope it's true .d
good luck
Describe the importance of SI units?
Answer:
I wouldnt say SI unit isnt important but the Metric System certainly is. And Metric System is more closer to SI unit than imperial unit. Amongst many , the most important one is the ease of use. We upgraded the number system to base 10, why hesitate to import the measurement units to base 10.
Explanation:hop this thelps you !!! :0 :)
AS WE CLIMB UP, THE PRESSURE INSIDE OUR BODY WILL BE.................. *
1 )low
2)high
3)very high
4)same
Tom rides his skateboard 2.4km in 20 mins and Max rides his scooter 3.6km in 30 mins. Who is moving at a faster rate (speed)? Choose the correct formula and show your work. (what you are plugging into the calculator) Use proper units in your answer.
Answer:
The are both moving at the same speed
Explanation:
Given the following :
Tom = 2.4km in 20 minutes
Max = 3.6km in 30 minutes
To calculate the rider moving at a faster spedd, we need to calculate the speed of each rider.
Speed = distance / time
Tom's speed :
Distance = 2.4km = 2.4 × 1000 = 2400meters
Time = 20 minutes = 20 × 60 = 1200 seconds
Speed = (2400 / 1200) = 2 meter per second
Max's speed :
Distance = 3.6km = 3.6 × 1000 = 3600meters
Time = 30 minutes = 30 × 60 = 1800 seconds
Speed = (3600 / 1800) = 2 meter per second
Both Tom and Max are riding at the same speed(rate)
the apparent weight of a body wholly immersed in water is 32N and its weight in 96N and calculate volume of the body
Answer:
0.0065 m³
Explanation:
Apparent weight = weight − buoyancy
32 N = 96 N − (1000 kg/m³) (9.8 m/s²) V
V = 0.0065 m³
A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?
Whoever answers will get the Brainliest.
Answer:
Explanation:
Given height of lamp from the ceiling = 2.6m
mass of the lamp = 3.8kg
acceleration due to gravity = 9.81m/s²
As the body falls to the ground, it falls under the influence of gravity.
Gravitational potential energy = mass*acc due to gravity * height
Gravitational potential energy = 3.8*2.6*9.81
Gravitational potential energy = 96.923 Joules
b) Kinetic energy = 1/2 mv²
m = mass of the body (in kg)
v = velocity of the body (in m/s²)
To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]
[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]
Since mass = 3.8kg
[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]
c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s
If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?
Answer:
3200kg
Explanation:
F=ma
16000=5m
m=3200kg
Hope this helps!
The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.
It is given that:
If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons
As we know,
Newton's second law:
F = ma
Here F is the force acting on an object.
m is the mass of the object
a is the acceleration of the object.
a = 5 m/s²
F = 16,000 N
m = 3200kg
16000 = 5m
3200 kg
Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
Learn more about the mass here:
https://brainly.com/question/15959704
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Using newtons law How much force is accelerated a 66kg skier 2m/s2
Answer:
SUPONIENDO QUE NO HAY FRICCIÓN
Explanation:
F = 66 kg([tex]2 m/s^{2}[/tex]) = 132 N
HELP ASAP!!! 100 points!!!!!!!!!
Indicate what happens to the resonant frequency of a mass-and-spring system which acts as simple harmonic oscillator when the following things are changed:
Only the spring constant,k, of the mass-and-spring system is increased.
Only the mass of the mass-and-spring system is increased.
Only the amplitude of the mass-and-spring system is increased.
Choices: Frequency increases, decreases or stays the same.
Answer:
Shown from explanation.
Explanation:
The resonant frequency is related by the formula;
Fo= 1/2π√(K/M)
Where Fo is resonant frequency
M is mass
K is the spring constant
From the expression above;
When K is increased frequency would increases since frequency is directly proportional to spring constant.
Similarly when the mass is increased the frequency decreases since frequency is inversely proportional to the mass.
Amplitude is a property of a wave and so the frequency stays same.
Answer:
Hi!
So, this is what you need to do.
Fo = 1/2 π √(K/M)
The m = mass (in case you didn't know)
Explanation:
That should help you with your answer :)