Answer:
to me equity means a fair treatment, access, opportunity, and advancement for all people, while at the same time striving to identify and eliminate barriers that have prevented the full participation of some groups
Explanation:
A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.
Answer:
The value is [tex]x = 200000000 \ m[/tex]
Explanation:
From the question we are told that
The distance between the earth and the moon is [tex]d = 200000 \ km[/tex]
Generally ,
[tex]1 \ km = 1000 \ m[/tex]
[tex]200000 \ km \to x \ m[/tex]
=> [tex]x = \frac{200000 * 1000}{1 }[/tex]
=> [tex]x = 200000000 \ m[/tex]
A cyclist moves a distance of 30 m from points A to B in a straught line towards East with a speed of 10 m/s. He then moves a distance of 40 m from points B to C in a straight line towards North with a speed of 20 m/s. Calculate the cyclist's (1) Average Speed, (2) Average Velocity, for the whole journey
Answer:
Average speed is 14 m/s and average velocity is 10 m/s.
Explanation:
The time consumed to travel from A to B = Distance / Speed = 30 / 10 = 3 seconds
The time consumed to travel from B to C = Distance / Speed = 40 / 20 = 2 seconds
Now, we find the average speed by using the below formula.
Average speed = total distance / total time
Average speed = (30 +40) / (3 + 2)
Avergae speed = 70 / 5 = 14 m/s.
Now find the average velocity.
Average velocity = displacement / time
Displacement, distance between A to C = [(30)^2 + (40)^2]^1/2 = 50 m
Average velocity = 50 / (3+2) = 10 m/s
Two particles with positive charges q1 and q2 are separated by a distance s. Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges zero
Answer:
The distance is [tex]z = \frac{1 + \sqrt{ \frac{k * q_2 }{ k * q_1}}}{s}[/tex]
Explanation:
From the question we are told that
The positive charges is [tex]q_1 \ and \ q_2[/tex]
The distance of separation is [tex]s[/tex]
Generally at the point where the electric field is zero would be a point where
The electric field due to [tex]q_1[/tex] = The electric field due to [tex]q_2[/tex]
Generally the electric field due to [tex]q_1[/tex] is mathematically represented as
[tex]E_1 = \frac{k * q_1}{ z^2 }[/tex]
Since we are taking our reference from [tex]q_1[/tex] then the electric field due to [tex]q_2[/tex] is mathematically represented as
[tex]E_2 = \frac{k * q_2}{ (s- z)^2 }[/tex]
So
[tex]\frac{k * q_1}{ z^2 } = \frac{k * q_2}{ (s- z)^2 }[/tex]
[tex]k * q_1 * (s- z)^2= k * q_2 * z^2[/tex]
[tex][ \frac{s -z }{z} ]^2 = \frac{k * q_2 }{ k * q_1}[/tex]
[tex]\frac{s -z }{z} = \sqrt{ \frac{k * q_2 }{ k * q_1}}[/tex]
[tex]\frac{s}{z} - 1 = \sqrt{ \frac{k * q_2 }{ k * q_1}}[/tex]
[tex]z = \frac{1 + \sqrt{ \frac{k * q_2 }{ k * q_1}}}{s}[/tex]
Can some please help me ? Thank you!
Answer:
Hey ! I think I can help with this question.
In the diagram you were given the speed which is 5.25m/s and you were also given distance which is 950metres.
So the formula which will be suitable in my own way will be speed=distance/time....Since you weren't given the time,then you can place the numbers in their respectively places which will be 5.25=950/time....Then you will cross multiply which will be 5.25t=950....Then 950÷5.25=180.952381 which is approximately 181. then don't forget to add your unit, time is measured in seconds so the answer is going to be 181seconds.This is what I know...I hope this helps you.....Thank you for the question
A train goes 25000 m East in 1500 sec and then turns around and travels 29,000 m West for 1740 sec. Determine the distance, speed, displacement, and velocity.
Answer:
scalar d = 54000 m , v_average = 16,667 m / s
vector d = -4000 m , moved 4000 to the west
v_average = 0
Explanation:
his is a uniform motion exercise, but we must be careful with quantities that are scalars and vector quantities
The distance traveled is a scalar
d = d₁ + d₂
d = 25000 + 29000
d = 54000 m
the speed is a scalar, in the exercise it is not specified if the speed of each trajectory or the average speed. Therefore we will calculate the two
v₁ = d₁ / t₁
v₁ = 25000/1500
v₁ = 16,667 m / s
v₂ = 29000/1740
v₂ = 16,667 m / s
Since the two speeds are equal, the average speed is
v = (v1 + v2) / 2
v_average = 16,667 m / s
now let's calculate the displacement that is a vector, so it has direction in addition to modules
suppose the eastward direction is positive and the bold are vectors
d = d₁ - d₂
d = 25000 - 29000
d = -4000 m
this means that it moved 4000 to the west
velocity is a vector, we assume positive eastward movement
v₁ = 16,667 m / s
v₂ = - 16,667 m / s
v_average = (v1 -v2) / 2
v_average = 0
Sliding a box is work against friction. Answer in short.
Answer:
Sliding a box is work against friction because force applied to move the box is in oppose of friction.
Rose’s checking account has a balance of Negative 54 dollars. She makes no more withdrawals but deposits $15 per day in her account over the next five days. On the sixth day, she makes no deposits, but the bank charges a maintenance fee of $5. What is the balance in her account on the sixth day?
Answer: $16
Explanation: The equation is:
x = -54 + (5 x 15) -5
x = -54 + 75 - 5 [remember to use PEMDAS!]
x= 21 - 5
x = 16 dollars
The answer is: $16
Proof⬇⬇
Using this equation: LaTeX: v\:=\frac{\Delta x}{\Delta t}v = Δ x Δ t, solve for LaTeX: \Delta tΔ t Group of answer choices LaTeX: \Delta t\:=\frac{v}{\Delta x} Δ t = v Δ x Δ t = v Δ x LaTeX: \Delta t\:=\Delta x\:.\:v Δ t = Δ x . V Δ t = Δ x . V LaTeX: \Delta t\:=\frac{\Delta x}{v} Δ t = Δ x v LaTeX: \Delta t\:=\Delta x-v
Answer:
[tex]\Delta t = \dfrac{\Delta x}{v} \\\\[/tex]
Explanation:
Given the expression [tex]v\:=\dfrac{\Delta x}{\Delta t}[/tex], we are to find the value of Δt from the expression. To find Δt, we will make Δt the subject of the formula from the given expression as shown;
[tex]v\:=\dfrac{\Delta x}{\Delta t}\\\\cross\ multiply\\\\v*\Delta t = \Delta x\\\\Divide \ both\ sides \ of\ the \ resulting \ equation \ by \ v\\\\\dfrac{v*\Delta t}{v} = \dfrac{\Delta x}{v} \\\\\Delta t = \dfrac{\Delta x}{v} \\\\[/tex]
Hence the equivalent expression for [tex]\Delta t = \dfrac{\Delta x}{v} \\\\[/tex].
If a 2000 kg car is at rest and a 500 N force is applied to it. What acceleration will it experience?
WHAT WAS THE ACCELERATION OF THE CART WITH THE LOW FAN SPEED?
Answer:
18.0 cm/s2
Explanation:
Which of the following is a science? (2 points)
A
Chemistry
B
Anthropology
C
Baseball statistics
D
Art
Chemistry is a subject studied in science.
What is Chemistry?Chemistry is the branch of Physical science, which undergoes the study of composition, structure, function, properties i.e., physical properties and chemical properties of the matter ( Solid, Liquid and Gas ) and the changes it undergoes.
Here, the matter that means that anything that have mass and occupies space.
Some of the branches of chemistry is as follows, Biochemistry, Analytical chemistry, Organic chemistry, Inorganic chemistry, Physical or computational chemistry.
Chemistry also studies the chemical interactions (bonding) between elements, atoms and molecules and also chemistry affects all aspects of life and mostly affects the natural process. Chemical things have been used much in our day today life.
Here, Anthropology is the study of Human beings, Baseball statistics can be studied under game or sports, Art is the study of culture.
Hence, Option A is the correct answer.
Learn more about Chemistry,
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In an element’s square on the periodic table, the number with the greatest numerical value represents the
number of neutrons.
number of electrons.
atomic number.
atomic mass
Answer:
Atomic mass I Just did the quiz and got 100% for edge
This is a science Question. Please help.
Answer:
B
Explanation:
This is a physics question, know that force is equals to mass divided by acceleration (acc.), so if the same force is applied, say 10 Newton and the mass of A is 2 and the mass of B is 4, then the acceleration of A is 0.2 and that of B is 0.4 by equating, and this applies to all cases.
How do think animals grow from babies to adults
Answer:
As animals get older, their bodies begin to change as well as their instincts and priorities. They get bigger and might adapt or develop.
Convert 142 weeks into years
Answer:
142 weeks/52 weeks per year = 2.7 years
so the answer is 2.7 years
Explanation:
Ganymede, one of Jupiter's moons, has a gravitational force of only 0.146 that of Earth. If a space probe with a mass of 126 kg on Earth lands on Ganymede, what would its mass be
Answer:
The mass of the space probe on Ganymede is 126 kg, and its weight is 180.2808 N.
Explanation:
The force of gravity, g, on the earth is 9.8 m/[tex]s^{2}[/tex].
The gravitational force on Ganymede = 0.146 × g
= 0.146 × 9.8
= 1.4308 m/[tex]s^{2}[/tex]
The gravitational force on Ganymede is 1.4308 m/[tex]s^{2}[/tex].
Mass of space probe on Earth is 126 kg.
Weight of the space probe on Earth = m × g
= 126 × 9.8
= 1234.8 kgm/[tex]s^{2}[/tex]
Weight of the space probe on Earth is 1234.8 N.
Since mass is constant, the mass of the space probe on Ganymede is 126 kg.
Weight of the space probe on Ganymede = m × g
= 126 × 1.4308
= 180.2808 kgm/[tex]s^{2}[/tex]
Weight of the space probe on Ganymede is 180.2808 N.
Answer:
126 kg
Explanation:
Mass is a constant for a body, and does not change with location.
A tennis ball moves 18 meters northward, then 22 meters
southward, then 14 meters northward, and finally 28 meters
southward.
What is the magnitude and direction of the displacement
Answer:
Magnitude = 18 m
Direction = southward
Explanation:
Given that a tennis ball moves 18 meters northward, then 22 meterssouthward, then 14 meters northward, and finally 28 meters
southward.
To calculate the displacement, let the
Northward = positive direction
Southward = negative direction
Displacement = 18 - 22 + 14 - 28
Displacement = 32 - 50
Displacement = - 18
Since the answer is negative,
The magnitude will be 18 m and direction of the displacement is southward
If a positively charged body is moved against an electric field it will gain?
Answer:
positive charge
Explanation:
Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of electric charge: positive and negative.
hope it helps :)
please mark it the brainliest!
A car drives at a constant speed of 40 m/s for 1000s how far does it go
Answer:
40,000 meters
Explanation:
We want to find how far the car travels, or the distance. Therefore, we can use the following formula:
[tex]d= s*t[/tex]
where [tex]s[/tex] is the speed and [tex]t[/tex] is the time
The speed of the car is 40 meters per second and the time is 1000 seconds. Therefore,
[tex]s= 40 m/s*\\t=1000s[/tex]
Substitute the values into the formula.
[tex]d= 40 m/s * 1000s[/tex]
Multiply. When you multiply, the 2 "s" variables will cancel out.
[tex]d= (40 m*1000)[/tex]
[tex]d= 40,000 m[/tex]
The distance traveled by the car is 40,000 meters.
3) Determine how many Altuves you could travel in a day if you were moving at 45.000 mph all day. 1 Altuve=1.65 m. 1 inch=2.54 cm. 1 mile=5280 ft
Answer:
Hey there!
Step one: Find how many miles you can travel per day.
45(24)=1008. You could travel 1008 miles a day.
Step two: Convert 1008 miles to meters.
1008 miles roughly equals 1622219 meters.
Step three: Convert meters to Altuves.
1622/1.65=983.03 Altuves.
Let me know if this helps :)
The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your school would be exactly twice as much if your school:
Explanation:
It is given that, the force of gravity pulls down on your school with a total force of 400,000 N.
The force of gravity is given by the formula as follows :
F = mg
m is mass and g is the acceleration due to gravity
Mass of an object remains same always. But if the mass of your school becomes twice of the initial mass, the force of gravity pulling down on your school would be exactly twice.
1. Plot the following graphs:
(a) distance –time graph for an object with uniform speed
(b) distance –time graph for an object with non- uniform speed
(c) velocity –time graph for uniform motion of a car
(d) Velocity –time graph for a car moving with uniform accelerations.
(e) Velocity –time graph for a car moving with non- uniform accelerations.
(f) A body at rest
Answer:
(a) The distance-time graph for an object with uniform speed is giving by a straight line sloped graph with a constant positive or negative gradient as shown in the attached diagram
(b) The distance-time graph for an object with non-uniform speed is giving by a curved line sloped graph with varying gradient as shown in the attached diagram
(c) The velocity-time graph for a car with uniform motion is giving by a horizontal line graph at the speed of constant motion with a zero gradient as shown in the attached diagram
(d) The velocity-time graph for a car moving with uniform acceleration is giving by a straight line sloped graph with a constant positive or negative gradient as shown in the attached diagram
(e) The velocity-time graph for a car moving with non-uniform acceleration is giving by a curved line sloped graph with varying gradient as shown in the attached diagram
(f) According to Newton's first law of motion, an object at rest will remain at rest with no motion unless acted by a force, an therefore, will have no motion with time
Explanation:
Why do specific heat capacity of objects differ?
how can energy and matter connected?
Answer:
Energy is a property that matter has. The same amount matter can have different amounts of energy and so represent different states of matter. For example, if you add energy to an ice cube made of water, it becomes liquid water, and if you add even more energy, it becomes steam.
Explanation: Look At Answer
In a liquid with a density of 1050 kg/m3, longitudinal waves with a frequency of 450 Hz are found to have a wavelength of 7.90 m. Calculate the bulk modulus of the liquid
Answer:jdhddj Nd
Explanation:xbxnbxx period
How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h if the cars' front bumpers are initially 119 m apart?
Answer:
The time taken is [tex]t = 32.5 \ s[/tex]
Explanation:
From the question we are told that
The speed of first car is [tex]v_1 = 66.7 \ km/h = 18.3 \ m/s[/tex]
The speed of second car is [tex]v_2 = 52.7 \ km/h = 14.64 \ m/s[/tex]
The initial distance of separation is [tex]d = 119 \ m[/tex]
The distance covered by first car is mathematically represented as
[tex]d_t = d_i + d_f[/tex]
Here [tex]d_i[/tex] is the initial distance which is 0 m/s
and [tex]d_f[/tex] is the final distance covered which is evaluated as [tex]d_f = v_1 * t[/tex]
So
[tex]d_t = 0 \ m/s + (v_1 * t )[/tex]
[tex]d_t = 0 \ m/s + (18.3 * t )[/tex]
The distance covered by second car is mathematically represented as
[tex]d_t = d_i + d_f[/tex]
Here [tex]d_i[/tex] is the initial distance which is 119 m
and [tex]d_f[/tex] is the final distance covered which is evaluated as [tex]d_f = v_2* t[/tex]
[tex]d_t = 119 + 14.64 * t[/tex]
Given that the two car are now in the same position we have that
[tex]119 + 14.64 * t = 0 + (18.3 * t )[/tex]
[tex]t = 32.5 \ s[/tex]
what is a conversion factor?
Answer:
It is often necessary to convert from one unit to another. For example, if you are reading a European cookbook, some quantities may be expressed in units of liters and you need to convert them to cups. Or perhaps you are reading walking directions from one location to another and you are interested in how many miles you will be walking. In this case, you may need to convert units of feet or meters to miles.
Explanation:
Because of research
What is the name(s) of your instructor(s)?
Answer:
they name if my instructor is mrs. Rodriguez
Which perspective emphasizes how we store and retrieve information? A. Cognitive behavioral B. Positive psychology C. Biopsychology D. Social
Answer:
a
Explanation:
Speeding truck slams on the brakes and accelerates at -7.40m/s^2 Before coming to a stop. It leaves skid marks on the pavement that are 43.1m long. How fast was the truck going before it slammed on the breaks?
Answer:
25.2563 m/s
Explanation
This is the equation needed
[tex]$v^2 = u^2 + 2ad$ where v is the final velocity, u is the initial velocity, a is the acceleration, and d the distance[/tex]
So Just plug in!