what element is represented by the orbital diagram above?

a- iron

b- calcium

c- krypton

d- zinc

Answer:

0.10 L

Explanation:

First we convert the 2.0 grams of solute (meaning sodium hydroxide) into moles, using its molar mass:

Then we can calculate the required volume of solution, using the definition of molarity:

Answer:

C: No correct response

Explanation:

Bond length is simply defined as the distance between two atoms that are participating in a bond.

Now, looking at the options, none of the options correctly defines it this way. The closest is option E which is "distance between two electrons" but it uses the word electrons instead of atoms. Thus none of the statements are correct

Answer:

B

Explanation:

an alkene because of the presence of the double bond

alcohol because of the presence of the OH group

Answer:

oficialismo hemostasia Jalisco

Answer:

K

Explanation:

Potassium is atomic no 19 and it is k because is from kalium, the Meldiaeval Latin for potash, which may have derived from an arabic word quality, meaning alkali.

Atomic mass, 39.098amu

Oxidation status, +1

Year discovered, 1807

Melting point, 63.28 degrees Celsius(145.90degrees Fahrenheit )

Boiling point, 760 degrees Celsius (1400 degrees Fahrenheit )

Answer:

The answer is "Option D".

Explanation:

The behavior of 0.1M NaCl also isn't substantially larger objectively than those of 0.05M NaCl because a p-value above 0.05 (p>0.05) indicates no ability to tell differential and is a strong proof in favor of a null hypothesis.

The other wrong choices can be defined as follows:

Answer:

2731.875 J

Explanation:

Applying

Q = cm(t₂-t₁)................ Equation 1

Where Q = amount of heat, c = specific heat capacity of silver, m = mass of silver, t₂ = Final temperature of silver, t₁ = Initial temperature of silver

From the question,

Given: c = 0.235 J/g°C, m = 250 g, t₁ = 22.0°C, t₂ = 68.5°C

Substitute these values into equation 1

Q = 0.235×250(68.5-22.0)

Q = 58.75(46.5)

Q = 2731.875 J

Answer:

81 gm

Explanation:

The mass of 1 mole is 27 g

So, Mass of 3 moles of Aluminium would be 3 × 27 = 81 gm..Thus mass of 3 Moles of Aluminium is 81 gm.

Answer:

a. 2.44 nm

b. 15.33 nm²

Explanation:

a. Calculate the thickness (in nm) of the surface film

Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²

The volume of the oil film, V' equals the volume of the oil in the teaspoon, V

V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film

So, V' = V

Ah = V

h = V/A

= 4.93 cm³/2023.43 × 10⁴ cm²

= 0.00244 × 10⁻⁴ cm

= 2.44 × 10⁻⁷ cm

=  2.44 × 10⁻⁷ cm × 1m/100 cm

= 2.44 × 10⁻⁹ m

= 2.44 nm

b. The surface area (in nm2) occupied by an oleic acid molecule on water.

Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²

r = h/2 = 2.44 nm/2 = 1.22 nm

A = 4πr²

A = 4π(1.22 nm)²

A = 4.88π nm²

A = 15.33 nm²

[tex]\huge\bf\red{\underline{\underline{Answer:-}}}[/tex]

Here, 16 L = 0.80 Mole

_____________________________

Answer:

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Explanation:

To find - Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest. Justify this ranking.

Solution -

Ranking is as follows :

(d) 0.80 wt% C with fine pearlite.

(b) 0.80 wt% C with spheroidite

(a) 0.25 wt% C with coarse pearlite

(c) 0 25 wt% C with spheroidite

Justification -

For some wt% C,

Fine pearlite is stronger than spheroidite

and

Coarse pearlite is stronger than spheroidite.

Now,

Due to carbon content,

0.80 wt% C with spheroidite is stronger than 0.25 wt% C with coarse pearlite.

So,

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Answer:

700 calories

Explanation:

Using the formula below:

Q = m × c × ∆T

Where;

Q = amount of heat required (calories)

m = mass of substance (g)

c = specific heat of substance (cal/g°C)

∆T = change in temperature (°C)

According to this question, the following information was provided;

Q = ?

m = 20g

c = 1.0 cal/g °C

∆T = 40°C - 5°C = 35°C

Using the formula; Q = m × c × ∆T

Q = 20 × 1 × 35

Q = 700 calories

Hence, 700 cal of heat energy is needed to raise 20 g of H2O from 5°C to 40°C.

Balanced Equation is

4H2SiCl2+4H2O → H8Si4O4 + 8HCl

Answer:

Climate change will make plants—and us—thirstier. The combined effects of increased CO2 levels and warmer temperatures will increase water consumption by vegetation. That will lead to water declines in streams and rivers like the Ashepoo River in South Carolina

Explanation:

Answer:

Answer:

D. C triple bond C.

Explanation:

The absorption frequency value is highest for carbon-carbon triple bond. The stretching frequencies are much higher than the bending frequency. It mainly depends upon the strength of the bonds as well as masses of the bonded atoms.

The triple bonds have higher stretching strength than the double bonds and double bonds have higher strength than single carbon to carbon bonds.

The triple bonds has a higher bond order, i.e. 3. So it has maximum stretching bonds.

Answer: A volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.

Explanation:

Given: [tex]V_{1}[/tex] = ?,          [tex]M_{1}[/tex] = 10 M

[tex]V_{2}[/tex] = 100 mL,            [tex]M_{2}[/tex] = 5 M

Formula used to calculate the volume is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\10 M \times V_{1} = 5 M \times 100 mL\\V_{1} = 50 mL[/tex]

Thus, we can conclude that a volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.

Answer:

39.57 °C

Explanation:

Applying,

Heat gain = Heat lost.

cm'(t₃-t₁) = cm(t₂-t₃)................. Equation 1

Where c = specific heat capacity of water, m = mass of the hotter water, m' = mass of the colder water, t₁ = initial temperature of the colder water, t₂ = initial temperature of the hotter water, t₃ = Final Temperature.

Equation 1 above can futher be simplified to

m'(t₃-t₁) = m(t₂-t₃)................. Equation 2

From the question,

Given: m' = 155 g, m' = 75 g, t₁ = 20 °C, t₂ = 80 °C

Substitute these values into equation 2

155(t₃-20) = 75(80-t₃)

Solve for t₃

155t₃- 3100 = 6000-75t₃

155t₃+75t₃ = 6000+3100

230t₃ = 9100

t₃ = 9100/230

t₃ = 39.57 °C

Assuming no heat is lost to the surrounding, the final temperature of the water is 39.57°C.

Given the following data:

To determine the final temperature of the water, assuming no heat is lost to the surrounding:

The quantity of heat lost by the water 1 = The quantity of heat gained by the water 2.

[tex]Q_{lost} = Q_{gained}\\\\m_1c\theta = m_2c\theta\\\\m_1\theta = m_2\theta\\\\m_1(T_2 - T_1) = m_2(T_3 - T_2)[/tex]

Substituting the given parameters into the formula, we have;

[tex]155(T_2 -20)=75(80-T_2 )\\\\155T_2 -3100=6000-75T_2\\\\155T_2 +75T_2=6000+3100\\\\230T_2=9100\\\\T_2=\frac{9100}{230}[/tex]

Final temperature = 39.57°C

Read more: https://brainly.com/question/6957411

Answer:

Plastics!!!!!

Explanation:

How do you print stone or honey or wood you melt plastic or filiment to print stuff

Answer:

atoms of C? 2.25 x 1022 atoms C x 1 mole C = 0.037 mol C

Explanation:

 How many moles of C are in 2.25 x 1022 atoms of C?

Taking into account the definition of Avogadro's number, 0.037 moles of carbon are 2.25×10²² atoms of carbon.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of moles of carbons

In this case, you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of carbon, then 2.25×10²² atoms are contained in how many moles of copper?

amount of moles of carbon= (2.25×10²² atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of carbon= 0.037 moles

Finally, 0.037 moles of carbon are 2.25×10²² atoms of carbon.

Learn more about Avogadro's Number:

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Answer:

I'm so sorry if this is wrong but I think its B

Answer:

3.31x10^24 atoms

Explanation:

1 mole of S atom = 6.023^23 atoms

5.5 moles            = 5.5 x 6.023^23

                           = 3.31x10^24 atoms

Answer:

si.mple fe

Explanation:

ghhsshzhzbbzhh

Solution :

A complex ion may be defined as a metal ion that is located at the center with other molecules or ions surrounding the center ion.

In the context, the number of the unpaired electrons for the following complex ions are :

1. [tex]$Ru(NH_3)62+$[/tex]  (low spin)

  [tex]$Ru^{2+} = [Kr] \ 4d^6 \ 5s^0$[/tex]

   Here all the d-electrons are paired. Therefore, there are no unpaired electrons.

2. [tex]$Ni(H_2O)62+$[/tex]  (high spin)

   [tex]$Ni^{2+} = [Ar] \ 4s^0 \ 3d^8$[/tex]

   Therefore, it has two unpaired electrons.

3. [tex]$V(en)33+$[/tex]  (high spin)

    [tex]$V=[Ar] \ 3d^2 \ 4s^0$[/tex]

   It has 2 unpaired electrons

Answer:

True

Explanation:

Diffusion is the movement of the particles of a substances from a region of higher concentration to a region of lower concentration.

Diffusion occurs in response to a concentration gradient.

In this case, the dye is at a higher concentration at the middle of the shallow dish of water. Diffusion causes the dye to spread out gradually thereby causing the red cloud to grow larger with time.

Answer:

a. The resonance effect of the hydroxyl group stabilizes the anionic intermediate

Explanation:

The resonance effect stabilizes the the charge through the delocalization of the pi bonds. The resonance stabilization mainly occurs in the conjugated pi systems.

For example, phenol forms a strong hydrogen bonds than the nonaromatic alcohols as the [tex]$O_2-H_2$[/tex] dipole present in the hydroxyl group is being stabilized by the presence of the aromatic ring of phenol.

Thus the resonance effect of the hydroxyl group stabilizes the anionic intermediate.