What happens to the electrical energy that does not become light energy?
A. The lightbulb transforms it into mechanical energy,
B. The lightbulb transforms it into thermal energy.
C. Some of the energy is destroyed over time rather than being
conserved
D. New energy is produced in the system when the lightbulb creates
light energy
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Answer:

Intensity at 12 meters will be 11.11 W/m^2

Explanation:

Recall that the intensity of sound is inversely proportional to the square of the distance from the source. Therefore, if at 4 m the intensity is 100 W/m^2

we have: 100 W/m^2 = k/16 and therefore, k = 1600 W

Then the intensity (I) at 12 m will be:

I = k/12^2 = 1600/144  W/m^2 = 11.11 W/m^2

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

From the question we have

[tex]V_2 = \frac{0.4 \times 500000}{0.9} = \frac{200000}{0.9} \\ = 222222.2222... \\ = 222222[/tex]

We have the final answer as

Hope this helps you

Answer:

V₀ = 45.81 m/s

H = 70.45 m

T = 5.36 s

Explanation:

The motion of the spare is projectile motion. Therefore, we will first use the formula of range of projectile:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 201.24 m

V₀ = Initial Speed = ?

θ = Launch Angle = 35°

g = 9.8 m/s²

Therefore,

201.24 m = V₀²[Sin 2(35°)]/9.8 m/s²

V₀ = √[(201.24 m)/(0.095 m/s²)

V₀ = 45.81 m/s

Now, for maximum height:

H = V₀² Sin² θ/g

H = (45.81 m/s)² Sin² 35°/9.8 m/s²

H = 70.45 m

For the total time of flight:

T = 2 V₀ Sin θ/g

T = 2(45.81 m/s) Sin 35°/9.8 m/s²

T = 5.36 s

Answer:

The minimum inductance needed is 2.78 H

Explanation:

Given;

frequency of the AC, f = 26.5 Hz

the root mean square voltage in the circuit, [tex]V_{rms}[/tex] = 41.2 V

the maximum current in the circuit, I₀ = 126 mA

The root mean square current is given by;

[tex]I_{rms} = \frac{I_o}{\sqrt{2} } \\\\I_{rms} = \frac{126*10^{-3}}{\sqrt{2} }\\\\I_{rms} =0.0891 \ A[/tex]

The inductive reactance is given by;

[tex]X_l = \frac{V_{rms}}{I_{rms}} \\\\X_l= \frac{41.2}{0.0891}\\\\X_l = 462.4 \ ohms[/tex]

The minimum inductance needed is given by;

[tex]X_l = \omega L\\\\X_l = 2\pi fL\\\\L = \frac{X_l}{2\pi f}\\\\L = \frac{462.4}{2\pi *26.5}\\\\L = 2.78 \ H[/tex]

Therefore, the minimum inductance needed is 2.78 H

Answer:

775 N  due North.

Explanation:

If the crate is pulled South with 350 N force, and the net force on the crate results into 425 N due North, then the other force (F) acting must be larger than the 350 N, and pointing North:

F - 350 N = 425 N

F = 425 N + 350 N = 775 N  due North.

Answer:

a

[tex]H =212.6 \ J[/tex]

b

[tex]v = 7.647 \ m/s[/tex]

Explanation:

From the question we are told that

   The child's weight is  [tex]W_c = 287 \ N[/tex]

    The length of the sliding surface of the playground is  [tex]L = 7.20 \ m[/tex]

    The coefficient of friction is  [tex]\mu = 0.120[/tex]

      The angle is [tex]\theta = 31.0 ^o[/tex]

      The initial  speed is  [tex]u = 0.559 \ m/s[/tex]

Generally the normal force acting on the child is mathematically represented as

=>    [tex]N = mg * cos \theta[/tex]

Note  [tex]m * g = W_c[/tex]

Generally the frictional force between the slide and the child is    

         [tex]F_f = \mu * mg * cos \theta[/tex]

Generally the resultant force acting on the child due to her weight and the frictional  force is mathematically represented as

      [tex]F =m* g sin(\theta) - F_f[/tex]

Here  F is the resultant force and it is represented as  [tex]F = ma[/tex]

=>   [tex]ma = m* g sin(31.0) - \mu * mg * cos (31.0)[/tex]

=>   [tex]a = g sin(31.0)- \mu * g * cos (31.0)[/tex]

=>  [tex]a = 9.8 * sin(31.0) - 0.120 * 9.8 * cos (31.0)[/tex]

=>[tex]a = 4.039 \ m/s^2[/tex]

So

   [tex]F_f = 0.120 * 287 * cos (31.0)[/tex]

=> [tex]F_f = 29.52 \ N[/tex]

Generally the heat energy generated by the frictional  force which equivalent tot the workdone by the frictional force  is mathematically represented as

     [tex]H = F_f * L[/tex]

=>  [tex]H = 29.52 * 7.2[/tex]

=>  [tex]H =212.6 \ J[/tex]

Generally from kinematic equation we have that

    [tex]v^2 = u^2 + 2as[/tex]

=>  [tex]v^2 = 0.559^2 + 2 * 4.039 * 7.2[/tex]

=>  [tex]v = \sqrt{0.559^2 + 2 * 4.039 * 7.2}[/tex]

=>  [tex]v = 7.647 \ m/s[/tex]

Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

Answer:

If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

Explanation:

I hope this helped

Hypothesis: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car gains more potential energy at the higher starting point.

When a toy car moves along a sloped racetrack, it converts its potential energy (due to its height above the ground) into kinetic energy (energy of motion). The higher the starting height of the racetrack, the more potential energy the toy car possesses initially.

As the toy car moves down the sloped track, it will accelerate due to the force of gravity. The potential energy is converted into kinetic energy, and the car's speed increases. According to the law of conservation of energy, the total mechanical energy (sum of potential and kinetic energy) remains constant as long as no external forces, such as friction, act on the car.

Therefore, if the starting height of the racetrack is increased, the toy car will have more potential energy to start with. As it moves down the track, it will convert this increased potential energy into kinetic energy, resulting in a higher speed compared to when it starts from a lower height.

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Answer:

The change in the internal energy of the gas 1,595 J

Explanation:

The first law of thermodynamics establishes that in an isolated system energy is neither created nor destroyed, but undergoes transformations; If mechanical work is applied to a system, its internal energy varies; If the system is not isolated, part of the energy is transformed into heat that can leave or enter the system; and finally an isolated system is an adiabatic system (heat can neither enter nor exit, so no heat transfer takes place.)

This is summarized in the expression:

ΔU= Q - W

where the heat absorbed and the work done by the system on the environment are considered positive.

Taking these considerations into account, in this case:

Replacing:

ΔU= 2,092 J - 500 J

ΔU= 1,592 J  whose closest answer is 1,595 J

The change in the internal energy of the gas 1,595 J

Answer:

Energy

Explanation:

work is actually a transfer of energy. When work is done to an object , energy is transferred to that object.

The ability to do work is called energy.

"Work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement."

"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.”  energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic."

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Answer:

Delivery truck

Explanation:

Answer:

The centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s²

Explanation:

Given;

distance traveled in the given time = 200 m

time to cover the distance, t = 29.6 s

speed of the runner, v = d / t

v = 200 / 29.6

v = 6.757 m/s

The centripetal acceleration of the runner is given by;

[tex]a_c = \frac{V^2}{r}[/tex]

where;

r is the radius of the circular arc, given as 50 m

Substitute the givens;

[tex]a_c = \frac{V^2}{r}\\\\a_c = \frac{(6.757)^2}{50}\\\\a_c = 0.91 \ m/s^2[/tex]

Therefore, the centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s².

Answer:

1. 6.15m/s

2. 820N

Explanation:

The total upward force

= 410x2

= 820

g = 9.81

a = v²/r

= 2xT - msg = m x v²/r

= 820-37*9.81 = 37v²/3.06

= 820-362.97 = 37v²/3.06

= 457.03 = 12.09v²

To get v²

V² = 457.03/12.09

V² = 37.8

V = √37.8

V = 6.15m/s

B. We already have the answer to this question

The force exerted is simply gotten by this calculation

2x410

= 820N

Answer: it causes some parts of the earth to get more radiation than others.

Explanation: earth rotates around the sun on a tilted axis so the Rays of the sun cause earth to have more radiation than it needs.

Answer:

 m = 876.71 kg

Explanation:

This is an exercise of Archimedes' principle, which states that the thrust on a body is equal to the weight of the dislodged liquid  

        B = ρ g V  

therefore the load that the balloon can lift is  

       B - W_structure - w_load = 0

       w_load = B - W_structure

The volume of the balloon is  

      v = 4/3 π r³

let's substitute  

      w_carga = rho g 4/3 π r³ - m_structure g  

the air density at T = 25ºc is ρ = 1.18 kg / m³

let's calculate  

     w_load = 1.18 9.8 4/3 π 7.15³ - 930 9.8  

     w_load = 17705,77 - 9114  

     w_ load = 8591.77 N

this corresponds to a mass of  

   w_load = m g  

   m = w_load / g  

   m = 8591.77 / 9.8  

   m = 876.71 kg

Answer:

the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

Explanation:

This is a case of reflection interference, we must be careful

* There is a 180º phase change when light passes from the air to the soap film (n = 1,339), but there is no phase change when passing from the pomp to the plastic (n = 1.3)

* the wavelength within the film is modulated by the refractive index

     λₙ =  λ₀ / n

if we consider these relationships the condition for constructive interference is

     2 t = (m + ½)  λₙ

     2t = (m + ½)  λ₀ / n

      λ₀ = 2t n / (m + ½)

we substitute the values

      λ₀= 2 255 10⁻⁹ 1,339 / (m + ½)

      λ₀  = 6.829 10⁻⁷ (m + ½)

let's calculate the wavelength for various interference orders

m = 0

       λ₀ = 6.829 10⁻⁷/ ( 0 +   ½ )

       λ₀ = 13.6 10⁻⁷

       it is not visible

m = 1

      λ₀ = 6,829 10⁻⁷/ (1 + ½)

       λ₀ = 4.55 10⁻⁷

      color blue

m = 2

      λ₀ = 6.829 10⁻⁷ / (2 + ½)

      λ₀ = 2,7 10⁻⁷

   it is not visible

therefore the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

Answer:abc defg hijk lmnop qrs tuv wx y and z

Explanation: now i know my abc's

Complete Question:

A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns.

They are on the same radial line. At one instant, the acceleration of the purse is (2.00 m/s2 ) i + (4.00 m/s2 ) j .At that instant and in unit-vector notation, what is the acceleration of the wallet

Answer:

aw = 3 i + 6 j m/s2

Explanation:

       [tex]a_{c} = \omega^{2} * r (1)[/tex]

       ∴ ωp = ωw (2)

           ⇒ [tex]a_{p} = \omega_{p} ^{2} * r_{p} (3)[/tex]

               [tex]a_{w} = \omega_{w}^{2} * r_{w} (4)[/tex]

        [tex]\frac{a_{w} }{a_{p}} = \frac{r_{w} }{r_{p}}[/tex]

        [tex]a_{w} = a_{p} *\frac{r_{w} }{r_{p} } = (2.0 i + 4.0 j) m/s2 * 1.5 = 3 i +6j m/s2[/tex]

Answer:

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Let [tex]F_{1}[/tex] = 2903.57 lb, [tex]F_{2}[/tex] = 24.41 lbs, [tex]r_{2}[/tex] = 3.26 cm = 0.0326 m.

[tex]A_{2}[/tex] = [tex]\pi r^{2}[/tex]

    = [tex]\frac{22}{7}[/tex] x [tex](0.0326)^{2}[/tex]

    = 0.00334 [tex]m^{2}[/tex]

So that:

[tex]\frac{2903.57}{A_{1} }[/tex] = [tex]\frac{24.41}{0.00334}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{2903.57*0.00334}{24.41}[/tex]

    = 0.3973

[tex]A_{1}[/tex] = 0.4 [tex]m^{2}[/tex]

The radius of the piston can be determined by:

[tex]A_{1}[/tex] = [tex]\pi r^{2}[/tex]

0.3973 = [tex]\frac{22}{7}[/tex] x [tex]r^{2}[/tex]

[tex]r^{2}[/tex] = [tex]\frac{0.3973*7}{22}[/tex]

   = 0.1264

r = [tex]\sqrt{0.1264}[/tex]

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).

Answer:  Please see answer in explanation column.

Explanation:

Given that

v≈(331 + 0.60T)m/s

where Temperature, T =  14°C

v≈(331 + 0.60 x 14)m/s

v =331+ 8.4 = 339.4m/s

In our solvings, note that

f= frequency

 λ=wavelength

L = length

v= speed of sound

a) Length of the pipe is calculated using the fundamental frequency formulae that

f=v/2L

Length = v/ 2f

= 339.4m/s/ 2 x 494Hz ( s^-1)= 0.3435m

b) wavelength of the fundamental standing wave in the pipe

L = nλ/2,

λ = 2L/ n

λ( wavelength )= 2 x 0.3435/ 1

= 0.687m

c) frequency of the fundamental standing wave in the pipe

F = v/  λ

= 339.4m/s/0.687m=

494.03s^-1 = 494 Hz

d) the frequency in the traveling sound wave produced in the outside air.

This is the same as the frequency in the open organ pipe = 494Hz

e)The wavelength of the travelling sound wave produced in the outside air is the same as the wavelength calculated in b above = 0.687m

f) To play D above middle c . the distance is given by

L =v/ 2 f

= 343/ 2 x 294

=0.583m

Answer:

6.56km

Explanation:

Given parameters:

Speed  = 11.5km/hr

Time  = 2060s

Unknown:

Distance covered  = ?

Solution:

Speed is distance divided by the time taken.

   Speed  = [tex]\frac{distance}{time}[/tex]

   Distance  = Speed x time

Let us convert the seconds to hours;

      3600s  = 1hr

      2060s = [tex]\frac{2060}{3600}[/tex]   = 0.57hr

Now

 Distance  = 11.5km/hr x 0.57hr  = 6.56km

The time taken by the car to achieve the final speed is 6.25 seconds.

The equations of motion can be defined as the equation that represents the relationship between the time, velocity, acceleration, and displacement of a moving object.

The mathematical expressions for the equations of motions can be written as:

[tex]v= u+at\\S=ut+(1/2)at^2\\v^2-u^2=2aS[/tex]

Given, the initial speed of the car, u = 15 m/s

The final speed of the given car, v = 25m/s

The distance covered by car, S = 125 m

From the third equation of motion: v² = u²+ 2aS

(25)² = (15)² + 2×a× 125

a = 1.6 m/s²

From the first equation of motion we can find the time to achieve the final speed:

v = u+ at

25 = 15 + (1.6) × t

t = 6.25 sec

Therefore, 6.25 seconds will be taken by the car to catch the final speed.

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Answer:

A

Explanation:

Answer:

A

Explanation:

Gases in the atmosphere absorb heat.

You know when you have a blanket around you and some heat gets trapped in but some still gets out. Thats basically what it is.

Plus I got it right in multiple questions including the test!

I hope that reassured you!

Have a good night!

Answer:

Explanation:

The centripetal acceleration is expressed as;

a = v²/r

a is the acceleration = 50m/s²

v is the velocity = 10m/s

r is the radius

To get the radius

r = v²/a

r = 10²/50

r = 100/50

r = 2m

Hence its radius is 2m

Answer:

7 m/s (agrees with answer a in your list)

Explanation:

Recall that the centripetal acceleration is defined by the square of the tangential velocity divided by the radius of the rotational motion:

[tex]a_c=\frac{v_t^2}{R}[/tex]

then the tangential velocity is extracted from here as:

[tex]a_c=\frac{v_t^2}{R} \\v_t^2=a_c * R\\v_t=\sqrt{a_c * R}[/tex]

in our case, this becomes:

[tex]v_t=\sqrt{7*7} = 7 \,\,m/s[/tex]

Answer:

angle minimum   θ = 41.3º

Explanation:

For this exercise let's use Newton's second law in the condition of static equilibrium

    N - W = 0

    N = W

The rotational equilibrium condition, where we place the axis of rotation on the wall

We assume that counterclockwise rotations are positive

     fr (l sin θ) - N (l cos θ) + W (l/2 cos θ) = 0

the friction force formula is

     fr = μ N

     fr = μ W

we substitute

      μ m g l sin θ - m g l cos θ + mg l /2   cos θ = 0

      μ sin θ - cos θ + ½ cos θ= 0

       μ sin θ - ½ cos θ = 0

       sin θ / cos θ = 1/2 μ

       tan θ = 1/2 μ

       θ = tan⁻¹ (1 / 2μ)

       θ = tan⁻¹ (1 (2 0.57))

      θ = 41.3º

Answer:

44.73 MP/H or 71.98 KM/H

Explanation:

Answer:

no deflection

Explanation:

current is flowing from west to east. As the magnetic field of a long wire carrying current is circular, its direction will be north below the wire and south above the wire (according to the right hand rule). So, when the compass is placed underneath the wire, it will still point towards the north direction.