What is 60 percent of 92?
O 1.53
0 5.52
O 15.3
0 55.2

Answer:

2/3

Step-by-step explanation:

y2-y1/x2-x1

9-7/9-6

2/3

Answer:

Well, You possibly did all the math depending on the question. But if it was subtraction that means there's one candy bar left

step-by-step explanation:

I hope this helped in any way!

Answer:

44.5 degrees.

Step-by-step explanation:

Since these triangles are congruent, their angles are the same.

Therefore, we can set an equation with the 2 labeled angles (which are angles C and F):

2.5x+8=3.5x-7

8=x-7

x=15

We can plug 15 back into one of the equations:

2.5(15)+8 = 45.5

This means angle F is 45.5.

To find out the measure of angle E, recall the fact that the angles in a triangle add up to 180. Since this is a right triangle, and F = 45.5, we can set up an equation and solve for x:

90 + 45.5 + x = 180

135.5 + x = 180

x = 44.5

Therefore, the angle E is 44.5 degrees.

Answer:

44.5

Step-by-step explanation:

These triangles are the same so we know that

2.5x + 8 = 3.5x - 7

Subtract 2.5 x from both sides

8 = x - 7

Add 7 to both sides

15 = x

Substitute x

37.5 +8

45.5

There is a right angle so we must add 45.5 + 90 to get 135.5

Subtract 135.5 from 180 to get

44.5

Answer:

X<1 or X>3/2

Step-by-step explanation:

Answer:

the answer to the question is 0.96.

Answer:

1 inch

Step-by-step explanation:

the 9 is in the tenths place.  5 or more you need to round up.

Answer

B

Step-by-step explanation:

Answer:

a) C(2000)=1915

C(2014)=1915

b) [tex]C'(2000)=-\frac{275}{14}[/tex]

[tex]C'(2014)=-\frac{275}{14}[/tex]

c) [tex]C(t)=-\frac{275}{14}t+\frac{288405}{7}[/tex]

d) t=2021

e) too early

Step-by-step explanation:

a)

Since C(t) is the concentration of CFCs in ppt in year t, all we need to do to solve this part is determine what the concentration of CFCs is in years 2000 and 2014. Luckily for us, the problem already gives us those values, so:

C(2000)=1915    concentration in year 2000

C(2014)=1915      concentration in year 2014

b)

By definition, the derivative of a function at a given point is interpreted as the slope of the tangent line to the point of interest, so in order to find this answer, we need to find the slope of the line. Since the problem specifies that the behavior is linear, this means that the slope will always be the same no matter the year, so we get:

[tex]m=C'(t)=\frac{C'(t_{2})-C'(t_{1})}{t_2-t_1}[/tex]

so:

[tex]C'(t)=\frac{1640-1915}{2014-2000}=-\frac{275}{14}\approx -19.64[/tex]

therefore:

[tex]C'(2000)=-\frac{275}{14}[/tex]

[tex]C'(2014)=-\frac{275}{14}[/tex]

c)

Since the behavior is linear, we can calculate it with the point-slope form of the line which is:

[tex]y-y_{1}=m(x-x_{1})[/tex]

in this case:

[tex]C(t)-C(t_1)=C'(t)(t-t_{1})[/tex]

so we get:

[tex]C(t)-1915=-\frac{275}{14}(t-2000)[/tex]

and we can now solve for C(t) so we get:

[tex]C(t)=-\frac{275}{14}t+\frac{275000}{t}+1915[/tex]

for a final answer of:

[tex]C(t)=-\frac{275}{14}t+\frac{288405}{7}[/tex]

d)

So next we solve the equation for C(t)=1500 so we get:

[tex]1500=-\frac{275}{14}t+\frac{288405}{7}[/tex]

[tex]1500-\frac{288405}{7}=-\frac{275}{14}t[/tex]

[tex]-\frac{277905}{7}=-\frac{275}{14}t[/tex]

[tex]t=2021 \frac{7}{55}[/tex]

so we will reach that concentration level at the year 2021 approximately.

e)

Since the second derivative of the concentration function is greater than zero, this means that the original function might be a function in the form: .

This means that the decrease of the concentration levels is slower than that of a linear equation. So the projected date will be too early than the real date.

Answer:

K must be greater than 5

G must be less than  4

Step-by-step explanation:

Answer:9

Step-by-step explanation:Set x to 0 and the answer is 9

Answer:

2.4x - 4.4

Step-by-step explanation:

0.3(4x – 8) – 0.5(–2.4x + 4)

1.2x - 2.4 + 1.2x -2

2.4x - 4.4

Answer:

1,2,4,8

Step-by-step explanation:

Try 1x8=8, put on factor list.

Take 2.

Take 3 next.

Since there's no more, iss done.

Answer:

1.8 x 71 = 127.8, just 18 x 71 = 1278, then count the the decimal place from the right, i.e 127.8

same for 2.6 x 83 = 215.8

.......ok try 5.52 x 5

Answer:

27,579.24 OR 343.6

Step-by-step explanation:

I don't know if this is what you mean but 1.8x71x2.6x83=27,579.24

Also, (if that was not what you meant), 1.8x71=127.8, 2.6x83=215.8, 127.8+215.8=343.6

Answer:

first one

Step-by-step explanation:

it is what is it

Answer:

(-2,-4) or (2,4) depending on which one you start on.

Step-by-step explanation:

if you start from the highest point it is (-2,-4)

And if you start from the lowest point (2,4)

Answer:

96000 corn

Step-by-step explanation:

80,000/43500 = 1.84

1.84/0.5 = 3.678

3.678 x 26100 = 96000

Answer:

x=-3

Step-by-step explanation:

Divide both sides by 2, so -4x+2=14

Subtract 2 from both sides, -4x=12

Divide both sides by -4, so x=-3

Answer:

4x2 = 28

Step-by-step explanation:

Answer:

d = 25/14

Step-by-step explanation:

5(2d+2) = 3 (8d-5)    

10d + 10 = 24d - 15   | +15

10d + 25 = 24d        | - 10d

25 = 14 d                  | :14

d = 25/14

Answer:

8<8

2>8

Step-by-step explanation:

yw:))

Answer:

Where's the table?

Step-by-step explanation:

Answer:

55%

Step-by-step explanation:

Answer:

I have 5/6 of a candy bad and I want to give each of my 3 friends some. How much would each friend get?

Step-by-step explanation:

The word problem that can be represented by the expression 5/6 divided by 1/3 is "There are a total of 5/6 chocolates. Divide these chocolates such that each person will get 1/3 part of that".

Given :

The expression 5/6 is divided by 1/3.

The following steps can be used in order to determine the word problem that can be represented by the expression 5/6 divided by 1/3:

Step 1 - The knowledge of arithmetic operations can be used in order to determine the word problem that can be represented by the expression 5/6 divided by 1/3.

Step 2 - There are a total of 5/6 chocolates. Divide these chocolates such that each person will get 1/3 part of that.

Step 3 - Solve the above problem by dividing 5/6 by 1/3.

[tex]= \dfrac{5\times 3}{6\times 1}[/tex]

= 2.5

For more information, refer to the link given below:

https://brainly.com/question/25834626

If ∆LMC ≅ ∆BJK, then ∆CL ≅ ∆KB. so the correct option is D.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given that ∆LMC ≅ ∆BJK.

The image of the triangles are attached below;

The triangle are congruent to each other so,

∆LMC ≅ ∆BJK

∆LM ≅ ∆BJ

∆LC ≅ ∆BK

∆MC ≅ ∆JK

Thus, ∆LC ≅ ∆BK so the correct option is D.

Learn more about congruent triangles;

https://brainly.com/question/12413243

#SPJ2

Answer:

474$

Step-by-step explanation:

Answer: a, b, d

Step-by-step explanation: don’t count me on it

Answer:

B, D

Step-by-step explanation:

just find the common denominator and see if it works

Answer:

the initial value is 15 and it represents the y-intersect in the context of this problem

Step-by-step explanation:

Answer:

A function is a relationship that maps the elements of a set, the domain, into elements of another set, the range.

The restriction that we have for functions is: The elements on the domain can be mapped into only one element in the range.

Then if:

f(x1) = y1

and

f(x1) = y2

where y1 is different than y2

f(x) is not a function.

Now, in the graph you can see a region where both lines overlap, then for some values of x we have two possible values of y, this means that the graph does not represent a function.

Then:

Ed: He is incorrect because we can have different values in the domain mapped into the same value in the range (like in the case of a line y = b, where we have all the elements in the domain mapped into the same element in the range, b)

Debra: There is something called piecewise functions, that are functions of this type, formed by different pieces.

Alejandro: He is correct.

Antoine: Not because you can write an equation means that the relation is a function. You can write an equation for a circle, but it will not be a function.