Answer:
A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.
How much work in joules is required to lift a 23 kg box up from the ground to your waist that is 1.0 meters high, carry it 6 meters horizontallyy across the room and place it on a shelf that is 5.7 meters off the ground? Do not type units. Round your answer to te tnths place
Answer:
2682
Explanation:
Work done is given by :
Work = Force x distance
= mg x d
So, work done in lifting the box of 23 kg up to my waist of 1 m high is :
W = mg x d
= 23 x 9.18 x 1
= 211.14
Now work done carrying the box horizontally 6 meters across the room is
W = mg x d
= 23 x 9.18 x 6
= 1266.84
Work done in placing the box on the shelf that is 5.7 m above the ground is
W = mg x d
= 23 x 9.18 x 5.7
= 1203.49
So the total work done is = 211.14 + 1266.84 + 1203.49
= 2681.47
= 2682 (rounding off)
pls help me with this one
Answer :
The answer is clearly C
Explanation:
Because the only way currents move are to the side
What is the smallest height needed to make a wave?
A
6 feet
B
90 millimeters
C
20 millimeters
D
any height
the answer for this question is 6 feet
A wave can be made at any magnitude of amplitude. Therefore, the smallest height needed to make a wave is at any height. The correct answer is option D
A wave is a disturbance which travels through a medium transferring energy from one point to another without causing any permanent displacement of the medium.
The height needed by a wave is its amplitude. We can define amplitude as the maximum displacement of wave from original position.
A wave can be made at any magnitude of amplitude. Therefore, the smallest height needed to make a wave is at any height.
The correct answer is option D
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a skier starts from rest and skis down a 82 meter tall hill labeled h1, into a valley and staught back up another 35 meter hill(labled h2). How fast in m/s is she going at the top of the 35 meter hill? Assume no friction
Answer:
She is going at 30.4 m/s at the top of the 35-meter hill.
Explanation:
We can find the velocity of the skier by energy conservation:
[tex] E_{1} = E_{2} [/tex]
On the top of the hill 1 (h₁), she has only potential energy since she starts from rest. Now, on the top of the hill 2 (h₂), she has potential energy and kinetic energy.
[tex] mgh_{1} = mgh_{2} + \frac{1}{2}mv_{2}^{2} [/tex] (1)
Where:
m: is the mass of the skier
h₁: is the height 1 = 82 m
h₂: is the height 2 = 35 m
g: is the acceleration due to gravity = 9.81 m/s²
v₂: is the speed of the skier at the top of h₂ =?
Now, by solving equation (1) for v₂ we have:
[tex] v_{2}^{2} = \frac{2mg(h_{1} - h_{2})}{m} [/tex]
[tex] v_{2} = \sqrt{2g(h_{1} - h_{2})} = \sqrt{2*9.81 m/s^{2}*(82 m - 35 m)} = 30.4 m/s [/tex]
Therefore, she is going at 30.4 m/s at the top of the 35-meter hill.
I hope it helps you!
F4
30. CHALLENGE A disk with a moment of inertia
of 0.26 kg ma is attached to a smaller disk
mounted on the same axle. The smaller disk has
a diameter of 0.180 m and a mass of 2.5 kg.
A strap is wrapped around the smaller disk,
as shown in Figure 14. Find the force needed
to give this system an angular acceleration of
2.57 rad/s?
Answer:
7.42 N
Explanation:
We know that:
τ = Iα = rF
Variables:
I = 0.26 kgm^2
α = 2.57 rad/s^2
r = 0.18m/2 = 0.09m
Solve:
τ = Iα = rF
τ = (0.26kgm^2) (2.57rad/s^2) = (0.09m) * F
F = 7.42 N
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Select three possible applications of a capacitor. Select all that apply.
- electrical test meter
- camera flash
- computer battery
- motor starter
Answer:
I'm pretty sure it's all of them i'm not completely sure though hope it helps anyways! :)
On the periodic table, the elements in the columns have the same number of —
a)protons in their outer shells.
b)electrons in their outer shells.
c)neutrons.
d)electrons.
Answer:
· Periodic table, in full periodic table of the elements, in chemistry, the organized array of all the chemical elements in order of increasing atomic number —i.e., the total number of protons in the atomic nucleus. When the chemical elements are thus arranged, there is a recurring pattern called the “periodic law” in their properties, in which elements in the same column (group) have similar properties.
its d btw
We know the role of Sun in our solar system and its importance to life on Earth. What would have happened if the Sun were bigger or smaller than it is now?
Answer:
If for any reason the Sun shrank smaller than the Earth, this shrunken Sun wouldn't have the mass to create fusion and would burn out completely. Our solar system would lose its only star. ... Earth's mass would be at least 333,000 times bigger than it is now. Imagine the gravity that planet would have.
Explanation:
. Determinar la magnitud de la fuerza que recibe un cuerpo de 45 kg, la cual le produce una aceleración cuya magnitud es de 5 m/s2.
Answer:
225 N
Explanation:
Según la segunda ley de Newton;
F = ma
F = fuerza
m = masa
a = aceleración
Por eso;
F = 45 kg * 5 m / s ^ 2
F = 225 N
I need help on this question!!
Answer:
[tex]\boxed {\boxed {\sf 6000 \ Joules}}[/tex]
Explanation:
Work is the product of force and distance.
[tex]W=F*d[/tex]
The force is 500 Newtons and the couch is raised 12 meters above the ground.
Substitute these values into the formula.
[tex]W=500 \ N * 12 \ m[/tex]
Multiply.
[tex]W=6000 \ N*m[/tex]
1 Newton meter is equal to 1 Joule.So, our answer of 6000 N*m equals 6000 J[tex]W= 6000 \ J[/tex]
The work done to move a 500 Newton couch 12 meters is 6000 Joules. Therefore, choice D is correct.
Answer:
Solution :-We know that
Work = Force × Displacement
Work = 500 × 12
Work = 6000 J
[tex] \\ [/tex]
What does the force of gravity do for us?
Answer:
Earth's gravity is what keeps you on the ground and what makes things fall. Anything that has mass also has gravity. Objects with more mass have more gravity.
Explanation:
It takes Alessandra 20 minutes to walk to school every day. If she walks at a rate of 3 km/hour, how far does she walk?
A. 1km
B. 17km
C. 23km
D. 60km
What is the differents between climate and weather
weather is short term while climate is over long periods of time.
for example during the winter it is cold which is the climate, but on some days it is warm which is the weather
Pls help! Thx!! Has anyone done the Hurricane Motion Gizmo??? If so, I could really use some help.
Answer:
Please post the question(s). We can provide you more help that way. Thanks
Explanation:
Is work being done when you carry something?
Answer:
Yes you are using energy to carry that thing.(Force is applied)
Explanation:
In the United States, which type of industry is often considered part of an oligopoly?
Answer:
In the United States,cell carrier services are often considered to be a part of an oligopoly
Explanation:
Cell carrier services are a brand value and imagine
An image is a copy of an object formed by ____
light.
The answer is: Reflected
Explanation:
An image is a copy of an object that is formed by reflected (or refracted) light. Regular reflection occurs when light reflects off a very smooth surface and forms a clear image. Diffuse reflection occurs when light reflects off a rough surface and forms a blurry image or no image at all.
Can an object have both kinetic energy and gravitational potential energy? Explain.
Generators convert mechanical energy to electrical energy by using _________.
Answer:
Magnetic Induction.
Explanation:
That be your answer.
(v) Which of the following is incorrect statement?
(a) A concave mirror can form a magnified virtual image.
(b) A convex mirror can form a magnified real image.
(c) A concave mirror can form a diminished real image.
(d) A convex mirror can form a diminished virtual image.
Answer:
(b) A convex mirror can form a magnified real image.
Explanation:
A convex mirror only forms diminished/highly diminished, virtual and erect image.
Hope it helps.
A sample of monatomic ideal gas occupies 5.00 L at atmospheric pressure and 300 K (point A). It is warmed at constant volume to 3.00 atm (point B). Then it is allowed to expand isothermally to 1.00 atm (point C) and at last compressed isobarically to its original state. (a) Find the number of moles in the sample. moles (b) Find the temperature at point B. K (c) Find the temperature at point C. K (d) Find the volume at point C. L (e) Now consider the processes A → B, B → C, and C → A. Describe just how to carry out each process experimentally. This answer has not been graded yet. (f) Find Q, W, and ΔEint for each of the processes. Q (kJ) W (kJ) Eint (kJ) A → B B → C C → A (g) For the whole cycle A → B → C → A, find Q, W, and ΔEint. Q = kJ W = kJ Eint = kJ
Answer:
(a) 0.203 moles
(b) 900 K
(c) 900 K
(d) 15 L
(e) A → B, W = 0, Q = Eint = 1,518.91596 J
B → C, W = Q ≈ 1668.69974 J Eint = 0 J
C → A, Q = -2,531.5266 J, W = -1,013.25 J, Eint = -1,518.91596 J
(g) ∑Q = 656.089 J, ∑W = 655.449 J, ∑Eint = 0 J
Explanation:
At point A
The volume of the gas, V₁ = 5.00 L
The pressure of the gas, P₁ = 1 atm
The temperature of the gas, T₁ = 300 K
At point B
The volume of the gas, V₂ = V₁ = 5.00 L
The pressure of the gas, P₂ = 3.00 atm
The temperature of the gas, T₂ = Not given
At point C
The volume of the gas, V₃ = Not given
The pressure of the gas, P₃ = 1 atm
The temperature of the gas, T₂ = T₃ = 300 K
(a) The ideal gas equation is given as follows;
P·V = n·R·T
Where;
P = The pressure of the gas
V = The volume of the gas
n = The number of moles present
R = The universal gas constant = 0.08205 L·atm·mol⁻¹·K⁻¹
n = PV/(R·T)
∴ The number of moles, n = 1 × 5/(0.08205 × 300) ≈ 0.203 moles
The number of moles in the sample, n ≈ 0.203 moles
(b) The process from points A to B is a constant volume process, therefore, we have, by Gay-Lussac's law;
P₁/T₁ = P₂/T₂
∴ T₂ = P₂·T₁/P₁
From which we get;
T₂ = 3.0 atm. × 300 K/(1.00 atm.) = 900 K
The temperature at point B, T₂ = 900 K
(c) The process from points B to C is a constant temperature process, therefore, T₃ = T₂ = 900 K
(d) For a constant temperature process, according to Boyle's law, we have;
P₂·V₂ = P₃·V₃
V₃ = P₂·V₂/P₃
∴ V₃ = 3.00 atm. × 5.00 L/(1.00 atm.) = 15 L
The volume at point C, V₃ = 15 L
(e) The process A → B, which is a constant volume process, can be carried out in a vessel with a fixed volume
The process B → C, which is a constant temperature process, can be carried out in an insulated adjustable vessel
The process C → A, which is a constant pressure process, can be carried out in an adjustable vessel with a fixed amount of force applied to the piston
(f) For A → B, W = 0,
Q = Eint = n·cv·(T₂ - T₁)
Cv for monoatomic gas = 3/2·R
∴ Q = 0.203 moles × 3/2×0.08205 L·atm·mol⁻¹·K⁻¹×(900 K - 300 K) = 1,518.91596 J
Q = Eint = 1,518.91596 J
For B → C, we have a constant temperature process
Q = n·R·T₂·㏑(V₃/V₂)
∴ Q = 0.203 moles × 0.08205 L·atm/(mol·K) × 900 K × ln(15 L/5.00 L) ≈ 1668.69974 J
Eint = 0
Q = W ≈ 1668.69974 J
For C → A, we have a constant pressure process
Q = n·Cp·(T₁ - T₃)
∴ Q = 0.203 moles × (5/2) × 0.08205 L·atm/(mol·K) × (300 K - 900 K) = -2,531.5266 J
Q = -2,531.5266 J
W = P·(V₂ - V₁)
∴ W = 1.00 atm × (5.00 L - 15.00 L) = -1,013.25 J
W = -1,013.25 J
Eint = n·Cv·(T₁ - T₃)
Eint = 0.203 moles × (3/2) × 0.08205 L·atm/(mol·K) × (300 K - 900 K) = -1,518.91596 J
Eint = -1,518.91596 J
(g) ∑Q = 1,518.91596 J + 1668.69974 J - 2,531.5266 J = 656.089 J
∑W = 0 + 1668.69974 J -1,013.25 J = 655.449 J
∑Eint = 1,518.91596 J + 0 -1,518.91596 J = 0 J
write any three advantages of using simple machine
Answer:
Simple machines are useful because they reduce effort or extend the ability of people to perform tasks beyond their normal capabilities. Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever.
advantage
Increase the amount of force applied to an object.
increase the distance and speed an object moves.
Transfer a force from one place to another.
Change the direction of a force.
Answer:
It saves on time
It reduces the energy used in that activity
It is available and affordable
Explanation:
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In which part of the EM spectrum do you see the colors red, orange, yellow, green, blue, indigo, and violet (ROYGBIV);
gamma rays
ultraviolet rays
microwaves
visible light
Answer:
gamma rays
Explanation:
hope it helps
What is social participation? Why is it important for socialization?
Answer:
I hope it helped u
stay safe stay happy
For stars to form, the temperature of the hydrogen in a nebula must be more than 14 million Kelvin. How did gravitational attraction help achieve these high temperatures?
Answer:
Gravitational attraction caused the volume of the nebula to decrease, which raised the particle motion and temperature at the center of the nebula to the necessary 14 million Kelvin.
Explanation:
Plato/edmentum sample answer
Gravitational attraction caused the volume of the nebula to decrease, which raised the particle motion and temperature at the center of the nebula to the necessary 14 million Kelvin.
What is Gravitational attraction ?Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.[note 1] The publication of the theory has become known as the "first great unification", as it marked the unification of the previously described phenomena of gravity on Earth with known astronomical behaviors.
This is a general physical law derived from empirical observations by what Isaac Newton called inductive reasoning. It is a part of classical mechanics and was formulated in Newton's work Philosophiæ Naturalis Principia Mathematica ("the Principia"), first published on 5 July 1687. When Newton presented Book 1 of the unpublished text in April 1686 to the Royal Society, Robert Hooke made a claim that Newton had obtained the inverse square law from him.
In today's language, the law states that every point mass attracts every other point mass by a force acting along the line intersecting the two points. The force is proportional to the product of the two masses, and inversely proportional to the square of the distance between them.
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While traveling north on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes
due to traffic conditions. Calculate the acceleration.
Answer:
the acceleration is 2.5 MPH over 12 mins.
Explanation:
30 MPH in 12 minutes=
30/12=
2.5
why do racing cars have wider wheels?
Answer:
So they can last longer and have more grip than normal on-road cars. They need that in order for them to run well
Explanation:
Answer:
Sports cars have large wheels to provide better road traction and grip. Since most sports cars are intended for racing around the track and doing high speed cornering maneuvers, the added stability increases your confidence to go faster. Slapping on new, larger wheels also enhances the overall look of your sports car.
Explanation:
Hello Mate, Here's your answer...
Marking brainliest help pls the formula are there to help ^
A 0.5kg squirrel climbs a tree. When it reaches the top its potential energy is 34.3J. How high did it climb?
Answer:
Explanation:
Look at the equation for Potential Energy. PE = mass times gravity times the height. Filling in and solving for h:
34.3 = .5(9.8)h so
34.3 = 4.9h so
h = 7 meters
Number 10. But I would like all of them so I can double check. Thank you.
Answer:
C=0.4m/s
a=v/t
0.1=v/4.0
v=0.1*4.0
V=0.4m/s
Joe is standing on the pedal of a bicycle. If his mass of 65 kg, the pedal makes an angle of 55º above the horizontal, and the pedal is 18 cm from the center of the chain ring, how much torque does he exert?
a. 4 N·m c. 94 N·m b. 18 N·m d. 122 N·m
...
Answer:
94 N-m
Explanation:
Joe is standing on the pedal of a bicycle. If his mass of 65 kg, the pedal makes an angle of 55º above the horizontal, and the pedal is 18 cm from the center of the chain ring. The amount of torque Joe exert is 94 N-m.
What is torque?The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.
Torque is defined as Γ = r×F = r.F.sin(θ). In other words, torque is the cross product of the force vector, where 'θ' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).
Given in question mass 65 Kg so force, F = mg = 637 N
Distance r = .18 m and θ = 55 so sinθ = .82
Torque = rFsin(θ) putting the values, we get
Torque = 94 N-m.
The amount of torque Joe exert is 94 N-m.
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