What is A line that a graph approaches as x or y increases, but never crosses?

Answer:

[tex]154m^{2}[/tex]

Step-by-step explanation:

8 · 7 = 56m (horizontal rectangle shape) the width was given by subtracting the total of the width (23m) minus (16m).

5 · 8 = 40m (square shape) Subtract 8m - 3m = 5m.

6 · 8 = 48m (square shape to the left of the polygon)

2 · 5 = 10m  (small rectangle shape bottom left) 8 - 6 = 2 for the length and 5 for the width by 8 - 3 = 5

56m + 40m + 48m + 10m = 154 [tex]m^{2}[/tex]

Answer:

the probability that they are assigned adjacent cubicles is  1 ÷ 4

Step-by-step explanation:

Given that

There is 8 new graduates are hired

2 of the graduates are bill and cathy

And, each one is assigned on random basis

We need to find out the probability

So,

= (2) (7!) ÷ (8!)

= (2) ÷ (8)

= 1 ÷ 4

Hence, the probability that they are assigned adjacent cubicles is  1 ÷ 4

The same would be relevant

Answer: Maybe a

Step-by-step explanation:

I mean it is confusing but still look over it

Answer:

The bottom one looks correct

Step-by-step explanation:

Any number from 1-infinity will make that true

Complete Question

A two-state system is in an environment at temperature 500 K. The energy of state 1 is[tex]E_1=4.1e-20 J[/tex], and the energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]. Let P(1) be the probability of finding the system in state 1, and be the probability of finding the system in state 2. What is the ratio P(2)/P(1)

Answer:

 [tex]X=0.0984[/tex]

Step-by-step explanation:

From the question we are told that:

Temperature T=500 K

Energy of state 1 [tex]E_1=4.1e-20 J[/tex],

Energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]

Generally the equation for Probability of finding the system in state is mathematically given by

 [tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]

Therefore

For Probability of finding the system in state 1 [tex]P(1)[/tex]

 [tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]

Where

   K is Boltzmann constant

   [tex]K=1.38*10^{-23}[/tex]

 [tex]P(1)=e ^{\frac{-(4.1e-20 J)}{1.38*10^{-23}*500}}[/tex]

For Probability of finding the system in state 1 [tex]P(2)[/tex]

 [tex]P(2)=e ^{\frac{-(5.7e-20 J)}{1.38*10^{-23}*500}}[/tex]

Generally the equation for The Ratio of [tex]P(2)[/tex] and [tex]P(2)[/tex] is mathematically given by

 [tex]X=\frac{P(2)}{p(1)}[/tex]

 [tex]X=e ^{\frac{E_1-E_2}{KT}}[/tex]

 [tex]X=e ^{\frac{-(4.1-5.7)e-20 J)}{1.38*10^{-23}*500}}[/tex]

 [tex]X=0.0984[/tex]

Answer:

More than half of the players are under age

40.

Step-by-step explanation:

Evaluating the expression : More than half of the players are under age 40.

Below 40s :

Number of players in 20s = 19

Number of players in 30s = 24

(19 + 24) = 43 players

40s and above :

40s = 8 players

50s = 10 players

60s = 5 players

70s = 2 players

(8 + 10 + 5 + 2) = 25 players

Hence, total number of players below 30s is more Than half of the total players

Multipuly po ba (15;000 7%)

Answer:

[tex]\frac{a^2 + b^2 +c ^2}{a*b + a*c + b*c} = -2[/tex]

Step-by-step explanation:

if:

a + b + c = 0

then we can rewrite:

c = -a - b

Now we can replace this in our expression:

[tex]\frac{a^2 + b^2 + c^2}{a*b + a*c + b*c} = \frac{a^2 + b^2 + (-a - b)^2}{a*b + a*(-a - b) + b*(-a - c)}[/tex]

Now we can rewrite:

(-a - b)^2 = a^2 + 2*a*b + b^2

Then we can rewrite our expression as:

[tex]\frac{a^2 + b^2 + a^2 + b^2 + 2*a*b}{a*b - a^2 - a*b - b^2 - b*a}[/tex]

Let's keep simplifying this:

[tex]\frac{2*(a^2 + b^2 + a*b)}{-a*b - b^2 - a^2}[/tex]

Here is easy to see the simplification we need to do, as we have the same factor in the denominator as in the numerator (just a different of sign).

[tex]\frac{2*(a^2 + b^2 + a*b)}{-a*b - b^2 - a^2} = \frac{2*(a^2 + b^2 + a*b)}{-(a^2 + b^2 + a*b)} = -2[/tex]

Then the expression is equal to -2

[tex]\frac{a^2 + b^2 +c ^2}{a*b + a*c + b*c} = -2[/tex]

Hence, the approximate length of the ladder​ is [tex]12ft[/tex].

What is the approximation value?

An approximation is anything that is similar, but not exactly equal, to something else. A number can be approximated by rounding.

A calculation can be approximated by rounding the values within it before performing the operations.

Here given that,

[tex](x)^2=(11.5)^2+(3.5)^2\\X^2=132.25+12.25\\X^2=144.5 \\X=\sqrt{144.5}\\X=12 feet[/tex]

Hence, the approximate length of the ladder​ is [tex]12ft[/tex].

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Answer: hello! have a good day! :)))

P = 2

Answer:

Jeffery because the other dude go the 2 numbers wrong (he put the x coordinates on y and y on x)

Answer:

23

Step-by-step explanation:

(a) 67900

(b) 291700

(a) 25 x 679 x 4

Rearrange the terms starting with the smallest

4 x 25 x 679

The property used here is the commutative property of multiplication which states that the order in which these numbers are multiplied does not matter.

Now solve

4 x 25 x 679 = 67900

(b) 2917 x 102 - 2917 x 2

Factor out the common terms

2917(102 - 2)

Using the distributive property which states that when a number is multiplied by the sum or difference of two numbers, the result is the same as multiplying each of the two numbers by the number and then adding or subtracting the products.

Now solve

2917(102 - 2) = 2917(100)

= 291700

Answer:

Look at the image.

Step-by-step explanation:

Answer:

7 socks were sold

Step-by-step explanation:

7*8=56

11-7=4

4×11=44

56+44=100

This proves the answer of 7 to be correct

Answer:

12

Step-by-step explanation:

y = 3 so

4 × 3 = 12

The value of 4y at y=3 is 12.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

Expression : 4y

Now, we have to put y= 3

So, 4y

= 4(3)

= 12

Hence, the value of 4y at y=3 is 12

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Answer:

Step-by-step explanation:

-4<n≤5

Answer:

How many thirds are equal to 2/6?

1/3 = 1/3

2/6 = 1/3

3/9 = 1/3

4/12 = 1/3

Step-by-step explanation:

I hope that this answer helps you to understand your question more thoroughly. If you have any other questions, please put them below.  

Have a great rest of your day/night!

1 thirds

divide 2/6 by 2 and you get 1/3. or multiply 1/3 by two and you get 2/6.

Well the answer is 3,375

9514 1404 393

Answer:

  $5.54

Step-by-step explanation:

 8.8% of $63 is ...

  0.088×$63 = $5.544

The tax is rounded to the nearest cent, so you would pay $5.54 in tax.

Answer: 5.54

Step-by-step explanation: khan said it was correct

Answer:

[tex]v=<\sqrt{32}cos(319.11^{\circ}),\sqrt{32}sin(319.11^{\circ})>[/tex] or [tex]v=\sqrt{32}cos(319.11^{\circ})i+\sqrt{32}sin(319.11^{\circ})j[/tex]

Step-by-step explanation:

Find the magnitude of [tex]<2\sqrt{6},-2\sqrt{2}>[/tex]:

[tex]||v||=\sqrt{(2\sqrt{6})^2+(-2\sqrt{2})^2}[/tex]

[tex]||v||=\sqrt{24+8}[/tex]

[tex]||v||=\sqrt{32}[/tex]

Find the direction angle of [tex]<2\sqrt{6},-2\sqrt{2}>[/tex]:

[tex]\alpha=tan^{-1}|\frac{-2\sqrt{2}}{2\sqrt{6}}|[/tex]

[tex]\alpha=tan^{-1}|-\frac{\sqrt{3}}{2}|[/tex]

[tex]\alpha=tan^{-1}(\frac{\sqrt{3}}{2})[/tex]

[tex]\alpha=40.89^{\circ}[/tex]

Since [tex]\alpha=40.89^{\circ}[/tex] is our reference angle, we determine our direction angle [tex]\theta[/tex] by verifying our angle is in Quadrant IV, which is where the vector is located. Therefore, [tex]\theta=360^{\circ}-\alpha=360^{\circ}-40.89^{\circ}=319.11^{\circ}[/tex]

To represent a vector's magnitude and direction in trigonometric form, we use the form [tex]v=<||v||cos\theta,||v||sin\theta>[/tex] or [tex]v=||v||cos\theta i+||v||sin\theta j[/tex].

In conclusion, the trigonometric form of the vector is:

[tex]v=<\sqrt{32}cos(319.11^{\circ}),\sqrt{32}sin(319.11^{\circ})>[/tex] or

[tex]v=\sqrt{32}cos(319.11^{\circ})i+\sqrt{32}sin(319.11^{\circ})j[/tex]

Answer:

11+y > -33

Step-by-step explanation:

Answer:

You wrote

"Which of the following" Meaning there's should be options present.

But Going with the statement...

The sum of 11 and y is greater than -33

I'd say

11 + y > -33.

Answer:

aaaaa

Step-by-step explanation:

Answer:

I think it’s A

Step-by-step explanation:

Answer:

a. 880

Step-by-step explanation:

Options are "a. 880 b. 90 c. 790 d. None of these choices"

Interval estimate of between 790 and 970 books checked out per day.

Lower limit is 790, Upper limit is 970

Point estimate of μ(x) = [Upper limit + Lower limit} / 2

Point estimate of μ(x) = [970 + 790] / 2

Point estimate of μ(x) = 1760/2

Point estimate of μ(x) = 880

So, the efficient, unbiased point estimate of the number of books checked out each day at the New York City Public Library is 880.

Solution :

From the table,

Number of countries = [tex]$N_i$[/tex]

Mean = [tex]$\overline Y_i$[/tex]

Standard deviation = [tex]$\sigma_i$[/tex]

Margin of error of B = 50,000 acres

So we determine the [tex]$\text{sample size n}$[/tex] and then allocate the four regions of [tex]$n_1, n_2, n_3$[/tex] and [tex]$n_4$[/tex].

Under the [tex]$\text{proportional allocation}$[/tex], the [tex]$\text{equation}$[/tex] for the value of [tex]$n_1$[/tex] which yields [tex]$V(\overline Y_{st}) = D = \frac{B^2}{H}$[/tex]  is given by :

[tex]$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$[/tex]

Let us complete the numerator

[tex]$\sum_{K=1}^L N_K \sigma^2_K = N_1\sigma_1^2 + N_2\sigma_2^2 + N_3\sigma_3^2 + N_4\sigma_4^2$[/tex]

                [tex]$= 1052 \times (271)^2 + 210 \times (79)^2 + 1376 \times (244)^2 + 418 \times (837)^2 $[/tex]

                = 453329920

The bound on the error of estimation is B = 50,000 acres

Hence we get

[tex]$D=\frac{B^2}{H}$[/tex]

  [tex]$=\frac{50000^2}{4}$[/tex]

  = 625,000,000

[tex]$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$[/tex]

  [tex]$=\frac{453329920}{3056 \times 625 + \frac{1}{3056} \times 453329920}$[/tex]

 = 220.24044

≈ 221 (approximately)

Therefore, the sample size under the proportional allocation from each stratum are given by :

[tex]$n_1=n\left[\frac{N_1}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{1052}{3056}\right]$[/tex]

   ≈ 76

[tex]$n_2=n\left[\frac{N_2}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{210}{3056}\right]$[/tex]

   ≈ 15

[tex]$n_3=n\left[\frac{N_3}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{1376}{3056}\right]$[/tex]

   ≈ 100

[tex]$n_4=n\left[\frac{N_4}{\sum_{K=1}^\mu N_K}\right]$[/tex]

   [tex]$=221\left[\frac{418}{3056}\right]$[/tex]

   ≈ 30

Thus, we should select 76 counties from North central region, 15 counties from the north east region, 100 from south region and 30 from west region.

We can also estimate mean acreage of each county across all the county with a margin of error of 50,000 acres.

Answer:

C. The number of hours she babysits

Step-by-step explanation:

In this situation, the number of hours she babysits is the independent variable.

This is because it will directly influence the amount of money that she earns, which is the dependent variable.

For example, working for 1 hour will earn her $15.

So, the correct answer is C. The number of hours she babysits

Answer:

3.333 hours

Step-by-step explanation:

Given the total distance is 30 miles, and boat 1 travels at 3 mph and boat 2 travels at 6 mph, and the time for both is the same. Distance is speed S times time T so

30 = D(boat 1) + D(boat 2)

30 = (S1 * T) + (S2 * T)

30 = 3T + 6T

30 = 9T

3.333 = T

Answer:

c

Step-by-step explanation:

Answer:

C

Step-by-step explanation: