what is a product concept?

Answer:

No solution (because the n's cancel out!)

Step-by-step explanation:

Let's solve your equation step-by-step.

8

2

=

6

n

+4

Multiply all terms by n and cancel:

8n

2

=6+4n

4n=4n+6(Simplify both sides of the equation)

4n−4n=4n+6−4n(Subtract 4n from both sides)

0=6

Answer:

No solutions.

Answer:

  C. 72 degrees

Step-by-step explanation:

Complementary angles total 90 degrees.

The second angle is ...

  90° - 18° = 72°

Answer:

3/8

Step-by-step explanation:

1/2*3/4

is

(1*3)/(2*4)

So it's 3/8

Answer:

Here,

a=[tex] \frac{1}{2} [/tex]

b=[tex] \frac{3}{4} [/tex]

Now,

[tex]ab \\ = \frac{1}{2} \times \frac{3}{4} \\ = \frac{3}{8} [/tex]

Add 2 x 2 + 5 x + 6 to − 4 x 2 − x + 7

Add the expressions.

13

Answer:

50 square units

Step-by-step explanation:

Using the formula provided, [tex]a = \frac{1}{2}h(b_1+b_2)[/tex], substituting the height (5), b1 (8) and b2 (12), we can solve for the formula.

[tex]a = \frac{1}{2}\cdot5(8+12)\\\\a = \frac{1}{2}\cdot5(20)\\\\a = \frac{1}{2}100\\\\a = 50[/tex]

Hope this helped!

Answer:

50 units²

Step-by-step explanation:

The area of a trapezoid can be found using the following formula.

[tex]A=\frac{1}{2}h(b_{1} +b_{2} )[/tex]

The height of the trapezoid is 5 units. The bases are 8 units and 12 units.

[tex]h= 5 \\b_{1} = 8\\b_{2} = 12[/tex]

Substitute the values into the formula.

[tex]A=\frac{1}{2}*5(8+12)[/tex]

Solve inside the parentheses. Add 8 and 12.

8+12=20

[tex]A=\frac{1}{2}*5(20)[/tex]

Multiply 5 and 20.

5*20= 100

[tex]A=\frac{1}{2}*100[/tex]

Multiply 1/2 and 100 or divide 100 by 2.

100 * 1/2= 50     or      100/2= 50

[tex]A= 50[/tex]

Add appropriate units. For this problem, the units are units².

[tex]A= 50 units^2[/tex]

The area of the trapezoid is 50 square units.

Answer:

A

Step-by-step explanation:

So we have the piecewise function:

[tex]f(x)= \begin{cases}\sqrt{2x} & \text{if }x<3 \\2x+10 & \text{if }3\leq x<8\\42&\text{if } x\geq 8\end{cases}[/tex]

And we want to find f(8).

Since our input value is 8, choose the equation that fits our input.

The first equation demand x to be less than 3. 8 is not less than 3, so we won't use that.

The second equation demand x to e greater than or equal to 3 and less than 8. 8 is not less than 8. So, we won't use that.

The third equation demands x to be greater than or equal to 8. 8 is greater than or equal to 8, so we'll use the third equation.

So:

[tex]f(x)=42\text{ if }x\geq 8[/tex]

[tex]f(8)=42[/tex]

There're nothing more to do, we're done :)

The answer is A.

Edit: Improved Format

Answer:

a. F=GMm/r^2; a. M =

[tex]M = \frac{Fr^{2} }{Gm}[/tex]

a.  F=GMm/r^2; b. r =

[tex]r = \sqrt{\frac{GMm}{F} \\}[/tex]

b. M=kxa^3/p^2; a. P =

[tex]p = \sqrt{\frac{kxa^{3}}{M}}[/tex]

b. M=kxa^3/p^2; b. a =

[tex]a = \sqrt[3]{\frac{Mp^{2}}{kx} }[/tex]

Step-by-step explanation:

For a.  F=GMm/r^2; a. M =

To solve for M, we will rearrange the given equation F=GMm/r^2 such that M is the subject of the formula

From

F=GMm/r^2

[tex]F = \frac{GMm}{r^{2} }[/tex]

First, Cross multiplication, we then get

[tex]Fr^{2} = GMm[/tex]

Now, divide both sides by [tex]Gm[/tex]

[tex]\frac{Fr^{2} }{Gm} = \frac{GMm}{Gm} \\[/tex]

The equation becomes

[tex]\frac{Fr^{2} }{Gm} = M[/tex]

∴ [tex]M = \frac{Fr^{2} }{Gm}[/tex]

For a.  F=GMm/r^2; b. r =

Also, to solve for r, we will rearrange the given equation F=GMm/r^2 such that r is the subject of the formula

From

F=GMm/r^2

[tex]F = \frac{GMm}{r^{2} }[/tex]

First, Cross multiplication, we then get

[tex]Fr^{2} = GMm[/tex]

Now, divide both sides by [tex]F[/tex], Such that we have

[tex]\frac{Fr^{2} }{F} = \frac{GMm}{F} \\[/tex]

Then, [tex]r^{2} = \frac{GMm}{F} \\[/tex]

∴ [tex]r = \sqrt{\frac{GMm}{F} \\}[/tex]

For b. M=kxa^3/p^2; a. P =

To solve for P, we will rearrange the given equation M=kxa^3/p^2 such that P becomes the subject of the formula

From

M=kxa^3/p^2

[tex]M = \frac{kxa^{3}}{p^{2} } \\[/tex]

First, Cross multiply, we then get

[tex]Mp^{2} = kxa^{3}[/tex]

Divide both sides by [tex]M[/tex], such that the equation becomes

[tex]\frac{Mp^{2} }{M} = \frac{kxa^{3}}{M}[/tex]

Then, [tex]p^{2} = \frac{kxa^{3}}{M}[/tex]

∴ [tex]p = \sqrt{\frac{kxa^{3}}{M}}[/tex]

For b. M=kxa^3/p^2; b. a =

To solve for a, we will rearrange the given equation M=kxa^3/p^2 such that a becomes the subject of the formula

From

M=kxa^3/p^2

[tex]M = \frac{kxa^{3}}{p^{2} } \\[/tex]

First, Cross multiply, we then get

[tex]Mp^{2} = kxa^{3}[/tex]

Now, Divide both sides by [tex]kx[/tex], such that the equation gives

[tex]\frac{Mp^{2}}{kx} = \frac{ kxa^{3}}{kx}[/tex]

Then, [tex]\frac{Mp^{2}}{kx} = a^{3}[/tex]

[tex]a^{3} = \frac{Mp^{2}}{kx}[/tex]

∴ [tex]a = \sqrt[3]{\frac{Mp^{2}}{kx} }[/tex]

Answer:

The percentage of students taking exactly one courses is 38.46%.

Step-by-step explanation:

The frequency distribution table provided for the number of courses taken by part-time students is as follows:

# of Courses      Frequency         Relative            Cumulative

                                                     Frequency          Frequency

________________________________________________

             1                    20                 0.3846                     20

             2                    19                 0.3654                     39

             3                    13                 0.2500                     52

        TOTAL               52                 1.0000

The relative frequency is actually the probability or chance of the particular class or category of a frequency distribution.

The probability of students taking exactly one courses is 0.3846.

Then the percentage of students taking exactly one courses is:

0.3846 × 100% = 38.46%

Thus, the percentage of students taking exactly one courses is 38.46%.

Answer:

x = 4

Step-by-step explanation:

6/x + 1/2 = 2

x(6/x + 1/2) = 2*x

x*6/x + x*1/2 = 2x

6 + x/2 = 2x

6 = 2x - x/2

6 = 4x/2 - x/2

6 = 3x/2

6*2/3 = x

12/3 = x

x = 4

probe:

6/4 + 1/2 = 2

3/2 + 1/2 = 4/2

Answer:

a. Types of computer software used in a database management system. =Qualitative

b. Life-lengths of laser printers =Quantitative

c. Brands of calculators used by 100 engineering students on campus =Qualitative

d. Mileage attained by 12 automobiles powered by alcohol= Quantitative

Step-by-step explanation:

Data is described as quantitative when it deals with numeric values whereas qualitative data is categorical in nature. Quantitative data tells us how much, how many, or the frequency of occurrence of certain variables. Qualitative data provides answers to the what, why, which, and where questions.

1. Types of computer software are not numeric variables as they answer the 'what' question.

2. Length deals with numbers, so the life-lengths of laser printers is a quantitative variable.

3. Brands of calculators are categorical data and are thus qualitative.

4. Mileage is a numerical variable and is thus quantitative.

Answer:

-11

Step-by-step explanation:

start with PEMDAS (parenthesis, exponents, multiplication, division, addition, subtraction)

so you would first start with 14 + (-12) so the + and - become a negative so it becomes 14 - 12 which is 2

so then do -8-5 which is -13

so then you combine them and get 2-13 which is -11

Answer:

7a  3  −7a+1

Step-by-step explanation: I hope this help.

STEP

1

:

Equation at the end of step 1

 ((7a3 -  2a) -  2) +  (3 - 5a)

STEP

2

:

Polynomial Roots Calculator :

2.1    Find roots (zeroes) of :       F(a) = 7a3-7a+1

Polynomial Roots Calculator is a set of methods aimed at finding values of  a  for which   F(a)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  a  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  7  and the Trailing Constant is  1.

The factor(s) are:

of the Leading Coefficient :  1,7

of the Trailing Constant :  1

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        1.00      

     -1       7        -0.14        1.98      

     1       1        1.00        1.00      

     1       7        0.14        0.02      

Polynomial Roots Calculator found no rational roots

Final result :

 7a3 - 7a + 1

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{7 {a}^{3} - 7a + 1}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{(7 {a}^{3} - 2a - 2) + ( - 5a + 3) }[/tex]

When there is a ( + ) in front of an expression in parentheses, there is no need to change the sign of each term. That means, the expressions remains the same. Just, remove the parentheses

⇒[tex] \sf{7 {a}^{3} - 2a - 2 - 5a + 3}[/tex]

Collect like terms

⇒[tex] \sf{7 {a}^{3} - 2a - 5a - 2 + 3}[/tex]

⇒[tex] \sf{7 {a}^{3} - 7a - 2 + 3}[/tex]

Calculate

⇒[tex] \sf{7 {a}^{3} - 7a + 1}[/tex]

Hope I helped!

Best regards!!

Answer:

(7, 3)

Step-by-step explanation:

(2+5, 6-3) = (7, 3)

Answer:

Complementary

Step-by-step explanation:

Complementary Angles add up to 90°

Supplementary Angles add up to 180°

60 + 30 = 90

Answer: The answer is 3.14 (also known as π)

Step-by-step explanation: The formula for the surface area of a sphere is:

A = 4πr^2

A = 4π (0.5)^2

A = 4π (0.25)

A = (4 x 0.25) π

A = 1π

A = π     or      A = 3.14

Answer:

Ok, the straightforward thing you can do, when you have a number line like in this situation, you can just "count" the number of units that are between A and B.

Now, a more correct way:

First, A is located at the value -3, then we can write:

A = -3.

And B is located at the value 5, then:

B = 5.

Now, the distance between A and B is equivalent to the difference between A and B:

D = B - A = 5 - (-3) = 8

The distance between A and B is 8 units.

Answer:

Undefined.

Step-by-step explanation:

Because there is a 0 in the denominator.

Answer:

Undefined

Step-by-step explanation:

Because you cant divide by 0

Answer:

a = 2500mm

b = 5km

c = 2e+7

Step-by-step explanation:

Answer:

a)

1cm = 10mm

250cm = 250*10 = 2500mm

b)

1km = 1000m

5000m = 5000/1000 = 5km

c)

1km = 1000m

1m = 100cm

1km = 1000*100 = 100000cm

200km = 200*100000 = 20000000cm

Answer:

Let's see it by an example!

The numbers are given:

5 , 77 , 23 ,45 & 0

Let's arrange this from least to greatest :

0<5<23<45<77

Note : This sign(<) means greater than.

Hope you understand!✔

You can also practice this by greatest to least!

You can use this sign(>) [ it means less than ]

SMALL Example is given :

55>2

Answer:

-21

Step-by-step explanation: a negative times a positive will always be a negative

Answer:

21/2

Step-by-step explanation:

[tex]\frac{3}{4}\times\:14\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:14=\frac{14}{1}\\=\frac{3}{4}\times\frac{14}{1}\\\\\mathrm{Cross-cancel\:common\:factor:}\:2\\=\frac{3}{2}\times\frac{7}{1}\\\\=\frac{3\times\:7}{2\times\:1}\\\\=\frac{21}{2}[/tex]

Answer:

x=4

Step-by-step explanation:

2x+3=11

2x+3-3=11-3

2x=8

x=4

2x+3=11

2(4)+3=11

8+3=11

11=11

Answer:

x =4

Step-by-step explanation:

[tex]2x +3=11\\\\Collect \:like\:terms\\2x =11-3\\\\Subtract\\2x =8\\\\Divide\:both\:sides\:of\:the\:equation\:by\:2\\\frac{2x}{2} =\frac{8}{2} \\\\x = 4[/tex]

Answer: 510°

Step-by-step explanation:

1st.  solution.

Draw the perpendicular EP ⊥FB.

So from quadrilateral FAEP we find the∡AEP  ( sum of all angles in quadrilateral=360°)

∡AEP= 360°-∡FAE-∡AFP-∡FPE=360°-20°-90°-90°=160°

Draw CK ⊥FB

From triangle CKB we can find ∡BCK=180°-10°-90°=80°

From pentagon PEDCK (sum of PEDCK angles= 540°) we can find the sum of ∡PED+∡DCK= 540°-∡EPK-∡EDC-∡CKP= 540°-90°-90°-90°=270°

∡DEA+∡DCB=∡AEP+∡PED+∡DCK+∡KCB=160°+270°+80°=510°

Answer:

CEVAP 50ymis knk öyle dediler iwkwjskaoqkwjwhd

Answer:

13 5/8

Step-by-step explanation:

3 3/4+9 7/8

15/4+79/8

30/8+79/8

109/8

simplify

13 5/8

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Use order of operations.

42/(15-2^3)

Exponents in Parentesis

42/(15-8)

Subtraction inParenthesis

42/7

Division

6

Answer:

[tex]=3-4i[/tex]

Step-by-step explanation:

So we have:

[tex](2-i)-(-1+3i)[/tex]

First, distribute:

[tex]=(2-i)+1-3i[/tex]

Combine like terms:

[tex]=-i-3i+2+1[/tex]

Add:

[tex]=-4i+3[/tex]

So, in the a+bi format, we will have:

[tex]=3-4i[/tex]

Answer:

3 -4i

Step-by-step explanation:

(2-i) - (-1+3i)

Distribute the minus sign

(2-i) + 1-3i

Combine like terms

3 -4i

Answer:

Step-by-step explanation:

Answer:

obtuse , 90 , 180 .

Step-by-step explanation:

Answer:

  sin(x) = tan(x) = 0

  cos(x) = sec(x) = -1

  cot(x) = csc(x) = UNDEFINED

Step-by-step explanation:

An angle of -7π is co-terminal with an angle of π (or 180°). Its trig ratios are ...

  sin(x) = tan(x) = 0

  cos(x) = sec(x) = -1

  cot(x) = csc(x) = UNDEFINED

Answer:

The percentage is  [tex]P(0.09 < \mu < 1.2 ) = 34.9\%[/tex]

Step-by-step explanation:

From the question we are told that

  The random number is  [tex]x_1 = 0.09 \ and \ x_2 = 1.2[/tex]

Generally the mean of standard normal distribution is  [tex]\mu = 0[/tex]

                 The  standard deviation of a standard normal distribution is  [tex]\sigma = 1[/tex]

The percentage of the data in a standard normal distribution lies between

  [tex]x_1 = 0.09 \ and \ x_2 = 1.2[/tex] is mathematically represented as

       [tex]P(x_1 < \mu < x_2 ) = P(\frac{x_1 - \mu}{\sigma } <\frac{X - \mu}{\sigma } < \frac{x_2 - \mu}{\sigma } )[/tex]

      [tex]P(0.09 < \mu < 1.2 ) = P(\frac{0.09 - 0}{1 } <\frac{X - \mu}{\sigma } < \frac{1.2 - 0}{1 } )[/tex]

      [tex]P(0.09 < \mu < 1.2 ) = P(0.09 <\frac{X - \mu}{\sigma } < 1.2 )[/tex]

The  [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )[/tex]

      [tex]P(0.09 < \mu < 1.2 ) = P(0.09 <Z < 1.2 )[/tex]

      [tex]P(0.09 < \mu < 1.2 ) = P (Z < 1.2 )- P( Z<0.09)[/tex]

From the z-table  

      [tex]P (Z < 1.2 )= 0.88493[/tex]

      [tex]P( Z<0.09) = 0.53586[/tex]

So

    [tex]P(0.09 < \mu < 1.2 ) = 0.88493 - 0.53586[/tex]

    [tex]P(0.09 < \mu < 1.2 ) = 0.349[/tex]

Hence the percentage  is  

     [tex]P(0.09 < \mu < 1.2 ) = 34.9\%[/tex]