explain why chromatography separates substances in the mixture
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calculate the heat (q) in kj released with combustion of methanol using 801 grams of water and the change in temperature is 4.3 degree celsius. the specific heat of water is 4.18 j/(g*c).
The heat (q) in kJ released with combustion of methanol using 801 grams of water and the change in temperature is 4.3 degree Celsius. the specific heat of water is 4.18 J/(g °C) is 14397.17 J.
given that :
The specific heat capacity is given as :
q = mc ΔT
where ,
m = mass = 801 g
c = specific heat capacity = 4.18 J/g °C
ΔT = change in temperature = 4.3 °C
q = heat = ?
now, by solving the values we get :
q = mc ΔT
q = 801 × 4.18 × 4.3
q = 14397.17 J
Thus, The heat (q) in kJ released with combustion of methanol using 801 grams of water and the change in temperature is 4.3 degree Celsius. the specific heat of water is 4.18 J/(g °C) is 14397.17 J.
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How does knowing the properties of a substance enable you to identify a substance?
Every substance might have its own unique properties. They can be of characteristic physical and chemical properties by which they can be identified.
What is physical properties?Physical properties of a substance include the properties related to its mass, volume, density its phase change etc. Various physical properties include density, conductivity, melting point, boiling point etc.
Chemical properties of a substance include its reactivity, bond type etc. The reactivity of each substance may vary based on their bond type and intermolecular force of attraction. Each substance shows different reactivity towards air, water, with other metals and chemicals.
Similarly, the state of each substance it mostly exists will be different. Therefore, by determining the physical and chemical properties of the substance, we can identify the substance.
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Which best represents a balanced equation?
200 grams of carbon dioxide
A. 120 grams of carbon plus 20 grams of oxygen -
B. 120 grams of carbon plus 50 grams of oxygen 200 grams of carbon dioxide
C. 120 grams of carbon plus 80 grams of oxygen 200 grams of carbon dioxide
D. 120 grams and carbon plus 100 grams of oxygen - 200 grams of carbon dioxide
Answer:
i think its C i may be wrong...
Explanation:
Sodium and lithium have similar chemical properties. What characteristic of these elements explains why they are chemically similar?.
Sodium metal (Na) has properties with lithium metal (Li) because the two metals are located in the same group, namely group IA.
What are the physical and chemical properties of group IA?All elements in group IA are included in the alkali metals, except hydrogen, because the character possessed by hydrogen is "different" and does not match the character of other alkali metals.
Physically properties, all alkali metals are shiny white (silver), except for cesium which is golden yellow. The texture of this metal tends to be soft. If we try to burn this metal, the resulting flame will be different, namely lithium (red), sodium (yellow), potassium (purple), rubidium (red), and cesium (blue).Chemical properties, alkali metals are the most reactive metal group. That is, the more reactive a metal is, the easier it is to lose electrons. In addition, if we order from top to bottom on the periodic table, the electronegativity, ionization energy, melting point, and boiling point properties will be smaller.Learn more about alkali metals here https://brainly.com/question/19109836
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In an isolated system, two copper bars at different temperatures transfer energy until both are at the same temperature How would the transfer of energy be difñerent if the bars were in an open system?
The copper bars and the surrounds would transfer energy energy be different if the bars were in an open system.
What is isolated system with example?Systems that are isolated are ones whose energy is constant at all times. Heat is neither generated nor absorbed in isolated systems. An illustration of such an isolated system Thermos flasks are the ideal illustration of isolated systems. There is neither a gain nor a loss of energy because the thermally flask is completely insulated.
Are isolated and isothermal systems similar?As a result, isothermal processes are not able to occur in closed systems. Q. In a thermodynamics cycle, the unit is in contact with an outside source of heat, and changes happen gradually to make regulating the temperature easier. An adiabatic process isolates the system.
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explain why atoms only emit certain wavelengths of light when they are excited. check all that apply.
Answer:
Explanation:
Atoms emit light because excited electrons are returning to lower energy states, emitting the energy difference :- Bohr model. This energy always has a specific wavelength because the electrons can only exist in set orbits.
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#SPJ4What is Electrovalant Bond?
Answer:
ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.
Explanation:
a. is the diode forward or reverse biased? explain your answer. b. what is the acceptor concentration on the p-side? c. what is the donor concentration on the n-side? d. what is the intrinsic carrier concentration? e. do low level injection conditions apply? f. what bias (in volts) is applied to the diode?
The diode is forward-biased. The acceptor concentration on the p-side is [tex]N_{A}[/tex] = 10¹⁶ cm⁻³. The donor concentration on the n-side is [tex]N_{D}[/tex] = 10¹⁴ cm⁻³. The intrinsic carrier concentration is [tex]n_{i}[/tex] = 3.16×10¹¹ cm⁻³. Yes, the low-level injection condition applies. The bias (in volts) applied to the diode is [tex]V_{A}[/tex] = 0.18V.
The diode is forward-biased because of the excess electrons on the P-side and the excess holes on the N-side. In the intrinsic carrier concentration on the P-side n₀p₀ = 10¹⁶ × 10⁷ = 10²³ = [tex]n_{i}[/tex] = √10²³ = 3.16×10¹¹ cm⁻³, while on the N-side n₀p₀ = 10¹⁴×10⁹ = [tex]n_{i}[/tex] = √10²³ = 3.16×10¹¹. The low-level injection applies on the P-side as Δn(-[tex]x_{p}[/tex]) = 10¹⁰ << p₀ and on the N-side Δp([tex]x_{n}[/tex])=10¹² << n₀ = 10¹⁴.
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while determining the volume during this experiment (part ii), if the total volume of the flask were incorrectly reported as 125 ml, how would this error affect the calculated molar mass of the unknown volatile liquid? explain.
While determining the volume during this experiment .if the total volume of the flask were incorrectly reported as 125 ml, this error affect the calculated molar mass of the unknown volatile liquid. yes
The number of mole calculated by the following formula :
number of moles = mass / molar mass
greater the number of number of moles low the molar mass.
the ideal gas equation is given as :
P V = n RT
and the volume is directly proportional to moles . if the volume increases molar mass decreases.
Thus, While determining the volume during this experiment .if the total volume of the flask were incorrectly reported as 125 ml, this error affect the calculated molar mass of the unknown volatile liquid. yes
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how does the standard entropy of a substance depend on its molar mass? the larger the molar mass, the lower the entropy. the standard entropy of a substance does not depend on its molar mass. the larger the molar mass, the greater the entropy.
The bigger the molar mass, the greater the entropy at room temperature. When looking at the state of matter of objects, entropy generally increases with increasing molecular complexity.
What is entropy ?
Entropy, a measure of a system's thermal energy per unit temperature not available for useful work. Work is obtained from ordered molecular motion, the amount of entropy is also a measure of the molecular disorder or randomness of a system. The concept of entropy gives us deep insight into the direction of spontaneous change in many everyday phenomena. Introduced in 1850 by German physicist Rudolf Clausius, it is the pinnacle of 19th-century physics.
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1. Which of the following gas samples contains the largest number of molecules?
(A) 12 g of He (molar mass=4)
(B) 14 g of N₂ (molar mass=28)
(C) 34 g of NH3 (molar mass= 17)
(D)88 g of CO₂ (molar mass = 44)
The molar mass of the gas samples must be known to find the greatest concentration of molecules.
What is a molar mass?
A substance's molar mass is its mass in grams per mole of the chemical. A mole measures a substance's quantity of atoms, molecules, or ions. A mole is 6.022 1023 molecules of any given chemical.
Molar Mass calculation formula
M=m/n
M= molar mass
m=mass of substances (in grams).
n= number of moles of a substance.
How is molar mass determined, and why is it important?
One mole of material is weighed to determine its molar mass. Add the masses of all the components in a molecule to determine the molecular mass of the molecule by multiplying the subscript (number of atoms) by the atomic mass of each element in the molecule.
Using the molar mass formula,
M= 12/4 = 3,
It can be determined that 3 moles (or 3*avogadro number of molecules) are present.
Hence we can conclude that option (a) is correct.
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a ground-state h atom absorbs a photon of wavelength 93.78 nm, and its electron attains a higher energy level. the atom then emits two photons: one of wavelength 2626 nm to reach an intermediate level, and a second to reach the ground state. what was the wavelength of the second photon emitted?
Wavelength of the second photon emitted is 97.3nm. By using the formula E = hc/λ.
What is hydrogen energy level?A photon's frequency and Planck's constant are used to calculate the quantum energy. The relationship between wavelength and frequency is inverse, as seen below.
v = c/ λ
The energy of photon of light: given by the formula,
E = hv
E = hc/λ
Given,
wavelength of photon of light at higher energy level is 93.78 nm.
wavelength of photon of light at intermediate level is 2626 nm = 2626×10⁻⁹m
Etotal = hc/λ
Where,
E is the energy of a photon.
h is the Planck's constant (6.626×10⁻³⁴J⋅s)
c is the speed of light (3.0×10⁸m/s)
λ is the wavelength, wavelength is 93.78 nm.
1nm = 1×10⁻⁹m
Therefore, conversion of 93.78 nm into m is, 93.78nm=93.78×10⁻⁹m
Substitute:
Etotal = [tex]\frac{(6.626 . 10^{-34} )(3.0 . 10^{8}) }{93.78 .10^{-9} }[/tex]
Etotal = 2.12 × 10⁻¹⁸ J
the energy of 1 photon, E1 = [tex]\frac{(6.626 . 10^{-34} )(3.0 . 10^{8}) }{2626 .10^{-9} }[/tex]
E1= 7.57×10⁻²⁰
the energy of 2 photon, E2 = Etotal-E1
E2 = 2.044× 10⁻¹⁸J
wavelength of second photon,
λ = hc/E2
λ = [tex]\frac{(6.626 . 10^{-34} )(3.0 . 10^{8}) }{2.04 .10^{-18} }[/tex]
λ = 9.73 × 10⁻⁸m
conversion of m into nm, 1m = 1×10⁹nm
Therefore, conversion of 9.73×10⁻⁸m into nm is
9.73×10⁻⁸m = 9.73×10⁻⁸×10⁹nm =97.3nm
∴ wavelength of second emitted photon is 97.3nm.
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which is the major product of the reaction of ethyl grignard and propiophenone (ethyl phenyl ketone)?
2-Methyl-butan-2-ol is the major product of the reaction of ethyl grignard and propiophenone (ethyl phenyl ketone).
What type of reaction is Grignard?The nucleophile in a keto or aldehyde is coupled to alkyl, ethyl ester, vinyl, or allylic halides in the Fermentation process, an organo combination of carbon monoxide. It takes place in this process for carbon-carbon bonds to form.
What purpose does Grignard reagent serve?It is possible to count the halogen atoms in a halide compound using Grignard reagents. For the chemical examination of several glycerides as well as numerous cross-coupling processes for the synthesis of various dioxide and carbon-heteroatom linkages, Grignard degradation is employed.
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Brainliest. Help please
Answer:
Sulphate ion
Explanation:
Zinc will undergoes oxidation. Zn2+ - - > Zn + 2e-
Copper will undergoes reduction. Cu2+ + 2e- - - > Cu
the half-life of the reaction in trial 4 is less than the half-life in trial 1. explain why, in terms of activation energy.
Trial 4's half-life of the reaction is shorter than Trial 1's half-life. Because the activation energy and half life are both precisely related. In comparison to trail 4, trail 1 activation energy is higher.
A reaction's t1/2, or half-life, It occurs when the concentration of a reactant is halved from its starting concentration. T1/2 is used to represent it.
Activation energy is the required amount of energy to start the reaction. Kilojoules per mole (kJ/mol) is the unit used to measure the activation energy (Ea) of a reaction. Activation energy is the force that causes an object to begin acting in a certain way or to start a specific process.
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a solution is made by dissolving 21.5 g of sodium chloride, nacl, in enough water to make exactly 100 ml of solution. what is the concentration (molarity) of nacl in mol/l?\
The concentration molarity of NaCl is 3.76 mol/l.
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of solution.
Calculation:-
mass = 21.5 g
volume = 100 ml = 0.1 L
the molar mass of NaCl = 58.5
mole = mass/molar mass
= 21.5 / 58.5
= 0.376
concentration = mole /volume
= 0.376 / 0.1
= 3.76
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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Fluorine,chlorine and iodine are all part of which family in the periodic table
What is the frequency of a wave whose wavelength is 5.67 x 10^-7
The frequency of a wave whose wavelength is 5.67 × 10-⁷m is 5.3 × 10¹⁴Hz.
How to calculate frequency?Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.
The wavelength of a wave is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency as follows:
λ = v/f
Where;
λ = wavelengthv = velocity of wavef = frequency of the waveThe frequency is the quotient of the number of times, n, a periodic phenomenon occurs over the time (t) in which it occurs.
According to this question, a wave has a wavelength is 5.67 × 10-⁷m. The frequency can be calculated as follows:
5.67 × 10-⁷ = 3 × 10⁸/f
f = 3 × 10⁸ ÷ 5.67 × 10-⁷
f = 5.3 × 10¹⁴Hz.
Therefore, 5.3 × 10¹⁴Hz is the frequency of the wave
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a five part per million standard has a percent transmission on a spectrometer of 34.780. what is the absorbance?
The absorbance of the sample with 34.780 percent transmittance is 3.54
What is transmittance?
Transmittance is the fraction of the incident light which passes through the sample and comes out successfully. In spectrometer, the detector detects the amount of light coming out of the sample and converts the reading into digital display. Absorbance is the fraction of the light which is being absorbed by the given sample.
The absorbance of the sample is,
A = 2 - log (-% T)
where, A = absorbance, %T = transmittance
A = 2 - log (-34.780) = 2 - (-1.54) = 3.54
Therefore, the absorbance of the sample having 34.780 percentage transmittance is 3.54.
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Initially, 0. 700 mol of A i preent in a 2. 50 L olution. 2A(aq)↽−−⇀2B(aq)C(aq) At equilibrium, 0. 200 mol of C i preent. Calculate K
Chemists employ the mole, a very significant unit of measurement. The initial SO3 concentration is 0.28 M.
Explain about the moles?A mole is defined as 6.02214076 1023 of a particular chemical unit, such as atoms, molecules, ions, or others. Because there are so many atoms, molecules, or other components in any compound, the mole is a useful quantity to utilize.
When an element's standard relative atomic mass is multiplied by the molar mass constant, 1 103 kg/mol = 1 g/mol, the result is the molar mass of its atoms.
An object's mass that comprises 6.023 x 1023 of that object's particles is referred to as a mole. The SI unit used to measure substance amounts is the mole. Molecule is its symbol. According to the definition, 1 mole of carbon-12 weighs 12 grams and has a carbon atom count of 6.022140857 x 1023.
2.50 L is the container's volume.
Initially, there were 0.700 moles.
first concentration of SO3 =0.700 moles /2.50 L
SO3 = 0.28 M
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the future value of a single sum: increases as the compound rate increases. increases as the compound rate decreases. decreases as the compound rate increases. increases as the number of compound periods decreases. decreases as the number of compound periods increases.
The future value of a single sum increases as the compound rate decreases.
Future value is the total amount received at a particular point in time if the initial investment and the interest earned on the initial investment are included.
Future value calculations are used for various accounting functions. The most common use is to understand how much money is in investment at a given point in time due to interest income.
The formula for the final value of the single sum is
Future value = P ( 1 + i )n
where P is the principal amount
i is the interest rate
n is the number of years
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A gas at 65.0°C occupies 4.22 L. If the pressure remains the same, at which
Celsius temperature will the volume be 3.87 L?
A gas at 65.0°C occupies 4.22 L. If the pressure remains the same, at which Celsius temperature will the volume be 3.87 L out to be 310 degrees
You can leave the pressure out of both sides of the equation since the pressure is constant to make it easy.
so all you have is volume over Temp = new volume over new temp which is we don't know.
4.22 liters over 338 Kelvin = 3.87 liters over T
cross multiply and solve for T which comes out to be 310 degrees K or 37 degrees C
Yes you are right it is 310
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the half-life of palladium-100 is 4 days. after 24 days a sample of palladium-100 has been reduced to a mass of 7 mg. what was the initial mass (in mg) of the sample?
448.142 mg was the initial mass (in mg) of the sample
What is half life ?
Half-life in radioactivity, the time interval required for half of the nuclei in a radioactive sample to decay (spontaneously converted to other types of nuclei by the release of particles and energy), or equivalently, the number of decays required Halve the amount of radioactive material per second of time interval.
For example, the radioisotope cobalt 60 used in radiotherapy has a half-life of 5.26 years. Therefore, after this interval, a sample that originally contained 8 g Cobalt-60 will only contain 4 g Cobalt-60 and emit half the amount of radiation. After another 5.26 year interval, the sample contains only 2 g of Cobalt-60. However, both the volume and the mass of the original sample are such that the unstable cobalt-60 nuclei decay into stable nickel-60 nuclei, leaving undecayed cobalt.
7/e^-4.1592 =448.142
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WILL MARK BRAINLIEST! 100 POINTS!
A solution of 0.2 M sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use the results of the titration as evidence for the ratio of sulfuric acid and the base in the balanced chemical reaction for the titration.
(Please answer in three to five sentences)
If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.
The reaction of sulfuric acid and a basic solution BOH occurs as follows;
H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)
In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.
The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.
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Put the following elements in order from smallest to largest atomic radius: Carbon, Oxygen, Tin, Strontium
Rank the following elements by increasing atomic radius: Carbon, Aluminum, Oxygen, Potassium
The order of the atomic radius is;
1) Potassium, Aluminum, Carbon, Oxygen
2) Potassium, Aluminum, Carbon, Oxygen
What is the order of the atomic radius?We know that the atomic radius has to do with the distance between one atom and another in that are not covalently combined. We know that the atomic radius is a function of the group to which the atom belongs.
We know that the atomic radius increases down the group but would tend to decrease across the period as more shells are added to the atom of the element.
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how much current is needed to plate 5g of Copper metal on a cathode from a copper sulfate, CuSO4 solution in 2 hours?
33× 10⁻⁷ A current is needed to plate 5g of Copper metal on a cathode.
Explain faraday's law of electrolysis.It states that during electrolysis, the amount of chemical reactions occurring at the electrodes under the influence of electrical energy is proportional to the amount of electricity conducted through the electrolyte.
n = zFQ
Where, n = moles of copper metal
n = 5/63.54
n = 0.078 moles
z = Number of electrons in the half-cell reaction
Cu²⁺ + 2e⁻ ⇔ Cu
z = 2
F = Faraday constant (96,485 A/mol)
Now, substitute the values in the equation mentioned above:
0.078 = 2 × 96,485 × Q
Q = 4.04 × 10⁻⁷ C
Since Q = I × t
Where, Q = charge
I = Current
t = Time (2 hours or 120 min.)
4.04 × 10⁻⁷ C = I × 120
I = 4.04 × 10⁻⁷/120
I = 33× 10⁻⁷ A
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a 0.2046 g sample of a diprotic acid of the general formula h2a required 18.55 ml of a 0.1040 m naoh solution to neutralize it in an acid-base titration. what is the molar mass of the diprotic acid?
The molar mass of the diprotic acid is 212 grams/mol.
Perimeter
Mass of a diprotic acid = m₂ = 0.2046 gThe general formula H₂A Volume of NaOH = V₁ = 18.55 mL = 0.01855 LMolarity of NaOH = M₁ = 0.1040 MCalculate the mole of a diprotic acid
n NaOH = M₁ × V₁Calculate the molar mass
[tex]n_2 = \frac{m_2}{M_2}[/tex]
[tex]M_2 = \frac{m_2}{n_2}[/tex]
[tex]M_2 = \frac{0.2046}{0.0009646}[/tex]
M₂ = 212 g/mol
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Which of these statements is one of the conclusions that formed the basis of dalton’s atomic theory?.
The correct answer is option D.
The statement that formed the basis of Dalton’s atomic theory is atoms are the smallest particles of matter and cannot be divided farther.
In 1808, Dalton presented a theory named atomic theory which suggests that atoms are the smallest particles of an element and it is impossible to divide them further.
According to his theory every element is composed of these tiny particles.
Furthermore, his theory suggests that atoms neither can be divided nor destroyed.
In a particular matter, for example gold, all atoms have similar properties while their mass varies for every single different element.
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The complete question is:
Which of these statements is one of the conclusions that formed the basis of Dalton’s atomic theory?
a. Atoms can only change into atoms of another element through nuclear reactions.
b. Atoms of gases have less mass than atoms of liquids and solids.
c. Atoms of a particular element all have the same number of protons.
d. Atoms are the smallest particles of matter and cannot be divided farther.
please help!!
(this is Rutherford's Black box experiment)
- please answer all the questions in full sentences :D
- do not answer "i'm not sure" on here.
1) Suppose the marble usually rolled right to the end of the box without bouncing off anything, what would this tell you about the size of the targets?
2) What conclusions did Rutherford draw from his data and how did the data change the model of the atom?
3) Niels Bohr was a student of Rutherford, Bohr's work went on to modify the atomic model even more. What changes did Bohr make to advance our understanding of the atom?
Answers:
1) If the marble usually rolls right to the end of the box without bouncing off anything, this indicates that the size of the targets is appropriate for the marble.
2) Rutherford's data led him to conclude that atoms are mostly empty space, with a very small, very dense nucleus at the center. This data changed the model of the atom from a solid, indivisible sphere to a mostly empty space with a small, dense nucleus.
3) Bohr's model of the atom was an improvement on Rutherford's model. Bohr made the following changes:
proposed that electrons orbit the nucleus in discrete energy levelsexplained the stability of atoms by postulating that electrons can only occupy certain energy levelsproposed that when an electron jumps from one energy level to another, it emits or absorbs a photon with an energy equal to the difference in the energy levelsThese changes helped to explain the spectral lines of atoms and the stability of atoms.