Answer:
Assimilation refers to the process by which a person or ethnic group that constitutes a minority people imitates the culture of the majority population and, when the process is complete, completely abandons its own culture. Thus, the original cultural differences disappear and society becomes a monoculture. For example, immigrant groups or colonized indigenous peoples may abandon their culture, either spontaneously or after religious persecution and coercive measures, called assimilation policies.
A number of immigrant groups were assimilated into American society during the 19th century in what is usually described as a cultural melting pot or Americanization. In this case, the adaptation was not one-way, and largely spontaneous.
Question 3 of 25
Matter can undergo chemical reactions and nuclear reactions. Which feature
of the components only stays the same in chemical reactions?
A. Chemical bonds between atoms
B. Number of compounds
O
C. Types of compounds
O D. Numbers of atoms
Answer:
D. Numbers of atoms
Explanation:
The feature of the components of matter that only stays the same in chemical reactions is: D. numbers of atoms.
What is the law of conservation of matter?The law of conservation of matter (LOCOM) states that mass can neither be created nor destroyed in any chemical reaction.
This ultimately implies that, a balanced chemical equation would always require the same number of atoms on both the reactant side and product side of a chemical reaction.
In conclusion, we can deduce that the feature of the components of matter that only stays the same in chemical reactions is: D. numbers of atoms.
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What causes the inner core to be solid?
A) Intense heat.
B) Intense pressure.
C) Because it is made of iron.
D) Because of it’s density.
What are the most essential skills in Team Handball and why?
Answer:
The most important skill in handball is passing or throwing
Explanation:
You need to be able to pass the ball with accuracy. Throwing and shooting drills are normally incorporated into every training session for handball.
Answer:
Explanation:
The most important skill in handball is passing or throwing. You need to be able to pass the ball with accuracy. Throwing and shooting drills are normally incorporated into every training session for handball.
Which combination of elements below results in a metallic bond?
Answer:
there isn't anything else posted to the question when you ask a question put a picture or write it out so people can see it
Explanation:
The properties of element 17 are most similar to which of the following elements?
Bromine
Sulfur
Argon
Lithium
Halogens are highly reactive nonmetal elements in group 17 of the periodic table. ... Halogens are among the most reactive of all elements. They have seven valence electrons, so they are very “eager” to gain one electron to have a full outer energy level.
What are some ways that humans depend on the ocean?
Answer:
A lot of the earth oxygen comes from the ocean around 50%-80%
Explanation:
Answer:
fishingswimming/entertainmentthe algae that gives us oxygenwater! It evaporates and gives us rainresearchExplanation:
Use the kinetic theory of matter to explain thermal expansion in liquids (2marks)
Answer:
Explanation:
When a substance is heated the average kinetic energy of molecules increases and they start moving with an increased speed.As a result between mean separation between the molecules also increases
What is the relationship between the density of a substance and the speed of sound through that substance?
Answer:The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object. The speed of sound in air is low, because air is easily compressible.
Explanation:
The African bush elephant weights over 8 tons, which is more than the weight of 4 cars! At maximum speed, it can run up to 40 km/h. How long does it take for an elephant running at top speed to go a distance of 10 kilometers?
Answer:
15 mins
Explanation:
Helppp please pleaseeee fr
A laserbeam takes 24ms to travel from a rocket to a reflective surface of a planet and back to the rocket. How far, in miles, is the rocket from this planet’s surface?
A)2200 miles
B)3600 miles
C)2400 miles
please show work, thank you!
Answer:B
Explanation:
Caso #1 Leo Messi está jugando la final de la Champion league 2019-2020 y va a cobrar un tiro libre importante, necesita aplicar un análisis para poder alcanzar su objetivo que es acertar el gol. Responder
Answer:
Tiene que patear el balón cerca del nivel del suelo para conseguir el gol.
Explicación:
Leo Messi necesita patear el balón no en el aire, en el nivel del suelo para poder meter el gol para el equipo. Delante del fútbol hay muchos jugadores del equipo contrario dispuestos a detener el tiro libre de Leo Messi. Cuando Leo Messi patea el balón en el aire, los jugadores también saltan en el aire para detener el tiro libre que atraviesa la cabeza y para conseguir el gol Leo Messi tiene que evitar patear el balón en el aire y patear el balón cerca del nivel del suelo. que puede atravesar a los jugadores oponentes cuando lo saltan para detener el balón a través de sus cabezas para que el balón pase por debajo de sus pies y llegue a la portería.
3/8 of light initial intensity is absorbed in the breaker with length of 2cm filled with 9% solution. Find the length of the beaker should be used to get transmittance 1/3 for the same solution
Answer:
Assume I1 = Io * T1 transmission proportional to thickness
I2 = Io * T2 I is intensity of light absorbed (3/8 absorbed)
I1 / I2 = T1 / T2
T2 = T1 * (I2 / I1) = 2 * (2/3 / 3/8) = 2 * 16/9 = 32/9 thickness for 2/3 absorbed
The length of the beaker when the transmittance is changed to one-third is 13.78 cm.
The given parameters;
length of the beaker when 3/8 of the light intensity is absorbed = 2 cm = 0.02 mTo find:
the length of the beaker when there is 1/3 transmittanceThe length of the beaker is calculated by applying Beer-Lambert law;
[tex]\frac{I}{I_o} = e^{-cl}[/tex]
[tex]\frac{I_1}{I_0} = e^{-cl_1} = \frac{3}{8} \ ----(1)\\\\\frac{I_2}{I_0} = e^{-cl_2}= \frac{1}{3} \ ---- (2)[/tex]
divide equation (1) by equation (2);
[tex]\frac{e^{-cl_1}}{e^{-cl_2}} = \frac{3}{8} \times \frac{3}{1} \\\\ (c \ is \ constant \ for \ both) \\\\e^{-l_1 + l_2} = \frac{9}{8} \\\\l_2 - l_1 = ln(\frac{9}{8} )\\\\l_2 - 0.02 = 0.1178\\\\l_2 = 0.1178 + 0.02\\\\l_2 = 0.1378 \ m\\\\l_2 = 13.78 \ cm[/tex]
Thus, the length of the beaker when the transmittance is changed to one-third is 13.78 cm.
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La temperatura de cambio de estado, ¿Puede ser igual para todos los materiales? Justifica comparando dos materiales
Answer:
No.
Explanation:
Para darnos cuenta de esto tenemos que pensar en lo siguiente:
Pensemos en un vaso de vidrio, lleno de agua hasta la mitad, la otra mitad puede ser manteca derretida
Si metemos el vaso en la heladera durante un par de horas, (sabemos que la manteca en la heladera se mantiene sólida) veremos que la manteca se solidificó en la parte de arriba, mientras que el agua sigue líquida.
Entonces encontramos dos compuestos con distintas temperaturas para cambio de fase, pero materiales es más específico, y puede referirse a materiales puros.
Entonces vamos a dos metales:
Primero tenemos una pieza de hierro y una de mercurio en el congelador (supongamos que ambas están a 0°C).
Ahora los sacamos del congelador y los dejamos llegar a temperatura ambiente.
Como bien sabemos, el mercurio es líquido a temperatura ambiente, entonces el mercurio va a sufrir un cambio de fase
Ahora pensemos en el hierro; claramente va a seguir siendo sólido a temperatura ambiente, entonces podemos ver dos materiales cuyo cambio de fase de sólido a líquido ocurre en distintas temperaturas, por lo que podemos concluir que no, la temperatura de cambio de estado no puede ser igual para todos los materiales, y esto se debe a que la estructura atómica de todos los materiales es diferente.
How much heat is required to change 200 mL of ice at -22°C (at typical Freezer temperature) into steam
Answer:
611.064 kJ
Explanation:
Given :
m = 200 mL = 200 g
Specific heat of ice = 2.06 J/g°C
Q = mcΔt
Δt = 0 - (-22) = 22
Q1 = 200 * 2.06 * 22 = 9064 J
Q2 = Melt 0 °C solid ice into 0 °C liquid water:
Q2 = m · ΔHf ; ΔHf = heat of fusion of water = 334j/g
Q2 = 200 * 334 = 66800 J
Q3 : Heat to convert from 0°C to 100°C
Q3 = mcΔt ; c = 4.19 J/g°C ; Δt = (100 - 0) = 100
Q3 = 200 * 4.19 * 100 = 83800 J
Q4: heat required to boil water to steam
Q = m · ΔHv
Hv = heat of vaporization of water = 2257 J/g
Q4 = 200 * 2257 = 451400 J
Total Q = Q1 + Q2 + Q3 + Q4
Q = 9064 + 66800 + 83800 + 451400
Q = 611,064 Joules
Q = 611.064 kJ
On a distance-time graph, time is shown on the y-axis.
A) True
B) False
Answer:
false : In distance time graph,time is shown on the x -axis
A rocket experiences a 45,000 N force as it accelerates at 30 m/s/s. What is the mass of the rocket?
Answer:
15,00kg
Explanation:
here's your solution
=> force = 45,000N
=> acceleration = 30m/s^2
=> mass = ?
=> Mass = force/acceleration
=> mass = 45,000/30
=> mass = 15,00kg
hope it helps
You have an electric field with an intensity of 18 N/C at a
distance of 6.0 m. What is the voltage?
Answer:
108 v
Explanation:
A kangaroo has a maximum gravitational potential energy during one jump of 770 J
Helppppp
When the kangaroo lands on the ground 14% of the maximum gravitational potential energy is transferred to elastic potential energy in one tendon.The tendon has an unstretched length of 35.0 cm
When the kangaroo lands on the ground the tendon stretches to a length of 42.0 cm
Calculate the spring constant of the tendon.
[5 marks]
Show ur working out
Answer:
k = 44000 N/m
Explanation:
Given the following data;
Maximum gravitational potential energy = 770 J
Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J
Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m
To find the spring constant, k;
The elastic potential energy of an object is given by the formula;
[tex] E.P.E = \frac {1}{2}kx^{2}[/tex]
Substituting into the equation, we have;
[tex] 107.8 = \frac {1}{2}*k*0.07^{2}[/tex]
[tex] 107.8 = \frac {1}{2}*k*0.0049 [/tex]
Cross-multiplying, we have;
[tex] 215.6 = k*0.0049 [/tex]
[tex] k = \frac {215.6}{0.0049} [/tex]
k = 44000 N/m
The spring constant of the tendon is 44000 N/m.
The following can be depicted from the question:
Elastic potential energy will be:
= 14% × 770J = 107.80 Joule.
The spring constant will be calculated thus:
107.8 = 1/2 × k × 0.07²
107.8 = 0.5 × k × 0.0049
k = 215.6 / 0.0049
k = 44000 N/m.
Therefore, the spring constant of the tendon is 44000 N/m.
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a hole in a copper plate has a diameter of 1.325 cm at 21C°. At what tempreture is the diameter equal to 1.164 cm
Answer:14C
Explanation:
what’s answer? pls help will mark brainliest
What are some examples of gravitational forces that keep an object in orbit? Pls give at least 2-3 example if you can.
Answer:
Without any external forces a moving object will continue to move in a straight line. The gravitational force between the two objects will provide the centripetal force to keep the objects moving around one another.
1. satellite in orbit around the earth (motion of earth is negligible)
2. moon in orbit around the earth (center of motion several thousand miles
from center of earth)
3. earth in orbit around sun (center of rotation close to center of sun)
4. binary stars (if masses of stars are equal center of rotation is in middle)
how to calculate motion
Answer:
Distnace per unit time
Explanation:
Answer:
Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.
Explanation:
A 31 kg child is traveling at 4 m/s while sledding down a hill. What is the child's kinetic energy at the bottom of the hill?
Answer:
K.E = 248 J
Explanation:
Since the child is travelling at a given velocity. The kinetic energy of the child down the hill can be given by the following formula:
[tex]K.E = \frac{1}{2}mv^2\\[/tex]
where,
m = mass of the child = 31 kg
v = velocity of the child = 4 m/s
Therefore,
[tex]K.E = \frac{1}{2}(31\ kg)(4\ m/s)^2\\[/tex]
K.E = 248 J
A tow truck pulls a 1,100kg car and accelerates at a rate of 3 m/s2. What is the force of the tow truck
Answer:
3300 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 1100 Kg
Acceleration (a) = 3 m/s²
Force (F) =?
Force is defined by the following equation:
Force (F) = mass (m) × acceleration (a)
F = m × a
With the above formula, we can obtain the force of the tow truck as follow:
Mass (m) = 1100 Kg
Acceleration (a) = 3 m/s²
Force (F) =?
F = m × a
F = 1100 × 3
F = 3300 N
Therefore, the force of the tow truck is 3300 N
Light traveling through air encounter a second medium which slows the light to 2.7 x 10^8. What is the index of the medium?
Answer:
1.11
Explanation:
The index of the medium can be calculated using below formula
V= c/ n ............eqn(1)
Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s
n= index of the medium
c= speed of light= 3 x 10^8 m/s
Substitute for the values in eqn(1)
2.7 x 10^8 = (3 x 10^8 m/s)/ n
Making " n" subject of the formula, we have
n= (3 x 10^8 )/(2.7 x 10^8)
n= 1.11
Hence, the index of the medium is 1.11
Consider two walls, A and B, with the same surface areas and the same temperature drops across their thicknesses. The ratio of their thermal conductivities is kA/kB=4 and the ratio of the wall thickness is LA/LB=2. The ratio of heat transfer rates through the walls qA/qB is:
(a) 0.5
(b) 1
(c) 2
(d) 4
(e) 8
(f) None of them
Answer:
(c) 2
Explanation:
Heat transfer across the walls due to conduction is given by:
[tex]q = -KA\frac{\Delta T}{L}[/tex]
where,
q = heat transfer rate
K = thermal conductivity
A = Area
ΔT = change in temperature
L = thickness
For wall A:
[tex]q_A = -K_AA\frac{\Delta T}{L_A}[/tex]
For wall B:
[tex]q_B = -K_BA\frac{\Delta T}{L_B}[/tex]
Because the change of temperature and area of walls are the same. Dividing both terms:
[tex]\frac{q_A}{q_B} = \frac{\frac{K_A}{L_A} }{\frac{K_B}{L_B}}\\\\ \frac{q_A}{q_B} =\frac{\frac{K_A}{K_B} }{\frac{L_A}{L_B}}[/tex]
using values given in the question:
[tex]\frac{q_A}{q_B} = \frac{4}{2}\\\\\frac{q_A}{q_B} = 2[/tex]
Therefore, the correct answer is:
(c) 2
Help me please
Which line shows the LOWEST frequency?
12. A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of
60 kg, how long did it take him to reach that speed?
We have that the Time it took him to reach that speed is
t=1.2sec
From the question we are told
A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of 60 kg, how long did it take him to reach that speed?
Generally the equation for the is mathematically given as
[tex]P=W/t[/tex]
Therefore
[tex]W=Pt\\\\W=250*t[/tex]
Where
[tex]W=f*d\\\\5*60=250*t\\\\t=\frac{5*60}{250}]\\\\t=1.2sec[/tex]
Therefore
Time it took him to reach that speed is
t=1.2sec
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verify the law of moment.
Explanation:
TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTIING ON A BODY S ,KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE,THE SUM OF THE CLOCKWISE MOMENTS ,IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.
please mark me brainlist :)Answer:
TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTING ON A BODY, KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE, THE SUM OF THE CLOCKWISE MOMENTS, IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.