What is Magnitude?
⚫ No Spam​

Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of [tex]SO_3[/tex] = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

            [tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]

I:             0.700

C:              -2x           +2x           x

E:           0.700-2x      2x            x

Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles

Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]

Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]

Molarity is calculated by using the equation:

[tex]Molarity=\frac{Moles}{Volume}[/tex]

So,

[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]

[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]

[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]

The expression of [tex]K_c[/tex] for above equation follows:

[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]

Plugging values in above expression:

[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]

Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Answer:

10⁰C

Explanation:

10⁰C is equal to 50⁰F

Answer: 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.

Explanation:

We are given:

Moles of sodium hydroxide = 3.50 moles

The given chemical equation follows:

[tex]Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)[/tex]

By stoichiometry of the reaction:

If 2 moles of NaOH produces 1 mole of [tex]Pb(OH)_2[/tex]

So, 3 moles of NaOH will produce = [tex]\frac{1}{2}\times 3=1.5mol[/tex] of [tex]Pb(OH)_2[/tex]

Hence, 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.

Answer:

in a solution with mass 30.55 grams, 4.25 grams is ethane

Option D is correct

Explanation:

Step 1: Data given

Volume of the solution = 50.0 mL = 0.05 L

Density of the solution = 0.611 m (g/mL)

mass % of the solution = 13.9 %

This means for every 100 grams of solution we have 13.9 grams of solute

Step 2: Calculate the mass of the solution

Density = mass/ volume

0.611 g/mL = mass of solution / 50.0 mL

Mass of the solution = 0.611 g/mL * 50.0 mL

Mass of the solution = 30.55 grams

Step 3: Calculate mass of ethane

Since the mass % = 13.9 % this means that there is 13.9 grams solute (ethane) for every 100 grams of solution

For a solution with mass 30.55 grams the mass of the solute (ethane) is:

(30.55/100)* 13.9 = 4.25 grams

This means that in a solution with mass 30.55 grams, 4.25 grams is ethane

Option D is correct

Answer:

Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.

Explanation:

Answer: 0.0285 moles of HCl is present in given amount of solution.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

[tex]0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles[/tex]

Hence, 0.0285 moles of HCl is present in given amount of solution.

Answer:

lead

Explanation:

As it is in group 4 so 4 electron In its outer shell

and you can find number of neutrons by taking

mass number - atomic number

207.2-82=124.2=125

hope it make sense:)

Answer:

motor oil

Explanation:

According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''

The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.

Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.

Answer:

Motor oil

Heat it

Water

Explanation:

Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

[tex]pH=-\log [H^+][/tex]      .....(1)

Given value of pH = 1.5

Putting values in equation 1:

[tex]1.5=-\log[H^+][/tex]

[tex][H^+]=10^{(-1.5)}=0.0316M[/tex]

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex]       .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

[tex]0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol[/tex]

The chemical equation for the reaction of HCl and calcium carbonate follows:

[tex]2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2[/tex]

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, [tex]4.74\times 10^{-4}mol[/tex] of HCl will react with = [tex]\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol[/tex] of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of calcium carbonate = [tex]2.37\times 10^{-4}mol[/tex]

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

[tex]\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g[/tex]

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Answer:

Explanation:

So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;

No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)

= 11.2 Litre / 22.4 Litre

= 0.5 moles

Now, mass can be calculated by;

Mass = no. Of moles × Molecular mass

= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)

= 16 g

This is the answer

Answer:

OH- is 1x 10^ + 3

Explanation:

- and - = +

Answer:

3.1621 × 10²⁵ molecules

Explanation:

From the given information:

Moles of C2H8 = 52.5 moles

number of moles = mass/molar mass

molar mass of C2H8 = (6 *2) + (1*8)

= 12 + 8

= 20 g/mol

∴

52.5 moles = mass of C2H8 / 20 g/mol

mass of C2H8 = 52.5 moles × 20 g/mol

mass of C2H8 = 1050 grams

Recall that;

1 mole = 6.023 × 10²³ molecules

∴ 52.5 moles of C2H8 = (52.5 × 6.023 × 10²³) molecules

=3.1621 × 10²⁵ molecules

Answer:

0.492 J/g °C

General Formulas and Concepts:

Thermodynamics

Specific Heat Formula: q = mcΔT

Explanation:

Step 1: Define

Identify variables

[Given] q = 45.0 J

[Given] m = 8.10 g

[Given] ΔT = 24.3 °C - 13.0 °C = 11.3 °C

[Solve] c

Step 2: Solve for c

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.491642 J/g °C ≈ 0.492 J/g °C

Answer:

n = 1.24 moles

Explanation:

Given that,

Mass = 153 grams

Molar mass of KClO₃ = 122.55 g/mol

We need to find the number of moles.

We know that,

No. of moles = given mass/molar mass

So,

[tex]n=\dfrac{153}{122.55 }\\\\n=1.24[/tex]

So, there are 1.24 moles in 153 g of KClO₃.

Answer:

Ionic Bond

Explanation:

The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.

Answer:

18 moles of H₂.

Explanation:

The balanced equation for the reaction is given below:

2Al + 6HCl –> 2AlCl₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

Thus, 18 moles of H₂ were obtained from the reaction.

Answer:

kinetic energy

Explanation:

this might help..

Answer:

1.10 g/L

Explanation:

Step 1: Calculate Henry's constant (k)

The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.

C = k × P

k = C / P

k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa

Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa

We will use Henry's law.

C = k × P

C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L

Solubility of the gas, if the temperature is held constant and pressure is increased to 150 kPa from 121 kPa, is 1.10 g/L.

Henry's law of gas states at solubility (C) of the dissolved gas is directly proportional to the partial pressure (P) of the gas.

C ∝ P

C = kP, where

k = Henry's constant

Let first we calculate the Henry's constant, when the solubility of a gas is 0.890 g/L at a pressure of 121 kPa is:

k = (0.890 g/L) / (121 kPa)

k = 7.36 × 10⁻³ g/L.kPa

Now we calculate the solubility of the gas, if the pressure is increased to 150 kPa as:

C = (7.36 × 10⁻³ g/L.kPa) (150 kPa)

C = 1.10 g/L

Hence, required solubility is 1.10 g/L.

To know more about Henry's constant, visit the below link:

https://brainly.com/question/7007748

Answer:

11.7 mL

Explanation:

5.25 is half of 10.5 so its .5 mL you can add. boom ez math 11.7

Answer:

decrease by a factor of 1.5

Answer:

Sublimation

Sublimation is the best method for separating iodine from common salt (NaCl). 

Explanation:

sana makatulong

im missing something though

Answer:

Draw and upload the structures

of the following derivatives of

the carboxylic acids:

a. Ethyl 2-hydroxypropanoate

b. Butyl 3,3-dimethyhexanoate

c. N-Ethyl-N-methylbenzamide

d. 2,3-Dibromohexanamide

Explanation:

a.  Ethyl 2-hydroxypropanoate

indicates that the given molecule has -oate suffix that means it has an ester(R-COO-R') functional group.

Prop- indicates that the main carbon chain has three carbon atoms.

Ethyl group at the second position is the substituent.

b. In this molecule has also -oate functional group which means it has an ester functional group.

The rootword hex-indicates that the main carbon chain has six carbons.

Butyl-3,3-dimethyl group is the substituent.

c. N-ethyl-N-methylbenzamide

In this molecule, the aimde group indicates the presence of -CONH2 group.

N-methyl group prefix indicates that the methyl group is attached to N-atom.

N-ethyl prefix indicates the presence of ethyl group to N-atom.

d. 2,3-dibromohexanamide indicates the presence of amide functional group and two bromo groups as substituents at the second and third carbons.

The structures of all the compounds are shown below:

Answer: The structures of all the acid derivatives are attached below.

Explanation:

Some of the acid derivatives are:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

Esters are a kind of organic molecules having functional groups, where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

For (a): Ethyl 2-hydroxypropanoate

The longest possible carbon chain has 3 carbon atoms and prefix used will be 'prop-'.

A hydroxy (-OH) group is attached to the 2nd position.

The structure is attached in the image below.

For (b): Butyl 3,3-dimethyhexanoate

The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.

2 methyl groups are attached at the 3rd position

The structure is attached in the image below.

For (c): N-Ethyl-N-methylbenzamide

The longest possible carbon chain is a benzene ring

1 methyl and 1 ethyl groups are attached directly to the N-atom

The structure is attached in the image below.

For (d): 2,3-Dibromohexanamide

The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.

2 bromo groups are attached at the 2nd and 3rd position

The structure is attached in the image below.

I am not sure abt the ans

molar mass= 88

1 molecule = 6.022×10^23

4.44 moles = 6.022×10^23×4.44/88

= 26.73768 × 10^23/88

= 0.3038372727 ×10^23

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

Answer:

4 on the top

He in the middle

2 on the bottom

Explanation:

Correct on plato

The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

The two atoms interact with each other as shown by the equation below;

[tex]^4_2He[/tex]

where;

Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

Learn more about helium atom here: https://brainly.com/question/26226232

#SPJ5

Answer: 100.000%

Explanation:

.