Answer:
C. Anything That Takes Up Space.
Explanation:
Some Reactions are endothermic
How does the temperature and energy change in an endo thermic reaction?
temperature change
energy change
А
decreases
energy taken in
B
decreases
energy given out
С
increases
energy taken in
increases
energy given out
D
increases
energy given out
Answer:
endothermic means energy is taken in and temperature increases.
as a change of state takes place, heat and temperature
a. increase stays the same
b. stays the same, stays the same
c.stays the same, changes.
d.increases,increases
Answer:
c. stays the same, changes
Explanation:
temperature and heat go hand in hand, however while the change of state occurs, the temperature remains the same while the heat increases since the heat input is constant.
As a change of state takes place, heat and temperature: C. stays the same, changes.
Matter can be defined as anything that has mass and occupies space. Thus, any physical object or substance that is found on earth is typically composed of matter.
Since all matter are made up of atoms, they have a property of existing in three (3) distinct states and these include;
Solid.Gas.Liquid.Generally, matter changes state when heat (thermal energy) is released or absorbed with a corresponding change in its temperature.
In conclusion, at the point when the change of state is taking place, heat stays the same and temperature changes.
Find more information: https://brainly.com/question/17203857
WILL MARK BRAINLIEST (if correct)
C or D i think maybe
Answer:
D and A
Explanation:
What are the possible consequences of adding a chemical to the environment
Answer:
The release into the air of chemicals and particles can cause direct damage to the troposphere (air pollution); alter the composition and function of atmospheric layers (greenhouse effect) or other indirect damages (ozone layer depletion).
Explanation:
Which statement best describes balancing equations and the law of conservation of mass?
O There are more atoms in the reactants than in the products, and the total mass is the same in the
reactants and in
the products
O The number of atoms is the same in the reactants and in the products, and the total mass is the same in the
reactants and in the products
O There are fewer atoms in the reactants than in the products, and the total mass is less in the reactants than in the
products
There are more atoms in the reactants than in the products, and the total mass is higher in the reactants than in
Toms
the products
Answer:
The number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in the products.
The statement best describes balancing equations and the law of conservation of mass is the number of atoms is the same in the reactants and in the products, and the total mass is the same in the reactants and in the products. Therefore, option B is correct.
What is the law of conservation of mass ?According to the law of conservation of mass or principle of mass conservation, any system that is closed to all transfers of matter and energy must maintain a constant mass over time since the system's mass cannot vary and neither more nor less amount can be added or subtracted.
This law states that no matter what physical or chemical change occurs, the overall mass of the products and reactants remain identical.
Understanding and producing different chemical reactions depend heavily on this law. Researchers might anticipate how much the result would be if they knew the identities and quantities of the reactants for each reaction.
Thus, option B is correct.
To learn more about the law of conservation of mass, follow the link;
https://brainly.com/question/20635180
#SPJ6
Which is the larger atom kr Or As
Answer:
I think As is larger
Explanation:
What step will be most effective for a manufacturer that wants to reduce the human costs of extracting the minerals it uses in its smartphones?(1 point)
committing to only mining minerals in the United States
decreasing the prices of its products
switching to using gold instead of tungsten in its products
verifying that child labor was not used in mining these minerals
Please Help ASAP
What is the density of a substance with a mass of 15.0 g and a volume of 5.0 mL?
A. 0.33 g/mL
B. 3.0 g/mL
C. 10.0 g/mL
D. 20.0 g/mL
Answer:
B. 3.0 g/ml
Explanation:
density formula: mass/volume
15/5=3
At what time was the frog sitting still or at rest
Answer:
frogs don't spend all their time swimming, nor do they spend all ... The frog is capable of sitting perfectly still for hours on end, only to suddenly ... When a frog is resting or hunting, he will sit on whatever is handy.
Explanation:
Hope I helped if I did please mark me brainiest Thanks! <333 :3
What ingredients can be alternative for cornstarch?
Answer:
their are many alternative for cornstarch.But I know only 10 of them and they are:
1.Rice Flour
2.wheat Flour
3.Potato Starch
4.Arrowroot
5.Tapioca
6.Ground Flaxseeds
7.Gaur Gum
8.Xanthan Gum
9.Glucomannan
10.Xanthan Gum
what is write out the following number as a decimal number
[tex]1.2 \times {10}^{5} [/tex]
Answer:
120000Explanation:
I hope this helps
I NEED AN ANSWER PLEASE!
A element is having atomic number 82. find the number of its protons and electrons
Answer:
the element is lead
Explanation:
the atomic number of lead is 82.
number of protons 82
number of electrons 82
Is crumbling sheet of paper physical or chemical change and why! Pls help fast!!!! :((
Answer:
Chemical
Explanation:
physical, because chemicl would be if it was disolving with water
radium 226 has a half life of 1600 yers. suppose we have a 300g sample. how much remains after 200 years
Answer:
[tex]A=275.1g[/tex]
Explanation:
Hello.
In this case, since the radioactive decay is computed via:
[tex]A=A_0*2^{-\frac{t}{t_{1/2}}[/tex]
For the initial amount of Ra-226 (300 g), once 200 years have passed, the remaining mass is:
[tex]A=300g*2^{-\frac{200years}{1600years}}\\\\A=275.1g[/tex]
This is, considering that the half-life is 1600 years, it means that the mass of Ra-226 is decreased.
Best regards.
chemistry question please help
Answer:
AR(18)
Explanation:
Try that it should work
*(
How much heat, in kilojoules, must be added to a 580 g aluminum pan to raise its temperature from 25∘C to 150∘C?
---The specific heat capacity for aluminum is 0.897 J/g∘C.
---Round the answer to two significant figures.
Answer:
Q = 65 kJ
Explanation:
Given that,
Mass, m = 580 g
Initial temperature, [tex]T_i=25^{\circ} C[/tex]
Final temperature, [tex]T_f=150^{\circ} C[/tex]
The specific heat capacity for aluminum is 0.897 J/g°C
We need to find the heat added to the aluminium pan so that its heat raised to a temperature from 25°C to 150°C. It is given by :
[tex]Q=mc\Delta T\\\\Q=580\ g\times 0.897\ J/g^{\circ} C\times (150-25)^{\circ} C\\\\Q=65032.5\ J[/tex]
or
Q = 65.03 kJ
or
Q = 65 kJ
Hence, the heat added to the pan is 65 kJ.
within a balloon there are 3 types of gases. the first gas, A, is 6.0 grams in amount, the second gas, B, is 4.0 grams and the last, C, is 3.5 grams. The molar mass of gas "A" is 13.56 g/mol, "B" is 11.76 g/mol and "C" is 12.07 g/mol. If the total pressure inside the balloon is 15 atm, what is the partial pressure of each gas?
Answer:
Partial pressure of Gas A = 3.91 atm
Partial pressure of Gas B = 5.10 atm
Partial pressure of Gas C = 5.99 atm
Explanation:
Number of moles of gas A;
n_A = 13.56 g/mol ÷ 6 g = 2.25 moles
Number of moles of gas B;
n_B = 11.76 g/mol ÷ 4 g
n_B = 2.94 moles
Number of moles of gas C;
n_C = 12.07 g/mole ÷ 3.5 moles
n_C = 3.45 moles
Total number of moles = n_A + n_B + n_C = 2.25 + 2.94 + 3.45 = 8.64 moles
Mole fraction of gas A; X_a = 2.25/8.64
Mole fraction of gas B;X_b = 2.94/8.64
Mole fraction of gas C;X_c = 3.45/8.64
Now, partial pressure of each gas will be;
Mole fraction × Total pressure
We are given total pressure of 15 atm.
Thus;
P_a = (2.25/8.64) × 15
P_a = 3.91 atm
P_b = (2.94/8.64) × 15
P_b = 5.10 atm
P_c = (3.45/8.64) × 15
P_c = 5.99 atm
Thus;
Partial pressure of Gas A = 3.91 atm
Partial pressure of Gas B = 5.10 atm
Partial pressure of Gas C = 5.99 atm
The reaction below shows how the potential energy changes during a
chemical reaction. What does the red arrow show?
Answer:
Option C. Change in enthalphy is negative, the reaction is exothermic.
Explanation:
In the profile diagram given in the question above, we can see clearly that the energy of the reactant (Hr) is higher than the energy of product (Hp).
Hence, the enthalpy change (ΔH) will be negative i.e
Enthalpy change (ΔH) = Energy of product (Hp) – Energy of reactant (Hr)
ΔH = Hp – Hr = negative (–) [since Hr is higher than Hp]
A reaction in which the enthalpy change (ΔH) is negative is termed exothermic reaction.
Lars observes a substance to be a solid and to float in water at room temperature (23°C). Based on the given properties, which substance is the most likely identity of this sample?
Substance Melting Point (°C) Boiling Point (°C) Density at Room Temperature (g/cm3)
carbon tetrachloride -22.9 76.7 1.59
cetyl alcohol 49.3 344 0.811
dichlorobenzene 53.5 174 1.25
sulfur hexafluoride -64 -50.8 0.00617
A.
carbon tetrachloride
B.
cetyl alcohol
C.
dichlorobenzene
D.
sulfur hexafluoride
Answer:D. Sulfur Hexafluride
Explanation:
D. Sulfur Hexafluride
Explanation:
above it says the substance floats above water at room temperature and lists some substances and their density at room temp!
we know that the density of water is 1.0 so the substance in order for it to float has to be less than 1.0 and the densities for Sulfer Hexa, are all less than 1!!
Instructions
Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your
file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network
folder. Upload each file separately.
1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.
To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.
My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.
2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.
A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.
3. Some formulas I used were KE= ½ mv^2 and Ht v^2/2g. The first was to calculate the kinetic energy of an object, m=mass v=speed. Second was for finding out what height I needed to drop something to reach a certain speed, Ht=Height and g= Gravitational Acceleration of 9.8 m/s^2.
I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.
This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.
4. To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.
The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.
To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.
Explanation:
Answer:
ima give my whole doc if anyone need it in future like i did Edge 2023
Explanation:
will mark brainliest, please hurry! :>
When a hydroxyl group is substituted for a hydrogen atom in a hydrocarbon, what type of molecule results?
a.
an alcohol
c.
a carboxylic acid
b.
an amine
d.
a polymer
Answer:
ans. will be a. an alcohol
The strength of an acid is affected by the polarity of the bond connected to the acidic hydrogen. The more highly polarized this bond, the more easily the hydrogen is ionized. Electronegative atoms or groups of atoms present in the structure of an acid can act to withdraw electrons and produce additional polarization. Two common groups of acids to which this principle can be applied are oxyacids and carboxylic acids. Arrange the following oxyacids in order of decreasing acid strength. Rank from strongest to weakest acid.
a. HBrO
b. HClO
c. HClO3
d. HClO2
Answer:
Explanation:
Oxyacids are acid containing oxygen; they are also known as acid-alcohol or acid-phenol. As said earlier, the strength of these acids increases with increases in the polarity of these compounds. So, what makes the polarity is as a result of the electronegative substituents attached to it. Halogen family possesses the highest electronegativity in the periodic table, and electronegativity decreases down the group.
The ranking of the oxyacids in order of decreasing acid strength from strongest to weakest acid is:
HClO3 > . HClO2 > HClO > HBrO
10. What is the change in the boiling point of water at 1000 C per Pa change under atmospheric pressure conditions? The molar enthalpy of vaporization is 40.69 kJ mol-1, the molar volume of liquid water is 0.019 x 10-3 m3 mol-1, and the molar volume of steam is 30.199 x 10-3m3 mol-1, all at 1000 C and 1.01325 bar. (Hint: change in temperature per change in pressure)
Answer:
The answer is [tex]\frac{dT}{dP} = 2.84*10^{-4}\ K/Pa[/tex]
Explanation:
From the question we are told that
The boiling point of water is [tex]T_b = 100^oC = 100 + 273 = 373 \ K[/tex]
The enthalpy of vaporization is [tex]\Delta H_{vap} = 40.69 \ kJ mol-1 = 40.69 *10^{3} \ J/mol[/tex]
The molar volume of liquid water is [tex]V =0.019 * 10^{-3} m^3 mol^{-1}[/tex]
The molar volume of steam is [tex]V_s = 30.199 * 10^{-3} \cddot m^3\cdot mol^{-1}[/tex]
The pressure is [tex]P = 1.01325 \ bar[/tex]
Gnerally from Clausius Clapeyron equation we have that
[tex]\frac{dP}{dT} = \frac{\Delta H_{vap}}{ T * \Delta V}[/tex]
Here [tex]\Delta V = V_s - V[/tex]
=> [tex]\Delta V = [30.199 * 10^{-3} ] - [ 0.019 * 10^{-3}][/tex]
=> [tex]\Delta V = [30.199 * 10^{-3} ] - [ 0.019 * 10^{-3}][/tex]
=> [tex]\Delta V = 0.03018 \ m^3 mol^{-1}[/tex]
So
[tex]\frac{dP}{dT} = \frac{40.69 *10^{3} }{ 373 * 0.03018}[/tex]
=> [tex]\frac{dP}{dT} = 3522.28 \ Pa/K[/tex]
Generally from the we are ask to obtain the change in the boiling point of water at 1000 C per Pa change under atmospheric pressure conditions which is mathematically represented as
[tex]\frac{d T}{dP}[/tex]
So
[tex]\frac{dT}{dP} = \frac{1}{\frac{dP}{dT} } = \frac{1}{3522.28}[/tex]
=> [tex]\frac{dT}{dP} = \frac{1}{\frac{dP}{dT} } = 2.84*10^{-4}\ K/Pa[/tex]
A student titrates 0.1719 g of an unknown monoprotic acid to the equivalence point with 21.85 mL of 0.1062 M NaOH. Which of the following is most likely to be the unknown acid? propionic acid (MM 74.08 g/mol) nitrous acid (MM 47.01 g/mol) chlorous acid (MM 68.46 g/mol) benzoic acid (MM 122.12 g/mol) lactic acid (MM: 90,08 gimol)
Answer:
Propionic acid
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
21.85 mL of 0.1062 M NaOH react.
0.02185 L × (0.1062 mol/L) = 2.320 × 10⁻³ mol
Step 3: Calculate the reacting moles of HA
The molar ratio of HA to NaOH is 1:1. The moles of HA are 1/1 × 2.320 × 10⁻³ mol = 2.320 × 10⁻³ mol.
Step 4: Calculate the molar mass of HA
0.1719 g of HA correspond to 2.320 × 10⁻³ moles.
MM = 0.1719 g/2.320 × 10⁻³ mol = 74.09 g/mol
With this molar mass, the most likely acid is propionic acid.
Add 92.2 km to 9426 m and report the answer in km. 92.2 km + 9426 m = ____ km
Answer:
Sum of both value is 101.63 km
Explanation:
Given data:
1st value = 92.2 km
2nd value = 9426 m
Sum of both value in km = ?
Solution:
We know that there are 1000 m in 1 km. Thus,
92.2 km + 9426 m/1000 m × 1 km = 101.63 km
Thus, sum of both value is 101.63 km
I really need help on this
..
Answer:
b
Explanation:
When an atom is trying to obtain stability, what part(s) of the atom change(s)?
Answer: If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability.
(hope this helps ^^)
Answer quick (image)
Answer:
The answer is boiling point
Mass and energy are conserved
Question 16 options:
A)
only in chemical changes.
B)
in chemical changes and physical changes.
C)
always in physical changes and sometimes in chemical changes.
D)
only in physical changes.
Question 17 (5 points)
Which of the following can't be broken down any further chemically?
Question 17 options:
A)
Compounds
B)
Elements
C)
Matter
D)
Molecules
Question 18 (5 points)
A/an _______ is the smallest unit of matter that has the characteristics of a chemical element.
Question 18 options:
A)
atom
B)
proton
C)
molecule
D)
electron
Question 19 (5 points)
The distance between consecutive peaks or troughs in a wave is
Question 19 options:
A)
frequency.
B)
displacement.
C)
amplitude.
D)
wavelength.
Question 20 (5 points)
The phase transition of dry ice (frozen carbon dioxide) to gas is an example of
Question 20 options:
A)
condensation.
B)
sublimation.
C)
deposition.
D)
vaporization.
Explanation:
16 A. 17C matter 18C molecule 19D wavelength 20 C deposition
5) A pure substance which can be decomposed by a chemical change is a
A) mixture
B) compound
C) metal
D) nonmetal