What is refractive index?​

Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]

Then the frequency will be:

[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]

Answer:

c

Explanation:

A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. The new interference pattern seen on the screen compared to the original interference pattern is the spacing between the bright fringes will increase. Thus, the correct option is A.

Interference is the net effect of the combination of two or more wave forms or trains which are moving on intersecting or coincident paths in a medium. The effect of this pattern is that of the addition of the amplitudes of the individual waves at each point which are affected by more than one wave in the medium.

A scientist when decreases the wavelength of the light used in a double-slit experiment and it keeps every other aspect of the wave the same. The new interference pattern seen on the screen as compared to the original interference pattern is that the spacing between the bright fringes will increase.

Therefore, the correct option is A.

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Answer:

Almost winter so fall

Explanation:

Hope this helps! Please let me know if you want me to elaborate more or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Answer:

It has gravitational energy because of its height above some reference point.

It also contains thermal energy due to the motion of the contained atoms and molecules.

Answer:

b and c :)

Explanation:

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

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For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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Answer:

The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.

Explanation:

Answer:

Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ

Explanation:

Answer:

The threshold frequency is defined as the minimum frequency of the incident radiation below which photoelectric emission or emission of electrons is not possible. The threshold frequency refers to the frequency of light that will cause an electron to dislodge emit from the surface of the metal.

Answer:

Power, technique, and timing

Explanation:

I just did the quiz and it was correct!! Hope this helps!

Answer:

Beaker

Graduated Cylinders

Volumetric flask

Test tube

Funnel

The linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

The linear mass density of the rope in the given motion of the wave is determined by dividing the mass of the rope with the length of the entire rope.

The linear mass density of the rope is calculated as follows;

μ = m/L

μ = 0.6 kg / 4 m

μ = 0.15 kg/m

Thus, the linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

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Answer:

4 degrees C

Explanation:

this is just a 'known'

Answer:

Explanation:

Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.

Using the data from point C, we can find out that the total energy of the system is 156 because  [tex]E = K+Pe[/tex].

Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].

At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:

[tex]156=104+K\\52=K[/tex]

At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.

Potential energy:-

Now

So

Power:-

Answer:

Explanation:

A rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.

Answer:

flammable  liquids

Explanation:when it catches on fire your going to get burned.hope this helps.

Answer:

100 kg

Explanation:

Net force = 350 - 50 = 300 N

F= ma

300 N  = m * 3 m/s^2

100 kg = mass

(1) The time taken for the drag racer to accelerate is 4.89 s

(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(2) To calculate the speed of the contestant, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(a) In feet = (9.43/0.3048) = 30.94 ft/s

(b)  in miles per hr = (9.43×2.24) = 21.12 miles per hr

Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

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Required Answer:

Given:

(A)

As we know that,

↠ Current = 75/120

↠ Current = 0.625 A

(B)

Here,

↠ Resistance = 120/0.625

↠ Resistance = 192 Ω

(C)

Here,

↠ Energy = 75 × 1

↠ Energy = 75 J

Answer:

its counting by 4 the multi 4,8,12,16

Answer:

Explanation:

The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.

Hi there!

We can begin by using Coulomb's Law:

[tex]E = \frac{kq}{r^2}[/tex]

k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)

E = Electric field strength (N/C)
r = distance from point (m)

q = charge (C)

Since this is a continuous charge, we must use calculus.

We can express this as the following:
[tex]q = \lambda L[/tex]

λ = Linear charge density (C/m)

L = Length of rod (m)

Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]

Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]

However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]

Integrate. For a semicircle, the bounds will be from -π/2 to π/2.

[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]

We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]

Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]

**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.

Answer:

The answer is in the picture above.

Answer:

real kinetic theory means that kinetic energy

Answer:

.002273 seconds

Explanation:

1/f = period

1/ 440 c/s = .002273  seconds

Answer:

out of the screen

Explanation:

because charge +Q is already moving upward

(a) The torque acting on the disk is 66 Nm.

(b) The moment of inertia of the disk is 0.05 kgm².

(c) The angular acceleration is produced by the torque is 1,320 rad/s².

(d) The final angular velocity of the disk is  3,960 rad/s.

(e) The angle of rotation of the disk is 5,940 rad.

The torque acting on the disk is calculated as follows;

τ = Fr

τ = 300 x 0.22

τ = 66 Nm

The moment of inertia of a solid disk is calculated as follows;

I = ¹/₂MR²

I = ¹/₂ x 2 x (0.22)²

I = 0.05 kgm²

The angular acceleration of the disk is calculated as follows;

τ = Iα

[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]

ωf = ωi + αt

ωf = 0 + (1320 x 3)

ωf = 3,960 rad/s

ωf² = ωi²+ 2αθ

(3,960)² = 0 + 2(1320)θ

θ = (3,960²) / (2 x 1320)

θ = 5,940 rad

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