what is the amount of power produced if 35Nm of work is done in 5 seconds

The compound's boiling point is around 73.65 °C.

Unexpected Responses. Favorable reactions are those that cause the system's enthalpy to drop while its entropy rises. The reaction happens naturally when both of these conditions are true. Both endothermic and exothermic reactions, which absorb heat and release it, can occur spontaneously.

We can use the Gibbs-Helmholtz equation to solve for the boiling point:

ΔG = ΔH - TΔS

At boiling point, ΔG = 0, so we can solve for T:

T = ΔH/ΔS

Substituting the given values:

T = (32.77 kJ·mol−1) / (94.72 J·mol−1·K−1)

T = 346.8 K

Converting to Celsius:

Boiling point = 346.8 K - 273.15 = 73.65 °C

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Consider that after recrystallization, you obtained 7.0 g of dry pure substance from 10.0 g of impure material. Your recovery rate is then 70% (7/10 × 100).

Recrystallization recovery percentages are often lower than 100%, though occasionally they might be higher (see the following issue). This is brought on by impurity loss, material that was left in the liquid solution after dissolving, and "mechanical losses."

The amount if pure compound that is present in the finished chemical synthesis product is calculated using the percent recovery. The ratio of actual yield to theoretical yield is used to compute percent yield. The ratio of the pure compound to the starting compound is used to calculate percent recovery.

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The mass of calcium in the original urine sample would be 0.0140 g.

First, we need to find the masses of calcium and magnesium oxalates in the original sample. Let x be the mass of calcium oxalate and y be the mass of magnesium oxalate. Then we have:

x + y = mass of the mixed oxalate precipitate

Next, we need to use the information given to find the mass of calcium in the original sample. The mass of calcium oxide formed after ignition is equal to the mass of calcium oxalate in the original sample. We can calculate the mass of calcium oxide using the mass of calcium carbonate formed and the molar mass ratio of calcium carbonate to calcium oxide.

The balanced chemical equations for the reactions are:

CaC2O4 -> CaCO3 + CO2

CaCO3 -> CaO + CO2

The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.

From the given information, we have:

0.0433 g = (x + y)(100.09 g/mol + 80.15 g/mol) / (128.10 g/mol + 80.15 g/mol)

0.0285 g = x(56.08 g/mol) + y(40.31 g/mol)

Solving these equations simultaneously, we get:

x = 0.0140 g

y = 0.0053 g

Therefore, the mass of calcium in the original sample (which is equal to the mass of calcium oxide formed after ignition) is:

0.0140 g

So the mass of calcium in the original sample is 0.0140 g.

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A concentrated saltwater solution weighing 29.97 g and fitting into a flask to the mark of 25.0 ml has a density of about 1199.2 g/L.

By dividing the solution's mass by its volume, we may get its density: density = mass/volume

We need to know the density of water at the solution's temperature as well as the capacity of the flask up to the 25.0 ml level in order to calculate the volume of the solution.

Since 1 mL = 0.001 L, volume is equal to 25.0 mL, or 0.0250 L.

Now, we may determine the solution's density as follows:

1199.2 g/L or 29.97 g/0.0250 L is what is referred to as density.

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The pH of .3 M NH, where is K = 1.7 x 10^-5 is 11.87 calculated from the equation of dissociation constant.

Kb= [A] /[A + ][X− ]

​1.7×10 −5 = x ^2 /0.3

⇒x= 7.5 ×10 −3

∴[OH − ][H + ]=7.5 ×10 −3

[H + ] =10 ^−14 ⇒pH=11.87

When describing the acidity or basicity of an aqueous solution, chemists use the pH scale, which is also known as acidity and previously stood for "potential of hydrogen". Greater pH values are seen in basic or alkaline solutions than acidic solutions.

Potential hydrogen is the meaning of the acronym pH, which indicates how much hydrogen is present in liquids and how active the hydrogen ion is.

As a first step, we shall ascertain the pKa of the solution before calculating its Ka. When a solution reaches the equivalence point, its pH and pKa are equal. So, by using a titration curve and the Ka = - log pKa equation, we may rapidly ascertain the value of Ka.

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In the peroxodisulfate ion, Peroxydisulfate-, all the atoms have oxidation values that add up to +6.

Most often, the polymerization of different alkenes, such as styrene, acrylonitrile, and fluoroalkenes, is started using salts of peroxydisulfate. The homolysis of peroxydisulfate causes polymerization to begin. 2 [Peroxydisulfate] [Sulfate]

Ag: +1

Sulfur: 0

Nitrogen: +2 (in Nitric oxide)

Oxygen: -2 (in Water)

Hydrogen: +1 (in Water)

The peroxodisulfate ion, Peroxydisulfate-, consists of one disulfate (Peroxydisulfate-) group and two peroxy (Oxygen2-) groups. Normal oxygen oxidation number is 2, however in a peroxy group it is -1. The charge of the ion, which is -2, is equal to the total sum of the oxidation numbers of all the atoms in the ion. As a result, we may write:

2(-1) + 2x + 8(-2) = -2

-2 + 2x - 16 = -2

2x = 12

x = +6

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Answer:

Molecules in the skin are moving faster than molecules in the glass.

Explanation:

Put it in your own words.

Answer:

The energy from the ice transferred to the glass.

Because it is not very effective at transferring [tex]H^{+}[/tex] ions to water, vinegar is a weak acid. Less than 0.4% of the [tex]CH_{3}CO_{2}H[/tex]molecules in a 1 M solution interact with water to create [tex]H_{3}O^{+}[/tex]and [tex]CH_{3}CO_{2}^{-}[/tex] ions. More than 99.6% of the acetic acid molecules are still whole.

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The ΔG for the reaction at 298 K and the given partial pressures is -55.53 kJ/mol.

What is ΔG ?

The Gibbs free energy change for a reaction under non-standard conditions can be calculated using the following equation:

ΔG = ΔG° + RTln(Q)

where ΔG is the Gibbs free energy change, ΔG° is the standard Gibbs free energy change, R is the gas constant (8.314 J/(mol·K)), T is the temperature in kelvin, and Q is the reaction quotient.

The reaction quotient, Q, can be calculated using the partial pressures of the gases involved in the reaction:

Q = (P(NH3))² / (P(N2) x P(H2)³)

Plugging in the given values, we get:

Q = (0.75 atm)² / (0.35 atm x 0.30 atm³) = 0.2667

Now we can calculate the ΔG for the reaction:

ΔG = ΔG° + RTln(Q)

ΔG = (-32.8 kJ/mol) + (8.314 J/(mol·K) x 298 K x ln(0.2667))

ΔG = -32.8 kJ/mol + (-22.73 kJ/mol)

ΔG = -55.53 kJ/mol

Therefore, the ΔG for the reaction at 298 K and the given partial pressures is -55.53 kJ/mol.

What is reaction quotient?

Reaction quotient, commonly denoted as Q, is a measure of the relative concentrations of reactants and products in a chemical reaction at a particular moment in time. It is calculated by dividing the concentration of the products raised to their stoichiometric coefficients by the concentration of the reactants raised to their stoichiometric coefficients.

The equation for the reaction quotient Q is similar to the equilibrium constant Kc, but with the concentrations of the reactants and products at any time during the reaction, rather than at equilibrium. When the reaction is at equilibrium, the reaction quotient is equal to the equilibrium constant.

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Since 2 moles of KI produce 1 mole of I2, then 7.0 moles of KI will produce 7.0/2 moles of I2. In other words, 3.5 moles of I2 will be produced

The volume of [tex]SO_{3}[/tex] would be produced by complete reaction of 100cm3 of [tex]H_{2}O[/tex]with [tex]O_{2}[/tex] is at STP is 60.03L.

22.4 L divided by 2.68 moles per mole yields 60.03 L [tex]SO_{3}[/tex].

describing the elements contributing to the response,

[tex]2SO_{2(g)}+ O_{2} = 2SO_{3}[/tex]

In this instance, [tex]SO_{3}[/tex] and [tex]O_{2}[/tex] have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 [tex]dm^{3}[/tex]of [tex]O_{2}[/tex] (1 dm3 = 1 L) equals 30 L of [tex]O_{2}[/tex] and 30 L/22.4 L times 1 mole equals 1.34 moles of [tex]O_{2}[/tex].

According to stoichiometry, when 1.34 moles of [tex]O_{2}[/tex]are reacted with [tex]SO_{2}[/tex], 2.68 moles of [tex]SO_{3}[/tex] are created, or 2/1 x 1.34 moles of [tex]SO_{3}[/tex].

This means that the amount of [tex]SO_{3}[/tex]produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L [tex]SO_{3}[/tex].

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The reaction [tex]2NH_3=N_2H_4+H_2[/tex] has a standard reaction free energy of -62.4 kJ/mol.

Energy is the capacity to carry out tasks or affect change. It comes in a variety of shapes and sizes, including kinetic energy (energy of motion), potential energy (stored energy of position), thermal energy (heat), electrical, chemical, and nuclear energy. Energy is required for the survival and growth of all living things. Additionally, it is necessary for the operation of industries and equipment.

Equation can be used to get a reaction's standard reaction free energy.

ΔG°rxn = ΣΔG°f (products) - ΣΔG°f (reactants).

For the reaction [tex]2NH_3=N_2H_4+H_2[/tex], the ΔG°f values are as follows:

ΔG°f ([tex]2NH_3[/tex]) = -46.2 kJ/mol

ΔG°f ([tex]N_2H_4[/tex]) = -20.8 kJ/mol

ΔG°f ([tex]H_2[/tex]) = 0 kJ/mo

The equation yields the average reaction free energy (ΔG°rxn) of the reaction is:

ΔG°rxn = (2 x -20.8) - (-46.2)

            = -62.4 kJ/mol

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I think it is Ba since the radius increases along the group.but decreases along the period

Answer:

Ba

Explanation:

Ba

Answer:

Explanation:

dilute solutions of hydrochloric acid (HCl), sulphuric acid (H₂SO₄), and nitric acid (HNO₃) react with active metals to produce a salt and hydrogen gas.

Active metals react strongly and quickly with other elements and compounds due to the electrons in its structure and its ease of sharing the electrons with other elements.

The most active metals are found in Groups 1  and 2 of the Periodic Table (i.e. the left side), and include lithium, potassium, magnesium, and calcium. Metals such as aluminium, lead, and zinc, are less active than magnesium or calcium, but are generally still labelled as 'active'. Metals such as copper, gold, or silver are inactive and will not react.

Therefore, in the provided question, all the metals listed, except for copper, will produce a metal salt + hydrochloric acid. Copper will not react.

In general:

Answer: Oxygen (??)

Explanation: Im not sure but smth like H2O (my brain is not braining T-T)

Answer: 40. g

Explanation:

To find the grams in 0.89 moles of CO2, we just need to use the molar mass of CO2. The molar mass which tells us how many grams are in a mole for an element or compound.

The molar mass of CO2 is equal to the molar mass of carbon, 12.0107, and 2 oxygens, 2*15.9994 (you can find the molar mass of an element on any periodic table). Add these, and you get the molar mass of CO2 to be 44.01 g/mol, a helpful value to remember.

Now, just multiply the molar mass by the amount of moles to find grams.

[tex]\frac{44.01g}{mole} * 0.89mole[/tex], moles cancel out, [tex]\frac{44.01g}{mole} * 0.89mole=40.48g[/tex]

There are 2 significant figures in the question, so I will round this answer to 2 significant figures, 40. g

The sandwich contains approximately 71.25 grams of carbohydrates.

Calories are a unit of measurement used to quantify the amount of energy contained in food and beverages. The number of calories in a particular food is determined by the amounts of carbohydrates, fats, proteins, and other nutrients it contains.

To determine the number of grams of carbohydrates in the sandwich, we need to use the fact that carbohydrates, fats, and proteins have different calorie densities. Specifically, carbohydrates and proteins each contain about 4 calories per gram, while fats contain about 9 calories per gram.

First, let's calculate the total number of calories coming from the fat and protein in the sandwich:

Total calories = calories from carbohydrates + calories from fat + calories from protein

475 Calories = calories from carbohydrates + 10g x 9 Calories/g + 25g x 4 Calories/g

475 Calories = calories from carbohydrates + 90 Calories + 100 Calories

475 Calories - 190 Calories = calories from carbohydrates

285 Calories = calories from carbohydrates

Now that we know the number of calories from carbohydrates, we can use the calorie density of carbohydrates to determine the number of grams of carbohydrates:

285 Calories = carbohydrates in grams x 4 Calories/g

71.25 g = carbohydrates in grams

Therefore, the sandwich contains approximately 71.25 grams of carbohydrates.

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four score and seven years ago (our father) brought this continent, a new nation,

The molecular formula of the compound, given that it contains 51.39% carbon, 8.64% hydrogen, and 39.97% nitrogen is C₆H₁₂N₄

To obtain the molecular formula, we must first determine the empirical formula. Details on how to obtain the empirical formula is given beloww:

Divide by their molar mass

C = 51.39 / 12 = 4.283

H = 8.64 / 1 = 8.64

N = 39.97 / 14 = 2.855

Divide by the smallest

C = 4.283 / 2.855 = 1.5

H = 8.64 / 2.855 = 3

N = 2.855 / 2.855 = 1

Multiply through by 2 to express in whole number

C = 1.5 × 2 = 3

H = 3 × 2 = 6

N = 1 × 2 = 2

Thus, we can conclude that the empirical formula is C₃H₆N₂

Finally, we shall determine the molecular formula. Details below

Molecular formula = empirical × n = mass number

[C₃H₆N₂]n = 140.22

[(12×3) + (1×6) + (14×2)]n = 140.22

70n = 140.22

Divide both sides by 70

n = 140.22 / 70

n = 2

Molecular formula = [C₃H₆N₂]n

Molecular formula = [C₃H₆N₂]₂

Molecular formula = C₆H₁₂N₄

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3.4 g of HCl is therefore equivalent to roughly 0.0932 moles of HCl.

Since each molecule of HCl contains one mole of hydrogen and one mole of chlorine, the mole quantity of HCl equals the mole quantity of hydrogen and chlorine in the sample.

Approximately 36.46 g/mol is the molar mass of hydrochloric acid (HCl). We must divide the mass by the molar mass to determine the number of moles of HCl in 3.4 g of HCl:

Mass of HCl / molar mass of HCl equals moles of HCl.

3.4 grams per 36.46 grams per mole of HCl

A mole of HCl is equal to 0.0932 mol.

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The final volume of the ideal gas is 156.6 L.

A sample of an ideal gas is allowed to expand adiabatically while producing external work (W) at first. The volume is then maintained at its new value with the help of heat Q until the pressure returns to its initial level.

We can use the combined gas law to solve this problem:

(P1 × V1) / T1 = (P2 × V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2 and V2 are the final pressure and volume, respectively. Since the gas is kept at a constant temperature, we can simplify this to:

P1 × V1 = P2 × V2

Plugging in the given values, we get:

2.01 bar × 78.3 L = 1.00 bar × V2

Solving for V2, we get:

V2 = (2.01 bar × 78.3 L) / 1.00 bar = 157 L

Therefore, the final volume of gas is 157 L.

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The following formula can be used to calculate the activation energy: ln (k 1 /k 1) = É a /R x (1/S n 1 - 1/T 2). where. E an is the reaction's activation energy, expressed in J/mol.

What does a scientific reaction mean?

reaction definitions in science. reaction. one or more new compounds are formed as a result of the reorganization of the atoms and molecules of two substances when come into contact. Electrons of one material interact with all those of another to produce chemical reactions.

What chemical process changes one substance into another?

Chemical reaction is the process through which two or more compounds, known as reactants, change into one or more new ones, known as products. Chemical components or compounds make up substances. The atoms that make up the reactants are rearranged in a chemical reaction to produce various products.

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The amount that would remain, given that 3 half-lives has pass when you started with 20.0 g is 2.50 grams (1st option)

The following data were obtained from the question:

The amount remaining can be obtained as shown below:

N = N₀ / 2ⁿ

N = 20 / 2³

N = 20 / 8

N = 2.50 grams

Thus, we can conclude from the above calculation that the amount that would remain after 3 half-lives to pass is 2.50 grams (1st option)

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Answer:

2.50g

Explanation:

The Two Aspects of Science: Control over nature and understanding of nature must both be held in equal honor.

A. The mass (in grams) of SnF₂ that can be produced theoretically from the reaction is 13.20 g

B. The percentage yield of the reaction is 83.3%

The mass of SnF₂ produced theorethically, can be obtained as shown below:

Sn + 2HF ->  SnF₂ +  H₂

From the balanced equation above,

118.71 g of Sn reacted to produce 156.71 g of SnF₂

Therefore,

10 g of Sn will react to produce = (10 × 156.71) / 118.71 = 13.20 g of SnF₂

Thus, the mass of SnF₂ produced is 13.20 g

The percentage yield for the reaction can be obtained as follow:

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of SnF₂ = (11 / 13.20) × 100

Percentage yield of SnF₂ = 83.3%

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Complete question:

See attached photo

When 3 g of a petroleum are burned with more oxygen than is required, 8.8 g of Atmospheric carbon dioxide plus 5.4 g liquid [tex]H_{2}O[/tex] are produced.

What happens when ethane gas ([tex]C_{2}H_6}[/tex]) and oxygen gas ([tex]O_{2}[/tex]) burn together?

Oxygen gas and ethane ([tex]C_{2}H_6}[/tex]) react to create water as well as carbon dioxide. Find the total quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of methane is burned and 16 mol of oxygen initially. 2[tex]C_{2}H_4}[/tex]+7[tex]O_{2}[/tex] →4[tex]CO_{2}[/tex]+6[tex]H_{2}O.[/tex]

How many tumours of CO2 are created when 2.2 blackheads of [tex]C_{2}H_4}[/tex]are burned?

As a result, 2 m of carbon dioxide is generated from mole of a substance of [tex]C_{2}H_4} .[/tex] Thus, multiply 2.2 over 2 by 1 pot to get 2.2 moles for c into h or just a cross. It consists of 4.4 moles of carbon.

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A compound formed between two or more non-metal elements that share electrons is called a covalent compound or a molecular compound.

In covalent compounds, the atoms share electrons in order to achieve a full outer shell of electrons and become more stable. Covalent compounds typically have low melting and boiling points, are often gases or liquids at room temperature, and are poor conductors of electricity. Examples of covalent compounds include water (H2O), carbon dioxide (CO2), and methane [CH4].

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