what is the answer to -2-(-2)

Answer:

Step-by-step explanation:

1 day, she travels 11/12 of a mile.

5 days, she travels 5 * 11/12 miles

5*11/12 = 55/12 = 4 7/12  miles.

Answer:

Rs. 32767

Step-by-step explanation:

Because the amount is doubling every day, we can use the expression 1*2^15-1 because there is 1 to start with. Also cool trick! if you need to do 2^1+2^2+2^3+....+2^x, it will be equal to 2^(x+1)-1. So:

2^15-1

32768-1

32767

Answer:

128

Step-by-step explanation:

Billy has 55 stamps and his brother Tommy has 73. Add 73 and 55 together. 55+73=128

Answer: x=20

Step-by-step explanation:

(6x-10)=(3x+50) (subtract both sides by 3x)

3x-10=50(add ten to both sides)

3x=60(divide both sides by 3)

x=20

The situation IS NOT represented by the tape diagram.

The situation can be represented by the equation:

s + s + s + s + s + 6 = 106

5s + 6 = 106

5s = 106 - 6

5s = 100

s = 100/5

s = 20

Therefore, the amount Noah earned each time he walked the dog is $20

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Answer:

Sam ate the most pizza.

Step-by-step explanation:

Mathew: 0.8 is equal to 80%

To get a percentage, you need to move the decimal two places to the right.

Lily: 3/4 = 75%

George: 77%

Sam: 82%

Considering it's concept, it is found that the net worth of the individual is given by:

D) $26,595.

It is given by the sum of the individual assets subtracted by the sum of it's liabilities.

Researching the problem on the internet, we have that:

Hence, his net worth is given by:

N = 171645 - 145050 = $26,595.

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The net worth of the individual with assets worth $171,645 and liabilities of $145,050 is D) $26,595.

The net worth is the value of assets less the value of liabilities.

The net worth shows the amount by which the assets have increased or decreased in value versus the liabilities.

Assets = $171,645

Liabilities = $145,050
Net worth = $26,595 ($171,645 - $145,050)

Thus, the net worth of the individual with assets worth $171,645 and liabilities of $145,050 is D) $26,595.

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Answer: 64 inches

Step-by-step explanation:

[tex]\sf\large\underline{Given:-}[/tex]

Speed of the train = 20km / 1hr.

[tex]\rightarrow[/tex] 1 hour = 60 minutes.

So, speed of the train = 20km/60min.

[tex]\sf\large\underline{To\: Find:-}[/tex]

[tex]\rightarrow[/tex]Distance covered by train in 1min.

[tex]\sf\large\underline{Solution:-}[/tex]

Let the distance covered by train in 1 min be [tex]\sf{x}[/tex] m.

So, if train covers 20 km in 60min then it covers [tex]\sf{x}[/tex] m in 1 min.

It can be written as,

[tex]\rightarrow[/tex] [tex]\sf{\frac{20}{60}}[/tex] [tex]\sf{=\frac{x}{1}}[/tex](by cross multiplication)

[tex]\rightarrow[/tex][tex]\sf{20\: = \: 60x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{\frac{20}{60}= x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{\frac{1}{3}= x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{0.33= x}[/tex](approx)

Therefore, distance covered by train in 1 min= 0.33km (approx).

_______________________________

Hope it helps you:)

well, if take a year to be 365 days so hmmm 150 days is really just 150/365 of a year, so let's use that.

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$11000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years\to \frac{150}{365}\dotfill &\frac{30}{73} \end{cases} \\\\\\ A=11000[1+(0.09)(\frac{30}{73})]\implies A=11000\left( \frac{757}{730} \right)\implies A\approx 11406.85[/tex]

Answer:

9

Step-by-step explanation:

He would need to by 9 boxes. There might be some left over pencils.

Answer:

no

Step-by-step explanation:

because mindy has already saved $20 and is putting $8 which is more than the amount georgette is putting (monthly) and plus georgette has no money saved so basically mindy will have more money saved

7.5x11 = 4.85

82.5x = 4.85

*divide 82.5 on both sides*

x = 4.85 ÷ 82.5

x = 0.058788

Answer:

0.058787879

Step-by-step explanation:

(7.5)(x)(11)=4.85

82.5(x)=4.85

x=4.85÷82.5

x= 0.058787879

Answer:

  0.772 seconds; 9.228 seconds

Step-by-step explanation:

The given projectile formula with the given numbers filled in is ...

  [tex]\displaystyle h=-16t^2+v_0t+h_0\\\\114=-16t^2+160t[/tex]

We can "complete the square" to solve this for t, the times at which the height is 114 feet.

  16(t² -10t) = -16(7.125) . . . . . rearrange, showing factor of 16

  t² -10t +25 = -7.125 +25 . . . . divide by 16, add 25 to complete the square

  t = 5 ±√17.875 ≈ 5 ± 4.228 . . . . take the square root, add 5

  t ∈ {0.772, 9.228}

The arrow is 114 feet high after 0.772 seconds and again after 9.228 seconds.

Answer:

Step-by-step explanati

- |10+8l=-2

Answer:

A=lw+l(w

2)2+h2+w(l

2)2+h2=30·20+30·(20

2)2+282+20·(30

2)2+282≈2127.25933

Your answer is 2127.259

I think it will help you

If "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

To find the length of "s" in the rectangular pyramid, we first need to understand the terminology used to describe the different dimensions of a pyramid.

In a rectangular pyramid, "l" usually represents the length of the base, "w" represents the width of the base, and "h" represents the height of the pyramid (the perpendicular distance from the base to the apex or top vertex of the pyramid).

However, there is no standard notation for the length of the slant height (s) in a rectangular pyramid. In this context, the term "s" could represent either the slant height or some other unknown dimension of the pyramid.

If "s" represents the slant height of the pyramid, we can use the Pythagorean theorem to find its value. The slant height, "s," is the hypotenuse of a right triangle formed by one of the triangular faces of the pyramid and the height and half the width of the base.

Using the given dimensions:

l = 30 (length of the base)

w = 20 (width of the base)

h = 28 (height of the pyramid)

Let's find the value of "s" using the Pythagorean theorem:

[tex]s^2 = h^2 + (w/2)^2\\s^2 = 28^2 + (20/2)^2\\s^2 = 28^2 + 10^2\\s^2 = 784 + 100\\s^2 = 884\\[/tex]

Now, take the square root of both sides to find the value of "s":

s ≈ √884

s ≈ 29.75 (rounded to two decimal places)

So, if "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

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#SPJ2

#1

Paved area:-

#b

Let's see

Answer:

(a)  121 miles

(b)  7 days

Step-by-step explanation:

Given function:

[tex]\sf L(d)=205-7d[/tex]

Question (a)

When d = 12:

[tex]\sf \implies L(12)=205-7(12)[/tex]

                [tex]\sf =205-84[/tex]

                [tex]\sf =121 \ miles[/tex]

Therefore, the crew has 121 miles left to pave after 12 days.

Question (b)

When L(d) = 156

[tex]\sf \implies 156=205-7d[/tex]

[tex]\sf \implies 7d=205-156[/tex]

[tex]\sf \implies 7d=49[/tex]

[tex]\sf \implies d=\pm\sqrt{49}[/tex]

[tex]\sf \implies d=\pm7[/tex]

As distance is positive, [tex]\sf d=7[/tex] only

Therefore, the crew has been paving the the road for 7 days.

Answer:

10 miles

Step-by-step explanation:

He could run 2 miles.

Now he can run 5 times as far.

Now he can run 5 times 2 miles.

5 × 2 miles = 10 miles

The value of x determined algebraically given the total area of the rectangle is 1.5 inches

Initial dimensions:

Length = 14 inches

Width = 10 inches

New dimensions:

Length = 14 + x

Width = 10 + x

Area = 320 square inches

Area of a rectangle = Length × Width

320 = (14 + x) × (10 + x)

320 = 14x × 10x

320 = 140x²

x² = 320/140

x² = 2.28571428571428

x = √2.28571428571428

x = 1.511857892036908908858066144936720243

Approximately,

x = 1.5

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Answer:

8(x+4)=3

Step-by-step explanation:

the answer is this!

Hey there!

Finding something that’s equivalent to: 4m - 20

Option A.
4(m - 5)

= 4(m) + 4(-5)

= 4m - 20

Possibly Option A. is your answer.

Option B.
2(2m - 10)

= 2(2m) + 2(-10)

= 4m - 20

Possibly Option B. could be your answer

Option C.
4(m - 20)

= 4(m) + 4(-20)

= 4m - 80

Optipn C. isn’t your answer

Option D.
2(2m - 20)

= 2(2m) + 2(-20)

= 4m - 40

Option D. also isn’t your answer just like Option C.

FACTORS OF: 4m - 20

4: 1,2,4, & m

20: 1,2,4,5,10,& 20

LIKE TERMS: 1,2,4

GCF: 4

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let [tex]f(n) = \frac{(-1)^{n+1}}{n!}[/tex]

The summation given to us represents the following

[tex]\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\[/tex]

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum [tex]S_1[/tex] is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say [tex]S_1 = f(1) = 1[/tex]

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

[tex]S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\[/tex]

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

[tex]S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\[/tex]

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

[tex]S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\[/tex]

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like [tex]S_3 = S_2 + f(3)[/tex] and [tex]S_4 = S_3 + f(4)[/tex]

In general, [tex]S_{n+1} = S_{n} + f(n+1)[/tex] so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find [tex]S_5[/tex]

[tex]S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333[/tex]

The scratch work for f(5) is shown below.

Answer:

D

Step-by-step explanation:

When you look for (f+g)(x), we are in essence say that we're looking for f(x)+g(x)

=(2x+1)+(x^2-7).        (substitute for f(x) and g(x))

=2x+1+x^2-7.            (remove the brackets by substituting positive 1 into g(x))

=2x+x^2-6                (add like terms- in this case 1-7=6)

=x^2+2x-6                 (rearrange the equation)

Answer:

B. 3

Step-by-step explanation:

we know 2x3 = 6 soo just add 2 zeros = 600

Answer:

f(x) = ax + b, where a and b are real numbers.

Answer:

1/8

Step-by-step explanation:

Answer:

D. 100

Step-by-step explanation:

Mean = Sum of all numbers divided by the count of all numbers

Mean = 50

Let say that the sum of all numbers = X

50 = X / 4

200 = X

X = (20+30+50) + The 4th Value

200 = 100 + 4th Value

The 4th Value = 100